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Students can Download Chapter 8 Arrays Questions and Answers, Plus One Computer Science Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus One Computer Science Chapter Wise Questions and Answers Chapter 8 Arrays

Plus One Arrays One Mark Questions and Answers

Question 1.
From the following which is not true for an array.
(a) It is easy to represent and manipulate array variable
(b) Array uses a compact memory structure
(c) Readability of program will be increased
(d) Array elements are dissimilar elements
Answer:
(d) Array elements are dissimilar elements

Question 2.
Consider the following declaration.
int mark(50) Is it valid? If no give the correct declaration
Answer:
It is not valid. The correct declaration is as follows, int mark[50]. Use square brackets instead of parenthesis

Question 3.
Consider the following declaration.
int mark[200]
The index of the last element is ________.
Answer:
199

Question 4.
Consider the following declaration int mark[200]. The index of the first element is ________.
Answer:
0

Question 5.
Consider the following int age[4] = {15,16,17,18};
From the following which type of initialisation is this.
(a) direct assignment
(b) along with variable declaration
(c) multiple assignment
(d) None of these
Answer:
(b) along with variable declaration

Question 6.
From the following which is used to read and display array elements.
(a) loops
(b) if
(c) switch
(d) if else ladder
Answer:
(a) loops

Question 7.
Write down the corresponding memory consumption in bytes

1. int age[10] = ——-
2. charname[10] = ——-
3. int age[10][10]= ——–

Answer:

1. 2 × 10 = 20 bytbs (2 bytes for one integer)
2. 1 × 10 = 10 (one byte for each character)
3. 2 × 10 ×10 = 200 (2 × (100 elements))

Question 8.
A two dimensional array is having ________ number of subscript
(a) one
(b) two
(c) three
(d) none of these
Answer:
(b) two

Question 9.
Consider the following
int age[10][10];
In this array how many elements will contain.
Answer:
10 × 10 = 100 elements

Question 10.
Consider the following int age[4] = {12, 13, 14};
cout<<age[3];
What will be the output?
(а) 14
(b) 12
(c) 13
(d) 0
Answer:
(d) 0

Question 11.
The elements of 2 dimensional array can be read using _________ loop.
Answer:
nested loop

Question 12.
________ is the process of reading/visiting elements of an array.
Answer:
traversal

Question 13.
Anjali wants to read the 10 marks that already stored in an array and find the total. This process is known as ________.
(a) insertion
(b) deletion
(c) traversal
(d) linear search
Answer:
(c) traversal

Question 14.
Mani wants to check a number from 100 numbers already stored in an array. This process is called ___________.
(a) insertion
(b) deletion
(c) searching
(d) None of these
Answer:
(c) searching

Question 15.
Divide and conquer method used in ____________ search.
Answer:
binary

Question 16.
“Each element of the array is composed with value to be searched from the beginning of the array”. This method is adopted by _____________ search.
Answer:
linear search

Question 17.
____________ search requires a sorted array as input.
Answer:
binary search

Question 18.
___________ searching is slower for larger array.
Answer:
linear searching

Question 19.
____________ is a simple sorting algorithm.
(a) bubble sort
(b) selection sort
(c) linear search
(d) binary search
Answer:
(a) bubble sort

Question 20.
Adjacent elements are checked and inter changed in _____________ sort.
Answer:
bubble sort

Question 21.
The array is divided into sorted part and unsorted part in ____________ sort.
selection.

Question 22.
The elements of an array of size ten are numbered from _____ to _______.
Answer:
0 to 9

Question 23.
Element mark[6] is which element of the array?
(a) The sixth
(b) the seventh
(c) the eighth
(d) impossible to tell
Answer:
(b) the seventh

Question 24.
When a multidimensional array is accessed, each array index is ________.
(a) Separated by column.
(b) Surrounded by brackets and separated by commas.
(c) Separated by commas and surrounded by brackets.
(d) Surrounded by brackets,
Answer:
(d) surrounded by brackets

Question 25.
You have used a 2D array with the Name Mat representing a matrix. Write the C++ expression to access the 3rd element in the 2nd row.
Answer:
mat[1] [2];

Question 26.
Write a C++ statement that defines a string variable called ‘name’ that can hold a string of upto 20 characters.
Answer:
char name[21j;

Question 27.
Given some array declaration. Pick the odd man out.
Float a[+40], int num[0-10], double [50], char name[50], amount[20] of float.
Answer:
char name[50]. It is a valid array decalaration the remaining are not valid.

Question 28.
__________ is a collection of elements with same datatype.
Answer:
Array

Question 29.
int num[10];
The above C++ statement declares an array named num that can store maximum ________ integer numbers. (SEP-2015 (IMP) (1)
(а) 9
(b) 10
(c) N
(d) none of these
Answer:
(b) 10

Question 30.
Declare a two dimensional array to store the elements of a matrix with order 3 × 5. (MARCH-2016) (1)
Answer:
int m[3] [5]; or float m[3] [5]

Question 31.
_________ search method is an example for ‘divide and conquer method’. (SEP-2016) (1)
Answer:
Binary

Question 32.
Read the following C++ statement:
int AR[10]
How many bytes will be allocated for this array? (1)
Answer:
To store an integer 4 bytes needed so AR[10] needs 10 × 4 = 40 bytes

Question 33.
Find the value of score [4] based on the following declaration statement. int score [5] = {988,87,92,79,85}; (MARCH-2017) (1)
Answer:

Hence (158)₁₀ = (9E)₁₆

Plus One Arrays Two Mark Questions and Answers

Question 1.
Whether the statement char text[] = “COMPUTER”; is True/False? Justify.
Answer:
It is a single dimensional array. If the user doesn’t specify the size the operating system allocates the number of characters + one (for null character for text) bytes of memory. So here OS allocates 9 bytes of memory.

Question 2.
Given a word ” Mathematics”. How will you locate this word in a standard dictionary. What are the steps used for this purpose
Answer:
In the standard dictionary the words are arranged in sorted order so binary search method is more suitable to find the word “MATHEMATICS”.

Question 3.
How can you find out the word “MATHEMATICS” from a text book. Which is the most convenient method? Justify your answer.
Answer:
In a text book the words are not arranged in sorted order so linear search method is convenient.

Question 4.
Consider the statement char str[] = “PROGRAM” What will be stored in last location of this array. Justify.
Answer:
The last location is the null character(\0) because each string must be appedend by a null character.

Question 5.
Explain different array operations in detail.
Answer:

1. Traversal: All the elements of an array is visited and processed is called traversal
2. Search: Check whether the given element is present or not
3. Sorting: Arranging elements in an order is called sorting

Question 6.
Read the following C++ statement: int MAT[5][4];

1. How many bytes will be allocated for this array?
2. Suppose MAT[4][4] is a 2D array that contains the elements of a square matrix. Write C++ statements to find the’ sum of all the elements in the array. (MARCH – 2015) (1)

Answer:

Question 7.
Declare an array of size 5 and intitialize it with the numbers 8, 7, 2, 4 and 6. (MARCH-2016) (2)
Answer:
int n[5] = {8, 7, 2, 4, 6};

Question 8.
Predict the output of the following C++ program.
#include <iostream.h>
int main()
{
int array[] = {1, 2, 4, 6,7,5};
for (int n =1; n<=5; n++)
array [n] = array [n – 1 ];
for (n = 0; n <= 5; n++)
cout<< array [n];
return 0;
}
Answer:
1, 1, 1, 1, 1, 1

Question 9.
Suppose M[5][5] is a 2D array that contains the elements of a square matrix. Write C++ statements to find the sum of the diagonal elements. (SCERT SAMPLE – II) (2)
Answer:
for (i = 0; i < 5, i++)
for (j = 0; j < 5; j++)
if (i == j)
S = S + M[i][j];

Question 10.

1. Write C++ program for sorting a list of numbers using Bubble Sort Method. (2)
2. Write the different passes of sorting the following numbers using Bubble Sort.
   32, 21, 9, 17, 5

Answer:
1. Example for Bubble sort is given below

2. Bubble sort (ascending order):
Consider the first 2 elements of the numbers and compare it. 32 is greater than 21 then interchange both of them. Then the numbers are
21, 32, 9, 17, 5
Next compare 32 and 9. Here 32 is greater so interchange both of them. Then the numbers are
21, 9, 32, 17, 5
Next compare 32 and 7. Then interchange and the numbers are
21, 9, 17, 32, 5
Next compare 32 and 5. Then interchange and the numbers are
21, 9, 17, 5, 32.
After the first phase the largest number is on the right side. Similarly do the remaining. At last we will get the result as follows.
5, 9, 17, 21, 32

Question 11.
Suppose M[5] [5] is a 2D array that contains the elements of a square matrix. Write C++ statements to find the sum of the diagonal elements. (MARCH-2017)
Answer:

Plus One Arrays Three Questions and Answers

Question 1.
Suppose you are given Total mark of 50 students in a class

1. How will you store these values using ordinary variable?
2. Is there any other efficient way to store these values? Give reason.

Answer:
We have to declare 50 variables individually to store total marks of 50 students. It is a laborious work. Hence we use array, it is an efficient way to declare 50 variables. With a single variable name we can store multiple elements.
eg: int mark[50]. Here we can store 50 marks. The first mark is in mark[0], second is in mark[1]…. etc the fiftieth mark is in mark[49],

Question 2.
Four friends are in a queue for watching a movie. How can you locate a particular person from that queue? Write all the steps sequentially.
Answer:
Locate a particular person from a queue can be carried out by using two ways.
1. Linear search:
In this method each element of the array is compared with the element to be searched starting from the first element. If it finds the position of the element in the array is returned.

2. Binary search:
It uses a technique called divide and conquer method. It can be performed only on sorted arrays. First we check the element with the middle element. There are 3 possibilities. The first possibility is the searched element is the middle element then search can be finished.

The second possibility is the element is less than the middle value so the upper bound is the middle element. The third possibility is the element is greater than the middle value so the lower bound is the middle element. Repeat this process.

Question 3.
Total mark of 50 students in a class are given in an array. A bonus of 10 marks is awarded to all of them. Write the program code for making such a modification.
Answer:

Question 4.
In School Assembly, try to arrange all the students in your class according to the increasing order of their heights separately for male/female students. Smallest one will be in front and tallest one at the last position. Write sequential steps for doing this, in two different methods.
Answer:
Arranging elements from smallest to largest (ascending) or largest to smallest(descending) is called sorting. There are two sorting methods
1. Bubble sort:
It is a simple sorting method. In this sorting considering two adjacent elements if it is out of order, the elements are interchanged. After the first iteration the largest(in the case of ascending sorting) or smallest(in the case of descending sorting) will be the end of the array. This process continues.

2. Selection sort:
In selection sort the array is divided into two parts, the sorted part and unsorted part. First smallest element in the unsorted part is searched and exchanged with the first element. Now there is 2 parts sorted part and unsorted part. This process continues.

Question 5.
Using the concept obtained from algorithms in question number (9), write complete program for the two types of sorting.
Answer:

Question 6.
Collect the heights of 12 students from your class in which 7 students are male and others are female students. Suppose these male and female students be seated in two separate benches and you are given a place which is used for sitting these 12 students in linear form. How will you combine and make them sit without mixing male/female students. Write a program for the same.
Answer:

Question 7.
Collect the heights of 12 students from your class in which 7 students are male and others are female students. Suppose you are given the heights according to a sorted order separately for male/female students. How will you combine these group according to the same order in linear form. Write a program for the same.
Answer:

Question 8.
Write the program code for counting the number of vowels from your school name.
Answer:

Question 9.
Write the program code for counting the number of words from the given string.” Directorate of Higher Secondary Examination”
Answer:

Question 10.
Given a word like “ECNALUBMA” Write the program code for arranging it in into a meaningful word.
Answer:

Question 11.
Explain the needs for arrays Array
Answer:
Array is collection of same type of elements. With the same name we can store more elements. The elements are distinguished by using its index or subscript. To store 50 marks of 50 students we have to declare 50 variables, it is a laborious work.

Hence the need for arrays arise. By using array this is very easy as follows int mark[50]. Here the index of first element is 0, then 1, 2, 3, etc upto 49.

Question 12.
Explain different types of arrays.
Answer:
There are two tyes of array
1. Single dimensional:
It contains only one index or subscript. The index starts from 0 and ends with size-1.
eg: int n[50];
char name[10];

2. Multi-dimensional:
It contains more than one index or subscript. The two dimensional array contains two indices, one for rows and another for columns. The row index starts from 0 and end at row size-1 and column index starts at 0 and ends at colunn size-1.
eg: int n[10][10] can store 10 × 10 = 100 elements. The index of the first element is n[0][0] and index of the 100th element is n[9][9],

Question 13.
Write a program to read the 5 marks of a students and display the marks and total
Answer:

Question 14.
Write a program to read 3 marks of 5 students and find the total and display it.
Answer:

Question 15.
Differentiate linear search and binary search
Answer:
1. Linear search:
In this method each element of the array is compared with the element to be searched starting from the first element. If it finds the position of the element in the array is re¬turned.

2. Binary search:
It uses a technique called divide and conquer method. It can be performed only on sorted arrays. First we check the element with the middle element. There are 3 possibilities. The first possibility is the searched element is the middle element then search can be finished.

The second possibility is the element is less than the middle value so the upper bound is the middle element. The third possibility is the element is greater than the middle value so the lower bound is the middle element. Repeat this process.

Question 16.
Differentiate bubble sort and selection sort.
Answer:
1. Bubble sort:
It is a simple sorting method. In this sorting considering two adjascent elements if it is out of order, the elements are interchanged. After the first iteration the largest(in the case of ascending sorting) or smallest (in the case of descending sorting) will be the end of the array. This process continues.

2. Selection sort:
In selection sort the array is divided into two parts, the sorted part and unsorted part. First smallest element in the unsorted part is searched and exchanged with the first element. Now there is 2 parts sorted part and unsorted part. This process continues.

Question 17.
Write a program to read a string and a character and find the character by using linear search.
Answer:

Question 18.
Write a program to read marks of 10 students and read a mark and check whether it is in the array or not using binary search
Answer:

Question 19.
Write a program reverse a string without using a function.
Answer:

Question 20.
Write a program to read a string and find the no. of vowels .consonents and special characters.
Answer:

Question 21.
Given a word “COMPUTER”, write a C++ program to reverse the word without using any string functions.
Answer:
#include<iostream>
using namespace std;
int main(()
{
char a[9] = “COMPUTER”;
inti;
for (i=8; i>=0; i- -)
{
cout<<a[i];
}
}

Question 22.
Write a program to accept marks of 10 students and find out the largest and smallest mark from the list.

OR

C++ program to store the scores of 10 batsmen of a school cricket team and find the largest and smallest score.
Answer:

Question 23.
Write the names of two searching methods in arrays. Prepare a chart that shows the comparisons of two searching methods. (MARCH-2015)
Answer:
It is the process of finding the position of the given element.
1. Linear search:
In this method each element of the array is compared with the element to be searched starting from the first element. If it finds the position of the element in the array is returned.

2. Binary search:
It uses a technique called divide and conquer method. It can be performed only on sorted arrays. First we check the element with the middle element. There are 3 possibilities. The first possibility is the searched element is the middle element then search can be finished.

The second possibility is the element is less than the middle value so the upper bound is the middle element. The third possibility is the element is greater than the middle value so the lower bound is the middle element. Repeat this process.

Question 24.
Write a C++ program to illustrate array traversal. (SAY-2015 (IMP) (3)
Answer:
#include<iostream>
using namespace std;
int main()
{
int i, mark[50];
for(i=0;i<50; i++)
{
cout<<“Enter mark “<<i + 1<<“: cirt>>mark[i];
}
cout<<“\nThe mark of 50 students after adding bonus mark 10 is given below \n”; for(i=0;i<50; i++)
cout<<mark[i] + 10<<endl;
}

Question 25.
Define an array. Also write an algorithm for searching an element in the array using any one method that you are familiar with. (MARCH-2016) (3)
Answer:
An array is a collection of elements with same data type. The index of first element is 0 (zero) and the index of last element is size -1. There are 2 methods linear search and binary search.

Searching: It is the process of finding the position of the given element.
1. Linear search:
In this method each element of the array is compared with the element to be searched starting from the first element. If it finds the position of the element in the array is returned.

2. Binary search:
It uses a technique called divide and conquer method. It can be performed only on sorted arrays. First we check the element with the middle element. There are 3 possibilities. The first possibility is the searched element is the middle element then search can be finished.

The second possibility is the element is less than the middle value so the upper bound is the middle element. The third possibility is the element is greater than the middle value so the lower bound is the middle element. Repeat this process.8.3 Two dimensional (2D) arrays.

Some occasions we have to store 6 different marks of 50 students. For this we use 2D arrays. An array with two subscripts is used, eg. int mark[r][c]; Here r is the row and c is the column.

Question 26.

1. Finding sum of all elements in an array is an example of _________ operation.
2. If 24, 45, 98, 56, 76, 24, 15 are the elements of an array, illustrate the working of selection sort for arranging the elements in descending order. (SCERT SAMPLE -1) (3)

Answer:
1. Traversal

2. In selection sort the array is divided into two parts the sorted part and unsorted part. First smallest elemant in the unsorted part in searched and exchanged with the first elemant now there is 2 parts sorted part and unsorted part. This process continues.

Question 27.
Read the following C++ statement:

1. How many bytes will be allocated for this array?
2. Write algorithm to sort this array using bubble sort method. (SCERT SAMPLE – II) (3)

Answer:
1. To store an integer 4 bytes needed so AR[10] needs 10 × 4 = 40 bytes.

2. Sorting – Arranging elements of an array in an order(ascending or descending).
(a) Bubble sort:
It is a simple sorting method. In this sorting considering two adjascent elements if it is out of order, the elements are interchanged. After the first iteration the largest(in the case of ascending sorting) or smallest(in the case of descending sorting) will be the end of the array. This process continues.

(b) Selection sort:
In selection sort the array is divided into two parts, the sorted part and unsorted part. First smallest element in the unsorted part is searched and exchanged with the first element. Now there is 2 parts sorted part and unsorted part. This process continues.

Question 28.
Explain ‘Call by Value’ and ‘Call by Reference’ methods of function calling with the help of a suitable example. (SEP-2016) (3)
Answer:
Two types are call by value and call by reference.
1. Call by value:
In call by value method the copy of the original value is passed to the function, if the function makes any change will not affect the original value.
Example

2. Call by reference:
In call by reference method the address of the original value is passed to the function, if the function makes any change will affect the original value.
Example

Question 29.
What is an array? Write C++ program to declare and use a single dimensional array for storing the computer science marks of all students in your
class. (SEP-2016) (3)
Answer:
An array is a collection of elements with same data type or with the same name we can store many elements, the first or second or third etc can be distinguished by using the index(subscript). The first element’s index is 0, the second elements index is 1, and so on.

Question 30.
Write an algorithm for arranging elements of an array in ascending order using bubble sort. (MARCH-2017) (3)
Answer:

Plus One Arrays Five Mark Questions and Answers

Question 1.
Write a program to perform matrix addition, multiplication, subtraction.
Answer:

Students can Download Chapter 10 Functions Questions and Answers, Plus One Computer Science Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus One Computer Science Chapter Wise Questions and Answers Chapter 10 Functions

Plus One Functions One Mark Questions and Answers

Question 1.
The process of dividing big programs into small programs are called __________.
Answer:
Modularization

Question 2.
The big programs are divided into smaller programs. This smaller programs are called __________.
Answer:
Functions

Question 3.
The execution of the program begins at __________ function.
Answer:
main function

Question 4.
One of the following is not involved in the creation and usage of a user defined function.
(a) Define a function
(b) Declare a function
(c) invoke a function
(d) None of these
Answer:
(d) None of these

Question 5.
The default data type returned by a function is ________.
(a) float
(b) double
(c) int
(d) char
Answer:
(c) int

Question 6.
After the execution of a function, it is returned back to the main function by executing _________ keyword.
Answer:
return

Question 7.
Supplying data to a function from the called func-tion by using _________.
Answer:
parameters (arguments)

Question 8.
_________ keyword is used to give a value back to the called function.
Answer:
return.

Question 9.
_________ key word is used to specify a function returns nothing.
Answer:
void

Question 10.
One of the following is not necessary in the function declaration. What is it?
(a) name of the function
(b) return type
(c) number and type of arguments
(d) name of the parameters
Answer:
(d) name of the parameters

Question 11.
A function declaration is also called _________.
Answer:
prototype

Question 12.
Consider the following declaration
int sum(int a , int b)
{
return a+b;
}
From the following which is the valid function call.
(a) n = sum(10)
(b) n = sum(10,20)
(c) n = sum(10,20,30)
(d) n = sum()
Answer:
(b) n = sum(10,20)

Question 13.
The ability to access a variable or a function from some where in a program is called ________.
Answer:
scope

Question 14.
A variable or a function declared within a function is have ______ scope.
Answer:
local

Question 15.
A variable or a function declared out side of all the functions is have __________ scope.
Answer:
global

Question 16.
State True/False

1. A local variable exist till the end of the program
2. A global variable destroyed when the sub function terminates

Answer:

1. False
2. False

Question 17.
consider the following declaration
int x;
void main()
{
……..
}
Here x is a _____ variable.
Answer:
global

Question 18.
consider the following declaration
void main()
{
int x;
}
Here x is a _______ variable
Answer:
local

Question 19.
__________ parameter is used when the function call does not supply a value for parameters
Answer:
default

Question 20.
The parameter used to call a function is called ____________.
Answer:
Actual parameter

Question 21.
The parameters appear in a function definition are ___________.
Answer:
formal parameters

Question 22.
After the distribution of answer scripts, the teacher gives the Photostat copy of the mark list to the students to check the marks. If the students make any change that do not affect the original mark list. There is a similar situation to pass the arguments to a function. What is this method?
(a) call by value
(b) call by reference
(c) call by address
(d) none of these
Answer:
(a) call by value

Question 23.
Your class teacher gives you the original mark list to check the mark. If you make any change it will affect the original mark list. There is a similar situation to pass the arguments to a function. What is this method?
(a) call by value
(b) call by reference
(c) call by function
(d) none of these
Answer:
(b) call by reference

Question 24.
Consider the following function declaration
int sum(int,a, int b)
{
Body
}
Here the arguments are passed by __________.
Answer:
call by value method

Question 25.
Consider the following function declaration
int sum(int &a, int &b)
{
Body
}
Here the arguments are passed by __________.
Answer:
call by reference method

Question 26.
A function calls it self is known as ____________.
Answer:
recursive function

Question 27.
Varun wants to copy a string by using strcpy() function. From the following which header file is used for this?
(a) cstdio
(b) cmath
(c) cstring
(d) cctype
Answer:
(c) cstring

Question 28.
__________ is a named group of statements to perform a job/task and returns a value.
Answer:
Function

Question 29.
In his C++ program Ajith wants to accept a lengthy text of more than one line. Which function in C++ can be used in this situation.
Answer:
gets() function can be used to accept a lengthy text.

Question 30.
A function can call itself for many times and return a result. What is the name given to such a function? (MARCH-2016)
Answer:
Recursive function

Question 31.
How many values can a C++ function return? (SCERT SAMPLE-I) (1)
Answer:
One Value

Question 32.
A function may require data to perform the task assigned to it. Which is the component of function prototype that serves this purpose? (SCERT SAMPLE – II) (1)
Answer:
Arguments (Parameters)

Question 33.
“Arguments used in call statement are formal arguments”. State true or false. (SAY-2016) (1)
Answer:
False

Question 34.
Name the built-in function to check whether a character is alphanumeric or not. (MARCH-2017)
Answer:
pisalnum()

Plus One Functions Two Mark Questions and Answers

Question 1.
How does C++ support modularity in programming C++
Answer:
The process of converting big programs into smaller programs is known as modularisation. This small programs are called modules or sub programs or functions. C++ supports modularity in programming called functions.

Question 2.
Consider the following code snippet
charch;
cout << “Enter an alphabet”;
cin>>ch;
cout<<toupper (ch);
What is the output of the above code? Give a sample output.
If the above code is used in a computer that has no cctype file, how will you modify the code to get the same output?
Answer:
It reads a character and convert it into upper case.
eg:
Enter an alphabet: a
The output is A.
If a computer has no cctype header file the code is as follows,
char ch;
cout<< “Enter an alphabet”;
cin»ch;
if (ch >= 97 && ch<<122)
cout<<ch – 32;

Question 3.
The following assignment statement will generate a compilation error.
char str[20];
str = “Computer”
Write a correct C++ statement to perform the same task
Answer:
char str[20] = “Computer”;

OR

char str[20];
strcpy(str,”Computer”); (The header file <string.h> should be included)

Question 4.
float area(const float pi = 3.1415, const float r)
{
r = 10;
return pi*r;
}
Is there any problem? If yes what is it?
Answer:
There is an error. The error is ‘r’ is a constant V must be initialised and cannot be changed during execution.

Question 5.
Match the following

Answer:
a. 3
b. 1
c. 5
d. 4
e. 2

Question 6.
What are the jobs of a return statement in a program?
Answer:
In the case of a sub function a return statement helps to terminate the sub function and return back to the main function or called function. But in the case of a main function it terminates the program.

Question 7.
How to invoke a function in C++ program?
Answer:
function can be called or invoked by providing the name of the function followed by the arguments in parenthesis.
eg: sum(m,n);

Question 8.
Briefly explain constant arguments
Answer:
By using the keyword const we can make argument (parameter) of a function as a constant argument. The value of the const argument cannot be modified within the function.

Question 9.
Short notes on header files
Answer:
A header file is a prestored file that helps to use some operators and functions. To write C++ pro-grams the header files are must. Following are the header files
alloc
iostream
iomanip
cstdio
cctype
cmath
cstring
The syntax for including a header file is as follows
#include<name of the header file>
eg: #include<iostream>

Question 10.
Identify the appropriate header files for the following.

1. setw()
2. cout
3. toupper()
4. exit()
5. strcpy()

Answer:

1. setw() – iomanip.h
2. cout – iostream
3. toupper() – cstring
4. exit() – process
5. strcpy() – cstring

Question 11.
Construct the function prototypes for the following functions.

1. The function Display() accepts one argument of type double and does not return any value.
2. Total () accepts two arguments of type int, float respectively and returns a float type value. (MARCH-2015) (2)

Answer:

1. void Display(double);
2. float Total(int, float);

Question 12.
Explain two types of variable according to its scope and life. (SAY-2015) (2)
Answer:
Scope and life of variables and functions
1. Local scope:
A variable declared inside a block can be used only in the block. It cannot be used any other block.
eg:
#include<iostream>
using namespace std;
int sum(int n1 ,int n2)
{
int s;
s = n1 + n2;
return (s);
}
int main()
{
int n1 ,n2;
cout<<“Enter 2 numbers cin>>n1>>n2;
cout<<“The sum is “<<sum(n1 ,n2);
}
Here the variable s is declared inside the function sum and has local scope;

2. Global scope:
A variable declared outside of all blocks can be used any where in the program.
#include<iostream>
using namespace std;
int s;
int sum(int n1,int n2)
{
s = n1 + n2;
return(s);
}
int main()
{
int n1 ,n2;
cout<<“Enter 2 numbers cin>>n1>>n2;
cout<<“The sum is “<<sum(n1,n2);
}
Here the variable s is declared out side of all functions and we can use variable s any where in the program.

Question 13.
There is a way to pass more than one value to the calling function from the called function. Explain how? (SCERT SAMPLE – I) (2)
Answer:
Methods of calling functions
Two types call by value and call by reference.
1. Call by value:
In call by value method the copy of the original value is passed to the function, if the function makes any change will not affect the original value.
Example
#include<iostream.h>
#include<conio.h> void
swap(int a, int b)
{
int temp;
temp = a;
a = b;
b = temp;
}
main()
{
clrscr();
int a,b;
cout<<“Enter values for a and b:-“;
cin>>a>>b;
cout<<“The values before swap a =”<<a<<“ and
b =”<<b;
swap(a,b);
cout<<“\nThe values before swap a =”<<a«“ and
b =”<<b;
getch();
}

2. Call by reference:
In call by reference method the address of the original value is passed to the function, if the function makes any change will affect the original value.
Example
#include<iostream.h>
#include<conio.h>
void swap(int &a, int &b)
{
int temp;
temp = a;
a = b;
b = temp;
}
main()
{
clrscrO;
int a,b;
cout<<“Enter values for a and b:- “; cin>>a>>b;
cout<<“The values before swap a =”<<a<<“ and
b=”<<b;
swap(a,b);
cout<<“\nThe values before swap a =”<<a<<“ and
b =”<<b;
getch();
}

Question 14.
A
Answer:
int sum (int N, int Start_No) .
{
int i, S = 0;
for (i = Start_No; i < = N + Start_No; i++)
S = S + i;
reurn S;
}

Question 15.
Differentiate between the string functions strcmp() and strcmpi(). (SAY-2016) (2)
Answer:
strcmp(): It is used to compare two strings and returns an integer.
Syntax:
strcmp(string1,string2)

• if it is 0 both strings are equal.
• if it is greater than 0(i.e. +ve) stringl is greater than string2
• if it is less than 0(i.e. -ve) string2 is greater than string1

strcmpi():
It is same as strcmp() but it is not case sensitive. That means uppercase and lowercase are treated as same.
eg: “ANDREA” and “Andrea” and “andrea” these are same.

Question 16.
Read the function definition given below. Predict the output, if the function is called as convert (7). (MARCH-2017) (2)
void convert (int n)
{
if (n>1)
convert (n/2);
cout<<n%2;
}
Answer:
The out put is 111. convert() is a recursive function.

Plus One Functions Three Mark Questions and Answers

Question 1.
Consider the following function declaration with optional (default) arguments and state legal or illegal and give the reasons

1. int sum(int x = 10, int y, int z)
2. int sum(int x = 10, int y = 20, int z)
3. int sum(int x = 10, int y = 20, int z = 30)
4. int sum(int x, int y = 20, int z)
5. int sum(int x, int y = 20, int z = 30)
6. inf sum(int x, int y, int z = 30)
7. int sum(int x = 10, int y, int z = 30)

Answer:
There is a rule to make an argument as default argument,i.e., to set an argument with a value that must be in the order from right to left. All the arguments in the right side of an argument must be set first to make an argument as a default argument.

1. illegal, because y and z are not have values
2. illegal, because z has no value
3. legal
4. illegal, because z has no value
5. legal
6. legal
7. illegal, because x has a value but y has no value

Question 2.
A list of C++ built-in functions are given. Classify them based on the usage and prepare a table with proper group names.

Answer:

Question 3.
Read the following program
#include<iostream>
using namespace std;
int main()
{
cout<<sum(2,3);
}
int sum(int x, int y)
{return (x + y);}
On compilation on the program, an error will be displayed. Identify and explain the reason. How can you rectify the problem
Answer:
The compilation of the program starts from the first line arid next line and so on( i.e. line by line). While compiling the line cout<<sum(2,3); The compiler does not understand the word sum(2,3) because it is not declared yet hence the error prototype required. To rectify this problem there are two methods

First method:
Give the function definition just before the main function as follows.
#include<iostream>
using namespace std;
int sum(intx, int y)
{return (x + y);}
int main()
{
cout<<sum(2,3);
}

Second Method:
Give the function declaration(prototype only) in the main function as follows.
#include<iostream>
using namespace std;
int main()
{
int sum(int.int);
cout<<sum(2,3);
}
int sum(int x, int y)
{return (x + y);}

Question 4.
Considering the following function definition.
{
for (int f = 1; n>0; n-)
f = f*n;
return f;
}
void main()
{
int a = 5, ans;
ans = fact (a);
cout<< a << “! = ” << ans;
}
The expected, desired output is 5! = 120
What will be the actual output of the program? It is not the same as above, why? What modification are required in the program to get the desired output.
Answer:
The output is 0! = 120
Because the address of variable ’a’ is given to the variable ‘n’ of the function fact(call by reference method). So the function changes its value (i.e. n-) to 0. Hence the result.
To get the desired result call the function as call by value method in this method the copy of the value of the variable ‘a’ is given to the function. So the actual value of ‘a’ will not changed. So instead of int fact(int &n) just write int fact(int n), i.e., no need of & symbol.

Question 5.
A function is defined as follows
int sum (int a, int b = 2)
{return (a + b);}
Check whether each of the following function calls is correct or wrong, Justify your answer

1. cout << sum (2,3);
2. cout << sum( 2) ;
3. cout << sum();

Answer:
Here the function is declared with one optional argument. So the function call with minimum one argument is compulsory.

1. It is valid. Here a becomes 2 and b becomes 3.
2. It is also valid . Here a becomes 2 and b takes the default value 2.
3. It is not a valid call. One argument is compulsory.

Question 6.
The factorial of a number, say N is the product of first N natural numbers. Thus, factorial of 5 can be obtained by taking the product of 5 and factorial of 4. Similarly factorial of 4 be found out by taking the product of 4 and factorial of 3. At last the factorial of 1 is 1 itself.

Which technique is applicable to find the factorial of a number in this fashion? Write a C++ function to implement this technique. Also explain the working of the function by giving the number 5 as input.
Answer:
A function calls itself is known as recursion.
#include<iostream>
using namespace std;
int fac(int);
int main()
{
int n;
cout<<“enter a number”;
cin>>n;
cout<<fac(n);
}
int fac(int n)
{
if (n == 1) return (1);
else
return (n × fac(n – 1));
}
The working of this program is as follows If the value of n is 5 then it calls the function as fa. The function returns value 5 × fac(4), That means this function calls the function again and returns 5 ×4 × fac(3). This process continues until the value n = 1. So the result is 5 × 4 × 3 × 2 × 1 = 120.

Question 7.
How do two functions exchange data between them? Compare the two methods of data transfer from calling function to called function
Answer:
There are two methods they are call by value and call by reference
1. call by value:
In call by value method, a copy of the actual parameters are passed to the formal parameters. If the function makes any change it will not affect the original value.

2. call by reference:
In call by reference method, the reference of the actual parameters are passed to the formal parameters. If the function makes any change it will affect the original value.

Question 8.
Read the following program
#include<iostream>
using namespace std;
int a = 0;
int main()
{
int showval(int);
cout<< a; a++;
cout << showval (a);
cout<< a;
}
int showval(int x)
{
int a = 5;
return (a + x);
}
Write down the value displayed by the output of the above program with suitable explanation. What are the inferences drawn regarding the scope of variables?
Answer:
The output is 061.
Global variable: A variable declared out side of all functions it is known as global variable.
Local variable: A variable declared inside of a function it is known as local variable.
If a variable declared inside a function(main or other) with the same name of a global variable. The function uses the value of local variable and does not use the value of the global variable.

Here int a = 0 is a global variable. In the main function the global variable ‘a’ is used. There is no local variable so the value of ‘a’, 0 is displayed. The statement ‘a++’ makes the value of ‘a’ is 1. It calls the function showval with argument ‘a = T.

The argument ‘x’ will get this value i.e. ‘x = 1 But in the function showval there is a local variable ‘a’ its value is 5 is used. So this function returns 6 and it will be displayed. After this the value 1 of the global variable ‘a’ will be displayed. Hence the result 061.

Question 9.
The following are function calling statements. Some of them will be executed, while some other generate compilation error. Write down your opinion on each of them with proper justification Function

1. har ch =
2. sqrt(25);
3. strcat (“Computer”, “Program”);
4. double num = pow(2,3,5)
5. putchar(getchar());

Answer:

1. getch get a character from the console(keyboard) but does not echo to the screen. So we can’t read a character from the console.
2. It returns the square root of 25.
3. It concatenates Program to computer, i.e. we will get a string “computer program”
4. The function pow should contains only two arguments. But here it contains 3 arguments so it is an error. We can write this function as follows Double num = pow(pow(2,3),5)
5. It reads a character from the console and display it on the screen.

Question 10.
Write down the operation performed by the following statements.

1. int l = strlen(“Computer Program”);
2. char ch[ ] = tolower(“My School”);
3. cout <<(strcmp(“High”, “Low”)>0 ? toupper(“High”):tolower(“Low”));

Answer:

1. The built in function strlen find the length of the string i.e. 16 and assigns it to the variable I.
2. This is an error because tolower is a character function.
3. This is also an error because tolower and toupper are character functions.

Question 11.
A line of given length with a particular character is to be displayed. For example, ********** js a line with ten asterisks (*). Define a function to achieve this output.
Answer:

Question 12.
Read the following function
int fib(int n)
{
if (n<3)
return 1;
else
return (fib(n – 1) + fib(n – 2));
}

1. What is the speciality of this function
2. How does it work?
3. What will be the output of the following code?

Answer:

1. This function is a recursive function. That means the function calls itself.
2. It works as follows
   • if i = 1, The function fib calls with value 1. i.e. fib(1) returns 1
   • if i = 2, The function fib calls with value 2. i.e. fib(2) returns 1
   • if i = 3, The function fib calls with value 3. i.e. fib(3) returns fib(2) + fib(1) i.e. it calls the function again.
     So the result is 1 + 1 = 2
   • if i = 4, The function fib calls with value 4. i.e. fib(4) returns fib(3) + fib(2) i.e. it calls the function again.
     So the result is 2 + 1 = 3
3. The output will be as follows 1 1 2 3

Question 13.
Explain scope rules of functions and variables in a C++ program
Answer:
Local variable or function:
A variable or function declared inside a function is called local variable or function. This cannot be accessed by the out-side of the function.
eg:
main()
{
int k; // local variable
cout<<sum(a,b); // local function
}

Global variable or function:
A variable or function declared out side of a function is called global variable or function. This can be accessed by any statements.
eg:
int k; // global variable
int sum(int a, int b); // global function
main()
{
}

Question 14.
Briefly explain default arguments Default arguments.
Answer:
A default value can be set for a parameter (argument) of a function. When the user does not give a value the function will take the default value. An important thing remember,is an argument cannot have a default value unless all arguments on its right side must have default value.
Functions with valid default arguments are given below

• float area(int x, int y, int z = 30);
• float area(int x, int y = 20, int z = 30);
• float area(int x = 10, int y = 20, int z = 30);

Functions with invalid default arguments are given below

• float area(int x = 10, int y, int z);
• float area(int x, int y = 20, int z);
• float area(int x = 10, int y = 20, int z);

Question 15.
How to pass an array to function.
Answer:
By using call by reference method we can send an array as argument. We have to send only the array name and its data type. The array name holds the starting address and will access the subsequent elements of an array.
The following example shows this

Question 16.
How to pass a structure to a function.
Answer:
A structure can be passed as argument to a function either call by value or call by reference method. An example is given below to read name and age of a structure and pass it to a function.

Question 17.
Write a program to read a character and check whether it is alphabet or not. If it is an alphabet check whether it is upper case or lower case?
Answer:

Question 18.
Write a program to read 2 strings and join them 2 string.
Answer:

Question 19.
Write a program to read 2 strings and compare it 2 string.
Answer:

Question 20.
Write a program to read a string and display the number of alphabets and digits and special characters.
Answer:

Question 21.
Write a program to perform the following opera-tions on a string

1. Length of a string
2. Search a character
3. Display the string

Answer:

Question 22.
Write short notes about conversion functions.
Answer:
The header file stdlib.h is used for conversion functions.Following are the important conversion functions
1. itoa():
It is used to convert an integer into a string.
eg:
int n = 100;
charstr[20];
itoa(n,str,10);

2. Itoa():
It is used to convert an long into a string.
eg:
long n = 1002345L
char str[20];
ltoa(n,str,10);

3. atoi():
It is used to convert a string into integer
eg:
int n;
str[] = “123”
n = atoi(str);

4. atoll():
It is used to convert a string into long
eg:
long n;
str[] = “123456”
n = atol(str);

Question 23.

1. Predict the output of both programs.
2. Justify your predictions.

Answer:
1. A. Output
value = 40

B. output
value = 0

2. In the first case (A) the argument x is passed by reference method. So the changes made in the function reflects in main()

In the second case (B) the argument x is passed by value method. So the changes made in the function will not reflect in main()

Question 24.
Consider the following C++ function.
int recfact(int x)
{
if(x == 0)
return 1;
else
return x * recfact(x – 1);
}

1. What type of function is this? Explain. (2 Scores)
2. What is the output of the above function when x = 5

Answer:

1. recursive function. The abilty of a function to call itself is called recursion. A function is said to be recursive if a statement in the body of the function calls itself.
2. Output 120

Question 25.
void initialise()
{
int k = 10;
}
int main()
{
int a, b;
float marks;
a = 20;
cout<<“First value =”<< a;
initialise();
b = k + a;
cout<<“New value =”<<b;
}

1. Identify the error in the above code and explain its reasons.
2. Correct the errors.

Answer:

1. K is a local variable in the function initialize 0. It is not accessible in main()
2. Making the variable K as global we can correct the error.

Question 26.
Write a program to read 2 strings and join them using string function.
Answer:
#include<iostream>
#include<cstring>
#include<cstdio>
using namespace std;
int main()
{
char str1 [50],str2[50],str[100];
cout<<“Enter a string:”; gets(strl);
cout<<“Enter another string:”; gets(str2);
strcat(str,str1);
strcat(str,str2);
cout<<“The concatenated string is”<<str;
}

Question 27.
Consider the following code.
#include<iostream>
#include<cstdlib>
using namespace std;
int main()
{
char str1 [] = “123”,str2[] = “45”;
int a,b;
a = atoi(str1);
b = atoi(str2);
cout<<a + b;
}
What will be the output and give the reason?
Answer:
The output is 123 + 45 = 168. Here the conversion function atoi is used to convert the string “123” into integer 123 and “45” into integer 45 so the result.

Question 28.
Name the different methods used for passing arguments to a function. Write the difference between them with examples. (MARCH-2015)
Answer:
Methods of calling functions:
Two types call by value and call by reference.
1. Call by value:
In call by value method the copy of the original value is passed to the function, if the function makes any change will not affect the original value.
Example

2. Call by reference:
In call by reference method the address of the original value is passed to the function, if the function makes any change will affect the original value.
Example

Question 29.
Write a C++ program to display the simple interest using function. (SAY-2015) (3)
Answer:
include < iostream>
using namespace std;
float Simplelnt (float p, int n, float r)
{
return (p*n*r/100);
}
int main()
{
float p, r, SI;
int n;
cout<<“Enter values for p,n,r:”; cin>>p>>n>>r;
SI = Simplelnt (p,n,r); cout<<“simple interest is”<<SI;
}

Question 30.
Write a function’s definition of the above type to find the sum of matural numbers from 1 to N. (Hint: If the value of N is 5, the answer will be 1 + 2 + 3 + 4 + 5 = 15). (MARCH – 2016) (3)
Answer:
int sum (int n)
{
if (n == 0)
return 0;
else
return (n + sum (n – 1));
}

Question 31.
A program requires functions for adding 2 numbers, 3 numbers and 4 numbers, How can you provide a solution by writing a single functio0n? (SCERT SAMPLE -1) (3)
Answer:
It can be solved by writing function with default values.
eg: int add (int n1, int n2, int n3 = 0, int n4 = 0)
{
return (n1 + n2 + n3 + n4);
}
This function can be invoked by the following function calling
1. add (5,2);
2. add (5,2,7);
3. add (5,2,7,10);

The 1. Call returns 5 + 2 = 7
2. Call returns 5 + 2 + 7 = 14
3. Call returns 5 + 2 + 7 + 10 = 24

Question 32.
Explain the difference between call-by-value method and call-by-reference method with the help of examples. (SCERT SAMPLE – II) (3)
Answer:
Methods of calling functions:
Two types call by value and call by reference.
1. Call by value:
In call by value method the copy of the original value is passed to the function, if the ’ function makes any change will not affect the original value.
Example

2. Call by reference:
In call by reference method the address of the original value is passed to the function, if the function makes any change will affect the original value.
Example

Question 33.
Explain recursive functions with the help of a suitable example. (SAY-2016) (3)
Answer:
A function calls itself is called recursive function.
#include<iostream>
using namespace std;
void convert(int n)
{
if(n>1)
convert(n/2);
cout<<n % 2;
}
int main()
{
convert(7);
}
Here the function convert is a recursive function, that means it calls itself and output of the above program is 111.

Question 34.
Name the built-in function to check whether a character is alphanumeric or not. (MARCH-2017) (3)
Answer:
isalnum()

Question 35
Briefly explain the three components in the structure of a C++ program. (MARCH-2017) (3)
Answer:
1. Preprocessor directives:
A C++ program starts with the preprocessor directive i.e., # .include, #define, #undef, etc, are such a preprocessor directives. By using #include we can link the header files that are needed to use the functions. By using #define we can define some constants.
eg: #define x 100. Here the value of x becomes 100 and cannot be changed in the program. No semicolon is needed.

2. Header files:
A header file is a pre stored file that helps to use some operators and functions. To write C++ programs the header files are must. Following are the header files iostream

• iomanip
• cstdio
• cctype
• cmath
• cstring

The syntax for including a header file is as follows
#include<name of the header file>
eg: #include<iostream>

3. The main function:
The main function is the first function which is invoked at the time of execution and the program ends within main(). The other functions are invoke from main().

Question 36.
Explain the difference between call by value method and call by reference method with the help of examples. (MARCH-2017) (3)
Answer:
Two types are call by value and call by reference.
1. Call by value:
In call by value method the copy of the original value is passed to the function, if the function makes any change wilt not affect the original value.
Example

2. Call by reference:
In call by reference method the address of the original value is passed to the function, if the function makes any change will affect the original value.
Example

Plus One Functions Five Mark Questions and Answers

Question 1.
Short notes about character functions and string functions
Answer:
A. Character functions:
1. isalnum():
t is used to check whether a character is alphabet or digit. It returns a non zero value if it is an alphabet or digit otherwise it returns zero.

2. isalpha():
It is used to check whether a character is alphabet or not. It returns a non zero value if it is an alphabet otherwise it returns zero.

3. isdigit():
It is used to check whether a character is digit or not. It returns a non zero value if it is digit otherwise it returns zero.

4. islower():
It is used to check whether a character is lower case alphabet or not. It returns a non zero value if it is a lowercase alphabet otherwise it returns zero.

5. isupper():
It is used to check whether a character is upper case alphabet or not. It returns a non zero value if it is an upper case alphabet otherwise it returns zero.

6. tolower():
It is used to convert the alphabet into lower case

7. toupper():
It is used to convert the alphabet into upper case

B. String functions:

1. strcpy():
This function is used to copy one string into another

2. strcat():
This function is used to concatenate(join) second string into first string

3. strlen():
This function is used to find the length of a string.

4. strcmp():
This function is used to compare 2 strings. If the first string is less than second string then it returns a negative value. If the first string is equal to the second string then it returns a value zero and if the first string is greater than the second string then it returns a positive value.

Question 2.
Write functions to perform the following operations

1. sqrt()
2. power of 2 numbers
3. sin
4. cos

Answer:

Question 3.
Write a C++ program to display the roots of quadratic equation. (SAY-2015) (5)
Answer:
#include<iostream>
#include<cmath>

Question 4.
Explain ‘Call by Value’ and ‘Call by Reference’ methods of function calling with the help of a suitable example. (SAY-2016)
Answer:
Two types are call by value and call by reference.
1. Call by value:
In call by value method the copy of the original value is passed to the function, if the function makes any change will not affect the original value.
Example

2. Call by reference:
In call by reference method the address of the original value is passed to the function, if the function makes any change will affect the original value.
Example

Question 5.
Define network topology. Explain any four network topologies in detail. (SAY-2016)
Answer:
Network topologies:
Physical or logical arrangement of computers on a network is called structure or topology. It is the geometrical arrangement of computers in a network. The major topologies developed are star, bus, ring, tree and mesh

1. Star Topology:
A star topology has a server all other computers are connected to it. If computer A wants to transmit a message to computer B. Then computer A first transmit the message to the server then the server retransmits the message to the computer B.

That means all the messages are transmitted through the server. Advantages are add or remove workstations to a star network is easy and the failure of a workstation will not effect the other. The disadvantage is that if the server fails the entire network will fail.

2. Bus Topology:
Here all the computers are attached to a single cable called bus. Here one computer transmits all other computers listen. Therefore it is called broadcast bus. The transmission from any station will travel in both the direction. The connected computers can hear the message and check whether it is for them or not.

Advantages are add or remove computer is very easy. It requires less cable length and the installation cost is less. Disadvantage is fault detection is very difficult because of no central computer.

3. Ring Topology:
Here all the computers are connected in the shape of a ring and it is a closed loop. Here also there is no central computer. Here a computer transmits a message, which is tagged along with its destination computer’s address. The message travels in one direction and each node check

whether the message is for them. If not, it passes to the next node. FIt requires only short cable length. If a single node fails, at least a portion of the network will fail. To add a node is very difficult.

4. Hybrid Topology:
It is a combination of any two or more network topologies. Tree topology and mesh topology can be considered as hybrid topology.
(a) Tree Topology:
The structure of a tree topology is the shape of an inverted tree with a central node and branches as nodes. It is a variation of bus topology. The data transmission takes place in the way as in bus topology. The disadvantage is that if one node fails, the entire portion will fail.

(b) Mesh Topology:
In this topology each node is connected to more than one node. It is just like a mesh (net). There are multiple paths between computers. If one path fails, we can transmit data through another path.

Students can Download Chapter 9 String Handling and I/O Functions Questions and Answers, Plus One Computer Science Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus One Computer Science Chapter Wise Questions and Answers Chapter 9 String Handling and I/O Functions

Plus One String Handling and I/O Functions One Mark Questions and Answers

Question 1.
To read a single character for gender i.e. ‘m’ or ‘f’ ________ function is used.
Answer:
(a) getch()
(b) getchar()
(c) gets()
(d) getline()
Answer:
(b) getchar()

Question 2.
To use getchar(), putchar(), gets() and puts(), which header file is used?
(a) iostream
(b) cstdio
(c) input
(d) output
Answer:
(b) cstdio

Question 3.
To use cin and cout, which header file is needed?
(a) iostream
(b) cstdio
(c) input
(d) output
Answer:
(a) iostream

Question 4.
Predict the output of the following code snippet.
#include<cstdio>
int mainO
{
char name[ ] = “ADELINE”;
for(int i=0; name[i]!=’\0′;i++)
putchar(name[i]);
}
Answer:
The output is “ADELINE”.

Question 5.
From the following which is equivalent to the function getc(stdin).
(a) putchar()
(b) gets()
(c) getchar()
(d) puts()
Answer:
(c) getchar()

Question 6.
From the following which is equivalent to the function putc(ch, stdout).
(a) putchar(ch)
(b) ch = gets()
(c) ch = getchar()
(d) puts(ch )
Answer:
(a) putchar(ch)

Question 7.
To print a single character at a time which function is used?
(a) puts()
(b) putchar()
(c) gets()
(d) getchar()
Answer:
(b) putchar()

Question 8.
To read a string _______ function is used.
(a) puts()
(b) putchar()
(c) gets()
(d) getchar()
Answer:
(b) gets()

Question 9.
To print a string _______ function is used.
(a) puts()
(b) putchar()
(c) gets()
(d) getchar()
Answer:
(b) puts()

Question 10.
Consider the following code snippet.
main()
{
char str[80];
gets(str);
for(int i=0. len=0;str[il!=’\0′;i++.len++);
cout<<“The length of the string is ” <<len;
}
Select the equivalent forthe under lined statement from the following
(a) int len = strlen(str)
(b) int len = strcmp(str)
(c) int len = strcount(str)
(d) None of these
Answer:
(a) int len = strlen(str)

Question 11.
Arjun wants to read a string with spaces from the following which is suitable.
(а) cin>>
(b) cin.getline(str,80)
(c) str = getc(stdin)
(d) none of these
Answer:
(b) cin.getline(str,80)

Question 12.
State whether the following statement is true or false. The ‘<<‘ insertion operator stops reading a string when it encounters a space.
Answer:
True

Question 13.
_________ function is used to copy a string to another variable. (SAY-2016) (1)
Answer:
strcpy();

Question 14.

1. Write the declaration statement for a variable ‘name’ in C++ to store a string of maximum length 30.
2. Differentiate between the statement cin>>name and gets (name) for reading data to the variable ‘name’. (SAY-2016)

Answer:
1. char name[31];(One for null(\0) character).

OR

cin>> does not allows space. It will take characters up to the space and characters after space will be truncated . Here space is the delimiter. Consider the following code snippet that will take the input upto the space.
#include<iostream>
using namespace std;
int main()
{
char name[20];
cout<<“Enter your name:”;
cin>>name;
cout<<“Hello “<<name;
}
If you input a name “Alvis Emerin” then the output will be Hello Alvis. The string after space is truncated.

2. gets(): This function is used to get a string from the keyboard including spaces. Considerthe following code snippet that will take the input including the space.
#include<iostream>
#include<cstdio>
using namespace std;
int main()
{
char name[20];
cout<<“Enter your name:”;
gets(name);
cout<<“Hello “<<name;
}
If you input a name “Alvis Emerin” then the output will be Hello Alvis Emerin.

Question 15.
What is the advantage of using gets() function in the C++ program to input string data? Explain with an example.
Answer:
gets() function is used to get a string from the keyboard including spaces. Consider the following code snippet that will take the input including the space.
#include<iostream>
#include<cstdio>
using namespace std;
int main()
{
char name[20];
cout<<“Enter your name:”;
gets(name);
cout<<“Hello “<<name;
}
If you input a name “Alvis” then the output is Hello Alvis.

Plus One String Handling and I/O Functions Two Mark Questions and Answers

Question 1.
In a C++ program, you forgot to include the header file iostream. What are the possible errors occur in that Program? Explain?
Answer:
Prototype error. To use cin and cout the header file iostream is a must.

Question 2.
Categorise the following into three according to their relationship
iostream, cstdio, gets(), puts(), getchar(), putchar(), getline(), write(), cin, cout.
Answer:

Question 3.
Pick the odd one out from the following and give reason.
gets(), getline(), getch() getchar().
Answer:
getline() – It is a stream function whereas the others are console functions.

Question 4.
My_name is a variable contains a string. Write two different C++ statements to display the string. (SAY-2016) (2)
Answer:

1. cout<<my_name;
2. puts(my_name);

Question 5.
Suggest most suitable built-in function in C++ to perform the following tasks: (MARCH-2016) (2)

1. To find the answer for 53
2. To find the number of characters in the string “KERALA” “HAPPY NEW YEAR”
3. To get back the number 10 if the argument is 100.

Answer:

1. pow(5,3);
2. strlen(“KERALA”)
3. tolower(‘M’)
4. sqrt(100);

Question 6.
Read the following C++ statements:
charstr[50];
cin>>str;
cout<<str;
During execution, if the string given as input is “GREEN COMPUTING”, the output will be only the word “GREEN”. Give reason for this. What modification is required to get the original string as output? (SCERT SAMPLE -1) (2)
Answer:
cin>>word;
cout<<word;
It displays “HAPPY” because cin takes characters upto the space. That is space is the delimiter for cin. The string after space is truncated. To resolve this use gets() function.

Because gets() function reads character upto the enter key.
Hence gets(word);
puts(word);
Displays “HAPPY NEW YEAR”

Question 7.
Suppose M[5][5] is a 2D array that contains the elements of a square matrix. Write C++ statements to find the sum of the diagonal elements. (2)
Answer:
gets() function is used to get a string from the keyboard including spaces. To use gets () function the header file cstdio must be included. It reads the characters upto the enter key pressed by the user.
eg:
char name[20];
cout << “Enter your name”;
gets(name);
cout<< “Hello”<< name;
When the user gives Alvis Emerin. It displays as “Hello Alvis Emerin”.

Plus One String Handling and I/O Functions Three Mark Questions and Answers

Question 1.
Suresh wants to print his name and native place using a C++ program. The program should accept name and native place first.
Name is: Suresh Kumar
Address is: Alappuzha
Answer:
#include<iostream>
#include<cstdio>
using namespace std;
int main()
{
char name[20],place[20];
cout<<“Enter your name”;
cin.getline(name,80);
cout<<“Enter your place”;
cin.getline(place,80);
cout<<“Your name is puts(name);
cout<<“Your place is puts(place);
}

Question 2.
“Programming is Fun”. Write a C++ program to read a string like this in lower case and print it in UPPER CASE. With out using toupper() library function.
Answer:
using namespace std;
#include<cstdio>
int main()
{
char line[80];
int i;
puts(Enter the string to convert”);
gets(line);
for(i=0;line[i]!=’\0′;i++)
if (Iine[i]>=97 && line[i]<=122)
line[i]=line[i] – 32;
puts(line);
}

Question 3.
An assignment Kumar has written a C++ program which reads a line of text and print the number of vowels in it. What will be his program code?
Answer:
#include<cstdio>
#include<cctype>
#include<iostream>
using namespace std;
int main()
{
char line[80];
int i,vowel=0;
puts(Enter a string”);
gets(line);
for(i=0;line[i]!=’\0′;i++)
switch(tolower(line[i]))
{
case ‘a’:
case ‘e’:
case ‘i’:
case ‘o’:
case ‘u’:
vowel++;
}
cout<<“The number of vowels is “<<vowel;

Question 4.
What will be the output of the following code if the user enter the value “GOOD MORNING”.
1. char string [80];
gets(string);
cout<<string;

2. char string [80];
cin>>string;
cout<<string;

3. charch;
ch = getchar();
cout<<ch;

4. char string [80];
cin.getline(string,9);
cout<<string;
Answer:

1. GOOD MORNING
2. GOOD
3. G
4. GOOD MORN

Question 5.
Consider the following code snippet.
int main()
{
int n;
cout<<“Enter a number”;
cin>>n;
cout<<“The number is “<<n;
}
Write down the names of the header files that must be included in this program
Answer:
Here cin and cout are used so the header file iostream must be included.

Question 6.
Write a program to display the following output.
A
BB
CCC
#include<iostream>
using namespace std;
int main()
{
char str[]=”ABC”;
int i,j;
for(i=0;i<3;i++)
{
for(j=0;j<=i;j++)
cout<<str[i];
cout<<endl;
}
}

Question 7.
Distinguish getchar and gets.
Answer:
getchar is a character function but gets is a string function. The header file cstdio.h must be included. It reads a character from the keyboard.
Eg.
char ch;
ch = getchar();
cout<<ch;
gets is used to read a string from the keyboard. It reads the characters upto enter key. The header file cstdio must be included.
char str[80J;
cout<<“Enter a string”;
gets(str);

Question 8.
Distinguish putch and puts.
Answer:
putch is a character function but puts is a string function. The header file cstdio must be included. It prints a character to the monitor.
Eg:
char ch;
ch = getc(stdin);
putch(ch);
puts is used to print a string. The header file stdio.h must be included.
charstr[80];
puts(“Entera string”);
gets(str);
puts(str);

Question 9.
Write a program to check whether a string is palindrome or not. (A string is said to be palindrome if it is the same as the string constituted by reversing the characters of the original string. eg: “MALAYALAM”, “MADAM”, “ARORA”, “DAD”, etc.)
Answer:
#include<iostream>
using namespace std;
int main()
{
char str[40];
int len,i,j;
cout<<“Enter a string:”;
cin>>str;
for(len=0;str[len]!-\0′;len++);
for(i=0,j=len-1;i<len/2;i++,j–)
if(str[i]!=str[j])
break;
if(i==len/2) .
cout<<str<<” is palindrome”;
else
cout<<str<<” is not palindrome”;
}

Question 10.
Explain multi-character function.
Answer:
getline() and write() functions are multi character functions:
1. getline() It reads a line of text that ends with a newline character. It reads white spaces also.
eg:
char line[80];
cin.getline(line,80);

2. write() It is used to display a string.
Eg.
char line[80];
cin.getline(line,80);
cout.write(line,80);

Question 11.
Read a string and print the number of vowels.
Answer:
#include<cstdio>
#include<cctype>
#include<iostream>
using namespace std;
int main()
{
char line[80];
int i,vowel=0;
puts(“Enter a string”);
gets(line);
for(i=0;line[i]!=’\0′;i++)
switch(tolower(line[i]))
{
case ‘a’:
case ‘e’:
case ‘i’;
case ‘o’:
case ‘u’:
vowel++;
}
cout<<“The number of vowels is in the string is “<< vowel;
}

Question 12.
Distinguish between get() and put() functions.
Answer:
get() function:
get() is an input function. It is used to read a single character and it does not ignore the white spaces and newline character.
Syntax is cin.get(variable);
eg: char ch;
cin.get(ch);

put() function:
put() is an output function. It is used to print a character.
Syntax is cout.put(variable);
eg:
charch;
cin.get(ch);
cout.put(ch);

Question 13.
Write a program to read a string and print the number of consonants.
Answer:
#include<iostream>
#include<cstdio>
#include<cctype>
using namespace std;
int main()
{
char str[40],ch;
int consonent = 0,i;
cout<<“Enter a string:”;
gets(str);
for(i=0;str[i]!=’\0′;i++)
{
ch = toupper(str[i]);
if(ch>=’B’ && ch<=’Z’)
if(ch!=’E’&& ch!=’I’&& ch!=’0’&& ch!=’U’)
consonent++;
}
cout<<“The number of consonents is “<<consonent;
}

Question 14.
Write a program to read a string and print the number of spaces.
Answer:
#include<iostream>
#include<cstdio>
using namespace std;
int main()
{
char str[40];
int space=0,i;
cout<<“Enter a string:”;
gets(str);
for(i=0;str[i]!=’\0′;i++)
if(str[i]==32)
space++;
cout<<“The number of spaces is “<<space;
}

Question 15.
Describe in detail about the unformatted console I/O functions.
Answer:
1. Single character functions: This function is used to read or print a character at a time,
(i) getchar():
It reads a character from the keyboard and store it in a character variable.
eg:
char ch;
ch=getchar();

(ii) putchar():
This function is used to print a character on the screen.
eg:
char ch;
ch = getchar();
putchar(ch);

2. String functions This function is used to read or print a string.
(i) gets():
This function is used to read a string from the keyboard and store it in a character variable.
eg:
charstr[80];
gets(str);

(ii) puts():
This function is used to display a string on the screen.
eg:
char str[80];
gets(str);
puts(str);

Question 16.
Write a program to input a string and find the number of uppercase letters, lowercase letters, digits, special characters and white spaces.
Answer:
#include<iostream>
#include<cstdio>
using namespace std;
int main()
{
char str[100];
int i,digit=0, Ualpha=0, Lalpha=0, special=0, wspace=0;
cout<<“Enter a string:”;
gets(str);
for(i=0;str[i]!=’\0′;i++)
if(str[i]>=48 && str[i]<=57)
digit++;
else if(str[i]>=65 && str[i]<=90)
Ualpha++;
else if(str[i]>=97 && str[i]<=122)
Lalpha++;
else if(str[i]==’ ‘ || str[i]==’\t’)
wspace++;
else
special++;
cout<<“The number of alphabets is “<<Ualpha+Lalpha<<
” the number of Uppercase letters is “<<Ualpha<< ” the number of Lowercase letters is “<<Lalpha<<” the number of digits is “<<digit<<” the special characters is “<<special<<” and the number of white spaces is “<<wspace;
}

Question 17.
Write a program to count the number of words in a sentence.
Answer:
#include<iostream>
#include<cstdio>
using namespace std;
int main()
{
int i,words=1;
char str[80];
cout<<“Enter a string\n”;
gets(str);
for(i=0;str[i]!=’\0′;i++)
if(str[i]==32)
words++;
cout<<“The number of words is “<<words;
}

Question 18.
Write a program to input a string and replace all lowercase vowels by the corresponding uppercase letters.
Answer:
#include<iostream>
#include<cstdio>
using namespace std;
int main()
{
char str[100];
int i;
cout<<“Enter a string:”;
gets(str);
for(i=0;str[i]!=\0′;i++)
if(str[i]>=65 && str[i]<=90 || str[i]> = 97 && str[i]<=122)
switch(str[i])
{
case ‘a’:
str[i] = str[i]-32;
break;
case ‘e’:
str[i] = str[i]-32;
break;
case ‘i’:
str[i] = str[i]-32;
break;
case ‘o’: .
str[i] = str[i]-32;
break;
case ‘u’:
str[i] = str[i]-32;
}
cout<<str;
}

Question 19.
Write a program to input a string and display its reversed string using console I/O functions only. For example if the input is “AND” the output should “DNA”.
Answer:
#include<iostream>
using namespace std;
int main()
{
char str[40],rev[40];
int len.ij;
cout<<“Enter a string:”;
cin>>str;
for(len=0;str[len]!=’\0′;len++);
for(i=0,j=len-1 ;i<len;i++,j–)
rev[il=str[j];
rev[i]=’\0′;
cout<<“The reversed string is “<<rev;
}

Question 20.
Write a program to input a word(say COMPUTER) and create a triangle as follows.
C
C O
C O M
C O M P
C O M P U
C O M P U T
C O M P U T E
C O M P U T E R
Answer:
#include<iostream>
#include<cstring>//for strlen()
using namespace std;
int main()
{
charstr[20];
cout<<“enter a word(eg.COMPUTER):”;
cin>>str;
int ij;
for(i=0;i<strlen(str);i++)
{
for(j=0;j<=i;j++)
cout<<str[j]<<“\t”;
cout<<endl;
}
}

Question 21.
Write a program to input a line of text and display the first characters of each word. Use only console I/O functions. For example, if the input is “Save Water, save Nature”, the output should be “SWSN”.
Answer:
#include<iostream>
#include<cstdio>
using namespace std;
int main()
{
int i;
charstr[80];
cout<<“Enter a string\n”;
gets(str);
if(str[0]!=32)
cout<<str[0];
for(i=0;str[i]!=’\0′;i++)
if(str[i]==32 && str[i+1]!=32)
cout<<str[i+1];
}

Students can Download Chapter 6 Data Types and Operators Questions and Answers, Plus One Computer Science Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus One Computer Science Chapter Wise Questions and Answers Chapter 6 Data Types and Operators

Plus One Data Types and Operators One Mark Questions and Answers

Question 1.
___________ is the main activity carried out in computers.
Answer:
Data processing

Question 2.
The data used in computers are different. To differentiate the nature and size of data ___________ is used.
Answer:
Data types

Question 3.
Classify the following data types,
int, array, function, char, pointer, void, float, double, structure
Answer:

Question 4.
Sheela wants to store her age. From the following which is the exact data type.
(a) void
(b) char
(c) int
(d) double
Answer:
(c) int

Question 5
Integer data type uses ________ bytes of memory.
(a) 5
(b) 2
(c) 3
(d) 4
Answer:
(d) 4

Question 6.
char data type ________uses bytes of memory.
(a) 1
(b) 3
(c) 7
(d) 8
Answer:
(a) 1

Question 7.
From the following which data type uses 4 bytes of memory.
(a) float
(b) short
(c) char
(d) double
Answer:
(a) float

Question 8.
Full form of ASCII is ___________
Answer:
American Standard Code for Information Interchange

Question 9.
Ramu wants to store the value of From the following which is correct declaration.
(a) char pi = 3.14157
(b) int pi = 3.14157
(c) float pi = 3.14157
(d) long pi = 3.14157
Answer:
(c) float pi = 3.14157

Question 10.
From the following which is not true, to give a variable name.
(a) Starting letter must be an alphabet
(b) contains digits
(c) Cannot be a keyword
(d) special characters can be used
Answer:
(d) special characters can be used

Question 11.
Pick a valid variable name from the following.
(а) 9a
(b) float
(c) age
(d) date of birth
Answer:
(c) age.

Question 12.
To perform a unary operation how many number of operands needed?
(a) 2
(b) 3
(c) 1
(d) None of these.
Answer:
(c) 1 (Unary means one)

Question 13.
To perform a binary operation how many number of operands needed?
(а) 2
(b) 3
(c) 1
(d) None of these.
Answer:
(a) 2 (binary means two)

Question 14.
To perform a ternary operation how many number of operands needed?
(a) 2
(b) 3
(c) 1
(d) None of these.
Answer:
(b) 3 (eg: ternary means three)

Question 15.
In C++ 13 % 26 =
(a) 26
(b) 13
(c) 0
(d) None of these
Answer:
(b) % is a mod operator i.e. it gives the remainder. Here the remainder is 13.

Question 16.
In C++ 41/2 =
(a) 20.5
(b) 20
(c) 1
(d) None of these
Answer:
(b) 20. (The actual result is 20.5 but both 41 and 2 are integers so .5 must be truncated)

Question 17.
++ is a __________ operator.
(a) Unary
(b) Binary
(c) Ternary
(d) None of these
Answer:
(a) Unary.

Question 18.
Conditional operator is _________ operator.
(a) Unary
(b) Binary
(c) Ternary
(d) None of these
Answer:
(c) Ternary

Question 19.
% is a _______ operator
(a) Unary
(b) Binary
(c) Ternary
(d) None of these
Answer:
(b) Binary

Question 20.
State True/False

1. Multiplication, division, modulus have equal priority
2. Logical and (&&) has less priority than logical or ()

Answer:

1. True
2. False

Question 21.
_______is composed of operators and operands.
(a) expression
(b) Keywords
(c) Identifier
(d) Punctuators
Answer:
(a) expression

Question 22.
Supply value to a variable at the time of declaration is known as __________.
Answer:
Initialisation

Question 23.
From the following which is initialisation.
(a) int k;
(b) int k = 100;
(c) int k[10];
(d) None of these
Answer:
(b) int k = 100;

Question 24.
State True/False
In an expression all the operands having lower size are converted(promoted) to the data type of the highest sized operand.
Answer:
True

Question 25.
Classify the following as arithmetic/Logical expression.
(a) x + y * z
(b) x < y && y > z
(c) x / y
(d) x > 89 || y < 80
Answer:
(a) and (c) are Arithmetic, (b) and (d) are Logical

Question 26.
Suppose x = 5 and y = 2 then what will be cout<<(float)x/y
Answer:
2.5 The integer x is converted to float hence the result.

Question 27.
Consider the following.
a = 10;
a* =10;
Then a =
(a) a = 100
(b) a = 50
(c) a = 10
(d) a = 20
Answer:
(a) a = 100. This short hand means a = a*10

Question 28.
Consider the following.
a = 10;
a+ = 10;
Then a =
(a) a = 30
(b) a = 50
(c) a = 10
(d) a = 20
Answer:
(d) a = 20. This short hand means a = a + 10

Question 29.
Pick the odd one out
(a) structure
(b) Array
(c) Pointer
(d) int
Answer:
(d) int, it is fundamental data type the others are derived data types

Question 30.
From the following select not a character of C++ language
(a) A
(b) 9
(c) \
(d) @
Answer:
(d) @

Question 31.
Consider the following
float x = 25.56;
cout<<(int)x;
Here the data type of the variable is converted. What type of conversion is this?
(a) type promotion
(b) type casting
(c) implicit conversion
(d) None of these
Answer:
(b) type casting (explicit conversion);

Question 32.
Identify the error in the following C++ statement and correct it.
short population = 68000;
Answer:
The maximum number that can store in short type is less than 32767. So to store 68000 we have to use long data type.

Question 33.
Consider the following statements in C++ if(mark>=18)
cout<<“Passed”;
else
cout<<“Failed”;
Suggest an operator in C++ using which the same output can be produced.
Answer:
Conditional operator (?:)

Plus One Data Types and Operators Two Mark Questions and Answers

Question 1.
Analyses the following statements and write True or False. Justify

1. There is an Operator in C++ having no special character in it
2. An operator cannot have more than 2 operands
3. Comma operator has the lowest precedence
4. All logical operators are binary in nature
5. It is not possible to assign the constant 5 to 10 different variables using a single C++ expression
6. In type promotion the operands with lower data type will be converted to the highest data type in expression.

Answer:

1. True (sizeof operator)
2. False(conditional operator can have 3 operands)
3. True
4. False
5. False(Multiple assignment is possible)
   eg: a = b = c ==5
6. True

Question 2.
Consider the following declaration.
const int bp;
bp = 100;
Is it valid? Explain it?
Answer:
This is not valid. This is an error. A constant variable cannot be modified. That is the error and a constant variable must be initialised. So the correct declaration is as follows, const int bp = 100;

Question 3.
Consider the following statements in C++

1. cout<<41/2;
2. cout<<41/2.0;

Are this two statements give same result? Explain?
Answer:
This two statements do not give same results. The first statement 41/2 gives 20 instead of 20.5. The reason is 41 and 2 are integers. If two operands are integers the result must be integer, the real part must be truncated.

To get floating result either one of the operand must be float. So the second statement gives 20.5. The reason 41 is integer but 2.0 is a float.

Question 4.
If mark = 70 then what will be the value of variable result in the following
result = mark > 50? ’P’: ’F’;
Answer:
The syntax of the conditional operator is given below
Condition ? Value if true : Value if false;
Here the conditional operator first checks the condition i.e., 70 > 50 it is true. So ’P’ is assigned to the variable result.
So the result is ’P’;

Question 5.
Is it possible to initialise a variable at the time of execution. What kind of initialisation is this? Give an example
Answer:
Yes it is possible. This is known as Dynamic initialisation. The example is given below
eg: int a = 10, b = 5; int c = a*b; here the variable c is declared and initialised with the value 10*5.

Question 6.
Boolean data type is used to store True/False in C++. Is it true? Is there any data type called Boolean in C++?
Answer:
No there is no data type for storing boolean value true/false. But in C++ non -zero (either negative or positive) is treated as true and zero is treated as false

Question 7.
Consider the following
n=-15;
if (n)
cout<<“Hello”;
else
cout<<“hai”;
What will be the output of the above code?
Answer:
The output is Hello, because n = -15 a non zero number and it is treated as true hence the result.

Question 8.
Is it possible to declare a variable in between the program as and when the need arise? Then what is it?
Answer:
Yes it is possible to declare a variable in between the program as and when the need arise. It is known as dynamic initialisation.
eg. int x = 10, y = 20;
int z = x*y;

Question 9.
char ch;
cout<<“Enter a character”;
cin>>ch;
Consider the above code, a user gives 9 to the variable ‘ch’. Is there any problem? Is it valid?
Answer:
There is no problem and it is valid since 9 is a character. Any symbol from the key board is treated as a character.

Question 10.
“With the same size we can change the sign and range of data”. Comment on this statement.
Answer:
With the help of type modifiers we can change the sign and range of data with same size. The important modifiers are signed, unsigned, long and short.

Question 11.
Write short notes about C++ short hands?
Answer:
x = x + 10 can be represented as x + = 10, It is called shorthands in C++. It is faster. This is used with all the arithmetic operators as follows.

Question 12.
What is the role of ‘const’ modifier?
Answer:
This ‘const’ keyword is used to declare a constant.
eg: const int bp=100;
By this the variable bp is treated as constant and cannot be possible to change its value during execution.

Question 13.
Specify the most appropriate data type for handling the following data.

1. Roll no. of a student.
2. Name of an employee.
3. Price of an article.
4. Marks of 12 subjects

Answer:

1. short Roll no;
2. char name[20];
3. float price;
4. short marks[12];

Question 14.
Write C++ statement for the following,

1. The result obtained when 5 is divided by 2.
2. The remainder obtained when 5 is divided by 2.

Answer:

1. 5/2
2. 5 % 2

Question 15.
Predict the output of the following code. Justify.
int k = 5;
b = 0;
b = k++ + ++k;
cout<<b;
Answer:
Output is 12. In this statement first it take the value of k in 5 then increment it K++. So first operand for + is 5. Then it becomes 6. Then ++k makes it 7. This is the second operand. Hence the result is 12.

Question 16.
Predict the output.
1. int sum = 10, ctr = 5;
sum = sum + ctr–;
cout<<sum;

2. int sum = 10, ctr = 5;
sum = sum + ++ctr;
cout<<sum;
Answer:

1. 15
2. 16

Question 17.
Predict the output.
int a;
float b;
a = 5;
cout<<sizeof(a + b/2);
Answer:
Output is 4. Result will be the memory size of floating point number

Question 18.
Predict the output.
int a, b, c;
a = 5;
b = 2;
c = a/b;
cout<<c;
Answer:
Output is 2. Both operands are integers. So the result will be an integer

Question 19.
Explain cascading of i/o operations
Answer:
The multiple use of input or output operators in a single statement is called cascading of i/o operators.
eg: To take three numbers by using one statement is as follows
cin>>x>y>>z;
To print three numbers by using one statement is as follows
cout<<x<<y<<z;

Question 20.
Trace out and correct the errors in the following code fragments

1. cout<<“Mark =”45;
2. cin<<“Hellow World!”;
3. cout>>”X + Y;
4. Cout<<‘Good,<<‘Morning’

Answer:

1. cout<<“Mark = 45”;
2. cout<<“Hellow World!”;
3. cout<<X + Y;
4. Cout<<“Good Morning”;

Question 21.
Raju wants to add value 1 to the variable ‘p’ and store the new value in ‘p’ itself. Write four different statements in C++ to do the task.
Answer:

1. P=P+1;
2. p++;(post increment)
3. ++p;(pre increment)
4. p+=1;(short hand in C++)

Question 22.
Read the following code
char str [30];
cin>>str;
cout<<str;
If we give the input “Green Computing”, we get the output “Green”. Why is it so? How can you correct that? (2)
Answer:
The input statement cin>> cannot read the space. It reads the text up to the space, i.e. the delimiter is space. To read the text up to the enter key gets() or getline() is used.

Question 23.

Answer:

Question 24.
Write a C++ expression to. calculate the value of the following equation.

Answer:
x = (-b + sqrt(b*b – 4*a*c)/(2*a)

Question 25.
A student wants to insert his name and school address in the C++ program that he has written. But this should not affect the compilation or execution of the program. How is it possible? Give an example.
Answer:
He can use comments to write this information. In C++ comments are used to write information such as programmer’s name, address, objective of the codes etc. in between the actual codes. This is not the part of the programme. There are two types of comments

1. Single line (//) and
2. Multi-line (/* and *f)

1. Single line (if):
Comment is used to make a single line as a comment. It starts with //.
eg: /./programme starts here.

2. Multi-line (/* and */):
To make multiple lines as a comment. It starts with /* and ends with */.
Eg: /* this programme is used to find sum of two numbers */

Question 26.
Consider the following C++ statements:
char word [20];
cin>>word;
cout<<word;
gets(word);
puts(word);
If the string entered is “HAPPY NEW YEAR”, predict the output and jsutify your answer.
Answer:
cin>>word;
cout<<word;
It displays “HAPPY” because cin takes characters upto the space. That is space is the delimiter for cin. The string after space is truncated. To resolve this use gets () function. Because gets () function reads character upto the enter key.
Hence
gets(word);
puts(word);
Displays “HAPPY NEW YEAR”

Question 27.
Write the difference between x = 5 and x == 5 in C++.
Answer:
x = 5 means the value 5 of the RHS is assigned to the LHS variable x . Here = is the assignment operator. But x == 5, == this is the relational (comparison) operator. Here it checks whether the value of RHS is equal to the value of LHS and this expression returns a boolean value as a result. It is the equality operation.

Question 28.
1. What is the output of the following program?
# include <iostream.h>
void main ()
{
int a;
a = 5 + 3*5;
cout << a;
}

2. How do 9, ‘9’ and “9” differ in C++ program?
Answer:
Here multiplication operation has more priority than addition.
hence
1. a = 5 + 15 = 20

2. Here 9 is an interger
‘9’ is a character
“9” is a string

Question 29.
Read the following C++ program and predict the output by explaining the operations performed.
#include<iostream.h>
void main ()
{
int a = 5, b = 3;
cout<<a++ /–b;
cout<<a/ (float) b;
}
Answer:
Here a = 5 and b = 3
a++ /– b = 5/2 = 2
That is a++ uses the value 5 and next it changes its value to 6
So a/(float) b = 6/(float)2
= 6/2.0
= 3
So the output is 2 and 3

Question 30.
What is the preprocessor directive statement? Explain with an example.
Answer:
A C++ program starts with the preprocessor directive i.e., # include, #define, #undef, etc, are such a preprocessor directives. By using #include we can link the header files that are needed to use the functions. By using #define we can define some constants.
eg. #define x 100. Here the value of x becomes 100 and cannot be changed in the program. No semicolon is needed.

Question 31.
The following C++ code segment is a part of a program written by Smitha to find the average of 3 numbers.
int a, b, c;
float avg;
cin>>a>>b>>c;
avg = (a + b + c)/3;
cout<<avg; .
What will be the output if she inputs 1, 4 and 5? How can you correct it?
Answer:
= (1 + 4 + 5)/3
= 10/3
= 3.3333
Instead of this 3.3333 the output will be 3. This is because if both operands are integers an integer division will be occurred, that is the fractional part will be truncated. To get the correct output do as follows
case 1: int a,b,c; is replaced by float a,b,c;

OR

case 2: Replace (a + b + c)/3 by (a + b + c)/3.0;

OR

case 3: Type casting.
Replace avg = (a + b + c)/3;
by avg = (float)(a + b + c)/3;

Plus One Data Types and Operators Three Mark Questions and Answers

Question 1.
In a panchayath or municipality all the houses have a house number, house name and members. Similar situation is in the case of memory. Explain
Answer:
The named memory locations are called variable. A variable has three important things

1. variable name: A variable should have a name
2. Memory address: Each and every byte of memory has an address. It is also called location (L) value
3. Content: The value stored in a variable is called content.lt is also called Read(R) value.

Question 2.
Briefly explain constants.
Answer:
A constant or a literal is a data item its value doe not change during execution. The keyword const is used to declare a constant. Its declaration is as follows
const data type variable name = value;
eg.const int bp = 100;
\const float pi = 3.14157;
const char ch = ‘a’;
const char[]=”Alvis”;

1. Integer literals:
Whole numbers without fractional parts are known as integer literals, its value does not change during execution. There are 3 types decimal, octal and hexadecimal.
eg: For decimal 100, 150, etc.
For octal 0100, 0240, etc.
For hexadecimal 0x100, 0x1A, etc.

2. Float literals:
A number with fractional parts and its value does not change during execution is called floating point literals.
eg: 3.14157, 79.78, etc

3. Character literal:
A valid C++ character enclosed in single quotes, its value does not change during execution.
eg: ‘m’, ‘f, etc.

4. String literal:
One or more characters enclosed in double quotes is called string constant. A string is automatically appended by a null character(‘\0’)
eg: “Mary’s”, “India”, etc.

Question 3.
Consider the following statements
int a = 10, x = 20;
float b = 45000.34, y = 56.78;
1. a = b;
2. y = x;
Is there any problem for the above statements? What do you mean by type compatibility?
Answer:
Assignment operator is used to assign the value of RHS to LHS. Following are the two chances
(a) The size of RHS is less than LHS. So there is no problem and RHS data type is promoted to LHS. Here it is compatible.

(b) The size of RHS is higher than LHS. Here comes the problem sometimes LHS cannot possible to assign RHS. There may be a chance of wrong answer. Here it is not compatible.
Here
1. a = b; There is an error since the size of LHS is 2 but the size of RHS is 4.
2. y = x; There is no problem because the size of LHS is 4 and RHS is 2.

Question 4.
A company has decided to give incentives to their salesman as perthe sales. The criteria is given below.
If the total sales exceeds 10,000 the incentive is 10%

1. If the total sales >= 5,000 and total sales <10,000, the incentive is 6 %
2. If the total sales >= 1,000 and total sales <5,000, the incentive is 3 %

Write a C++ program to solve the above problem and print the incentive after accepting the total sales of a salesman. The program code should not make use of ‘if’ statement.
Answer:
#include<iostream>
using namespace std;
int mainO
{
float sales,incentive;
cout<<“enter the sales”;
cin>>sales;
incentive = (sales>10000 ? sales*.10: (sales > =5000 ? sales * .06 : (sales >= 1000 ? sales * -03: 0)));
cout<<“\nThe incentive is ” << incentive;
}

Question 5.
A C++ program code is given below to find the value of X using the expression
\(x=\frac{a^{2}+b^{2}}{2 a}\)
where a and b are variables

#include<iostream>
using namespace std;
int main()
{
int a;b;
float x
cout<<“Enter the values of a and b;
cin>a>b;
x = a*a + b*b/2*a;
cout>>x;
}
Predict the type of errors during compilation, execution and verification of the output. Also write the output of two sets of input values

1. a = 4, b = 8
2. a = 0, b = 2

Answer:
This program contains some errors and the correct program is as follows.
#include<iostream>
using namespace std;
int main()
{
int a,b;
float x; .
cout<<“Enterthe values of a and b”;
cin>>ab;
x=(a*a + b*b)/(2*a);
cout<<x;
}
The output is as follows

1. a = 4 and b = 8 then the output is 10
2. a = 0 and b = 2 then the output is an error divide by zero error(run time error)

Question 6.
A list of data items are given below
45, 8.432, M, 0.124,8 , 0, 8.1 × 1031, 1010, a, 0.00025, 9.2 × 10120, 0471,-846, 342.123E03

1. Categorise the given data under proper headings of fundamental data types in C++.
2. Explain the specific features of each data type. Also mention any other fundamental data type for which sample

data is not given
Answer:
1.

2. The specific features of each data type.
(i) int data type:
It is used to store whole numbers without fractional (decimal point) part. It can be either negative or positive. It con¬sumes 4 bytes (32 bits) of memory.i.e. 232 . numbers. That is 231 negative numbers and 231 positive numbers (0 is considered as +ve ) So a total of 232 numbers. We can store a number in between -231 to + 231-1.

(ii) char data type:
Any symbol from the keyboard, eg. ‘A’ , ‘?’, ‘9’,…. It consumes one byte( 8 bits) of memory. It is internally treated as integers, i.e. 28 = 256 characters. Each character is having a ASCII code, ‘a’ is having ASCII code 97 and zero is having ASCII code 48.

3. float data type:
It is used to store real numbers i.e. the numbers with decimal point. It uses 4 bytes(32 bits) of memory.
eg: 67.89, 89.9 E-15.

4. double data type:
It is used to store very large real numbers. It uses 8 bytes(64 bits) of memory.

5. void data type:
void means nothing. It is used to represent a function returns nothing.

Question 7.
Write valid reasons after reading the following statements in C++ and comment on their correctness by give reasons.

1. char num = 66;
   char num = B’;
2. 35 and 35L are different
3. The number 14, 016 and OxE are one and the same
4. Char data type is often said to be an integer type
5. To store the value 4.15 float data type is preferred over double

Answer:

1. The ASCII number of B is 66. So it is equivalent.
2. 35 is of integer type but 35L is Long
3. The decimal number 14 is represented in octal is 016 and in hexadecimal is OXE.
4. Internally char data type stores ASCII numbers.
5. To store the value 4.15 float data type is better because float requires only 4 bytes while double needs 8 bytes hence we can save the memory.

Question 8.
Suggest most suitable derived data types in C++ for storing the following data items or statements

1. Age of 50 students in a class
2. Address of a memory variable
3. A set of instructions to find out the factorial of a number
4. An alternate name of a previously defined variable.
5. Price of 100 products in a consumer store
6. Name of a student

Answer:

1. Integer array of size 50
2. Pointer variable
3. Function
4. Reference
5. Float array of size 100
6. Character array

Question 9.
Considering the following C++ statements. Fill up the blanks

1. If p = 5 and q = 3 then q%p is _______
2. If E1 is true and E2 is False then E1 && E2 will be _______
3. If k = 8, ++k < = 8 will be ________
4. If x = 2 then (10* ++x) % 7 will be ________
5. If t = 8 and m = (n=3,t-n), the value of m will be ______
6. If i = 12 the value i after execution of the expres¬sion i+ = i- – + – -i will be ______

Answer:

1. 3
2. False
3. False(++k makes k = 9. So 9<=8 is false)
4. 2(++x becomes 3 ,so 10 * 3 = 30%7 = 2)
5. 5( here m = (n = 3,8-3) = (n = 3,5), so m = 5, The maximum value will take)
6. Here i = 12

i + = i- – + – -i
here post decrement has more priority than pre decrement. So “i- -” will be evaluated first. Here first uses the value then change so it uses the value 12 and i becomes 11
i + = 12 + – -i
now i = 11.
Here the value of i will be changed and used so “i- -” becomes 10
i + = 12 + 10 = 22
So, i = 22 +10
i = 32
So the result is 32.

Question 10.
The Maths teacher gives the following problem to Riya and Raju.
x = 5 + 3 * 6.
Riya got x = 48 and Raju got x = 23. Who is right and why it is happened? Write down the operator precedence in detail?
Answer:
Here the answer is x = 23. It is because of precedence of operators. The order of precedence of operators are given below.

Here multiplication has more priority than addition

Question 11.
Explain the data types’ in C++. (3)
Answer:
Fundamental data types:
It is also called built-in data type. They are int, char, float, double and void
1. int data type:
It is used to store whole numbers without fractional (decimal point) part. It can be either negative or positive. It consumes 4 bytes (32 bits) of memory. i.e. 232 numbers. That is 231 negative numbers and 231 positive numbers (0 is considered as +ve) So a total of 232 numbers. We can store a number in between -231 to + 2311.

2. char data type Any symbol from the keyboard, eg. ‘A’,‘9’, …. It consumes one byte( 8 bits) of memory. It is internally treated as integers, i.e. 28 = 256 characters. Each character is having an ASCII code, ‘a’ is having ASCII code 97 and zero is having ASCII code 48.

3. float data type:
It is used to store real numbers i.e. the numbers with decimal point. It uses 4 bytes(32 bits) of memory.
eg: 67.89, 89.9 E-15.

4. double data type:
It is used to store very large real numbers. It uses 8 bytes(64 bits) of memory.

5. void data type:
Void means nothing. It is used to represent a function returns nothing.

• User defined Data types: C++ allows programmers to define their own data type. They are Structure(struct), enumeration (enum), union, class, etc.
• Derived data types: The data types derived from fundamental data types are called Derived data types. They are Arrays, pointers, functions, etc

Question 12.
Predict the output of the following C++ statements.
int a = -5, b = 3, c = 4;
C+ = a++ + –b;
cout<<a<<b<<c;
Answer:
a = -4, b = 2 and c = 1.

Question 13.
Match the following

Answer:

Question 14.
Write any five unary operators of C++. Why are they called so?
Answer:
A unary operator is an operator that need only one operand to perform the operation. The five unary operators of C++ are given below.
Unary +, Unary -, ++, – – and ! (not)

Question 15.
Write C++ examples for the following:

1. Declaration statement
2. Assignment statement
3. Type casting

Answer:

1. int age;
2. age = 16;
3. avg = (float)a + b + c/3;

Plus One Data Types and Operators Five Mark Questions and Answers

Question 1.

• Name: Jose
• Roil no: 20
• Age: 17
• Weight: 45.650

Consider the above data, we know that there are different types of data are used in the computer. Explain different data types used in C++.
Answer:
1. int data type:
It is used to store whole numbers without fractional (decimal point) part. It can be either negative or positive. It consumes 4 bytes (32 bits) of memory, i.e. 232 numbers. That is 231 negative numbers and 231 positive numbers (0 is considered as +ve) So a total of 232 numbers. We can store a number in between -231 to + 2311.

2. char data type:
Any symbol from the keyboard, eg. A’,’9′,…. It consumes one byte( 8 bits) of memory. It is internally treated as integers, i.e. 28 = 256 characters. Each character is having a ASCII code, ‘a’ is having ASCII code 97 and zero is having ASCII code 48.

3. float data type:
It is used to store real numbers i.e, the numbers with decimal point. It uses 4 bytes(32 bits) of memory.
eg: 67.89, 89.9 E-15.

4. double data type:
It is used to store very large real numbers. It uses 8 bytes(64 bits) of memory.

5. void data type:
void means nothing. It is used to represent a function returns nothing.

Question 2.
Define an operator and explain operator in detail.
Answer:
An operator is a symbol that performs an operation. The data on which operations are carried out are called operands. Following are the operators
1. lnput(>>) and output(<<):
These operators are used to perform input and output operation.
eg: cin>>n;
cout<<n;

2. Arithmetic operators:
It is a binary operator. It is used to perform addition(+), subtraction(-), division (/), multiplication (*) and modulus (%- gives the remainder) operations.
eg: If x = 10 and y = 3 then

x/y = 3, because both operands are integer. To get the floating point result one of the operand must be float.

3. Relational operator:
It is also a binary operator. It is used to perform comparison or relational operation between two values and it gives either true(1) or false(O). The operators are <,<=,>,>=,== (equality)and !=(not equal to)
eg: If x = 10 and y = 3 then

4. Logical operators:
Here AND(&&), OR(||) are binary operators and NOT(!) is a unary operator. It is used to combine relational operations and it gives either true(1) or false(O). If x=True and y=False then

Both operands must be true to get a true value in the case of AND(&&) operation If x = True and y = False then

Either one of the operands must be true to get a true value in the case of OR(||) operation If x = True and y = False then

5. Conditional operator:
It is a ternary operator hence it needs three operands. The operator is ?:
Syntax: expression ? value if true : value if false. First evaluates the expression if it is true the second part will be executed otherwise the third part will be executed.
eg: If x = 10 and y = 3 then x>y ? cout<<x : cout<<y;. Here the output is 10

6. sizeof():
This operator is used to find the size used by each data type.
eg. sizeof(int) gives 2.

7. Increment and decrement operator:
These are unary operators.
(a) Increment operator (++): It is used to incre¬ment the value of a variable by one i.e., x++ is equivalent to x = x + 1;
(b) Decrement operator (–): It is used to decre¬ment the value of a variable by one i.e., x-is equivalent to x = x – 1.

8. Assignment operator (=):
lt is used to assign the value of a right side to the left side variable.
eg: x = 5; Here the value 5 is assigned to the variable x.

Students can Download Chapter 5 Introduction to C++ Programming Questions and Answers, Plus One Computer Science Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus One Computer Science Chapter Wise Questions and Answers Chapter 5 Introduction to C++ Programming

Plus One Introduction to C++ Programming One Mark Questions and Answers

Question 1.
IDE means _____________
Answer:
Integrated Development Environment

Question 2.
We know that C++ is a high level language. From the following which statement is true.
(a) C++ contains English like statements.
(b) C++ contains mnemonics
(c) C++ contains only 0 and 1
(d) None of these
Answer:
(a) C++ contains English like statements.

Question 3.
C++ is a ______ language.
(a) High level
(b) Low level
(c) Middle level
(d) None of these
Answer:
(a) High level

Question 4.
C++ was developed at ___________
(a) AT & T Bell Laboratory
(b) Sanjose Laboratory
(c) Kansas University Lab
(d) None of these
Answer:
(a) AT & T Bell Laboratory

Question 5.
C++ is a successor of ___________ language
(a) C#
(b) C
(c) java
(d) None of these
Answer:
(b) C

Question 6.
The most adopted and popular approach to write programs is __________
Answer:
Structured programming

Question 7.
From the following which uses OOP concept
(a) C
(b) C++
(c) Pascal
(d) Fortran
Answer:
(b) C++

Question 8.
______________ is the smallest individual unit
Answer:
Token

Question 9
Pick the odd one out
(a) float
(b) void
(c) break
(d) Alvis
Answer:
(d) Alvis, the others are keywords.

Question 10.
Reserved words for the compiler is ____________
(a) Literals
(b) Identifier
(c) Keywords
(d) None of these
Answer:
(c) Keywords

Question 11.
Pick an identifier from the following
(а) auto
(b) age
(c) float
(d) double
Answer:
(b) age

Question 12.
Pick the invalid identifier
(a) name
(b) Date of birth
(c) age
(d) joining time
Answer:
(b) Date of birth, because it contains space.

Question 13.
Pick the octal integer from the following
(a) 217
(b) 0 X 217
(c) 0217
(d) None of these
Answer:
(c) 0217, an octal integer precedes 0

Question 14.
Pick the hexadecimal integer from the following
(a) 217
(b) 0 × 217
(c) 0217
(d) None of these
Answer:
(b) 0 × 217, a hexadecimal integer precedes 0×

Question 15.
From the following pick a character constant
(a) ‘A’
(b) ‘ALL’
(c) ‘AIM’
(d) None of these
Answer:
(a) ‘A’, a character enclosed between single quote

Question 16.
Non graphic symbol can be represented by using ___________
Answer:
Escape Sequence

Question 17.
Manish wants to write a program to produce a beep sound. Which escape sequence is used to get an alert (sound)
(a) \a
(b) \d
(c) Vs
(d) None of these
Answer:
(a) \a.

Question 18.
Ajo wants to print a matter in a new line. Which escape sequence is used for this?
(a) \a
(b) \n
(c) \s
(d) None of these
Answer:
(b) \n

Question 19.
To represent null character is used ______
(a) \n
(b) \0
(c) \f
(d) As
Answer:
(b) \0

Question 20.
State True/ False a string is automatically appended by a null character.
Answer:
True

Question 21.
From the following pick a string constant
(a) ‘a’
(b) “abc”
(c) ‘abc’
(d) None of these
Answer:
(b) “abc”, a character constant must be enclosed between double quotes.

Question 22.
C++ was developed by __________
(a) Bjarne Stroustrup
(b) James Gosling
(c) Pascal
(d) None of these
Answer:
(a) Bjarne stroustrup

Question 23.
From the following which is not a character constant.
(а) ‘c’
(b) ‘e’
(c) ‘d’
(d) “c”
Answer:
(d) “c”, It is a string constant the others are character constant.

Question 24.
From the following which is a valid declaration.
(a) int 91;
(b) int x;
(c) int 9x;
(d) int “x”;
Answer:
(b) int x;

Question 25.
Symbols used to perform an operation is called ____________
(a) Operand
(b) Operator
(c) Variable
(d) None of these
Answer:
(b) Operator

Question 26.
Consider the following
C = A + B. Here A and B are called
(a) Operand
(b) Operator
(c) Variable
(d) None of these,
Answer:
(b) Operand

Question 27.
The execution of a program starts at ________ function
Answer:
main()

Question 28.
The execution of a program ends with ________ function
Answer:
main()

Question 29.
______ is used to write single line comment
(a) //
(b) /*
(c) */
(d) None of these
Answer:
(a) //

Question 30.
const k = 100 means
(a) const float k = 100
(b) const double k = 100
(c) const int k = 100
(d) const char k = 100
Answer:
(c) const int k = 100

Question 31.
Each and every statement in C++ must be end with ________
(а) Semicolon
(b) Colon
(c) full stop
(d) None of these
Answer:
(a) Semicolon

Question 32.
From the following select the input operator
(а) >>
(b) <<
(c) >
(d) <
Answer:
(a) >>

Question 33.
From the following select the output operator
(a) >>
(b) <<
(c) >
(d) <
Answer:
(b) <<

Question 34.
From the following which is known as a string terminator.
(а) ‘\0’
(b) ‘\a’
(c) ‘As’
(d) ‘\t’
Answer:
(a) ‘\0’

Question 35.
Adeline wrote a C++ program namely sum.cpp and she compiled the program successfully with no error. Some files are generated. From the following which file is a must to run the program
(a) sum.exe
(b) sum.obj
(c) sum.vbp
(d) sum.htm
Answer:
(a) sum.exe

Question 36.
Adeline wrote a C++ program namely sum.cpp and she compiled the program successfully with no error. Some files are generated namely sum.obj and sum.exe. From this which file is not needed to run the program
Answer:
sum.obj is not needed and can be deleted.

Question 37.
From the following which is ignored by the compiler
(a) statement
(b) comments
(c) loops
(d) None of these
Answer:
(b) comments

Question 38.
To write a C++ program, from the following which statement is a must
(a) sum()
(b) main()
(c) #include<iostream>
(d) #include<iomanip>
Answer:
(b) main(). A C++ program must contains at least one main() function

Question 39.
State True / False
Comment statements are ignored by the compiler
Answer:
True

Question 40.
More than one input/output operator in a single statement is called _______
Answer:
Cascading of I/O operator

Question 41.
Is 0X85B a valid integer constant in C++? If yes why?
Answer:
Yes. It is a hexadecimal number.

Plus One Introduction to C++ Programming Two Mark Questions and Answers

Question 1.
Mr. Dixon declared a variable as follows
int 9age. Is it a valid identifier. If not briefly explain. the rules for naming an identifier.
Answer:
It is not a valid identifier because it violates the rule
The rules for naming an identifier is as follows:

1. It must be start with a letter(alphabet)
2. Under score can be considered as a letter
3. White spaces and special characters cannot be used.
4. Key words cannot be considered as an identifier

Question 2.
How many bytes used to store ‘\a’.
Answer:
To store ‘\a’ one byte is used because it is an escape sequence. An escape sequence is treated as one character. To store one character one byte is used.

Question 3.
How many bytes used to store “\abc”.
Answer:
A string is automatically appended by a null character.

• Here one byte for \a (escape sequence).
• One byte for character b.
• One byte for character c.
• And one byte for null character.
• So a total of 4 bytes needed to store this string.

Question 4.
How many bytes used to store “abc”.
Answer:
A string is automatically appended by a null character.

• Here one byte for a.
• One byte for character b.
• One byte for character c.
• And one byte for null character.
• So a total of 4 bytes needed to store this string.

Question 5.
Consider the following code
int main()
{
cout<<“welcome to C++”;
}
After you compile this program there is an error called prototype error. Why it is happened? Explain.
Answer:
Here we used the output operator cout<<. It is used to display a message “welcome to C++” to use this operator the corresponding header file <iostream> must be included. We didn’t included the header file hence the error.

Question 6.
In C++ the size of the string “book” is 5 and that of “book\n” is 6. Check the validity of the above statement. Justify your answer.
Answer:
A string is automatically added by a null character(\0). The null character is treated as one character. So the size of string “book” is 5. Similarly, a null character (\0) is also added to “book\n”. \n and \0 is treated as single characters. Hence the size of the string “book\n” is 6.

Question 7.
Pick the odd man out. Justify
TOTSAL, TOT_SAL, totsal5, Tot5_sal, SALTOT, tot.sal
Answer:
tot.sal. Because it contains a special character dot(.). An identifier cannot contain a special character. So it is not an identifier. The remaining satisfies the rules of naming identifier. So they are valid identifiers.

Question 8.
Write a C++ statement to print the following sentence. Justify.
“\ is a special character”
answer:
cout<<“\\ is a special character”
\\ is treated as an escape sequence.

Question 9.
A student type a C++ program and saves it in his personal folder as Sample.cpp. After getting the output of the program, he checks the folder and finds three files namely Sample.cpp, Sample.obj and Sample.exe. Write the reasons for the generation of the two files in the folder.
Answer:
After the compilation of the program sample.cpp, the operating system creates two files if there is no error. The files are one object file (sample.obj) and one executable file(sample.exe). Now the source file(sample.cpp) and object file(sample.obj) are not needed and can be deleted. To run the program sample.exe is only needed.

Question 10.
Mention the purpose of tokens in C++. Write names of any four tokens in C++. (2)
Answer:
Token: It is the smallest individual units similar to a word in English or Malayalam language. C++ has 5 tokens.

1. Keywords
2. Identifier
3. Literals (Constants)
4. Punctuators
5. Operators

Question 11.
The following are some invalid identifiers. Specify its reason.

1. Sum of digits
2. 1 year
3. First jan
4. For

Answer:

1. Sum of digits → space not allowed hence it is invalid
2. 1 year → First character must be an alphabet hence it is invalid
3. First.jan → special characters such as dot (.) not allowed hence it is invalid.
4. For → It is valid. That is it is not the keyword for

Question 12.
Some of the literals in C++ are given below. How do they differ?(5, ‘5’, 5.0, “5”)
Answer:

• 5 – integer literal
• ‘5’ – Character literal
• 5.0 – floating point literal
• “5”- string literal

Question 13.
Identify the invalid literals from the following and write reason for each:

1. 2E3.5
2. “9”
3. ‘hello’
4. 55450 (2)

Answer:
1. 2E3.5 → The mantissa part (3.5) will not be a floating point number. Hence it is invalid

3. ‘hello’ → It is a string hence it must be enclosed in double quotes instead of single quotes. It is invalid.

Question 14.
Which one of the following is a user defined name?
(a) Keyword
(b) Identifier
(c) Escape sequences
(d) All of these
Answer:
(b) Identifier

Question 15.
Identify whether the following are valid identifiers or not? If not give the reason.

1. Break
2. Simple.interest (2)

Answer:

1. Break – It is valid( break is the keyword, not Break);
2. Simple.interest – It is not valid, because dot(.) is used.

Question 16.
Identify the invalid literals from the following and write a reason for each:

1. 2E3.5
2. “9”
3. ‘hello’
4. 55450 (2)

Answer:
1. Invalid, because exponent part should not be a floating point number

2. valid

Plus One Introduction to C++ Programming Three Mark Questions and Answers

Question 1.
Rose wants to print as follows
\n is used for New Line. Write down the C++ statement for the same.
Answer:
#include<iostream>
using namespace std;
int main()
{
cout<<“\\n is used for New Line”;
}

Question 2.
Alvis wants to give some space using escape sequence as follows
Welcome to C++. Write down the C++ statement for the same
Answer:
#include<iostream>
using namespace std;
int main()
{
cout<<“Welcome to \t C++”;
}

Question 3.
We know that the value of pi = 3.14157, a constant (literal). What is a. constant? Explain it.
Answer:
A constant or a literal is a data item its value doe not change during execution.
1. Integer literals:
Whole numbers without fractional parts are known as integer literals, its value does not change during execution. There are 3 types decimal, octal and hexadecimal.
Eg. For decimal “100, 150, etc

• For octal 0100, 0240, etc
• For hexadecimal 0 × 100, 0x1 A, etc

2. Float literals:
A number with fractional parts and its value does not change during execution is called floating point literals.
eg: 3.14157,79.78, etc

3. Character literal:
A valid C++ character enclosed in single

Question 4.
Write a program to print the message “TOBACCO CAUSES CANCER” on screen.
Answer:
#include<iostream>
using namespace std;
int main()
{
cout<<” TOBACCO CAUSES CANCER”;
}

Question 5.
You are supplied with a list of tokens in C++ program, Classify and Categorise them under proper headings.
Explain each category with its features. tot_mark, age, M5, break, (), int, _pay, ;, cin.
Answer:

Question 6.
Write a program to print the message “SMOKING IS INJURIOUS TO HEALTH” on screen.
Answer:
#include<iostream>
using namespace std;
int mainO
{
cout<<” SMOKING IS INJURIOUS TO HEALTH”;
}

Plus One Introduction to C++ Programming Five Mark Questions and Answers

Question 1.
Consider the following code
The new line character is \n. The output of the following code does not contain the \n. Why it is happened? Explain.
Answer:
\n is a character constant and it is also known as escape sequence. This is used to represent the non graphic symbols such as carriage return key(enter key), tab key, backspace, space bar, etc. It consists of a backslash symbol and one more characters.

Question 2.
You are about to study the fundamentals of C++ programming Language. Do a comparative study of the basics of the new language with that of a formal language like English or Malayalam to familiarize C++? Provide sufficient explanations for the compared items in C++ Language.
Answer:
1. Character set:
To study a language first we have to familiarize the character set. For example, to study English language first we have to study the alphabets. Similarly here the character set includes letters(A to Z & a to z), digits(0 to 9), special characters(+, -, ?, *, /, …..) white spaces(non printable), etc.

2. Token:
It is the smallest individual units similar to a word in English or Malayalam language. C++ has 5 tokens

• Keywords: These are reserved words for the compiler. We can’t use for any other purposes.
  Eg: float is used to declare variable to store numbers with decimal point. We can’t use this for any other purpose
• Identifier: These are user defined words. Eg: variable name, function name, class name, object name, etc…
• Literals (Constants): Its value does not change during execution
  eg: In maths % = 3.14157 and boiling point of water is 100.
• Punctuators: In English or Malayalam language punctuation mark are used to increase the readability but here it is used to separate the tokens.
  eg:{,}, (,), ……..
• Operators: These are symbols used to perform an operation(Arithmetic, relational, logical, etc…).

Students can Download Chapter 2 Data Representation and Boolean Algebra Questions and Answers, Plus One Computer Science Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus One Computer Science Chapter Wise Questions and Answers Chapter 2 Data Representation and Boolean Algebra

Plus One Data Representation and Boolean Algebra One Mark Questions and Answers

Question 1.
___________ is a collection of unorganized fact.
Answer:
Data

Question 2.
Data can be organized into useful ____________
Answer:
Information

Question 3.
___________ is used to help people to make decision.
Answer:
Information

Question 4.
Processing is a series of actions or operations that convert inputs into __________
Answer:
Output

Question 5.
The act of applying information in a particular context or situation is called ____________
Answer:
Knowledge

Question 6.
What do you mean by data processing?
Answer:
Data processing is defined as a series of actions or operations that converts data into useful information.

Question 7.
Odd man out and justify your answer.
(a) Adeline
(b) 12
(3) 17
(d) Adeline aged 17 years is in class 12.
Answer:
(d) Adeline aged 17 years is in class 12. This is information. The others are data.

Question 8.
Raw facts and figures are known as _______
Answer:
data

Question 9.
Processed data is known as _______
Answer:
Information

Question 10.
Which of the following helps us to take decisions?
(a) data
(b) information
(c) Knowledge
(d) intelligence
Answer:
(b) information

Question 11.
Manipulation of data to get information is known as ___________
Answer:
Data processing

Question 12.
Arrange the following in proper order
Process, Output, Storage, Distribution, Data Capture, Input.
Answer:

1. Data Capture
2. Input
3. Storage
4. Process
5. Output
6. Distribution

Question 13.
Pick the odd one out and give reason:
(a) Calculation
(b) Storage
(c) Comparison
(d) Categorization
Answer:
(b) Storage. It is one of the data processing stage the others are various operations in the stage Process

Question 14.
Information may act as data. State true or False.
Answer:
False

Question 15.
Complete the Series.

1. (101)₂, (111)₂, (1001)₂, ……….
2. (1011)₂, (1110)₂, (10001)₂, ………

Answer:

1. 1011, 1101
2. 10101, 10111

Question 16.
What are the two basic types of data which are stored and processed by computers?
Answer:
Characters and number

Question 17.
The number of numerals or symbols used in a number system is its _______________
Answer:
Base

Question 18.
The base of decimal number system is ________
Answer:
10

Question 19.
MSD is ________
Answer:
Most Significant Digit

Question 20.
LSD is _________
Answer:
Least Significant Digit

Question 21.
Consider the number 627. Its MSD is _________
Answer:
6

Question 22.
Consider the number 23.87. Its LSD is __________
Answer:
7

Question 23.
The base of Binary number system is ___________
Answer:
2

Question 24.
What are the symbols used in Binary number system?
Answer:
0 and 1

Question 25.
Complete the following series,
(101)₂, (111)₂, (1001)₂
Answer:
1011, 1101

Question 26.
State True or False. In Binary, the unit bit changes either from 0 to 1 or 1 to 0 with each count.
Answer:
True

Question 27.
The base of octal number system is ________
Answer:
8

Question 28.
Consider the octal number given below and fill in the blanks.
0, 1, 2, 3, 4, 5, 6, 7, __
Answer:
10

Question 29.
The base of Hexadecimal number system is ________
Answer:
16

Question 30.
State True or False.
In Positional number system, each position has a weightage.
Answer:
True

Question 31.
In addition to digits what are the letters used in Hexadecimal number system.
Answer:
A(10), B(11), C(12), D(13), E(14), F(15)

Question 32.
Convert (1110.01011)₂ to decimal.
Answer:
1110.01011 = 1 × 23 + 1 × 22 + 1 × 21 + 0 × 20 + 0 × 2 – 1 + 1 × 2 – 2 + 0 × 2 – 3 + 1 × 2 – 4 + 1 × 2 – 5
= 8 + 4 + 2 + 0 + 0 + 0.25 + 0 + 0.0625 + 0.03125
= (14.34375)10

Question 33.
1 KB is bytes.
(a) 2⁵
(b) 2¹⁰
(c) 2¹⁵
(d) 2²⁰
Answer:
(b) 2¹⁰

Question 34.
The base of hexadecimal number system is ________.
Answer:
16

Question 35.
A computer has no _________
(a) Memory
(b) l/o device .
(c) CPU
(d) IQ
Answer:
(d) IQ

Question 36.
Pick the odd man out.
(AND, OR, NAND, NOT)
Answer:
NOT

Question 37.
Select the complement of X + YZ.
(a) \(\bar{x}+\bar{y}+\bar{z}\)
(b) \(\bar{x} .\bar{y}+\bar{z}\)
(c) \(\bar{x} \cdot(\bar{y}+\bar{z})\)
(d) \(\bar{x}+\bar{y} \cdot \bar{z}\)
Answer:
(c) \(\bar{x} \cdot(\bar{y}+\bar{z})\)

Question 38.
Select the expression for absorption law.
(a) a + a = a
(b) 1 + a = 1
(c) o . a = 0
(d) a + a . b = a
Answer:
(a) a + a . b = a

Question 39.
What is the characteristic of logical expression?
Answer:
Logical expressions yield either true or false values

Question 40.
Name the table used to define the results of Boolean operations.
Answer:
Truth Table

Question 41.
According to ________ law, \(\bar{x}+\bar{y}=\overline{x y}\) and \(\overline{x y}=\bar{x}+\bar{y}\)
Answer:
De Morgan’s law

Question 42.
A NOR gate is ON only when all its inputs are
(a) ON
(b) Positive
(c) High
(d) OFF
Answer:
(d) OFF

Question 43.
The only function of a NOT gate is __________
Answer:
Invert an output signal

Question 44.
NOT gate is also known as _________
Answer:
Inverter

Question 45.
What is the relation between the following statements.
x + 0 = x and x . 1 = x
Answer:
One is the dual of the other expression.

Question 46.
The algebra used to solve problems in digital systems is called __________
Answer:
Boolean Algebra

Question 47.
Pick the one which is not a Basic Gate.
(AND, OR, XOR, NOT)
Answer:
XOR

Question 48.
Select the universal gates from the list. (NAND, NOR, NOT, XOR)
Answer:
NAND, NOR

Question 49.
Which is the final stage in data processing?
Answer:
Distribution of information is the final stage in data processing

Question 50.
Fill up the missing digit.
(41)₈ = ( )₁₆
Answer:

• Step 1: Divide the number into one each and write down the 3 bits equivalent.
• Step 2: Then divide the number into group of 4 bits starting from the right then write its equivalent hexa decimal.

Answer:
So the answer is 21.

Question 51.
Real numbers can be represented in memory by using __________
Answer:
Exponent and Mantissa

Question 52.
Consider the number 0.53421 x 10^-8 Write down the mantissa and exponent.
Answer:
Mantissa: 0.53421
Exponent: -8

Question 53.
Characters can be represented in memory by using _________
Answer:
ASCII Code

Question 54.
ASCII Code of A’ is __________
Answer:
(100 0001)₂ = 65

Question 55.
ASCII Code of’a’ is __________
Answer:
(110 0001)₂ = 97

Question 56.
Define the term ‘bit’?
Answer:
A bit stands for Binary digit. That means either 0 or 1.

Question 57.
Find MSD in the decimal number 7854.25
Answer:
Because it has the most weight

Question 58.
ASCII stands for __________.
Answer:
American Standard Code for Information Interchange

Question 59.
List any two image file formats.
Answer:
BMP, GIF

Question 60.
Name the operator which performs logical multiplication.
Answer:
AND

Question 61.
Name a gate which is ON when all its inputs are OFF .
Answer:
NAND or NOR

Question 62.
Specify the laws applied in the following cases.

1. a (b + c) = ab + ac
2. (a + b) + c = a + (b + c)

Answer:

1. Distribution law
2. Associative law

Question 63.
Pick the correct Boolean expression from the following.
(a) \(A +\bar{A}=163.\)
(b) \(\text { A. } \bar{A}=1\)
(c) \(A \cdot \overline{A B}=A + B\)
(d) A + AB = A
Answer:
(a) & (d)

Question 64.
1’s complement of the binary number 110111 is _________
Answer:
Insert 2 zeroes in the left hand side to make the binary number in the 8 bit form 00110111
To find the 1’s complement, change all zeroes to one and all ones to zero. Hence the answer is 11001000

Plus One Data Representation and Boolean Algebra Two Mark Questions and Answers

Question 1.
Why do we store information?
Answer:
Normally large volume of data has to be given to the computer for processing so the data entry may be taken more days, hence we have to store the data. After processing these stored data, we will get information as a result that must be stored in the computer for future references.

Question 2.
What is source document.
Answer:
Acquiring the required data from all the sources for the data processing and by using this data design a document, that contains all relevant data in proper order and format. This document is called source document.

Question 3.
Briefly explain data, information and processing with real life example.
Answer:
Consider the process of making coffee. Here data is the ingredients – water, sugar, milk and coffee powder
Information is the final product i.e. Coffee Processing is the series of steps to convert the ingredients into final product, Coffee. That is mix the water,sugar and milk and boil it. Finally pour the coffee powder.

Question 4.
ASCII is used to represent characters in memory. Is it sufficient to represent all characters used in the written languages of the world? Propose a solution. Justify.
Answer:
No It is not sufficient to represent all characters used in the written languages of the world because it is a 7 bit code so it can represent 2⁷ = 128 possible codes. To represent all the characters Unicode is used because it uses 4 bytes, so it can represent 232 possible codes.

Question 5.
The numbers in column A have an equivalent number in another number system of column B.
Find the exact matvh

Answer:

Question 6.

1. Name various number systems commonly used in computers.
2. Include each of the following numbers into all possible number systems
   123 569 1101

Answer:

1. The number system are binary, octal, decimal and hexa decimal
2. All possible number systems are
   • 123 Octal, decimal and hexa decimal
   • 569 Decimal, hexa decimal
   • 1101 Binary, Octal, Decimal, Hexa decimal

Question 7.
Fill up the missing digit. (Score 2)
If (220)_a = (90)_b then (451)_a = (  )₁₀
Answer:
It contains 2 & 9, so a and b 2, b 8. The values of a can be 8 or 10. The values of b can be 10 or 16. L.H.S > R.H.S. a < b and a b also.
The possible values of a and b are given below.

Question 8.
Convert (106)₁₀ = (  )₂?
Answer:

Question 9.
Convert (106)₁₀ = (  )₈?
Answer:

Question 10.
(106)₁₀ = (  )₁₆?
Answer:

Question 11.
Convert (55.625)₁₀ = (  )₂?
Answer:
First convert 55, for this do the following

Write down the remainders from bottom to top.
(55)₁₀ = (110111 )₂
Next convert 0.625, for this do the following.

Write down the remainder from top to bottom. So the answer is
(55.625)₁₀ = (110111.101)₂

Question 12.
Convert (55.140625)₁₀ = (  )₈?
Answer:
First convert 55, for this do the following.

Write down the remainders from bottom to top.
(55)₁₀ = (67)₈
Next convert 0.140625, for this do the following.

Write down the remainders from top to bottom. So the answer is
(55.140625)₁₀ = (67.11 )₈

Question 13.
Convert (55.515625)₁₀ = (  )₁₆
Answer:
First convert 55, for this do the following.

Write down the remainders from bottom to top.
ie. (55)₁₀ = (37)₁₆
Next convert .515625

So the answer is
(55.515625)₁₀ = (37.84)₁₆

Question 14.
Convert (101.101)₂ = ( )₁₀?
Answer:
101.101 = 1 × 2² + 0 × 2¹ + 1 × 2⁰ + 1 × 2^-1 + 0 × 2^-2 + 1 × 2^-3 = 4 + 0 + 1 + 1/2 + 0 + 1/8 = 5 + 0.5 + 0.125
(101.101)₂ = (5.625)₁₀

Question 15.
Convert (71.24)₈ = (  )₁₀?
Answer:
71.24 = 7 × 8¹ + 1 × 8⁰ + 2 × 8^-1 + 4 × 8⁼²
= 56 + 1 + 2/8 + 4/82
= 57 + 0.25 + 0.0625 (71.24)8
(71.24)₈ = (57.3125)₁₀

Question 16.
Convert (AB.88)₁₆ = (  )₁₀?
Answer:

= 160 + 11 + 0.5 + 0.03125
(AB.88)₁₆ = (171.53125)₁₀

Question 17.
Convert (1011)₂ = (  )₈?
Answer:
Step I: First divide the number into groups of 3 bits starting from the right side and insert necessary zeroes in the left side.
0 0 1 | 0 1 1

Step II: Next write down the octal equivalent.

So the answer is (1011)₂ = (13)₈.

Question 18.
Convert (110100)₂ = (  )₁₆
Answer:

• Step I: First divide the number into groups of 4 bits starting from the right side and insert necessary zeroes in the left side.
• Step II: Next write down the hexadecimal equivalent.

So the answer is (110100)₂ = (34)₁₆.

Question 19.
(72)₈ = ( )₂?
Answer:
Write down the 3 bits equivalent of each digit.

So the answer is (72)₈ = (111010)₂.

Question 20.
Convert (AO)₁₆ = (  )₂ ?
Answer:
Write down the 4 bits equivalent of each digit

So the answer is (AO)₁₆ = (1010 0000)₂.

Question 21.
Convert (67)₈ = (  )₁₆?
Answer:
Step I: First convert this number into binary equivalent for this do the following

Step II: Next convert this number into hexadecimal equivalent for this do the following.

So the answer is (67)₈ = (37)₁₆

Question 22.
Convert (A1)₁₆ = (  )₈?
Answer:
Step I: First convert this number into binary equivalent. For this do the following

Step II: Next convert this number into octal equivalent. For this do the following.

So the answer is (A1)₁₆ = ( 241)₈.

Question 23.
What is the use of the ASCII Code?
Answer:
ASCII means American Standard Code for Information Interchange. It is a 7 bit code. Each and every character on the keyboard is represented in memory by using ASCII Code.
eg: A’s ASCII Code is 65 (1000001), a’s ASCII Code is 97 (1100001)

Question 24.
Pick invalid numbers from the following.

1. (10101)₈
2. (123)₄
3. (768)₈
4. (ABC)₁₆

Answer:

1. (10101)₈ – Valid
2. (123)₄ – Valid
3. (768)₈ – Invalid. Octal number system does not contain the symbol 8
4. (ABC)₁₆ – Valid

Question 25.
Convert the decimal number 31 to binary.
Answer:

(31)₁₀ = (11111)₂

Question 26.
Find decimal equivalent of (10001 )₂
Answer:

= 1 × 24 + 0 × 23 + 0 × 22 + 0 × 21 + 1 × 20
= 16 + 0 + 0 + 0 + 1
= (17)₁₀

Question 27.
If (X)₈ =(101011 )₂ then find X.
Answer:
Divide the binary number into groups of 3 bits and write down the corresponding octal equivalent.

X = 53

Question 28.
Fill the blanks:
(a) (………..)₂ = (AB)₁₆
(b) (——D—–)₁₆ = (1010 1000)₂
(c) 0.25₁₀ = (—–)₂

Answer:
Write down the 4bit equivalent of each digit
(a) (………..)₂ = (AB)₁₆

= (10101011)₂
(b) (——D—–)₁₆ = (1010 1000)₂
(A D 8)₁₆ =(1010 1101 1000)₂

(c) 0.25₁₀ = (—–)₂

0.25₁₀ = (0.01)₂

Question 29.
Which is the MSB of representation of -80 in SMR?
Answer:
It is 1 because In SMR if the number is negative then the MSB is 1.

Question 30.
Write 28.756 in Mantissa exponent form.
Answer:
28.756 = .28756 × 100
= .28756 × 102
= .28756 E + 2

Question 31.
Represent -60 in 1’s complement form.
Answer:
+60 = 00111100
Change all 1 to 0 and all 0 to 1 to get the 1’s complement.
-60 is in 1’s complement is 11000011

Question 32.
Define Unicode.
Answer:
The limitations to store more characters is solved by the introduction of Unicode. It uses 16 bits so 2¹⁶ = 65536 characters(i.e, world’s all written language characters) can store by using this.

Question 33.
Substract 1111 from 10101 by using 2’s complement method.
Answer:
To subtract a number from another number find the 2’s complement of the subtrahend and add it with the minuend. Here the subtrahend is 1111 and minuend is 5 bits. So insert a zero. So subtrahend is 01111. First take the 1’s complement of subtrahend and add 1 to it

Here is a carry. So ignore the carry and the result is +ve.
So the answer is 110

Question 34.
You purchased a soap worth Rs. (10010)₂ and you gave Rs. (10100)₂ and how much rupees will you get back in binary.
Answer:
Substract (10010)₂ from (10100)₂

You will get rupees (10)₂

Question 35.
Draw the logic circuit diagram for the following Boolean expression.
Answer:

Question 36.
Simplify the expression using basic postulates and laws of Boolean algebra.

1. \(\bar{x}+x \cdot \bar{y}\)
2. \(x(y+y . z)+y(\bar{x}+x z)\)

Answer:

1. \(\bar{x}+\bar{y}\)
2. y

Question 37.
Show \(A(\bar{B}+C)\) using NOR gates only.
Answer:

Question 38.
The following statement Demorgan’s theorem of Boolean algebra. Identify and state ‘Break the line, change the sign’.
Answer:
Demorgan’s theorems,
Demorgan’s first theorem,
\(\overline{x + y}\) = \(\bar{x} . \bar{y}\)
Demorgan’s second theorem,
\(\overline{x – y}\) = \(\bar{x} + \bar{y}\)

Question 39.
Prove algebraically that
\(x \cdot y + x \cdot \bar{y} \cdot z\) = x . y + x . z
Answer:
\(x \cdot y + x \cdot \bar{y} \cdot z\) = \(x(y+\bar{y} . z)\)
= x . (y + z) = x . y + x . z
Hence proved.

Question 40.
State which of the following statements are logical statements.
(a) AND is a logical operator
(b) ADD 3 to y
(c) Go to class
(d) Sun rises in the west.
(e) Why are you so late?
Answer:
(a) and (d) are logical statements because these statements have a truth value which may be true or false.

Question 41.
Express the integer number -39 in sign and magnitude represnetation.
Answer:
First find the binary equivalent of 39 for this do the following

In sign and magnitude representation -39 in 8 bit form is (10100111)₂.

Question 42.

1. Which logic gate does the Boolean expression \(\overline{\mathrm{AB}}\) represent?
2. Some NAND gates are given. How can we construct AND gate, OR gate and NOT gate using them?

Answer:
1. NAND

2. AND gate

Question 43.
Perform the following number conversions.

1. (110111011.11011)₂ = (….)₈
2. (128.25)₁₀= (…..)₈

Answer:
1. 110111011.11011
Step 1: Insert a zero in the right side of the above number and divide the number into groups of 3 bits as follows
110 111 011 . 110 110

Step 2: Write down the corresponding 3 bit binary equivalent of each group
6 7 3 .6 6
Hence the result is (673.66)₈

2. It consists of 2 steps.
Step 1: First convert 128 into octal number for this do the following

Write down the remainders from bottom to top.
(128)₁₀ = (200)₈

Step 2: Then convert .25 into octal number for this do the following

(0.25)₁₀ = (0.2)₈.
Combine the above two will be the result.
(128.25)₁₀= (200.2)₈

Question 44.
Represent -38 in 2’s complement form.
Answer:
+38 = 00100110
First take the 1 ’s complement for this change all 1 to 0 and all 0 to 1

2’s complement of -38 is (11011010)₈.

Plus One Data Representation and Boolean Algebra Three Mark Questions and Answers

Question 1.
Differentiate manual data processing and electronic data processing?
Answer:
In manual data processing human beings are the processors. Our eyes and ears are input devices. We get data either from a printed paper, that can be read using our eyes or heard with ears. Our brain is the processor and it can process the data, and reach in a conclusion known as result. Our mouth and hands are output devices.

In electronic data processing the data is processing with the help of a computer. In a super market, key board and hand held scanners are used to input data, the CPU process the data, monitor and printers (Bill) are output devices.

Question 2.
Complete the series.

1. 3248, 3278 ,3328, …., ….
2. 5678, 5768, 605s, ……, …..

Answer:
1. (324)₈ = 3 × 82 + 2 × 81 + 4 × 80
= 3 × 64 + 2 × 8 + 4 × 1
= 192 + 16 + 4 = (212)10

(327)₈ = 3 × 82 + 2 × 81 + 7 × 80
= 192 + 16 + 7 = (215)₁₀

(332)₈= 3 × 82 + 3 × 81 +2 × 80
= 192 + 24 + 2 = (218)₁₀
So the missing terms are (221)₁₀, (224)₁₀ we have to convert this into octal.

So the missing terms are (335)₈, (340)₈

2. (567)₈ = 5 x 82 + 6 x 81 + 7 x 80
= 5 x 64 + 6 x 8 + 7 x 1
= 320 + 48 + 7 = (375)₁₀

(576)₈ = 5 x 82 + 7 x 81 + 6 x 80
= 320 + 56 + 6 = (382)₁₀

(605)₈ = 6 x 82 + 0 x 81 + 5 x 80
= 6 + 64 + 0 + 5
= 384 + 0 + 5 = (389)₁₀
So the missing terms are (396)₁₀, (403)₁₀ we have to convert this into octal.

So the missing terms are (614)₈, (623)₈

Question 3.
Fill up the missing digits.

1. (4……)₈ = (……110)₂
2. (…….7……)₈ = (100…….110)₂

Consider the following

Answer:
1. 4…….100 and 110……….6
So (46)₈ = (100 110)₂

2. 100…….4
7……111
110………6
So (476)₈ = (100 111 110)₂

Question 4.
Fill up the missing numbers.

1. (A…….)₁₆ = (……..1001)₂
2. (…….B…….)₁₆ = (1000………1111)₂

Consider the following:


Answer:
1. A……..1010
1001………9
So (A9)₁₆ = (1010 1001)₂

2. B…….1011
1000………8
1111………F
So (8BF)₁₆ = (1000 1011 1111)₂

Question 5.
Complete the Series.

1. 6ADD, 6ADF, 6AE1, ……., …….
2. 14A9, 14AF, 14B5, …….., ……

Answer:
1. Consider the sequence
6ADD, 6ADF, 6AE1, ………….
Here the ‘numbers’ are
0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F, 10, 11,——–
The difference between 6ADD & 6ADF is 2

Similarly 6ADF & 6AE1 is 2

So Add 2 to 6AE1 we will ge 6AE3 Then add 2 to 6AE3 we will get 6AE5 Therefore the missing terms 6AE3, 6AE5

2. Consider the sequence.
14A9, 14AF, 14B5, ———
The difference between 14A9 and 14AF is 6.
The normal sequence is

The difference between 14AF and 14B5 is also 6.

The normal sequence is

Similarly the next 6 terms in the sequence are given below.

Similarly the next 6 terms are

So the missing terms are 14BB and 14C1

Question 6.
Find the octal numbers corresponding to the following numbers using shorthand method.

1. (ADD)₁₆
2. (DEAD)₁₆

Answer:
1. (ADD)₁₆
Step 1: Write down the 4 bit binary equivalent of each digit

Step 2: Divide this number into groups of 3 bits starting from the right and write down the octal equivalent.

(ADD)(ADD)₁₆ = (5335)(ADD)₈

2. (DEAD)₁₆
Step 1: Write down the 4 bit binary equivalent of each digit.

Step 2: Divide this number into groups of 3 bits starting from the right and write down the octal equivalent.

(DEAD)₁₆ = (157255)₈

Question 7.
If (126)x = (56)y, then find x and y.
Answer:
L.H.S contains 2 & 6, so x ≠ 2
R.H.S contains 5 & 6, so y ≠ 2
L.H.S > R.H.S
So x < y and x ≠ y also The possible values of x and y are given below.

Case I:
Let x = 8 then y = 10

It is grater than (56)₁₀
so when x = 8 then y ≠ 10

case II:
let x = 8 and y = 16

Question 8.
If (102)x = (42)y then (154)x = (  )y.
Answer:
L.H.S contains 2, so x ≠ 2
R.H.S contains 5 & 4, so y ≠ 2
L.H.S > R.H.S
So x < y and x ≠ y also
The possible values of x and y are given below.

case I:
let x = 8 and y = 10

So when x = 8 then y ≠ 10

case II:
let x = 8 and y = 16

So x = 8 and y = 16
then we have fo find the hexadecimal equivalent of (154)₈ For this first convert this into binary thus again convert it into hexadecimal. First write down the 3 bit equivalent of 154.

Then divide this number into groups of 4 bits starting from the right and write down the hexa decimal equivalent.

so the result is (154)₈ = (6C)₁₆

Question 9.
Fill up the missing digit.
If (121)_a = (441)_b then (121)_b = (  )₁₀
Answer:
L.H.S. contains 2, so a ≠ 2
R.H.S. contains 4, so b ≠ 2
L.H.S. < R.H.S. So a > b and a b also.
Hence the values of a can be 10 or 16.
The values of b can be 8 or 10.
The possible values of a and b are given below.

Case I:
Let a = 16 and b = 10
(121 )₁₆ = (289)_10, so b ≠ 10

Case II:
Let a = 16 and b = 8
(121)₁₆ = (289)₁₀
(441)₈ = 4 × 8² + 4 × 8¹ + 1 × 8⁰
= 256 +32 + 1
= (289)₁₀.
So a = 16 and b = 8.
Then (121)₈ = 1 × 82 + 2 × 81 + 1 × 80
= 64 + 16 + 1 = (81)₁₀

Question 10.
Fill up the missing digit. (Score 3)
If (128)_a = (450)_b then (16)_a = (  )₁₀
Answer:
L.H.S. contains 2 & 8, so a 2 and a ≠ 8.
R.H.S. contains 4 and 5, so b ≠ 2.
L.H.S. < R.H.S. so a > b and a ≠ b also.
The possible values of a and b are given below.

Case I:
a = 16 and b = 8
(128)₁₆ = (296)₁₀
(450)₈ = (296)₁₀ So a = 16 and b = 8.
Then (16)₁₆ = 1 × 16 + 6 × 16⁰ = (22)₁₀

Question 11.
Fill up the missing digit.
(3A.6D)₁₆ = (  )₈
Answer:
Step I: Write down the 4 bits equivalent of each digit.

Step II: Divide this number into groups of 3 bit starting from the right side of the left side of the decimal point and starting from the left side of the right side of the decimal point.
So 00/111/010.011/011/010

Step III: Write the octal equivalent of each group. SO we will get. (72.332)₈.
(3A.6D)₁₆ = (72.332)₈

Question 12.
What are the various ways to represent integers in computer?
Answer:
There are three ways to represent integers in computer. They are as follows:

1. Sign Magnitude Representation (SMR)
2. 1’s Complement Representation
3. 2’s Complement Representation

1. SMR:
Normally a number has two parts sign and magnitude, eg: Consider a number +5. Here + is the sign and 5 is the magnitude. In SMR the most significant Bit (MSB) is used to represent the sign. If MSB is 0 sign is +ve and MSB is 1 sign is – ve.
eg: If a computer has word size is 1 byte then

Here MSB is used for sign then the remaining 7 bits are used to represent magnitude. So we can represent 27 = 128 numbers. But there are negative and positive numbers. So 128 + 128 = 256 number. The numbers are 0 to +127 and 0 to -127. Here zero is repeated. So we can represent 256 – 1 = 255 numbers.

2. 1 ‘s Complement Representation: To get the 1’s complement of a binary number, just replace every 0 with 1 and every 1 with 0. Negative numbers are represented using 1’s complement but +ve number has no 1’s complement.
eg: To find the 1’s complement of 21 +21 = 00010101
To get the 1 ‘s complement change all 0 to 1 and all 1 to 0.
-21 = 11101010
1’s complement of 21 is 11101010

3. 2’s Complement Representation: To get the 2’s complement of a binary number, just add 1 to its 1’s complement +ve number has no 2’s complement.
eg: To find the 2’s complement of 21 +21 =00010101
First take the 1’s complement for this change all 1 to 0 and all 0 to 1

2’s complement of 21 is 1110 1011

Question 13.
Write short notes about Unicode (3)
Answer:
It is like ASCII Code. By using ASCII, we can represent limited number of characters. But using Unicode we can represent all of the characters used in the written languages of the world.
eg: Malayalam, Hindi, Sanskrit .

Question 14.
Match the following.

Answer:
1 – b, 2 – f, 3 – a, 4 – c, 5 – d, 6 – e

Question 15.
Find the largest number in the list.

1. (1001)₂
2. (A)₁₆
3. (10)₈
4. (11)₁₀

Answer:
Convert all numbers into decimal
1. (1001)₂ = 1 × 2³ + 0 × 2² + 0 × 2¹ + 1 × 2⁰
= 8 + 0 + 0 + 1
= (9)₁₀

2.) (A)₁₆ = (10)₁₀

3. (10)₈ = 1 × 8¹+0 × 8⁰
= (8)₁₀
So the largest number is 4 – (11)₁₀

Question 16.
Subtract 10101 from 1111 by using 2’s complement method.
Answer:
To subtract a number from another number find the 2’s complement of the subtrahend and add it with the minuend. Here subtrahend is 10101 and minuend is 1111 First take the 1’s complement of subtrahend and add 1 to it.
1’s complement of 10101 is 01010 add 1 to it

Here is no carry. So the result, is -ve and take the 2’s complement of 11010 and put a -ve symbol. So 1’s complement of 11010 is 00101 add 1 to this

So the result is -00110

Question 17.
Mr. Geo purchased (10)₂ kg sugar @Rs. (110 10)₂ and (1010)₂ kg Rice @Rs. (10100)₂. So how much rupees he has to pay in decimal.
Answer:
Convert each into decimal number system multiply and sum it up.
(10)₂ = (2)₁₀

(11010)₂ = 1 × 2⁴ + 1 × 2³ + 0 × 2² + 1 × 2¹ + 0 × 2¹
= 16 +8 + 0 +2 + 0
= (26)₁₀

(1010)₂ = 1 × 2³ + 0 × 2² + 1 × 2¹ +0 × 2⁰
= 8 + 0 + 2 + 0
= (10)₂

(10100)₂ = 1 × 2⁴ + 0 × 2³ + 1 × 2² +0 × 2¹ + 0 × 2⁰
= 16 + 0 + 4 + 0 + 0
= (20)₂
therfore 2 × 26 + 10 × 20
= 52 + 200
= 252
So Mr. Geo has to pay Rs. 252/-

Question 18.
Mr. Vimal purchased a pencil @ Rs. (101)2, a pen @ Rs. (1010)2 and a rubber @ Rs. (10)2. So how much rupees he has to pay in decimal.
Answer:
Add 101 + 1010 + 10

then convert (10001)₂ into decimal
(10001)₂ = 1 × 2⁴ + 0 × 2³ + 0 × 2² + 0 × 2¹ + 1 × 2⁰
= 16 + 0 + 0 + 0 + 1
= (17)₁₀
So Mr. Vimal has to pay Rs. 17/-

Question 19.
Mr. Antony purchased 3 books worth Rs. a total of (1100100)₂. Atlast he returned a book worth Rs. (11001)₂. So how much amount he has to pay for the remaining two books in decimal number sys¬tem.
Answer:

then convert (1001011 )₂ into decimal
(1001011)₂ = 1 × 2⁶ + 0 × 2⁵ + 0 × 2⁴ + 1 × 2³ + 0 × 2² + 1 × 2¹ + 1 × 2⁰
=64 + 0 + 0 + 8 + 0 + 2 + 1
= (75)₁₀
So he has to pay Rs. 75/-

Question 20.
Mr. Leones brought two products from a super market a total of Rs. (11010010)₂ and he got a dicount of Rs. (1111)₂ So how much he has to pay for this products in decimal number system.
Answer:
Substract (1111)₂ from (11010010)₂

then convert (11000011)₂ into decimal
(11000011)₂ = 1 × 2⁷ + 1 × 2⁶ + 0 × 2⁵ + 0 × 2⁴ + 0 × 2³ + 0 × 2² + 1 × 2¹ + 1 × 2⁰
=128 + 64 + 0 + 0 + 0 + 0 + 2 + 1
= (195)₁₀

Question 21.
A textile showroom sells shirts with a discount of Rs. (110010)₂ on all barads. Mr. Raju wants to buy a shirt worth Rs. (11111000)₂. So after discount how much amount he has to pay in decimal.
Answer:
Substract (110010)₂ from (11 111 000)₂

then convert (11000110)₂ into decimal
(11000110)2 = 1 × 2⁷ + 1 × 2⁶ + 0 × 2⁵ + 0 × 2⁴ + 0 × 2³ + 1 × 2² + 1 × 2¹ + 0 × 2⁰
= 128 + 64 + 0 + 0 + 0 + 4 + 2 + 0
= (198)₁₀

Question 22.
Mr. Lijo purchased a product worth Rs. (1110011)₂ and he has to pay VAT @ Rs. (1100)₂. Then calculate the total amount he has to pay in decimal.
Answer:
Add (1110011)₂ and (1100)₂

then convert (1111111)₂ into decimal
(1111111)₂ = 1 × 2⁶ + 1 × 2⁵ + 1 × 2⁴ + 1 × 2³ + 1 × 2² + 1 × 2¹ + 1 × 2⁰
= 64 + 32 + 16 + 8 + 4 + 2 + 1
= (127)₁₀

Question 23.
By using truth table, prove the following laws of Boolean Algebra.

1. Idempotent law
2. Involution law

Answer:
1. A + A = A
A = A = A

2. (A¹)¹ = A

Question 24.
Consider the logical gate diagram.

1. Find the logical expression for the circuit given.
2. Find the compliment of the logical expression.
3. Draw the circuit diagram representing the compliment.

Answer:
1. \((x+\bar{y}) \cdot z\)

2. \((\bar{x} . y)+\bar{z}\)
3.

Question 25.
Draw the logic circuit diagram for the following Boolean expression.
\(A \cdot(\bar{B} + \bar{C})+\bar{A} \bar{B} \bar{C}\)
Answer:

Question 26.
Consider a bulb with three switches x, y and z. Write the Boolean expression representing the following states.

1. All the switches x, y and z are ON
2. x is ON and y is OFF or Z is OFF
3. Exactly one switch is ON.

Answer:

1. xy . z
2. \(x \bar{y}+\bar{z}\)
3. \(x . \bar{y} . \bar{z}+\bar{x} . y . \bar{z}+\bar{x} . \bar{y} . \bar{z}\)

Question 27.
Match the following.

Answer:
i – f, ii – e, iii – d, iv – c, v – b, vi – a

Question 28.
Explain the principle of duality.
Answer:
It states that, starting with a Boolean relation, another Boolean relation can be derived by

1. Changing each OR sign (+) to a AND sign (.)
2. Changing each AND sign (.) to an OR sign (+)
3. Replacing each 0 by 1 and each 1 by 0.

The relation derived using the duality principle is called the dual of the original expression,
eg: x + 0 = x is the dual of x . 1 = x

Question 29.
Draw the circuit diagram for \(F=A \bar{B} C+\bar{C} B\) using NAND gate only.
Answer:
\(F=A \bar{B} C+\bar{C} B\)
= (A NAND (NOT B) NAND C) NAND ((NOT C) NAND B)

Question 30.
Draw a logic diagram for the function f = YZ + XZ using NAND gates only.
Answer:
f = YZ + XZ
= (Y NAND Z) NAND (X NAND Z)

Question 31.
How do you make various basic logic gates using NAND gates.
Answer:
1. AND operation using NAND gate,
A.B = (A NAND B) NAND (A NAND B)

2. OR operation using NAND gate,
A + B = (A NAND A) NAND (B NAND B)

3. NOT operation using NAND gate,
NOT A = (A NAND A)

Question 32.
Which of the following Boolean expressions are correct? Write the correct forms of the incorrect ones.

1. A + A¹ = 1
2. A + 0 = A
3. A . 1 = A
4. A . A¹ = 1
5. A + A . B = A
6. A . (A + B) = A
7. A + 1=1
8. \((\overline{\mathrm{A} . \mathrm{B}})=\overline{\mathrm{A}} . \overline{\mathrm{B}}\)
9. A + A¹B = A + B
10. A + A = A
11. A + B . C = (A+B) . (B+C)

Answer:

1. Correct
2. Correct
3. Correct
4. Wrong, A . A¹ = 0
5. Correct
6. Correct
7. Correct
8. Wrong \(\overline{\mathrm{A} . \mathrm{B}}=\overline{\mathrm{A}}+\overline{\mathrm{B}}\)
9. Correct
10. Correct
11. Wrong, A + B . C = (A + B) . (A + C)

Question 33.
Prove algebraically that (x + y)’ . (x’ + y’) = x’ . y’
Answer:
LHS = (x + y)’ . (x’ + y’)
= (x’ . y’) . (x’ . y’)
= x’ . y’ . x’ + x’ . y’ . y’
= x’ . y’ + x’ . y’
= x ‘. y’ = RHS
Hence proved.

Question 34.
Give the complement of the following Boolean Expression.

1. (A + B) . (C + D)
2. (P + Q) + (Q + R) . (R + P)
3. (B + D’) . (A + C’)

Answer:
1. ((A+B) . (C+D))1 = (A+B)’ + (C+D)’
= A’ . B’ + C’ . D’

2. ((P+Q) + (Q+R) . (R.P))’ = (P+Q) ‘. ((Q+R) . (R+P))’
= P’ . Q’ . (Q+R)’ + (R+P)’
= P’ . Q’ . (Q’ . R’ + R’ . P’),

3. ((B+D’).(A+C’))’ = (B+D’)’0 + (A+C’)’
= B’ . D” + A’ . C”
= B’ . D + A’ . C

Question 35.
State and prove the idempotent law using truth table. Idempotent law
Answer;
Idempotent law states that

1. A + A = Aand
2. A . A = A Proof

1. A + A = A
Truth table is as follows:

ie. A + A = A as it is true for both values of A. Hence proved.

2. A . A = A
Truth table is as follows:

ie. A . A = A itself. It is true for both values of A. Hence proved.

Question 36.
State the Absorption laws of Boolean algebra with the help of truth tables.
Answer:
Absorption law states that
A + A . B = A and A . (A + B) = A
Proof:
The Truth table of the expression A + A . B=A is as follows.

Here both columns A and A + A . B are identical. Hence proved.
For A . (A + B) = A, the truth table is as follows:

Both columns A & A . (A + B) are identical. Hence proved

Question 37.
State Demorgen’s laws. Prove anyone with truth table method.
Answer:
Demorgan’s first theorem states that (A + B)’ = A’ . B’
ie. the complement of sum of two variables equals product of their complements,

The second theorem states that (A . B)’ = A’ + B’
ie. The complement of the product of two variables equals the sum of the complement of that variables.
Proof:
Truth table of first one is as follows:

From the truth table the columns of both (A + B)’ and A’ . B’ are identical. Hence proved.

Question 38.
Fill in the blanks:

1. (0.625)₁₀ = (……….)₂
2. (380)₁₀ = (……..)₁₆
3. (437)₈ = (………)₂

Answer:

1. (0.101)₂
2. (17C)₁₆
3. (100 011 111)₂

Question 39.
What do you mean by universal gates? Which gates are called Universal gates? Draw their symbols.

OR

Construct a logical circuit for the Boolean expression \(\bar{a} \cdot b+a \cdot \bar{b}\). Also write the truth table.
Answer:
Universal gates:
By using NAND and NOR gates only we can create other gate hence these gates are called Universal gate.
NAND gate:

NOR gate:

Truth table:

Logical circute:

Question 40.
Computers uses a fixed number of bits to respresent data which could be a number, a character, image, sound, video etc. Explain the various methods used to represent characters in memory.
Answer:
Representation of characters.
1. ASCII(American Standard Code for Information Interchange):
It is 7 bits code used to represent alphanumeric and some special characters in computer memory. It is introduced by the U.S. government. Each character in the keyboard has a unique number.
eg: ASCII code of ‘a’ is 97.

When you press ‘a’ in the keyboard , a signal equivalent to 1100001 (Binary equivalent of 97 is 1100001) is passed to the computer memory. 2⁷ = 128, hence we can represent only 128 characters by using ASCII. It is not enough to represent all the characters of a standard keyboard.

2. EBCDIC(Extended Binary Coded Decimal Interchange Code):
It is an 8 bit code introduced by IBM(International Business Machine). 2⁸ = 256 characters can be represented by using this.

3. ISCII(Indian Standard Code for Information Interchange):
It uses 8 bits to represent data and introduced by standardization committee and adopted by Bureau of Indian Standards(BIS).

4. Unicode:
The limitations to store more characters is solved by the introduction of Unicode. It uses 16 bits so 2¹⁶ = 65536 characters (i.e, world’s all written language characters) can store by using this.

Question 41.
Draw the logic circuit for the function
\(f(a, b, c)=a . b . c+\bar{a} . b+a . \bar{b}+a . b . \bar{c}\)

OR

Prove algebrically.
\(x . y+x . \bar{y} . z=x . y .+x . z\)
Answer:

OR

\(x \cdot y+x \cdot \bar{y} \cdot z=x \cdot(y+\bar{y} \cdot z)\)
= x . (y + z) = x . y + x . z
Hence proved.

Question 42.
Following are the numbers in various number systems. Two of the numbers are same. Identify them:

1. (310)₈
2. (1010010)₂
3. (C8)₁₆
4. (201)₁₀

OR

Consider the following Boolean expression:
(B’ + A)’ = B . A’
Identify the law behind the above expression and prove it using algebriac method.
Answer:
1. (310)₈ = 3 * 8² + 1 * 8¹ + 0 * 8⁰
= 192 + 8 + 0
= (200)₁₀

2. (1010010)₂ = 1 × 2⁶+ 0 × 2⁵ + 1 × 2⁴ + 0 × 2³ + 0 × 2² + 1 × 2¹ + 0 × 2⁰
= 64 + 0 + 16 + 0 + 0 + 2 + 0
= (82)₁₀

3. (C8)₁₆ = C × 16 + 8 × 16⁰
= 12 × 16 + 8 × 1
= 192 + 8
= (200)₁₀
Here (a) (310)₈ and (C8)₁₆ are same

OR

This is De Morgan’s law (B’ + A’) = (B’)’ . A’
= B . A’
Hence it is proved

Question 43.
Find the decimal equivalent of hexadecimal number (2D)₁₆. Represent this decimal number in 2’s complement form using 8 bit word length.
Answer:
Convert (2D)₁₆ to binary number for this write down the 4 bit binary equivalent of each number

(2D)₁₆ = (00101101 )₂
First find the 1’s complement of (00101101 )₂ and add 1 to it

Hence 2’s complement is (11010011)₂

Question 44.
Answer any one question from 15(a) and 15(b).
1. Draw the logic circuit for the Boolean expression:
\((A+\overline{B C})+\overline{A B}\)

2. Using algebraic method prove that
\(\bar{Y} \cdot \bar{Z}+\bar{Y} \cdot Z+Y \cdot Z+Y=1\)
Answer:
1.

OR

2. L.H.S. = \(\bar{Y} \cdot \bar{Z}+\bar{Y} \cdot Z+Y Z+Y\)
= \(\bar{y} \cdot(\bar{z}+z)+y \cdot(z+1)\)
= \(\bar{y}. 1+\bar{y} \cdot 1=y \cdot y=1\)

Question 45.
With the help of a neat circuit diagram, prove that NAND gate is a universal gate.
Answer:
1. AND operation using NAND gate,
A . B = (A NAND B) NAND (A NAND B)

2. OR operation using NAND gate,
A + B = (A NAND A) NAND (B NAND B)

3. NOT operation using NAND gate,
NOT A = (A NAND A)

Question 46.
Boolean expression:
\((A+\overline{B C})+\overline{A B}\)

OR

Using algebraic method, prove that
\(\bar{Y} \cdot \bar{Z}+\bar{Y} \cdot Z+Y \cdot Z+Y=1\)
Answer:

OR

= Y . Z + Y . Z + Y . Z + Y
= Y . (Z + Z) + Y . (Z + 1)
= Y . 1 + Y. 1
= Y + Y
= 1
Hence the result.

Plus One Data Representation and Boolean Algebra Five Mark Questions and Answers

Question 1.
Explain the components of Data processing.
Answer:
Data processing consists of the techniques of sorting, relating, interpreting and computing items of data in orderto convert meaningful information. The components of data processing are given below.

1. Capturing data: In this step acquire or collect data from the user to input into the computer.
2. Input: It is the next step. In this step appropriate data is extracted and feed into the computer.
3. Storage: The data entered into the computer must be stored before starting the processing.
4. Processing/Manipulating data: It is a laborious work. It consists of various steps like computations, classification, comparison, summarization, etc. that converts input into output.
5. Output of information: In this stage we will get the results as information after processing the data.
6. Distribution of information: In this phase the information(result) will be given to the concerned persons/computers.

Question 2.
Define computer. What are the characteristics?
Answer:
A computer is an electronic device used to perform operations at very high speed and accuracy.
Following are the characteristics of the computer.

1. Speed: It can perform operations at a high speed.
2. Accuracy: It produces result at a high degree of accuracy.
3. Diligence: Unlike human beings, a computer is free from monotony, tiredness, lack of concentration etc. We know that it is an electronic ma chine. Hence it can work four hours without making any errors.
4. Versatility: It is capable of performing many tasks. It is useful in many fields.
5. Power of Remembering: A computer consists of huge amount of memory. So it can store and recall any amount of information. Unlike human beings, it can store huge amount of data and can be retrieved when needed.

Disadvantages of computer:

1. No. IQ: It has no intelligent quotient. Hence they are slaves and human beings are the masters. It can’t take its own decisions.
2. No feelings: Since they are machines they have no feelings and instincts. They can perform tasks based upon the instructions given by the humans (programmers)

Students can Download Chapter 10 Applications of Computers in Accounting Questions and Answers, Plus One Accountancy Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus One Accountancy Chapter Wise Questions and Answers Chapter 10 Applications of Computers in Accounting

Plus One Accountancy Applications of Computers in Accounting One Mark Questions and Answers

Question 1.
The physical components of computer is called as …………..
(a) Software
(b) Hardware
(c) Liveware
Answer:
(b) Hardware

Question 2.
Set of programs which governs the operation of a computer system is termed …………..
(a) System software
(b) Software
(c) Application of window
Answer:
(b) Software

Question 3.
A centrally controlled integrated collection of data is called ……………
(a) DBMS
(b) Information
(c) Database
Answer:
(c) Database

Question 4.
Tally is a
(a) Utility software
(b) Application software
(c) Operating system
(d) Connecting software
Answer:
(b) Application software

Question 5.
…………… is a software system that manages the creation of use of database.
(a) Database
(b) DBMS
(c) Management system
Answer:
(b) DBMS

Question 6.
Which one of the following is an output device of a computer?
(a) Mouse
(b) Keyboard
(c) Monitor
(d) Barcode reader
Answer:
(c) Monitor

Question 7.

…………. is the storehouse of a computer.
Answer:
Memory

Question 8.
…………… are set of program designed to carry out operations for a specified application.
Answer:
Application software.

Question 9.
The output obtained from VDU (Visual Display Unit) is termed ………..
Answer:
Hard copy.

Question 10.
The part.of the computer which controls the various operations of a computer is called ………..
Answer:
Control unit.

Question 11.
………….. is temporary memory and anything stored in it will remain there a long as the system is on.
Answer:
RAM (Random Access Memory)

Question 12.
Modern computerised accounting systems are based on the concept of ………..
Answer:
Database.

Question 13.
A sequence of actions taken to transform the data into decision-useful information is called ………..
Answer:
Data processing

Question 14.
The joystick is a …….. device of a computer.
Answer:
Input.

Question 15.
VDU is also called ……….
Answer:
Monitor.

Question 16.
Complete the series using the hint given.
Hint: System analyst → Human beings → liveware
a. Windows → Operating system → ?
Answer:
Software.

Plus One Accountancy Applications of Computers in Accounting Two Mark Questions and Answers

Question 1.
Match the following.

Answer:
1-b
2-e
3-d
4-c
5-a

Question 2.
What is a computer?
Answer:
Sp A computer is an electronic device that accepts data and instruction as input, stores them, process the data according to the instructions and communicate the results as output.

Question 3.
Hardware includes different devices. Name any four devices.
Answer:
Keyboard, Mouse, Monitor, Processor.

Question 4.
Redraw the given block diagram of a computer correctly:

Answer:

Question 5.
List out any four features of a computer.
Answer:

1. Highspeed
2. Large volume of data can be stored.
3. Accuracy is very high.
4. Computers are multipurpose information machine ie. versatility.

Question 6.
List out any four limitations of a computer.
Answer:

1. Computers lacks common sense.
2. Lack of decision-making skills
3. Computers have no intelligence.
4. Computers cannot make judgments based on feelings.

Question 7.
What is Accounting Information System?
Answer:
Accounting Information System (AIS) is a collection of resources (people and equipment), designed to transform financial and other data into information. Such information is organised in a manner that correct decisions can be based on it.

Question 8.
What are the basic requirements of a computerised accounting system?
Answer:
Every computerised accounting system has two basic requirements.

1. Accounting Framework: It consists of a set of principles, coding and grouping structure of accounting.
2. Operating procedure: It is a well defined operating procedure blended suitably with the operating environment of the organisation.

Question 9.
State the various essential features of an accounting report.
Answer:
The accounting report must have the following features it.

1. Relevance
2. Timelines
3. Accuracy
4. Completeness
5. Summarisation

Question 10.
Give examples of the relationship between a Human Resource Information System and MIS.
Answer:
There is a relationship between the Human Resource Information System and Management Information System, the following are the example of it.

1. Hiring employees as per the requirement.
2. Evaluating the performance of the workers.
3. Enrolling employees in benefit.

Question 11.
Give examples of two types of Operating System.
Answer:

• DOS – Disk Operating System
• Windows – Windows Operating System

Plus One Accountancy Applications of Computers in Accounting Three Mark Questions and Answers

Question 1.
Explain the term ‘Liveware’.
Answer:
People interacting with computers are called Live-ware of the computer system. It consists of the following three groups.
1. System analysts:
System analysts are the people who design data. processing systems.

2. Programmers:
Programmers are the people who write programs for processing data.

3. Operators:
Operators are the people who participate in operating the computer.

Question 2.
What is the Transaction processing system? Name three components of a Transaction processing system.
Answer:
Transaction processing systems (TPS) are among the earliest computerised systems catering to the requirements of large business enterprises. The purpose of a TPS is to record, process, validate and store transactions that occur in the various functional areas of business for subsequent retrieval and usage.
TPS system has three components:

• Input-Processing-Output
• ATM facility.
• Telephone Account and Airline Seat Reservation System are examples of TPS.

Question 3.
Discuss the different types of accounting packages. The accounting packages are classified into the following categories.
Answer:
1. Ready to use accounting software:
It is relatively easier to learn and people adaptability is very high. It is suited to small/ conventional organisations. The level of secrecy is relatively low. This software offers little scope of linking to other information systems.

2. Customised Accounting software:
Helps to meet the special requirement of the user. It is suited to large and medium organisations and can be linked to the other information system.

3. Tailored:
The accounting software is generally tailored in large business organisations with multi-users and geographically scattered locations. This software requires specialised training for users. The level of secrecy is relatively high and they offer high flexibility in terms of number of users.

Question 4.
“Computers are the servants or masters of human beings.” Elucidate.
Answer:
A computer system have certain special features or advantages which in comparison to human beings become its capabilities.
The advantages of computers are as follows:

1. High speed
2. Accuracy
3. Storage of huge data
4. Versatility
5. Deligence

Even though computers possess the above-mentioned features, it suffers from the following limitations:

1. Computers lack common sense.
2. Lack of IQ
3. Lack of decision making skill
4. No feeling

Question 5.
Find out the odd one and state reasons.

1. Mouse, Monitor, Programmers, Processor.
2. DACEASY, FORTRAN, ALU, LINUX
3. Monitor, Barcode reader, Printer, Plotter

Answer:

1. Programmers, others are hardware components.
2. ALU, others are software
3. Barcode reader, others are output devices.

Plus One Accountancy Applications of Computers in Accounting Four Mark Questions and Answers

Question 1.
Find the odd one and state reason.

1. Keyboard, Mouse, Light pen, Printer
2. System Analysts, Language Processors, System software, Utility Programmes.
3. RAM, Floppy disk, Compact disk, Hard disk
4. COBOL, C++, DOS, BASIC

Answer:

1. A printer is an output unit, all others are input units.
2. System Analyst is a human ware.
3. RAM is the Internal memory unit, all others are. external memory unit.
4. DOS is an operating system, all others are computer languages.

Question 2.
Classify the following into input unit and output unit devices.
Keyboard, Mouse, VDU (Visual Display Unit), Printer, Magnetic tape, Magnetic disk, Light pen, Optical scanner, Plotter, Speech synthesiser, MICR, OCR, Barcode reader, Smart card reader, Speaker, LCD projector.
Answer:

Question 3.
What are the generic consideration before sourcing accounting software?
Answer:
The following factors are considered before sourcing accounting software:

1. Flexibility
2. Cost of installation and maintenance
3. Size of organisation
4. Ease of adaptation and training needs
5. Utilities / MIS reports
6. Expected level of secrecy (Software and data)
7. Exporting/importing data facility
8. Vendors reputation and capability

Question 4.
Classify the following components as Hardware, soft-ware and liveware.

1. Programmers
2. Keyboard
3. Windows or Linux
4. COBOL or C++
5. Mouse
6. Assembler or Compiler
7. Operators
8. Virus/Antivirus/ Scanners
9. Monitor
10. Processor
11. System Analysts
12. MS-Excel or MS Office

Answer:
a. Hardware:

• Keyboard
• Mouse
• Monitor
• Processor

b. Software:

• Windows or Linux (Operating System)
• COBOL or C++ (Computer Language)
• Assembler or Compilers (Language processor)
• Virus/Antivirus and Scanner (Utility programs)
• MS Excel or MS Office

c. Liveware:

• System analyst
• Programmers
• Operators

Question 5.
Complete the following diagrams showing the functional relationship of the various components of computers.

Answer:
a. Input devices:

1. Keyboard
2. Mouse
3. Light pen

b. Output devices:

1. Monitor
2. Printers
3. Plotters

c. CPU:

1. Memory unit
2. ALU
3. Control unit

d. Secondary storage devices:

1. Floppy disk
2. Hard disk
3. Optical disk

Plus One Accountancy Applications of Computers in Accounting Five Mark Questions and Answers

Question 1.
Computerised Accounting is different from Manual accounting. Explain.
Answer:
Computerised accounting is different from manual accounting, the following are the main difference between these two:

Plus One Accountancy Applications of Computers in Accounting Six Mark Questions and Answers

Question 1.
What are the elements of a computer system?
Answer:
A computer system is a combination of six elements. They are as follows:
1. Hardware:
The physical components of a computer system is termed as Hardware. Eg: Mouse, Keyboard, Monitor, Processor, etc.

2. Software:
Set of programs that govern the operations of a computer system is termed as soft-ware. There are six types of software as follows.

1. Application software
2. Operating system
3. Utility programs
4. Language processors
5. System software
6. Connectivity software

3. People:
People interacting with computers are also called the “live-wave” of the computer system. It consists of the following three groups.

1. System analysis
2. Programmers
3. Operators

4. Procedures:
The procedure means a series of operations in a certain order or manner to achieve desired results. There are three types of procedures which constitute part of computer system

1. Hardware oriented
2. Software oriented
3. Internal procedure

5. Data:
These are facts and may consist of numbers, text, etc. These are gathered and entered into a computer system.

6. Connectivity:
Tie manner in which a particular computer system is connected to others says through telephone lines, microwave transmission, satellite, etc. is the element of connectivity.

Question 2.
Define computerised accounting. List out various advantages and limitations of computerised accounting system.
Answer:
A computerised accounting system is an accounting information system that processes financial transactions and events to produce reports as per user requirements.
a. Advantages:

1. Speed
2. Accuracy
3. Reliability
4. Efficiency
5. Storage and Retrieval
6. Automated document production
7. Quality reports
8. Real-time user interface

b. Limitations:

1. Huge training costs
2. Staff opposition
3. System failure
4. Breaches of security
5. Inability to check unanticipated errors

Students can Download Chapter 4 Principles of Programming and Problem Solving Questions and Answers, Plus One Computer Science Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus One Computer Science Chapter Wise Questions and Answers Chapter 4 Principles of Programming and Problem Solving

Plus One Principles of Programming and Problem Solving One Mark Questions and Answers

Question 1.
The process of writing program is called _______.
Answer:
programming or coding

Question 2.
One who writes program is called _________
Answer:
Programmer

Question 3.
The step by step procedure to solve a problem is known as ________
Answer:
Algorithm

Question 4.
Diagrammatic representation of an algorithm is known as __________
Answer:
Flow Chart

Question 5.
Program errors are known as _________
Answer:
bugs

Question 6.
Process of detecting and correcting errors is called ________
Answer:
debugging

Question 7.
Mr. Ramu represents an algorithm by using some symbols. This representation is called _______.
Answer:
Flow Chart

Question 8.
Your computer teacher asked you that which symbol is used to indicate beginning or ending flow chart? What is your answer?
(a) Parallelogram
(b) Rectangle
(c) Oval
(d) Rhombus
Answer:
(c) Oval

Question 9.
You are suffering from stomach ache. The doctor prescribes you for a scanning. This process is related in a phase in programming. Which phase is this?
Answer:
Problem identification

Question 10.
Your friend asked you a doubt that to draw a flow chart parallelogram is used for what purpose?
Answer:
To input/output

Question 11.
Mr. Anil wants to perform a multiplication which symbol is used to represent in a flow chart.
Answer:
It is a processing so rectangle is used

Question 12.
Mr. George wants to check a number is greater than zero and to perform an operation while drawing a flow chart which symbol is used for this?
Answer:
Rhombus

Question 13.
ANSI means ________
Answer:
American National Standards Institute

Question 14.
To indicate the flow of an operation which symbol is used to draw a flow chart.
Answer:
Flow lines with arrow heads

Question 15.
Mr. Johnson is drawing a flow chart but it is not fit in a single page. Which symbol will help him to complete the flow chart?
Answer:
Connectors

Question 16.
Mr. Ravi developed a s/w student information system, He wants to protect the s/w from unauthorized copying. There is an act what is it?
Answer:
Copy right act

Question 17.
Odd man out.
(а) Parallelogram
(b) Oval
(c) Rectangle
(d) Star
Answer:
(d) Star, others are flowchart symbols

Question 18.
Odd man out
(a) Oval
(b) Rhombus
(c) Connector
(d) Triangle
Answer:
(d) Triangle, Others are flowchart symbols

Question 19.
Raju wrote a program and he wants to check the errors and correct if any? What process he has to do for this?
Answer:
debugging

Question 20.
Odd one out.
(a) Problem identification
(b) Translation
(c) debugging
(d) copyright
Answer:
(d) Copy right, others are phases in programming

Question 21.
Odd man out.
(a) syntax error
(b) logical error
(c) Runtime error
(d) printer error
Answer:
(d) Printer error, Others are different types of errors

Question 22.
A computerized system is not complete after the execution and testing phase? What is the next phase to complete the system?
Answer:
Documentation.

Question 23.
Mr. Sathian takes a movie DVD from a CD library and he copies this into another DVD without permission. This process is called _______________
Answer:
Piracy

Question 24.
Mr. Santhosh purchased a movie DVD and he takes several copies without permission. He is a _________
(a) Programmer
(b) Administrator
(c) Pirate
(d) Organizer
Answer:
(c) Pirate

Question 25.
The symbol used for copy right is a _______
(a) @
(b) Copy
(c) &
(d) ©
Answer:
(d) ©

Question 26.
Following are the advantages of flowcharts one among them is wrong. Find it.
(a) Better communication
(b) Effective analysis
(c) proper program documentation
(d) Modification easy
Answer:
(d) Modification easy. It is a disadvantage.

Question 27.
Which flow chart symbol has one entry flow and two exit flows?
Answer:
Diamond

Question 28.
Which flow chart symbol is always used in pair?
Answer:
connector

Question 29.
Program written in HLL is known as ____________
Answer:
Source code

Question 30.
Some of the components in the phases of programming are given below. Write them in order of their occurrence. (1)

1. Translation
2. Documentation
3. Problem identification
4. Coding of a program

Answer:
The chronological order is as follows

1. Problem Identification
2. Coding of a program
3. Translation
4. Documentation

Question 31.
_________ is the stage where programming errors are discovered and corrected.
Answer:
Debugging or compiling

Question 32.
Ramesh has written a C++ program. During compilation and execution there were no errors. But he got a wrong output. Name the type of error he faced.
Answer:
Logical Error

Question 33.
Pick out the software which rearranges the scattered files in the hard disk and improves the performance of the system.
(a) Backup software
(b) File compression software
(c) Disk defragmenter
(d) Antivirus software
Answer:
(c) Disk defragmenter

Question 34.
Some phases in programming are given below.

1. Source coding
2. Execution
3. Translation
4. Problem study

These phases should follow a proper order. Choose the correct order from the following:
(a) 4 → 2 → 3 → 1
(b) 1 → 3 → 2 → 4
(c) 1 → 3 → 4 → 2
(d) 4 → 1 → 3 → 2
Answer:
(d) 4 → 1 → 3 → 2

Question 35.
Which one of the following errors is identified at the time of compilation?
(a) Syntax error
(b) Logical error
(c) Run-time error
(d) All of these
Answer:
(a) Syntax error

Question 36.
Pick the odd one out and give a reason for your finding

Answer:
c. This has one entry flow and more than one exit flow.

OR

b. Used for both input and output.

Plus One Principles of Programming and Problem Solving Two Mark Questions and Answers

Question 1.
A debate on ‘Whether Free Software is to be promoted’ is planned in your class. You are asked to present points in support of Free Software. What would be your arguments, (at least three)?
Answer:
Freedom to use Comparatively cheap Freedom to modify and redistribute

Question 2.
Mr. Roy purchased a DVD of a movie and he found that on the cover there is a sentence copyright reserved and a mark ©. What is it? Briefly explain?
Answer:
It is under the act of copyright and the trademark is © copyright is the property right that arises automatically when a person creates a new work by his own and by Law it prevents the others from the unauthorized or intentional copying of this without the permission of the creator.

Question 3.
Can a person who knows only Malayalam talk to a person who knows only Sanskrit normally consider the corresponding situation in a computer program and justify your answer?
Answer:
Normally it is very difficult to communicate. But it is possible with the help of a translator. Translation is the process of converting programs written in High Level Language into Low Level Language (machine Language). The compiler or interpreter is used for this purpose. It is a program.

Question 4.
Define the term, debugging. Write the names of two phases that are included in debugging. (2)

OR

Define the different types of errors that are encountered during the compilation and running of a program.
Answer:
Debugging:
The program errors are called ‘bugs’ and the process of detecting and correcting errors is called debugging. Compilation and running are the two phases.

OR

In general there are two types of errors syntax errors and logical errors. When the rules or syntax of the language are not followed then syntax errors occurred and it is displayed after compilation.

When the logic of a program is wrong then logical errors occurred and it is not displayed after compilation but it is displayed in the execution and testing phase.

Question 5.
Write an algorithm to input the scores obtained in three unit tests and find the average score.

OR

Explain the flowchart and predict the output.
Answer:

• Step 1: Start
• Step 2: Read S1, S2, S3
• Step 3: avg = S1 + S2 + S3/3
• Step 4: Print avg
• Step 5: Stop

OR

This flowchart is used to print the numbers as 1,2, 3, ………, 10.

Question 6.
Differentiate between top down design and bottom up design in problem sloving.
Answer:
Bottom up design:
Here also larger programs are divided into smaller ones and the smaller ones are again subdivided until the lowest level of detail has been reached. We start solving from the lowest module onwards. This approach is called Bottom up design.

Question 7.
Answer any one question from 5 (a) and 5 (b).
1. Draw a flowchart for the following algorithm.

• Step 1: Start
• Step 2: Input N
• Step 3: S = 0, K = 1
• Step 4: S = S + K
• Step 5: K = K + 1
• Step 6: If K < = N Then Go to Step 4
• Step 7: Print S
• Step 8: Stop

OR

2. Name the two stages in programming where debugging process is involved. What kinds of errors are removed in each of these stages?
Answer:
1.

2. The two stages are compile time and run time. In the debugging process can remove syntax error, logical error and runtime error.

Question 8.
Answer any one question from 7(1) and 7(2)
1. Observe the following portion of a flowchart. Fill in the blank symbols with proper instructions to get 321 as the output.

2. The following flowchart can be used to print the numbers from 1 to 100. Identify another problem that can be solved using this flowchart and write the required instructions in the symbols.

Answer:
1.

2. The following flowchart can be used to store another problem such as used to print odd numbers lessthan 200.

Question 9.
Write an algorithm to print the numbers upto 100 in reverse order, That is the output should be as 100, 99, 98, 97, …………., 1

OR

Draw a flow chart to check whether the given number is positive, negative or zero.
Answer:

• Step 1: Start
• Step 2: Set i ← 100
• Step 3: if i <= 0 then go to step 6
• Step 4: Print i
• Step 5: Set i ← i — 1 go to step 3
• Step 6: Stop

OR

Plus One Principles of Programming and Problem Solving Three Mark Questions and Answers

Question 1.
When you try to execute a program, there are chances of errors at various stages, Mention the types of errors and explain.
Answer:
1. Syntax error,
eg: 5 = x

2. Logic error:
If the programmer maks any logical mistakes, it is known as logical error.
eg: To find the sum of values A and B and store it in a variable C you have to write C = A + B. Instead of this if you write C = A × B, it is called logic error.

3. Runtime error:
An error occured at run time due to inappropriate data.
eg: To calculate A/B a person gives zero to B. There is an error called division by zero error during run time.

Question 2.
Following is a flow chart to find and display the largest among three numbers. Some steps are missing in the flowchart. Redraw the flow chart by adding necessary steps and specify its purpose. How can this flow chart be modified without using a fourth variable?
Answer:

Question 3.
A flow chart is given below.

1. What will be the output of the above flow chart?
2. How can you modify the above flow chart to display the even numbers upto 20, starting from 2.

Answer:
1. 1, 2, 3, 4, 5

2.

Question 4.
Write an algorithm to check whether the given number is even or odd.
Answer:

• Step 1: Start
• Step 2: Read a number to N
• Step 3: Divide the number by 2 and store the remainder in R.
• Step 4: If R = O Then go to Step 6
• Step 5: Print “N is odd” go to step 7
• Step 6: Print “N is even”
• Step 7: Stop

Question 5.
Write an algorithm to find the largest of 2 numbers?
Answer:

• Step 1: Start
• Step 2: Input the values of A, B Compare A and B.
• Step 3: If A > B then go to step 5
• Step 4: Print “B is largest” go to Step 6
• Step 5: Print “A is largest”
• Step 6: Stop

Question 6.
Write an algorithm to find the sum of n natural numbers and average?
Answer:

• step 1: Start
• Step 2: Set i ←1, S 0
• Step 3: Read a number and set to n
• Step 4: Computer i and n if i > n then go to step 7.
• Step 5: Set S ← S + i
• Step 6: i ← i + 1 go to step 4
• Step 7: avg ← S/n
• Step 8: Print “Sum = S and average = avg”
• Step 9: Stop

Question 7.
Write an algorithm to find the largest of 3 numbers.
Answer:

• Step 1: Start
• Step 2: Read 3 numbers and store in A, B, C
• Step 3: Compare A and B. lf A > Bthengotostep 6
• Step 4: Compare B and C if C > B then go to step 8
• Step 5: print “B is largest” go to step 9
• Step 6: Compare A and C if C > A then go to step 8
• Step 7: Print”A is largest” go to step 9
• Step 8: Print “C is largest”
• Step 9: Stop

Question 8.
Write an algorithm to calculate the simple interest (I =P × N × R/100)
Answer:

• Step 1: Start
• Step 2: Read 3 values for P, N, R
• Step 3: Calculate I ← P × N × R/100
• Step 4: Print “The simple interest = l”
• Step 5: Stop

Question 9.
Write an algorithm to calculate the compound interest (C.l = P × (1 + r/100)n – P)
Answer:

• Step 1: Start
• Step 2: Read 3 number for p, n, r
• Step 3: Calculate C.I = p × (1 + r/100)n – p
• Step 4: Print “The compound Interest = C.l”
• Step 5: Stop

Question 10.
Write an algorithm to find the cube of first n natural numbers (eg: 1, 8, 27, …., n3)
Answer:

• Step 1: Star
• Step 2: Set i ← 1
• Step 3: Read a number and store in n
• Step 4: Compare i and n if i > n then go to step 7
• Step 5: Print i × i × i
• Step 6: i ← i + 1 go to step 4
• Step 7: Stop

Question 11.
Write an algorithm to read a number and find its factorial (n ! = n × (n – 1) × (n – 2) ×………..3 × 2 × 1)
Answer:

• Step 1: Start
• Step 2: Fact ← 1
• Step 3: Read a number and store in n
• Step 4: If n = 0 then go to step 7
• Step 5: Fact ← Fact × n
• Step 6: n ← n – 1 go to step 4
• Step 7: Print “Factorial is fact”
• Step 8: Stop

Question 12.
Draw a flow chart to find the sum of n natural numbers and average.
Answer:

Question 13.
Draw a flow chart to find the largest of 3 numbers.
Answer:

Question 14.
Draw a flow chart to find the largest of 2 numbers.
Answer:

Question 15.
Draw a flow chart to check whether the given number is even or odd.
Answer:

Question 16.
Draw a flow chart to calculate simple interest.
Answer:

Question 17.
Draw a flow chart to calculate compound interest.
Answer:

Question 18.
Draw a flow chart to find the cube of n natural numbers.
Answer:

Question 19.
Draw a flow chart to read a number and find its factorial.
Answer:

Question 20.
Mr. Vimal wants to represent a problem by using a flowchart, which symbols are used for this. Explain.
Answer:
Flow chart symbols are explained below
1. Terminal (Oval)

It is used to indicate the beginning and ending of a problem

2. Input/Output (parallelogram)

It is used to take input or print output.

3. Processing (Rectangle)

It is used to represent processing. That means to represent arithmetic operation such as addition, subtraction, multiplication.

4. Decision (Rhombus)

It is used to represent decision making. One exit path will be executed at a time.

5. Flowlines (Arrows)

It is used to represent the flow of operation

6. Connector

These symbols will help us to complete the flow chart, which is not fit in a single page. A connector symbol is represented by a circle and a letter or digit is placed within the circle to indicate the link.

Question 21.
Jeena uses an algorithm to represent a problem while Neena uses flowchart which is better? Justify your answer?
Answer:
Flowchart is better. The advantages of flow chart is given below.
1. Better communication:
A flow chart is a pictorial representation while an algorithm is a step by step procedure to solve a program. A programmer can easily explain the program logic using a flow chart.

2. Effective analysis:
The program can be analyzed effectively through the flow chart.

3. Effective synthesis:
If a problem is big it can be divided into small modules and the solution for each module is represented in flowchart separately and can be joined together final system design.

4. Proper program documentation:
A flow chart will help to create a document that will help the company in the absence of a programmer.

5. Efficient coding:
With the help of a flowchart it is easy to write program by using a computer language.

Question 22.
A flow chart is a better method to represent a program. But it has some limitation what are they?
Answer:
The limitations are given below

• To draw a flowchart, it is time consuming and laborious work.
• If any change or modification in the logic we may have to redraw a new flow chart.
• No standards to determine how much detail can include in a flow chart.

Question 23.

Answer:
1 – e
2 – a
3 – d
4 – f
5 – b
6 – c

Question 24.
Alvis executes an error free program but he got an error. Explain different types of error in detail.
Answer:
There are two types of errors in a program before execution and testing phase.They are syntax error and logical error. When the programmer violates the rules or syntax of the programming language then the syntax error occurred.
eg: It involves incorrect punctuation.

Keywords are used for other purposes, violates the structure etc,… It detects the compiler and displays an error message that include the line number and give a clue of the nature of the error, When the programmer makes any mistakes in the logic, that types of errors are called logical error. It does not detect by the compiler but we will get a wrong output.

The program must be tested to check whether it is error free or not. The program must be tested by giving input test data and check whether it is right or wring with the known results. The third type of errors are Runtime errors.

This may be due to the in appropriate data while execution. For example consider B/C. If the end user gives a value zero for c, the execution will be interrupted because division by zero is not possible. These situation must be anticipated and must be handled.

Question 25.
The following are the phases in programming. The order is wrong rearrange them in correct order.

1. Debugging
2. Coding
3. Derive the steps to obtain the solution
4. Documentation
5. Translation
6. Problem identification
7. Execution and testing

Answer:
The correct order is given below.

1. Problem identification
2. Derive the steps to obtain the solution
3. Coding
4. Translation
5. Debugging
6. Execution and testing
7. Documentation

Question 26.
Draw a flow chart to input ten different numbers and find their average.
Answer:

Question 27.
Draw the flow chart to find the sum of first N natural numbers.
Answer:

Question 28.
Make a flow chart using the given labelled symbols, for finding the sum of all even numbers upto ‘N’

OR

Write an algorithm to accept an integer number and print the factors of it.

Answer:
Draw flowchart in any of the following order
e, c, d, f, i, h, a, b, g
e, d, c, f, i, h, a, b, g
e, c, d, a, f, i, h, b, g
e, d, c, a, f, i, h, b, g

• Step 1: Start
• Step 2: Input n
• Step 3: i = I
• Step 4: if i <= n/2 then repeat step 5 & 6
• step 5: if n % i == 0 print i
• Step 6: i = i + I
• Step 7: Stop

Question 29.
List the two approaches followed in problem solving or programming. How do they differ?
Answer:
Approaches in problem solving:
(a) Top down design:
Larger programs are divided into smaller ones and solve each tasks by performing simpler activities. This concept is known as top down design in problem solving

(b) Bottom up design:
Here also larger programs are divided into smaller ones and the smaller ones are again subdivided until the lowest level of detail has been reached. We start solving from the lowest module onwards. This approach is called Bottom up design.

Phases in Programming
1. Problem identification:
This is the first phase in programming. The problem must be identified then only it can be solved, for this we may have to answer some questions.

During this phase we have to identify the data, its type, quantity and formula to be used as well as what activities are involved to get the desired out put is also identified for example if you are suffering from stomach ache and consult a Doctor.

To diagnose the disease the Doctor may ask you some question regarding the diet, duration of pain, previous occurrences etc, and examine some parts of your body by using stethoscope X-ray, scanning etc.

2. Deriving the steps to obtain the solution. There are two methods, Algorithm and flowchart, are used for this.
(a) Algorithm:
The step-by-step procedure to solve a problem is known as algorithm. It comes from the name of a famous Arab mathematician Abu Jafer Mohammed Ibn Musaa Al-Khowarizmi. The last part of his name Al-Khowarizmi was corrected to algorithm.

(b) Flowchart:
The pictorial or graphical representation of an algorithm is called flowchart.

Question 30.
Write an algorithm to find the sum of the squres of the digits of a number. (For example, if 235 is the input, the output should be 2² + 3² + 5² = 38)
Answer:

• Step 1: Start
• Step 2: Set S = O
• Step 3: Read N
• Step 4: if N > O repeat step 5, 6 and 7
• Step 5: Find the remainder. That is rem = N % 10
• Step 6 : S = S + rem × rem
• Step 7 : N = N/10
• Step 8 : Print S
• Step 9 : Stop

Question 31.
Consider the following algorithm and answer the following questions:

• Step 1: Start
• Step 2 : N = 2, S = 0
• Step 3: Repeat Step 4, Step 5 while N <= 10
• Step 4: S = S + N
• Step 5: N = N + 2
• Step 6: Print S
• Step 7: Stop

1. Predict the output of the above algorithm.
2. Draw a flowchart for the above algorithm

Answer:
1. The output is 30

2.

Question 32.
“It is better to give proper documentation within the program”. Give a reason.
Answer:
It is the last phase in programming. A computerized system must be documented properly and it is an ongoing process that starts in the first phase and continues till its implementation. It is helpful for the modification of the program later.

Plus One Principles of Programming and Problem Solving Five Mark Questions and Answers

Question 1.
Mr. Arun wants to develop a program to computerize the functions of supermarket. Explain different phases he has to undergo is detail.

OR

Briefly explain different phases in programming.
Answer:
The different phases in programming is given below:
1. Problem identification:
This is the first phase in programming. The problem must be identified then only it can be solved, for this we may have to answer some questions.
During this phase we have to identify the data, its type, quantity and formula to be used as well as what activities are involved to get the desired output is also identified for example if you are suffering from stomach ache and consult a Doctor.

To diagnose the disease the doctor may ask you some question regarding the diet, duration of pain, previous occurrences, etc and examine some parts of your body by using stethoscope X-ray, scanning, etc.

2. Deriving the steps to obtain the solution.
There are two methods, Algorithm and flowchart, are used for this.
(a) Algorithm:
The step-by-step procedure to solve a problem is known as algorithm. It comes from the name of a famous Arab mathematician Abu Jafer Mohammed Ibu Musaa Al-Khowarizmi. The last part of his name Al-Khowafizmi was corrected to algorithm.

(b) Flowchart:
The pictorial or graphical representation of an algorithm is called flowchart.

3. Coding:
The dummy codes (algorithm)or flow chart is converted into program by using a computer language such s Cobol, Pascal, C++, VB, Java, etc.

4. Translation:
The computer only knows machine language. It does not know HLL, but the human beings HLL is very easy to write programs. Therefore a translation is needed to convert a program written in HLL into machine code (object code).

During this step, the syntax errors of the program will be displayed. These errors are to be corrected and this process will be continued till we get “No errors” message. Then it is ready for execution.

5. Debugging:
The program errors are called ‘bugs’ and the process of detecting and correcting errors is called debugging. In general there are two types of errors syntax errors and logical errors. When the rules or syntax of the language are not followed then syntax errors occurred and it is displayed after compilation.

When the logic of a program is wrong then logical errors occurred and it is not displayed after compilation but it is displayed in the execution and testing phase.

6. Execution and Testing:
In this phase the program will be executed and give test data for testing the purpose of this is to determine whether the result produced by the program is correct or not. There is a chance of another type of error, Run time error, this may be due to inappropriate data.

7. Documentation:
It is the last phase in programming. A computerized system must be documented properly and it is an ongoing process that starts in the first phase and continues till its implementation. It is helpful for the modification of the program later.

Question 2.
Briefly explain the characteristic of an algorithm.
Answer:
The following are the characteristics of an algorithm

1. It must starts with ‘start’ statement and ends with ‘stop’ statement.
2. it should contains instructions to accept input and these are processed by the subsequent instructions.
3. Each and every instruction should be precise and must be clear. The instructions must be possible to carry out, for example consider the examples the instruction “Go to market” is precise and possible to carried out but the instruction “Go to hell” is also precise and can not be carried out.
4. Each instruction must be carried out in finite time by a person with paper and pencil.
5. The number of repetition of instructions must be finite.
6. The desired results must be obtained after the algorithm ends.

Students can Download Chapter 7 Bill of Exchange Questions and Answers, Plus One Accountancy Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus One Accountancy Chapter Wise Questions and Answers Chapter 7 Bill of Exchange

Plus One Accountancy Bill of Exchange One Mark Questions and Answers

Question 1.
The Maker of the bill of exchange is called the ……….
(a) Drawer
(b) Drawee
(c) Payee
Answer:
(a) Drawer.

Question 2.
Bill of exchange before its acceptance is called is ……………
(a) Bill
(b) Promissory Note
(c) Draft
Answer:
(c) Draft.

Question 3.
When a discounted bill is dishonoured, the ………… account is credited in the books of the drawer,
(a) Bank
(b) Drawee
(c) Payee
Answer:
(a) Bank

Question 4.
A bill is noted when it is
(a) Dishonoured
(b) Honoured
(c) Discounted
(d) Accepted
Answer:
(a) Dishonoured

Question 5.
The process of transferring the ownership of the bill is called
(a) Acceptance
(b) Negotiation
(c) Endorsement
Answer:
(c) Endorsement

Question 6.
The credit instrument which contains a promise made by the debtor to pay a certain sum of money for value received is
(a) Bill of Exchange
(b) Debenture
(c) Promissory Note
(d) Equity Share
Answer:
(c) Promissory Note

Question 7.
A bill of exchange is an Instrument.
Answer:
Negotiable

Question 8.
………………. days of grace are allowed in case of time bills for calculating the date of maturity.
Answer:
Three

Question 9.
If the date of maturity of a bill is on a holiday then the bill will mature on ………….. day.
Answer:
The Previous day

Question 10.
When noting charges are paid finally the amount will
be recovered from
Answer:
Drawee.

Question 11.
Complete the following on the basis of hints given

1. Dishonour of discounted bill – An entry in the book of drawer.
2. ………………………………………………. – No entry in the book of drawer.

Answer:
Honouring of discounted bill.

1. Noting charges incurred – When bill is dishonoured.
2. Rebate is allowed – …………………….

Answer:
When bill is honoured before due date.

Question 12.
Bill of exchange in Indian languages is called
Answer:
Hundi.

Question 13.
The person to whom the amount mentioned in the promissory note is payable is known as ………………..
Answer:
Promisee.

Question 14.
A person who endorse the promissory note in favour of another is known as ………………..
Answer:
Endorser

Question 15.
In a promissory note, the person who makes the promise to pay is called ……………………
Answer:
Promissor.

Question 16.
Bill of exchange is drawn on the ………….
Answer:
Debtor/Drawee.

Question 17.
The person to whom payment of the bill is to be made is known as ……………….
Answer:
Payee

Question 18.
A promissory note does not require ………..
Answer:
Acceptance.

Question 19.
Making payment of the bill of exchange before the due date is called …………..
Answer:
Retiring of the bill

Question 20.
A bill of exchange accepted without consideration, just to oblige a friend is known as
Answer:
Accommodation Bill

Question 21.
If the proceeds of the bill of exchange is to be paid after a particular period is called …………
Answer:
Time Bill.

Question 22.
Find the odd one and state the reasons.

1. Bill of exchange, cheque, promissory note, fixed deposit receipt.
2. Drawer, Drawee, Payee, Endorser.

Answer:

1. Fixed Deposit Receipt – Others are negotiable instruments
2. Drawee – Others may be the same person

Question 23.
On the date of maturity, Arun (acceptor) requested to Santhosh (drawer) to cancel the old bill and draw a new bill upon him for a period of 2 months. Santhosh agrees to this. It is a case of ………………
Answer:
Renewal of bill

Plus One Accountancy Bill of Exchange Two Mark Questions and Answers

Question 1.
A bill of exchange must contain “an unconditional promise to pay.” Do you agree with a statement?
Answer:
No. The bill of exchange contains an unconditional order to pay a certain amount on an agreed date.

Question 2.
Define Bill of exchange.
Answer:
According to the Negotiable Instruments Act, 1881 a bill of exchange is “an instrument in writing containing an unconditional order, signed by the maker, directing a certain person to pay a certain sum of money only to, or to the order of a certain person, or to the bearer of the instrument.”

Question 3.
What are the features of bill of exchange?
Answer:
Following are the essential features of a bill of exchange.

1. It must be in writing.
2. It must be an order to pay, and not a request to pay.
3. No condition should be attached to the order.
4. The drawer must sign the bill
5. The order must be for the payment of money only.
6. It should be properly stamped.
7. The amount mentioned in the bill may be made payable either on demand or after the expiry of a ‘stipulated period.

Question 4.
Who are.the parties to a bill of exchange ?
Answer:
There are three parties to a bill of exchange:

1. Drawer – He is the creditor who draws a bill of exchange upon the debtor.
2. Drawee – He is the person upon whom the bill of exchange is drawn. He is the purchaser of the goods on credit and the debtor.
3. Payee – He is the person to whom payment of the bill is to be made on the maturity date. The drawer and the payee can be one party when payment is to be made to the drawer.

Question 5.
What are days of grace?
Answer:
Three extra days over the nominal due date legally given to the acceptor of a bill to make payment are called days of grace. Days of grace are allowed only in the case of time bills.

Question 6.
Calculate the maturity date of the following bill.

1. Drawn on January 5^th for three months.
2. Drawn on May 1^st for 4 months.

Answer:
1.

• January 5^th to February 5^th
• February 5^th to March 5^th
• March 5^th to April 5^th
• April 5^th + 3 days of grace = April 8^th

2.

• May 1^st – June 1^st
• June 1^st – July 1^st
• July 1^st – August 1^st
• August 1^st – September 1^st
• September 1^st + 3 days of grace = September 4^th

Question 7.
What do you mean by Endorsement?
Answer:
An endorsement is a written order on the back of the instrument by the payee or the holder, for transferring his right to another person. The person who makes the endorsement is called endorser and in whose favour the endorsement is made is called the endorsee.

Question 8.
What is an Accommodation Bill?
Answer:
A bill of exchange and Promissory note may be used for raising funds temporarily. Such a bill is called an ‘accommodation bill’ as it is accepted by the drawee to accommodate the drawer. These are drawn and accepted without consideration with a view to provide funds to one or more parties. There is no trade or debtor-creditor pfifationsip between parties. It is also known as ‘kite bill’ or ‘Wind bill’.

Question 9.
Ram received a bill from Anil on 1/7/2009 for 3 months for Rs. 4,000. Later the bill has been endorsed to Kumar. In this statement identify the parties involved in terms of drawer, drawee endorser and payee.
Answer:

• Drawer – Ram
• Drawee – Anil
• Payee – Kumar
• Endorsee – Kumar

Question 10.
Manu purchased goods on credit from Kumar for Rs. 40,0 on 1^st April 2009. On the same date Kumar draws a bill for 2 months and got it accepted by Manu. What are the options available to Kumar in dealing with the bill?
Answer:
The following options are available to deal with the bill.

1. He can retain the bill till the date of maturity.
2. He can get the bill discounted through the bank.
3. He can endorse the bill in favour of his creditor.
4. He may sent the bill for collection to the bank.

Question 11.
Mr. Mohan holds a bill of exchange. He approaches a bank to receive the amount of bill before the maturity date. Does he get the money? Write your comments,
Answer:
If the drawer of the bill needs cash immediately or before the maturity date he can discount the bill with the bank. Discounting of the bill means encashing the bill with the banker on the security of the bill before the maturity date. The banker will deduct a certain sum from the bill amount as discount and pays the balance to the holder. The bank will present the bill to the drawee on the due date and get the payment of the bill.

Question 12.
Explain the term “Noting”
Answer:
When a bill of exchange is dishonoured due to nonpayment, it is usual to get it ‘noted’, to establish the matter of dishonour legally. The noting is done by the “Notary public”, who is an officer appointed by the Government for this purpose. Noting authenticates the facts of dishonour.

For providing this service, a number of fees is charged which is called “Noting charges” Noting charges either paid by the holder or any other parties should be borne by the acceptor in the absence of any agreement.

Question 13.
What do you mean by ‘Retiring of Bill’?
Answer:
The acceptor can pay the amount of the bill before its due date. The process of paying the amount of the bills payable before the due date is called retiring the bill. In such case, the holder usually allows some discount to the acceptor of bill. Such a discount is called “rebate on retired bill”. The amount of rebate depends on the period that the bill has yet to run.

Question 14.
What do you mean by Renewal of Bills?
Answer:
process of drawing and accepting a new bill by cancelling the old bill is called renewal of a bill. It is a granting of extension of credit to the acceptor. When this is done the acceptor may have to pay interest for the extended period of credit. It is paid in cash or may be included in the amount of the new bill.

Question 15.
On 1.1.2005 Raju sold goods to Anil for Rs. 20,000/ – and draw upon him a bill for 2 months. Anil accepted the bill and returned it to Raju. Later Raju endorsed the bill to Tom. On the date of maturity the bill was dishonoured.
Give advice to Tom, regarding the steps to be undertaken immediately after the dishonour.
Answer:
1. The holder of the bill, Tom should send a notice of dishonour to the drawer, Raju within a reasonable time. Otherwise, the other parties of the bill may deny their liability.

2. When the bill is dishonoured it is better to get the fact noted with a Notary public.

Question 16.
Identify the endorser, endorsee and type of endorsement from the following

Answer:

• Endorser – Santhosh
• Endorsee – Arunkumar
• Type – Conditional Endorsement

Plus One Accountancy Bill of Exchange Three Mark Questions and Answers

Question 1.
Define promissory Note and Point out its Features.
Answer:
According to the Negotiable Instruments Act 1881, a promissory note is “an instrument in writing containing an unconditional undertaking, signed by the maker, to pay a certain sum of money only to or to the order of a certain person, or to the bearer of the instrument.”
The following are the features of promissory note

1. It must be in writing
2. It must contain an unconditional promise to pay.
3. It must be signed by the maker
4. The person to whom payment is to be made must also be certain.
5. The amount payable must be certain.
6. It should be properly stamped.

Question 2.
Who are the parties to a promissory note:
Answer:
There are two parties to a promissory note.
1. The maker or the promisor:
He is the person who makes or draws the promissory notable is the debtor.

2. The payee or the promisee:
He is a person in whose favour the promissiory note is drawn.

Question 3.
Syam sold goods to Anil on credit for Rs. 3,000, on 10th April 2003. He drew a bill on Anil for the amount at 3 months after date. Anil accepted the same and returned it to syam. At maturity, he met his obligation. Pass journal entries in the books of both parties.
Answer:
Book of Syam (Drawer) Journal

Book of Anil [Drawee] Journal

Question 4.
Haridas discounts a bill for Rs. 10,000 with his banker on 4th February, 2007. The bill was drawn on 1^st January for Four months. The discount rate was 12%. p.a. write Journal entries in the book of Haridas.
Answer:
Book of Haridas [Drawer] Journal


Note: Calculation of discount
Discount = 10.000 × 12/100 × 3/12 = 300 It may be noted that discount has been charged for three months and not for 4 months because the bank will have to wait for 3 months to get the payment of bill on the due date.

Question 5.
From the given specimen of a promissory note identify:-
a) Promisor
b) Promisee
c) Consideration

Answer:

Plus One Accountancy Bill of Exchange Four Mark Questions and Answers

Question 1.
On January 1^st, 2006, Ramesh sold goods worth ₹2,000 to Kannan and drew abill for the amount for 3 months. Kannan accepted the bill and returned it to Ramesh. Ramesh endorsed the bill in favour of Jayan, on 6^th January. The bill was duly met on maturity. Pass journal entries in the book of Ramesh, Kannan and Jayan.
Answer:
Book of Ramesh [Drawer] Journal

Book of Kannan [Drawee] Journal

Book of Jayan [Endorser] Journal

Question 2.
On 10^th March 2004, Chandran drew and Devan accepted a 2 months bill for Rs. 2000. On April 11 Chandran sends the bill to his bank for collection. On due date the amount is collected. Give journal entries in the book of both the parties.
Answer:
Journal (In the book of Chandran)

Journal (In the book of Devan)

Question 3.
On 1^st June 2005, ‘A’ Sold goods to ‘B’ worth Rs.
20,000 and drew on him a bill for 3 months. ‘B’ accepted the same and returned to ‘A’. On 5^th June 2005, ‘A’ discounted the bill with his banker and received Rs. 19,000. On the due date, ‘B’ failed to pay the amount and the bill got dishonoured. Pass journal entries in the books of A and B.
Answer:
Book of A [Drawer] Journal

Book of B [Drawee] Journal

Question 4.
Identify the document shown below and state Any 6 features of the document.

Answer:
Document is a Bill of Exchange.
Features:

1. It contains an order to pay money.
2. The order shortly be unconditional
3. The drawer must sign the bill
4. The drawee must be a certain person.
5. The order must be for the payment of money only.
6. It should be properly stamped.

Question 5.
From the given specimen of Bill of exchange, identify:

1. Drawer
2. Drawee
3. Payee
4. Term of bill
5. Date of maturity
6. Consideration on the bill

Answer:

Question 6.
Complete the following table.

Answer:

1. Debtor
2. Order or promise, order to make payment
3. Needs acceptance by drawee/does not need any acceptance.
4. Three – Drawer, Drawee, Payee Two – Drawer and payee
5. Drawer has secondary liability.

Question 7.
Complete the journal on the basis of the narration given for a bill of exchange of Rs. 20,000/-
Book of Santhosh Journal

Answer:
Journal Book of Santhosh

Plus One Accountancy Bill of Exchange Five Mark Questions and Answers

Question 1.
Ajay sold goods to Babu for Rs. 2,700 on 1.1.2007 and immediately drawn a bill for 4 months upon Babu for the same amount Babu accepted the bill and returned it to Ajay. On the 4^th February 2007, Babu retires his acceptance under a rebate of 12% p.a. Give journal entries in the books of both the parties.
Answer:
Book of Ajay [Drawer] Journal


Book of Babu [Drawee] Journal