Prasanna

Students can Download Chapter 1 Physical World Questions and Answers, Plus One Physics Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus One Physics Chapter Wise Questions and Answers Chapter 1 Physical World

Plus One Physics Physical World One Mark Questions and Answers

Question 1.
The word ‘Science’ originated from a Latin verb. Which is that verb?
Answer:
‘Scientia’ means ‘to know’.

Question 2.
The word physics comes from a Greek word______.
Answer:
‘Fusis’ means ‘nature’.

Question 3.
Name the branch of science that deals with

1. Study of stars
2. Study of earth

Answer:

1. Astronomy
2. Geology

Plus One Physics Physical World Three Mark Questions and Answers

Question 1.
Fill in the blanks

Answer:

Students can Download Chapter 16 Probability Questions and Answers, Plus One Maths Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus One Maths Chapter Wise Questions and Answers Chapter 16 Probability

Plus One Maths Probability Three Mark Questions and Answers

Question 1.
Two dice are thrown. The events A, B and C are as follows:

1. A: getting an even number on the first die.
2. B: getting an odd number on the first die.
3. C: getting sum of the numbers on the dice ≤ 5.

Describe the events.
Answer:

1. A = {(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}
2. B = {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6),(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)}
3. C = {(1, 1), (1, 2), (2, 1), (2, 2), (1, 3), (3, 1), (2, 3), (3, 2), (1, 4), (4, 1)}

Question 2.
A bag contains 6 red and 12 green balls. Two balls are drawn. What is the probability that one is red and other is green?
Answer:
Here total number of balls = 6 + 12 = 18 Two balls from 18 can be drawn in
¹⁸C₂ = \(\frac{18 \times 17}{1 \times 2}\) = 153
One red ball out of 6 red can be drawn in ⁶C₁ = 6 ways. One green balls from 12 green may be done in ¹²C₁ = 12 ways.
Therefore, number of favorable cases
= 6 × 12 = 72
The probability that one is red and other is green \(=\frac{72}{153}=\frac{8}{17}\).

Question 3.
In class XI of a school 40% of the students study Mathematics and 30% study Biology, 10% of the class study both Mathematics and Biology. If a student is selected at random from the class, find the probability that he will be studying Mathematics or Biology.
Answer:
Let M- Mathematics and B – Biology be the events.
P(M) = \(\frac{40}{100}\) = \(\frac{2}{5}\); P(B) = \(\frac{3}{10}\);
P(M ∩ B) = \(\frac{1}{10}\)
P(M ∪ B) = P(M) + P(B) – P(M ∩ B)

Plus One Maths Probability Four Mark Questions and Answers

Question 1.
Two die are rolled, A is the event that the sum of the numbers shown on the two die is 7 and B is the event that at least one of the die shows up 2. Are the two events A and B

1. Mutually exclusive
2. Exhaustive.

Answer:
S = {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5),(2,6), (3, 1) , (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}
A = {(6, 1), (1, 6), (4, 3), (3, 4), (2, 5), (5, 2)}
B = {(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (1, 2), (3, 2), (4, 2), (5, 2), (6, 2)}
1. Now; A ∩ B = {(2, 5), (5, 2)} ≠ Φ
Therefore not mutually exclusive.

2. A ∪ B = {(6, 1), (1, 6), (4, 3), (3, 4), (2, 5), (5, 2), (2, 1), (2, 2), (2, 3), (2, 4), (2, 6), (1, 2), (3, 2), (4, 2), (6, 2)} ≠ S
Therefore not mutually exhaustive.

Question 2.
A letters of the word ASSASSINATION are randomly chosen. Find the probability that letter is

1. a vowels. (2)
2. a consonant (2)

Answer:
There 13 letter in the word, with 6 vowels and 7 consonants.
One letter is selected out of 13 in ¹³C₁ = 13 ways.
1. One vowel is selected out of 6 in ⁶C₁ = 6 ways.
Thus the probability of a vowel = \(\frac{6}{13}\).

2. One consonant is selected out of 7 in ⁷C₁ = 7 ways.
Thus the probability of a consonant = \(\frac{7}{13}\).

Question 3.
If E and F are events such that P(E) = \(\frac{1}{4}\), P(F) = \(\frac{1}{2}\) and P(E and F) = \(\frac{1}{8}\). Find

1. P(E or F)
2. P(not E and not F)

Answer:
P(E) = \(\frac{1}{4}\), P(F) = \(\frac{1}{2}\); P(E ∩ F) = \(\frac{1}{8}\)
1. P(E ∪ F) = P(E) + P(F) – P(E ∩ F)

2. P(not E and not F) = P(E’ ∩ F’) = P(E ∪ F)’
= 1 – P(E ∪ F) = 1 – \(\frac{5}{8}\) = \(\frac{3}{8}\)

Plus One Maths Probability Practice Problems Questions and Answers

Question 1.
A die is thrown. Describe the following events: (1 score each)

1. A: a number less than 7.
2. B: a number greater than 7.
3. C: a multiple of 3:
4. D: a number less than 4.
5. E: An even number greater than 4.
6. F: a number not less than 3.

Also find
A ∪ B, A ∩ B, B ∪ C, E ∩ F, D ∩ E, A – C, D – E F’, E ∩ F’.
Answer:

1. A = {1, 2, 3, 4, 5, 6}
2. B = Φ
3. C = {3, 6}
4. D = {1, 2, 3}
5. E = {6}
6. F = {3, 4, 5, 6}

Now; A ∪ B = {1, 2, 3, 4, 5, 6}
A ∩ B = Φ; B ∪ C = {3, 6}, E ∩ F = {6}
F’ = {1, 2}, E ∩ F’ = Φ.

Question 2.
Describe the sample space for the following events: (2 score each)

1. A coin is tossed and a die is thrown.
2. A coin is tossed and then a die is rolled.
3. 2 boys and 2 girls are in a Room X and 1 boy and 3 girls in Room Y. Specify the sample space for the experiment in which a room is selected and then a person.
4. One die of red colour, one of white colour and one of blue colour are placed in a bag. One die is selected at random and rolled, its colour and the number on its upper most face is noted.
5. An experiment consists of tossing a coin and then throwing it second time if a head occur. If a tail occurs on the first toss, then a die is rolled once.
6. A coin is tossed. If the outcome is a head, a die is thrown. If the die shows up shows up an head, a die is thrown. If the die shows up an even number, the die is thrown again.

Answer:
1. A coin is tossed then S₁ = {H, T}
A die is rolled then S₂ = {1, 2, 3, 4, 5, 6}
Hence sample space
S = {H1, H2, H3, H4, H5, H6, T1, T2, T3, T4, T5, T6}.

2. A coin is tossed then S₁ = {H, T}
A die is rolled then S₂ = {1, 2, 3, 4, 5, 6}
Hence sample space S = {H1, H2, H3,H4, H5,H6, T}

3. Let B₁, B₂ denote the boys and G₁, G₂ girls in room X, B₁ denote the boys and G₃, G₄, G₅ girls in room Y. Hence sample space
S = {XB₁, XB₂, XG₁, XG₂, YB₁, YG₃, XG₄, XG₅}

4. Three die are R,W, and B, then S₁ = {R, W, B)
A die is rolled then S₂ = {1, 2, 3, 4, 5, 6}
Hence sample space S = {R1, R2, R3, R4, R5, R6, W1, W2, W3, W4, W5, W6, B1, B2, B3, B4, B5, B6}

5. A coin is tossed then S₁ = {H, T}
A coin tossed again then S₂ = {H, T}
A die is rolled then S₃ = {1, 2, 3, 4, 5, 6}
Hence sample space
S = {HH, HT, T1, T2, T3, T4, T5, T6}

6. A coin is tossed then S₁ = {H, T}
When the coin shows T, then there is no action. When the coin shows H, a die is thrown
S₂ = {1, 2, 3, 4, 5, 6}
When the die shows {1, 3, 5}, then there is no action.
When the die shows {2, 4, 6}, then a die is thrown again.
Hence;
S = {T, H1, H3, H5, H21, H22, H23, H24, H25, H26, H41, H42, H43, H44, H45, H46,H61, H62, H63, H64, H65, H66}.

Question 3.
A die is rolled. Let E be the event “die shows 4” and F be the event “die shows even number”. Are E and F mutually exclusive?
Answer:
When die is rolled the sample space is S = {1, 2, 3, 4, 5, 6}.
E: die shows 4 = {4}
F: die shows even number = {2, 4, 6}
Now E ∩ F = {4} ≠ Φ
Thus E and F are not mutually exclusive.

Question 4.
Two die are thrown simultaneously. Find the probability of getting 4 as the product.
Answer:
n(S) = 36
A = {(1, 4), (4, 1), (2, 2)}
P(A) = \(\frac{n(A)}{n(S)}=\frac{3}{36}=\frac{1}{12}\).

Question 5.
A coin is tossed, twice, what is the probability that atleast one tail occurs?
Answer:
Here, S = {HH, HT, TH, TT}; n(S) = 4
A = {TH, HT, TT}; n(A) = 3
P(A) = \(\frac{n(A)}{n(S)}=\frac{3}{4}\).

Question 6.
A die is rolled, find the probability of following events: (2 score each)

1. A prime number will appear.
2. A number greater than or equal to 3 will appear.
3. A number less than or equal to one will appear.
4. A number more than 6 will appear.
5. A number less than 6 will appear.

Answer:
Here sample space is S = {1, 2, 3, 4, 5, 6}
1. A: A prime number will appear A = {2, 3, 5};
P(A) = \(\frac{n(A)}{n(S)}=\frac{3}{6}=\frac{1}{2}\)

2. B: A number greater than or equal to 3 will appear. B = {3, 4, 5, 6};
P(B) = \(\frac{n(B)}{n(S)}=\frac{4}{6}=\frac{2}{3}\)

3. C: A number less than or equal to one will appear. C = {1};
P(C) = \(\frac{n(C)}{n(S)}=\frac{1}{6}\)

4. D: A number more than 6 will appear.
D = Φ; P(D) = \(\frac{n(D)}{n(S)}=\frac{0}{6}=0\)

5. E: A number less than 6 will appear. E = {1, 2, 3, 4, 5, 6};
P(E) = \(\frac{n(E)}{n(S)}=\frac{6}{6}=1\).

Question 7.
One card is drawn from a pack of 52 cards, each of the 52 cards being equally likely to be drawn. Find the probability that (2 score each)

1. The card drawn is black.
2. The card drawn is a king.
3. The card drawn is black and a king.
4. The card drawn is either black ora king.

Answer:
1. A pack of 52 cards has 26 black cards. So one black card may be drawn in 26 ways. Therefore; Probability of card drawn is black
= \(\frac{26}{52}=\frac{1}{2}\)

2. A pack of 52 cards has 4 kings. So one king card may be drawn in 4 ways. Therefore; Probability of drawing a king
= \(\frac{4}{52}=\frac{1}{13}\)

3. A pack of 52 cards has 2 black king cards. So one black king card may be drawn in 2 ways. Therefore; Probability of drawing a king
= \(\frac{2}{52}=\frac{1}{26}\)

4. A pack of 52 cards has 26 black cards which include 2 black king and 2 red king cards. So number of cards which are black or king cards
= 26 + 2 = 28.
Therefore; Probability of drawing either a black or king card = = \(\frac{28}{52}=\frac{7}{13}\).

Question 8.
GivenP(A) = \(\frac{3}{5}\) and P(B) = \(\frac{1}{5}\). Find P(A or B), if A and B are mutually exclusive events.
Answer:
Here; P(A) = \(\frac{3}{5}\) and P(B) = \(\frac{1}{5}\)
Since A and B mutually exclusive events
P(A ∪ B) = P(A) + P(B)

Students can Download Chapter 15 Statistics Questions and Answers, Plus One Maths Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus One Maths Chapter Wise Questions and Answers Chapter 15 Statistics

Plus One Maths Statistics Three Mark Questions and Answers

Question 1.
Find the mean deviation about the median for the following data: (3 score each)

1. 13, 17, 16, 14, 11, 13, 10, 16, 11, 18, 12, 17.
2. 36, 72, 46, 42, 60, 45, 53, 46, 51, 49.

Answer:
1. Arrange the data in the ascending order we have;
10, 11, 11, 12, 13, 13, 14, 16, 16, 17, 17, 18
Here n = 12. So median is the average of 6^th and 7^th observations.
Therefore; Median, M =\(\frac{13+14}{2}\) = 13.5

Mean deviation = \(\frac{\sum_{i=1}^{n}\left|x_{i}-M\right|}{n}=\frac{28}{12}\) = 2.33

2. Arrange the data in the ascending order we have; 36, 42, 45, 46, 46, 49, 51, 53, 60, 72
Here n = 10. So median is the average of 5^th and 6^th observations.
Therefore; Median, M = \(\frac{46+49}{2}\) = 47.5

Mean deviation = \(\frac{\sum_{i=1}^{n}\left|x_{i}-M\right|}{n}=\frac{70}{10}\) = 7.

Question 2.
The mean and standard deviation of marks obtained by 50 students of a class in three subjects, mathematics, Physics, and Chemistry are given below:

Which of the three subject shows the highest variability in marks and which shows the lowest?
Answer:
For Mathematics:
\(\bar{x}\) = 42, σ = 12
∴ CV of Mathematics = \(\frac{12}{42}\) × 100 = 28.57%
For Physics:
\(\bar{x}\) = 32, σ = 15
∴ CV of Physics = \(\frac{15}{32}\) × 100 = 46.88%
For Chemistry:
\(\bar{x}\) = 40.9, σ = 20
∴ CV of Chemistry = \(\frac{20}{40.9}\) × 100 = 48.9%
Thus Chemistry with highest CV shows highest variability and Mathematics with lowest CV shows lowest variability.

Plus One Maths Statistics Four Mark Questions and Answers

Question 1.
Find the mean deviation about the mean for the following data: (4 score each)
1.

2.

Answer:
1.

2.

Question 2.
Find the mean deviation about the median for the following data: (4 score each)
1.

2.

Answer:
1.

\(\frac{\sum_{i=1}^{n} f_{i}}{2}=\frac{26}{2}\) = 13
The c.f just greater than 13 is 14 and corresponding value of x is 7. Therefore; median, M = 7
Hence; M.D about median

2.

\(\frac{\sum_{i=1}^{n} f_{i}}{2}=\frac{29}{2}\) = 14.5
The c.f just greater than 14.5 is 21 and corresponding value of x is 30. Therefore; median, M = 30
Hence; M.D about median

Question 3.
Find the mean deviation about the mean for the following data: (4 score each)
1.

2.

Answer:
1.

2.

Question 4.
Find the mean deviation about the median for the following data: (4 score each)
1.

2.

Answer:
1.

Median class is the class in which the \(\left(\frac{N}{2}\right)^{th}\) observation lies.
\(\frac{N}{2}=\frac{50}{2}\) = 25
Median class = 20 – 30
M = Median

2.

Median class is the class in which the \(\left(\frac{N}{2}\right)^{th}\) observation lies.
\(\frac{N}{2}=\frac{100}{2}\) = 50
Median class = 35.5 – 40.5
M = Median

Question 5.
Find the variance and standard deviation of 3, 4, 6, 5, 5, 3, 8, 1, 7, 5
Answer:



\(\frac{259}{10}\) – (4.7)² = 25.9 – 22.09 = 3.8
Standard Deviation (σ) = \(\sqrt{\text {Variance}}\) = \(\sqrt{3.8}\) =1.95.

Question 6.
Find the variance and standard deviation of

Answer:


Standard Deviation (σ) = \(\sqrt{\text {Variance}}\)
= \(\sqrt{15.08}\) = 3.88.

Question 7.
An analysis of monthly wages paid to workers in two firms A and B, belonging to the same industry, gives the following result.

1. Which firm A or B pays larger amount as monthly wages?
2. Which firm A or B, shows greater variability in individual wages?

Answer:
1. Firm: A
Number of wages earners (n₁) = 586
Number of wages earners (\(\bar{x}_{1}\)) = 5253
Total monthly wages = 5253 × 586 = 3078258
Firm: B
Number of wages earners (n₁) = 648
Number of wages earners (\(\bar{x}_{1}\)) = 5253
Total monthly wages = 5253 × 648 = 3403944

2. Since both the firms have same mean of monthly wages, so the firm with greater variance will have more variability in individual wages. Thus firm B will have more variability in individual wages.

Question 8.
The sum and sum of squares corresponding to length x (in cm) and weight y (in gm) of 50 plant products are given below:

which is more varying, the length or weight?
Answer:
Here,

Now

C.V of weight = \(\frac{1.38}{5.22}\) × 100 = 26.44
C.V of weight > C.V of length
Thus weight have more variability than length

Plus One Maths Statistics Six Mark Questions and Answers

Question 1.
Find the variance and standard deviation of

Answer:

Standard Deviation (a) = \(\sqrt{\text {Variance}}\)
= \(\sqrt{223.22}\) = 14.94.

Plus One Maths Statistics Practice Problems Questions and Answers

Question 1.
Find the mean deviation about the mean for the following data: (2 score each)

1. 4, 7, 8, 9, 10, 12, 13, 17.
2. 38, 70, 48, 40, 42, 55, 63, 46, 54, 44.

Answer:
1.

2.

Students can Download Chapter 11 Computer Networks Questions and Answers, Plus One Computer Science Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus One Computer Science Chapter Wise Questions and Answers Chapter 11 Computer Networks

Plus One Computer Networks One Mark Questions and Answers

Question 1.
An interconnected collection of autonomous computers is called _________
Answer:
Computer Networks

Question 2.
State true/false
A computer connected to a network is called work station.
Answer:
True

Question 3.
A work station is also called
Answer:
Node

Question 4.
Which hardware is used to connect a work station to a network?
Answer:
Network Interface Card (NIC)

Question 5.
Rules and convention to transmit data on a network is called _________
Answer:
Protocol

Question 6
In your computer lab sometimes you can see that cable from some computers are connected to a small box. What is it?
Answer:
It is a Hub/Switch

Question 7.
The computers connected in your school lab is a _________ type network.
Answer:
Local Area Network

Question 8.
A Cable TV Network that spread over the city is a _________ type network.
Answer:
Metropolitan Area Network

Question 9.
Internet is a __________type network.
Answer:
Wide Area Network

Question 10.
The school management is decided to connect computers in your HSS lab and high school lab located adjacent buildings. Which type of network is this?
Answer:
Local Area Network

Question 11.
A company decided to connect the computers of their branch located in another city away from 10 km. Name this network.
Answer:
Metropolitan Area Network

Question 12.
Geometrical arrangement of computers in a network is called _________
Answer:
Topology

Question 13.
From the following select an ISP.
(a) KSEB
(b) KSRTC
(c) BSNL
(d) PWD
Answer:
(c) BSNL

Question 14.
ISP means
Answer:
Internet service provider

Question 15.
ISDN means
Answer:
Integrated services digital network

Question 16.
State true/false.
In peer to peer configuration all the computers are with equal configuration.
Answer:
True

Question 17.
State true/false.
In client server configuration, a computer is powerful than others.
Answer:
True

Question 18.
Consider the following address.
http://www.nic.kerala.gov.in, “in” is used to represent what?
Answer:
“in” is used to represent the country “India”.

Question 19.
Which top level domain is used for non commercial organisation?
Answer:
org

Question 20.
Which geographical top level domain is used for the country “France”?
Answer:
Fr

Question 21.
DNS stands for.
Answer:
Domain Name System

Question 22.
An IP address consists of bits long.
(a) 4
(b) 16
(c) 32
(d) 64
Answer:
(c) 32 bits

Question 23.
An IP address consists of bytes long.
(a) 4
(b) 16
(c) 32
(d) 64
Answer:
(a) 4 Bytes

Question 24.
From the following which media is using light rays for data transfer.
(a) Twisted pair cable
(b) Optical fibre
(c) Coanial cable
(d) Microwave station
Answer:
(b) Optical fibre

Question 25.
The wiring is not shared in a topology. Which is that topology?
Answer:
Star

Question 26.
________ is a combination of any two or more network topologies.
Answer:
Hybrid Topology

Question 27.
The nodes in a topology with two or more paths. Which topology is this?
Answer:
Mesh topology

Question 28.
Copying the signals from the earth to satellite is called __________
Answer:
Uplink

Question 29.
Copying the signals from the satellite to earth is called ____________
Answer:
Downlink, Mesh topology

Question 30.
In very short distance networks, which communication media is used?
Answer:
Twisted pair cables or coaxial cables.

Question 31.
In long distance networks, which communication medias are used?
Answer:
microwave station, satellites, etc.

Question 32.
From the following which connector is used to connect UTP/STP twisted pair cable to a computer.
(a) RJ – 45
(b) RS – 1
(c) CG – 1
(d) None of these.
Answer:
(a) RJ – 45

Question 33.
The cable media that use light to transmit data signals to very long distance is ________.
Answer:
Optical fibre cable

Question 34.
AM and FM radio broadcast and mobile phones make use of _________ medium for transmission.
Answer:
Radio waves

Question 35.
A short range communication technology that does not require line of sight between communicating device is __________.
Answer:
Wi-Fi

Question 36.
A communication system that is very expensive, but has a large coverage area when compared to other wireless communication system is ______
Answer:
Satellite link

Question 37.
In which topology is every node connected to other nodes?
Answer:
Mesh topology

Question 38.
Any device which is directly connected to a network is generally known as ___________
Answer:
Node or Work station or Client or Terminal

Question 39.
In ____________ topology all the nodes are connected to a main cable. (1)
Answer:
Bus topology

Question 40.
Write the full from of FTTH.
Answer:
Fibre To The Home

Question 41.
Which one of the following statements is TRUE in relation with Wi-MAX Internet connectivity?
(a) make use of satellite connection
(b) Uses cable connection
(c) Uses laser beam for connection
(d) Microwave is used for connectivity
Answer:
(d) Microwave is used for connectivity

Question 42.
Identify the type of LAN topology in which there are more than one path between nodes,
(a) Star
(b) Ring
(c) Mesh
(d) Bus
Answer:
(c) Mesh topology

Question 43.

1. To make data transfer faster, a switch stores two different addresses of all the devices connected to it. Which are they?
2. Name the device that can interconnect two different networks having different protocols.

Answer:

1. IP and MAC address
2. Gateway

Question 44.

1. Different networks with different protocols are connected by a device called ________
   • Router
   • Bridge
   • Switch
   • Gateway
2. Define Protocol

Answer:

1. Gateway
2. Protocol: The rules and conventions for transmitting data.

Plus One Computer Networks Two Mark Questions and Answers

Question 1.
Is it possible to connect all the computers to a network? Justify your answer.
Answer:
No. It is not possible to connect all the computers to a network. A computer, with a hardware called Network Interface Card (NIC), can only connect to a network.

Question 2.
Define Computer Networks?
Answer:
Two or more computers connected through a communication media that allows exchange of information between computers is called a Computer Network.
eg: LAN, MAN, WAN

Question 3.
Do you heard about work station/Node. What is it?
Answer:
A personal computer connected to a network is called work station/Node.

Question 4.
Define a protocol.
Answer:
A protocol is the collection of rules and conventions used to exchange information between computers as a network.

Question 5.
Is the following a valid IP address? 258.1001.10.1. Justify your answer?
Answer:
No. It is not a valid IP address. An IP address has 4 parts numeric address. Each parts contains 8 bits. By using 8 bits we can represent a decimal number between 0 to 255. Here 258 and 1001 are greater than 255. So it is not valid.

Question 6.
Mr. Dixon purchased a Laptop with bluetooth technology. What is bluetooth?
Answer:
It is a specification that allows mobile phones, computers and PDAS to be connected wirelessly over short distance.

Question 7.
Some Airport or college campus offers Wi-Fi facility. What is Wi-Fi?
Answer:
Wi-Fi means Wireless Fidelity. It is a wireless technology. Some organisation offers Wi-Fi facility. Here we can connect internet wirelessly over short distance, using Wi-Fi enabled devices.

Question 8.
What is a protocol?
Answer:
A protocol is a collection of rules and regulations to transmit data from one computer to another on a network.
eg: Http, FTP, TCP/IP, etc.

Question 9.
Explain Infrared waves in detail?
Answer:
These waves are used for transmitting data in short distance and its frequency range is 300 GHz to 400 GHz. Tv’s remote control, wireless mouse and intrusion detectors etc are the devices that used infrared.

Question 10.
Define resource sharing.
Answer:
Resource sharing means the computers on a network can share resources like software (programs, data) and hardware (printer, scanner, CD drive etc.).

Question 11.
Name two classification of communication channels between computers in a network.
Answer:
The two classification of communication channels are guided media and unguided media.

Question 12.
What is the use of a Repeater ?
Answer:
A Repeater is a device used to strengthen weak signals on the network and retransmits them to the destination.

Question 13.
Differentiate between router and Bridge.
Answer:
Bridge is a device used to link same type of networks while Router is similar to a bridge, but it can connect two networks with different protocols.

Question 14.
Categorise and classify the different types of network given below.
ATM network, Cable television network, Network within the school, Network at home using Bluetooth, Telephone network, Railway network ,
Answer:

• PAN: Network at home using Bluetooth
• LAN: Network within the school
• MAN: Cable television network
• WAN: ATM network, Telephone network, Railway network

Question 15.
What is PAN?
Answer:
PAN means Personal Area Network. It is used to connect devices situated in a small radius by using guided media(USB cable)or unguided media (Bluetooth, infrared,etc).

Plus One Computer Networks Three Mark Questions and Answers

Question 1.
What are the advantages of Networks?

OR

In a school lab all the 10 computers are connected to a network. We know that there is no need of 10 printers or 10 scanners why? Explain the advantages of Networks?
Answer:
The advantages of Networks are given below:
1. Resource sharing:
All the computers in a network can share software (programs, data) and hardware (printer, scanner, CD drive etc.).

2. Reliability:
If one computer fails, the other computer can perform the work without any delay. This is very important for banking air traffic control and other application.

3. Price Vs Performance:
A main frame computer can be 10 times faster than a PC but it costs thousand times a PC. Therefore instead of a main frame 10 personal computers are used with less cost and same performance.

4. Communication Medium:
It is a powerful communication medium. We can exchange information between computers in a network.

5. Scalable:
This means, System performance can be increased by adding computers to a network.

Question 2.
Match the following,

Answer:
(1) c
(2) a
(3) b
(4) f
(5) d
(6) e

Question 3.
Your friend told you that a workstation and server are same. What is your opinion? Is it true?
Answer:
No it is not true. A work station is a ordinary computer connected to a network. But a server is a powerful computer connected to a network. Its main aim is to serve the needs of a workstation. Server is the master and workstations are the slaves.

Question 4.
Your friend told you that there are different types of servers. Do you agree with that ? Justify your answer?
Answer:
Yes, there are different types of servers, dedicated and non dedicated servers.
1. Dedicated Server:
In large networks, a computer is reserved only for doing server function like sharing software and hardware resources and it is unavailable for running user applications and therefore increases system cost.
eg: File server, Printer server etc.

2. Non dedicated Server:
In smaller networks, a computer is doing the function of a server as well as it also act as a workstation.

Question 5.
Your friend asked you that a Hub or switch is better. What is your opinion?
Answer:
A Hub is a device that receives data from a PC and transmit it to all other PC’s on the network. If two or more PC’s transmit data at the same time, there is a chance for collision.

Hub is a cheap device and data transfer through a Hub is slow. A switch is also a device and it transmits data to the right recipient. Therefore collision rate is low. A switch is faster but it is expensive.

Question 6.
A LAN is classified by their configuration. What are they?
Answer:
They are, peer to peer or client-server.
1. Peer to peer:
In this configuration all the computers have equal priority. That means each computer can function as both a workstation and a server. There is no dedicated server.

2. Client-Server:
In this configuration a computer is powerful which acts as a dedicated server and all others are clients (work stations). Server is the master and others are slaves.

Question 7.
Your friend told you that internet and intranet are same. Do you agree with that. Justify your answer.
Answer:
No. Internet and intranet are not same. They are different.
1. Internet:
It is a network of networks. It means that international network. We can transfer information between computers within nations very cheaply and speedily.
2. Intranet:
A private network inside a company or organisation is called intranet.

Question 8.
Your friend decides to start an internet cafe in his shop. What are the requirements forthis? Help him.
Answer:
The following are the requirements.

1. Computer with a built in Modem or a facility to connect an external modem.
2. A telephone connection
3. An account with an ISP
4. Install respective software
   • eg: Internet explorer or mozilla or netscape Navigator etc.

Question 9.
Consider the following URL and explain each parts.
http://www.nic.kerala.gov.in / results.html.
Answer:
1. http:
http means hyper text transfer protocol. It is a protocol used to transfer hyper text.

2. www:
World Wide Web. With an email address we can open our mail box from anywhere in the world.

3. nic.kerala:
It is a unique name. It is the official website name of National Informatic Centre

4. gov:
It is the top level domain. It means that it is a government organisation’s website,

5. in:
It is the geographical top level domain. It represents the country, in is used for India,

6. results.html:
It represents the file name.

Question 10.
Write any valid email and explain the working of an email.
Answer:
An example of an email id is jobi_cg@rediffmail. com. Here jobi_cg is the user name, rediffmail is the website address and .com is the top level domain which identifies the types of the organisation. To send an email we require an email address.

Some websites provide free email facility. To send an email first type the recipients address and type the message then click the send button. The website’s server first check the email address is valid, if it is valid it will be sent otherwise the message will not be sent and the sender will get an email that it could not deliver the message.

This message will be received by the recipient’s server and will be delivered to recipient’s mail box. He can read it and it will remain in his mail box as ong as he will be deleted.

Question 11.
Is it possible to give numeric address (IP address) to URL instead of string address of a website just like the following, http://210.212.239.70/
Answer:
Our Post Office has two addresses one string ad¬dress (Irinjalakuda) and one numeric code (680121). Just like this the website has also two addresses a string address www.agker.cag.gov.in and a numeric address (http://210.212.239.70/).

Numeric Address (IP address):
It has 4 parts one byte (8 bits) each separated by dots. One byte can represent a number in between 0 to 255. So we can use a number in between 0 to 255 separated by dots. It is the fastest method to access a website. To remember this number is not easy to humans. So a string address is used by humans, eg:- http://203.-127.54.1/

String Address:
It uses a string to represent a website, it is familiar to the humans. The string address is mapped back to the numeric address using a Domain Name System (DNS). It may consists of 3 or 4 parts. The first part is www., the second part is website name, the third top level domain and the fourth geographical top level domain,
eg: www.kerala.gov.in

Question 12.
Arun is in charge of networking the computers in your newly built computer lab.

1. Suggest any two options for communication media that can be usedfor connecting computers in your school lab.
2. Explain the structure and features of both. (3)

Answer:
1. Twisted pair cables and coaxial cables.

2. Twisted Pair Wire :
Two copper wires individually insulated, twisted around each other and covered by a PVC. There are two types of twisted pair wire. They are UTP and STP. It is very cheap and easy to install.

Coaxial Cable:
A sturdy copper wire(conductor) is insulated by plastic. This is covered just like a mesh by a conductor , which in turn is enclosed in an protective plastic coating. Compared to twisted pair wire it is more expensive, less flexible and more difficult to install. But it is more reliable and carry for higher data rates.

Question 13.
The computer uses digital signals and this signal is transmitted through telephone lines to computers at distant locations. Discuss how this is made possible.
Answer:
1. Modem

2. A Modem is a two in one device. That is it performs two functions. It is used to convert Digital signals to Analog, the process is Modulation(DAM) and the reverse process is converting Analog to Digital known as Demodulation (ADD).

Question 14.
Explain the structure of the television cable in your house.
Answer:
Coaxial Cable:
A sturdy copper wire(conductor) is insulated by plastic. This is covered just like a mesh by a conductor, which in turn is enclosed in an protective plastic coating. Compared to twisted pair wire it is more expensive, less flexible and more difficult to install. But it is more reliable and carry far higher data rates. The various coaxial cables are RG – 8, RG – 9, RG – 11,…………

Question 15.
Answer the following questions from the list given below.
[Router, Modem, Bridge, Gateway]
Answer:

1. Device used to connect a network using TCP/IP protocol and a network using IPX/SPX protocol.
2. Device that can convert a message from one code to another and transfer from one network to a network of another type.
3. Device used to link two networks of the same type.

Question 16.
Find the most suitable match.

Answer:
i. www.keralapsc.org
ii. first page of a web site
iii. file with extension.htm
iv. www.yahoo.com

Question 17.
What do you mean by line of sight method of propagation.

OR

Why Microwave station use tall towers instead of short one?
Answer:
MicroWave signals can travel only in straight line. It cannot bend when the obstacles in between. There fore it uses tall towers instead of short one. The dish like antenna mounted on the top of the tower. Hence the two antennas must be in a straight line, able to look at each other without any obstacle in between.

Question 18.
Mr. Alvis took a photograph by using his mobile phone and he sends that photograph to his friend by using blue tooth. What is Bluetooth? Explain.
Answer:
This technology uses radio waves in the frequency range of 2.402 GHz to 2.480 GHz. And transmit data in short distance. Mobile phones, Laptops, tablets etc use Bluetooth technology to transmit data.

By using Bluetooth Dongle(a small device that can be buy from the shop) we can convert non Bluetooth PC into Bluetooth enabled and transmits data with data transmission rate of 3 Mbs onwards.

Question 19.
Differentiate Wi-Fi and Wi-Max in detail.
Answer:
WI Fi(Wireless Fidelity) uses radio waves to transmit information across a network in a range 2.4 GHz to 5 GHz in short distance. Nowadays this technology is used to access internet in Laptops, Desktops, Tablets, Mobile phones etc. But Wi MAX(Wireless Microwave Access) uses microwaves to transmit information across a network in a range 2 GHz to 11 GHz over very long distance.

Question 20.
What is MAC address? What is the difference between a MAC address and an IP address?
Answer:
MAC means Media Access Control address. It is a unique 12 digit hexadecimal number(IMEI for mobile phones, it is a 15 digit decimal number) assigned to each NIC by its manufacturer. This address is known as MAC address and it is permanent. It is of the form. MM:MM:MM:SS:SS:SS.

The first MM:MM:MM contains the ID number of the adapter company and the second SS:SS:SS represents the serial number assigned to the adapter by the company.

IP address means Internet Protocol address. It has 4 parts numeric address. Each parts contains 8 bits. By using 8 bits we can represent a decimal number between 0 to 255(28=256 numbers). Each part is separated by dot. A total of 4 × 8=32 bits used. But nowadays 128 bits are used for IP address.

Question 21.
What is the limitation of microwave transmission? How is it eliminated?
Answer:
MicroWave signals can travel only in straight line. It cannot bend when the obstacles in between. Therefore it uses tall towers instead of short one. The dish like antenna mounted on the top of the tower. Hence the two antennas must be in a straight line, able to look at each other without any obstacle in between.

Question 22.
Explain the different types of networks.
Answer:
The networks are classified into the following.
1. Local Area Network (LAN):
This is used to connect computers in a single room, rooms within a building or buildings of one location by usin(j twisted pair wire or coaxial cable. Here the computers can share Hardware and software. Data transferrate is high and error rate is less,
eg: The computers connected in a school lab.

2. Metropolitan Area Network (MAN):
A Metropolitan Area Network is a network spread over a city. For example a Cable TV network. MAN have lesser speed than LAN and the error rate is less. Here opticalfibre cable is used.

3. Wide Area Network (WAN):
This is used to connect computers over a large geographical area. It is a network of networks. Here the computers are connected using telephone lines or Micro Wave station or Satellites. Internet is an example for this. LAN and MAN are owned by a single organisation but WAN is owned by multiple organisation. The error rate in data transmission is high.

Question 23.

1. To make data transfer faster, a switch stores two different addresses of all the devices connected to it. What are they?
2. There are 5 computers in your computer lab. Write short notes on any three possible methods to interconnect these computers. Draw the diagram of each method.

Answer:
1. Identification of computers over a network:
A computer gets a data packet on a network, it can identify the senders address easily. It is similarto oursnails mail, each letter is stamped in sender’s post office as well as receiver’s post office.

(1) Media Access Control(MAC) address:
It is a unique 12 digit hexadecimal number(IMEI for mobile phones, it is a 15 digit decimal number) assigned to each NIC by its manufacturer. This address is known as MAC address and its permanent. It is of the form. MM:MM:MM:SS:SS:SS. The first MM:MM:MM contains the ID number of the adapter company and the second SS:SS:SS represents the serial number assigned to the adapter by the company.

(2) Internet Protocol (IP) address:
An IP address has 4 parts numeric address. Each parts contains 8 bits. By using 8 bits we can represent a decimal number between 0 to 255(2°=256 numbers). Each part is separated by dot. A total of 4*8=32 bits used. But nowadays 128 bits are used for IP address.

2. Network topologies:
Physical or logical arrangement of computers on a network is called structure or topology. It is the geometrical arrangement of computers in a network. The major topologies developed are star, bus, ring, tree and mesh.

(1) Star Topology:
A star topology has a server all other computers are connected to it. If computer A wants to transmit a message to computer B. Then computer A first transmit the message to the server then the server retransmits the message to the computer B.

That means all the messages are transmitted through the server. Advantages are add or remove workstations to a star network is easy and the failure of a workstation will not effect the other. The disadvantage is that if the server fails the entire network will fail.

(2) Bus Topology:
Here all the computers are attached to a single cable called bus. Here one computer transmits all other computers listen. Therefore it is called broadcast bus. The transmission from any station will travel in both the direction. The connected computers can hear the message and check whether it is for them or not.

Advantages are add or remove computer is very easy. It requires less cable length and the installation cost is less. Disadvantage is fault detection is very difficult because of no central computer.

(3) Ring Topology:
Here all the computers are connected in the shape of a ring and it is a closed loop. Here also there is no central computer. Here a computer transmits a message, which is tagged along with its destination computer’s address.

The message travels in one direction and each node check whether the message is for them. If not, it passes to the next node. It requires only short cable length. If a single node fails, at least a portion of the network will fail. To add a node is very difficult.

(4) Hybrid Topology:
It is a combination of any two or more network topologies. Tree topology and mesh topology can be considered as hybrid topology.
(a) Tree Topology:
The structure of a tree topology is the shape of an inverted tree with a central node and branches as nodes. It is a variation of bus topology. The data transmission takes place in the way as in bus topology. The disadvantage is that if one node fails, the entire portion will fail.

(b) Mesh Topology:
In this topology each node is connected to more than one node. It is just like a mesh (net). There are multiple paths between computers. If one path fails, we can transmit data through another path.

Question 24.
ABC Ltd. required to connect their computers in their company without using wires. Suggest suitable medium to connect the computers. Explain. (3)
Answer:
Unguided Media

1. Radio waves: It transmits data at different frequencies ranging from 3 kHz. to 300 GHz.
2. Microwaves: Microwave signals can travel in straight line if there is any obstacle in its path, it can’t bend. So it uses tall towers instead of short one.
3. Infrared waves: These waves are used for transmitting data in short distance and its frequency range is 300 GHz to 400 GHz.

Question 25.
It is needed to set up a PAN, interconnecting one tablet, two mobile phones and one laptop. Suggest a suitable communication technology and list its features for the following situations:

1. the devices are in a room at distance of 5 to 10 meters.
2. the devices are in different rooms at a distance of 25 to 50 meters.

Answer:
1. Wireless communication technologies using radio waves
Bluetooth:
This technology uses radio waves in the frequency range of 2.402 GHz to 2.480 GHz. And transmit data in short distance. Mobile phones, Laptops, tablets etc use Bluetooth technology to transmit data.

2. Wi Fi(Wireless Fidelity):
It uses radio waves to transmit information across a network in a range 2.4 GHz to 5 GHz in short distance. Nowadays this technology is used to access internet in Laptops, Desktops, tablets. Mobile phones etc.

Question 26.
Computers and other communication devices can be connected a network using wireless technology.

1. A song is transferred from mobile phone to a laptop using this technology. Name the transmission medium used here.
2. Explain any other three communication media which use this technology

Answer:

1. Blue tooth or Radio waves
2. Wireless communication technologies using radio waves

(1) Bluetooth:
This technology uses radio waves in the frequency range of 2.402 GHz to 2.480 GHz. And transmit data in short distance. Mobile phones, Laptops, tablets etc use Bluetooth technology to transmit data.

(2) Wi Fi(Wireless Fidelity):
It uses radio waves to transmit information across a network in a range 2.4 GHz to 5 GHz in short distance. Nowadays this technology is used to access internet in Laptops, Desktops, tablets, Mobile phones etc.

(3) Wi MAX(Wireless Microwave Access):
It uses micro waves to transmit information across a network in a range 2 GHz to 11 GHz over very long distance.

(4) Satellites:
By using satellite we can communicate from any part of the world to any other. The ground stations are connected via the satellite. The data signals transmitted from earth to satellite (uplink) and from the satellite to the earth (downlink).

Question 27.
Find the correct match for each item in column A from columns B and C.

Answer:
(a) QR code – (iii) – 3
(b) USB flash drives – (i) – 4
(c) Bridge – (V) – 1
(d) FTTH – (ii) – 6

Question 28.
Write notes on the following:

1. IP address
2. MAC address
3. Modem

Answer:
1. IP address:
An IP address has 4 parts numeric address. Each parts contains 8 bits. By using 8 bits we can represent a decimal number between 0 to 255(2⁸=256 numbers). Each part is separated by dot. A total of 4 × 8=32 bits used. But nowadays 128 bits are used for IP address.

2. Media Access Control(MAC) address:
It is a unique 12 digit hexadecimal number(IMEI for mobile phones, it is a 15 digit decimal number) assigned to each NIC by its manufacturer. This address is known as MAC address. It is of the form. MM:MM:MM:SS:SS:SS.

3. Modem:
It is a device used to connect the computer to the internet. It converts digital signal into analog signal (modulation) and vice versa (De modulation)

Question 29.
Compare any three types of networks based on span of geographical area.
Answer:
Types of networks:
The networks are classified into the following based upon the amount of geographical area that covers.
1. Personal Area Ne,twork(PAN):
It is used to connect devices situated in a small radius by using guided media or unguided media

2. Local Area Network (LAN):
This is used to connect computers in a single room, rooms within a building or buildings of one location by using twisted pair wire or coaxial cable. Here the computers can share Hardware and software. Data transfer rate is high and error rate is less,
eg:The computers connected in a school lab.

3. Metropolitan Area Network (MAN):
A Metropolitan Area Network is a network spread over a city. For example a Cable TV network. MAN have lesser speed than LAN and the error rate is less. Here optical fiber cable is used.

4. Wide Area Network (WAN):
This is used to connect computers over a large geographical area. It is a network of networks. Here the computers are connected using telephone lines or Micro Wave station or Satellites.

Internet is an example for this. LAN and MAN are owned by a single organization but WAN is owned by multiple organization. The error rate in data transmission is high.
In short

Plus One Computer Networks Five Mark Questions and Answers

Question 1.
Explain the different network topologies.
Answer:
physical or logical arrangement of computers of a network is called structure or topology. It is the geometrical arrangement of computers in a network. The major topologies developed are star, bus, ring, tree and mesh.
1. Star Topology:
A star topology has a server all other computers are connected to it. If computer A wants to transmit a message to computer B. Then computer A first transmits the message to the server then the server retransmits the message to the computer B.

That means all the messages are transmitted through the server. Advantages are add or remove workstations to a star network is easy and the failure of a workstation will not effect the other. The disadvantage is that if the server fails the entire network will fail.

2. Bus Topology:
Here all the computers are attached to a single cable called bus. Here one computer transmits all other computers listen. Therefore it is called broadcast bus. The transmission from any station will travel in both the direction. The connected computers can hear the message and check whether it is for them or not.

Advantages are add or remove computer is very easy. It requires less cable length and the installation cost is less. Disadvantage is fault detection is very difficult because of no central computer.

3. Ring Topology:
Here all the computers are connected in the shape of a ring and it is a closed loop. Here also there is no central computer. Here a computer transmits a message, which is tagged along with its destination computer’s address.

The message travels in one direction and each node check whether the message is for them. IF not, it passes to the next node. It require only short cable length. If a single node fails, atleast a portion of the network will fail. To add a node is very difficult.

4. Hybrid Topology:
It is a combination of any two or more network topologies. Tree topology and mesh topology can be considered as hybrid topology.

(a) Tree Topology:
The structure of a tree topol-ogy is the shape of an inverted tree with a central node and branches as nodes. It is a variation of bus topology. The data transmis-sion takes place in the way as in bus topology. The disadvantage is that if one node fails, the entire portion will fail.

(b) Mesh Topology:
In this topology each node is connected to more than one node. It is just like a mesh (net). There are multiple paths between computers. If one path fails, we can transmit data through another path.

Question 2.
What are the different data communication equipments?
Answer:
1. Modem:
A Modem is a two in one device. That is it performs two functions. It is used to convert Digital signals to Analog, the process is Modulation (DAM) and the reverse process is converting Analog to Digital known as Demodulation (ADD).

2. Multiplexer(Many to One):
A multiplexer is a device that combines the inputs from different sources and produces one output. A demultiplexer does the reverse process.

3. Bridge:
It is a device used to link two same type of networks.

4. Router:
It is a device used to link two networks with different protocols.

5. Gateway:
It is a device used to link two networks of different types.lt can convert a message from one code to another.

Question 3.
Explain the protocol TCP/IP.
Answer:
1. TCP:
(Transmission Control Protocol) is a connection oriented protocol. It is responsible for sending the data from one PC to another and also verifying the correct delivery of data from client to server. Data can be lost in the intermediate network. TCP adds support to detect errors or lost data and to trigger retransmission until the data is correctly and completely received.

2. IP:
is responsible for moving packet of data from node to node. IP forwards each packet based on a four byte destination address (the IP number). The Internet authorities assign ranges of numbers to different organizations.

The organizations assign groups of their numbers to departments. IP operates on gateway machines that move data from department to organization to region and then around the world. In short TCP handle the flow control and error free packet delivery and IP provides basic addressing and data packets forwarding services.
eg: 101.65.105.255

Question 4.
What is a protocol. Explain any four.

OR

Why protocol is necessary for communication? Explain any two of them.
Answer:
A protocol is a collection of rules and regulations to transfer data from one location to another. Transmission Control Protocol (TCP), which uses a set of rules to exchange messages with other Internet points at the information packet level. Internet Protocol (IP), which uses a set of rules to send and receive messages at the Internet address level.
1. FTP:
File Transfer Protocol which is used for transferring files between computers connected to local network or internet.

2. HTTP:
HTTP is a protocol used for WWW for enabling the web browse to access web server and request HTML documents.

Students can Download Chapter 6 Depreciation, Provisions and Reserves Questions and Answers, Plus One Accountancy Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus One Accountancy Chapter Wise Questions and Answers Chapter 6 Depreciation, Provisions and Reserves

Plus One Accountancy Depreciation, Provisions and Reserves One Mark Questions and Answers

Question 1.
Depreciation arises due to ………
(a) Wear and tear
(b) Fall in money value
(c) Fall in the market value of asset
(d) None of these
Answer:
(a) Wear and Tear

Question 2.
Reason for a reduction in the value of a quarry is
(a) Depletion
(b) Wear and Tear
(c) Passage of time
(d) Obsolescence
Answer:
(a) Depletion

Question 3.
Scrap value can also be called as …………….. value.
(a) Realisable
(b) Break-up
(c) Resale
Answer:
(b) Break up

Question 4.
Decrease in the value of intangible asset is termed as …………..
(a) Wear and tear
(b) Depletion
(c) Amortization
(d) Accident
Answer:
(c) Amortization

Question 5.
Under diminishing value method, depreciation is calculated on ……………
(a) Original cost
(b) Written down value
(c) Scrap value
(d) None of these
Answer:
(b) Written down value

Question 6.
Capital profits are used to create ………………
(a) General reserve
(b) Capital reserve
(c) Secret reserve
(d) None of these
Answer:
(b) Capital reserve

Question 7.
Profit on sale of fixed assets is a ………………….
Answer:
Capital profit.

Question 8.
Purpose of Provision is to meet a ………….
Answer:
Liability.

Question 9.
……………… is an appropriation from the profit.
Answer:
Reserve.

Question 10.
……………. are usually created out of business profits which are available for distribution of dividend.
Answer:
Revenue Reserves.

Question 11.
Under …………….. method, the percentage of depreciation is applied on the original cost of the asset.
Answer:
Fixed Instalment Method

Question 12.
Depreciation is a expense.
Answer:
Non-cash

Question 13.
……………. implies to an existing asset becoming out-of-date on account of the availability of better type of asset.
Answer:
Obsolescence.

Question 14.
Installation, freight, and transport expenses are a part of …………
Answer:
Acquisition cost.

Question 15.
…………….. reserve is a reserve which does not appear in the balance sheet.
Answer:
Secret reserve.

Question 16.
Reserve created for maintaining a stable rate of dividend is termed as ………….
Answer:
Dividend Equalisation Reserve

Question 17.
…………. is created to make for decline in the value of investment due to market fluctuation.
Answer:
Investment Fluctuation Fund.

Question 18.
……………. is a charge against profit.
Answer:
Provision.

Question 19.
Choose odd one and give reason.
(a) Copyright
(b) Goodwill
(c) Building
(d) Patent
Answer:
(c) Building. Others are intangible assets.

Question 20.
Which of the following is a natural cause of depreciation?
(a) Obsolescence
(b) Wear and Tear
(c) Prohibition of an asset by the govt.
(d) None of these
Answer:
(b) Wear and Tear

Plus One Accountancy Depreciation, Provisions and Reserves Two Mark Questions and Answers

Question 1.
Is depreciation an expense like salary or rent etc? How is it distinguished from any other type of expense?
Answer:
In case of depreciation, there is no payment or outflow occurring.

Question 2.
Define Depreciation.
Answer:
Depreciation is defined as “a fall in the value of fixed assets owing to wear and tear, obsolescence, passage of time or exhaustion.”

Question 3.
List out the causes of depreciation.
Answer:

1. Wear and Tear
2. Obsolescence
3. Passage of time
4. Depletion
5. Accident.

Question 4.
What are the factors affecting the amount of depreciation?
Answer:
There are three basic factors which are required to charge depreciation, they are:

1. Cost of Assets
2. Estimated Net Residual value or Scrap value or salvage value
3. Estimated Useful life

Question 5.
True profit is arrived at only if depreciation is taken into account. Explain.
Answer:
Depreciation is the operating expenses of a physical asset. It should be considered in arriving at the true profit earned during each year.

Question 6.
Mr. Raju running a soda manufacturing company is of the view that ‘‘no depreciation need be provided on
the fixed assets because he does not pay any amount as depreciation to anyone.” As a commerce student, how will you respond to his statement? State reasons.
Answer:
The need for providing depreciation in accounting records arises from conceptual, legal and practical business considerations. Though depreciation is not paid it has to be identified as important business expenditure. The consequence of not providing depreciation as

1. Timely replacement of fixed assets become impossible.
2. Cost of production cannot be exactly calculated.
3. Paying dividend out of capital.

Plus One Accountancy Depreciation, Provisions and Reserves Three Mark Questions and Answers

Question 1.
What are the objectives or needs of providing depreciation?
Answer:
The main objectives of providing depreciation are:

1. To ascertain the true result of the business.
2. To present true Balance sheet.
3. To retain funds for replacement.
4. To avoid excess payment of income tax
5. To fulfill the legal requirements

Question 2.
“Provision is a must and reserve is an option.” – Elucidate.
Answer:
A provision is created for meeting some expected contingency and can only be utilized for the purpose for which it is meant. Thus provision are the amounts set aside out of profit’s to provide for:

1. Depreciation, renewals or decrease in the value of fixed assets and
2. Any known liabilityof which the amount cannot be determined with substatial accuracy.

A reserve is meant for meeting an unanticipated situation and can also be used in the payment of any future liability or loss. It is an appropriation from profit, which are not earmarked in any way to meet any liability. Thus, provision is a must and reserve is an option.

Question 3.
Explain the terms:

1. Depletion
2. Scrap value
3. Obsolescence

Answer:
1. Depletion:
Assets such as mines, quarries, etc. are of wasting nature. By extraction of these natural depositions, their value is reduced. This reduction in value of natural deposition due to depletion in quantity is a cause of depreciation.

2. Scrap value:
This is the estimated value of a fixed asset at the end of its useful life. It is the amount which is expected to be received when the asset is sold after being removed from service. It is also known as Salvage value or residual or Break-up value of asset.

3. Obsolescence:
As a result of change in fashion or new inventions, some assets may be discarded before their productive life comes to an end. This is called obsolescence.

Question 4.
Explain the concept of secret Reserve.”
Answer:
Secret reserve is a reserve that does not appear in the balance sheet. It may help to reduce profit and also tax liability. Management may resort to creation of secret reserve by charging higher. depreciation than required. It is termed as ‘Secret Reserve’, as it is not known to outside stakeholders. Secret reserve can also be created by way of

1. Undervaluation of inventories /stock
2. Charging capital expenditure to P/L account
3. Making excessive provision for doubtful debts.
4. Showing contingent liability as actual liabilities.

Plus One Accountancy Depreciation, Provisions and Reserves Four Mark Questions and Answers

Question 1.
Match the following.

Answer:

• 1 – c
• 2 – d
• 3 – g
• 4 – f
• 5 – a
• 6 – b
• 7 – e
• 8 – i

Question 2.
Discuss the straight-line method and written down value method of depreciation.
Answer:
1. Straight Line Method:
Under this method, a fixed percentage on the original cost of the asset is written off every year so that the value of the asset become zero at the end of its effective working life. The amount of depreciation charged annually will be constant. This method is also known as “Fixed Instalment Method” or“Original Cost method”.
\(Depreciation =\frac{\text { Original cost – Scrap value }}{\text { Expected working life }}\)

2. Written down value method:
Under this method, depreciation is charged on the book value of asset. This method uses a fixed percentage on the book value of the asset at the beginning of every year. The amount of depreciation charged in each period is not uniform and it reduces year after year. This method is also known as “Diminishing value method” or “Reducing Balance method”.

Question 3.
Give any four difference between Fixed Instalment method and Diminishing Value method for providing depreciation.
Answer:

Question 4.
Ram Brothers acquired a machine on 1^st July 2000 at a cost of ₹14000 and spent ₹1000 on its installation. The firm writes off depreciation at 10% of the original cost every year. The books are closed on 31^st December every year. On March 31, 2003, the machine is sold for ₹9500. Show the machinery account under Fixed Instalment method.
Answer:

Question 5.
John Enterprises has the following balances in its books as on March 31, 2005.
Machinery (Gross value) -₹6,00,000 Provision for depreciation – ₹2,50,000 A machine purchased for ₹1,00,000 on December 1^st 2001, having accumulated depreciation amounting to₹60,000 was sold on April 1^st 2006 for₹35,000. Prepare Machinery a/c and Machinery Disposal a/c.
Answer:
Machinery Disposal a/c

Question 6.
Manjusha Ltd. purchased a machinery for ₹1,00,000/ – on 1^st January 2001. Depreciation is charged at 10% p.a. on straight line method. After two years the company decided to change the method to written down value at 10% p.a. Prepare machinery a/c for first four years assuming that accounts are closed on 31^st December every year.
Answer:

Question 7.
Explain Revenue Reserve & Capital Reserve.
Answer:
1. Revenue Reserve:
Revenue reserve are usually created out of business profits which are available for distribution of dividend. It is further classified in to:
a. Specific Reserve:
An amount set aside for meeting a specific purpose or objective is called specific reserve. Eg: Debenture redemption reserve, dividend equalisation reserve, Investment fluctuation reserve, etc.

b. General Reserve:
The amount kept aside is used for the overall improvement of business, it is called general reserve. Eg: Contingency reserve

2. Capital Reserve:
A reserve created out of capital profit is called capital reserve. Usually such reserves are not available for dividend to shareholders. The following are some of the capital profit usually kept as capital reserve.

• Profit on sale of fixed assets
• Premium on issue of shares
• Profit prior to incorporation
• Profit on reissue of shares
• Profit made on purchase of a business.

Plus One Accountancy Depreciation, Provisions and Reserves Five Mark Questions and Answers

Question 1.
Provision is a charge against Profit whereas reserve is an appropriation of Profit.” Comment.
Answer:
The provision means any amount set aside as a charge against profit to meet a loss, the amount of which cannot be determined with substantial accuracy. Reserve refers to amount set aprt from profit and loss account to meet unforeseen contingencies.
The following are the difference between provision and reserve.

Question 2.
‘X’ Ltd, purchased a machinery on 1.1.2005 for a sum of ₹40,000. It is expected to have a working life of 7 years, by the end of which it would get a scrap value of ₹5000. Prepare machinery account in the book of X Ltd. for the last 3 years by providing depreciation under Fixed Instalment Method and also prepare depreciation account for the 3 years.
Answer:

Question 3.
On 1.1.2001, Anil and Co. purchases machinery for ₹19000 and spend ₹1500 for its installation. Show machinery account for 2001, 2002 and 2003 if the company writes off depreciation at 20% p.a. on diminishing balance method.
Answer:

Question 4.
The following data is given to you regarding the asset- Plant of Tinu Ltd. whose accounting year ends on 31^st December every year.

• Plant held on 1.1.2006-₹10,000
• Plant bought on 1.1.2007 – ₹20,000
• Plant bought on 1.4.2007 – ₹30,000
• Plant held on 1.1.2006 sold on 1.4.2007 – ₹7000
• Depreciation @ 10% p.a. on original cost method.
• Prepare Plant A/c.

Answer:

Question 5.
A firm purchased 3 machines of ₹1,00,000 each on 01/01/2003. Depreciation is charged @ 10% p.a. of original cost and accumulated on depreciation provision account. On 01/01/2004 one machine was sold for ₹80,000and a new one was purchased on 1/ 1/2004 for Rs. 2,00,000.
Show Asset Disposal Account.
Answer:

Question 6.
A machine purchased for ₹8,00,000 on April 01, 2000. Depreciation was provided on straight-line basis at the rate of 20% on original cost. On April 01, 2002, a substantial modification was made in the machine to make it more efficient at a cost of ₹80,000. This amount is to be depreciated @ 20% on straight line basis. Routine maintenance expenses during the year 2003-04 were ₹2000. Draw up the Machinery account, Provision for depreciation account and charge to Profit and Loss account in respect of the accounting year ended on 31.3.2003.
Answer:

Plus One Accountancy Depreciation, Provisions and Reserves Six Mark Questions and Answers

Question 1.
On 1^st January 2004, a company bought Plant and Machinery costing ₹45,000 and spent ₹5000 on its erection. Addition is made on 1^st July 2006 for the value of ₹20,000. Depreciation is provided @ 10% p.a. Prepare plant and machinery account for 4 years under:

1. Fixed Instalment system
2. Diminishing Balance method

Answer:
1. Fixed Instalment method

2. Diminishing Balance Method

Question 2.
A machine costing ₹30000 was bought on 1/4/2000. Further machinery costing ₹2000 was acquired on 1/10/2000 and another machinery costing ₹10000 was installed on 1/7/2001. On 1/7/2002 the machinery bought on 1/7/2001 was sold for ₹3000. Accounts are closed on 31^st December every year. Assuming 10% depreciation p.a.
Prepare Machinery a/c under the diminishing balance method.
Answer:

Students can Download Chapter 14 Mathematical Reasoning Questions and Answers, Plus One Maths Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus One Maths Chapter Wise Questions and Answers Chapter 14 Mathematical Reasoning

Plus One Maths Mathematical Reasoning Three Mark Questions and Answers

Question 1.
Write the contrapositive and converse of the following statements: (3 score each)

1. If x is a prime number, then x is odd.
2. If the two lines are parallel, then they do not intersect in the same plane.
3. Something is cold implies that it has low temperature.
4. You cannot comprehend geometry if you do not know how to reason deductively.
5. x is an even number implies that x is divisible by 4.

Answer:
1. Here p: x is a prime number.
q: x is odd.
Now, ~ p: x is not a prime number.
~ q: x is not odd.
The contrapositive statement is:
If x is not odd x is not a prime number.
The converse statement is:
If x is an odd, then x is a prime number.

2. Here p: Two lines are parallel.
q: They do not intersect in the same plane.
Now, ~ p: Two lines are not parallel.
~ q: They intersect in the same plane.
The contrapositive statement is:
If two intersect in the same plane then they are not parallel.
The converse statement is:
If the two lines do not intersect in the same plane, then they are parallel.

3. Here p: Something is cold.
q: It has low temperature.
Now, ~ p: Something is not cold.
~ q: It does not have low temperature.
The contrapositive statement is:
If something does not have low temperature then it is not cold.
The converse statement is:
If something has low temperature then it is cold.

4. Here p: You cannot comprehend geometry.
q: You do not know how to reason deductively.
Now, ~ p: You can comprehend geometry.
~ q: You know how to reason deductively.
The contrapositive statement is:
If you know how to reason deductively, then you can comprehend geometry.
The converse statement is:
If you do not know how to reason deductively then you cannot comprehend geometry.

5. Here p: x is an even number.
q: x is divisible by 4.
Now, ~ p: x is not an even number.
~ q: x is not divisible by 4.
The contrapositive statement is:
If x is not divisible by 4 then x is not an even number.
The converse statement is:
If x is divisible by 4 then x is an even number.

Question 2.
Show that the statement: “For any real numbers a and b, a² = b² implies that a = b” is not true by giving a counter-example.
Answer:
The given compound statement is of the form “if p then q”.
We assume that p is true then
a, b ∈ R such that a² = b²
Let us take a = -3 and b = 3
Now a² = b² but a ≠ b
So when p is true, q is false.
Thus the given compound statement is not true.

Plus One Maths Mathematical Reasoning Four Mark Questions and Answers

Question 1.
State whether the or used in the following statements is “exclusive” or “inclusive”. Give reasons for your answer.

1. A rectangle is a quadrilateral or a pentagon. (2)
2. A square is a polygon or a parallelogram. (2)

Answer:
1. This statement make use of exclusive ‘or’. Since a geometrical figure cannot be a quadrilateral and also a pentagon.

2. This statement make use of inclusive ‘or’. Since a geometrical figure can be a polygon as well as a parallelogram.

Plus One Maths Mathematical Reasoning Six Mark Questions and Answers

Question 1.
Show that the statement p: “If x is a real number such that x³ + 4x = 0 then x is 0” is true by

1. Direct method. (2)
2. Method of contradiction. (2)
3. Method of contrapositive. (2)

Answer:
The given compound statement is of the from “if p then q”.
P: x ∈ R such that x³ + 4x = 0
q: x = 0

1. Direct method:
We assume that p is true then
x ∈ R such that x³ + 4x = 0
x ∈ R such that x(x² + 4) = 0
x ∈ R such that x = 0 or x² + 4 = 0
⇒ x = 0
⇒ q is true.
So when p is true, q is true.
Thus the given compound statement is true.

2. Method of contradiction:
We assume that p is true and q is false, then x ≠ 0
x ∈ R such that x³ + 4x = 0
x ∈ R such that x(x² + 4) = 0
x ∈ R such that x = 0 or x² + 4 = 0
⇒ x = 0
Which is a contradiction. So our assumption that x ≠ 0 is false. Thus the given compound statement is true.

3. Method of contrapositive.
We assume that q is false, then x ≠ 0
⇒ x ∈ R such that x³ + 4x ≠ 0
⇒ q is false
So when q is false, p is false.
Thus the given compound statement is true.

Plus One Maths Mathematical Reasoning Practice Problems Questions and Answers

Question 1.
Which of the following sentences are statements: (1 score each)

1. There are 35 days in a month.
2. Mathematics is difficult.
3. The sum of 5 and 7 is greater than 10.
4. The square of a number is an even number.
5. The sides of a quadrilateral have equal length.
6. Answer this question
7. The product of -1 and 8 is -8.
8. The sum interior angles of a triangle is 180.
9. Today is a windy day.
10. All real numbers are complex numbers.

Answer:

1. No month have 35 days. Hence it is a statement.
2. Here the correctness of the sentence depends upon the observer. So the sentence is not a statement.
3. The sentence is true so it is a statement.
4. Here the correctness of the sentence depends upon the observer. So the sentence is not a statement.
5. This sentence is sometimes true and some time false. So the sentence is not a statement.
6. This sentence is an order. So the sentence is not a statement.
7. The sentence is true so it is a statement.
8. The sentence is true so it is a statement.
9. It is not clear from the context which day is referred. Hence not a statement.
10. The sentence is true, so it is a statement.

Question 2.
Write the negation of the following statements: (1 score each)

1. Chennai is the capital of Tamil Nadu.
2. \(\sqrt{2}\) is not a complex number.
3. All triangles are not equilateral triangle.
4. The number 2 is greater than 7.
5. Every natural number is an integer.

Answer:

1. Negation: Chennai is not the capital of Tamil Nadu.
2. Negation: \(\sqrt{2}\) is a complex number.
3. Negation: All triangles are equilateral triangle.
4. Negation: The number 2 is not greater than 7.
5. Negation: Every natural number is not an integer.

Question 3.
Find the component statements of the following compound statements and check they are true or false. (1 score each)

1. Number 3 is prime or it is odd.
2. All integers are positive or negative.
3. 100 is divisible by 3,11 and 5.
4. The sun shines or it rains.
5. India is a democracy and a monarchy.

Answer:
1. The component statements are
p: Number 3 is prime
q: Number 3 is odd.
Both the component statements p and q are true.

2. The component statements are
p: All integers are positive
q: All integers are negative.
Both the component statements p and q are true.

3. The component statements are
p: 100 is divisible by 3.
q: 100 is divisible by 11.
r: 100 is divisible by 5.
The component statements p and q are false, whereas r is true.

4. The component statements are
p: The sun shines
q: It rains.
Both the component statements p and q are true.

5. The component statements are
p: India is a democracy.
q: India is a monarchy.
Both the component statements p is true, whereas the component statement q is false.

Question 4.
For each of the following compound statement first identify the connecting words and then break it into component statement: (2 score each)

1. All rational numbers are real and all real numbers are not complex.
2. Square of an integer is positive or negative.
3. The sand heats up quickly in the sun and does not cool down fast at night.
4. x = 2 and x = 3 are the roots of the equation 3x² – x – 10 = 0

Answer:
1. The component statement has the connecting word ‘and’ component statements are
p: All rational numbers are real
q: All real numbers are not complex.

2. The component statement has the connecting word ‘or’ component statements are
p: Square of an integer is positive.
q: Square of an integer is negative.

3. The component statement has the connecting word ‘and’ component statements are
p: The sand heats up quickly in the sun.
q: The sand does not cool down fast at night.

4. The component statement has the connecting word ‘and’ component statements are
p: x = 2 are the roots of the
equation 3x² – x – 10 = 0.
q: x = 3 are the roots of the equation 3x² – x – 10 = 0.

Students can Download Chapter 13 Limits and Derivatives Questions and Answers, Plus One Maths Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus One Maths Chapter Wise Questions and Answers Chapter 13 Limits and Derivatives

Plus One Maths Limits and Derivatives Three Mark Questions and Answers

Question 1.
Evaluate the following: (3 score each)

Answer:

Question 2.
Evaluate the following: (3 score each)

Answer:

ii) Put x + 1 = y, x → 0, y → 1

iii) Put 1 – x = y, x → 0, y → 1

Question 3.
Evaluate the following: (3 score each)

Answer:


= 1 × 3 × 1 × 3 = 9

iv) Put π – x = y, x → π, y → 0

vii) Put x – \(\frac{\pi}{2}\) = y, x → \(\frac{\pi}{2}\), y → 0

Question 4.
Evaluate the following: (3 score each)

Answer:






= \(\frac{1}{1}\) × 1 = 1.

Question 5.
Find \(\lim _{x \rightarrow 0} f(x)\) and \(\lim _{x \rightarrow 1}\) f(x) where
f(x) = \(\left\{\begin{array}{cc}{2 x+3,} & {x \leq 0} \\{3(x+1),} & {x>0} \end{array}\right.\).
Answer:

Question 6.
Find \(\lim _{x \rightarrow 1}\)f(x) where f(x) = \(\left\{\begin{array}{cc}
{x^{2}-1,} & {x \leq 1} \\{-x^{2}-1,} & {x>1}\end{array}\right.\).
Answer:

Therefore; \(\lim _{x \rightarrow 1^{-}}\)f(x) ≠ \(\lim _{x \rightarrow 1^{-}}\)f(x)
Hence \(\lim _{x \rightarrow 1^{-}}\)f(x) does not exist.

Question 7.
Evaluate

Answer:

Plus One Maths Limits and Derivatives Practice Problems Questions and Answers

Question 1.
Evaluate the following:(2 score each)

Answer:

Question 2.
Find the derivatives of the following: (2 score each)

1. y = (x – d)(x – b)
2. y = (ax² + b)²
3. y = \(\frac{x-a}{x-b}\)
4. y = x^-3(5 + 3x)

Answer:
1.

= (x – a) × 1 + (x – b) × 1
= x – a + x – b = 2x – a – b

2. y = a²x⁴ + b² + 2abx²
\(\frac{d y}{d x}\) = 4a²x³ + 4abx.

3.

4. y = 5x^-3 + 3x^-2
\(\frac{d y}{d x}\) = 5(-3)x^-3-1 + 3(-2)x^-2-1
= -15x^-4 – 6x^-3

Question 3.
Find the derivatives of the following: (3 score each)

Answer:

Question 4.
If xy = c² , prove that x² \(\frac{d y}{d x}\) + c² = 0.
Answer:
xy = c² ⇒ y = \(\frac{c^{2}}{x}\)
Differentiating with respect to x;

Question 5.
Evaluate: \(\lim _{x \rightarrow 0} \frac{(x+5)^{2}-25}{x}\).
Answer:

Question 6.
Find the derivative of f(x) = x sin x.
Answer:
f'(x) = x × cosx + sin x × 1 = xcosx + sinx.

Question 7.
Find the derivative of f(x) = \(\frac{\sin x}{x}\).
Answer:

Question 8.
Evaluate \(\lim _{x \rightarrow 0} \frac{\sin a x}{b x}\).
Answer:

Students can Download Chapter 3 Components of the Computer System Questions and Answers, Plus One Computer Science Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus One Computer Science Chapter Wise Questions and Answers Chapter 3 Components of the Computer System

Plus One Components of the Computer System One Mark Questions and Answers

Question 1.
The Tangible parts of a computer is _________
Answer:
Hardware

Question 2.
The instructions that tell the hardware to perform a task is __________
Answer:
Software

Question 3.
The brain of the computer is __________
Answer:
CPU

Question 4.
CPU means _________
Answer:
Central Processing Unit

Question 5.
ALU is
Answer:
Arithmetic Logic Unit

Question 6.
I am an input device. I can read text or picture on paper and translate into computer usable form. Who am I?
Answer:
Scanner

Question 7.
Odd man out.
(a) Trackball
(b) Joy Stick
(c) Scanner
(d) LCD
Answer:
(d) LCD. It is an output device. Others are input device

Question 8.
Odd man out.
(a) Inkjet
(b) Laser
(c) Dot Matrix Printer
(d) Thermal
Answer:
(c) Dot Matrix Printer. It is impact printer others are non impact printers.

Question 9.
The storage capacity of a CD is ________
(a) 1.44 MB
(b) 700 GB
(c) 700 MB
(d) 650 GB
Answer:
(c) 700 MB

Question 10.
__________ sheet is used to write answers in Kerala Entrance Exam.
Answer:
OMR Sheet

Question 11.
ABC textile uses reader to input the item and its price.
Answer:
Bar code reader

Question 12.
_________ device senses the presence or absence of a pencil mark.
Answer:
OMR

Question 13.
Name any two printing devices.
Answer:
Mouse and touchpad

Question 14.
__________ is a device that draws pictures on a paper.
Answer:
Plotter

Question 15.
Primary memory is classified into two. What are they?
Answer:
RAM and ROM

Question 16.
The storage capacity of a DVD is _________.
Answer:
4.7 GB

Question 17.
Winzip is a ___________ utility.
Answer:
Compression utility

Question 18.
Win Rar is a ________ utility.
Answer:
Compression utility

Question 19.
Most commonly used input device is _________________
Answer:
Keyboard or mouse

Question 20.
Govt, decided to conduct a test that contains all objective type questions. Which device is most suitable for evaluation.
Answer:
OMR

Question 21.
__________ is used mostly for computer games.
Answer:
Joy stick

Question 22.
I am an input device. I have a stick with two buttons called triggers on the top. Who am I?
Answer:
Joy stick

Question 23.
I am a pointing device. I am a stationary device. Who am I?
Answer:
Touchpad

Question 24.
In portable computers which pointing device is suitable?
Answer:
Touchpad

Question 25.
State true or false.
Hard copy devices are very slow compared to soft copy devices.
Answer:
True

Question 26.
________ is also called firrfi ware.
Answer:
ROM

Question 27.
__________ is acts as an interface between user and computer.
Answer:
Operating system

Question 28.
_________ is used to create and modify any type of document.
Answer:
Word Processor

Question 29.
_________ is a set of programs that manage the database.
Answer:
DBMS

Question 30.
__________ package contains rows & columns.
Answer:
Spread sheet

Question 31.
_________ is a presentation package.
Answer:
Power point

Question 32.
Your computer teacher asked you to explain the project work done by your group. Which package will help you to do so?
Answer:
Power Point

Question 33.
___________ is a DTP Package.
(a) Excel
(b) Powerpoint
(c) PageMaker
(d) None of these
Answer:
(c) PageMaker

Question 34.
DTP is ________
Answer:
Desk Top Publishing

Question 35.
_______ is designed to help computer for its smooth functioning.
Answer:
Utilities

Question 36.
Customised software is also called _________
Answer:
Tailor made software

Question 37.
__________ S/W is used to remove virus from a computer.
Answer:
Anti Virus S/W

Question 38.
Name any Antivirus S/W.
Answer:
Norton Antivirus, McAfee, Avira, AVG

Question 39.
Name the two classifications of output devices.
Answer:
Hard copy and soft copy

Question 40.
Name the two classifications of printers.
Answer:
Impact printer and non-impact printer

Question 41.
_______ gas is used in plasma panels
Answer:
(a) Oxygen
(b) Neon
(c) Mercury
(d) helium Neon
Answer:
(b) Neon

Question 42.
__________ printers are used in fax machine.
Answer:
Thermal Printers

Question 43.
_________ is read/write memory.
Answer:
RAM

Question 44.
________ is of volatile memory
(a) ROM
(b) RAM
(c) CD
(d) DVD
Answer:
(b) RAM

Question 45.
From the following which is expensive?
(a) CD
(b) DVD
(c) HDD
(d) RAM
Answer:
(d) RAM

Question 46.
You want to input your photograph into computer. Which device is used for this?
(a) Scanner
(b) Mouse
(c) OMR
(d) OCR
Answer:
(a) Scanner

Question 47.
The primary memory which is commonly used in electronic billing machines to store price of products is
(a) P R O M
(b) E P R O M
(c) E E P R O M
(d) None of these
Answer:
(b) E P R O M

Question 48.
Name any three pointing devices,
Answer:
Mouse, Touchpad and light pen.

Question 49.
You want to print your brother’s resume which printer will you choose. Why?
Answer:
I will choose either Ink-jet or Laser printer. Because these produce less noise and produce high quality printing output. They are used to print characters as well as graphics (Photos) with very high quality.

Question 50.
The fastest memory in a computer is
Answer:
Registers

Question 51.
The storage capacity of a single layer DVD is _______
Answer:
4.7 GB

Question 52.
Give two examples for OS.
Answer:
Windows 7, Windows Vista

Question 53.
A program in execution is called _______
Answer:
Process

Question 54.
Name the software that translates assembly language program into machine language program.
Answer:
Assembler

Question 55.
DBMS stands for _________.
Answer:
Data Base Management System .

Question 56.
Duplicating disc information is called __________.
Answer:
Backup

Question 57.
An example of free and open source software is _______?
Answer:
Linux

Question 58.
The software that gives users a chance to try it before buying is __________
Answer:
Shareware

Question 59.
An example of proprietary software is _________.
Answer:
Tally

Question 60.
Which software is used for calculation?
(a) Word processor
(b) Spreadsheet
(c) Presentation
(d) Multimedia
Answer:
(b) Spreadsheet

Question 61.
Accumulator stores ________
(a) address of data
(b) instruction to be executed
(c) address of next instruction to be executed
(d) intermediate result
Answer:
(d) intermediate result

Question 62.
If Tracks and Sectors : Hard disk, then
___________ : Compact disk
Answer:
Pits and Lands (OR) 0 and 1

Question 63.
Which one of the following file extensions is different from others?
(a) WAV
(b) MP3
(c) PNG
(d) MIDI
Answer:
(c) PNG, the others are audio files.

Question 64.
Which register holds the memory address of next instruction to the executed?
(a) Accumulator
(b) PC
(c) MBR
(d) MAR
Answer:
(b) PC

Question 65.
1. Write the following memory devices in the order of their speed. (fastest to slowest order)

• Cache
• RAM
• Hard Disk
• Registers

2. What do you mean by Freeware and Shareware?
Answer:
1. Memory devices in the order of their speed.

• Registers
• Cache
• RAM
• Hard Disk

2. Freeware and Shareware:

• Freeware: A s/w with Copy right is available free of cost for unlimited use.
• Shareware: It is an introductory pack distributed on a trial basis with limited functionality and period.

Plus One Components of the Computer System Two Mark Questions and Answers

Question 1.
The Higher Secondary Department wishes to conduct an examination for +1 students with multiple choice questions and publish results as soon as possible. Suggest a method to evaluate the answer scripts and publish the results quickly & correctly with the help of computers.
Answer:
OMR has to be used, it senses the presence or absence of a mark (bubbles) using a high density beam then converted into electric signals for computer. It needs good quality expensive paper and accurate alignment of printing on forms.

Question 2.
Remesh is a graphic designer who prepares his drawing using a computer. He desires for an alternative device by which he can draw directly on the screen. Suggest a device for this and explain it working.
Answer:
Light pens are used for this. It consists fo a photocell placed in a small tube, it is able to detect the light coming from the screen. Hence locate the exact position on the screen. It is used by graphic designers, illustrators and drafting engineers, with the help of CAD to draw directly on the screen.

Question 3.
You might have noticed that in some shops billing is done using computers without typing the item name, price, quantity, etc. Mention the device used for entering data and explain its working.
Answer:
A device called Bar Code Reader is used for this. It contains photoelectric scanner that read the bar code and input the information to the computer attached to it. It helps to reduce the errors and process the bills quickly.

Question 4.
Your scholl has arranged an excursion. You are having an ordinary camera whereas your friend has a digital camera. List the benefits your friend enjoys by using digital camera.
Answer:

1. Digital camera does not need film.
2. More number of shots can take
3. Operational cost is less
4. Very easy to manipulate images in digital form using computers.

Question 5.
A medical shop in your locality wishes to purchase a printer for their billing purpose. Which type of printer will you recommend if carbon copies are to be taken. Justify.
Answer:
Dot Matrix Printer. To take carbon copies impact printer is a must, operational cost is less and it can print bills in a moderate speed.

Question 6.
Find the extact match.

Answer:

1. D
2. C
3. B
4. A

Question 7.
Your friend wishes to start a DTP centre with facilities to design posters and notices, to scan pictures and modify them and to print them. What would be your suggestions regarding the computer and peripherals?
Answer:
The requriements are computer, scanner, printer and software.

Question 8.
Find the most appropriate match.

Answer:
1 – D
2 – C
3 – A
4 – B

Question 9.
Suggest a suitable device for the following.

1. High quality printing
2. High quality drawing
3. Printing with carbon copies
4. Economical printing of small quantities of data

Answer:

1. Non impact – Laser printers, Inkjet
2. Plotter
3. Impact (DMP(Dot Matrix Printer))
4. Dot Matrix Printers

Question 10.
“Not all primary memory is volatile”. Justify this statement.
Answer:
Primary Memory (Main memory) is classified into two RAM and ROM. Out of this RAM is volatile but ROM is non-volatile.

Question 11.
Categorise the softwares in the list according to the appropriate classifications given below.

1. Classification: OS, Compiler, DTP Software, Compression software, Word processor
2. List: Open Office Writer, Photoshop, 7 Zip, MS Word, Unix, C++, PageMaker, Winzip, C, Windows 98.

Answer:

• OS – Unix, Windows 98
• Compiler – C, C++
• DTP Software – Photoshop, PageMaker
• Compression – 7 Zip, Winzip
• Word Processor – Open Office Writer, MS word

Question 12.
Your friend has just assembled a computer. Now he is provided with installation CD’s of MS Word and Microsoft Windows XP. In what order will he install them? Justify your answer.
Answer:
First he has to install the Microsoft Windows XP because it is the OS, it makes the computer to work other programmes. After that only he can install MS Word It is a package.

Question 13.
A group of 20 students is given a test in 6 subjects. The examiner wishes to prepare a neatly formatted mark list with total and Rank. Suggest a suitable software to serve this purpose. Give reasons.
Answer:
The spreadsheet Excel is a suitable software to serve this purpose. It consists of inbuilt functions, that facilitates to find total and rank easily.

Question 14.
A program is written in BASIC, C and assembly language. Mention the difference in converting these programs to machine language.
Answer:

1. C – Compiler
2. BASIC – Interpreter
3. Assembly Language – Assembler

Question 15.
Your friend told you that he has a system. What is a system? Explain.
Answer:
A computer is also called a system. A computer is not a single unit. It consists of more than one unit such as input unit, output unit, memory unit, ALU and control unit. Therefore a computer is called a system.

Question 16.
What is cache memory?
Answer:
A cache (pronounced cash) memory is a high-speed memory placed in between the processor and primary memory to reduce the speed mismatch between these two.

Question 17.
What is the use of program counter register?
Answer:
This register stores the memory address of the next instruction to be executed by the CPU.

Question 18.
What is HDMI?
Answer:
Its full form is High Definition Multimedia Interface. Through this port we can connect high definition quality video and multi channel audio over a single cable.

Question 19.
Give two examples for customized software.
Answer:

1. Payroll System: It keeps track of details of employee and their salary details in an organisation
2. Inventory Management System: It keeps tack of all about inventory in a company

Question 20.
What do you mean by free and open source s/w?
Answer;
Here “free” means there is no copy right or licensing. That is we can take copies of the s/w or modify the source code without legal permission of its vendor (creator) we can use and distribute its copy to our friends without permission. That is Freedom to use, to modify and redistribute

Question 21.

1. What do you mean by cache memory? (1)
2. Write the names of the figures given below.

Answer:
1. It is a high speed memory placed in between the CPU and RAM. CPU is a high speed memory compared to RAM. There is a speed mismatch between the CPU and RAM to resolve this problem a high speed memory called cache memory is placed in between the CPU and RAM

2. QR code and Bar Code

Question 22.
What is the role of students in e-Waste disposal?
Answer:
Student’s role in e-Waste disposal

• Stop buying unnecessary electronic equipments
• Repair Faulty electronic equipments instead of buying a new one.
• Give electronic equipments to recycle
• Buy durable, efficient, quality, toxic free, good warranty products
• check the website or call the dealer if there is any exchange scheme
• Buy rechargeable battery products

Plus One Components of the Computer System Three Mark Questions and Answers

Question 1.
Why is the paper coming from the laser printer hot? Explain.
Answer:
Laser printer uses photocopying technology. It uses a positively charged drum and negatively charged toner (dry powder). A laser beam is used to scan the page to be printed on the drum with positive charge and then rolled through a reservoir of negatively charged toner.

It uses a combination of heat and pressure to adhere the dry powder to the paper. That is why, the paper coming from the laser printer is hot.

Question 2.
Explain the process how data from the hard disk is taken to the processor for processing.
Answer:
A processor is a high speed device. It can access data only from the Primary Memory (RAM). So we have to transfer data from hard disk to RAM. We know that a hard disk is a slow device also. So data is first transferred to RAM.

A RAM is comparatively slower than processor. To reduce the speed mismatch between the RAM and processor, the data has to transfer to CPU registers. Then the processor takes the data from the CPU register because CPU register has almost equal speed as processor.

Question 3.
Why computer is called as a system? (3)
Answer:
A computer is also called a system. A computer is not a single unit. It consists of more than one unit such as input unit, output unit, memory unit, ALU and control unit. Therefore a computer is called a system.

Question 4.
Differentiate hardware and software. (3)
Answer:
The tangible parts of a computer is called hard¬ware. We can see, touch and feel the hardware in a computer. The set of instructions that tell the hardware how to perform a task is called software. Without software computer cannot do anything.

Question 5.
We all have a brain. Just like this, is the computer has a brain? Explain it?
Answer:
Yes. CPU is the brain of a computer. The CPU comprises three parts ALU, Control Unit and Memory. The control unit control the overall functioning of a system. ALU performs all the arithmetic calculations and takes logical decisions. Memory is used for storage of data for future reference.

Question 6.
Explain the various functions of a control unit.
Answer:
The control unit performs the following functions.

1. It controls data flow between input device ALU, memory and output devices.
2. Normal execution of a program is line by line. The control unit controls this sequence with the help of ALU and memory.
3. It controls the decoding and interpretation of in-structions.

Question 7.
Match the following

Answer:
1 – c
2 – d
3 – f
4 – a
5 – b
6 – e

Question 8.
Write down the full form of the following.

1. VDU
2. OMR

Answer:

1. VDU – Visual Display Unit
2. OMR – Optical Mark Reader

Question 9.
We know that a scanner is a hardware. What do you think of a virus scanner? Explain.
Answer:
We know that a scanner is a hardware but a virus scanner is not a hardware. It is a program. That is a virus scanner is an antivirus software. That scans your disk (HDD, CD, DVD, Pen Drive) for viruses and removes them (if it can), if any virus is found.

Question 10.
Your friend told you that a compiler is a hardware. Is it true? Justify your answer.
Answer:
It is not true. A compiler is not a hardware but it is a software. A compiler is a collection of programs that translates program written in HLL into machine language.

Question 11.
Anil purchased a product from a supermarket and he found that its wrapper contains light and dark bars. What is the purpose of this ?
Answer:
This light and dark bars are called bar code. It is used to record some details about the product such as item code, name, price etc. A device called Bar Code Reader contains photo electric scanner that read the bar code and input the information to the computer attached to it. It helps to reduce error and process the bills quickly.

Question 12.
What are the disadvantages of OMR? (2)
Answer:
The disadvantages are:

1. It needs accurate alignment of printing on forms.
2. It needs good quality expensive paper.

Question 13.
Differentiate CRT and LCD (OR) Your friend going to purchase a computer. He asked you which is better, CRT or LCD? What is your opinion?
Answer:
The difference between CRT and LCD is given below:

So LCD is more better than CRT

Question 14.
While you pressing “A” on the keyboard what is actually stored in the memory?
Answer:
The keyboard is an electro mechanical device that is designed to create electronic codes when a key is pressed and this code is transmitted to the memory through the cable. Here while you pressing “A” on the keyboard, the electronic codes corresponding to the ASCII value 01000001 is transmitting to the memory.

Question 15.
Your family friend started a supermarket. He asked you, which printer is suitable to print bills. Give your suggestion.
Answer:
According to my opinion, dot matrix printer is most suitable. Because they are capable of faster printing as well as it is cheap also. It’s printing quality is not good but cost per copy is very cheap. Dot matrix printer consists of a ribbon cartridge that is cheap and can be changed easily. Here we have to print more copies at a time. So dot matrix is suitable.

Question 16.
Suppose your brother is an engineer. He wants to draw some drawings. Which output device is suitable? Explain.
Answer:
Plotter is suitable for him. A plotter is a device that draws pictures ordiagrams on paper based on commands from a computer. Plotters draw lines using a pen. Pen plotters generally use drum or flat bed paper holders.

In a drum plotter the paper is mounted on the surface of a drum. Here the paper is rotated. But in a flatbed plotter the paper does not move and the pen holding mechanism provides the motion that draws pictures. Plotters are used in engineering applications where precision is needed.

Question 17.
Match the following.

Answer:
1 – b
2 – a
3 – d
4 – e
5 – c

Question 18.
There are special purpose storage locations within the CPU. What are they explain ?
Answer:
Registers are special purpose storage locations within the CPU. They are temporary storage locations. The processing power of a CPU depends on register. Registers appears with storage capacity of 8 bits, 16 bits, 32 bits an 64 bits. They accept, store and transfer data from the CPU at a very high speed.

• Program Counter: This register stores the memory address of the next instruction to be executed by the CPU.
• Instruction Register: The instruction to be executed is stored in this register.
• Memory Address Register: The address on the memory location from which data has to be read is stored here.
• Memory Buffer Register: The data read from the location specified by the MAR is stored in this register.
• General Purpose Registers: These are used to store the result and intermediate results during a processing.

Question 19.
What is an operating system?
Answer:
An operating system acts as an interface between user and computer without an operating system computer is a bare machine. That is without an OS computer cannot do anything. The OS not only makes the system convenient to use but also use hardware in an efficient manner,
eg: Windows XP, Vista, Linux, MS Dos, Windows 7.

Question 20.
We know that a computer only knows low level language and human beings use high level language. So how is it possible to communicate? Explain.
Answer:
The language processors translate the programs written in HLL into machine language which is understood by the computer. The different language processors are given below:
1. Assembler:
This language processor translates programs written in assembly language into machine language.

2. Interpreter:
This language processor translates programs written in HLL into machine language by converting and executing it line by line. If there is any error, the execution is stopped we, can continue after the correction of the program.

3. Compiler:
This language processor is same as interpreter. But it translates HLL into machine language by converting whole lines at a time. If there is any error, correcting all the errors then only it will execute.

Question 21.
Normally a CD contains 700 MB. Is it possible to store a file with size 1 GB? Explain.

OR

Normally a Car has a seating capacity of 5 persons including the driver. But some adjustments more persons can be accommodated in Car. This is connected with a utility. Which is the utility? Explain.
Answer:
Compression utility is used for this. By using compression utility programs we can reduce the file size upto the one third of the file size. So by using this we can reduce 1GB file and store in a CD. It is provided by the OS.

The other compression utility programs are Winzip, WinRar etc. It is possible to compress the files and when needed, these compressed files can be uncompressed and it is restored to their original form.

Question 22.
What is a Virus?
Answer:
A virus is a bad program or harmful program to damage routine working of a computer system. It reduces the speed of a computer. It may be delete the useful system files and make the computer useless.

Question 23.
What do you mean by Utilities?
Answer:
Utilities are useful programs which are designed to help computer for its smooth functioning. Some utilities are back up utility, Disk defragmentation. Virus scanner, etc. It is provided by the O.S.

Question 24.
Differentiate RAM and ROM.
Answer:
The difference between RAM and ROM is given below.

Question 25.
Mention any two functions of OS.
Answer:
Major functions of an operating System

1. Process management: It includes allocation and de allocation of processes(program in execution) as well as scheduling system resources in efficient manner
2. Memory management: It takes care of allocation and de allocation of memory in efficient manner
3. File management: This includes organizing, naming, storing, retrieving, sharing, protecting and recovery of files.
4. Device management: Many devices are connected to a computer so it must be handled efficiently.

Question 26.
Give two examples of human ware.
Answer:
(Write any two from the following). The term refers the persons who use computer System Administrator: It is a person who has central control over the computer systems.

• System Managers: He is responsible for all business transactions with all vendors and contractors.
• System Analysts: He is responsible to improve the productivity and efficiency.
• Database Administrator: It is a person who has a central control over the DBMS.
• Computer Engineer: The person design either h/w or s/w of a computer system.
• Application Programmer: These are computer professionals who interact with the DBMS through programs.
• Computer operators: He is an end user and does not know computer in detail.

Question 27.
Explain how e-waste creates environmental and health problems. What are the different methods for e-waste disposal? Which one is the most effective in your point of view? Why? (5)
Answer:
e-Waste(electronic waste): It refers to the malfunctioning electronic products such as faulty computers, mobile phones, tv sets, toys, CFL, batteries etc. It contains poisonous substances such as lead, mercury, cadmium etc and may cause diseases if not properly managed.

A small amount is recycled. Due to this our natural resources are contaminated(poisoned). Some of them can .recycle properly. But it is a very big problem in front of the Government to collect segregate, recycle and disposal of e-Waste.
e-Waste disposal methods:

1. Reuse: Reusability has an important role of e-Waste management and can reduce the volume of e-Waste
2. Incineration : It is the process of burning e-Waste at high temperature in a chimney
3. Recycling of e-Waste: It is the process of making new products from this e-Waste.
4. Landfilling: It is used to level pits and cover by thick layer of soil.

Question 28.
What do you mean by e-waste? Explain the role of students in e-waste disposal.
Answer:
e-Waste(electronic waste): It refers to the malfunctioning electronic products such as faulty computers, mobile phones, tv sets, toys, CFLetc. It contains poisonous substances such as lead, mercury, cadmium etc and may cause diseases if not properly managed.
Student’s role in e-Waste disposal

1. Stop buying unnecessary electronic equipments
2. Repair Faulty electronic equipments instead of buying a new one.
3. Give electronic equipments to recycle
4. Buy durable, efficient, quality, toxic free, good warranty products
5. check the website or call the dealer if there is any exchange scheme
6. Buy rechargeable battery products

Plus One Components of the Computer System Five Mark Questions and Answers

Question 1.
Write short notes about input devices.
Answer:
An input device is used to supply data to the computer. They are given below:
1. Key board:
It is the most widely used device to input information in the form of words, numbers etc. There are 101 keys on a standard key board. The keys on the key board are often classified into alpha numeric keys (A to Z, Oto 9), function keys (F1 to F12), special purpose keys (Special characters), cursor movement keys (arrow keys). While pressing a key, the corresponding code’s signal is transmitted to the computer.

2. Mouse:
It is a pointing device, that controls the movement of the cursor, or pointer as a display screen. A mouse has two or three buttons, it is often used in GUI oriented computers. Under the mouse there is a ball, when the mouse moves on a flat surface this ball also moves. This mechanical motion is converted into digi¬tal values that represents x and y values of the mouse movement.

3. Optical Mark Reader (OMR):
This device identifies the presence or absence of a pen or pen¬cil mark. It is used to evaluate objective type exams. In this method special preprinted forms r.e designed with circles can be marked with dark pencil or ink.

A high intensity beam in the OMR converts this into computer usable form and detects the number and location of the pencil marks. By using this we can evaluate easily and reduce the errors.

4. Bar code / Quick Response (QR) code reader:
Light and dark bars are used to record item name, code and price is called Bar Code. This information can be read and input into a computer quickly without errors using Bar Code Readers.

It consists of a photo electric scanner and it is used in super market, jewellery, textiles etc. QR codes are similar to barcodes but it uses two dimensional instead of single dimensional used in Barcode.

5. Joy Stick:
It is a device that lets the user move an object quickly on the screen. It has a liver that moves in all directions and controls the pointer or object. It is used for computer games and CAD / CAM systems.

6. Light Pen:
It is an input device that use a light sensitive detector to select objects directly on a display screen using a pen. Light pen has a photocell placed in a small tube. By using light pen, we can locate the exact position on the screen.

7. Scanner:
It is used to read text or pictures printed on paper and translate the information into computer usable form. It is just like a photostat machine but it gives information to the computer.

8. Digital Camera:
By using digital camera, we can take photographs and store in a computer. Therefore we can reduce the use of film. Hence it is economical.

9. Touchpad:
It is a pointing device found on the portable computers(laptop). Just like a mouse it consists of two buttons below the touch surface to do the operations like left click and right click. By using our fingers we can easily operate.

10. Microphone:
By using this device we can convert voice signals into digital form.

11. Biometric sensor:
It is used to read unique human physical features like fingerprints, retina, iris pattern, facial expressions etc. Most of you give these data to the Government for Aadhaar.

12. Smart card reader:
A plastic card(maybe like your ATM card) stores and transmit data with the help of a reader.

13. Digital Camera :
By using digital camera, we can take photographs and store in a computer. Therefore we can reduce the use of film. Hence it is economical.

Question 2.
Briefly explain the various visual display units.
Answer:
The visual display units are given below:
1. Cathode Ray Tube (CRT):
There are two types of CRT’s, monochrome (Black and white) and colour. Monochrome CRT consists of one elec-tron gun but colour CRT consists of 3 electron guns (Red, Green and Blue) at one end and the other end coated with phosphor. It is a vacuum tube. The phosphor coated screen can glow when electron beams produced by electron guns hit.

It is possible to create all the colours using Red, Green and Blue. The images produced by this is refreshed at the rate of 50 or 60 times each second.Its disadvantage is it is heavy and bulky. It consumes more power and emits heat. But it is cheap. Nowadays its production is stopped by the company.

2. Liquid Crystal Display (LCD):
It consists of two, electrically conducting plates filled with liquid crystal. The front plate has transparent electrodes and the back plate is a mirror. By applying proper electrical signals across the plates, the liquid crystals either transmit or block the light and then reflecting it back from the mirror to the viewer and hence produce images. It is used in where small sized displays are required.

3. Light Emitting Diocte(LED):
It uses LED behind the liquid crystals in order to light up the screen. It gives a better quality and clear image with wider viewing angle. Its power consumption is less.

4. Plasma Panels:
It consists of two glass plates filled with neon gas. Each plate has several parallel electrodes, right angles to each other. When low voltage is applied between two electrodes, one on each plate, a small portion of gas is glow and hence produce images. Plasma displays provide high resolution but are expensive. It is used in, where quality and size is a matter of concern.

5. Organic Light Emitting Diode(OLED) Monitors:
It is made up of millions of tiny LEDs. OLED monitors are thinner and lighter than LCDs and LEDs. It consumes less power and produce better quality images but it is very expensive.

Question 3.
Your friend wants to buy a printer. He wants to know more about printers. Explain different types of printers.
Answer:
Printer: There are two types of printers impact and non-impact printers. Printers are used to produce hard copy.
Impact Printers: There is a mechanical contact between print head and the paper.

1. Dot Matrix Printer:
Here characters are formed by using dots. The printing head contains a vertical array of pins. The letters are formed by using 5 dot rows and 7 dot columns. Such a pattern is called 5 × 7 matrix.

This head moves across the paper, the selected pins fire against an inked ribbon to form characters by dot. They are capable of faster printing, but their quality is not good.

2. Non-impact Printers:
There is no mechanical contact between print head and paper so carbon copies cannot be possible to take. They are inkjet, laser, thermal printers etc.

(a) Inkjet Printer:
It works in the same fashion as dot matrix printers, but the dots are formed with tiny droplets of ink to be fired from a bottle through a nozzle. These droplets are deflected by an electric field using horizontal and vertical deflection plates to form characters and images.

It is possible to generate colour output. They produce less noise and produce high quality printing output. The printing cost is higher. Here liquid ink is used.

(b) Laser Printer:
It uses photo copying technology. Here instead of liquid ink dry ink powder called toner is used. A drum coated with positively charged photo conductive material is scanned by a laser beam. The positive charges that are illuminated by the beam are dissipated. The drum is then rolled through a reservoir of negatively charged toner which is picked up by the charged portions of the drum.

It adheres to the positive charges and hence creating a page image on the drum. Monochrome laser printer uses a single toner whereas the colour, laser printer uses four toners. Its print quality is good less noise and printing cost is higher.

(c) Thermal Printers:
It is same as dot matrix printer but it needs heat sensitive paper. It produces images by pushing electrically heated pins to the special paper. It does not make an impact on the paper so we cannot produce carbon copies. It produce less noise, low quality print and inexpensive. It is used in fax machine.

3. Plotter:
A plotter is a device that draws pictures ordiagrams on paper based on commands from a computer. Plotters draw lines using a pen. Pen plotters generally use drum or flat bed paper holders. In a drum plotter the paper is mounted on the surface of a drum.

Here the paper is rotated. But in a flatbed plotter the paper does not move and the pen holding mechanism provides the motion that draws pictures. Plotters are used in engineering applications where precision is needed.

4. Three Dimensional (3D) printer: This device is used to print 3D objects.

Question 4.
Your school got two printers. One dot matrix and one Laser printer through ICT scheme of Central Govt. What is the difference between these two printers? Explain.
Answer:

Question 5.
Explain Primary Memory in detail.
Answer:
Primary memory is classified into two, Random Access Memory (RAM) and Read Only Memory (ROM). The primary memory holds the data which is to be processed by the CPU and the set of instructions to be executed next. The CPU can access the instructions in the primary memory only.

1. Random Access Memory (RAM):
RAM is used to store data and instructions needed by the CPU for processing. RAM can be used for both reading and writing of data so it is called Read and Write memory. It is a volatile memory, that is contents of the RAM will be lost when the power is turned off.

The invention of integrated circuits (chips) increased the memory capacity and reduced the size and cost. Static RAM, Dynamic RAM, Synchronous Dynamic RAM (SDRAM) are the various types of RAM.

2. Read Only Memory (ROM):
We can read this memory but we cannot write into this memory. It is a nonvolatile memory, that is its contents will not lost when the power is turned off. This memory is stored in the ROM chip at the time of manufacture ing itself hence it is called firmware.

ROM contains instructions to check the hardware components connected to the system, perform some basic input/output operations (BIOS), initiates loading of essential software. The different categories are PROM, EPROM and EE PROM.

(a) PROM (Programmable Read Only Memory):
It is just like WORM. That means the instructions are write once but read many. But we cannot change the instructions.

(b) EPROM (Erasable Programmable Read Only Memory):
It functions just like PROM. But by using ultraviolet light we can erase the old data and can write new data.

(c) EEPROM (Electrically Erasable Programmable Read Only Memory):
Here instead of ultraviolet light electric signals are used to erase old data and write new data under software control. It is highly expensive than regular ROM chips.

Question 6.
Explain secondary memory in detail.

OR

To store large volume of data permanently. Which memory is used? Explain.
Answer:
Primary memory has a limited storage capacity and it is not permanent that is why to store large volume of data permanently secondary memory or storage devices are used. They are of many types and they vary in the capacity of storage, speed of data access and media of storage. Nowadays magnetic disks and optical disks are commonly used.

1. Magnetic Disk:
Magnetic disk allows the storage and retrieval for contents of the disk from anywhere at a moderate speed. Magnetic Disks available in various size and storage capacity but the storage media and data access mechanism are similar.

The storage media is circular platters or disks coated with magnetic material. It consists of a spindle capable of rotating with the help of an electrical motor and a read/write head.

(a) Floppy disk:
Floppy means flexible or soft, it uses flexible disk. Its storage capacity is 1,44MB and slower in data transfer rate.

(b) Hard Disk:
Instead of flexible or soft disk it uses rigid material hence the name hard disk. Its storage capacity and data transfer rate are high and low access time. These are more lasting and less error prone. The accessing mechanism and storage media are combined together in a single unit and connect to the mother board via cable.

Therefore we call it as hard disk drive (HDD). It contains one or more rigid platters coated both sides with a special magnetic material and a spindle. Datas are recorded on either surface of the disk except the outer side of last and first disk. Each surface will have one or more read/write heads (fixed head or movable head).

The spindle is attached to a motor that rotates at high speed typically 7200 rotation per minute (rpm). A floppy disk rotates only at 300 rpm.

2. Optical Disk:
The high power laser uses a concentrated, narrow beam of light, which is focuses and directed with lenses, prisms and mirrors for recording data. The optical disks are given below:

(a) Compact Disk Read Only Memory (CDROM):
The data in CDROM is imprinted.by the manufacturers. The user cannot erase or write on the disk but user can only read its contents. CDROM is written in a single continuous spiral unlike magnetic disks that uses concentric circles. Its storage capacity is 700MB.

(b) Erasable Optical Disk:
The disadvantage of CDROM is that we cannot change or erase the contents. But erasable disks can be changed and erased.

(c) Digital Versatile Disk: It is capable of storing upto 4.7GB and more faster.

(d) Blu-ray Disc:
It is used to read and write High Definition video data as well as to store very huge amount of data. While Cd and DVD uses red laser to read and write but it uses Blue-Violet laser, hence the name Blu ray disc. The blue-violet laser has shorter wavelength than a red laser so it can pack more data tightly.

3. Semiconductor storage (Flash memory): It uses EEPROM chips. It is faster and long lasting.

1. USB flash drive: It is also called thumb drive or pen drive. Its capacity varies from 2 GB to 32 GB.
2. Flash memory cards: It is used in Camera, Mobile phones, tablets etc to store all types of data.

Question 7.
What do you mean by a computer software? Mention its different classification.

OR

Your friend wants to know more about software. Explain more about different classification.

OR

Your friend told you that COBOL and MS Word are same softwares. Do you agree with him. Explain. What is a software and its classification?
Answer:
A Software is a collection of programs to perform a task. The softwares can be classified into two major groups.

1. System software
2. Application software

1. System Software:
It is a collection of programs used to manage system resources and control its operations. It is further classified into two.
(a) Operating System
(b) Language Processor
(a) Operating System:
It is collection of programs which acts as an interface between user and computer. Without an operating system computer cannot do anything. Its main function is make the computer usable and use hardware in an efficient manner,
eg: WindowsXP, Windows Vista, Linux, Windows 7, etc.

(b) Language Processes:
We know that a program is a set of instructions. The instructions to the computer are written in different languages. They are high level language (HLL) and low level language. In HLL english like statements are used to write programs. They are C, COBOL, PASCAL, VB, Java etc. HLL is very easy and can be easily understood by the human being.

Low level language are classifed into Assembly Language and Machine Language. In assembly language mnemonics (codes) are used to write programs

In Machine Language 0’s and 1’s are used to write program. It is very difficult but this is the only language which is understood by the computer. Usually programmers prefer HLL to write programs because of its simplicity. But computer understands only machine language. So there is a translation needed. The program which perform this job are language processors.

The different language processors are given below:
1. Assembler:
This converts programs written in assembly language into machine language.

2. Interpreter:
This converts a HLL program into machine language by converting and executing it line by line. The first line is converted if there is no error it will be executed otherwise you have to correct it and the second line and so on.

3. Compiler:
It is same as interpreter but there is a difference, it translate HLL program into machine language by converting all the lines at a time. If there is no error then only it will executed.

2. Application Software:
Programs developed to serve a particular application is known as application software, eg:- MS Office, Compression Utility, Tally etc.
Application software can further be sub divided into three categories.
(a) Packages
(b) Utilities
(c) Customized Software

(a) Packages:
Application software that makes the computer useful for people to do every task. Packages are used to do general purpose application.
They are given below:
1. Word Processes:
This is used for creation and modification of text document. That means a word processor helps the people to create, edit and format a textual data with less effort and maximum efficiency.

By using word processor we can change font and font size of character, change alignment (left, right, center and justify), check spelling and grammar of the whole document etc. eg: MS Word.

2. Spread Sheets:
It contains data or information in rows and columns and can perform calculation (Arithmetic, Relational and logi¬cal operation). It helps to calculate results of a particular formula and the formula can apply different cells (A cell is the intersection of a row and column. Each column carries an alphabet for its name and row is numbered).

It is used to prepare budgets, balance sheets, P & L account, Payroll etc. We can easily prepare graphs and charts using data entered in a worksheet. A file is a workbook that contains one or more worksheets, eg: MS Excel is a spreadsheet software.

3. Presentation and Graphics:
You can present your idea with sound and visual effects with the help of presentation software by preparing slides. The application software that manipulate visual images is known as graphics software. eg: MS Power Point is a presentation package.

4. Data base package:
Database is a collection of large volume of data. DBMS is a set of programs that manages the datas are for the centralised control of data such that creating new records to the database, deleting, records whenever not wanted from the database and modification of the existing database. Example for a DBMS is MS Access.

(b) Utilities: Utilities are programs which are designed to assist computer for its smooth functioning.
The utilities are given below:

1. Text editor:
It is used for creating and editing text files.

2. Backup utility:
Creating a copy of files in another location to protect them against loss, if your hard disk fails or you accidently overwrite or delete data.

3. Compression Utility:
It is used to reduce the size of a file by using a program and can be restored to its original form when needed.

4. Disk Defragmenter:
It is used to speeds up disk access by rearranging the files that are stored in different locations as fragments to contiguous memory and free space is consolidated in one contiguous block.

5. Vims Scanner:
It is a program called antivirus software scans the disk for viruses and removes them if any virus is found.

(c) Customised software:
It is collection of programs which are developed to meet user needs to serve a particular application. It is also called tailor made software.

Question 8.
To use a computer not only the hardware but also software are required. Explain the classification of software.
Answer:
Software: The set of instructions that tell the hardware how to perform a task is called software. Without software computer cannot do anything. Two types System s/w and Application s/w System software.
It is a collection of programs used to manage system resources and control its operations. It is further classified into two.

1. Operating System
2. Language Processor

1. Operating System: It is collection of programs which acts as an interface between user and computer. Without an operating system computer cannot do anything. Its main function is make the computer usable and use hardware in an efficient manner, eg: Windows XP, Windows Vista, Linux, Windows 7, etc.
Major functions of an operating System:

• Process management: It includes allocation and de allocation of processes(program in execution) as well as scheduling system resources in efficient manner.
• Memory management: It takes care of allocation and de allocation of memory in efficient manner
• File management: This includes organizing, naming , storing, retrieving, sharing , protecting . and recovery of files.
• Device management: Many devices are connected to a computer so it must be handled efficiently.

2. Language Processes:
We know that a program is a set of instructions. The instructions to the computer are written in different languages. They are high level language (HLL) and low level language. In HLL English like statements are used to write programs. They, are C, C++, COBOL, PASCAL, VB, Java etc. HLL is very easy and can be easily understood by the human being.

Low level language are classified into Assembly Language and Machine Language.
In assembly language mnemonics (codes) are used to write programs

In Machine Language 0’s and 1’s are used to write program. It is very difficult but this is the only language which is understood by the computer. Usually programmers prefer HLL to write programs because of its simplicity. But computer understands only machine language. So there is a translation needed. The program which perform this job are language processors.

The different language processors are given below:
1. Assembler:
This converts programs written in assembly language into machine language.

2. Interpreter:
This converts a HLL program into machine language by converting and executing it line by line. The first line is converted if there is no error it will be executed otherwise you have to correct it and the second line and so on.

3. Compiler:
It is same as interpreter but there is a difference it translate HLL program into machine language by converting all the lines at a time. If there is no error then only it will executed.

Application Software:
Programs developed to serve a particular application is known as application software, eg:- MS Office, Compression Utility, Tally etc. Application software can further be sub-divided into three categories.
(a) Packages
(b) Utilities
(c) Customized Software

(a) Packages:
Application software that makes the computer useful for people to do every task. Packages are used to do general purpose application.
They are given below:

1. Word Processes:
This is used for creation and modification of text document. That means a word processor helps the people to create, edit and format a textual data with less effort and maximum efficiency. By using word processor we can change font and font size of character, change alignment (left, right, center and justify), check spelling and grammar of the whole document etc.
eg: MS Word.

2. Spread Sheets:
It contains data or information in rows and columns and can perform calculation (Arithmetic, Relational and logical operation). It helps to calculate results of a particular formula and the formula can apply different cells (A cell is the intersection of a row and column.

Each column carries an alphabet for its name and row is numbered). It is used to prepare budgets, balance sheets, P & L account, Pay roll etc. We can easily prepare graphs and charts using data entered in a worksheet. A file is a work book that contains one or more work sheets,
eg : MS Excel is a spread sheet software.

3. Presentation and Graphics:
You can present your idea with sound and visual effects with the help of presentation software by preparing slides. The application software that manipulate visual images is known as graphics software.
eg: MS Power Point is a presentation package.

4. Data base package:
Data base is a collection of large volume of data. DBMS is a set of programs that manages the datas are for the centralized control of data such that creating new records to the database, deleting, records whenever not wanted from the database and modification of the existing database. Example for a DBMS is MS Access.

DTP Packages: DTP means Desk Top Publishing. By using this we can create books, periodicals, magazines etc. easily and fastly. Now DTP packages are used to create in Malayalam also,
eg: PageMaker.

5. Utilities:
Utilities are programs which are designed to assist computer for its smooth functioning.
The utilities are given below:

1. Text editor: It is used for creating and editing text files.
2. Backup utility: Creating a copy of files in another location to protect them against loss, if your hard disk fails or you accidentally overwrite or delete data.
3. Compression Utility: It is used to reduce the size of a file by using a program and can be restored to its original form when needed.
4. Disk Defragmenter: It is used to speeds up disk access by rearranging the files that are stored in different locations as fragments to contiguous memory and free space is consolidated in one contiguous block.
5. Virus Scanner: It is a program called antivirus software scans the disk for viruses and removes them if any virus is found.

(c) Specific purpose software (Customized software):
It is collection of programs which are developed to meet user needs to serve a particular application. It is also called tailor made software.

Question 9.
Describe the different types of memories and memory devices in computer with features and examples.
Answer:
Memory:
Storage Unit(Memory Unit): A computer has huge storage capacity. It is used to store data and instructions before starts the processing. Secondly it stores the intermediate results and thirdly it stores information(processed data), that is the final results before send to the output unit(Visual Display Unit, Printer, etc)
Memory measuring units are given below.

• 1 bit = 1 or 0(Binary Digit)
• 4 bits = 1 Nibble
• 8 bits = 1 Byte
• 1024 Bytes = 1 KB(Kilo Byte)
• 1024 KB = 1 MB(MegaByte)
• 1024 MB = 1 GB(Giga Byte)
• 1024 GB = 1 TB(Tera Byte)
• 1024 TB = 1 PB(Peta Byte)

Two Types of storage unit:
1. Primary Storage alias Main Memory:
It is further be classified into Two Random Access Memory (RAM) and Read Only Memory(ROM). The one and only memory that the CPU can directly access is the main memory at a very high speed.

It is expensive hence storage capacity is less. RAM is volatile(when the power is switched off the content will be erased) in nature but ROM is non volatile(lt is permanent). In ROM a “boot up” program called BIOS(Basic Input Output System) is stored to “boots up” the computer when it switched on. Some ROMs are given below.

1. PROM(Programmable ROM): It is programmed at the time of manufacturing and cannot be erased.
2. EPROM (Erasable PROM): It can be erased and can be reprogrammed using special electronic circuit.
3. EEPROM (Electrically EPROM): It can be erased and rewritten electrically

Cache Memory:
The processor is a very high speed memory but comparatively RAM is slower than Processor. So there is a speed mismatch between the RAM and Processor, to resolve this a high speed memory is placed in between these two this memory is called cache memory. Commonly used cache memories are Level(L1) Cache(128 KB), L2(1 MB),L3(8 MB), L4(128MB).

2. Secondary Storage alias Auxiliary Memory :
Because of limited storage capacity of primary memory its need arises. When a user saves a file, it will be stored in this memory hence it is permanent in nature and its capacity is huge. Eg: Hard Disc Drive(HDD), Compact Disc(CD), DVD, Pen Drive, Blu Ray Disc etc.

(a) Magnetic storage device:
It uses plastic tape or metal/plastic discs coated with magnetic material.
Hard Disk: Instead of flexible or soft disk it uses rigid material hence the name hard disk. Its storage capacity and data transfer rate are high and low access time.

These are more lasting and less error prone. The accessing mechanism and storage media are combined together in a single unit and connect to the mother board via cable.

(b) Optical storage device:
Optical Disk: The high power laser uses a concentrated, narrow beam of light, which is focuses and directed with lenses, prisms and mirrors for recording data. This beams burns very very small spots in master disk, which is used for making molds and these molds are used for making copies on plastic disks.

A thin layer of aluminium followed by a transparent plastic layer is deposited on it. The holes made by the laser beam are called pits, interpreted as bit 0 and unburned areas are called lands interpreted as bit 1. Lower power laser beam is used to retrieve the data.

1. DVD(Digital Versatile Disc):
It is similar to CD but its storage capacity is much higher. The capacity of a DVD starts from 4.7 GB

2. Blu-ray Disc:
It is used to read and write High Definition video data as well as to store very huge amount of data. While Cd and DVD uses red laserto read and write but it uses Blue-Violet laser, hence the name Blu ray disc. The blue violet laser has shorter wave length than a red laser so it can pack more data tightly.

3. Semiconductor storage (Flash memory):
It uses EEPROM chips. It is faster and long lasting.

• USB flash drive: It is also called thumb drive or pen drive. Its capacity varfes from 2 GB to 32 GB.
• Flash memory cards: It is used in Camera, Mobile phones, tablets etc to store all types of data.

Question 10.
Explain how e-Waste creates environmental issues. Usually there are four methods for e-Waste dispoal. Which one is the most effective? Why? Write a slogan to aware the public about e-Waste hazards.
Answer:
e-Waste disposal methods:

1. Reuse: Reusability has an important role of e-Waste management and can reduce the volume of e-Waste
2. Incineration: It is the process of burning e-Waste at high temperature in a chimney
3. Recycling of e-Waste: It is the process of making new products from this e-Waste.
4. Land filling: It is used to level pits and cover by thick layer of soil.

Question 11.
With the help of a block diagram, explain the functional units of a computer.
Answer:
Functional units of computer:
A computer is not a single unit but it consists of many functional units(intended to perform jobs) such as Input unit, Central Processing Unit(ALU and Control Unit), Storage (Memory) Unit and Output Unit.
1. Input Unit:
Its aim is to supply data (Alphanumeric, image , audio, video, etc.) to the computer for processing. The Input devices are keyboard, mouse, scanner,mic, camera,etc

2. Central Processing Unit (CPU):
It is the brain of the computer and consists of three components

• Arithmetic Logic Unit(ALU): As the name implies it performs all calculations and comparison operations.
• Control Unit(CU): It controls overall functions of a computer
• Registers: It stores the intermediate results temporarily.

3. Storage Unit(Memory Unit):
A computer has huge storage capacity. It is used to store data and instructions before starts the processing. Secondly it stores the intermediate results and thirdly it stores information(processed data), that is the final results before send to the output unit(Visual Display Unit, Printer, etc)

Two Types of storage unit
(a) Primary Storage alias Main Memory:
It is further be classified into Two- Random Access Memory(RAM) and Read Only Memory(ROM). The one and only memory that the CPU can directly access is the main memory at a very high speed.

It is expensive hence storage capacity is less. RAM is volatile (when the power is switched off the content will be erased) in nature but ROM is non volatile(lt is permanent)

(b) Secondary Storage alias Auxiliary Memory:
Because of limited storage capacity of primary memory its need arises. When a user saves a file, it will be stored in this memory hence it is permanent in nature and its capacity is huge. eg: Hard Disc Drive(HDD), Compact Disc(CD), DVD, Pen Drive, Blu Ray Disc etc.

4. Output Unit:
After processing the data we will get information as result, that will be given to the end user through the output unit in a human readable form. Normally monitor and printer are used.

Students can Download Chapter 12 Introduction to Three Dimensional Geometry Questions and Answers, Plus One Maths Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus One Maths Chapter Wise Questions and Answers Chapter 12 Introduction to Three Dimensional Geometry

Plus One Maths Introduction to Three Dimensional Geometry Three Mark Questions and Answers

Question 1.
Prove by using distance formula that the A(1, 2, 3), B(-1, -1, -1) and C(3, 5, 7) are collinear.
Answer:

Now BC = AB + AC
Thus A, B, C are collinear.

Question 2.
Verify the following: (3 score each)

1. (0, 7, -10), (1, 6, -6) and (4, 9, -6) are the vertices of an isosceles triangle.
2. (0, 7, 10), (-1, 6, 6) and (-4, 9, 6) are the vertices of a right angled triangle.
3. (-1, 2, 1), (1, -2, 5), (4, -7, 8) and (2, -3, 4) are the vertices of a parllelogram.

Answer:
1. Let A(0, 7, -10), B(1, 6, -6) and C(4, 9, -6) be the two points.

Now AB = BC, thus ABC is an isosceles triangle.

2. Let A(0, 7, 10), B(-1, 6, 6) and C(-4, 9, 6) be the two points.


Now AC² = AB² + BC², thus ABC is a right triangle.

3. Let A(-1, 2, 1), B(1, -2, 5), C(4, -7, 8) and D(2, -3, 4) be the two points.

Now AB = CD, BC = AD, AC ≠ BD, thus A, B, C, D are vertices of a parallelogram.

Question 3.
Find the equation of set points which are equidistant from the points (1, 2, 3) and (3, 2, -1).
Answer:
Let P(x,y,z) be any point which is equidistant from the point A(1, 2, 3) and B (3, 2, -1).
Given; PA = PB

(x – 1)² + (y – 2)² + (z – 3)²
= (x – 3)² + (y – 2)² + (z + 1)²
= x² – 2x + 1 + y² – 4y + 4 + z² – 6z + 9
= x² – 6x + 9 + y² – 4y + 4 + z² + 2z + 1 – 2x + 14 – 6z = -6x + 14 + 2z
⇒ 4x – 8z = 0
⇒ x – 2z = 0.

Question 4.
Find the coordinate of the point which divides the line segment joining the points (3, -2, 5) and (3, 4, 2) in the ratio 2:1 (3 score each)

1. 2:1 internally
2. 2:1 externally

Answer:
1. Let P(x, y, z) be any point which divides the line segment joining points A(3, -2, 5) and B (3, 4, 2) in the ratio 2:1 internally.

Therefore coordinates of P are (3, 2, 3).

2. Let P(x, y, z) be any point which divides the line segment joining points A(3, -2, 5) and B (3, 4, 2) in the ratio 2:1 externally.

Therefore coordinates of P are (3, 10, -1).

Question 5.
Find the ratio in which the line joining the points (1, 2, 3) and (-3, 4, -5) is divided by the xy-plane.
Answer:
Let the line joining the points A(1, 2, 3) and B(-3, 4, -5) is divided by the xy-plane in the ratio k:1.
Then the coordinate

Since the point lies on xy-axis, we have;

Thus the required ratio is \(\frac{3}{5}\); ie, 3:5.

Question 6.
Find the coordinates of the points which trisect the line segment joining the points P(4, 2, -6) and Q (10, -16, 6).
Answer:

Let R and S be two points which trisect the line join of PQ. Therefore PR = RS = SQ Then coordinate of R is

= (6, -4, -2)
Then coordinate of S is

= (8, -10, 2).

Plus One Maths Introduction to Three Dimensional Geometry Practice Problems Questions and Answers

Question 1.
Find the distance between the following pair of points: (1 score each)

1. (2, 3, 5) and (4, 3, 1)
2. (-3, 7, 2) and (2, 4, -1)
3. (-1, 3, -4) and (1, -3, 4)

Answer:
1. Let A(2, 3, 5) and B(4, 3, 1) be the two points.

2. Let A(-3, 7, 2) and B(2, 4, -1) be the two points.

3. Let A(-1, 3, -4) and B(1, -3, 4) be the two points.

Students can Download Chapter 5 Trial Balance and Rectification of Errors Questions and Answers, Plus One Accountancy Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus One Accountancy Chapter Wise Questions and Answers Chapter 5 Trial Balance and Rectification of Errors

Plus One Accountancy Trial Balance and Rectification of Errors One Mark Questions and Answers

Question 1.
Which of the following statement is wrong regarding Trial Balance.
(a) Trial balance is a part of the double-entry system.
(b) It is not an account
(c) It is prepared on a specific date
(d) It is prepared to check the arithmetical accuracy of the books of accounts.
Answer:
(a) Trial balance is a part of double entry system.

Question 2.
Sale of machinery is credited to sales a/c is an error of
(a) Commission
(b) Omission
(c) Principle
(d) None of these
Answer:
(c) Principle

Question 3.
Debiting wages account with the amount of wages paid on erection of machinery is an errors of be debited with
(a) Rs. 400
(b) Rs. 800
(c) Rs. 200
(d) None of the above
Answer:
(b) Rs. 800

Question 4.
Which of the errors does not affect the trial balance?
(a) Wrong balancing
(b) Wrong totaling
(c) Writing an amount in the wrong account but in the correct side.
(d) None of the above.
Answer:
(c) Writing an amount in the wrong account but in the correct side.

Question 5.
Instead of debiting Sanoj’s A/c his account was credited by Rs. 400. To rectify this his account should
(a) Omission
(b) Principle
(c) Commission
Answer:
(b) Principles

Question 6.
Trial balance is
(a) An account
(b) A statement
(c) A subsidiary Book
(d) A Principal book
Answer:
(b) A Statement

Question 7.
Agreement of trial balance is affected by>
(a) One-sided errors only
(b) Two-sided errors only
(c) Both a and b
(d) None of these
Answer:
(c) Both a and b

Question 8.
A trial balance is prepared to check the …………… of ledger accounts.
Answer:
Arithmetical accuracy

Question 9.
If purchase of furniture is recorded in the purchase book, it is an error of …………..
Answer:
Principle

Question 10.
If purchase of goods on credit is not recorded in the books, it is an error of …………
Answer:
Omission

Question 11.
An account in which the difference of trial balance is temporarily put is ………… account.
Answer:
Suspense.

Question 12.
Error of …………. does not affect the trial balance.
Answer:
Principle.

Plus One Accountancy Trial Balance and Rectification of Errors Two Mark Questions and Answers

Question 1.
Match the following.

1. Installation charges debited to wages account.
2. Cash paid to ‘X’ is not posted to his account.
3. Cash paid to ‘A’ is posted, to B’s account.
4. Sales books and purchase books are undercast by same account.
5. The sales book is overcast by Rs. 100.

a. Error of commission
b. Compensating error
c. Error of principle
d. One side error
e. Error of omission

Answer:

• 1-c
• 2-e
• 3-a
• 4-b
• 5-d

Question 2.
Complete the following on the basis of hint given.

1. Errors of principle – Rule of accounting is violated
2. _____ – Wrong amount is written in subsidiary books.

Answer:
Error of commission.

Question 3.

1. One-sided error – Undercast in Sales returns book
2. ______ – Purchase of machinery entered in purchase book.

Answer:
Two-sided error.

Question 4.
What do you mean by Trial Balance?
Answer:
Trial balance is a statement that shows either the balance or total amounts of debit items and credit items of all accounts. It is prepared on a particular date to test the arithmetical accuracy of the books of accounts kept under the double-entry system.

Question 5.
Why a trial balance is prepared?
Answer:
A trial balance is prepared:

1. To check the arithmetical accuracy of the ledger accounts.
2. To help in locating errors
3. To provide a basis for preparing the financial statements.

Question 6.
Agreement of Tial balance is a proof of accuracy of books of accounts. Do you agree? Explain.
Answer:
No, the tallying of the trial balance does not mean that no errors have been committed in the accounting records. There can be errors which do not affect the equality of debits and credits and there can be errors which affect the equality of debits and credits.

Question 7.
Furniture purchased for Rs. 10,000 from Nirmal has been recorded as follows:

• Nirmal A/c Dr 10,000
• FurnitureA/c 10,000
• If it is incorrect, rectify it by passing rectification entry.

Answer:

• The journal entry is incorrect.
• Rectification entry is – FurnitureA/c Dr 20,000
• Nirmal A/c 20,000

Question 8.
On 31^st March 2005, when the trial balance of Abi stores was prepared it showed a difference. Inspite of his continuous efforts, the accountant could not locate errors. But the preparation of financial statements cannot be delayed. Is it possible to prepare financial statements with such a trial balance. Can you suggest a solution at the juncture?
Answer:
If the trial balance doesn’t agree even after the repeated efforts, it is better to place the difference under suspense A/c. Otherwise it will cause inordinate delay in tpe preparation of final accounts. However, the suspense a/c has to be later removed by closely scrutinising the books of accounts in due course.

Question 9.
‘Closing stock is normally given out the trial balance’. State the reason.
Answer:
Usually no separate ledger accounts are maintained for stock account. The valuation of stock will be done at the end of a particular period when financial statements are prepared. Therefore it appears out the trial balance.

Question 10.
What are the methods of preparing trial balance?
Answer:
There are three methods of preparing trial balance They are:

1. Totals method (Total of each side in the ledger)
2. Balance method (Showing the balances of all ledger accounts.
3. Totals – cum – balances method

Question 11.
Explain Error of principles with examples.
Answer:
If any accounting rules or principles are violated in recording a transaction, it is an error of principles. This error does not affect the agreement of trial balance.
Examples :-

1. Expenses paid for installation of machinery debited to expenses account.
2. The sale of building is credited to sales account.
3. Amount spent on repair of machinery debited to machinery account.
4. Purchase of furniture debited to purchase account.

Plus One Accountancy Trial Balance and Rectification of Errors Three Mark Questions and Answers

Question 1.
When do you open a suspense account? Explain its uses.
Answer:
When all attempts fails to locate errors and the preparation of the final accounts can not be further delayed, the difference in the trial balance is temporarily transferred to an account called “suspense account’’. Uses of suspense Account.

1. It facilitates the preparation of financial statements even when the trial balance has not tallied.
2. It helps in giving rectifying entries after the preparation of trial balance.

Question 2.
Mr. Murali’s trial balance showed a difference of Rs. 5,500 on the credit side. The following errors were revealed from the books of account.

• The purchase of books were overcast by Rs. 3000.
• The salary paid to Renjith Rs. 7000 has been posted twice.
• Received from Manu Rs. 5000 has been credited Rs. 500.
• Prepare a suspense account.

Answer:
Suspense A/c

Question 3.
Explain Error of omission with Examples.
Answer:
Error of omission:
When a transaction is not entered in the books of original entry or not posted from the books original entry to the ledger, an error of omission is caused. The omission may be complete or partial. If a transaction is not entered in the subsidiary books, it is a case of complete omission as the posting in the ledger accounts are also omitted.

In this both the debit and credit aspects go unrecorded, it does not affect the agreement of Trial Balance. If only one aspect of a transaction is recorded, it is a case of Partial omission. It happens while posting from day books to ledger accounts. This will affect the agreement of Trial balance.

Question 4.
Explain Error of Commission with example.
Answer:
Error of commission:
Errors committed when transactions are incorrectly recorded are called error of commission. These are the errors caused by wrong posting, wrong totaling, wrong balancing, wrong carryforwards, etc. For example- if Rs. 290 received from Ram is credited to his account as Rs. 209, it is an error of commission, Error in posting as to the side of account – Rs. 300 received from Kumar is posted his Debit side.

Question 5.
Explain Error of Principles Error with examples.
Answer:
Error of principles:
If any accounting rules or principles are violated in recording a transaction, it is an error of principles. This error does not affect the agreement of trial balance.
Examples:

1. An item of capital expenditure is wrongly debited to a revenue account.
2. Sale of building is credited to sales account.

Question 6.
Explain compensating error with examples.
Answer:
Compensating Error:
These errors arise when a mistake made in one direction is compensated by another mistake made in the opposite direction, to the extent of same amount. These errors do not affect the agreement of trial balance.

For example:
If Purchase of goods from ‘X’ for Rs. 800 is credited to his account as Rs.80 and a purchase from T for Rs. 80 is credited to y’s account as Rs. 800.

Question 7.
Name the errors which do not affect the Trial Balance.
Answer:

1. Error of complete omission
2. Error of principle,
3. Compensating Error
4. Error of recording in the book of original entry
5. Error of posting to wrong account on credit side with correct amount.

Question 8.
Name the errors which affect the Trial Balance.
Answer:

1. Errors due to partial omission
2. Error of casting
3. Posting an amount in the wrong side of an account.
4. Posting of a wrong amount
5. Wrong totaling or balancing of accounts

Question 9.
Rectify the following errors:
Cash sales Rs. 16,000
a) were not posted to sales a/c
b) were posted as Rs. 6000 in sales account
c) were posted to commission account
Answer:

Question 10.
Locate the types of errors involved in the following transactions.

1. Purchased goods for 10,000 debited to furniture a/c.
2. Carriage paid Rs. 1,000 debited to carriage a/c as Rs. 100.
3. Amount received from Rajesh Rs. 1,800 has not been entered in the books of accounts.

Answer:

1. Error of principle
2. Error of commission
3. Error of omission

Plus One Accountancy Trial Balance and Rectification of Errors Four Mark Questions and Answers

Question 1.
What are the objectives of preparing a trial balance?
Answer:
A Trial balance is prepared with the following objectives:
1. To ascertain the arithmetical accuracy of ledger accounts:
A Trial balance is prepared to check the arithmetical accuracy of ledger accounts. If the sum of the debit and credit columns of Trial balance is equal, it is assumed that the posting to the ledger accounts is accurate. This is because, for every debit we give an equal credit.

2. To help in ascertaining errors:
Some of the errors in the books of account can be detected by the trial balance. An untallied trial balance indicates that some errors have been committed.

3. To provide a basis for preparing final accounts:
The ultimate aim of maintaining books of accounts is to ascertain the financial result and position of the business. For this purpose profit and loss account and blance sheet is prepared on the basis of trial balance.

Question 2.
Check the arithmetical accuracy of the ledger account balances from the following.

Trial Balance as on …………..
Answer:

Question 3.
Pass journal entries to rectify the following transactions.
a) Purchase of machinery was debited to purchase a/c Rs. 8,000.
b) Goods sold on credit was recorded twice Rs. 1,500.
c) The repair of building was debited to building a/c Rs. 6,000.
d) Rs. 200 received from Jose posted to the debit of his account.
Answer:

Question 4.
Rectify the following errors:

1. Stationery purchased for ₹500 has been wrongly debited to drawings a/c.
2. A credit sale of ₹1,500 has been wrongly passed through the purchase book.
3. ₹4,000 received from Sidhu have been posted on the credit side of his account ₹4,400.
4. Salary ₹10,000 paid to Mr. Shaju was debited to his personal account.

Answer:
Journal

Plus One Accountancy Trial Balance and Rectification of Errors Five Mark Questions and Answers

Question 1.
Show how you would correct the following errors, write Journal entries.

1. Rs. 5,000 received on the sale of an asset has been credited to sales account.
2. A credit purchase of goods amounting to Rs. 500 from Raghavan had not been recorded in the books.
3. Sales book was undercast by Rs. 500.
4. Wages Rs. 750 paid for the installation of a new machine are debited to salaries and wages account.
5. An amount of Rs. 500 written off as depreciation has not been posted to depreciation account.

Answer:
Journal Proper

Question 2.
Identify the mistakes crept into the trial balance and redraft it in its proper form.
Trial Balance

Answer:

Question 3.
Rectify the following errors
(a) Furniture purchased for ₹10,000 wrongly debited to purchase account.
(b) Machinery purchased on credit from Raman for ₹20,000 was recorded through purchase book.
(c) Repairs on machinery ₹1.400 debited to machinery account.
(d) Repairs on overhauling of secondhand machinery purchased ₹2,000 was debited to repair the account.
(e) Sales of old machinery at book value of ₹3,000 was credited to sales account.
Rectification Entries in Journal
Answer:

Plus One Accountancy Trial Balance and Rectification of Errors Six Mark Questions and Answers

Question 1.
Rectify the following Mistakes.

1. The purchase day book is undercast (totaled less) by Rs. 180.
2. Sales day book is overcast (totaled more) by Rs. 100.
3. The purchase return book is totaled more by Rs. 80.
4. Sales return book is less by Rs. 110.
5. Rent paid Rs. 600 is omitted to post to rent account.
6. The commission received Rs. 40 is omitted and not posted to the commission account.
7. Salary paid Rs. 350 is posted twice to salary A/c.

Answer:
1. As the purchase account is less by Rs. 180, It should be debited to the purchase account. It should be shown in the debit side as : Undercast in purchase Day Book Rs. 180 Or Mistake in posting.

2. Sales Account is more by Rs. 100. To correct it, Rs. 100 be shown in the debit side of sales A/c as: Overcast in Day Book Rs. 100.

3. Purchase Returns Accounts is credited more by Rs. 80. Now it should be debited with the amount as Overcast in Day Book Rs. 100.

4. The effect is that the sales Return Account is less by Rs. 110. It should how be debited with the amount as Mistake in totaling Rs. 110.

5. Rent account should be debited with Rs. 600 as Omission in posting Rs. 600.

6. The commission account should be credited with Rs. 40 as Omission in posting Rs. 40.

7. The salary account is debited more by Rs. 350. It should now be credited with Rs. 350 as Mistake in polling Rs.350.

Question 2.
Veeran failed to balance his trial balance the credit side being more by Rs. 420. The difference is placed in a suspense a/c. Later on the following are discovered. Give rectifying entries and also prepare suspense A/c.

1. Sales Book was undercast by Rs. 100.
2. Goods for Rs. 300 purchased on credit from Raj was wrongly entered in the sales book. The account of Raj was correctly credited.
3. The sales return book was undercast by Rs. 30.
4. A credit item of Rs. 10 was wrongly debited to Renny’s account as Rs. 100.

Answer:
Journal

Suspense A/c

Question 3.
Rectify the following errors:-
a) Discount allowed to Ramesh Rs. 60 on receiving Rs.2000 from him was not recorded in the books.
b) Discount received from Ram Rs. 80 on paying 1900 to him was not posted at all.
c) Bill receivable from Narayan Rs. 1000 was dishonored and wrongly debited allowance account as Rs. 10,000.
d) Cash received from Mohan Rs. 3000 was posted to Naveen as Rs. 1000.
e) Cheques for Rs. 7800 received from Anu in full settlement of his account of Rs. 8000, was dishonored. No. entry was passed in the books on dishonor of the cheque.
f) Old machinery sold to Kannan at its book value of Rs.4000 was recorded through sales book.
g) Depreciation written off as the Machinery Rs.3000, was not posted at all.
Answer:

Plus One Accountancy Trial Balance and Rectification of Errors Eight Mark Questions and Answers

Question 1.
Rectify the following errors by giving correcting entries.

1. Credit purchase of goods for Rs. 850 from chand and sons has not been recorded in the daybook.
2. Rent paid to landlord is debited in landlord’s account Rs. 600.
3. Purchase of Machinery from Precision Machinery Ltd. for Rs. 28,000 is recorded in purchase daybook. j
4. Carriage paid on purchase of furniture Rs. 300 is debited in carriage account.
5. Private expenses Rs. 200 is debited in Trade Expenses Account.
6. Goods sold to Renjith for Rs. 500 has been wrongly recorded in purchase daybook.
7. Purchase of furniture for the personal use of the proprietor of Rs. 920 has been debited in furniture a/c.
8. Rs. 180 received from Salini has been credited in the account of Sajini.

Answer:

Students can Download Chapter 11 Conic Sections Questions and Answers, Plus One Maths Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus One Maths Chapter Wise Questions and Answers Chapter 11 Conic Sections

Plus One Maths Conic Sections Three Mark Questions and Answers

Question 1.
Find the coordinate of the foci, the vertices, the length of major axis, the minor axis, the eccentricity and the length of the latus rectum of the ellipse. (3 score each)

1. \(\frac{x^{2}}{4}+\frac{y^{2}}{25}\) = 1
2. \(\frac{x^{2}}{16}+\frac{y^{2}}{9}\) = 1

Answer:
1. Since 25 > 4 the standard equation of the ellipse is \(\frac{x^{2}}{b^{2}}+\frac{y^{2}}{a^{2}}\) = 1 ⇒ a² = 25; b² = 4
c² = a² – b² = 25 – 4 = 21 ⇒ c = \(\sqrt{21}\)
Coordinate of foci are (0, ±\(\sqrt{21}\))
Coordinate of vertex are (0, ±5)
Length of major axis = 2a = 2 × 5 = 10
Length of minor axis = 2b = 2 × 2 = 4
Eccentricity = e = \(\frac{c}{a}=\frac{\sqrt{21}}{5}\)
Length of latus rectum = \(\frac{2 b^{2}}{a}=\frac{2 \times 4}{5}=\frac{8}{5}\).

2. Since 16 > 9 the standard equation of the ellipse is \(\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}\) = 1 ⇒ a² = 16; b² = 9
c² = a² – b² = 16 – 9 = 7 ⇒ c = \(\sqrt{7}\)
Coordinate of foci are (±\(\sqrt{7}\), 0)
Coordinate of vertex are (±4, 0)
Length of major axis = 2a = 2 × 4 = 8
Length of minor axis = 2b = 2 × 3 = 6
Eccentricity = e = \(\frac{c}{a}=\frac{\sqrt{7}}{4}\)
Length of latus rectum = \(\frac{2 b^{2}}{a}=\frac{2 \times 9}{4}=\frac{9}{2}\).

Question 2.
Find the ellipse satisfying the following conditions: (3 score each)

1. Vertex (±5, 0); foci (±4, 0)
2. Ends of the major axis (±3, 0), ends of minor axis (0, ±2)
3. Length of the major axis 26, foci (±5, 0)
4. b = 3, c = 4, centre at origin; foci on the x-axis

Answer:
1. Foci (±4, 0) lie on the x-axis. So the equation of the ellipse is of the form \(\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}\) = 1
Given; Vertex (±5, 0) ⇒ a = 5
Given; Foci(±4, 0) Foci ⇒ c = 4 = \(\sqrt{a^{2}-b^{2}}\)
⇒ 4 = \(\sqrt{25-b^{2}}\) ⇒ 16 = 25 – b² ⇒ b² = 9
Therefore the equation of the ellipse is
\(\frac{x^{2}}{25}+\frac{y^{2}}{9}=1\).

2. The ends of major axis lie on the x-axis. So the equation of the ellipse is of the form
\(\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}\) = 1
Given; Ends of the major
axis (±3, 0) ⇒ a = 3, ends of minor axis
(0, ±2) ⇒ b = 2
Therefore the equation of the ellipse is
\(\frac{x^{2}}{9}+\frac{y^{2}}{4}=1\).

3. Since foci (±5, 0) lie on x-axis, the standard form of ellipse is \(\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}\) = 1
Given; 2a = 26 ⇒ a = 13
Given; c = 5 = \(\sqrt{a^{2}-b^{2}}\)
⇒ 25 = 169 – b² ⇒ b² = 144
Therefore the equation of the ellipse is
\(\frac{x^{2}}{169}+\frac{y^{2}}{144}=1\).

4. The standard form of ellipse is
\(\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}\) = 1
Given; c = 4 = \(\sqrt{a^{2}-b^{2}}\)
⇒ 16 = a² – 9 ⇒ a² =25
Therefore the equation of the ellipse is
\(\frac{x^{2}}{25}+\frac{y^{2}}{9}=1\).

Question 3.
Find the coordinates of foci, the vertices, eccentricity and the length of latus rectum of the following hyperbolas. (3 score each)

1. \(\frac{y^{2}}{9}-\frac{x^{2}}{27}=1\)
2. 5y² – 9x² = 36

Answer:
1. The equation of the hyperbola is of the form
\(\frac{y^{2}}{a^{2}}-\frac{x^{2}}{b^{2}}=1\) ⇒ a² = 9; b² = 27
⇒ c² = a² + b² ⇒ c² = 9 + 27 = 36 ⇒ c = 6
Coordinate of foci are (0, ±6)
Coordinate of vertices are (0, ±a) ⇒ (0, ±3)
Eccentricity = \(\frac{c}{a}=\frac{6}{3}=2\)
Length of latus rectum = \(\frac{2 b^{2}}{a}=\frac{2 \times 27}{3}=18\).

2. Given; 5y² – 9x² = 36


The equation of the hyperbola is of the form

Coordinate of vertices are

Question 4.
Find the hyperbola satisfying the following conditions: (3 score each)

1. Vertices (+2, 0), foci (±3, 0)
2. Foci (±5, 0), the transverse axis is of length 8.
3. Foci(0, ±13), the conjugate axis is of length 24.
4. Foci (±3\(\sqrt{5}\), 0), the latus rectum is of length 8.
5. Vertices (±7, 0) , e = \(\frac{4}{3}\).

Answer:
1. Since Vertices are (±2, 0) the standard form of hyperbola is

⇒ a = 2
Given; foci (±3, 0) ⇒ c = 3
⇒ c² = a² + b² ⇒ 9 = 4 + b² ⇒ b² = 5
The equation of the hyperbola;

2. Since Foci are (±5,0) the standard form of hyperbola is

⇒ c = 5
Given; the transverse axis is of length 8.
⇒ 2a = 8 ⇒ a = 4
⇒ c² = a² + b² ⇒ 25 = 16 + b² ⇒ b² = 9
The equation of the hyperbola;

3. Since Foci are(0, ±13)the standard form of hyperbola is

⇒ c = 13
Given; the conjugate axis is of length 24.
⇒ 2b = 24 ⇒ b = 12
⇒ c² = a² + b² ⇒ 169 = a² + 144 ⇒ a² = 25.
The equation of the hyperbola;

4. Since Foci are(±3\(\sqrt{5}\), 0) the standard form of hyperbola is

⇒ c = 3\(\sqrt{5}\)
Given; the latus rectum is of length 8.
⇒ \(\frac{2 b^{2}}{a}\) = 8 ⇒ b² = 4a
⇒ c² = a² + b²
⇒ 45 = a² + 4a ⇒ a² + 4a – 45 = 0
⇒ (a + 9)(a – 5) = 0 ⇒ a = -9, 5
a = -9 is not possible
⇒ a = 5 ⇒ b² = 20
The equation of the hyperbola;

5. Since Vertices are (±7, 0) the standard form of hyperbola is

⇒ a = 7
Given;

⇒ c² = a² + b²

The equation of the hyperbola;

Question 5.
The line x – 1 = 0 is the directrix of a parabola, y² = kx then

1. Find the value of k. (1)
2. Find the vertex, focus, axis of parabola and length of latus rectum of the parabola. (3)

Answer:
1. Given directrix x – 1 = 0, so a = 1, then the equation of the parabola is
y² = -4ax ⇒ y² = -4x
Hence k = – 4

2. Vertex is (0, 0)
Focus of SS’ = (-1, 0)
Length of latus rectum = 4 × 1 = 4.

Question 6.
In the figure S and S’ are foci of the ellipse, \(\frac{x^{2}}{25}+\frac{y^{2}}{16}=1\) and P is a viable point on the ellipse.

1. Find the co-ordinate of foci. (2)
2. Find the distance between S and S1. (1)
3. What is the maximum area of the triangle PSS’. (1)

Answer:
1. Since 25 > 16 the standard equation of the ellipse is \(\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}\) = 1
⇒ a² = 25; b² = 16
c² = a² – b² = 25 – 16 = 9 ⇒ c = 3
Coordinate of foci are (±3, 0).

2. Distance between the two focus is 3 + 3 = 6.

3. Maximum area is attained when the point P reaches the point the ellipse meet the y
axis. Then area is = \(\frac{1}{2}\) × 6 × 4 = 12.

Plus One Maths Conic Sections Four Mark Questions and Answers

Question 1.
Find the equation of the circle passing through the points (4, 1) and (6, 5) and whose centre is on the line 4x + y = 16.
Answer:
Let the equation of the circle be
x² + y² + 2gx + 2fy + c = 0 ______(1)
Since (1) passes through (4, 1)
16 + 1 + 8g + 2f + c = 0
⇒ 8g + 2f + c = -17 ______(2)
Since (1) passes through (6, 5)
36 + 25 + 12g + 10f + c = 0
⇒ 12 g + 10f + c = -61 _______(3)
(1) – (2) ⇒ -4g – 8f = 16
⇒ -g – 2f = 4 ______(4)
Since centre is on the line 4x + y = 16, we have;
⇒ -4g – f = 16 ______(5)
Solving (4) and (5) We get; g = -3; f = -4
(2) ⇒ 8(-3) + 2(-4) + c = -17
⇒ -24 – 8 + c = -17 ⇒ c = 15
Then the equation of the circle is
x² + y² – 6x – 8y + 15 = 0.

Question 2.
Find the equation of the circle with radius 5 whose centre lies on x-axis and passes through the point (2, 3).
Answer:
Let the equation of the circle be
(x – h)² + (y – k)² = r²
centre lies on x axis so let the centre be (h, 0),
then (x – h)² + y² = 25
Since circle pass through (2, 3) we have;
(2 – h)² + 3² = 25
⇒ (2 – h)² = 16 ⇒ 2 – h = ±4
⇒ h = 6, -2
When h = 6 ; equation of circle is
(x – 6)² + (y – 0)² = 25
⇒ x² + 36 – 12x + y² = 25
⇒ x² + y² – 12x + 11 = 0
When h = -2; equation of circle is
(x + 2)² + (y – 0)² = 25
⇒ x² + 4 + 4x + y² = 25
⇒ x² + y² + 4x – 21 = 0.

Question 3.
Centre at (0, 0), major axis on the y-axis and passes through the points (3, 2) and (1, 6).
Answer:
Major axis lie on the y-axis so the standard equation of the ellipse is of the form

Since the ellipse passes through (3, 2)

Since the ellipse passes through (1, 6)

Solving (1) and (2), we have Since the ellipse passes through (3, 2)
a² = 40; b² = 10
Thus the equation of the ellipse is

Plus One Maths Conic Sections Six Mark Questions and Answers

Question 1.
Consider the point A (0, 0), B (4, 2) and C (8, 0)

1. Find the mid-point of AB. (1)
2. Find the equation of the perpendicular bisector of AB. (2)
3. Find the equation of the circum circle (Circle passing through the point A, B, and C) of triangle ABC. (3)

Answer:
1. Mid-point of AB is (2, 1).

2. Slope of line through AB
\(=\frac{2-0}{4-0}=\frac{1}{2}\)
Slope of perpendicular line is – 2
Equation of the perpendicular line to AB is
y – 1 = -2(x – 2) ⇒ 2x + y = 5.

3. The meeting point of perpendicular bisector of AB and AC will be the centre of the circum circle.
The line perpendicular to AC is x = 4
Solving and x = 4
We get y = 5 – 8 = -3 and x = 4
Hence centre is (4, -3) and radius is

Equation of the circle is
(x – 4)² + (y + 3)² = 5.

Plus One Maths Conic Sections Practice Problems Questions and Answers

Question 1.
Find the equation of the circle In each of the following cases. (2 score each)

1. Centre (0, 2) and radius 2.
2. Centre (-2, 3) and radius 4.
3. Center \(\left(\frac{1}{2}, \frac{1}{4}\right)\) and radius \(\frac{1}{12}\).

Answer:
1. The equation of the circle is
(x – 0)² + (y – 2)² = 2²
⇒ x² + y² – 4y + 4 = 4
⇒ x² + y² – 4y = 0.

2. The equation of the circle is
(x + 2)² + (y – 3)² = 4²
⇒ x² + 4x + 4 + y² – 6y + 9 = 16
⇒ x² + y² + 4x – 6y – 3 = 0.

3. The equation of the circle is

⇒ 144x² + 36 – 144x + 144y² + 9 – 72y = 1
⇒ 144x² + 144y² – 144x – 72y + 44 = 0
⇒ 36x² + 36y² – 36x – 18y + 11 = 0.

Question 2.
Find the centre and radius of the following circles. (2 score each)

1. x² + y² – 4x – 8y – 45 = 0
2. x² + y² – 8x – 10y -22 = 0
3. 2x² + 2y² – x = 0

Answer:
1. Comparing with the general equation we have
g = -2; f = -4; c = -45
Centre – (-g, -f) ⇒ (2, 4)
Radius – \(\sqrt{g^{2}+f^{2}-c}\)

2. Comparing with the general equation we have
g = -4; f = -5; c = -22
Centre – (-g, -f) ⇒ (4, 5)
Radius – \(\sqrt{g^{2}+f^{2}-c}\)

3. Convert the equation into standard form

Question 3.
Find the coordinate of the focus, axis of the parabola, the equation of the directrix and the length of the latus rectum. (2 score each)

1. y² = 20x
2. x² = 8
3. 3x² = -15

Answer:
1. Comparing the equation with the general form we get; 4a = 20 ⇒ a = 5
Coordinate of focus are (5, 0)
Axis of the parabola is y = 0
Equation of the directrix is x = -5
Length of latus rectum = 4 × 5 = 20.

2. Comparing the equation with the general form we get; 4a = 8 ⇒ a = 2
Coordinate of focus are (0, 2)
Axis of the parabola is x = 0
Equation of the directrix is y = – 2
Length of latus rectum = 4 × 2 = 8.

3. Convert the equation into general form, we get x² = -5y. Comparing the equation with the general form we get;
4a = 5 ⇒ a = \(\frac{5}{4}\)
Coordinate of focus are (0, \(-\frac{5}{4}\))
Axis of the parabola is x = 0
Equation of the directrix is y = \(\frac{5}{4}\)
Length of latus rectum = \(\frac{4 \times 5}{4}\) = 5.

Question 4.
Find the equation of the parabola satisfying the following conditions; (2 score each)

1. Focus(6, 0); directrix x = – 6
2. Vertex (0, 0); Focus (3, 0)
3. Vertex (0, 0) passing through (2, 3) and axis along x-axis

Answer:
1. Since the focus (6, 0) lies on the x-axis, therefore x-axis is the axis of parabola.
Also the directrix is x = – 6, ie; x = – a And focus (6, 0), ie; (a, 0)
Therefore the equation of the parabola is
y² = 4ax ⇒ y² = 24x.

2. The vertex of the parabola is at (0, 0) and focus is at (3, 0). Then axis of parabola is along x-axis. So the parabola is of the form y² = 4ax . The equation of the parabola is y² = 12x.

3. The vertex of the parabola is at (0, 0) and the axis is along x-axis. So the equation of parabola is of the torn y² = 4ax .
Since the parabola passes through point (2, 3)
Therefore, 3² = 4a × 2 ⇒ a = \(\frac{9}{8}\)
The required equation of the parabola is
y² = 4 × \(\frac{9}{8}\) x ⇒ y² = \(\frac{9}{2}\)x.

Question 5.
Find the Focus, vertex and latus rectum of the parabola y² = 8x.
Answer:
Given; y² = 8x, we have 4a = 8 ⇒ a = 2
Focus = (2, 0); Vertex = (0, 0)
Latus rectum = 4a = 8

Students can Download Chapter 10 Straight Lines Questions and Answers, Plus One Maths Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus One Maths Chapter Wise Questions and Answers Chapter 10 Straight Lines

Plus One Maths Straight Lines Three Mark Questions and Answers

Question 1.
Find the equation of the line passing through the point (2, 2) and cutting off intercepts on the axis whose sum is 9.
Answer:
Let equation of the line is \(\frac{x}{a}+\frac{y}{b}\) = 1 ______(1)
Given a + b = 9
Since (1) passes through (2, 2) we have;
\(\frac{2}{b}+\frac{2}{b}\) = 1 ⇒ 2a + 2b – ab ⇒ 2 (a + b) = ab
⇒ 18 = ab. Then the numbers are 3 and 6.
Hence the equation of the line is
\(\frac{x}{3}+\frac{y}{6}\) = 1 ⇒ 6x + 3y = 18 ⇒ 2x + y = 6

OR

\(\frac{x}{6}+\frac{y}{3}\) = 1 ⇒ 3x + 6y = 18 ⇒ x + 2y = 6.

Question 2.
The perpendicular from the origin to a line meets it at the point (-2, 9), find the equation of the line.
Answer:
Slope of the line through the origin and (-2, 9)

Then the slope of the required line is \(\frac{2}{9}\).
Hence the equation is y – y₁ = m(x – x₁)
⇒ y – 9 = \(\frac{2}{9}\)(x – (-2))
⇒ 9y – 81 = 2x + 4 ⇒ 2x – 9x + 85 = 0.

Question 3.
Reduce the following into normal form. (3 score each)

1. \(\sqrt{3}\)x + y – 8 = 0
2. 3x + 3y – 1 = 0

Answer:
1. The given equation can be written in the form \(\sqrt{3}\)x + y = 8
Divide the above equation by

we get;

which is the normal form. On comparing with
x cos θ + y sin θ = p
Where; cosθ = \(\frac{\sqrt{3}}{2}\); sinθ = \(\frac{1}{2}\) and p = 4.

2. The given equation can be written in the form 3x + 3y = 1
Divide the above equation by

we get;

which is the normal form. On comparing with x cosθ + y sinθ = p
Where; cosθ = \(\frac{1}{\sqrt{2}}\); sinθ = \(\frac{1}{\sqrt{2}}\) and p = \(\frac{1}{3 \sqrt{2}}\).

Question 4.
Find the angle between the given lines. (3 score each)

1. y – \(\sqrt{3}\)x – 5 = 0 and \(\sqrt{3}\)y – x + 6 = 0
2. 3x – 2y + 9 = 0 and 2x + y – 9 = 0

Answer:
1. Given; y – \(\sqrt{3}\)x – 5 = 0 and \(\sqrt{3}\)y – x + 6 = 0

⇒ θ = 30°.

2. Given; 3x – 2y + 9 = 0 and 2x + y – 9 = 0
⇒ 2y = 3x + 9 and y = -2x + 9

Question 5.
Find the transformed equation of the straight line 2x – 3y + 5 = 0, when the origin is shifted to the point (3, -1) after translation of axes.
Answer:
Let coordinates of a point P changes from (x, y) to (X, Y) in new coordinate axes whose origin has the coordinates h = 3, k = -1. Therefore, we can write the transformation formulae as x = X + 3 and y = y – 1.

Substituting, these values in the given equation of the straight line, we get 2(X + 3) – 3 (Y – 1) + 5 = 0 or 2X – 3Y + 14 = 0. Therefore, the equation of the straight line in new system is 2x – 3y + 14 = 0.

Question 6.
Find what the following equations become when the origin is shifted to the point (1, 1) x² + xy – 3y² – y + 2 = 0.
Answer:
We can write the transformation formulae as x = X + 1 and y = Y+ 1.
The new equation is
(X + 1)² + (X + 1)(Y + 1) – 3(Y + 1)² – (Y + 1) + 2 = 0
X² + XY – 3Y² + 3X – 6Y + 1 = 0
Therefore, the equation of the straight line in new system is x² + xy – 3y² + 3x – 6y + 1 = 0.

Question 7.
1. Identify the figure in which the line has a positive slope. (1)
a.

b.

c.

d.

2. Find the x and y intercepts of the line 3x + 4y – 12 = 0 (2)
Answer:
1. Figure b

2. 3x + 4y = 12

x – intercept = 4; y – intercept = 3.

Plus One Maths Straight Lines Six Mark Questions and Answers

Question 1.
Consider the line 4x – 3y + 12 = 0

1. Find the equation of the line passing through the point (1, 2) and parallel to the given line. (2)
2. Find the distance between these two parallel lines. (1)
3. Which among the following lines is perpendicular to the line 4x – 3y + 12 = 0 (1)
   • 2x + 3y – 8 = 0
   • 4x – 3y + 5 = 0
   • x + y = 7
   • 3x + 4y + 9 = 0

Answer:
1. Equation of the parallel line 4x – 3y + k = 0
Passing through (1, 2)
4(1) – 3(2) + k = 0 ⇒ k = 2
⇒ 4x – 3y + 2 = 0.

2. Distance \(\left|\frac{12-2}{\sqrt{25}}\right|=\frac{10}{5}=2\).

3. 3x + 4y + 9 = 0.

Plus One Maths Straight Lines Practice Problems Questions and Answers

Question 1.
Find the slope of the lines passing through the points (1 score each)

1. (3, -2) and (-1, 4)
2. (4, -5) and (2, 1)
3. (0, -2) and (4, 3)

Answer:
1. Slope

2. Slope

3. Slope

Question 2.
Find a point on the x-axis, which is equidistant from the points (7, 6) and (3, 4).
Answer:
Let (x, 0) be the points on the x-axis. Then the distance will be same;
(x – 3)² + 16 = (x – 7)² + 36
⇒ x² – 6x + 9 + 16 = x² – 14x + 49 + 36
⇒ 14x – 6x = 49 + 36 – 9 – 16
⇒ 8x = 60 ⇒ x = \(\frac{15}{2}\)
Hence the point is (\(\frac{15}{2}\), 0).

Question 3.
Find the value of x for which the points (x, -1), (2, 1) and (4, 5) are collinear.
Answer:
The slope of the lines joining the points (x, -1) and (2, 1); (2, 1) and (4, 5) are same.

Question 4.
Line through the points (-2, 6) and (4, 8) is perpendicular to the line through the points (8, 12) and (x, 24). Find the value of x.
Answer:
The product of the slopes of the lines joining the points (-2, 6) and (4, 8); (8, 12) and (x, 24) will be equal to -1.

⇒ 12 = -3x + 24 ⇒ 3x = 12⇒ x = 4.

Question 5.
Find the equation the following lines satisfying the given conditions. (2 score each)

1. Passing through the point (-2, 3) with slope -4.
2. Passing through the point (-4, 3) with slope \(\frac{1}{2}\).
3. Line with y-intercept \(-\frac{3}{2}\) and slope \(\frac{1}{2}\)
4. Line with x-intercept – 3 and slope – 2.
5. Line which makes intercepts -3 and 2 on the x- and y-axis respectively.
6. Perpendicular distance from origin is 5 units and the angle the perpendicular makes with the positive direction of x-axis is 30°.
7. Passing through the point (-1, 1) and (2, -4).
8. Passing through the point (1, -1) and (3, 5).

Answer:
1. Equation of the line is y – y₁ = m(x – x₁)
⇒ y – 3 = -4(x – (-2))
⇒ y – 3 = -4x – 8 ⇒ 4x + y + 5 = 0.

2. Equation of the line is y – y₁ = m(x – x₁)
⇒ y – 3 = \(\frac{1}{2}\)(x – (-4))
⇒ 2y – 6 = x + 4 ⇒ x – 2y + 10 = 0.

3. Equation of the line is y = mx + c
⇒ y = \(\frac{1}{2}\) x – \(\frac{3}{2}\) ⇒ 2y = x – 3
⇒ x – 2y – 3 = 0.

4. Equation of the line is y = m(x – d)
⇒ y = -2(x – (-3)) ⇒ y = -2x + 6
⇒ 2x + y = 6.

5. Equation of the line is \(\frac{x}{a}+\frac{y}{b}\) = 1
⇒ \(\frac{x}{-3}+\frac{y}{2}\) = 1 ⇒ 2x – 3y = -6
⇒ 2x – 3y + 6 = 0.

6. Equation of the line is xcosθ + ysinθ = p
⇒ xcos30° + ysin30° = 5

7. Equation of the line is

8. Equation of the line is

Question 6.
Find the equation of the line passing through the point (-3, 5) and perpendicular to the line through the points (2, 5) and (-3, 6).
Answer:
Slope of the line through the points (2, 5) and (-3, 6)

Then the slope of the required line is 5. Hence the equation is y – y₁ = m(x – x₁)
⇒ y – 5 = 5(x – (-3)
⇒ y – 5 = 5x + 15 ⇒ 5x – y + 20 = 0.

Question 7.
Find the equation of the line that cut off equal intercepts on the coordinate axis and passes through the point (2, 3).
Answer:
Let the equal intercept is ‘a’, then equation of the required line is \(\frac{x}{a}+\frac{y}{a}=1\)
Since this line passes through the point (2, 3),
we have; \(\frac{2}{a}+\frac{3}{a}=1\) ⇒ \(\frac{5}{a}\) = 1 ⇒ a = 5
Therefore the equation of the line is \(\frac{x}{5}+\frac{y}{5}=1\)
⇒ x + y = 5.

Question 8.
P(a, b) is the mid-point of a line segment between axis. Show that equation of the line is \(\frac{x}{a}+\frac{y}{a}=2\).
Answer:
Since the P(a, b) is the mid-point of the line segment, then the x-intercept and the y-intercept will be 2a and 2b. Hence the equation of the line is

Question 9.
Find the slope, x-intercept and y-intercept of the following lines. (2 score each)

1. 3x – 4y + 10 = 0
2. 6x + 3y – 5 = 0
3. 4x – 3y = 6

Answer:
1. Given the equation of the line is 3x – 4y + 10 = 0 ⇒ 4y = 3x + 10

2. Given the equation of the line is 6x + 3y – 5 = 0 ⇒ 3y = -6x + 5

3. Given the equation of the line is
4x – 3y = 6 ⇒ 3y = 4x – 6

Question 10.
Find the distance between the parallel lines. (2 score each)

1. 3x – 4y + 7 = 0 and 3x – 4y + 5 = 0
2. 15x + 8y – 34 = 0 = 0 and 30x + 16y + 62 = 0

Answer:
1. The distance between the lines 3x – 4y + 7 = 0 and 3x – 4y + 5 = 0

2. The distance between the lines
15x + 8y – 34 = 0 = 0 and 15x + 8y + 31 = 0 is

Question 11.
Find the distance between the given point and the line. (2 score each)

1. Line 3x – 4y – 26 = 0 and point (3, -5)
2. Line 12(x + 6) = 5(y – 2)and point(-1, 1)

Answer:
1. The distance between the line and the

2. Express the line in standard form
12(x + 6) = 5(y – 2) ⇒ 12x + 72 = 5y – 10
⇒ 12x – 5y + 82 = 0
The distance between the line and the point is

Question 12.
Find the equation of the line parallel to the line 3x – 4y + 2 = Oand passing through the point (-2, 3).
Answer:
The equation of the line parallel to the line 3x – 4y + 2 = 0 is of the form 3x – 4y + k = 0.
Since it passes through (-2, 3), we have;
3(-2) – 4(3) + k = 0 ⇒ -6 – 12 + k = 0
⇒ -18 + k = 0 ⇒ k = 18
Hence the equation is 3x – 4y + 18 = 0.

Question 13.
Find the equation of the line x – 7y + 5 = 0 perpendicular to the line and having x-intercept 3.
Answer:
The equation of the perpendicular line will be 7x + y + k = 0.
Since x-intercept is 3, the line passes through the point (3, 0). So we have;
7(3) + 0 + k = 0 ⇒ 21 + 0 + k = 0 ⇒ k = -21
Therefore the equation is 7x + y – 21 = 0.

Question 14.
Find the new coordinates of point (3, -4) if the origin is shifted to (1, 2) by a translation.
Answer:
The coordinates of the new origin are h = 1, k = 2, and the original coordinates are given to be
x = 3, y = -4
X = x – h; Y = y – k
Substituting the values, we have
X = 3 – 1 = 2 and Y = -4 – 2 = -6
Hence, the coordinates of the point (3, -4) in the new system are (2, – 6).

Students can Download Chapter 1 The Discipline of Computing Questions and Answers, Plus One Computer Science Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus One Computer Science Chapter Wise Questions and Answers Chapter 1 The Discipline of Computing

Plus One The Discipline of Computing One Mark Questions and Answers

Question 1.
Which is the base of Mayan’s Number System?
Answer:
Base 20

Question 2.
Greek Number System is known as _________.
Answer:
Ionian number system

Question 3.
Which was the first computer for basic arithmetic calculations?
Answer:
Abacus

Question 4.
Who invented logarithms?
Answer:
John Napier

Question 5.
What is the name of the machine developed by Blaise Pascal?
Answer:
Pascaline

Question 6.
Who was the first programmer in the world?
Answer:
Augusta Ada Lowelace

Question 7.
Computing machines recognizes and operates in ___________ language.
Answer:
Machine

Question 8.
What does EDVAC stand for?
Answer:
Electronic Discrete Variable Automatic Computer. It is designed by Von Neumann.

Question 9.
Give the name for a simple kind of theoretical computing machine.
Answer:
Turing Machine.

Question 10.
The Sumerian number system is also known as _________
Answer:
Sexagesimal

Question 11.
What are the features of Hindu Arabic Number system?
Answer:
The Hindu – Arabic number system had a symbol (0) for zero originated in India 1500 years ago. Its base is 1 0 and it is adopted by many countries.

Question 12.
How is the zero represented in the Babylonian Number System.
Answer:
Blank space

Question 13.
Write the number that is represented in the following Abacus.

Answer:

• 3 beads of the leftmost rod moved hence it represents 3.
• No beads (0) of the next rod moved hence it represents 0.
• 2 beads of the rightmost rod in the lower part is moved (2+) and one bead is moved in the upper part represents 5.

Hence 2 + 5 = 7
So the answer is 307

Question 14.
Which is the first automatic electromechanical computer?
(a) Pascaline
(b) Abacus
(c) Mark 1
(d) Analytical Engine
Answer:
(c) Mark 1

Question 15.
Find the correct match for each item in column A and B.

Answer:

Question 16.
Write the number represented in the abacus given below.

Answer:

• 2 Beads of the left most rod are moved hence it represents 2 – (a)
• 2 Beads of the next rod are moved (2) and one bead is moved in the upper part represents 5. Hence 2 + 5 = 7 – (b)
• 4 Beads of the next rod are moved (4) and one bead is moved in the upper part represents 5. Hence 4 + 5 = 9 – (c)

One bead of the right most rod in the lower part is moved (1) and one bead is moved in the upper part represents 5. Hence 1+5 = 6 – (d)
Join a, b, c and d hence the result is 2796

Question 17.
Who invented a machine to multiply any number by a number between 2 to 9? (1)
(a) Blaise Pascal
(b) John Napier
(c) G.W. Von Leibniz
(d) Joseph Marie Jacquard
Answer:
(c) G.W. Von Leibniz

Question 18.
Order the following technologies according to different generations of a computer (First to Fifth Generation) (1)

1. Transistor
2. Vacuum Tube
3. Artificial intelligence
4. Microprocessor

Answer:

1. Vacuum tube
2. Transistor
3. Microprocessor
4. Artificial intelligence

Question 19.
The number (158)10 can be represented in Hexadecimal number system as ______________
Answer:

Plus One The Discipline of Computing Two Mark Questions and Answers

Question 1.
Discuss the impact of the Hindu- Arabic numeral system in the world.
Answer:
It was originated in India around 1500 years ago and was a positional number system with symbol for zero. This greatest contribution is adopted by many of the countries.

Question 2.
Compare the Roman Number System and Mayan’s Number System.
Answer:
The Roman numerals consists of 7 letters such as I, V, X, L, C, D, M and the base is 7.
The Mayans used number system with base 20 because of the sum of the number of fingers and toes is 10 + 10 = 20. This was used for astronomical observations.

Question 3.
A full room sized computer in the first generation now becomes palm sized by the fourth generation. Explain the technological changes that made it possible.
Answer:
Vaccum tubes were used in first generation computers. Hence the size of computer was a size of full room. Instead of vaccum tubes transistors were used in the 2^nd generation hence size became smaller. In 3^rd generation, Integgted circuits (IC’s) were used. It reduced the size again in 4^th generation, microprocessors are used. It reduces the size again and again.

Plus One The Discipline of Computing Three Mark Questions and Answers

Question 1.
Discuss the developments of the number system from the Egyptian to the Chinese Era.
Answer:
Around 3000 BC Egyptians introduced a number system with base 10. They used unique symbols for 1 to 9, 10 to 90, 100 to 900 and 1000 to 9000. They write from right to left. The next era was of Sumerian/Babylonian number system its base was 60, the largest base also known as sexagesimal system.

They write from left to right. They use blank space for zero. Around 2500 BC Chinese introduced simplest and the most efficient number system. Its base was 10.

Question 2.
Discuss the features of Abacus.
Answer:
In 3000 BC Mesopotamians introduced this and it means calculating board or frame. It is considered as the first computer for basic arithmetical calculations and consists of beads on movable rods divided into two parts.

The Chinese improved the Abacus with seven beads on each wire. A horizontal divider separates the top two beads from the bottom five. The top two beads have a place value of 5 and the below five beads. The beads which are pushed against the horizontal bar represent the number.

Question 3.
Compare the Analytical Engine and Difference Engine of Charles Babbage.
Answer:
The intervention of human beings was eliminated by Charles Babbage in calculations by using Difference engine in 1822. It could perform arithmetic operations and print results automatically.

The Analytical Engine was a proposed mechanical general-purpose computer designed by English mathematician Charles Babbage. The Analytical Engine incorporated an arithmetic logic unit, control flow in the form of conditional branching and loops, and integrated memory.

Charles Babbage is considered as the “Father of computer” It is considered as the predecessor of today’s computer. This engine was controlled by programs stored in punched cards. These programs were written by Babbage’s assistant, Augusta Ada King, who was considered as the first programmer in the World.

Question 4.
Bring out the significance of Hollerith’s machine.
Answer:
In 1887, Herman Hollerith an American made first electromechanical punched cards with instructions for input and output. The card contained holes in a particular pattern with special meaning.

The Us Census Bureau had large amount of data to tabulate, that will take nearly 10 years. By this machine this work was completed in one year. In 1896, Hollerith started a company Tabulating Machine Corporation. Now it is called International Business Machines(IBM).

Question 5.
State the Moore’s Law and discuss its significance.
Answer:
The number of transistors on IC’s doubles approximately every two years. This law is called Moore’s Law, it is named after Gordon E Moore. It is an observation and not a physical or natural law. He predicted that the trend would continue for at least ten years. It is true and the trend continued for more than half a century.

Question 6.
Discuss the evolution of computer languages.
Answer:
The instructions to the computer are written in different languages. They are Low Level Language (Machine language), Assembly Language (Middle level language) and High Level Language (HLL). In Machine Language 0’s and 1’s are used to write , program. It is very difficult but this is the only language which is understood by the computer. In assembly language mnemohics (codes) are used to write programs.

Electronic Delay Storage Automatic Caleulator(EDSAC) built during 1949 was the first to use assembly language. In HLL English like statements are used to write programs. A – 0 programming language developed by Dr. Grace Hopper, in 1952, for UNIVAC-I is the first HLL.

A team lead by John Backus developed FORTRAN @IBM for IBM 704 computer and ‘Lisp’ developed by Tim Hart and Mike Levin at Massachusetts Institute of Technology. The other HLLs are C, C++, COBOL, PASCAL, VB, Java, etc. HLL is very easy and can be easily understood by the human being.

Usually programmers prefer HLL to write programs because of its simplicity. But computer understands only machine language. So there is a translation needed. The program which performs this job are language processors.

Question 7.
Discuss the working of Turing Machine.
Answer:
In 1936 Alan Turing introduced a machine, called Turing Machine. A Turing machine is a hypothetical device that manipulates symbols on a strip of tape according to a table of rules. This tape acts like the memory in a computer. The tape contains cells which starts with blank and may contain 0 or 1. So it is called a 3 Symbol Turing Machine.

The machine can read and write, one cell at a time, using a tape head and move the tape left or right by one cell so that the machine can read and edit the symbol in the neighbouring cells. The action of a Turing machine is determined by

1. the current state of the machine
2. the symbol in the cell currently being scanned by the head and
3. a table of transition rules , which acts as the program.

Question 8.
Explain Turing Test in detail?
Answer:
The Turing test is a test of a machine’s ability to exhibit intelligent behaviour equivalent to, or indistinguishable from, that of a human. The test involves a human judge engages in natural language conversations with a human and a machine designed to generate performance indistinguishable from that of a human being.

All participants are separated from one another. If the judge cannot reliably tell the machine from the human, the machine is said to have passed the test. The test does not check the ability to give the correct answer to questions; it checks how closely the answer resembles typical human answers. Turing predicted that by 2000 computer would pass the test.

Question 9.
Following are some facts related to evolution of computers :
(Usage of Transistors, Introduction of Very Large Scale Integrated Circuit, Construction of ENIAC) Categorize these under respective generations and briefly explain each. (3)
Answer:

• Transistor – Second generation
• VLSI – Fourth generation
• ENIAC – First generation

Question 10.
Why is it said “Turing machines are equivalent to modem electronic computers at a certain theoretical level”? (3)
Answer:
In 1887, Herman Hollerith an American made first electromechanical punched cards with instructions for input and output. The card contained holes in a particular pattern with special meaning. The Us Census Bureau had large amount of data to tabulate, that will take nearly 10 years.

By this machine this work was completed in one year. In 1896, Hollerith started a company Tabulating Machine Corporation. Now it is called International Business Machines(IBM).

Question 11.
Compare any three features of five generations of computers.
answer:

Plus One The Discipline of Computing Five Mark Questions and Answers

Question 1.
List out and explain the various generations of computers.
Answer:
There are five generations of computers from 16^th century to till date.

1. First generation computers (1940 – 1956):
Vacuum tubes were used in first generation computers. The input was based on punched cards and paper tapes and output was displayed on printouts. The Electronic Numerical Integrator and Calculator(ENIAC) belongs to first generation was the first general purpose programmable electronic computer built by J. Presper Eckert and John V. Mauchly.

It was 30 – 50 feet long, weight 30 tons, 18,000 vacuum tubes, 70,000 registers, 10,000 capacitors and required 1,50,000 watts of electricity. It requires Air Conditioner. They later developed the first commercially Successful computer, the Universal Automatic Computer(UNIVAC) in 1952.

The mathematician John Von Neumann designed a computer structure that structure is in use nowadays. Von Neumann structure consists of a central processing unit (CPU), Memory unit, Input and Output unit.

The CPU consists of arithmetic logical unit(ALU) and control unit(CU). The instructions are stored in the memory and follows the “Stored Program Concept”. Colossus is the secret code breaking computer developed by a British engineer Tommy Flowers in 1943 to decode German messages.

2. Second generation computers (1956 -1963):
Transistors, instead of Vacuum tubes, were used in 2nd generation computers hence size became smaller, less expensive, less electricity consumption and heat emission and more powerful and faster. A team contained John Bardeen, Walter Brattain and William Shockley developed this computer at Bell Laboratories.

In this generation onwards the concept of programming language was developed and used magnetic core (primary) memory and magnetic disk(secondary) memory.

These computers used high level languages(high level language means English like statements are used) like FORTRAN (Formula translation) and COBOL(Common Business Oriented Language). The popular computers were IBM 1401 and 1620.

3. Third generation computers (1964 – 1971):
Integrated Circuits(IC’s) were used. IC’s or silicon chips were developed by Jack Kilby, an engineer in Texas Instruments. It reduced the size again and increased the speed and efficiency. The high level language BASIC(Beginners All purpose Symbolic Instruction Code) was developed during this period The popular computers were IBM 360 and 370.

Due to its simplicity and cheapness more people were used . The number of transistors on IC’s doubles approximately every two years. This law is called Moore’s Law, it is named after Gordon E Moore. It is an observation and not a physical or natural law.

4. Fourth generation computers (1971 onwards):
Microprocessors are used hence computers are called microcomputers. Microprocessor is a single chip which contains Large Scale of IC’s(LSI) like transistors, capacitors, resistors etc due to this a CPU can place on a single chip. Later LSI were replaced by Very Large Scale Integrated Circuits(VLSI). The popular computers are IBM PC and Apple II.

5. Fifth generation computers (future):
Fifth generation computers are based on Artificial Intelligence(AI). AI is the ability to act as human intelligence like speech recognition, face recognition, robotic vision and movement etc. The most common Al programming language are LISP and Prolog.

Question 2.
Prepare a seminar report on evolution of positional number system.
Answer:
In positional number system, each and every number has a weight. Earlier sticks are used to count items such as animals or objects. Around 3000 BC the Egyptians use number systems with radix 10(base the number of symbols or digits used in the number system) and they write from right to left.

Later Sumerian/Babylonian use number system with largest base 60 and were written from left to right. They use space for zero instead of a symbol,0. In 2500 BC, the Chinese use simple and efficient number system with base 10 very close to number system used in nowadays.

In 500 BC, the Greek number system known as Ionian, it is a decimal number system and used no symbols for zero. The Roman numerals consists of 7 letters such as l, V, X, L, C, D, M.

The Mayans used number system with base 20 because of the sum of the number of fingers and toes is 10 + 10 = 20. It is called vigesimal positional number system. The numerals are made up of three symbols zero (shell shape, with the plastron uppermost), one (a dot) and five (a bar or a horizontal line).

To represent 1 they used one dot, two dots for 2, and so on. The Hindu – Arabic number system had a symbol (0) for zero originated in India 1500 years ago.

Question 3.
Discuss the various computing machines emerged till 1900’s.
Answer:
1. Abacus:
In 3000 BC Mesopotamians introduced this and it means calculating board or frame. It is considered as the first computer for basic arithmetical calculations and consists of beads on movable rods divided into two parts. The Chinese improved the Abacus with seven beads on each wire. Different Abacus are given below.

2. Napier’s bones:
A Mathematician John Napier introduced this in AP 1617.

3. Pascaline:
A French mathematician Blaise Pascal developed this machine that can perform arithmetical operations.

4. Leibniz’s calculator:
In 1673, a German mathematician and Philosopher Gottfried Wilhelm Von Leibniz introduced this calculating machine.

5. Jacquard’s loom:
In 1801, Joseph Marie Jacquard invented a mechanical loom that simplifies the process of manufacturing textiles with complex pattern. A stored program in punched cards was used to control the machine with the help of human labour. This punched card concept was adopted by Charles Babbage to control his Analytical engine and later by Hollerith.

6. Difference engine:
The intervention of human beings was eliminated by Charles Babbage in calculations by using Difference engine in 1822. It could perform arithmetic operations and print results automatically.

7. Analytical engine:
In 1833, Charles Babbage introduced this. Charles Babbage is considered as the “Father of computer” It is considered as .the predecessor of today’s computer. This engine was controlled by programs stored in punched cards. These programs were written by Babbage’s assistant, Augusta Ada King, who was considered as the first programmer in the World.

8. Hollerith’s machine:
In 1887, Herman Hollerith an American made first electromechanical punched cards with instructions for input and output. The card contained holes in a particular pattern with special meaning.

The Us Census Bureau had large amount of data to tabulate, that will take nearly 10 years. By this machine this work was completed in one year. In 1896, Hollerith started a company Tabulating Machine Corporation. Now it is called International Business Machines(IBM).

9. Mark -1:
In 1944 Howard Aiken manufactured automatic electromechanical computer in collaboration with engineers at IBM that handled 23 decimal place numbers and can perform addition, subtraction, multiplication and subtraction.

Students can Download Chapter 9 Sequences and Series Questions and Answers, Plus One Maths Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus One Maths Chapter Wise Questions and Answers Chapter 9 Sequences and Series

Plus One Maths Sequences and Series Three Mark Questions and Answers

Question 1.
The 10^th term of an AP is 73 and the 20^th term is 43. Find the 44^th term.
Answer:
a + 9d = 73 ______(1)
a + 19d = 43 ______(2)
(1) – (2) ⇒ -10d = 30 ⇒ d = -3
(1) ⇒ a + 9(-3) = 73
⇒ a – 27 = 73 ⇒ a = 100
a₄₄ =100 + (44 – 1)(-3) = 100 + (43)(-3) = -29.

Question 2.
The 7^th term of an AP is 34 and the 15^th term is 74. Find the 40^th term.
Answer:
a + 6d = 34 ______(1)
a + 14d = 74 ______(2)
(1) – (2) ⇒ -8d = -40 ⇒ d = 5
(1) ⇒ a + 6(5) = 34 ⇒ a + 30 = 34 ⇒ a = 4
a₄₀ = 4 + (40 – 1)(5) = 4 + (39)(5) = 199.

Question 3.
Find the sum to 32 terms of an AP whose third term is 1 and the 6^th term is -11.
Answer:
a + 2d = 1 ______(1)
a + 5d = -11 ____(2)
(1) – (2) ⇒ -3d = 12 ⇒ d = -4
(1) ⇒ a + 2(-4) = 1 ⇒ a – 8 = 1 ⇒ a = 9
S₃₂ = \(\frac{32}{2}\)(2 × 9 + (32 – 1)(-4))
= 16(18 + (31)(-4)) = 16(18 – 124)
= 16(-106) = -1696.

Question 4.
The sum to n terms of a series is 7n² – 5n. Show that it is an AP and find the 15^th term.
Answer:
Given; S_n = 7n² – 5n
t_n = S_n – S_n-1
= 7n² – 5n – {7(n -1)² – 5(n – 1)}
= 7n² – 5n – {7n² – 14n + 7 – 5n + 5}
= 7n² – 5n – 7n² + 14n – 7 + 5n – 5}
= 14n – 12
Since t_n is linear the given series is an AP.
t₁₅ = 14(15) – 12 = 198.

Question 5.
Find three numbers in AP whose sum is -3 and whose product is 8.
Answer:
Let the three consecutive terms be a – d, a, a + d
a – d + a + a + d = -3 ⇒ 3a = -3 ⇒ a = -1
Given; (-1 – d)(-1)(-1 + d) = 8
⇒ (-1 – d)(-1)(-1 + d) = 8
⇒ (1 – d²)(-1) = 8 ⇒ 1 – d² = -8
⇒ d² – 9 ⇒ d = -3, 3
The AP is 2, -1, -4 or -4, -1, 2.

Question 6.
Find three numbers in AP whose sum is 21 and product is 231.
Answer:
Let the three consecutive terms be a – d, a, a + d
a – d + a + a + d = 21 ⇒ 3a = 21 ⇒ a = 7
Given; (7 – d)(7)(7 + d) = 231
⇒ (7 – d)(7 + d) = 33
⇒ 49 – d² = 33 ⇒ d² = 16 ⇒ d = -4, 4
The AP is 11, 7, 3 or 3, 7, 11.

Question 7.
Find the sum of all natural numbers between 100 and 1000 which are multiple of 5.
Answer:
105 will be the starting number and will end in 995.
⇒ 105 + (n – 1)5 = 995
⇒ (n – 1)5 = 890 ⇒ n – 1 = 178 ⇒ n = 179
S₁₇₉ = \(\frac{179}{2}\)(t₁ + t_n) = \(\frac{179}{2}\)( 105 + 995)
\(\frac{179}{2}\)(1100) = 98450.

Question 8.
If the AM and GM between two numbers are 34 and 16 respectively. Find the numbers.
Answer:
Let the numbers be a and b.

(2) ⇒ a(68 – a) = 256 ⇒ 68a – a² = 256
⇒ a² – 68a + 256 = 0
⇒ a² – 64a – 4a + 256 = 0
⇒ (a – 64)(a – 4) = 0 ⇒ a = 64, 4
When a = 64, b = 4 and when a = 4, b = 64.

Question 9.
If the p^th, q^th and r^th terms of a GP are a, b, c respectively, show that a^q-r b^r-p c^p-q = 1.
Answer:
t_p = AR^p-1 = a; t_q = AR^q-1 = b; t_r = AR^r-1 = c

Plus One Maths Sequences and Series Four Mark Questions and Answers

Question 1.
The sum of the first p,g,r terms of an AP are a,b,c respectively, prove that

Answer:
Given;

= 2A{q – r + r – p + p – q} + {(q – r)(p – 1) + (r – p)(q – 1) + (p – q)(r – 1)}D

= 2A{0} + {qp – rp – q + r + rq – pq – r + p + pr – qr – p – q}D
= 0 + {0}D = 0
⇒ \(\frac{a}{p}\)(q – r) + \(\frac{b}{q}\)(r – p) + \(\frac{c}{r}\)(p – q) = 0.

Question 2.
The ratio between the sums to n terms of two AP is 7n + 1: 4n + 27. Find the ratio of their 11^th terms.
Answer:

For 11^th term \(\frac{n-1}{2}\) = 10 ⇒ n = 21
Put n = 21 in (1), we have;

Question 3.
If the sum of p terms of an AP is the same as the sum of its q terms, show that the sum of its (p+q) terms is zero.
Answer:
Given; S_p = S_g
⇒ \(\frac{P}{2}\)[2a + (p – 1 )d] = \(\frac{q}{2}\)[2a + (q – 1 )d]
⇒ 2ap + (p – 1)pd = 2aq + (q – 1 )qd
⇒ 2a(p – q) + (p² – p – q² +q)d = 0
⇒ 2a(p – q) + (p² – q² – (p – q))d = 0
⇒ (p – q){2a + (p + q – 1)d} – 0
⇒ {2a + (p + q – 1 )d} = 0
⇒ \(\frac{p+q}{2}\){2a + (p + q – 1 )d} = 0
⇒ S_p+q = 0.

Question 4.
The sum of the first two terms of a GP is -4 and the fifth term is 4 times the third term.

1. Find the first term and the common ratio. (2)
2. Find the GP. (2)

Answer:
1. Given; S₂ = -4
a + ar = -4 ⇒ a(1 + r) = -4 _____(1)
Also given; t₅ = 4t₃ ⇒ ar⁴ = Aar²
⇒ r² = 4 ⇒ r = ±2
When r = 2(1) ⇒ a(1 + 2) = -4 ⇒ a = \(-\frac{4}{3}\)
When r = -2 (1) ⇒ a(1 – 2) = -4 ⇒ a = 4

2. When r= 2; GP is \(-\frac{4}{3},-\frac{8}{3},-\frac{16}{3}, \dots\)
When r = – 2; GP is 4, -8, 16,…

Question 5.
The sum of three numbers in GP is 38 and their product is 1728. Find the GP.
Answer:
Let the numbers be \(\frac{a}{r}\), a, ar, the given;

⇒ 6(1 + r + r²) = 19r ⇒ 6 + 6r + 6r² = 19r
⇒ 6r² – 13r + 6 = 0
⇒ 6r² – 9r – 4r + 6 = 0
⇒ 3r(2r – 3) – 2(2r – 3) = 0
⇒ (3r – 2)(2r – 3) = 0
⇒ r = \(\frac{2}{3}, \frac{3}{2}\)
Therefore GP is 8, 12, 18 or 18, 12, 8.

Question 6.
Find the three numbers in GP whose sum is 13 and the sum of whose squares is 91.
Answer:
Let the numbers be \(\frac{a}{r}\), a, ar, the given;

⇒ 3 + 3r + 3r² = 13r ⇒ 3r² – 10r + 3 = 0
⇒ 3r² – 9r – r + 3 = 0
⇒ 3r(r – 3) – (r – 3) = 0
⇒ (3 r – 1)(r – 3) = 0 ⇒ r = 3, \(\frac{1}{3}\)
Therefore the numbers are 1, 3, 9 and 9, 3, 1.

Question 7.
Find the sum to n terms of the following series. (4 score each)

1. 1 × 4 + 3 × 7 + 5 × 10 +……….
2. 1 × 2² + 2 × 3² + 3 × 4² +………..
3. \(\frac{1}{1 \times 2}+\frac{1}{2 \times 3}+\frac{1}{3 \times 4}+\ldots \ldots\)
4. 1² + 3² + 5²+……….

Answer:
1. The given series is the product of two AP
1 , 3, 5, with t_n = 1 + (n – 1)2 = 2n – 1
4, 7, 10, with t_n = 4 + (n – 1)3 = 3n + 1
Then the n^th term of the given series is
t_n = (2n – 1)(3n + 1) = 6n² – n – 1

2. The given series has two AP
1, 2, 3,……. with t_n = 1 + (n – 1)1 = n
2, 3, 4,…… with t_n = 2 + (n – 1)1 = n + 1
Then the n^th term of the given series is
t_n = n(n + 1)² = n(n² + 2n + 1) = n³ + 2n² + n

3.

4. The given series has an AP
1, 3, 5……… with t_n = 1 + (n – 1)2 = 2n – 1
Then the n^th term of the given series is
t_n = (2n – 1)² = 4n² – 4n + 1

Question 8.
(i) n^th term of some sequence are given below. Which term can be the n th term ofanAP? (1)
(a) a_n = n(n + 1)
(b) a_n = 2 + 5n
(c) a_n = 2ⁿ + 2
(d) a_n = n² + n + 1
(ii) If the sum of 12^th and 22^nd terms of an AP is 100. Find the sum of first 33 terms. (3)
Answer:
(i) (b) a_n = 2 + 5n.

(ii) t₁₂ + t₂₂ = 100 ⇒ a + 11d + a + 21d = 100
⇒ 2a + 32d = 100

Plus One Maths Sequences and Series Six Mark Questions and Answers

Question 1.
1. The product of first 3 terms of a GP is 1000. If 6 terms to the second term and 7 is added to the third term, the terms become an AP.
(a) Find the second term of GP. (1)
(b) Find the terms of the GP. (2)
2. Find the sum of n terms of the series 7 + 77 + 777 +…………… (3)
Answer:
1. (a) \(\frac{a}{r}\) × a × ar = 1000 ⇒ a = 10
(b) \(\frac{a}{r}\), a + 6, ar + 7 from an AP
(a + 6) – \(\frac{a}{r}\) = (ar + 7) – (a + 6)
16 – \(\frac{10}{r}\) = 10r + 7 – 16
⇒ 16r – 10 = 10r² – 9r
⇒ 10r² – 25r + 10 = 0 ⇒ r = 2; \(\frac{1}{2}\)
Hence, 20, 10, 5 and 5, 10, 20;

2. S_n = 7 + 77 + 777 +……………
= 7(1 + 11 + 111 +…………)
= \(\frac{7}{9}\)(9 + 99 + 999 +………..)
= \(\frac{7}{9}\)(10 – 1 + 100 – 1 + 1000 – 1 +………..)
= \(\frac{7}{9}\)(10 + 100 + 1000+……….-1 – 1 – 1-………)

Plus One Maths Sequences and Series Practice Problems Questions and Answers

Question 1.
Find the n^th term of the following sequence (2 score each)

1. 5, 2, -1, -4, -7,…
2. 12, 7, 2, -3, -8,…….

Answer:
1. a = 5; d = 2 – 5 = -3
t_n = a + (n – 1)d = 5 + (n – 1)(-3)
= 5 – 3n + 3 = -3n + 8

2. a = 12; d = 7 – 12 = -5
t_n = a + (n – 1)d = 12 + (n – 1)(-5)
= 12 – 5n + 5 = -5n + 17.

Question 2.
A sequence is given {a_n} by a_n = n² – 1, n ∈ N Show that it is not an AP.
Answer:
Common difference = a_n+1 – a_n
= (n + 1)² – 1 -(n² – 1)
= n² + 2n + 1 – 1 – n² + 1
= 2n + 1.
Common difference is not independent of n so not an AP.

Question 3.
Find the sum to

1. 15 terms of the AP 3, 7, 11,………
2. 20 terms of the AP 10, 7, 4,……..
3. 81 terms of the AP -1, \(\frac{1}{4}, \frac{3}{2}, \ldots \ldots .\) (2 score each)

Answer:
a = 3; d = 7 – 3 = 4

2. a = 10; d = 7 – 10 = -3

= 10(20 + 19(-3)) =10(-37) = -370

3. a = -1; d = \(\frac{1}{4}\) + 1 = \(\frac{5}{4}\)

Question 4.
Insert 6 arithmetic means between 3 and 24.
Answer:
Let t₁ = 3, t₂, t₃, t₄, t₅, t₆, t₇, t₈ = 24 be the sequence.
Then;
t₈ = 24 ⇒ a + 7d = 24 ⇒ 3 + 7d = 24
⇒ 7d = 21 ⇒ d = 3
Hence the arithmetic means between 3 and 24 are 6, 9, 12, 15, 18, 21.

Question 5.
If the n^th term of a GP -2, 4, -8, 16 is 1024. Find n.
Answer:
Given; r = \(\frac{4}{-2}\) = -2; t_n = 1024 ⇒ 1024 = ar^n-1
⇒ 1024 = -2(-2)^n-1 ⇒ 1024 = (-2)ⁿ
⇒ (-2)¹⁰ = (-2)ⁿ ⇒ n = 10.

Question 6.
If the n^th term of a GP 2, 2\(\sqrt{2}\), 4,………is 64. Find n.
Answer:
Given; r = \(\frac{2 \sqrt{2}}{2}=\sqrt{2}\);
t_n = 64
⇒ 64 = ar^n-1
⇒ 64 = 2(\(\sqrt{2}\))^n-1

⇒ n = 11.

Question 7.
Find the sum of first 20 terms of the GP \(\sqrt{3}, 2 \sqrt{3}, 4 \sqrt{3}, 8 \sqrt{3}, \ldots \ldots\).
Answer:
Given;

Question 8.
In a GP{a_n}, if a₁ = 3, a_n = 96 and S_n = 189. Find common ratio and n.
Answer:
Given; a₁ = 3, a_n = 96 ⇒ ar^n-1 = 96
⇒ 3 × r^n-1 = 96 ⇒ r^n-1 = 32 = 2⁵
⇒ r^n-1 = 2⁵
Then, r = 2; n = 6.

Question 9.
Find the sum to n terms of the following; (3 score each)

1. 9 + 99 + 999 +………..
2. 4 + 44 + 444 +………..

Answer:
S_n = 9 + 99 + 999 +………..
= 10 – 1 + 100 – 1 + 1000 – 1 +………..
= 10 + 100 + 1000 +…….-1-1-1-…….
= 10 + 10² + 10³ +………-n

2. S_n = 4 + 44 + 444 +………..
= 4(1 + 11 + 111 +……..)

Question 10.
The third term of a GP is 4. Find the product of the first five terms.
Answer:
Given; t₃ = 4 ⇒ ar² – 4
The product of the first five terms
= a × ar × ar² × ar³ × ar⁴
= a⁵r¹⁰ = (ar²)⁵ = 4⁵ = 1024.

Question 11.
Insert 4 geometric means between 4 and 972.
Answer:
Let t₁ = 4, t₂, t₃, t₄, t₅, t₆ = 972 be the sequence. Then;
t₆ = 972 ⇒ ar⁵ = 972 ⇒ 4r⁵ = 972
⇒ r⁵ = 243 = 3⁵ ⇒ r = 3
Hence the arithmetic means between 4 and 972 are 12, 36, 108, 324.

Question 12.
Find the sum to infinity in each of the following Geometric Progression. (2 score each)

Answer:

Students can Download Chapter 11 Chemical Coordination and Integration Questions and Answers, Plus One zoology Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus One Zoology Chapter Wise Questions and Answers Chapter 11 Chemical Coordination and Integration

Plus One Chemical Coordination and Integration One Mark Questions and Answers

Question 1.
Listed below are the hormones of anterior pituitary origin. Tick the wrong entry.
(a) Growth hormone
(b) Follicle stimulating hormone
(c) Oxytocin
(d) Adrenocorticotrophic hormone
Answer:
(c) Oxytocin

Question 2.
Mary is about to face an interview. But during the first five minutes before the interview she experiences sweating, increased rate of heart beat, respiration etc. Which hormone is responsible for her restlessness?
(a) Estrogen and progesterone
(b) Oxytocin and vasopressin
(c) Adrenaline and noradrenaline
(d) Insulin and glucagon
Answer:
(c) Adrenaline and noradrenaline

Question 3.
The steroid responsible for balance of water and electrolytes in our body is
(a) Insulin
(b) Melatonin
(c) Testosterone
(d) Aldosterone
Answer:
(d) Aldosterone

Question 4.
Name the birth hormone.
Answer:
Oxytocin

Question 5.
A slow runner runs exceptionally fast when a dog chases him. Name the hormone involved in this situation.
Answer:
Adrenaline

Question 6.
Pars intermedia produce hormone. (GH, PRL.TSH, MSH)
Answer:
MSH

Question 7.
The excessive secretion of thyroxine hormone is followed by the enlargement of the thyroid glands. Name the disease occurs due to this,
Answer:
Exophthalmic goiter or Grave’s disease.

Question 8.
Thymosin is responsible for
(a) Raising the blood sugar level
(b) Raising the blood calcium level
(c) Increased production of T lymphocytes
(d) Decrease in blood RBC
Answer:
(c) Increased production of T lymphocytes

Question 9.
In the mechanism of action of a protein hormone, one of the second messengers is
(a) Cyclic AMP
(b) Insulin
(c) 73
(d) Gastrin
Answer:
(a) Cyclic AMP

Question 10.
Note the relationship between first two words and suggest a suitable word for fourth place.

1. Alpha cell : Glucagon – Beta cell : __________
2. Glucocorticoids : Cortisol – Mineralocorticoids: _________

Answer:

1. Insulin
2. Aldosterone

Question 11.
Expand the following.
ACTH
Answer:
ACTH – Adreno Cortico Trophic Hormone.

Question 12.
The excessive secretion of thyroxine hormone is followed by the enlargement of the thyroid glands. Name the disease occurs due to this.
Answer:
Exophthalmic goiter or Grave’s disease.

Plus One Chemical Coordination and Integration Two Mark Questions and Answers

Question 1.
Match the following.

Answer:

1. Hyperglycemic hormone – Glucagon
2. Pregnancy hormone – Progesterone
3. Inhibiting hormone – Somatostatin

Question 2.
Functions of certain hormones are given below. Identify the hormones.

1. Regulation of BMR
2. Differentiation of T cells
3. Stimulate gluconeogenesis, lipolysis and proteolysis.
4. Support pregnancy and act on mammary gland and stimulate milk secretion.

Answer:

1. Thyroxine
2. Thymosin
3. Glucocorticoids
4. Progesterone

Question 3.
Give example of

1. Hyper calcaemic hormone
2. Hyperglycemic hormone

Answer:

1. PTH (Parathyroid Hormone)
2. Glucagon

Question 4.
Name the hormone that regulate each of the following.

1. Storage of glucose as glycogen.
2. Sodium Potassium metabolism
3. Basal Metabolic Rate
4. Urinary elimination of water

Answer:

1. Insulin
2. Aldosterone
3. Thyroxine
4. ADH

Question 5.
The destruction of adrenal cortex leads to the low production of both glucocorticoids and mineralocorticoids.

1. Name the disease occurs due to this.
2. Give the symptoms of this disease.

Answer:

1. Addison’s disease.
2. loose weight, their blood glucose and sodium levels drop and potassium levels rise.

Question 6.
It is necessary to include iodised salt in our diet. Do you agree with this statement? Justify your answer.
Answer:
Yes. Deficiency of iodine in food causes simple goitre.

Question 7.
Diagrammatic representation of the mechanism of action of a steroid hormone is shown here.

1. Label A & B
2. Name any two protein hormones.

Answer:

1. Label A & B
   • A – MRNA
   • B – Proteins
2. FSH, LH

Question 8.
Match the following.

Answer:

Question 9.
Anitha saw a poisonous snake on her way to school. She was frightened and her heart rate and breathing rate increased.

1. Name the hormones which are dominant at that time in her blood.
2. Which endocrine gland produces the hormone?
3. Which is the name given to these hormones?
4. To which organ this endocrine gland is attached?

Answer:

1. Adrenaline and noradrenaline
2. Adrenal gland
3. Emergency hormones
4. Kidney

Question 10.
Read column A and using the terms given in bracket fill column B.
(Progesterone, Testosterone, Glucagon, Glucocorticoids, Prolactin, Vasopressin, Thymosin, Adrenaline, Follicle Stimulating hormone)

Answer:

Question 11.
Match the following.

Answer:

Question 12.
A boy witnessed an accident on his way to school. Following changes occurred in him. (Increased heart beat, profuse sweating, pupils dilated, shivering, pale face, increased respiration)

1. Name the hormone responsible for these changes?
2. Name the gland which secretes this hormone?

Answer:

1. Adrenaline
2. Adrenal gland

Question 13.
After delivery milk ejection starts in human females. It is due to the hormonal interaction. Name the hormones involved in this process.
Answer:
Estrogen, Progesterone, Prolactin and Oxytocin

Question 14.
Diagram shows the location of the various endocrine glands in human body. Identify the labelled parts.

Answer:

1. A – Hypothalamus
2. B – Thymus
3. C – Thyroid gland
4. D – Thymus
5. E – Pancreas
6. F – Adrenal gland
7. G – Ovary
8. H – Testis

Question 15.
Name a hormone that has the following action and give the source of the hormone.
Regulate blood sugar level – causes it to fall
Answer:
Insulin produced from Islets of Langerhans of pancreas.

Question 16.
Comment on the following flow chart.

Answer:
The figure explain the feed back mechanism between hypothalamus and pituitary by hypothalamo-pituitary axis. It also specifies the existence of feed back control mechanism between the hypothalamo-pituitary axis and other endocrine gland.

Question 17.
Note the relationship and suggest a suitable word in the gap.

1. Exocrine: ducted; Endocrine: ______
2. Adenohypophysis: Growth _______ hormone; Neurohypophysis: _________
3. Glucocorticoid: Cortisol; Mineralocorticoid: __________
4. Alpha cells: Glucagon; Beta cells: _________
5. Thymus: Infentile gland; Thymosin: __________
6. Diabetes mellitus: lnsulin; Diabetes insipidus: _________

Answer:

1. ductless gland
2. Vasopressin
3. Aldosterone
4. Insulin
5. Infentile hormone
6. Vasopressin

Question 18.
Complete the concept map.

Answer:

1. A – 80-120 mg/ml
2. B – Insulin
3. C – Glycogenesis
4. D – Glucagon

Question 19.
The male’s body is stronger and rigid than female’s body. Give reason.
Answer:
Androgens control the muscular development in males. This hormones are absent in females.

Question 20.
The sight and sound of a baby can induce secretion of a hormone in a nursing mother.

1. Name the hormone.
2. Give the functions of this hormone.

Answer:

1. Prolactin
2. Prolactin promote growth of mammary gland, secretion of milk and keeps corpus luteum functional.

Question 21.
Pancreas is found to be not functioning in a patient. How this condition will affect physiological functioning in him?
Answer:
Pancreas is a mixed gland, produce hormones and enzymes. Hormonal imbalance problem is due to insulin and glucagon and problems in digestion is due to absence of pancreatic juice.

Question 22.

The given bar diagram shows the relative amount of glucose and insulin in a normal man. Redraw the graph to show the conditions in a diabetic patient.
Answer:

Question 23.
Construct a table and arrange the following items in three columns with appropriate headings: Tetany, adenohypophysis, Insulin, Myxoedema, Parathyroid, Dwarfism, Growth hormone, Thyroid, Diabetes mellitus, Pancreas, Thyroxin, PTH.
Answer:

Question 24.
A person with a swelling in the thyroid gland consults a doctor.

1. What type of disease does this person have?
2. As a student of biology, what remedy would you suggest for these?

Answer:

1. Goitre
2. Iodine is essential for the functioning of the thyroid gland. It is normally obtained from drinking water and iodised table salt. Other sources are onion, seafood etc.

Deficiency of Iodine causes a disorder known as goitre. In this disorder thyroid glands swell up. So taking adequate amount of Iodised salt is a remedy for goitre.

Question 25.
The destruction of adrenal cortex leads to the low production of both glucocorticoids and mineralocorticoids.

1. Name the disease occurs due to this.
2. Give the symptoms of this disease.

Answer:

1. Addison’s disease.
2. Weight loss, blood glucose and sodium levels drop and potassium levels rise.

Question 26.
Match column B & C with column A.

Answer:

Question 27.

• Identify the gland in the picture.
• How many layers are present in the adrenal gland? Name them and write the hormones from these layers.

Answer:

1. Adrenal gland
2. Two layers are present in the adrenal gland. They are the outer cortex and inner medulla. Adrenal cortex secretes glucocorticoids, mineralocorticoids and sex corticoids. Adrenal medulla, secretes adrenalin and Noradrenalin.

Question 28.
1. A flowchart showing the process of production of testosterone, is given below.

2. Redraw the chart correctly if there are any mistakes.
Answer:

Question 29.
Find the odd one out in each group and give reason.

1. TSH, ACTH, FSH, LH, ADH
2. Cretinism, Myxoedema, Simple goitre, Gigantism
3. Thyrotropin releasing hormone, Corticotropin releasing hormone, Gonadotropin releasing hormone, Somatostatin.
4. Adenohypophysis, Neurohypophysis, Hypothalamus, pars intermedia.

Answer:

1. ADH, ADH is a hormone from neurohypophysis all others are from adenohypophysis.
2. Gigantism – Gigantism is due to the imbalance of growth hormone, all others are due to the imbalance of thyroid hormone.
3. Somatostatin – Somatostatin is an inhibitory hormone, all others are releasing hormone.
4. Hypothalamus – remaining three are different parts of pituitary gland.

Question 30.
Progesterone is called as pregnancy hormone. Do you agree? Give reason.
Answer:
Yes. Progesterone helps in

1. Maintenance of pregnancy
2. Implantation
3. Formation of Placenta
4. Growth of mammary glands

Question 31.
Fill in the blanks:
Hormones Target gland

1. Hypothalamic hormones _______
2. Thyrotrophin(TSH) ____
3. Corticotrophin (ACTH)
4. Gonadotrophins(LH, FSH)

Answer:

1. Hypothalamic hormones Pituitary
2. Thyrotroph in (TSH) Thyroid gland
3. Corticotrophin (ACTH) Adrenal gland
4. Gonadotrophins(LH, FSH) Gonads

Plus One Chemical Coordination and Integration Three Mark Questions and Answers

Question 1.
Can you identify us?
Clue – We are two diseases, one is related to sugar in urine. Our first name is same and second name is different. Distinguish us.
Answer:

• Diabetes Mellitus and Diabetes insipidus.
• Diabetes mellitus is due to Insulin deficiency and elimination of sugarthrough urine.
• Diabetes Insipidus is due to ADH deficiency and elimination of excess water through urine.

Question 2.
When checked the blood sugar of a person, it is found to be 220 mg/100ml of blood; Is this a disorder?

1. If this is a disorder, name the disorder.
2. Which hormonal imbalance is responsible for this condition?
3. Can you suggest any remedial measures to get rid of?

Answer:

1. Yes. Diabetes mellitus
2. Insulin
3. Diet control, Exercise etc.

Question 3.
During Sunbath the body colour is changed.

1. Why the body colour is changed?
2. Do you think any hormone is responsible for this? If so, name the hormone.
3. Explain the action of hormone.

Answer:

1. Melanocyte stimulating hormone produced during the sunbath is the reason for the change.
2. Melanocyte stimulating hormone from pituitary.
3. Melanocyte stimulating hormone (MSH) stimulate cutaneous pigmentation by dispersion of melanin pigments.

Question 4.
A pregnant lady is admitted in a hospital for delivery. But the delivery is delayed than the expected time. Doctor prescribed to take an injection.

1. Which hormone is injected to the lady?
2. Which glands in the body normally secretes this hormone?
3. How this hormone helps in this process?

Answer:

1. Oxytocin
2. Oxytocin is secreted from pituitary.
3. Oxytocin helps the contraction of uterine wall and thereby helps in parturition

Question 5.
Expand the following.

1. AMP
2. ANF
3. ICZN

Answer:

1. CAMP – Cyclic Adenosine Mono Phosphate
2. ANF – Atrial Natriuretic Factor
3. ICZN – International Code of Zoological Nomenclature

Question 6.
The diagram shows the interaction between the hypothalamus, pituitary and thyroid glands. Arrow indicates the probable pathway of direct influence. Answer the following questions.

1. Name the hormones A and B.
2. State the effect of hormone A on the thyroid.
3. State the effect of hormone B on the hypothalamus.
4. Describe the control on pituitary by the hypothalamus in this situation.

Answer:

1. A-Thyroid stimulating hormone B-Thyroxine
2. Thyroid stimulating hormone stimulates the thyroid follicle to synthesis two hormones, thyroxine and triiodothyronine.
3. The high level of thyroxin inhibits the production of thyrotropin releasing hormone.
4. Thyrotropin releasing hormone of the hypothalamus stimulates the pituitary to release thyrotropin stimulating hormone (TSH) which in turn stimulate thyroid gland to produce thyroxine

Question 7.
Copy the table and fill in the blanks using appropriate words.

Answer:

Plus One Chemical Coordination and Integration NCERT Questions and Answers

Question 1.
Give example of:

1. Hypercalcemic harmone and hypoglycemic hormone
2. Hypercalcemic hormone
3. Gonadotropic hormone
4. Progestational hormone
5. Blood Pressure lowering hormone
6. Androgens and estrogens

Answer:

1. Hyperglycemic hormone. Glucagon, Hypoglycemic Hormone. Insulin
2. Hype – calcemic hormone. Parathyroid Hormone (PTH)
3. Gonadotrophic hormones. Luteinizing Hormone and Follicle Stimulating Hormone
4. Progestrone and estrogen
5. Blood pressure lowering hormone. Atrial Natriuretic Factor.
6. Androgen, Testosterone Estrogens. Estrone, Estradiole, Estriol

Question 2.
Which hormonal deficiency is responsible for the following?

1. Diabetes mellitus
2. Goitre
3. Cretinism

Answer:

1. Insulin
2. Thyroid
3. Thyroid

Question 3.
Briefly mention the mechanism of action of FSH
Answer:
In males, FSH and androgens regulate spermatogenesis. FSH stimulates growth and development of the ovarian follicles in females.

Question 4.
Match the following.

Answer:
(a) – (ii)
(b) – (iv)
(c) – (i)
(d) – (iii)

Plus One Chemical Coordination and Integration Multiple Choice Questions and Answers

Question 1.
Endemic goitre is a state of
(a) increased thyroid function
(b) normal thyroid function
(c) decreased thyroid function
(d) moderate thyroid function
Answer:
(c) decreased thyroid function

Question 2.
Name the hormone that stimulates the secretion of gastric juice.
(a) Rennin
(b) enterokinase
(c) Enterogastrone
(d) gastrin
Answer:
(d) gastrin

Question 3.
Islets of Langerhans are found in
(a) anterior pituitary
(b) kidney cortex
(c) spleen
(d) endocrine pancreas
Answer:
(d) endocrine pancreas

Question 4.
The hormone responsible response flight, flight and fight response is
(a) adrenalin
(b) thyroxin
(c) ADH
(d) oxytocin
Answer:
(a) adrenalin

Question 5.
Foetal ejection reflex in human female is induced by
(a) pressure exerted by amniotic fluid
(b) release of oxytocin from pituitary
(c) fully developed foetus and placenta
(d) differentiation of mammary glands
Answer:
(b) release of oxytocin from pituitary

Question 6.
A health disorder that results from the deficiency of thyroxin in adults and characterized by
(i) a low metabolic rate
(ii) increase in body weight
(iii) tendency to retain water in tissues is
(a) hypothyroidism
(b) simple goitre
(c) myxoedema
(d) cretinism
Answer:
(c) myxoedema

Question 7.
Gland responsible for calcium metabolism is
(a) thymus
(b) thyroid
(c) parathyroid
(d) adrenal
Answer:
(c) parathyroid

Question 8.
Secretion is under control of neurosecretory nerve axons in
(a) pineal gland
(b) adrenal cortex
(c) anterior pituitary
(d) posterior pituitary
Answer:
(d) posterior pituitary

Question 9.
The smallest endocrine gland is
(a) thyroid
(b) parathyroid
(c) pituitary
(d) adrenal
Answer:
(c) pituitary

Question 10.
Gigantism and acromegaly are due to
(a) hypothyroidism
(b) hyperthyroidism
(c) hypopituitarism
(d) hyperpituitarism
Answer:
(d) hyperpituitarism

Question 11.
Spermatogenesis is under the regulatory influence of
(a) ADH
(b) FSH
(c) LH
(d) STH
Answer:
(b) FSH

Question 12.
Which hormone is secreted in a woman if pregnancy has occurred?
(a) Oestrogen
(c) Luteinizing hormone
(d) Chorionic gonadotrophin
Answer:
(d) Chorionic gonadotrophin

Question 13.
Insulin and glucagon are transported to target organ by
(a) lymph
(b) blood
(c) pancreatic duct
(d) cystic duct
Answer:
(d) cystic duct

Question 14.
Neurons of people suffering from diabetes insipidus do not secrete
(a) enzyme
(b) steroid
(c) fatty acid
(d) ADH
Answer:
(d) ADH

Question 15.
The hormone that increases the blood calcium level and decreases its excretion by kidney is
(a) parathormone
(b) calcitonin
(c) thyroxin
(d) insulin
Answer:
(a) parathormone

Question 16.
If the pituitary gland of an adult rat is surgically removed, which of the following endocrine glands will be less affected?
(a) Adrenal cortex
(b) Adrenal medulla
(c) Thyroid
(d) Gonads
Answer:
(b) Adrenal medulla

Question 17.
Oestrogen and testosterone are steroid hormones, and are most likely bind to
(a) membrane ions channels
(b) enzyme-linked membrane receptors
(c) G-protein linked membrane receptors
(d) cytoplasmic receptors
Answer:
(d) cytoplasmic receptors

Question 18.
Steroid hormones easily pass through the plasma membrane by simple diffusion because they
(a) are water soluble
(b) contain carbon and hydrogen
(c) enter through pores
(d) are lipid soluble
Answer:
(d) are lipid soluble

Question 19.
A hormone secreted by the endocrinal cells of duodenal mucosa which influences the release of pancreatic juice is
(a) relaxin
(b) cholecystokinin
(c) secretin
(d) progesterone
Answer:
(b) cholecystokinin

Question 20.
Which of the following hormones does not contain a polypeptide?
(a) Prostaglandin
(b) Oxytocin
(c) Insulin
(d) Antidiuretic hormone
Answer:
(b) Oxytocin