Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants

Students can Download Chapter 3 Morphology of Flowering Plants Questions and Answers, Plus One Botany Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations

Kerala Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants

Plus One Botany Morphology of Flowering Plants One Mark Questions and Answers

Question 1.
Which plant part is modified into a pitcher in pitcher plants?
(a) stem
(b) leaf
(c) flower
(d) root
Answer:
(b) leaf

Question 2.
Marginal placentation is generally found in the family
(a) Solanaceae
(b) Fabaceae
(c) Liliaceae
(d) Cucurbitaceae
Answer:
(b) Fabaceae

Question 3.
Nonendospermic seeds are found in
(a) pea
(b) groundnut
(c) beans
(d) all of these
Answer:
(d) all of these

Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants

Question 4.
Monocotyledonous seed possess a cotyledon which is represented by
(a) teg men
(b) endosperm
(c) scutellum
(d) aleurone
Answer:
(c) scutellum

Question 5.
Which floral family has (9) + 1 arrangement of anthers in the andoecium
(a) Malvaceae
(b) Fabaceae
(c) Solanaceae
(d) Liliaceae
Answer:
(b) Fabaceae

Question 6.
Based on the relationship, fill in the blanks.

  1. Prop root: Support
    Pneumatophore: ……….
  2. Transpiration: Stomata
    Guttation: ……….

Answer:

  1. breathing /respiration
  2. Hydathode

Question 7.
The arrangement of petals in the flower is known as
Answer:
Aestivation

Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants

Question 8.
When your teacher asked to write a few examples for root modifications, a student wrote Potato. Is it correct? Why ?
Answer:
No. Stem modification

Question 9.
Write the name of the family which has the given floral formula.
Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants img1
Answer:
Solanaceae

Question 10.
Observe the relationship between first two words and fill up the suitable word in the next place.

  1. Shoot – plumule: Root …………..
  2. Outer integument – testa: inner integnment ……….

Answer:

  1. Radicle
  2. tegmen

Question 11.
Observe the first pair in a and b and then complete the second pair.

  1. gourd – Tendril
    citrus – …………
  2. Brinjal – Hypogynous flower
    Rose – …………..

Answer:

  1. Thom
  2. Epigynous

Question 12.
Identify the family having the given floral formula.
Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants img2
Answer:
Papilionaceae

Question 13.
“Stilt roots are adventitious and give mechanical support’’. How does prop root help the plant?
Answer:
Support the horizontal branches.

Question 14.
“Some flowers are called perigynous”. What do you mean by it?
Answer:
Ovary half inferior or half superior.

Question 15.
From the following terms relating a flower, write its floral formula.
Bisexual; sepals 5 and united petal 5 and united; stamens 5 and epipetalous, carpels 2 and Syncarpous, superior..
Answer:
Solanaceae

Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants

Question 16.
Based on morphology pick up the odd one and state reason for your selection (Carrot, Beetroot, Potato, Sweetpotato, radish).
Answer:
Potato- because it is a stem modifications.

Question 17.
Phyllotaxy is the arrangement of leaves on the branch. Identify the order of plants showing Alternate, opposite and Whorled phyllotaxy in the following.
(a) China rose, Calotropis, Nerium
(b) Nerium, China rose, Caltropis
(c) Nerium, Caltropis, China rose
(d) China rose, Nerium, Caltropis
Answer:
(a) China rose, Calotropis, Nerium

Plus One Botany Morphology of Flowering Plants Two Mark Questions and Answers

Question 1.
Identify the types of aestivation in the following diagrams. Justify your answer.
Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants img3
Answer:

  • Valvate aestivation – Petals touching each other.
  • Imbricate aestivation – petals arranged as one completely in, one completely out & others in and out.

Question 2.
“Potato is a stem and sweet potato is a root”. Justify the statement on the basis of external features only.
Answer:
Potato has distinct nodes and internodes whereas sweet potato does not have nodes and internodes. Potato tuber has scale leaves while sweet potato does not have scale leaves.

Question 3.
Identify the given family. Write the floral formula, mention the economic importance.

  1. Bisexual, actinomorphic
  2. Perianth six
  3. Valvate aestivation
  4. Ovary superior, Prilocular with many ovules.

Answer:
Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants img4

Question 4.
Note the difference between the placenta and thalamus.
Answer:

  • Placenta – Region with which ovules are attached to ovary.
  • Thalamus – Region where floral parts are attached

Question 5.
Based on the relationship, fill in the blanks.

  1. Prop root: Support
    Pneumatophore: …………
  2. Transpiration: Stomata
    Guttation: …………….

Answer:

  1. Breathing
  2. Hydathode

Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants

Question 6.

  1. Identify the type of placentation given below.
  2. Differentiate between apocarpous and syncarpous condition

Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants img5
Answer:

  1. marginal, axile, parietal, freecentral,basal
  2. apocarpous – free carpels.
    Syncarpous – fused carpels

Question 7.
In early morning, on the margins of leaves water drops are seen. Why does it occur?
Answer:
Guttation – The lose of water in the form of water droplets through water stomata seen on the margin on the leaves.

Question 8.
You are provided with the rhizome of a ginger plant.

  1. Name the part of the plant modified to form this structure.
  2. Write any three differentiating characters.

Answer:

  1. Stem
  2. Presence of Node, internode, terminal bud, axillary buds & scale leaves.

Question 9.
The following diagrams show different types of placentation.
Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants img6

  1. Name the type of placentations.
  2. write one example for each placentation.

Answer:

  1. Marginal, Basal
  2. Pea & Sunflower

Question 10.
L.S of maize seed is given below.Observe the diagram and label the parts.
Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants img7
Answer:

  1. Endosperm
  2. Scutellum
  3. Coleoptile
  4. Plumule

Question 11.
The floral formula of a flower is
Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants img8

  1. Identify the family.
  2. Write the characters of androecium and gynoecium of this family.

Answer:

  1. Solanaceae
  2. Androecium – Five stamens epipetalous
    Gynoecium – bicarpellary, syncarpous, superior ovary.

Question 12.
Expand the floral formula
Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants img9
Answer:
zygomorphic bisexual pentamerous gamosepalous papilionaceous corolla diadelphous – Androecium. Gynoecium – superior.

Question 13.
Observe the following diagram and answer to the following Questions.
Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants img10

  1. Name the part of the plant modified in ‘A’ and ‘B’.
  2. Mention their functions.

Answer:

  1. A – Taproot B – Adventitious root
  2. A – Storage B – Respiration

Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants

Question 14.
The rhizome of ginger is found underground. But it is not root. Give reason.
Answer:
It has nodes, internodes, scale, leaves, axillary bud, terminal bud, adventitious root etc.

Question 15.
How is pinnately compound leaf different from palmately compound leaf?
Answer:
When a number of leaflets are present on either sides of a common axis, rachis it is pinnately compound leaf. Rachis represents the midrib of leaf. Eg. Neem When the leaflets are attached at a common point like fingers on palm it is palmately compound leaf. Eg. Bombax or silk cotton.

Question 16.
Identify the phyllotaxy of A and B
Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants img11
Answer:
(a) Alternate
(b) Oppositemedicinal.

Question 17.
Roots obtain oxygen from air in the soil for respiration. In the absence or deficiency of 02, root growth is restricted or completely stopped. How do the plants growing in marshlands or swamps obtain their 02 required for root respiration?
Answer:
In marshy area, the plants get 02 through special roots called pneumatophores or respiratory roots.Such roots are negatively geotropic.

Question 18.
During a feild trip to the coastal areas of Kochi, your team saw many trees growing in swampy areas, when thourdughly observed they found many roots growing upwards above the soil level.

  1. In your opinion what kind of roots were seen in that trees?
  2. How do these roots help the trees?

Answer:

  1. Pneumatophore
  2. Gaseous exchange

Question 19.
Rhizome of ginger is like the roots of other plants that grows underground. Despite this fact ginger is a stem and not a root. Justify.
Answer:
Because it possess nodes and internodes, buds, scale leaf, and adventitious roots. Hence these are stem characters.

Question 20.
Tendrils are found in the following plants. Identify whether they are stem tendrils or leaf tendrils,
a. Cucumber
b. Peas
c. Pumpkins
d. Watermelons
Answer:
a,c,d – stem tendril b – leaf tendril

Question 21.
You have heard about several insectivorous plants that feed on insects. Nepenthes or the pitcher plant is one such example, which usually grows in shallow water or in marshlands. What part of the plant is modified into a pitcher1? How does this modification help the plant for food even though it can photosynthesize like any other green plant?
Answer:
Lamina, Plant get additional nutrition (nitrogen) from the digested insect body.

Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants

Question 22.
Mangrove plants have negatively geotropic roots

  1. Name the root
  2. Identify its function

Answer:

  1. Pneumatophore
  2. Gaseous exchange

Question 23.
1. Write the floral formula of the flower having following description (Bisexual, Zygomorhic, Calyx 5 gamosepalous, Corolla 5 polysepalous, vexillary aestivation, Androecium 10 (stamens 9 united and1 free), Gynoecium 1 carpel, ovary superior)
2. Identify the family of the flower
Answer:

  1. K(5)C 1 + 2 + (2) A(9) + 1G1
  2. Fabaceae

Question 24.
The following diagrams show different types of placentation.

  1. Name the types of placentations?
  2. Write one example for each placentations?

Answer:

  1. Marginal and Basal placentation
  2. Marginal – pea, Basal – sunflower

Question 25.
Dicot and monocot leaves shows differences on their leaves mostly in the arrangement of veins, explain it.
Answer:
In Dicot, the veins are repeatedly branched to form network. This is called Reticulate venation. In Monocot, the veins run parallel to one another. This is called Parallel venation.

Question 26.
What is placentation ?Give two types with example.
Answer:
It is the mode of arrangement of ovules in an Ovary

  1. Axile placentation – Arrangement of ovules in the axis of ovary having septa.
  2. Free central placentation – Arrangement of ovules in the central part of ovary without having septa.

Question 27.
Common functions of roots are absorption, fixation and conduction. Besides these, roots perform other functions. Justify this statement with two example.
Answer:
1. In addition to absorption, fixation, and conduction, roots perform mechanical support, eg -prop root and stilt root.

2. Some are Breathing roots eg:- Pneumatophore.

Question 28.
Differentiate between
Hypogynous and Epigynous
Answer:

  1. In hypogynous flower the position of Gynoecium is superior to all other floral whorls.
  2. In epigynous flower the position of Gynoecium is inferior to all other floral whorls.

Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants

Question 29.
A list of some plant parts are given below. Note the morphological modification in each item.

  1. Carrot
  2. Tapioca
  3. Potato
  4. Ginger

Answer:

  1. Carrot – Tap root modification
  2. Tapioca – Adventitious root modification
  3. Potato – Underground stem modification
  4. Ginger – Underground stem modification

Question 30.
Some flowers are called perigynous”. What do you mean by it?
Answer:
In such flowers ovary is half inferior that means position of ovary comes to the same level of other floral whorls lies.
Eg:- plum, rose, and peach

Question 31.
How is pinnately compound leaf different from palmately compound leaf?
Answer:
1. In pinnately compound leaf lamina divided into number of leaflets. It is due to the incisions touch the midrib Eg:- Neem.

2. In palmately compound leaf, lamina is divided into number of leaflets, they are arranged like fingers on the palm Eg:- Silk cotton

Question 32.
When your teacher asked to write a few examples for root modifications, a student wrote Potato. Is it correct? Why ?
Answer:
No, Potato is an example of underground stem modification.

Question 33.
How can you differentiate between free central and axile placentation?
Answer:
In free central placentation ovules are arranged at central axis of ovary without septa but in axile placentation ovules are arranged at central axis of ovary with septa/ cross walls.

Question 34.

  1. Name the aestivations given below
  2. Give an example for each

Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants img12
Answer:
1. Twisted and imbricate
Hibiscus and cassia

Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants

Question 35.
Potato is a stem and sweet potato is a root”. Justify the statement on the basis of external features only.
Answer:
Potato is an underground stem. It possess adventitious bud, nodes and internodes Sweet potato is adventitious root modification. It possess root hairs and stores food.

Question 36.
The floral formula of a family is given below Give two examples for economically important plants
Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants img13
Answer:

  • Indigofera – dye obtained
  • Sesbania- Used as Fodder

Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants img14

Question 37.
The mature seeds of plants such as gram and peas possess no Endosperm. Why?
Answer:
Endosperm gets used up by the developing embryo during seed development.

Question 38.
Match the following.

Group AGroup B
A.  Aleurone layer

B.  Parthenocarpic fruit

C.  Ovule

D.  Endosperm

i.    without fertilization

ii.    Nutrition

iii.   Double fertilization

iv.  Seed

Answer:
A – iv
B – i
C – iii
D – ii

Question 39.
Mango and coconut are ‘drupe’ type of fruits. In mango fleshy mesocarp is edible.

  1. What is the edible part of coconut?
  2. What does milk of tender coconut represent?

Answer:

  1. Endosperm
  2. Liquid endosperm (free nuclear endosperm)

Question 40.
The mode of arrangements of sepals or petals in a floral bud is known as aestivation. Draw the various types of aestivation possible for a typical pentamerous flower.
Answer:
Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants img15

Question 41.
Give the technical term and examples of the flowers given here based on the position of the ovary.
Answer:
Hypogynous- hibiscus and perigynous- plum and rose.

Question 42.
Modified adventitious roots in Banyan tree and Maize plant are known in different names

  1. Which are they?
  2. Give its function

Answer:

  1. Banyan tree – Prop root, Maize plant-Stilt root
  2. Mechanical support

Question 43.
Thorns and spines are different modified structures in citrus and cactus.

  1. Which plant part is modified ?
  2. Give its function.

Answer:

  1. Thorns – stem modification, Spines – Leaf modification
  2. protective function

Question 44.
Some important family characters are given below flowers are zygomorphic, Hypogynous, monocarpellary ovary, anthers diadelphous, and papilionaceous corolla

  1. Identify the family
  2. Give 2 economically important plants

Answer:

  1. Fabaceae
  2. dye – Indigofera, fodder yielding – sesbania and Trifolium

Question 45.
Give the technichal term of the following

  1. Two leaves at each node
  2. flowers cannot be divided into two equal halves
  3. position of ovary is higher than other floral whorls
  4. carpels are fused

Answer:

  1. opposite phyllotaxy
  2. asymmetric
  3. Hypogynous flower
  4. syncarpous

Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants

Question 46.
Mention the statement given below are true or false

  1. In axile placentation ovules are arranged in axis of single-chambered ovary
  2. In Imbricate aestivation floral appendages are in irregular overlapping
  3. In Alstonia phyllotaxy is whorled
  4. Floral axis has definite growth in racemose type

Answer:

  1. False
  2. True
  3. True
  4. False

Plus One Botany Morphology of Flowering Plants Three Mark Questions and Answers

Question 1.
Justify the following statements on the basis of external features.

  1. Underground parts of plants are not always roots
  2. Flower is a modified shoot

Answer:
1. Underground stem get modified for different purposes like food storage, reproduction and perennation. They can be recognized from root in having nodes, internodes,scale leaves, terminal bud &axillary bud eg. Rhizome – ginger, stem tuber- potato.

2. A flower can be considered as a modified shoot because each whorl of a flower represents each node. The leaves at each node is modified to perform functions like protection, attraction and reproduction. The internodes are compressed to form a flower.

Question 2.

  1. What is meant by modification of root?
  2. What type of root is found in
    • banyan tree
    • turnip
    • mangrove tree root modification is the change in shape and structure of root for performing functions other than absorption and conduction.

Answer:

  1. It is modified for performing different functions.
    • Modification of root in banyan tree-prop roots- for mechanical support
    • Turnip-napiform modification – for food storage
    • Mangrove tree-pneumatophores – respiration

Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants

Question 3.
Some characters of a flower is given below. Bisexual, sepals 5 and united, Petals 5 and united, stamens 5 and epipetalous, carpels 2, syncarpous and superior ovary.

  1. Write its floral formula.
  2. Identify the family.
  3. List any two economically important plants belonging to this family.

Answer:
1.
Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants img16
2. Solanaceae
3. Potato – Solanum tuberosum Tomato – Lycopersicum esculentum

Question 4.
A particular flower of a family is characterised by this type of aestivation.
Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants img17
a) Identify the family.
b) Write the floral formula.
c) Mention two economic importance of the family.
Answer:
Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants img18

Question 5.
Observe the relationship between first two words and fill up the suitable word in the fourth place.

  1. Shoot – plumule: Root ………..
  2. Nepenthes – pitcher: Utricularia …………
  3. Outer integument – testa: inner integument …………..
  4. Ovule – seed: Ovary – …………..

Answer:

  1. Radicle
  2. Bladder
  3. Tegmen
  4. Fruit

Question 6.
Label the regions of the root tip in the given diagram.
Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants img19
Answer:

  1. Root cap
  2. Meristematic
  3. Region of elongation
  4. Root hair region

Question 7.
The arrangements of ovules within the ovary is known as placentation.

  1. What does the term placenta refer to?
  2. Name and draw various types of placentations in the flower as seen in T.S. or V.S.

Answer:
1. Placenta It is the cushion-like structure in which ovules are arranged.
2.
Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants img20

Question 8.
Define the following terms.

  1. Aestivation:
  2. Placentation:
  3. Actinomorphic:
  4. Zygomorphic:
  5. superior ovary:
  6. Perigynous flower:
  7. Epigynous

Answer:

  1. Aestivation: Arrangement of sepals and petals in an unopened flower bud.
  2. Placentation: The mode of arrangement of ovules within the ovary
  3. Actinomorphic: When a flower can be divided into two equal radial halves at any radial plane. Eg: Chinarose.
  4. Zygomorphic: When a flower can be cut into two equal halves only in one vertical plane. Eg: pea.
  5. Superior ovary: When gynoecium occupies superior or highest position while other parts are situated below it. Eg: Mustard.
  6. Perigynous flower: If the gynoecium is at the centre and all other, parts arise on the rim of the thalamus. Eg: Rose

Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants

Question 9.
Differentiate between

  1. Racemose and cymose inflorescence.
  2. Fibrous and adventitious root
  3. Apocarpous and syncarpous ovary.

Answer:
1. Racemose:The axis or peduncle shows indefinite growth. Flowers are arranged in acropetal succession.
Cymose: the axis or peduncle shows definite growth or ends in a flower. Flowers are arranged in basipetal succession.

2. Fibrous: The primary root stops its growth and lateral roots arise from the base of the stem.
Adventitious: The roots arise from the part of the plant other than the radicle.

3. Apocarpous: When the carpels of ovary are free.
Syncarpous: When the carpels of ovary are fused.

Question 10.
Floral characters of a plant are given below: Pentamerous flowers, Polypetalous, Stamens 5, Polyandrous, Bicarpellary Syncarpous, Swollen placenta, Oblique ovary.
a) Name the Family of this plant belongs.
b) Write the floral formula of this family.
c) Give two examples with its importance.
Answer:
Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants img21

Plus One Botany Morphology of Flowering Plants NCERT Mark Questions and Answers

Question 1.
How is a pinnately compound leaf different from a plamately compound leaf?
Answer:
1. Pinnately Compound Leaf.
In pinnately compound leaf a number of leaflets are present on a common axis. Example, neem leaves.

2. Palmately Compound Leaf.
In palmately compound leaf number of leaflets are attached at the common point. Example, cotton leaves.
Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants img22

Question 2.
Explain with suitable examples the different types of phyllotaxy.
Answer:
1. Phyllotaxy. Phyllotaxy is the pattern of arrangement of leaves on the stem or branch. This is usually of three types – alternate, opposite and whorled.

2. In alternate type of phyllotaxy, a single leaf arises at each node in alternate manner, as in china rose, mustard and sunflower plants.

3. In the Opposite type, a pair of leaves arise at each node and lie opposite to each other as in Calotropis and guava plants.

4. If more than two leaves arise at a node and form a whorl, it is called whorled, as in Alstonia.
Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants img23

Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants

Question 3.
What is meant by modification of root? What type of modification of root is found to the :

  1. Banyan tree
  2. Turnip
  3. Mangrove trees

Answer:
The Primary function of the root is absorption of water and minerals and giving mechanical support to the plant. Sometimes roots get modified to carry out other functions like storage of food or additional mechanical support.

1. Banyan Tree. In banyan trees long roots develop from branches and they hanging deep down to reach the ground. They are providing additional mechanical support to the huge banyan tree. This modification is called a prop root.

2. Turnip. In turnip the root is modified to store extra food.

3. Mangrove Trees. Mangrove trees are found in marshy area. The roots are modified into pneumatophore providing extra passage to allow additional oxygen to the plant.

Plus One Botany Plant Kingdom Multiple Choice Questions and Answers

Question 1.
The obliquely growing roots that provides mechanical support to the main stem are
(a) prop root
(b) stilt root
(c) pneumatophore
(d) pillar root
Answer:
(b) stilt root

Question 2.
Lateral branches arise from the base of main stem that grows aerially at first and arch downwards in
(a) pistia
(b) mint
(c) jasmine
(d) both b & C
Answer:
(d) both b & C

Question 3.
Pulvinus is found in the leaf base of
(a) Rosaceae
(b) Leguminosae
(c) Malvaceae
(d) Solanaceae
Answer:
(b) Leguminosae

Question 4.
The appearance of more than one leaf at each node is represented by
(a) china rose
(b) sunflower
(c) Alstonia
(d) guava
Answer:
(c) Alstonia

Question 5.
Roots are significant in the exchange of gases
(a) pneumatophore
(b) stilt root
(c) pillar root
(d) assimilatory root
Answer:
(a) pneumatophore

Question 6.
The type of flower cannot be divided into two similar halves in any vertical plane through centre is
(a) actinomorphic
(b) zygomorphic
(c) asymmetric
(d) both b & c
Answer:
(c) asymmetric

Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants

Question 7.
Ovary half inferior is seen in
(a) plum
(b) china rose
(c) peach
(d) both a & c
Answer:
(d) both a & c

Question 8.
Find out the papilionaceous type of corolla from the given figure.
Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants img24
(a) A
(b) B
(c) C
(d) D
Answer:
(d) D

Question 9.
9. Flowers with bisexual, zygomorphic, diadelphous and monocarpellary superior ovary are the characteristic feature of
(a) fabaceae
(b) malvaceae
(c) solanaceae
(d) liliaceae
Answer:
(a) fabaceae

Question 10.
The type of placentation given here is
Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants img25
(a) axile
(b) basal
(c) marginal
(d) parietal
Answer:
(d) parietal

Question 11.
Hilum is found in
(a) embryo
(b) seed coat
(c) radicle
(d) chalaza
Answer:
(b) seed coat

Question 12.
Ashwagandha is represented by the family
(a) Fabaceae
(b) papillionaceae
(c) Solanaceae
(d) Liliaceae
Answer:
(c) Solanaceae

Question 13.
The family represented by the floral formula given below is
Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants img26
(a) fabaceae
(b) papillionaceae
(c) solanaceae
(d) liliaceae
Answer:
(c) solanaceae

Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants

Question 14.
Negatively geotropic roots are seen in
(a) zaminkand
(b) Rhizophora
(c) maize
(d) euphorbia
Answer:
(b) Rhizophora

Question 15.
In the following picture, plant part is modified for
Plus One Botany Chapter Wise Questions and Answers Chapter 3 Morphology of Flowering Plants img27
(a) storage
(b) respiration
(c) support
(d) protection
Answer:
(a) storage

Question 16.
When the filaments of stamens are attached to the perianth, the condition is
(a) Epiphyllous
(b) epipetalous
(c) adelphous
(d) syngenesious
Answer:
(a) Epiphyllous

Question 17.
In China rose, five carpels are fused at base. This condition is called
(a) Pentacarpellary, syncarpous and pentalocular
(b) Pentacarpellary, apocarpous and pentalocular
(c) polycarpellary, syncarpous and penalocular
(d) Pentacarpellary, syncarpous and multilocular
Answer:
(a) Pentacarpellary, syncarpous and pentalocular

Plus One Botany Chapter Wise Questions and Answers Chapter 2 Plant Kingdom

Students can Download Chapter 2 Plant Kingdom Questions and Answers, Plus One Botany Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations

Kerala Plus One Botany Chapter Wise Questions and Answers Chapter 2 Plant Kingdom

Plus One Botany Plant Kingdom One Mark Questions and Answers

Question 1.
Artificial system of classification is mainly based on
(a) vegetative characters
(b) androecium structure
(c) habit and habitat
(d) all of these
Answer:
(d) all of these

Question 2.
Fusion between morphologically alike gametes is referred to as
(a) anisogamy
(b) isogamy
(c) oogamy
(d) sygamy
Answer:
(b) isogamy

Question 3.
Gametophytic generation is dominant in
(a) bryophytes
(b) pteridophytes
(c) angiosperms
(d) gymnosperms
Answer:
(a) bryophytes

Plus One Botany Chapter Wise Questions and Answers Chapter 2 Plant Kingdom

Question 4.
Mycorrhizal roots of _____ are associated with some fungal symbionts
(a) Cedrus
(b) pinus
(c) cycas
(d) lichens
Answer:
(b) pinus

Question 5.
Haplontic life cycle is generally occurs in
(a) algae
(b) pteridophytes
(c) bryophytes
(d) gymnosperms
Answer:
(a) algae

Question 6.
Name the type of cell division which produce four haploid cells with new combination of characters from a diploid cell.
Answer:
Meiosis.

Question 7.
Name the dominating pigment in red algae.
Answer:
Phycoerythrin

Question 8.
Name the algae from which algin is prepared commercially.
Answer:
Laminaria (brown algae)

Question 9.
Name the filamentous structure that appears in the mosses due to the germination of spores.
Answer:
Protonema

Question 10.
Give an example of plant group which produce seed but not fruit.
Answer:
Gymnosperms

Question 11.
What is the genetic constitution of endosperm of angiosperm.
Answer:
Triploid

Question 12.
Fill in the blanks.

  1. Bryophytes – Haplo-diplontic
    Gymnosperms – ________
  2. Algin – Brown algae
    Carrageen – _______

Answer:

  1. Diplontic
  2. Red algae

Question 13.
If chlorophyll b is for Chlorophyceae, chlorophyll d is for _______
Answer:
Rhodophyceae

Question 14.
Pick out the correct pairs of plant groups that bearing archegonium.
(a) gymnosperm angiosperm
(b) angiosperm Bryophyta
(c) Bryophyta Pteridophyta
(d) Pteridophyta gymnosperm
Answer:
(d) Pteridophyta gymnosperm

Plus One Botany Chapter Wise Questions and Answers Chapter 2 Plant Kingdom

Question. 15
Select the odd one.
(Nitrosomonas, archaebacteria, Nitrococcus, Nitrobacteria)
Answer:
Archaebacteria

Question 16.
The majority of pteridophytes are homosporous ie. they produce similar kind of spores. Give one example of a heterosporous pteridophyte.
Answer:
Selaginella

Question 17.
Archaebacteria, special type of bacteria, which are able to survive in extreme conditions, What is the feature helping them for this?
Answer:
Structure of the cell wall.

Question 18.
Complete the following:
1. Plasmogamy: Fusion of Protoplasms
……………: Fusion of nuclei
Answer:
karyogamy

Question 19.
Laminarin is a stored food in Phaeophyceae, what is the stored food in Rhodophyceae?
Answer:
Floridean starch

Question 20.
The essential element is present in the ring structure of chlorophyll. Which is the element?
Answer:
Mg.

Question 21.
By observing the relationship of the first and fill up the second.
1. Algae and Fungi: Lichen
Roots of higher plants and Fungus:………….
Answer:
Mycorrhiza

Question 22.
Observe the relationship between the first two terms and fill up the blank.

  1. Moss: Protonema; Fern ………….
  2. Egg: Zygote; …………; PEN

Answer:

  1. Prothallus
  2. Secondary Nucleus

Question 23.
Pick the odd one out from the following and justify your answer.
Chlamydomonas, Volvox, laminaria, Chara.
Answer:
laminaria-brown algae

Question 24.
Choose the correct answer.

  1. food materials in fungi are stored in the form of (glucose, glycogen, sucrose, starch)
  2. Membrane covering the vacuole (meninges, tonoplast, pleura).

Answer:

  1. Glycogen
  2. Tonoplast

Question 25.
Name the organisms which are not included in any of the kingdoms,
Answer:
Viruses

Question 26.
Name the plant group in which ‘protonema’ is present.
Answer:
Bryophytes

Question 27.
Observe the relationship between the first two pairs and fill up the blanks.

  1. Sac fungi: Ascomycetes
    Imperfect fungi: …………
  2. Transpiration: Loss of water in the form of water vapour.
    ……………: Loss of water in the form of liquid

Answer:

  1. Deuteromycetes
  2. Guttation

Question 28.
Fusion of two gametes which are dissimilar in size is termed as
(a) Oogamy
(b) Isogamy
(c) Anisogamy
(d) Zoogamy
Answer:
(c) Anisogamy

Question 29.
Holdfast, stipe, and frond constitutes the plant body in case of
(a) Rhodophyceae
(b) Chlorophyceae
(c) Phaeophyceae
(d) All of the above
Answer:
(c) Phaeophyceae

Question 30.
Food is stored as Floridean starch in Rhodophyceae. Mannitol is the reserve food material of which group of algae?
Answer:
Brown algae

Question 31.
A plant shows thallus level of organization. It shows rhizoids and is haploid. It needs water to complete its life cycle because the male gametes are motile. Identify the group to which it belongs to
Answer:
Bryophytes

Question 32.
My body is a gametophyte and I grow under moist and shaded conditions. My group is commonly known as amphibians of the plant kingdom. Name my group.
Answer:
Bryophyta

Question 33.
Name the gametophyte that is free-living structure formed in pteridophytes.
Answer:
Prothallus

Question 34.
The plant body in higher plants is well differentiated and well developed. Roots are the organs used for the purpose of absorption. What is the equivalent of roots in the less developed lower plants?
Answer:
Rhizoids

Question 35.
Plants are generally autotrophic. Can you think of certain plants that are partially heterotrophic?
Answer:
Loranthus – Partial stem parasite

Plus One Botany Chapter Wise Questions and Answers Chapter 2 Plant Kingdom

Question 36.
Choose the correct pair.
(a) Spirogyra – Algae
(b) Sphagnum – Gymnosperm
(c) Selaginella – Bryophyte
(d) Funaria – Pteridophyte
Answer:
(a) Spirogyra – Algae

Plus One Botany Plant Kingdom Two Mark Questions and Answers

Question 1.
Diagrams of three bryophytes are given below.
Plus One Botany Chapter Wise Questions and Answers Chapter 2 Plant Kingdom img1

 

  1. Observe and give the names of these bryophytes.
  2. Which of the three bryophytes is the most advanced?

Answer:
1. names of these bryophytes.

  • A – Riccia,
  • B – Marchantia,
  • C – Funaria

2. Funaria

Question 2.
Observe the relationship between the first two terms and fill up the blanks.

  1. Kingdom fungi – multicellular decomposer
    Kingdom Plantae – _____________
  2. Gymnosperm – Cone
    Angiosperm – _____________

Answer:

  1. Kingdom plantae – multicellular producers
  2. Angiosperm – flower

Question 3.
Bryophytes are “amphibians of the plant kingdom”. Comment.
Answer:
The vegetative structure are well adapted to live on land but water is essential for fertilization.

Question 4.
Prothallus is the gametophytic stage of Pteridophyte What is protonema?
Answer:
Protonema is the young stage of moss gametophyte

Question 5.

AB
Chlamydomonas

Cycas

Selaginella

Sphagnum

Moss

Pteridophytes

Algae

gymnosperms

Answer:

AB
Chlamydomonas

Cycas

Selaginella

Sphagnum

Algae

Gymnosperms

Pteridophytes

Moss

Question 6.
Analyse the table and arrange the matter in an appropriate order.
Plus One Botany Chapter Wise Questions and Answers Chapter 2 Plant Kingdom img2
Answer:
Plus One Botany Chapter Wise Questions and Answers Chapter 2 Plant Kingdom img3

Question 7.
Lichens are the symbiotic association between algae and fungi.

  1. What is symbiosis?
  2. How both the partners help each other?

Answer:
1. Relationship between 2 organisms, both are benefited.

2. Algae – prepare food
Fungus – Gives shelter to algae

Plus One Botany Chapter Wise Questions and Answers Chapter 2 Plant Kingdom

Question 8.
Arrange the following plants in the table given below, (two members from each group)
Riccia, Spirogyra, Adiantum, Chlorella, Funaria, Cycas, Nephrolepis, Pinus.
Plus One Botany Chapter Wise Questions and Answers Chapter 2 Plant Kingdom img4
Answer:
Plus One Botany Chapter Wise Questions and Answers Chapter 2 Plant Kingdom img5

Question 9.
The following is a list of plants. Arrange them in the table given below.
Marchantia, Selaginella, Salvinia, Sunflower, Funaria, Pinus, Maize, Cycas.
Plus One Botany Chapter Wise Questions and Answers Chapter 2 Plant Kingdom img6
Answer:
Plus One Botany Chapter Wise Questions and Answers Chapter 2 Plant Kingdom img7

Question 10.
Plus One Botany Chapter Wise Questions and Answers Chapter 2 Plant Kingdom img8

  1. Identify the life cycle pattern?
  2. Cite two examples of organisms showing the above life cycle pattern?

Answer:

  1. Haplo-diplontic.
  2. Bryophytes and pteridophytes

Question 11.
The classical Taxonomy of organisms is mainly based . on morphological characters. But modern taxonomy gives equal weightage to all characters.
Answer:

  1. Name this new approach in modern taxonomy.
  2. Mention any two branches of this taxonomy.

Answer:

  1. Numerical taxonomy
  2. Chemo taxonomy, cytotaxonomy

Question 12.

AB
Sargassum

Bryophyte

ABA

Ribosomes

Anabaena

Stomatal movement

Palade

N2 fixation

Brown alga

Sphagnum

Answer:

AB
SargassumBrown alga
BryophyteSphagnum
ABAStomatal movement
RibosomesPalade
AnabaenaN2 fixation

Question 13.
Pick up the odd one.

  1. Oscillatoria, Spirulina, Actinomycetes, Nostoc
  2. Epipetalous, Epiphyllous, Monadelphous, Apocarpous.

Answer:

  1. Actinomycetes
  2. Apocarpous

Question 14.
Green algae are considered as the ancestors of angiosperms.

  1. Is this statement correct?
  2. Justify your answer.

Answer:

  1. Yes
  2. Chloroplast is present

Question 15.
Red algae reach the maximum depth in sea where no other photosynthetic form grow. Justify.
Answer:
The pigment phycoerythrin absorb the blue-green part of the sunlight’s spectrum. The blue-green light has short wavelength and penetrates deep into the water.

Question 16.
During summer you cannot see the growth of Funaria. What is the reason for this?
Answer:
Water is needed for reproduction – amphibians of plant kingdom.

Plus One Botany Chapter Wise Questions and Answers Chapter 2 Plant Kingdom

Question 17.
By observing the relationship between the first pair, fill up the blanks.

  1. Chlorophyceae: Starch: Rhodophyceae: ……………….
  2. Moss:Protonema; Nephrolepis : ………….

Answer:

  1. Floridean starch
  2. Prothallus

Question 18.
Match the following. (Column I with Column II)
Plus One Botany Chapter Wise Questions and Answers Chapter 2 Plant Kingdom img9
Answer:

Column IColumn II
a) ChlamydomonasAlgae
b) CycasGymnosperm
c) SelaginellaPteridophyte
d) SphagnumMoss

Question 19.
Observe the relationship between first two terms and fill up the blanks.

  1. Phycobiont: Algal partner
    ……………: Fungal partner
  2. Rhizopus: Phycomycetes
    Penicillin: ………….

Answer:

  1. Mycobiont
  2. Ascomycetes

Question20.
When & where does reduction division takes place in the life cycle of liverwort, moss, ferns, gymnosperm, and angiosperm?
Answer:

  • Liver wort – Reduction division takes place inside the capsule at the time of spore production.
  • Moss – Reduction division takes place inside the capsule at the time of spore formation.
  • Ferns- Reduction division takes place in sporangium in the leaves at the time of spore formation.
  • Gymnosperm – Reduction divsion takes place in the sporangium born on sporophyte of cone.
  • Angiosperm – reduction division takes place at the time of gamete formation in male & female gametophyte during sexual reproduction.

Question 21.
Observe the given table and arrange the matter in an appropriate order.
Plus One Botany Chapter Wise Questions and Answers Chapter 2 Plant Kingdom img10
Answer:
Plus One Botany Chapter Wise Questions and Answers Chapter 2 Plant Kingdom img11

Question 22.
Complete the table using appropriate terms.
Plus One Botany Chapter Wise Questions and Answers Chapter 2 Plant Kingdom img12
Answer:
Plus One Botany Chapter Wise Questions and Answers Chapter 2 Plant Kingdom img13

Question 23.
What is the basis of the classification of algae?
Answer:
Algae is classified on the basis of pigment Sreserve food.
Eg:

  • Green algae(Chlorophyceae)
  • Red algae(Rhodophyceae)
  • Brown algae(Phaeophyceae)

Question 24.
Liverworts, mosses and ferns usually grow near water. Comment.
Answer:
External water is required for dehiscence of antheridia, liberation of antherozoids, transfer of antherozoids from antheridia to archegonia, opening of archegonial neck and the movement of antherozoids into the archegonial neck for fertilisation during sexual reproduction.

Question 25.
Both gymnosperm & Angiosperm are seed-bearing plants. Why are they classified separately?
Answer:
Gymnosperm and angiosperm are seed-producing plants. In gymnosperm ovules or seeds are not enclosed by ovary wall after fertilisation. In angiosperm, the seeds are protected by ovary wall after fertilisation.

Question 26.
Some characteristic features of the plant is given below.

  • The main plant body posesses rhizoids.
  • The nucleus of main plant body have haploid chromosome number.
  • Zygote develops into a new plant which is dependant on main plant body.
  • The sporophyte has foot, seta, and capsule.

1. Identify the plant.
2. Name the cells where reduction division (meiosis) takes place in the life cycle of the plant.
Answer:

  1. Moss plant
  2. Spore mother cells

Question 27.
Differentiate between the following,

  1. Red algae & Brown algae
  2. Liverworts & Mosses
  3. Homosporous & Heterosporous
  4. Sygamy & Triple fusion

Answer:
1.

Red AlgaeBrown Algae
1. Rhodophycea1. Phaeophycea
2. Predominant pigment is phycoerythrin2. Predominant pigment is fucoxanthin
3. Stored food is laminarin and mannitol3. Stored food is floridean starch

2.

Liver wortsMosses
1. Dorsiventral thallus1. The plant is upright bearing leaves, & rhizoids
2.  Asexual reproduction by fragmentation & gemma2. Asexual reproduction by budding
3.  Protonema absent3.  Protonema stage present

3.

HomosporousHetero sporous
1.  Spores are of same type1.  Spores produce are 2 types
2.  Gametophyte is prothallus & develops male & female sex organs2.  Female Gemetophyte is retained in the parent sporophyte

4.

SygamyTriple fusion
1. The fusion between egg & sperm to give rise to diploid zygote
egg + sperm = zygoten           n              2n
1. The fusion between the secondary nucleus and male gamete to form the Primary endosperm nucleus.
secondary nucleus + sperm =PEN                                     n                                  n           2n

Question 28.
The following is a list of plants.
Riccia, Chlorella, Selaginella, Adiantum, Chalamydomas, Sugarcane, Funaria, Gnetum, Ficus, Cycas. Categorise these plants into Algae, Bryophytes, Gymnosperms, and Angiosperms.
Answer:

  • Algae – Chlorella, Chlamydomonas
  • Bryophytes – Riccia, Funaria
  • Pteridophytes – Selaginella, Adiantum
  • Gymnosperms-Gnetum, Cycas
  • Angiosperms- Sugarcane, Ficus

Plus One Botany Chapter Wise Questions and Answers Chapter 2 Plant Kingdom

Question 29.
Some plants of cycas produce seeds, but not others. Justify.
Answer:
Cycas plants are dioecious. Male plants of cycas produce microsporophylls and female plants produce megasporophyll. So only female cycas produce seeds and not the males.

Question 30.
Complete the table using the following terms.
Plus One Botany Chapter Wise Questions and Answers Chapter 2 Plant Kingdom img15
Primitive vascular plants, Sprogyra, Triploid endosperm, Marchantia, Naked seeded plants, Pteris, Aquatic autotrophs, Wolfie, Amphibians of plant Kingdom, Pinus
Answer:
Plus One Botany Chapter Wise Questions and Answers Chapter 2 Plant Kingdom img16

Question 31.
The following is the list of plants Arrange them in the table given below.
Marchantia, Chlorella, Lycopodium, Adiantum, Clamydomonas, Sunflower, Funaria, Gnetum, Cycas, Maize.
Plus One Botany Chapter Wise Questions and Answers Chapter 2 Plant Kingdom img17
Answer:
Plus One Botany Chapter Wise Questions and Answers Chapter 2 Plant Kingdom img18

Question 32.
The haplodiplontic life cycle is present in fern plants. Justify your answer.
Answer:
ln fern plants, the haploid phase is alternate with diploid phase in life cycle. Haploid and diploid phases have equal weightage in life cycle.

Question 33.
What is mixotrophic mode of nutrition?
Answer:
It is the type of nutrition found in Euglena that means both autotrophic and heterotrophic nutrition.

Question 34.
Why seed plants are most successful of all land plants?
Answer:
They are most successful of all land plants because external supply of water is not required for fertilization.

Question 35.
How bryophytes are advanced over algae?
Answer:
In higher bryophytes plant body is differentiate into root-like,stem-like and leaf-like structures. They also shows amphibious habit.

Question 36.
Differentite between gametophyte and sporophyte.
Answer:
Gametophyte is haploid and bears gametes. Sporophyte is diploid and bears spores

Question 37.
In which plant will you look for mycorrhiza and corolloid roots? Also explain what these terms mean, pinus and cycas.
Answer:

  1. Mycorrhiza – association of root and fungus
  2. Corolloid root – association of root and N2 fixing cyanobacteria.

Question 38.
Why rhizoids are not called roots?
Answer:
Rhizoids are haploid and lack vascular tissue, on the other hand, roots are diploid and bear vascular tissue.

Question 39.
Both gymnosperms and angiosperms bear seeds, then why are they classified separately?
Answer:
Because the gymnosperms are plants that bear ovules that are not covered by any ovary wall i.e the seeds of gymnosperms are not covered( naked). But in the angiosperms the seeds remain enclosed inside the fruits.

Question 40.
Why are some bryophytes called liverworts?
Answer:
Some bryophytes are called liverworts because their gametophyte resembles liver lobes.

Question 41.
Heterospory i.e., formation of two types of spores microspores and megaspores is a characteristic feature in the life cycle of a few members of pteridophytes and all spermatophytes. Do you think heterospory has some evolutionary significance in plant kingdom?
Answer:
It is considered as precursor to seed habit. The microspores of angiosperms develops into male gametophyte and megaspores develops into female gametophyte or embryosac.

Question 42.
Most algal genera show a haplontic lifestyle. Name an alga which is

  1. Haplo-diplontic
  2. Diplontic

Answer:

  1. Ectocarpus, polysiphonia and kelps
  2. Fucus

Question 43.
What is heterospory? Give its significance?
Answer:
Heterospory is the production of two kinds of spores in pteridophytes. EgfSalvina and Selaginella They produces 2 kind of spores i.e macrospores- these are large in size and microspores-these are small in size.

Question 44.
The spores and gametes produced by some members of algae are nonmotile.

  1. Do you agree the above statement.
  2. Give reasons.

Answer:

  1. Yes
  2. In members of red algae, the pear-shaped spores and gametes do not possess flagella, hence they are non-motile.

Question 45.
Nature of spore development is different in bryophytes and pteridophytes.

  1. Give the common name for the structures arise from spores.
  2. Identify these two.

Answer:

  1. Gametophyte
  2. Protonema and Prothallus

Plus One Botany Chapter Wise Questions and Answers Chapter 2 Plant Kingdom

Question 46.

  1. Name the diploid and triploid products formed in Embryosac after fertilisation.
  2. What will be the fate of haploid structures not participate in fertilisation?

Answer:

  1. Diploid – Zygote,
    Triploid – PEN
  2. Synergids and antipodals degenerate after fertilisation.

Question 47.

  1. Identify the types of associations in some members of gymnosperms
  2. Name organisms forms in such associations

Answer:

  1. Mycorrhiza and corrolloid root
    Mycorrhiza – pinus and fungus,
  2. Corrolloid root – N2 fixing cyanobacteria and cycas

Question 48.

  1. Differentiate the nature of plant body in Bryophytes and gymnosperms.
  2. Identify the life cycle shown by the above two plant group

Answer:

  1. Bryophytes – Thallus type (plant body is not differentiated)
    Gymnosperms – Plant body is differentiated into root, stem, and leaves
  2. Bryophytes – Haplo-diplontic
    Gymnosperms – Diplontic

Plus One Botany Plant Kingdom Three Mark Questions and Answers

Question 1.
Mark the statement Ture or False,

  1. Potato, ginger, turmeric are underground stems. They are modified to store food in them
  2. Phyllotaxy is the pattern of arrangement of leaves on the stem or branch
  3. A flower having only stamens or carpel is bisexual.
  4. Calyx and corolla are reproductive organs
  5. Lamina is the green expanded part of the leaf with veins and veinlets
  6. In racemose inflorescence, the main axis terminates in a flower.
  7. Ovary in epigynous flower is superior
  8. If the margin of sepals or petals overlap one another but not in particular direction, the aestivation is called imbricate.
  9. A sterilse stamen is called staminode
  10. The seed coat has two layers the outer testa and the inner tegmen.

Answer:

  1. True
  2. True
  3. False
  4. False
  5. True
  6. False
  7. False
  8. True
  9. True
  10. True

Question 2.
What is heterospory. Give brief account of its significance with examples.
Answer:
Hetrospory is the production of 2 types of spores, Macro (large) and Micro(Small). They give rise to female and male gametophyte respectively. The gamete fused to form zygote which retained in the female gametophyte. This event can be considered as a precursor of seed habit and is an important step in evolution.

Question 3.
Mention the ploidy of the following.

  1. Protonemal cell of a moss
  2. Primary endosperm nucleus in dicot.
  3. Leaf cell of moss.
  4. Fern Prothalus
  5. Meristem cell of monocot
  6. Ovum cell of liverwort
  7. Zygote of a fern

Answer:

  1. n – Haploid
  2. 3n triploid
  3. n – haploid
  4. n – haploid
  5. 2n – diploid
  6. n – haploid
  7. 2n)diploid

Question 4.
Explain briefly the following term with suitable examples. Protonejjia, Antheridium, Archegonium, Diplonticand Sporophyll.
Answer:

  1. Protonema – the 1st gametophytic stage developed by the germination of spores in Bryophytes
  2. Antheridium – Male sex organs which produce flagellated motile male gamtes. eg: Bryophyte
  3. Archegonium – Female sex organ which produce nonmotile egg it is a flask shaped. eg: pteridophyte & Gymnosperm
  4. Diplontic – Diploid sporophytic generation is dominant photosynthetic independent phase of the plant and gametophytic phase is represented by haploid gametophyte eg: gymnosperm & angiosperm

Plus One Botany Chapter Wise Questions and Answers Chapter 2 Plant Kingdom

Question. 5
Based on the relationship, fill in the blanks:

  1. Nephrolepis:Prothallus:: Funaria: ……….
  2. Penicillium: ………..:: Agaricus Basidiocarp
  3. …………… Phaeophyceae::Carageen: Rhodophyceae

Answer:

  1. Protonema
  2. Conidia
  3. Mannitol

Question. 6
A few statements regarding algae are given below. Study them carefully and state true or false. If false make them correct.

  1. Algae are thallophytes.
  2. Volvox is a red algae.
  3. Algin is obtained from red algae.
  4. Floridean starch is found in green algae.
  5. Green algae are known as Rhodophyte.
  6. Green algae possess chlorophyll a

Answer:

  1. True
  2. False. Green algae 1
  3. False. Brown algae
  4. False. Red algae
  5. False. Chloropyta
  6. True

Question.7
Write a note on the economic importance of algae & gymnosperm.
Answer:
Algae – increase the level of oxygen in enviomment. They are the chief producers in aquatic ecosystems Some species of brown algae like sargassum, laminaria & Porphyra are used as food. Red algae and brown algae produce hydrocolloids which are water-holding substances. Eg: Gracilaria & gelidium Clorella is used as food supplement by space travelers.

Gymnosperm – Produce alkaloids like terpentine from the stem. They are grown as an ornamental plant. Certain species like ephedra are medicinal.

Plus One Botany Plant Kingdom NCERT Questions and Answers

Question 1.
How would you distinguish monocots from dicots?
Answer:

  • The easiest way is by looking at their seeds. Seeds of monocots have one cotyledon while that of dicots have two cotyledons.
  • Dicots have tap root system, while monocots have fibrous root system.
  • Dicots show reticulate venation, while monocots show parallel venation.

Plus One Botany Chapter Wise Questions and Answers Chapter 2 Plant Kingdom

Question 2.
Match the followings (column I with column II)
Plus One Botany Chapter Wise Questions and Answers Chapter 2 Plant Kingdom img19
Answer:

  • a) – iii
  • b) – iv
  • c) – ii
  • d) – i

Question 3.
What is heterospory? Briefly comment on its significance. Give two examples.
Answer:
Certain pteridophytes produce two kinds of spores. This phenomenon is called heterospory.

Question 4.
Both gymnosperms and angiosperms bear seeds, then why are they classified separately?
Answer:
The seeds of gymnosperms are naked, while that of angiosperms are covered by a membrane. That is why they are classified separately.

Question 5.
What is the basis of classification of algae?
Answer:
The main basis of classification of algae is the presence or absence of pigments, which impart an algae
its colour.
1. Chiorophyceae contains chlorophyll a and b, giving it the green colourand the name ‘green algae’.

2. Phaeophyceae contains chlorophyll a and c and fucoxanthin. The fucoxanthin gives it the brown colourand hence the name ‘brown algae’.

3. Rhodophyceae contains chlorophyll a and d and phycoerythrin. The phycoerythrin gives the distinct red colour and hence the name ‘red algae’.

Plus One Botany Plant Kingdom Multiple Choice Questions and Answers

Question 1.
The major pigment present in brown algae is
(a) chlorophyll a
(b) fucoxanthin
(c) Floridian starch
(d) phycoerythrin
Answer:
(b) fucoxanthin

Question 2.
Hetrospory is first noticed in
(a) gymnosperm
(b) pteridophytes
(c) gymnosperm
(d) ferns
Answer:
(b) pteridophytes

Question 3.
Mycorrhizal association is found in the root of
(a) ferns
(b) pinus
(c) cycas
(d) potytrichum
Answer:
(b) pinus

Plus One Botany Chapter Wise Questions and Answers Chapter 2 Plant Kingdom

Question 4.
Which one of the following belongs to brown algae
(a) polysiphonia
(b) ectocarpus
(c) ulothrix
(d) volvox
Answer:
(b) ectocarpus

Question 5.
Sexual reproduction of bryophytes involves the production of
(a) sperms
(b) biflagellate antherozooids
(c) antheroids
(d) cilliate antherozooids
Answer:
(b) biflagellate antherozooids

Question 6.
The asexual reproductive structures occurs in bryophytes are
(a) zoospores
(b) gemmae
(c) fronds
(d) rhizoids
Answer:
(b) gemmae

Question 7.
Protonema stage occurs when
(a) spore of bryophytes germinate
(b) seed germinates
(c) spore of ferns germinate
(d) none of the above
Answer:
(a) spore of bryophytes germinate

Question 8.
PEN is formed in
(a) angiosperm
(b) pteridophytes
(c) gymnosperm
(d) ferns
Answer:
(a) angiosperm

Question 9.
The life cycle occurs in ectocarpus is
(a) haplontic
(b) haplodiplontic
(c) diplontic
(d) none of the above
Answer:
(b) haplodiplontic

Question 10.
Prothallus is
(a) photosynthetic gametophyte
(b) photosynthetic sporophyte
(c) non photosynthetic gametophyte
(d) non photosynthetic sporophyte
Answer:
(a) photosynthetic gametophyte

Plus One Botany Chapter Wise Questions and Answers Chapter 2 Plant Kingdom

Question 11.
Phylogenetic system of classification is mainly based on
(a) embryological characters
(b) evolutionary characters
(c) morphological Characters
(d) floral characters
Answer:
(b) evolutionary characters

Question 12.
Classification based on cytological information, chromosome number etc.called
(a) chemotaxonomy
(b) cytotaxonomy
(c) numerical taxonomy
(d) cytogenetics
Answer:
(b) cytotaxonomy

Question 13.
In which of the following groups would you place plants having vascular tissue but lacking seeds
(a) pteridophytes
(b) gymnosperms
(c) angiosperms
(d) bryophytes
Answer:
(a) pteridophytes

Question 14.
Life cycle found in pteridophytes
(a) haplontic
(b) diplontic
(c) haplo-diplontic
(d) either haplontic or diplontic
Answer:
(c) haplo-diplontic

Question 15.
Fucoxanthin is the chief pigment in
(a) red algae
(b) brown algae
(c) green algae
(d) blue green algae
Answer:
(b) brown algae

Question 16.
Algae which grow on animals and also occur on shells of molluscs or other invertebrates are called
a) parasitic
b) epiphytic
c) epizoic
d) coenobia

Question 17.
Xylem of gymnosperm lack
(a) tracheids
(b) vessels
(c) both a and b
(d) fibres
Answer:
(b) vessels

Question 18.
Pyrenoids are present in
(a) angiosperms
(b) gymnosperms
(c) algae
(d) pteridophytes
Answer:
(c) algae

Plus One Botany Chapter Wise Questions and Answers Chapter 2 Plant Kingdom

Question 19.
The first plants to appear after forest fire are the ferns this is because of the survival of their
(a) fronds
(b) rhizome
(c) spores
(d) both a and c
Answer:
(b) rhizome

Question 20.
The endosperm of gymnosperm is
(a) diploid
(b) triploid
(c) tetraploid
(d) haploid
Answer:
(d) haploid

 

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays

Students can Download Chapter 2 Arrays Questions and Answers, Plus Two Computer Application Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays

Plus Two Computer Application Arrays One Mark Questions and Answers

Question 1.
From the following which is not true for an array
(a) It is easy to represent and manipulate array variable
(b) Array uses a compact memory structure
(c) Readability of program will be increased
(d) Array elements are dissimilar elements
Answer:
(d) Array elements are dissimilar elements.

Question 2.
Consider the following declaration. int mark (50).
Is it valid? If no give the correct declaration.
Answer:
It is not valid. The correct declaration is as follows, int mark[50]. Use square brackets instead of parenthesis.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays

Question 3.
Consider the following declaration. int mark[200].
The index of the last element is____.
Answer:
199.

Question 4.
Consider the following declaration int mark[200]
The index of the first element is_____
Answer:
0.

Question 5.
Consider the following int age[4]={15, 16, 17, 18};
From the following which type of initialisation is this.
(a) direct assignment
(b) along with variable declaration
(c) multiple assignment
(d) None of these
Answer:
(b) along with variable declaration

Question 6.
From the following which is used to read and display array elements
(а) loops
(b) if
(c) switch
(d) if else ladder
Answer:
(a) loops

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays

Question 7.
Write down the corresponding memory consumption in bytes

  1. int age[10]=_____
  2. charname[10] =_____
  3. intage[10][10]=____

Answer:

  1. 4*10 = 40 bytes (4 bytes for one integer)
  2. 1*10=10 (one byte for each character)
  3. 4*10*10 = 400 (4 * 100 elements)

Question 8.
Consider the following intage[4] = {12, 13, 14};
cout<<age[3]; What will be the output?
(а) 14
(b) 12
(c) 13
(d) 0
Answer:
(d) 0

Question 9.
The elements of 2-dimensional array can be read using_____loop
Answer:
nested loop.

Question 10.
_____is the process of reading / visiting elements of an array
Answer:
traversal.

Question 11.
Anjaly wants to read the 10 marks that already stored in an array and find the total. This process is known as_____
(a) insertion
(b) deletion
(c) traversal
(d) linear search
Answer:
(c) traversal

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays

Question 12.
The elements of an array of size ten are numbered from____to___.
Answer:
0 to 9.

Question 13.
Element mark[6] is which element of the array?
(a) The sixth
(b) the seventh
(c) the eighth
(d) impossible to tell
Answer:
(b) the seventh

Question 14.
When a multidimensional array is accessed, each array index is
(a) Separated by column.
(b) Surrounded by brackets and separated by commas.
(c) Separated by commas and surrounded by brackets.
(d) Surrounded by brackets.
Answer:
(d) surrounded by brackets

Question 15.
Write a C++ statement that defines a string variable called ‘name’ that can hold a string of upto 20 characters.
Answer:
char name[21];

Question 16.
_____is a collection of elements with same data type
Answer:
Array

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays

Question 17.
Following are some of the statements regarding array. Identify the correct statement.
(a) Array is a collection of elements of same data type.
(b) Array cannot be initialised during the time of declaration.
(c) Array allocates continuous memory.
(d) An array element can be accessed using index or subscript.
Answer:
(a) Array is a collection of elements of same data type.

Question 18.
Which of the following is the correct declaration of an array?
(a) int a(10);
(b) int 10[a];
(c) a[1] int;
(d) inta[10];
Answer:
(d) int a[10];

Question 19.
Which is the last subscript of the array int m[25]?
(a) 24
(b) 25
(c) 0
(d) 26
Answer:
(a) 24

Question 20.
The memory size of the data type float is 4 bytes. What is the total bytes required for the array declaration float salary[10];?
(a) 10
(b) 4
(c) 40
(d) 400
Answer:
(c) 4*10 = 40.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays

Question 21.
int num[100]; The above statement declares an array named num that can store maximum_____integer numbers.
(a) 99
(b) 100
(c) 101
(d) Any number
Answer:
(b) 100

Question 22.
If int a[10]; is array, then which element of the array will be referenced as a[4].
Answer:
Fifth element.

Question 23.
Consider the following array declaration int A[ ] = {4, 5, 8}; int B[ ]={2, 10};
Write a valid C++ statement for finding the difference between the last element of the array ‘B’ and the first element of the array ‘A’.
Answer:
B[1] – A[0]; ORA[0] – B[1];

Question 24.
Consider the following code and predict the output.
int sum=0;
int a[5] = {1, 2, 3, 4, 5};
for(i=0;i<4;++i)
{
sum=sum+a[i];
}
cout<<sum;
Answer:
10.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays

Question 25.
Which data type is used to declare a variable to hold string data?
Answer:
The data type char is used for this.

Question 26.
The terminating character of string array is______
Answer:
\0 or NULL character.

Question 27.
Write a statement for storing the string “NO SMOKING” using a character array with name ‘ARR’
of minimum size.
Answer:
char APR[11] = ”NO SMOKING”;

Plus Two Computer Application Arrays Two Mark Questions and Answers

Question 1.
Given some array declaration. Pick the odd man out.
Float a[+40], int num[0-10], double [50]. char name[50], amount[20] of float.
Answer:
char name[50]. It is a valid array decalaration the remaining are not valid.

Question 2.
Whether the statement char text[] = “COMPUTER”; is True / False ? Justify.
Answer:
It is a single-dimensional array. If the user doesn’t specify the size the operating system allocates the number of characters + one (for null character for text) bytes of memory. So here OS allocates 9 bytes of memory.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays

Question 3.
Suppose you are given Total mark of 50 students in a class

  1. How will you store these values using ordinary variable?
  2. Is there any other efficient way to store these values? Give reason

Answer:
We have to declare 50 variables individually to store total marks of 50 students. It is a laborious work. Hence we use array, it is an efficient way to declare 50 variables.

With a single variable name we can store multiple elements. Eg: int mark[50]. Here we can store 50 marks. The first mark is in mark[0], second is in mark[1], …etc the fiftieth mark is in mark[49].

Question 4.
Consider the statement charstr[ ] = “PROGRAM” What will be stored in last location of this array. Justify
Answer:
The last location is the null character(\0) because each string must be appedend by a null character.

Question 5.
Explain the needs for arrays
Answer:
Array is collection of same type of elements. With the same name we can store more elements. The elements are distinguished by using its index or subscript. To store 50 marks of 50 students we have to declare 50 variables, it is a laborious work.

Hence the need for arrays arise. By using array this is very easy as follows int mark[50]. Here the index of first element is 0, then 1, 2, 3, etc upto 49.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays

Question 6.
Consider the following code and predict the output.
int a[5]= {6, 8, 10,20,40};
cout<<“\n”<<a[3];
cout<<“\n”<<a[1]+1[4];
Answer:
20(The fourth element).
48(Sum of second element 8 and fifth element 40, i.e 8 + 40 =48).

Question 7.
Suppose you need to store the value 10, 20, 30, 40 and 50 into an array. Write different methods to do this problem. Answer:
Method 1:
int a[5]={10, 20, 30, 40, 50};

OR

int a[ ]={10, 20, 30, 40, 50};

Method 2:
int a[5];
a[0]=10;
a[1]=20;
a[2]=30;
a[3]=40;
a[4]=50;

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays

Question 8.
What would be the appropriate array declaration to store the following?

  1. Name of a student
  2. Age of 20 students
  3. Mark of 6 subject
  4. Average mark of 10 students in 5 subjects

Answer:

  1. charname[20];
  2. intage[20];
  3. intmark[6];
  4. float mark[10];

Question 9.
Consider the following code and predict the output.
int A[5] = {11, 12, 13, 14, 15};
int i;
for (i=4;i>=0;–i)
{
cout<<“\n”<<A[i];
}
Answer:
It prints the array in reverse order as follows.
15
14
13
12
11.

Question 10.
Predict the output of the following code segment.
int K[ ] = {1, 2, 3, 4};
for (int i=0; i<4; i++)
cout<<K[i] * K[i]<<“\t”;
Answer:
The output is as follows
1 4 9 16
Hint: 1(1*1) 4(2*2) 9(3*3) 16(4*4).

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays

Question 11.
Consider the following code and predict the output.
Justify your answer.
int A[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
int sum=0, i;
for(i=0;i<10;++i)
{
if (A[i]%2==0)
{
sum=sum+A[i];
}
}
cout<<“\nSum=”<<sum;
Answer:
The output is 30. That is sum of all even numbers in the array.

Question 12.
Predict the output of the following C++ statement.
char str[8] = “WELCOME”;
cout<<“\n’’<,str[3];
cout<<“\n”<<str;
Answer:
The output is as follows
C(The fourth character)
WELCOME.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays

Question 13.
How many bytes will be allocated in the memory for storing the string “MY SCHOOL”? Justify your answer.
Answer:
A total of 10 bytes. 9 bytes is used to store 9 characters in the string MY SCHOOL(including 1 byte for space) and 1 byte is used to store the NULL character.

Plus Two Computer Application Arrays Three Mark Questions and Answers

Question 1.
Total mark of 50 students in a class are given in an array. A bonus of 10 marks is awarded to all of them. Write the program code for making such a modification.
Answer:
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays - 1

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays

Question 2.
Write the program code for counting the number of vowels from your school name
Answer:
# include
# include
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays - 2
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays - 3

Question 3.
Write the program code for counting the number of words from the given string.” Directorate of Higher Secondary Examination”
Answer:
# include
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays - 4

OR

(Program for more than one space between words)
# include
# include
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays - 5

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays - 6
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays - 7

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays

Question 4.
Given a word like “ECNALUBMA” Write the program code for arranging it in into a meaningful word Answer:
# include
# include
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays - 8

Question 5.
Explain different types of arrays.
Answer:
1. Single dimensional:
It contains only one index or subscript. The index starts from 0 and ends with size-1.
Eg. int n[50]; charname[10];

2. Multidimensional:
It contains more than one index or subscript. The two dimensional array contains two indices, one for rows and another for columns. The row index starts from 0 and end at row size-1 and column index starts at 0 and ends at colunn size-1.
Eg. int n[10][10] can store 10 * 10 =100 elements. The index of the first element is n[0][0] and index of the 100th element is n[9][9].

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays

Question 6.
Write a program to read the 5 marks of a students and display the marks and total. Answer:
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays - 9

Question 7.
Explain different array operations in detail.
Answer:

  1. Traversal:- All the elements of an array is visited and processed is called traversal
  2. Search:- Check whether the given element is present or not
  3. Sorting:-Arranging elements in an order is called sorting.

Question 8.
Given a word “COMPUTER”, write a C++ program to reverse the word without using any string functions.
Answer:
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays - 10

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays

Question 9.
Write statements to declare an array and initialize it with the numbers 1, 2, 3, 4, 5 and print 5, 4, 3, 2, 1.
Answer:
# include
using namespace std;
int main()
int a[5]={1, 2, 3, 4, 5},i;
for(i=4;i>=0;i-)
cout<<a[i]<<“,”;
}

Question 10.
Consider the following array declaration. Write statements to count how many numbers are greater than zero.
int p[ ] = {-5, 6, -7, 0, 8, 9};
Answer:
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays - 11

Question 11.
Write a C++ program to read 10 integer values and find the largest number among them using array.
Answer:
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays - 12

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays

Question 12.
Write a C++ program to accept a string from the keyboard and find its length without using function. For example if “WELCOME” is accepted, the output will be 7.
Answer:
# include
# include
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays - 13

Question 13.
Considerthe following C++ statements

  1. charword[20];
    cin>>word;
    cout<<word;
  2. char word[20];
    gets(word);
    puts(word);

If the string entered is “HAPPY NEW YEAR”. Predict the output in both cases and justify your answers.
Answer:

  1. HAPPY. When we use cin to accept string then space is the delimiter. The string after space is truncated.
  2. HAPPY NEW YEAR. gets() reads all the characters (including space) upto the user presses the enter key.

Question 14.
Consider the following C++ statements
char str[] = “NO/nSMOKING”;
cout<<str;

  1. What is the output of the above code?
  2. How many bytes will be allocated in the memory for the variable str?

Answer:

  1. NO
    SMOKING. The output is in 2 lines.
  2. A total of 11 bytes is used to store this string.

1 byte for \n. 1 byte for \0(The null character that is automatically appended) and 9 bytes for the remaining characters (N, 0, S, M, 0, K, l, N AND G).

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays

Question 15.
Write a C++ program to store the given string in an array and display it in reverse order without using string function. For example if ABCD is given, the output should be DCBA.
Answer:
# include
#include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays - 14

Plus Two Computer Application Arrays Five Mark Questions and Answers

Question 1.
Collect the heights of 12 students from your class in which 7 students are male and others are female students. Suppose these male and female students be seated in two separate benches and you are given a place which is used for sitting these 12 students in linear form. How will you combine and make them sit without mixing male/female students? Write a program for the same.
Answer:
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays - 15

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays - 16

Question 2.
Write a program to read 3 marks of 5 students and find the total and display it
Answer:
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays - 17

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays

Question 3.
Write a program to read a string and a character and find the character by using linear search.
Answer:
# include
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays - 18

Question 4.
Write a program to read a string and find the no. of vowels consonents and special characters.
Answer:
# include
#include
#include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays - 19
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays - 20

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays

Question 5.
Write a program to accept marks of 10 students and find out the largest and smallest mark from the list.

OR

Write a C++ program to store the scores of 10 batsmen of a school cricket team and find the largest and smallest score.
Answer:
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays - 21

Question 6.
Write a C++ program to read 6 marks of a student and find total and average mark.
Answer:
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays - 22

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays

Question 7.
Write a C++ proram to accept a sentence and count the number of times the letter ‘s’ occurs in it. For example if the sentence is This is my school’, the output should be 3.
Answer:
# include
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 2 Arrays - 23

Plus Two Accountancy Chapter Wise Questions and Answers Chapter 6 Data Base Management System for Accounting

Students can Download Chapter 6 Data Base Management System for Accounting Questions and Answers, Plus Two Accountancy Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus Two Chemistry Chapter Wise Questions and Answers Chapter 6 Data Base Management System for Accounting

Plus Two Accountancy Data Base Management System for Accounting One Mark Questions and Answers

Question 1.
DBMS stands for __________
Answer:
Data Base Management system.

Question 2.
Name of database object to hold data
(a) Tables
(b) Forms
(c) Queries
(d) Reports
Answer:
(a) Tables

Question 3.
LibreOffice Base is a
a) Word Processing Software
b) Presentation Software
c) Spread sheet Software
d) Data Base Management Software
Answer:
d) Data Base Management Software

Plus Two Accountancy Chapter Wise Questions and Answers Chapter 6 Data Base Management System for Accounting

Question 4.
The common fields used in a relationship between tables are called
(a) Joint field
(b) Main field
(c) Key field
(d) Table field
Answer:
(c) Key field

Question 5.
The result of Query can be displayed by clicking on ___________
Answer:
Run Button

Question 6.
SQL stands for _______
Answer:
Structural Query Language

Question 7.
______ denotes the number of rows in the table
(a) Tuple
(b) Cardinality
(c) DBMS
(d) Domain
Answer:
(b) Cardinality

Question 8.
A single row in the table is called
(a) Attribute
(b) Tuple
(c) Column
(d) Cardinality
Answer:
(b) Tuple

Plus Two Accountancy Chapter Wise Questions and Answers Chapter 6 Data Base Management System for Accounting

Question 9.
Database in LibreOffice Base is called ________
(a) Data group
(b) Mass Data
(c) Rows and columns
(d) Data Source
Answer:
(d) Data Source

Question 10.
A data base consists of a number of that ______ contains the individual pieces of data
Answer:
fields

Question 11.
A _________ of the database is a group of fields
(a) Table
(b) Forms
(c) Query
(d) None of these
Answer:
(a) Table

Question 12.
The data type suitable to the name of a person
Answer:
Text: [VARCHAR]

Question 13.
The default extension of LibreOffice Base file is
(a) .bmp
(b) .xls
(c) .lob
(d) .odb
Answer:
(d) .odb

Question 14.
Which among the format searches for all values ending with R?
(a) LIKE ‘*R*’
(b) LIKE ‘*R’
(c) LIKE ‘R*’
(d) LIKE ‘END\‘R’
Answer:
(b) LIKE ‘*R’

Plus Two Accountancy Chapter Wise Questions and Answers Chapter 6 Data Base Management System for Accounting

Question 15.
ODBC stands for _______
Answer:
Open Database Connectivity

Question 16.
The data type suitable to the age of an employee is;
Answer:
Number (Numeric)

Question 17.
__________are used to store the data in the database
(a) Reports
(b) Forms
(c) Tables
(d) Queries
Answer:
(c) Tables

Question 18.
________ is a tool to connect tables in a database
(a) Forms
(b) Queries
(c) Relationships
(d) Fields
Answer:
(c) Relationships

Question 19.
Choose the right path to start up LibreOffice Base
(a) Applications → Office → LibreOffice Base
(b) Applications → Create → LibreOffice Base
(c) Applications → Login → Office → LibreOffice Base
(d) Applications → Create → Office → LibreOffice Base
Answer:
(a) Applications → Office → LibreOffice Base

Plus Two Accountancy Chapter Wise Questions and Answers Chapter 6 Data Base Management System for Accounting

Question 20.
LibreOffice Base runs on _____ and _____ operating system
Answer:
Windows and Linux

Question 21.
Which among the following is not an advantage of LibreOffice Base
(a) The information is portable
(b) Ensure Data security
(c) Initial training is required for all users
(d) Many people can access the same database at the same time
Answer:
(c) Initial training is required for all users

Question 22.
Which among the following is not a component of Database system?
(a) Data
(b) Hardware
(c) Software
(d) None of these
Answer:
(d) None of these

Question 23.
RDBMs stands for ____________
Answer:
Relational Data Base Management System

Question 24.
The data type suitable to basic pay of employee:
Answer:
Number (Numeric)

Question 25.
What field type is used to store picture in a table?
Answer:
OLE object.

Question 26.
‘Join Line’ in the context of LibreOffice Base Tables means:
Answer:
Graphical representation of relationship between tables.

Question 27.
Reports are created from
(a) Tables
(b) Forms
(c) Relationships
(d) Tabs
Answer:
(a) Tables

Plus Two Accountancy Chapter Wise Questions and Answers Chapter 6 Data Base Management System for Accounting

Question 28.
Database is referred to as _______________
(a) Front-end program
(b) Back – end program
(c) User-end program
(d) None of these
Answer:
(b) Back – end program

Question 29.
Which among the following is not a DBMS?
(a) Base
(b) Access
(C) Oracle
(d) None of these
Answer:
(d) None of these

Question 30.
Choose the right pairs.
(a) Desktop data base – Single user applications
(b) Desktop data base – Multi user applications
(c) Server data base – Multi user applications
(d) Server data base – Single user applications.
Answer:
(a) & (c)

Question 31.
_______ are the fundamental building blocks fo the database.
(a) Tables
(b) Forms
(c) Queries
(d) Reports
Answer:
(a) Tables

Question 32.
Each column of the table is called …..(a)…… and characteristics of which is called …….(b)…….
Answer:
(a) field
(b) attributes

Question 33.
The format for getting the employees whose names begins with ‘K’ is ______
Answer:
LIKE ‘K*’

Question 34.
To expect a well formatted printable data from LibreOffice Base database, we may use
Answer:
Report

Question 35.
__________ are used for connecting tables in database to get the advantage of data redundancy
(a) Relationships
(b) Primary key
(c) Forms
(d) Tables
Answer:
(a) Relationships

Question 36.
In a database context is a window or screen that contain numerous fields, or spaces to enter data
(a) Tables
(b) Forms
(c) Query
(d) Reports
Answer:
(b) Forms

Plus Two Accountancy Chapter Wise Questions and Answers Chapter 6 Data Base Management System for Accounting

Question 37.
________ section contains the tittle of the report
(a) Field name
(b) Report header
(c) Form Header
(d) Report name
Answer:
(b) Report header

Question 38.
A ________ is a reference to a field in another relation or table
(a) Primary key
(b) Candidate key
(c) Foreign key
(d) Super key
Answer:
(c) Foreign key

Question 39.
The name which indicate the number of columns in the table
(a) Domain
(b) Tuple
(c) Degree
(d) Attribute
Answer:
(c) Degree

Question 40.
The end result of normalisation is known as ___________
Answer:
Refinement

Question 41.
Data type ‘Text’ can store up to characters
(a) 65,535
(b) 255
(c) 35,423
(d) 555
Answer:
(b) 255

Question 42.
Relationship between primary key of one table to primary key of another table is called
(a) One to one
(b) One to many
(c) Many to many
(d) Many to one
Answer:
(a) One to one

Plus Two Accountancy Chapter Wise Questions and Answers Chapter 6 Data Base Management System for Accounting

Question 43.
A query criteria LIKE ‘RAJU*’ returns all names that: LIKE ‘RAJU*’
(a) Contains RAJU
(b) Starts with RAJU
(c) Ends with RAJU
(d) None of these
Answer:
(b) Starts with RAJU

Question 44.
The characteristics of an entity is ________________
Answer:
Attributes

Question 45.
The data type _______ can store upto 65, 535 characters
(a) Text
(b) Number
(c) Memo
(d) Date
Answer:
(c) Memo

Question 46.
Anything which has a real life existence is called ___________
Answer:
Entities

Question 47.
What criteria is used to get return a text starts with ‘A’
Answer:
LIKe ‘A*’

Question 48.
A text data field is used to hold ______ values
(a) Alpha numeric
(b) Numbers only
(c) Alphabets only
(d) Any data
Answer:
(a) Alpha numeric

Plus Two Accountancy Chapter Wise Questions and Answers Chapter 6 Data Base Management System for Accounting

Question 49.
DBMS is an aggregate of data, hardware, software and ______
Answer:
Users

Question 50.
A _______ is a two dimensional array containing rows and columns
Answer:
Table

Plus Two Accountancy Data Base Management System for Accounting Two Mark Questions and Answers

Question 1.
What do you mean by Data base?
Answer:
Database/ Data source – Introduction
A database is a collection of related data. It is organised in such a way that its contents can easily be accessed, managed and updated. In LibreOffice, database is also called data source.

Database consists of interrelated data tables that are structured in a manner that ensures-data consistency and integrity. LibreOffice base, MS Access, Oracle, SQL server, etc. Are the commonly used softwares for data base management.

Question 2.
Define Primary Key.
Answer:
Primary key is a unique key which identify a row in a table. A primary key comprises a single column or set of columns.

Question 3.
What are the different ‘views’ of a form?
Answer:
Form view, Layout view and Design view

Plus Two Accountancy Chapter Wise Questions and Answers Chapter 6 Data Base Management System for Accounting

Question 4.
What are the components of Database system?
Answer:

  • Data
  • Hardware
  • Software
  • Users

Question 5.
What do you mean by Normalisation?
Answer:
Normalisation is the Alteration of tables that reduces data redundancy. Data redundancy means data duplication.

Question 6.
What are the different objects in LibreOffice Base?
Answer:
Tables, Relations, Forms, Queries and Reports.

Question 7.
Write the step for starting up Libre Office Base.
Answer:

  • Step 1 – Click on Applications
  • Step 2 – Select Office
  • Step 3 – Select LibreOffice Base

Path → Application → office → LibreOffice Base

Question 8.
What is an attribute?
Answer:
Attributes: These define the characteristics of an entity. Eg: Name, Age, Caste, Salary etc.

Question 9.
What do you mean by Query?
Answer:
Query:
Query is a question. Queries are used to view, change and analyse data in different ways. It creates a new table from the existing tables based upon the question/ request asked to the data base.

Question 10.
What is Join line?
Answer:
It is the graphical representation of relationship between tables.

Question 11.
What is relationships?
Answer:
These are links between tables.

Plus Two Accountancy Chapter Wise Questions and Answers Chapter 6 Data Base Management System for Accounting

Question 12.
How to run saved Query?
Answer:
Select Queries option from the left panel of the LibreOffice Base window. The saved query can be seen in the right side. Double click on the query name to run the query.

Question 13.
What are the different methods to create Forms in LibreOffice Base?
Answer:

  1. Create Form in Design view
  2. Use wizard to create Form

The second method is the easy way to create Forms in LibreOffice Base

Question 14.
How to close a Database file and Exit from it?
Answer:

  • Step 1 – Click on the File menu
  • Step 2 – Select Close

Then the file will be closed. To exit from the Base file, follow these steps:

  • Step 1 – Click on the File menu
  • Step 2 – Select exit LibreOffice

Question 15.
Give short note on Tables in LibreOffice Base
Answer:
A table is a database object used to store data about a particular subject. A table consists of records and fields, the columns are called fields the and rows are called records.

Question 16.
Write down the character length of the ‘Text’ data type and ‘memo’ data type.
Answer:

  • Text – 225 Characters
  • Memo – 65535 Characters

Plus Two Accountancy Chapter Wise Questions and Answers Chapter 6 Data Base Management System for Accounting

Question 17.
List down the disadvantages of LibreOffice Base
Answer:
Disadvantages of database / Data source:

  1. Designing of database is a complex and time consuming process.
  2. Initial training is required for all the users.
  3. Installation cost is high.

Question 18.
Distinguish between database and database management system
Answer:
Database is a collection of data. It consists of inter-related data tables.
Database management system is a collection of programs that enables users to work on database. DBMS enables the user to create and maintain a database.

Question 19.
Match the following

  1. One to One Relationship – Non Primary Key to Non Primary Key
  2. One to Many Relationship – Primary key to Primary Key
  3. Many to Many Relationship – Non Primary key to Primary Key
  4. Many to One Relationship – Primary key to Non Primary Key

Answer:

  1. One to One Relationship – Primary key to Primary Key
  2. One to Many Relationship – Primary key to Non Primary Key
  3. Many to Many Relationship – Non Primary key to Non Primary Key
  4. Many to One Relationship – Non Primary key to Primary Key

Question 20.
What are the different methods for creating Queries?
Answer:

  • Using the Query Wizard
  • Using Design view

Plus Two Accountancy Data Base Management System for Accounting Four Mark Questions and Answers

Question 1.
List down the advantages of using Database.
Answer:
Advantage of database/ data source:

  1. All of the information is together
  2. The information is portable
  3. Information can be accessed at any time
  4. Many users can access the same database at the same time.
  5. Reduced data entry, storage and retrieval cost.

Question 2.
Explain the importance of Database Management System.
Answer:

  1. It helps to maintain records for ongoing use.
  2. It helps to generate reports based on the database.
  3. Mass volume of data can be managed easily.
  4. It is very useful; if the information stored in the system is subject to many changes.

Plus Two Accountancy Chapter Wise Questions and Answers Chapter 6 Data Base Management System for Accounting

Question 3.
Three options are available in database wizard to create a new database. What are they?
Answer:

  1. Create a new Database.
  2. Open an existing database.
  3. Connect to an existing database.

1.Create a new Database:
This option helps to create a new database with new tables, forms, queries, reports, etc.

2. Open an existing database:
This option helps to open an existing database file which had been created earlier.

3. Connect to an existing database:
This option helps to connect a database which is created on a server.

Question 4.
Distinguish between Desktop Database and Server Database.
Answer:

Desktop DatabaseServer Database
(a) It is single user database.(a) It is multi user database.
(b) It helps to do simple analysis and calculations.(b) It helps to do complex analysis and calculations.
(c) It is less expensive.(c) It is expensive.
(d) It is residing on personal computers.(d) It is residing on server computer.

Question 5.
List down the steps to create a Database in LibreOffice base
Answer:

  • Step 1 – Creation of Blank Database
  • Step 2 – Creation of Tables
  • Step 3 – Creation of Relationships
  • Step 4 – Creation of Forms
  • Step 5 – Creation of Queries
  • Step 6 – Creation of Reports

Question 6.
What are the different Data types commonly used in LibreOffice Base?
Answer:

  1. Text – Used to hold alphanumeric values
  2. Memo- Used to enter long pieces of text
  3. Number – Used to enter Numeric data
  4. Date – Used to enter data information
  5. Time – Used to enter time information

Question 7.
Some query criteria are given below. Write the query format.

  1. Search for all values which contain salary
  2. Search for all values beginning with K
  3. Search for all values ending with P
  4. Searches for all values beginning with Dr
  5. Searches for all values ending with Cr.

Answer:

  1. LIKE ‘*salary*’
  2. LIKE ‘K*’
  3. LIKE ‘*P’
  4. LIKE ‘Dr*’
  5. LIKE ‘*Cr’

Plus Two Accountancy Data Base Management System for Accounting Practical Lab Work Questions and Answers

Question 1.
Create a Table named ‘Tblstudents’ in LibreOffice Base with the following fields. Set the Admn No. as Primary Key
Plus Two Accountancy Chapter Wise Questions and Answers Chapter 6 Data Base Management System for Accounting - 1
procedure:
Step 1 – Open Libre Office Base
Application → Office → LibreOffice Base.

Step 2 – Create a new database
Database wizard → Create a New Database → Next → Yes register the database for me → Open the database for editing Finish.

Step 3 – In Save Dialogue box, give the name STUDENTFEE and select a location to save the database and click Save button.
The new database file STUDENTFEE.odb. is created

Step 4 – Create Data Tables
From the left Database Pane, click on the icon Tables and below the Tasks section, click on ‘Create Table in Design view’
Database Pane → Tables → Create Table in Design view

Plus Two Accountancy Chapter Wise Questions and Answers Chapter 6 Data Base Management System for Accounting

Step 5 – Field Name Entry
In Table creation Screen, Enter the Field names and select appropriate Data Types as given below.

Field NameData Type
Admn No.Number (Numeric)
Name of studentText (VARCHAR)
ClassText (VARCHAR)
Admission dateDate(DATE)
Fee PaidNumber (Numeric)

Step 6 – Setting Primary Key
To set the Admn No. as the Primary key, Right click on the row selector of Admn No. and select the Primary key from the drop down menu

Step 7 – Save Table
Click on Save button (or press Ctrl+S) to save the table. In save as dialogue box, Enter Tblstuderrts as table name and click on OK button Close the table creation screen

Step 8 – Data Entry
Database Pane → Tables → Created Tables → Select Tbl students → Double click to open it

Enter all the data given one by one

Output:
Plus Two Accountancy Chapter Wise Questions and Answers Chapter 6 Data Base Management System for Accounting - 2

Question 2.
Create Two Data Tables named TBLSTUDENT and TBLMARKS in LibreOffice Base with the following fields and show the relationship assuming that the first fields in both tables are set as primary keys

Table – 1
Plus Two Accountancy Chapter Wise Questions and Answers Chapter 6 Data Base Management System for Accounting - 3
Table – 2
Plus Two Accountancy Chapter Wise Questions and Answers Chapter 6 Data Base Management System for Accounting - 4
procedure:
Step 1 – Open LibreOffice Base
Application → Office LibreOffice Base

Step 2 – Create new Database
Datebase wizard → Create a new database Next → Yes, register database for me → Open the data base for editing → click on Finish button

Step 3 – In save Dialogue box, give the name STUDENTFILE and select a location to save the database and click Save button.
The new database file STUDETFILE.odb is created

Step 4 – Create Data Tables
Create Table – 1
From the left Data base pane, click on the Icon Tables and below the Tasks section, click on ‘Create Table in Design view’,
Data base Pane → Tables → Create Table in Design view

Plus Two Accountancy Chapter Wise Questions and Answers Chapter 6 Data Base Management System for Accounting

Step 5 – Field name Entry:
In Table creation screen, Enter the field names and select appropriate Data Types as given below

Field NameData Type
Admn No.Number (Numeric)
NameText (VARCHAR)
ClassText(VARCHAR)

Step 6 – Setting Primary key
To set Admn No as the primary key Right click → Primary key from the drop-down menu

Step 7 – Save Table
Press Ctrl+S on click on save button to save the table. Enter the name TBLSTUDENT → Click OK button.

Step 8 – Repeat the same steps for creating the second Table
Create Table -2

Field nameData Type
Class No.Number (Numeric)
MarkNumber (Numeric)

Set ‘Class No’ as the ‘Primary key’ save the table by naming TBLMARKS. Then close the table creation screen.

Step 9 – Data Entry
Data base Pane → Tables → Created Tables → Select → (Two tables TBLSTUDENT and TBLMARKS one by one) → Double click to open it
Enter all the details one by one.

Step 10 – Create Relationship
(a) Go to the Tools menu, select Relationships. Now Add Table dialogue box will appear. Add both the tables to the relationship window and close the Add Table dialogue box

(b) Create relationship between TBLSTUDENT and TBLMARK. Position the mouse pointer over the primary key of TBLSTUDENT table, hold down the left mouse button, drag the pointer right to the primary key in the TBLMARK table and then release the mouse button.

(c) Click on Save button in relation design window to save the relationship File → Save Click Close button to close the relation design window
Output:
Plus Two Accountancy Chapter Wise Questions and Answers Chapter 6 Data Base Management System for Accounting - 5

Plus Two Accountancy Chapter Wise Questions and Answers Chapter 6 Data Base Management System for Accounting

Question 3.
Create a Form in LibreOffice Base to Manage data in a table named customers with the following details.
Plus Two Accountancy Chapter Wise Questions and Answers Chapter 6 Data Base Management System for Accounting - 6
Step 1 – Open LibreOffice base
Application → Office LibreOffice Base

Step 2 – Create New Database
Database wizard → Create a new database Next → Yes, register database for me Open the database for edting → Click on Finish button

Step 3 – In save dialogue box, give the name CUSTOMERFILE . Select the location to save the database and cfick Save button.
The new database file CUSTOMERFILE.odb is created.

Step 4 – Create Data Tables
From the left database pane, click on the Icon Tables, and below the Tasks section, click on ‘Create Table in Design View’
Database Pane → Tables Create Tables in Design View

Step 5 – Enter necessary field names and select appropriate Data Type. Save the Table in the name TBLCUSTOMER and close the window

Step 6 – Create Form
From the left database pane, click on the Forms button and in right side, under Tasks section, click on Use Wizard to Create a Form.
Now Form wizard window opens
Data base Pane → Forms → Use wizard to create a Form

Step 7 – Selection of fields

  • In Form wizard, select TBLCUSTOMER from the combo box under the head Tables/Queries. → Click on Next button.
  • Add all Fields to Fields in the Form section in the right side by clicking >> button → Next button
  • Setup subform → Next → Arrange controls → Next
  • Set Data entry → Select The form is to display all data → Next → Apply styles → Next
  • Enter the name of the form inset Name Option as FORM CUSTOMER → select work with the Form → Finish

Now the data entry form will be opened

Step 8 – Data Entry in the form
Enter data in each field and Press Enter Key or Tab Key
Output:
Plus Two Accountancy Chapter Wise Questions and Answers Chapter 6 Data Base Management System for Accounting - 7

Question 4.
Enter the following data in a database table
Plus Two Accountancy Chapter Wise Questions and Answers Chapter 6 Data Base Management System for Accounting - 8

  • Display the names of students who scored greater than or equal to 500.
  • Display the name of student whose name begin with ‘S’

Procedure:
Step 1 – Open LibreOffice Base
Application → Office → LibreOffice Base

Step 2 – Create New Database
Datebase wizard → Create New Data base Next Yes, register the database form → Open the database for editing → Finish

Step 3 – In Save dialogue box, give the name STUDENTMARK and select the location to Save the data base and click Save button, the new data base file STUDENTMARK.odb. is created.

Step 4 – Create Data Table
From the left Database Pane, Click on the icon Tables, and below the Tasks section, Click on ‘Create Table in Design view’
Database Pane → Tables → Create Tables in Design view

Step 5 – Filed Name Entry
In Table creation Screen, Enter the Field names and select appropriate Data Types as given below

Step 6 – Setting Primary Key
To set STUDROLL_NO as primary key Right click → Select Primary key from the drop down menu

Plus Two Accountancy Chapter Wise Questions and Answers Chapter 6 Data Base Management System for Accounting

Step 7 – Save Table
Click on Save button or Press Ctrl+S to save the table. In save as dialogue box, Enter TBLSTUDENTDETAILS as the name and dick on OK Button
Close the Table creation screen.

Step 8 – Data Entry
Data base pane → Tables → Created Tables → Select TBLSTUDENTDETAILS → Double click to open it Enter all the data on by one

Step 9 – Create Query

  • From the Data base Pane, Click on Queries button and in the right side under Task section, Click on Create Query in Design view. Now Add Table or Query Window opens.
  • Select the table TBLSTUDENTDETAILS and click Add button, then close the window.
  • In the Query Design window, double click on each Field in Table window to add all the fields to query design grid.

Step 10 – Enter Query Criteria (Question 1)
In Query design Grid, set the Criteria for the query.

  • Enter >=500, in the Criterion row in STUDMARK column.
  • Click on the RUN Query Button or Press F5 to display the result.
  • Save and close the query. File → Save. ‘Save as’ window opens. Give the name Query 1 and click on OK button.

Step 11 – Enter the Query Criteria (Question 2)
In the Query design grid, set the criteria for the query

a) Enter LIKE ‘S*’, in the criterion row in STUDNAME column.
b) Click on the Run Query Button or Press F5 to display the result.
c) Save and close the query.
File → Save. ‘Save as’ window opens. Give the name ‘Query 2’ and click on OK button.
Output – 1
Plus Two Accountancy Chapter Wise Questions and Answers Chapter 6 Data Base Management System for Accounting - 9

Output – 2
Plus Two Accountancy Chapter Wise Questions and Answers Chapter 6 Data Base Management System for Accounting - 10

Question 5.
Enter the following list of employees in Tblemployee and make a report from this table sorted in the order of Designation.
Plus Two Accountancy Chapter Wise Questions and Answers Chapter 6 Data Base Management System for Accounting - 11
Procedure:
Step 1 – Open Libre Office base

Step 2 – Create new database
Database wizard → Create a new database → Next → Yes, register database for me → Open the database for editing → Click on Finish Button.

Step 3 – In save dialogue box, give the name Employee file. Select the location to save the database and click Save button.
Now, the new database file Employeefile.odb is created.

Step 4 – Create data tables
From the left database pane, click on the icon Tables, and below the Tasks section, Click on Create Table in Design View. Database Pane → Tables → Create Tables in design view.

Step 5 – Enter the necessary field names and select appropriate Data Type. Save the Table in the name Tbl employee and close the window.

Step 6 – Create Report
In the left Pane of the data base window, click on the Reports button and in right side, Under Tasks section click on Use Wizard to create a Report. This will open a Report wizard.

Plus Two Accountancy Chapter Wise Questions and Answers Chapter 6 Data Base Management System for Accounting

Step 7 – In Field selection step, under Tables Queries, Select the table Tblemployee. Then Press Add All buttons [>>] to all fields to report. Then click Next button.

Step 8 – Labelling fields (Skip this Step) → Next → Grouping Level (Skip this Step) → Next → In sort Option, Select Designation against sort by, and click Next button.

Step 9 – Choose Layout section, Select Tabular in the layout. → Click Next → In create Report Section → Give the tittle of Report as Report-Designation and select modify I Report Layout → Click Finish button.

Step 10 – Report Design window, click on Page Header area → Insert → Report controls → Label field to insert a Header for the report

Step 11 – Double click on the Label Field inserted and in the property window edit the Label as “Designation List of Employees” and Press Enter.

Step 12 – Click on Execute Report button to view the Report.

Plus One Economics Chapter Wise Questions and Answers Chapter 9 Uses of Statistical Methods

Students can Download Chapter 9 Uses of Statistical Methods Questions and Answers, Plus One Economics Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations

Kerala Plus One Economics Chapter Wise Questions and Answers Chapter 9 Uses of Statistical Methods

Plus One Economics Uses of Statistical Methods One Mark Questions and Answers

Question 1.
An essential part of a project report is
(i) Objectives
(ii) Methodology
(iii) Analysis
(iv) All the above
Answer:
(iv) All the above

Plus One Economics Chapter Wise Questions and Answers Chapter 9 Uses of Statistical Methods

Question 2.
Data collection is covered under which part of a project works?
(i) Statement of the problem
(ii) Methodology
(iii) Analysis
(iv) Conclusion
Answer:
(ii) Methodology

Plus One Economics Uses of Statistical Methods Two Mark Questions and Answers

Question 1.
List the statistical tools you use for the analysis of data collected.
Answer:
The following statistical tools can generally be used for the analysis of data collected

  • Measure of central tendency
  • Standard deviation
  • Coefficient of variation
  • Regression
  • Correlation

Plus One Economics Uses of Statistical Methods Three Mark Questions and Answers

Question 1.
Explain the steps towards making a project report.
Answer:
The following are the steps towards making a project report

  1. Identifying a problem or area of study
  2. Choice of target group
  3. Collection of data
  4. Organization and presentation of data
  5. Analysis and interpretation 0 Conclusion
  6. Bibliography

Plus One Economics Chapter Wise Questions and Answers Chapter 9 Uses of Statistical Methods

Question 2.
Write down the features of a good questionnaire.
Answer:
The features of a gdb questionnaire are mentioned
below.

  1. The questionnaire should not be too long.
  2. The number of questions should be as minimum as possible.
  3. The series of questions should move from general to specific.
  4. The questions should be precise and clear.
  5. The questions should not be ambiguous, to enable the respondents to answer quickly, correctly and clearly.
  6. If possible ask ‘yes’ or ‘no’ questions.
  7. The question should not be a leading question, which gives a clue about how the respondent should answer.
  8. The question should not indicate alternatives to the answer.

Plus One Economics Uses of Statistical Methods Five Mark Questions and Answers

Question 1.
Prepare a questionnaire to study the socio-economic conditions of students in your class.
Answer:
Questionnaire to study the socio-economic conditions

1. Name
2. Sex
3. Age
4. Class
5. The community to which you belong to
6. Details of family members:
Plus One Economics Chapter Wise Questions and Answers Chapter 9 Uses of Statistical Methods img1
7. Monthly income of the family

  • below 1000
  • between 1000 and 5000
  • between 5000 and 10000
  • above 10000

8. Do you live in the
a) rental house b) own house

9. Is your house electrified
a) yes b) no

Plus One Economics Chapter Wise Questions and Answers Chapter 9 Uses of Statistical Methods

10. Do you subscribe to the newspaper at home
a) yes b) no

11. Details of amenities at home:

  • cooking gas
  • television
  • bicycle
  • washing machine
  • motorcar
  • scooter
  • refrigerator
  • others

Plus One Economics Chapter Wise Questions and Answers Chapter 8 Index Numbers

Students can Download Chapter 8 Index Numbers Questions and Answers, Plus One Economics Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations

Kerala Plus One Economics Chapter Wise Questions and Answers Chapter 8 Index Numbers

Plus One Economics Index Numbers One Mark Questions and Answers

Question 1.
Which of the following is known as cost of living index?
(a) Consumers price index
(b) Wholesale price index
(c) Industrial production index
(d) All the above
Answer:
(a) Consumers price index

Question 2.
Index number can be calculated for ……….
(a) Price
(b) Quantity
(c) Volume
(d) All the above
Answer:
(d) All the above

Question 3.
In 2017 the price of oil increased by 30% compared to 2010. Identify the base year and the current year.
Answer:
Base year 2010, Current year 2017

Plus One Economics Chapter Wise Questions and Answers Chapter 8 Index Numbers

Question 4.
Which of the following indicates the changes in general price level?
(a) Consumers price index
(b) Wholesale price index
(c) Industrial production index
(d) All the above
Answer:
(b) Wholesale price index

Question 5.
An index number which accounts for the relative importance of the items is known as
(a) weighted index
(b) simple aggregative index
(c) simple average of relatives
(d) all the above
Answer:
(a) weighted index

Question 6.
In most of the weighted index numbers the weight pertains to
(a) base year
(b) current year
(c) both base and current year
(d) none of these
Answer:
(b) current year

Question 7.
The impact of change in the price of a commodity with little weight in the index will be
(a) small
(b) large
(c) uncertain
(d) none of these
Answer:
(a) small

Question 8.
A consumer price index measures changes in
(a) retail prices
(b) wholesale prices
(c) producers prices
(d) none of these
Answer:
(a) retail prices

Question 9.
The item having the highest weight in consumer price index for industrial workers is
(a) Food
(b) Housing
(c) Clothing
(d) all the above
Answer:
(a) Food

Plus One Economics Chapter Wise Questions and Answers Chapter 8 Index Numbers

Question 10.
In general, inflation is calculated by using
(a) wholesale price index
(b) consumer price index
(c) producers’ price index
Answer:
(a) wholesale price index

Question 11.
What is the other name of the consumer price index?
Answer:
The other name of the consumer price index is price deflator of income.

Question 12.
What is base period?
Answer:
Base period is the reference period with which the current period is compared.

Plus One Economics Index Numbers Two Mark Questions and Answers

Question 1.
Index numbers are very useful in deflating. Explain.
Answer:
Index numbers are very useful in deflating. They are very useful adjusting original data into real values. For example, money wages can be adjusted for price changes to find out the level of real wages.

Question 2.
Write down the uses of the wholesale price index.
Answer:
The wholesale price index number indicates the change in the general price level. The uses of the wholesale price index are noted down below.

  1. With the help of the wholesale price index, we can estimate the future demand and supply situations
  2. It helps in forecasting future prices
  3. It is used to measure the rate of inflation
  4. It can be used to eliminate the effect of change in price on aggregates such as national income, capital formation, etc.

Question 3.
Define index number.
Answer:
An index number is a statistical device for measuring changes in the magnitude of a group of related variables.

Question 4.
Mention the formula of ‘simple aggregative’ method?
Answer:
\(P_{01}=\frac{\sum P_{1}}{\Sigma P_{0}} \times 100\)
Here,
ΣP = Total of current year’s prices of different commodities.
ΣP0 = Total of base year’s prices of different commodites.

Question 5.
Give utility of index numbers.
Answer:

  1. Index numbers simplify the facts
  2. It is helpful to policymakers
  3. It makes comparative study easy
  4. It helps to study the general trend

Question 6.
Write a short note on Sensex.
Answer:
Sensex is the short form of Bombay Stock Exchange Sensitive Index with 1978 – 79 as base. The value of Sensex is with reference to this period. It consists of 30 stocks represented by 13 sectors of the economy. If Sensex rises, it indicates that the market is doing well and investors expect better earnings on their investment.

Plus One Economics Chapter Wise Questions and Answers Chapter 8 Index Numbers

Question 7.
Consumer price indices are of great useful because of various reasons. What are they?
Answer:

  1. They determine the purchasing power of money.
  2. They are helpful in the determination of real wages.
  3. They are helpful in wage negotiations and wage contracts.
  4. They help in deflating income and value series in national accounts.
  5. They help the government in formulation of wage policy, price policy, rent control and making general economic policies.

Plus One Economics Index Numbers Three Mark Questions and Answers

Question 1.
Name some important index number in use.
Answer:
some important index number in use are mentioned below.

  • Consumer price index
  • Wholesale Price Index
  • Industrial production index
  • Producer Price Index
  • Index number of agricultural production

Question 2.
Construct an index number for 1991 taking 1990 as base year.
Plus One Economics Chapter Wise Questions and Answers Chapter 8 Index Numbers img1
Answer:
Plus One Economics Chapter Wise Questions and Answers Chapter 8 Index Numbers img2
It shows when compared to 1990 the general price level in 1991 increased by 20%.

Plus One Economics Chapter Wise Questions and Answers Chapter 8 Index Numbers

Question 3.
Point out the desirable properties of the base year.
Answer:
The desirable properties of base year are:

  • The base year should be a normal year.
  • Extreme values should not be selected as base period.
  • It should not belong to too far in the past.

Plus One Economics Index Numbers Four Mark Questions and Answers

Question 1.
What are the limitations of index numbers?
Answer:
The limitations of index numbers are mentioned below.

  • Index numbers are not fully true.
  • They do not help in international comparison.
  • They are prepared with certain specific objectives.
  • It is difficult to collect retail prices. So, index numbers based on wholesale prices may be misleading.

Question 2.
“Index number is used in economics for policymaking” substantiate.
Answer:
Wholesale price index number (WPI), consumer price index number (CPI) and industrial production index (IIP) are widely used in policymaking.

1. Consumer index number (CPI) or cost of living index numbers are helpful in wage negotiation, formulation of income policy, price policy, rent control, taxation and general economic policy formulation.

2. The wholesale price index (WPI) is used to eliminate the effect of changes in prices on aggregates such as national income, capital formation, etc.

3. WPI is widely used to measure the rate of inflation. Inflation is a general and continuing increase in prices. If inflation becomes sufficiently large, money may lose its traditional function as a medium of exchange and as a unit of account. Its primary impact lies in lowering the value of money.

4. CPI are used in calculating the purchasing power of money and real wage.

5. Index of industrial production gives us a quantitative figure about the change in production in the industrial sector.

6. Agricultural production index provides us a ready reckoner of the performance of agricultural sector.

7. Sensex is a useful guide for investors in the stock market. If the sensex is rising, investors are optimistic of the future performance of the economy. It is an appropriate time for investment.

Plus One Economics Index Numbers Five Mark Questions and Answers

Question 1.
Certain important issues should be kept in mind while constructing an index number”. Do agree? Substantiate your answer.
Answer:
Yes, certain important issues should be kept in mind, while constructing an index number. Those issues are mentioned below

1. You need to be clear about the purpose of the index. The calculation of a volume index will be inappropriate when one needs a value index.

2. Besides this, the items are not equally important for different groups of consumers when a consumer price index is constructed. The rise in petrol price may not directly impact the living condition of the poor agricultural labourers.

Thus the items to be included in any index have to be selected carefully to be as representative as possible. Only
then you will get a meaningful picture of the change.

3. Every index should have a base. This base should be as normal as possible. Extreme values should not be selected as base period. The period should also not belong to too far in the past. The comparison of between 1993 and 2005 is much more meaningful than a comparison between 1960 and 2005.

Many items in a 1960 typical consumption basket have disappeared at present. Therefore, the base year for any index number is routinely updated.

4. Another issue is the choice of the formula, which depends on the nature of question to be studied. The only difference between the Laspeyres index and Paasche’s index is the weights used in these formulae.

5. Besides, there are many sources of data with different degrees of reliability. Data of poor reliability will give misleading results. Hence, due care should betaken in the collection of data. If primary data are not being used, then the most reliable source of secondary data should be chosen.

Plus One Economics Chapter Wise Questions and Answers Chapter 8 Index Numbers

Question 2.
Explain various types of index numbers.
Answer:
Some Important Index Numbers
1. Consumer price index:
Consumer price index (CPI), also known as the cost of living index, measures the average change in retail prices. The CPI for industrial workers is increasingly considered the appropriate indicator of general inflation, which shows the most accurate impact of price rise on the cost of living of common people.

2. Wholesale price index:
The wholesale price index number indicates the change in the general price level. Unlike the CPI, it does not have any reference consumer category. It does not include items pertaining to services like barber charges, repairing, etc.

3. Industrial production index:
The index number of industrial production measures changes in the level of industrial production comprising many industries. It includes the production of the public and the private sector. It is a weighted average of quantity relatives. In India, it is currently calculated every month with 1993 – 94 as the base.

4. Index number of agricultural production:
The index number of agricultural production is a weighted average of quantity relatives. Its base period is the triennium ending 1981 – 82. In 2003 – 04 the index number of agricultural production was 179.5.

It means that agricultural production has increased by 79.5 percent over the average of the three years 1979 – 80, 1980 – 81 and1981 – 82. Foodgrains have a weight of 62.92 percent in this index.

5. Producer Price Index:
The producer price index number measures price changes from the producers’ perspective. It uses only basic prices including taxes, trade margins, and transport costs.

Plus One Economics Chapter Wise Questions and Answers Chapter 7 Correlation

Students can Download Chapter 7 Correlation Questions and Answers, Plus One Economics Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations

Kerala Plus One Economics Chapter Wise Questions and Answers Chapter 7 Correlation

Plus One Economics Correlation One Mark Questions and Answers

Question 1.
Who developed rank correlation co-efficient.
(i) Karl Pearson
(ii) Karl Marx
(iii) Spearman
(iv) None of the above
Answer:
(iii) Spearman

Question 2.
If r= +1, if shows:
(i) Positive correlation
(ii) Perfect positive correlation
(iii) No correlation
(iv) Rank correlation
Answer:
(ii) Perfect positive correlation

Question 3.
If ‘r’ is positive the two variables will more in
(i) Opposite direction
(ii) Inverse direction
(iii) Same direction
(iv) None of the above
Answer:
(iii) Same direction

Plus One Economics Chapter Wise Questions and Answers Chapter 7 Correlation

Question 4.
Which of the following correlation can be used to measure numerically only leniar relationship between two variables?
(i) Karl Pearsons coefficient of correlation
(ii) Spearman correlation
(iii) Rank correlation
(iv) None of the above
Answer:
(i) Karl Pearsons coefficient of correlation

Question 5.
The unit of correlation coefficient between height in feet and weight in kgs is
(i) kg/feet
(ii) percentage
(iii) non-existent
Answer:
(iii) non-existent

Question 6.
The range of simple correlation coefficient is
(i) 0 to infinity
(ii) minus one to plus one
(iii) minus infinity to infinity
Answer:
(ii) minus one to plus one

Question 7.
If rxy is positive the relation between X and Y is of the type.
(i) When Y increases X increases
(ii) When Y decreases X increases
(iii) When Y increases X does not change
Answer:
(i) When Y increases X increases

Question 8.
If rxy = 0 the variable X and Y are
(i) linearly related
(ii) not linearly related
(iii) independent
Answer:
(ii) not linearly related

Question 9.
Of the following three measures which can measure any type of relationship
(i) Karl Pearson’s coefficient of correlation
(ii) Spearman’s rank correlation
(iii) Scatter diagram
Answer:
(iii) Scatter diagram

Question 10.
If precisely measured data are available the simple correlation coefficient is
(i) more accurate than rank correlation coefficient
(ii) less accurate than rank correlation coefficient
(iii) as accurate as the rank correlation coefficient
Answer:
(iii) as accurate as the rank correlation coefficient

Question 11.
Define correlation.
Answer:
Correlation studies and measures the direction and intensity of relationship among variables.

Plus One Economics Chapter Wise Questions and Answers Chapter 7 Correlation

Question 12.
Write the formula for calculating correlation.
Answer:
1. Karl Pearson’s coefficient of correlation
\(r=\frac{\sum x y}{\sqrt{\sum x^{2} \times \sum y^{2}}}\)

2. Spearman’s Rank correlation coefficient
\(R=1-\frac{6 \Sigma D^{2}}{N\left(N^{2}-1\right)}\)

Plus One Economics Correlation Two Mark Questions and Answers

Question 1.
Can r lie outside the -1 and 1 range depending on the type of data?
Answer:
No, r cannot lie outside -1 and 1 range depending on the types of data. It lies between minus one and plus one.

Question 2.
Indicate the kind of relationship between X and Y, if the points of the scatter diagram tend to cluster about.

  1. A straight line sloping upward.
  2. A straight line sloping downward.

Answer:

  1. A straight line sloping upward: it is the case of positive correlation.
  2. A straight line sloping downward: it is the case of negative correlation.

Question 3.
Name the correlation mentioned in the graph.
Plus One Economics Chapter Wise Questions and Answers Chapter 7 Correlation img1
Answer:
(a) Positive correlation
(b) Negative correlation
(c) No correlation
(d) Perfect positive correlation
(e) Perfect negative correlation

Question 4.
Give two examples each for positive and negative correlation.
Answer:
1. Positive Correlation

  • Relation between price and supply
  • Relation between height and weight

2. Negative Correlation

  • Relation between price and demand
  • Sale of woolen garment and day temperature

Plus One Economics Chapter Wise Questions and Answers Chapter 7 Correlation

Question 5.
What are perfect correlations? Give examples.
Answer:
Perfect correlation is that where changes in two related variables are exactly proportional. It is of two types:
a) Positive perfect correlation and
b) Negative perfect correlation
There is perfect positive correlation between the two variables of equal proportional changes are in the same direction. It is expressed as +1. If equal proportional changes are in the reverse direction. Then there is negative perfect correlation and it is described as -1.
Plus One Economics Chapter Wise Questions and Answers Chapter 7 Correlation img2

Question 6.
Show in scatter diagram the following.

  1. Positive correlation
  2. Negative correlation

Answer:
Plus One Economics Chapter Wise Questions and Answers Chapter 7 Correlation img3

Plus One Economics Correlation Three Mark Questions and Answers

Question 1.
Interpret the values for as 1, -1 and 0.
r=1 r = -1 r = 0
Answer:
r as 1 means that there is perfect positive relationship between two variables r as -1 means that there is perfect negative relationship between two variables r as 0 means that there lack correlation between two variables

Question 2.
List some variables where accurate measurement is difficult.
Answer:
The following are some variables where accurate measurement is difficult.

  • Secularism
  • Honesty
  • Beauty
  • Impartiality
  • Patriotism

Question 3.
State the nature of relationship.

  1. sale of woolen garments and the day temperature
  2. amount of rainfall and yield of crop
  3. the colour of dress and intelligence of the lady

Answer:

  1. negative correlation
  2. positive correlation
  3. no correlation

Question 4.
Write down the merits of scatter diagram.
Answer:
Merits of scatter diagram are pointed out below:

  1. It is a very simple method of studying correlation.
  2. Just a glance of the diagram will show the relationship.
  3. It indicates whether the relationship is positive or negative.

Question 5.
Construct a flow chart showing the methods of measuring correlation?
Answer:
Plus One Economics Chapter Wise Questions and Answers Chapter 7 Correlation img4

Question 6.
Illustrate positive correlation and negative correlation.
Answer:
Correlation is commonly classified into negative and positive correlation.
The correlation is said to be positive when the variables move together in the same direction. When the income rises, consumption also rises. When income falls, consumption also falls. For instance, sale of ice-cream and temperature move in the same direction.

The correlation is negative when they move in opposite directions. When the price of apples falls its demand increases. When the prices rise its demand decreases. When you spend more time in studying, chances of your failing decline. These are instances of negative correlation. The variables move in opposite direction.

Question 7.
Calculate the coefficient of correlation from the following data.
Plus One Economics Chapter Wise Questions and Answers Chapter 7 Correlation img5
Answer:
Plus One Economics Chapter Wise Questions and Answers Chapter 7 Correlation img6

Plus One Economics Chapter Wise Questions and Answers Chapter 7 Correlation

Question 8.
The following are the ranks obtained by 10 students in two subjects. Calculate Spearman’s rank correlation.

Rank of StatisticsRank of Economics
12
24
31
45
53
69
77
810
96
108

Answer:
Plus One Economics Chapter Wise Questions and Answers Chapter 7 Correlation img7

Question 9.
Calculate coefficient of correlation using the following data.
Plus One Economics Chapter Wise Questions and Answers Chapter 7 Correlation img8
Answer:
Plus One Economics Chapter Wise Questions and Answers Chapter 7 Correlation img9

Plus One Economics Correlation Five Mark Questions and Answers

Question 1.
What do you mean by Spearman’s rank correlation coefficient? Point out the situations where it is used. Also, bring about its usefulness.
Answer:
Spearman’s rank correlation was developed by the British psychologist C.E. Spearman. It is used when the variables cannot be measured meaningfully as in the case of price, income, weight, etc. The ranking may be more meaningful when the measurements of the variables are suspect.

There are also situations when you are required to quantify qualities such as fairness, honesty, etc. Ranking may be a better alternative to the quantification of qualities. Moreover, sometimes the correlation coefficient between two variables with extreme values may be quite different from the coefficient without the extreme values. Under these circumstances, rank correlation provides a better alternative to simple correlation.

Rank correlation coefficient and simple correlation coefficient have the same interpretation. Its formula has been derived from simple correlation coefficient where individual values have been replaced by ranks. These ranks are used for the calculation of correlation. This coefficient provides a measure of linear association between ranks assigned to these units, not their values. It is the Product Moment Correlation between the ranks.

Plus One Economics Chapter Wise Questions and Answers Chapter 7 Correlation

Question 2.
“Correlation Coefficient has certain essential properties”-substantiate.
Answer:
Correlation Coefficient has certain essential properties as discussed below.
1. r has no unit. It is a pure number. It means units of measurement are not part of r. r between height in feet and weight in kilograms, for instance, is 0.7.

2. A negative value of /-indicates an inverse relation. A change in one variable is associated with change in the other variable in the opposite direction. When price of a commodity rises, its demand falls. When the rate of interest rises the demand for funds also falls. It is because now funds have become costlier.

3. If r is positive the two variables move in the same direction. If/”= 0 the two variables are uncorrelated. There is no linear relation between them. However other types of relationships may be there.

4. If r = 1 or r = -1 the correlation is perfect. The relation between them is exact.

5. A high value of r indicates strong linear relationship. Its value is said to be high when it is close to+1 or-1.

6. A low value of r indicates a weak linear relation. Its value is said to be low when it is dose to zero.

7. The value of the correlation coefficient lies between minus one and plus one, -1 < r < +1. If, in any exercise, the value of r \s outside this range indicates error in calculation.

8. The value of r is unaffected by the change of origin and change of scale. Given two variables X and Y let us define two new variables.

Question 3.
Illustrate the following ideas in scatter diagrams.
i. Positive correlation
ii. Perfect positive correlation
iii. Negative correlation
iv. Perfect negative correlation No correlation
Answer:
Plus One Economics Chapter Wise Questions and Answers Chapter 7 Correlation img10
Plus One Economics Chapter Wise Questions and Answers Chapter 7 Correlation img11
Plus One Economics Chapter Wise Questions and Answers Chapter 7 Correlation img12

Plus One Economics Chapter Wise Questions and Answers Chapter 6 Measures of Dispersion

Students can Download Chapter 6 Measures of Dispersion Questions and Answers, Plus One Economics Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations

Kerala Plus One Economics Chapter Wise Questions and Answers Chapter 6 Measures of Dispersion

Plus One Economics Measures of Dispersion One Mark Questions and Answers

Question 1.
Find out the measure of dispersion from the following.
Answer:
(i) Range
(ii) Mean deviation
(iii) Standard deviation
(iv) All the above
Answer:
(iv) All the above

Question 2.
Variance is equal to:
(i) SD
(ii) SD²
(iii) √SD
(iv) SD/2
Answer:
(ii) SD²

Question 3.
Lorenz curve is used to measure
Answer:
(i) Literacy rate
(ii) Unemployment
(iii) Inequality
(iv) None of these
Answer:
(iii) Inequality

Plus One Economics Chapter Wise Questions and Answers Chapter 6 Measures of Dispersion

Question 4.
Which is the graphical method of determining dispersion?
(i) Range
(ii) Q.D
(iii) S.D
(iv) Lorenz curve
Answer:
(iv) Lorenz curve

Question 5.
Which among the following is not an absolute measure of dispersion?
(i) Range
(ii) Co-efficient of variation
(iii) Mean deviation
(iv) Standard deviation
Answer:
(ii) Co-efficient of variation

Question 6.
Which of the following is the most widely used measure of dispersion?
(i) Range
(ii) Standard deviation
(iii) Mean deviation
(iv) Quartile deviation
Answer:
(ii) Standard deviation

Question 7.
Which of the following is useful in comparing the variability of two or more distributions?
(i) Lorenz Curve
(ii) Standard deviation
(iii) Mean deviation
(iv) Quartile deviation
Answer:
(iii) Mean deviation

Question 8.
Which of the following is not based on all the values?
(i) Mean deviation from mean
(ii) Mean deviation from median.
(iii) Range
(iv) Standard deviation
Answer:
(iii) Range

Question 9.
Mean deviation
(i) is least when calculated from median and higher when calculated from mean.
(ii) is least when calculated from mean and higher when calculated from median.
(iii) same when calculated from median and mean.
(iv) cannot be calculated either from median or mean.
Answer:
(i) is least when calculated from median and higher when calculated from mean.

Plus One Economics Chapter Wise Questions and Answers Chapter 6 Measures of Dispersion

Question 10.
Mention the purpose for which Lorenz Curve is drawn.
Answer:
Lorenz curve is drawn for the presentation of inequality (or dispersion)

Plus One Economics Measures of Dispersion Two Mark Questions and Answers

Question 1.
Which measure of dispersion is the best and how?
Answer:
Standard deviation is the best measure of dispersion. Because it possesses most of the characteristics of an ideal measure of dispersion.

Question 2.
Range is not based on all the values. Do you agree? Substantiate.
Answer:
Yes, I agree with the statement that range is not based on all the values. It is simply the difference between the largest (L) and the smallest value (S) in a distribution. Therefore, range cannot be considered as a good measure of dispersion.

Question 3.
Give two limitations of range.
Answer:
Given below two limitations of range.

  1. range is unduly affected by extreme values
  2. range is not based on all values.

Question 4.
Differentiate between range and interquartile range.
Answer:
Range is the difference between the value of extreme while interquartile range is the difference between quarter extreme values of the series.

Question 5.
Some measures of dispersion depend upon the spread of values whereas some calculate the variation of values from a central value. Do you agree?
Answer:
Yes, I agree with this statement. Range and quartile deviation measure the dispersion by calculating the spread within which the values lie. That is they de-pend.on the spread of values. On the other hand, mean deviation and standard deviation calculate the variation of value from a central value.

Plus One Economics Chapter Wise Questions and Answers Chapter 6 Measures of Dispersion

Question 6.
Write the merits and demerits of mean deviation.
Answer:
1. Merits

  • It is based on all observations
  • It is less affected by extreme items
  • It is easy to calculate & simple to understand

2. Demerits

  • It ignores + signs
  • It is difficult to compute when
  • or median comes infraction.

Plus One Economics Measures of Dispersion Three Mark Questions and Answers

Question 1.
Calculate coefficient of standard deviation from the following information SD = 22.4, Mean = 159
Answer:
Coefficient of standard deviation = \(\frac{\mathrm{SD}}{\bar{x}} \times 100\)
\(=\frac{22.4}{159} \times 100=0.14 \times 100=14\)

Question 2.
Following are certain measures of dispersion. Classify them into absolute measures and relative measures.
{Range, Coefficient of variation, Mean Deviation, Coefficient of Quartile Deviation, coefficient of Range, Standard deviation}
Answer:
Plus One Economics Chapter Wise Questions and Answers Chapter 6 Measures of Dispersion img1

Question 3.
Find odd ones out and justify your answer.

  1. range, quartile deviation, mode, standard deviation
  2. scatter, spread, variation, correlation
  3. Range, Mean Deviation, coefficient of variation, Standard deviation.

Answer:

  1. Mode. Others are methods of studying measures of dispersion.
  2. Correlation. Others are different expressions of dispersion.
  3. Coefficient of variation. Others are absolute measures of dispersion.

Question 4.
Calculate the coefficient of variation, if,
Number of Boys = 72
Average Height = 68
The variance of distribution = 9
Answer:
Plus One Economics Chapter Wise Questions and Answers Chapter 6 Measures of Dispersion img2

Question 5.
Point out features of good measure of dispersion.
Answer:
The features of a good measure of dispersion are pointed out below:

  • It should be easy to understand
  • It should be simple to calculate
  • It should be rigidly defined
  • It should be based on all observations
  • It should not be affected by extreme values

Plus One Economics Chapter Wise Questions and Answers Chapter 6 Measures of Dispersion

Question 6.
The size of landholdings of 5 persons are given below:

IndividualsLand in acres
A1.5
B3.0
C0.5
D6.0
E2.0

 

  1. Analyse the data by measuring the dispersion using the easiest method.
  2. What are the drawbacks of that method?

Answer:
1. Range is the simplest method of studying dispersion.
Range = L – S
where L = Largest item
S = Smallest item
Range = 6 – 0.5 = 5.5 acres
2.

  • It is not based on each and every item of the distribution.
  • It is subject to fluctuations from sample to sample.
  • It cannot be computed in case of open-end classes.

Question 7.
If the sum of 10 values is 100 and the sum of their square is 1090, find the coefficient of variation.
Answer:
Plus One Economics Chapter Wise Questions and Answers Chapter 6 Measures of Dispersion img3

Plus One Economics Measures of Dispersion Four Mark Questions and Answers

Question 1.
In a town, 25% of the persons earned more than Rs 45,000 whereas 75% earned more than 18,000. Calculate the absolute and relative values of dispersion.
Answer:
We get the following information from the above.
Q1 = Rs. 18000 and Q3 = Rs. 45000
Absolute measure of dispersion (quartile deviation)
= Q3 – Q1/2 = 45000 – 18000/2
= Rs. 13500
Relative measure of dispersion (coefficient of Q. D)
= Q3-Q1/Q3 + Q1
= 45000 -18000 / 45000 + 18000
= 27000/63000
= 3/7
= 0.43

Question 2.
What do you mean by dispersion? Name the important methods of measuring dispersion.
Answer:
Dispersion is the extent to which values in a distribution differ from the average of the distribution.
To quantify the extent of the variation, there are certain measures namely:

  1. Range
  2. Quartile Deviation
  3. Mean Deviation
  4. Standard Deviation
  5. Lorenz curve

Question 3.
Mention the merits of standard deviation.
Answer:
Merits of standard deviation are:

  1. It is rigidly defined
  2. It is based on all observations
  3. It takes algebraic signs in consideration
  4. It serves the basis of other measures like correlation.

Question 4.
The number of telephone calls received at an exchange in 245 successive one-minute intervals are shown in the following frequency distribution. Compute the mean deviation about the median.

No. of callsFrequency
014
121
225
343
451
540
639
712

Answer:
Plus One Economics Chapter Wise Questions and Answers Chapter 6 Measures of Dispersion img4

Plus One Economics Chapter Wise Questions and Answers Chapter 6 Measures of Dispersion

Question 5.
The coefficient of variation of two series are 58% and 69% and their standard deviation are 21.2 and 15.6. Calculate their mean.
Answer:
Plus One Economics Chapter Wise Questions and Answers Chapter 6 Measures of Dispersion img5

Question 6.
Calculate the standard deviation.

MarksFrequency
20 – 403
40-806
80-10020
100-12012
120-1409

Answer:
Plus One Economics Chapter Wise Questions and Answers Chapter 6 Measures of Dispersion img6

Plus One Economics Measures of Dispersion Five Mark Questions and Answers

Question 1.
Match the following.

AB
Measures of dispersionKarl Pearson
Standard deviationSD2
Graphical methodSD/mean x 100
VarianceAverage of the second order
Quartile deviationSemi-interquartile range
Coefficient of variationLorenz curve

Answer:

AB
Measures of dispersionAverage of the second order
Standard deviationKarl Pearson
Graphical methodLorenz curve
VarianceSD2
Quartile deviationSemi-inter quartile range
Coefficient of variationSD/mean x 100

Plus One Economics Measures of Dispersion Eight Mark Questions and Answers

Question 1.
What do you mean by Lorenz curve? Give the steps required in the Construction of the Lorenz Curve.
Answer:
The measures of dispersion discussed so far give a numerical value of dispersion. A graphical measure called Lorenz Curve is available for estimating dispersion. In constructing a Lorenz curve, the following steps are involved.

  1. Calculate class mid-points and find cumulative totals
  2. Calculate cumulative frequencies
  3. Express the grand totals and convert the cumulative totals in these columns into percentages,
  4. Now, on the graph paper, take the cumulative percentages of the variable on Y-axis and cumulative percentages of frequencies on X-axis. Thus each axis will have values from ‘0’to ‘100’.
  5. Draw a line joining Co-ordinate (0, 0) with (100,100). This is called the line of equal distribution
  6. Plot the cumulative percentages of the variable with corresponding cumulative percentages of frequency.
  7. Join these points to get the curve OAC.

Plus One Economics Chapter Wise Questions and Answers Chapter 6 Measures of Dispersion

Question 2.
Calculate

  1. standard deviation and
  2. mean deviation

from the following data.
X = 7, 9, 18, 11, 10, 8, 17, 13, 11, 16
Answer:
Plus One Economics Chapter Wise Questions and Answers Chapter 6 Measures of Dispersion img7
1. Standard deviation
\(s=\sqrt{\frac{\sum d^{2}}{N}}\)
\(=\sqrt{\frac{134}{10}}=3.66\)

2. Median deviation
\(M D=\frac{\Sigma|d|}{N}=\frac{32}{10}=3.2\)

Question 3.
The following table gives the distribution of income of 100 families in a village. Calculate standard deviation.

IncomeNo. of Families
0-100018
1000-200026
2000-300030
3000 – 400012
4000 – 500010
5000 – 60004

Answer:
Plus One Economics Chapter Wise Questions and Answers Chapter 6 Measures of Dispersion img8

Question 4.
Write down the formula for finding out various measures of dispersion.
Answer:
Plus One Economics Chapter Wise Questions and Answers Chapter 6 Measures of Dispersion img9
Plus One Economics Chapter Wise Questions and Answers Chapter 6 Measures of Dispersion img10
Plus One Economics Chapter Wise Questions and Answers Chapter 6 Measures of Dispersion img11

Plus One Economics Chapter Wise Questions and Answers Chapter 5 Measures of Central Tendency

Students can Download Chapter 5 Measures of Central Tendency Questions and Answers, Plus One Economics Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations

Kerala Plus One Economics Chapter Wise Questions and Answers Chapter 5 Measures of Central Tendency

Plus One Economics Measures of Central Tendency One Mark Questions and Answers

Question 1.
The midpoint of the class ‘5-10’ is:
(i) 5
(ii) 7.5
(iii) 10
(iv) 15
Answer:
(ii) 7.5

Question 2.
Mode is equal to:
(i) 3 median – 2 mean
(ii) 2 median – 3 mea
(iii) 3 median – 3 mean
(iv) 3 median -1 mean
Answer:
(i) 3 median – 2 mean

Question 3.
Which of the following is a positional average?
(i) Mean
(ii) Median
(iii) Mode
(iv) All the above
Answer:
(ii) Median

Question 4.
Which of the following divides the data into four equal parts?
(i) decile
(ii) percentile
(iii) quartiles
(iv) none of the above
Answer:
(iii) quartiles

Plus One Economics Chapter Wise Questions and Answers Chapter 5 Measures of Central Tendency

Question 5.
Which of the following is the most commonly used average?
(i) Arithmetic Mean
(ii) Median
(iii) Mode
(iv) Percentile
Answer:
(i) Arithmetic Mean

Question 6.
Mode can be graphically located by means of
(i) bio diagram
(ii) pie diagram
(iii) histogram
(iv) ogive
Answer:
(iii) histogram

Question 7.
The most suitable average for qualitative measurement is
(i) Arithmetic mean
(ii) Median
(iii) Mode
(iv) Geometric mean
(v) None of the above
Answer:
(ii) Median

Question 8.
Which average is affected most by the presence of extreme items?
(i) median
(ii) Mode
(iii) Arithmetic mean
(iv) Geometric mean
(v) Harmonic mean
Answer:
(iii) Arithmetic mean

Question 9.
The algebraic sum of deviation of a set of n values from A.M. is
(i) n
(ii) 0
(iii) 1
(iv) None of the above
Answer:
(ii) 0

Question 10.
The average value of a given variable is known as ____
Answer:
A.M

Question 11.
Total of given variables can be depicted by _____
Answer:
Σx

Question 12.
Common factor is depicted by ____
Answer:
‘c’

Plus One Economics Chapter Wise Questions and Answers Chapter 5 Measures of Central Tendency

Question 13.
A.M should be
(i) Simple
(ii) Based on all items
(iii) Rigidly defined
(iv) All the above
Answer:
(iv) All the above

Question 14.
Median is the _____ value in a series.
Answer:
Middle.

Question 15.
Q3 represents ____ Quartile.
Answer:
Middle.

Question 16.
_____ is the division of the series into 100 equal parts.
Answer:
Percentiles.

Question 17.
\(\left(\frac{N+1}{10}\right)^{t h}\) is used to calculate _____.
Answer:
Deciles

Question 18.
Value of median is equal to _____Answer:
Answer:
II Quartile – 50th percentile, 5th Decile

Question 19.
Pick out the odd one out and Justify.
Arithmetic mean, Median, Standard deviation, Mode
Answer:
Standard deviation. Others are measures of central tendency.

Plus One Economics Chapter Wise Questions and Answers Chapter 5 Measures of Central Tendency

Question 20.
Which average would be suitable in the following cases?

  1. Average size of readymade garments.
  2. Average intelligence of students in a class.
  3. Average production in a factory per shift.
  4. Average wages in an industrial concern.
  5. When the sum of absolute deviations from average is least.
  6. When quantities of the variable are in ratios.
  7. In case of open-ended frequency distribution.

Answer:

  1. Mode
  2. Median
  3. Mode or median
  4. Mode or median
  5. Mean
  6. Mode or mean
  7. Median

Plus One Economics Measures of Central Tendency Two Mark Questions and Answers

Question 1.
Name the types of positional averages.
Answer:
Positional averages are median and mode.

Question 2.
Explain weighted Arithmetic mean
Answer:
When calculating Arithmetic means it is important to assign weights to various items according to their importance. The arithmetic mean calculated with the relative importance to different items is known as weighted arithmetic mean.

Question 3.
Give the special features of arithmetic mean.
Answer:
It is interesting to know and useful for checking your calculation that the sum of deviations of items about arithmetic mean is always equal to zero. Symbolically, S (X-X) = 0.However, arithmetic mean is affected by extreme values. Any large value, on either end, can push it up or down.

Question 4.
If median and mean of distribution are respectively 18.8 and 20.2. What would be its made?
Answer:
Mode = 3 Median – 2 Mean
= 3 × 18.8 – 2 × 20.2
= 56.4 – 40.4 = 16

Plus One Economics Chapter Wise Questions and Answers Chapter 5 Measures of Central Tendency

Question 5.
Mention two demerits of median.
Answer:

  1. Median is not based on all observations
  2. It cannot be given for further mathematical treatment

Question 6.
Give the formulae of median in all series
Answer:
Formulae of Median
Plus One Economics Chapter Wise Questions and Answers Chapter 5 Measures of Central Tendency img 1

Question 7.
If median is 15 and mean is 17, calculate mode?
Answer:
Mode = 3 median – 2 mean
= 3 × 15 – 2 × 17
= 45 – 34 = 11

Question 8.
Can there be a situation where mean, median and mode are equal?
Answer:
Yes. Mean, median and mode will be equal when all given variables are the same.

Question 9.
Mark the missing value of the following data. The mean marks are 10.05.
5, 6, 7, 8, 12, ?, 15, 17, 18, 3, 10 5, 10, 12, 15, 11, 13, 1
Answer:
Plus One Economics Chapter Wise Questions and Answers Chapter 5 Measures of Central Tendency img 2

Plus One Economics Measures of Central Tendency Three Mark Questions and Answers

Question 1.
What is the relative position of arithmetic mean, median and mode?
Answer:
Relative position of arithmetic mean, median and mode can be understood from the following narration. Suppose we express,
Arithmetic Mean = Me
Median = Mi
Mode = Mo
The relative magnitude of the three is
Me>Mi>Moor
Me<Mi<Mo
That is the median is always between the arithmetic mean and the mode.

Question 2.
Write down the advantages of median.
Answer:
Merits of median:

  • It is easy to understand
  • It is not affected by extreme values It can be graphically determined
  • It is suitable in case of open-end classes
  • It is suitable for qualitative measurement

Plus One Economics Chapter Wise Questions and Answers Chapter 5 Measures of Central Tendency

Question 3.
Write the merits of mode.
Answer:
Merits of mode

  • It is easy to understand and simple to calculate
  • It is not affected by extreme values
  • It can be graphically determined
  • It is suitable in case of open-end classes.

Question 4.
Complete the following

  1. ………………. divides the series into two equal parts
  2. The central tendency based on all values is …………..
  3. The average which can be determined through ogive is ………

Answer:

  1. median
  2. mean
  3. median

Question 5.
The mean mark of 60 students in section A are 40 and mean mark if 40 student in section B is 35. Calculate the combined mean of all the students.
Answer:
Plus One Economics Chapter Wise Questions and Answers Chapter 5 Measures of Central Tendency img 3

Plus One Economics Measures of Central Tendency Four Mark Questions and Answers

Question 1.
Point out important features of a good average.
Answer:
The important features of a good average are given below.

  1. It should be easy to understand
  2. It should be simple to calculate
  3. It should be rigidly defined
  4. It should be based on all observations
  5. It should not be affected by extreme values.
  6. It should be capable for further statistical calculations.

Question 2.
Following information pertains to the daily income of 150 families. Calculate the arithmetic mean.
Plus One Economics Chapter Wise Questions and Answers Chapter 5 Measures of Central Tendency img 4
Answer:
Plus One Economics Chapter Wise Questions and Answers Chapter 5 Measures of Central Tendency img 5

Plus One Economics Chapter Wise Questions and Answers Chapter 5 Measures of Central Tendency

Question 3.
Calculate the median from the following data.

XF
0-105
10-208
20-3010
30-4014
40-503

Answer:
Plus One Economics Chapter Wise Questions and Answers Chapter 5 Measures of Central Tendency img 6

Plus One Economics Measures of Central Tendency Five Mark Questions and Answers

Question 1.
Comment whether the following statements are true or false.

  1. The sum of deviation of items from median is zero.
  2. An average alone is not enough to compare series.
  3. Arithmetic mean is a positional value.
  4. The upper quartile is the lowest value of top 25% of items.
  5. Median is unduly affected by extreme observations.

Answer:

  1. False
  2. True
  3. False
  4. True
  5. False

Question 2.
There are three types of averages. Name them. Also, give appropriate definitions.
Answer:
There are several statistical measures of central tendency or “averages”. The three most commonly used averages are:

  • Arithmetic Mean
  • Median
  • Mode

1. Arithmetic mean:
Arithmetic mean is the most commonly used measure of central tendency. It is defined as the sum of the values of all observations divided by the number of observations

2. Median:
Median is that positional value of the variable which divides the distribution into two equal parts, one part comprises all values greater than or equal to the median value and the other comprises all values less than or equal to it. The Median is the “middle” element when the data set is arranged in order of the magnitude.

3. Mode:
The word mode has been derived from the French word “la Mode” which signifies the most fashionable values of distribution because it is repeated the highest number of times in the series. Mode is the most frequently observed data value. It is denoted by Mo.

Plus One Economics Chapter Wise Questions and Answers Chapter 5 Measures of Central Tendency

Question 3.
What are the merits and demerits of arithmetic mean?
Answer:
1. Merits

  • It is simple to calculate
  • It is regidly defined
  • It is easy to understand
  • It is based on all observations

2. Demerits

  • It is affected by extreme values.
  • It cannot be calculated in open-end series.
  • It cannot be determined graphically.
  • It may sometimes give misleading results.

Plus One Economics Measures of Central Tendency Eight Mark Questions and Answers

Question 1.
Prepare a list of peculiarities of median, quartiles, and percentiles.
Answer:
1. Median

  • The arithmetic mean is affected by the presence of extreme values in the data.
  • If you take a measure of central tendency which is based on middle position of the data, it is not affected by extreme items.
  • Median is that positional value of the variable which divides the distribution into two equal parts, one part comprises all values greater than or equal to the median value and the other comprises all values less than or equal to it.
  • The Median is the middle element when the data set is arranged in order of the magnitude.

2. Quartiles

  • Quartiles are the measures that divide the data into four equal parts; each portion contains equal number of observations. Thus, there are three quartiles.
  • The first Quartile (denoted by Q1) or lower quartile has 25% of the items of the distribution below it and 75% of the items are greater than it.
  • The second Quartile (denoted by Q2) or median has 50% of items below it and 50% of the observations above it.
  • The third Quartile (denoted by Q3) or upper Quartile has75% of the items of the distribution below it and 25% of the items above it.
  • Thus, Q1 and Q3 denote the two limits within which central 50% of the data lies.

3. Percentiles

  • Percentiles divide the distribution into hundred equal parts, so you can get 99 dividing positions denoted by P1 P2, P3, ………., P99.
  • P50 is the median value.
  • If you have secured 82 percentile in a management entrance examination, it means that your position is below 18 percent of total candidates appeared in the examination.

Plus One Economics Chapter Wise Questions and Answers Chapter 5 Measures of Central Tendency

Question 2.
The daily sales of car of 20 distributing companies is given below. Calculate:

  1. Median, upper quartile and lower quartile.
  2. Interpret the result obtained.

 

Daily SalesNo. of Companies
0-201
20-403
40-609
60-805
80-1002
20

Answer:
1.
Plus One Economics Chapter Wise Questions and Answers Chapter 5 Measures of Central Tendency img 7
Plus One Economics Chapter Wise Questions and Answers Chapter 5 Measures of Central Tendency img 8
Plus One Economics Chapter Wise Questions and Answers Chapter 5 Measures of Central Tendency img 9
2. The median divides the values into two equal parts. Lower quartile (Q1) divides the values into 1/4 and upper quartile (Q3) divides the values into 3/4.

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 9 Small Business

Students can Download Chapter 9 Small Business Questions and Answers, Plus One Business Studies Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examination

Kerala Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 9 Small Business

Plus One Small Business Two Mark Questions and Answers

Question 1.
Define small scale industries.
Answer:
Small scale industry:
A small scale industrial undertaking is defined as one in which the investment in fixed assets of plant and machinery does not exceed rupees one crore.

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 9 Small Business

Question 2.
State the features of cottage industries.
Answer:
Cottage industries:
cottage industries are characterised by certain features:

  1. These are organised by individuals, with private resources.
  2. Normally use family labour and locally available talent.
  3. The equipment used is simple.
  4. Capital investment is small.
  5. Produce simple products, normally in their own premises.
  6. Production of goods using indigenous technology.

Plus One Small Business Three Mark Questions and Answers

Question 1.
Discuss the problems faced by small scale industries. (3)
Answer:
Problems of small business:
Small businesses are faced with the following problems:

  1. Small scale industries find it difficult to get adequate finance from banks and other financial institutions.
  2. They are not able to get quality raw materials at reasonable prices.
  3. Small business is generally operated by people who may not have all the managerial skills required to run the business.
  4. Small business firms cannot afford to pay higher salaries to the employees. So productivity per employee is relatively low and employee turnover is generally high.
  5. Small business depends excessively on middlemen for marketing the products. Middlemen exploit them by paying low price and delayed payments.
  6. Small business organization uses outdated technology to produce products. So they cannot compete with global enterprises with low quality products.
  7. Due to lack of marketing skills or lack of demand, many small business firms have to operate below full capacity.
  8. Use of outdated technology results low productivity and uneconomical production.
  9. Small-scale units find it very difficult to compete .with the product of multinational companies which are comparatively very cheap and of better quality
  10. Other important problems are poor project planning, inefficient management, transportation problems, lack of power, and lack of adequate warehousing, etc.

Plus One Small Business Four Mark Questions and Answers

Question 1.
Write short note on

  1. NSIC
  2. DIC (4)

Answer:
1. National Small Industries Corporation (NSIC):
This was set up in 1955 to promote, aid and foster the growth of small scale units in India.
Functions of NSIC :

  • It supplies imported machines and raw materials to small scale industries on easy hire-purchase schemes.
  • It exports the products of small units.
  • It provides technology to small scale Industries.
  • Helps in up-gradation of technology
  • Provides advisory service
  • Developing software technology parks and technology transfer centres.

2. The District Industries Centers (DICs):
DICs were established in May 1978. District Industries Centers is the institution at the district level which provides all the services and support facilities to the entrepreneurs for setting up small and village industries. Identification of suitable schemes, preparation of feasibility reports, arranging for credit, machinery and equipment, provision of raw materials and other extension services are the main activities undertaken by these centers.

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 9 Small Business

Question 2.
What measures has the government taken to solve the problem of finance and marketing in the small scale sector? (4)
Answer:
Government assistance to small Industries and Small Business:
Institutional Support:
1. National Bank for Agriculture and Rural Development (NABARD):
NABARD was set up in 1982 to promote integrated rural development.
Functions of NABARD:

  • It provides financial support to small Industries, cottage and village industries and agriculture.
  • It provides counseling and consultancy services.
  • It also organises training and development programme for rural entrepreneurs.

2. The Rural Small Business Development Centre (RSBDC):
It aims at providing management and technical support to current and prospective micro and small entrepreneurs in rural areas. RSBDC has organized several programmes on rural entrepreneurship, skill upgradation workshops, training programmes, etc.

3. National small Industries Corporation (NSIC):
This was set up in 1955 to promote, aid and foster the growth of small scale units in India.
Functions of NSIC :

  • It supplies imported machines and raw materials to small scale industries on easy hire-purchase schemes.
  • It exports the products of small units.

4. Small Industries Development Bank of India (SIDBI):
SIDBI was set up in 1980. SIDBI is the main financial Institution for financing and development of small Business in India.
Functions of SIDBI:

  • Helps SSI unit for modernization and technology upgradation by providing loan
  • Meet working capital requirements of SSI.

5. The National Commission for Enterprises in the Unorganised Sector (NCEUS):
The NCEUS was constituted in September, 2004.
The objectives of NCEUS:

  • To recommend measures for improving the productivity of small enterprises
  • To generate more employment opportunities in rural areas

6. Rural and Women Entrepreneurship Development (RWED):
RWE provides the following services:

  • Creating a business environment that encourages initiatives of rural and women entrepreneurs.
  • Enhancing the human and institutional capacities required to foster entrepreneurial dynamism and enhance productivity.
  • Providing training manuals for women entrepreneurs and training them.
  • Rendering all types of advisory services.

7. World Association for Small and Medium Enterprises (WASME):
It is the only International Non-Governmental Organisation of micro, small and medium enterprises based in India, which set up an International Committee for Rural Industrialisation. Its aim is to develop an action plan model for sustained growth of rural enterprises.

There are several schemes to promote the non-farm sector initiated by the Government of India, i.e. IRDP, PMRY, TRYSEM, JRY, Development of Women and Children in Rural Areas (DWCRA) etc.

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 9 Small Business

8. Scheme of Fund for Regeneration of Traditional Industries (SFURTI):
To make the traditional industries more productive and competitive, the Central Government set up a fund with₹100 crores.
The main objectives of the scheme are as follows:

  • To develop clusters of traditional industries in various parts of the country
  • To make traditional industries competitive, profitable and sustainable
  • To create employment opportunities in traditional industries.

9. The District Industries Centers (DICs):
DICs were established in May 1978. District Industries Centers is the institution at the district level which provides all the services and support facilities to the entrepreneurs for setting up small and village industries.

Identification of suitable schemes, preparation of feasibility reports, arranging for credit, machinery and equipment, provision of raw materials and other extension services are the main activities undertaken by these centers.

Plus One Small Business Five Mark Questions and Answers

Question 1.
What are the incentives provided by the Government for industries in backward and hilly areas? (5)
Answer:
Incentives:
The incentives offered by the government to develop backward areas are:

  1. Availability of land at concessional rate.
  2. Supply power at a concessional rate of 50% or exempt such units from payment in the initial years.
  3. Water is supplied on a no-profit, no-loss basis or with 50 percent concession or exemption from water charges for a period of 5 years.
  4. All union territories, industries are exempted from sales tax,
  5. Most states have abolished octroi.
  6. Units located in backward areas get scarce raw materials at concessional rates.
  7. Subsidy of 10-15% for building capital asset. Loans are offered at concessional rates.
  8. Some states encourage setting up of industrial estates in backward areas.
  9. Exemption from paying taxes for 5 or 10 years is given to industries established in backward, hilly and tribal areas.

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 9 Small Business

Question 2.
Small scale industrial sector has an important role in Indian economy. To meet the financial and developmental needs of small business in India a separate bank had been set up. (5)

  1. Give the name of the bank.
  2. What are its major functions?

Answer:
1. SIDBI: Small Industries Development Bank of India (SIDBI). SIDBI was set up in 1980. SIDBI is the main financial Institution for financing and development of small Business in India.

2. Functions of SIDBI:

  • Helps SSI unit for modernisation and technology upgradation by providing loan
  • Meet working capital requirements of SSI.
  • Provides means forthe rehabilitation of sick units
  • Provides service like leasing, hire purchase, venture capital financing etc.
  • Provide equity support to small entrepreneurs.

Plus One Small Business Six Mark Questions and Answers

Question 1.
Describe the role of small business in rural India. (6)
Answer:
Role of small business in Rural India:

  1. Cottage and rural industries provide employment opportunities in the rural areas especially for the traditional artisans and the weaker sections of society.
  2. It prevents migration of rural population to urban areas in search of employment.
  3. Small business helps to eradicate poverty, income inequalities, etc in rural area.
  4. Small scale industries are powerful instrument for the accelerated industrial growth and creating productive employment in rural and backward areas.

Plus One Small Business Eight Mark Questions and Answers

Question 1.
How do small scale industries contribute to the socio-economic development of India? (8)
Answer:
Role of small business in India:

  1. Small industries are labour intensive and less capital intensive. They generate more number of employment opportunities.
  2. The share of product from small industries is 45% of total export from India. So it earn valuable foreign exchange.
  3. Small scale Industries produces a wide variety of goods e.g. readymade garments, stationery, soaps, leather goods, plastic and rubber goods.
  4. The contribution of small industries to the balanced regional development of the country is very significant.
  5. Small industries provide ample opportunity for entrepreneurship.
  6. It enjoys the advantage of low cost of production because they used local resources in their product.
  7. Due to the small size of the organisation, quick and timely decisions can be taken without consulting many people.
  8. Small industries are best suited for the products which are designed according to the taste, needs and preferences of the customers.
  9. Small industries maintain good personal relations with both customers and employees.

Plus Two Maths Chapter Wise Questions and Answers Chapter 13 Probability

Students can Download Chapter 13 Probability Questions and Answers, Plus Two Maths Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus Two Maths Chapter Wise Questions and Answers Chapter 13 Probability

Plus Two Maths Probability Three Mark Questions and Answers

Question 1.
Determine P(E/F). A die is thrown three times, E: ‘4 appears on the third toss’, F: ‘6 and 5 appears respectively on the two tosses’.
Answer:
n(S) = 63 = 216
E = {( 1, 1, 4), (1, 2, 4), (1, 3, 4)……….(1, 6, 4),
(2, 1, 4), (2, 2, 4), (2, 3, 4)……..(2, 6, 4),
(3, 1, 4), (3, 2, 4), (3, 3, 4)……..(3, 6, 4),
(4, 1, 4), (4, 2, 4), (4, 3, 4)…….(4, 6, 4),
(5, 1, 4), (5, 2, 4), (5, 3, 4)……..(5, 6, 4),
(6, 1, 4), (6, 2, 4), (6, 3, 4)……..(6, 6, 4)}
F = {(6, 5, 1), (6, 5, 2), (6, 5, 3), (6, 5, 4), (6, 5, 5), (6, 5, 6)}
⇒ E ∩ F = {(6, 5, 4)}
P(F) = \(\frac{6}{216}\) and P(E ∩ F) = \(\frac{1}{216}\)
Then, P(E/F) = \(\frac{P(E \cap F)}{P(F)}=\frac{\frac{1}{216}}{\frac{6}{216}}=\frac{1}{6}\).

Plus Two Maths Chapter Wise Questions and Answers Chapter 13 Probability

Question 2.
Determine P(E/F). Mother, Father and son lineup at random for a photograph.
E: ‘Son on one end’, F: ‘ Father in middle.
Answer:
Let Mother-M, Father-F and Son-S.
n(S) = 3! = 6
E = {SMF, SFM, MFS, FMS},
F = {MFS, SFM}
⇒ E ∩ F = {SFM, MFS}
P(F) = \(\frac{2}{6}\) = \(\frac{1}{3}\) and P(E ∩ F) = \(\frac{2}{6}\) = \(\frac{1}{3}\)
Then, P(E/F) = \(\frac{P(E \cap F)}{P(F)}=\frac{\frac{1}{3}}{\frac{1}{3}}=1\).

Question 3.
A black and a red dice are rolled

  1. Find the conditional probability of obtaining a sum greater than 9, given that the black die resulted in a 5.
  2. Find the conditional probability of obtaining the sum 8, given that the red die resulted in a number less than 4.

Answer:
We have, n(S) = 36
1. E = Event of 5 on black die.
E = {(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)}
P(E) = \(\frac{6}{36}\) = \(\frac{1}{6}\)
F = Getting a sum greater than 9.
F = {(4, 6), (5, 5), (6, 4)(5, 6), (6, 5), (6, 6)}
⇒ E ∩ F = {(5,5), (5,6)}
P(E ∩ F) = \(\frac{2}{36}\)= \(\frac{1}{18}\)
Therefore the required probability
P(E/F) = \(\frac{P(E \cap F)}{P(F)}=\frac{\frac{1}{18}}{\frac{1}{6}}=\frac{1}{3}\).

2. E = Event of a number less than 4 on red die.
E = {(1, 1), (1, 2), (1, 3), (2, 1), (2, 2), (2, 3),
(3, 1), (3, 2), (3, 3), (3, 1), (3, 2), (3, 3),
(5, 1), (5, 2), (5, 3), (6, 1), (6, 2), (6, 3)}
P(E) = \(\frac{18}{36}\) = \(\frac{1}{2}\)
F = Getting a sum 8.
F = {(4, 4), (5, 3), (3, 5)(2, 6), (6, 2), (6, 6)}
⇒ E ∩ F = {(5, 3),(6, 2)}
P(E ∩ F) = \(\frac{2}{36}\)= \(\frac{1}{18}\)
Therefore the required probability
P(E/F) = \(\frac{P(E \cap F)}{P(E)}=\frac{\frac{1}{18}}{\frac{1}{2}}=\frac{1}{9}\).

Plus Two Maths Chapter Wise Questions and Answers Chapter 13 Probability

Question 4.
An instructor has a question bank consisting of 300 easy True/False questions, 200 difficult true/False questions, 500 easy multiple choice questions, and 400 difficult multiple choice questions. If a question is selected from the test question bank, what is the probability that it will be an easy question given that it is a multiple choice question?
Answer:
Describe the events as follows
E: ‘getting an easy question.’
F: ‘getting a multiple choice question.’
Total Questions = 300 + 200 + 500 + 400 = 1400
n(F) = 500 + 400 = 900, n(E ∩ F) = 500
P(F) = \(\frac{900}{1400}=\frac{9}{14}\), P(E ∩ F) = \(\frac{500}{1400}=\frac{5}{14}\)
Therefore the required probability
= P(E/F) = \(\frac{P(E \cap F)}{P(F)}=\frac{\frac{5}{14}}{\frac{9}{14}}=\frac{5}{9}\).

Question 5.
Two cards are drawn at random without replacement from a pack of 52 playing cards. Find the probability that both the cards are black.
Answer:
Describe the events as follows
B1: ‘getting a black card in the first draw.’
B2: ‘getting a black card in the second draw.’
P(B1) = \(\frac{26}{52}\) = \(\frac{1}{2}\)
When the first event is executed and since no replacement is allowed, the remaining total number of cards become 51 and black cards become 25.
P(B2/B1) = \(\frac{25}{51}\)
Therefore the required probability
P(B1 ∩ B2) = P(Bl) × P(B2/B1) = \(\frac{1}{2} \times \frac{25}{51}=\frac{25}{102}\).

Plus Two Maths Chapter Wise Questions and Answers Chapter 13 Probability

Question 6.
If P(A) = \(\frac{6}{11}\), P(B) = \(\frac{5}{11}\) and P(A ∪ B) = \(\frac{9}{11}\) Find

  1. P(A ∩ B)
  2. P(A/B)
  3. P(B/A)

Answer:
1. P(A ∩ B) = P(A) + P(B) – P(A ∪ B)
Plus Two Maths Probability 3 Mark Questions and Answers 1

2. P(A/B)
Plus Two Maths Probability 3 Mark Questions and Answers 2

3. P(B/A)
Plus Two Maths Probability 3 Mark Questions and Answers 3

Question 7.
Events A and B are such that P(A) = \(\frac{1}{2}\), P(B) = \(\frac{7}{12}\) and P(not A or not B) = \(\frac{1}{4}\) State whether A and B are independent.
Answer:
P(not A or not B) = \(\frac{1}{4}\) ⇒ \(P(\bar{A} \cup \bar{B})=\frac{1}{4}\)
Plus Two Maths Probability 3 Mark Questions and Answers 4
We have, P(A) × P(B) = \(\frac{1}{2} \times \frac{7}{12}=\frac{7}{24}\)
Therefore, P(A ∩ B) ≠ P(A) × P(B)
Hence A and B are not independent.

Plus Two Maths Chapter Wise Questions and Answers Chapter 13 Probability

Question 8.
Consider two events such that P(A) = \(\frac{1}{2}\), P(A ∪ B) = \(\frac{3}{5}\) and P(B) = p. Find p, if A and B are independent events.
Answer:
If A and B are independent then
P(A ∩ B) = P(A) × P(B)
We have,
P(A ∪ B) = P(A) + P(B) – P(A) × P(B)
Plus Two Maths Probability 3 Mark Questions and Answers 5

Question 9.
One card is drawn at random from a well shuffled pack of 52 cards. In which of the following cases are the events E and F independent? (3 scores each)

  1. E: ‘the card drawn is a spades.’
    F: ‘the card drawn is an ace.’
  2. E: ‘the card drawn is a black.’
    F: ‘the card drawn is a king.’
  3. E: ‘the card drawn is a king or a queen.’
    F: ‘the card drawn is queen or a jack.’

Answer:
1. P(E) = \(\frac{13}{52}=\frac{1}{4}\), P(F) = \(\frac{4}{52}=\frac{1}{13}\)
There is only one card which is an ace of spade.
P(E ∩ F) = \(\frac{1}{52}\)
We have,
P(E) × P(F) = \(\frac{1}{4} \times \frac{1}{13}=\frac{1}{52}\) = P(E ∩ F)
Hence E and F are independent events.

2. P(E) = \(\frac{26}{52}=\frac{1}{2}\), P(F) = \(\frac{4}{52}=\frac{1}{13}\)
There are two king of black.
P(E ∩ F) = \(\frac{2}{52}\) = \(\frac{1}{26}\)
We have,
P(E) × P(F) = \(\frac{1}{2} \times \frac{1}{13}=\frac{1}{26}\) = P(E ∩ F)
Hence E and F are independent events.

3. There are 4 king and 4 queen cards
P(E) = \(\frac{8}{52}\) = \(\frac{2}{13}\),
There are 4 queen and 4 jack cards.
P(F) = \(\frac{8}{52}\) = \(\frac{2}{13}\)
There 4 queen common for both.
P(E ∩ F) = \(\frac{4}{52}\) = \(\frac{1}{13}\)
We have,
P(E) × P(F) = \(\frac{2}{13} \times \frac{2}{13}=\frac{4}{169}\) ≠ P(E ∩ F)
Hence E and F are not independent events.

Plus Two Maths Chapter Wise Questions and Answers Chapter 13 Probability

Question 10.
A fair coin and an unbiased die are tossed. Let A be the event ‘head appears on the coin’ and B be the event ‘3 on the die’. Check whether A and B are independent events or not.
Answer:
P(A) = \(\frac{1}{2}\) and P(B) = \(\frac{1}{6}\)
When a coin and die are tossed the sample space will be as follows.
S = {H1, H2, H3, H4, H5, H6, T1, T2, T3, T4, T5, T6}
Here head and 3 come only once.
⇒ P(A ∩ B) = \(\frac{1}{12}\)
P(A) × P(B) = \(\frac{1}{2} \times \frac{1}{6}=\frac{1}{12}\) = P(A ∩ B)
Hence A and B are independent.

Question 11.
Rani and Joy appear in an interview for two vacancies in the same post. The probability of Rani’s selection is \(\frac{1}{7}\) and that of Joy’s selection is \(\frac{1}{5}\) .What is the probability that

  1. Rani will not be selected? (1)
  2. Both of them will be selected? (1)
  3. None of them will be selected? (1)

Answer:
1. Let Rani’s selection be the event A and Joy’s selection be the event B.P(Rani will not be selected)
Plus Two Maths Probability 3 Mark Questions and Answers 6

2. P(Both of them will be selected)
P(A ∩ B) = P(A).P(B) = \(\frac{1}{7} \cdot \frac{1}{5}=\frac{1}{35}\).

3. P(None selected)
Plus Two Maths Probability 3 Mark Questions and Answers 7

Plus Two Maths Chapter Wise Questions and Answers Chapter 13 Probability

Question 12.
Find the probability distribution of number heads in two tosses of a coin.
Answer:
S = {HH, HT, TH, TT}
Let X denotes the random variable of getting a head. Then X can take values 0, 1, 2.
P(X = 0) = P(no heads) = P({TT})
= P(T) × P(T) = \(\frac{1}{2} \times \frac{1}{2}=\frac{1}{4}\)
P(X = 1) = P(one heads)
= P({HT, TH})
= P(H) × P(T) + P(T) × P(H)
= \(\frac{1}{2} \times \frac{1}{2}+\frac{1}{2} \times \frac{1}{2}=\frac{1}{2}\)
P(X = 2) = P(two heads) = P({HH})
= P(H) × P(H) = \(\frac{1}{2} \times \frac{1}{2}=\frac{1}{4}\)
The required Probability Distribution is
Plus Two Maths Probability 3 Mark Questions and Answers 8

Question 13.
Ten eggs are drawn successively with replacement from a lot containing 10% defective eggs. Find the probability that there is at least one defective egg.
Answer:
Let X denotes the random variable of number of defective eggs in the 10 eggs drawn.
Clearly X has a Binomial Distribution with n = 10 and p = 10% = \(\frac{1}{10}\), q = 1 – p = \(\frac{9}{10}\)
⇒ P(X = x) = 10Cxq10-xpx = 10Cx\(\left[\frac{9}{10}\right]^{10-x}\left[\frac{1}{10}\right]^{x}\)
P(at least 1 defective egg) = P(X ≥ 1)
1 – P(X = 0) = 1 – 10C0\(\left[\frac{9}{10}\right]^{10}=1-\frac{9^{10}}{10^{10}}\).

Plus Two Maths Probability Four Mark Questions and Answers

Question 1.
In a hostel 50 % of the girls like tea, 40 % like coffee and 20% like both tea and coffee. A girl is selected and random.

  1. Find the probability that she likes neither tea nor coffee. (2)
  2. If the girl likes tea, then find the probability that she likes coffee. (1)
  3. If she likes coffee then find the probability she likes tea. (1)

Answer:
Let T denotes the set of girls who like tea and C denotes who like coffee.
1. P(T) = 50% = \(\frac{1}{2}\); P(C) = 40% = \(\frac{2}{5}\);
P(T ∩ C) = 20% = \(\frac{1}{5}\)
P(T ∪ C) = 1 – P(T ∪ C)
= 1 – {P(T) + P(C)-P(T ∩ C)}
\(=1-\left\{\frac{1}{2}+\frac{2}{5}-\frac{1}{5}\right\}=\frac{3}{10}\).

2.
Plus Two Maths Probability 3 Mark Questions and Answers 9

3.
Plus Two Maths Probability 3 Mark Questions and Answers 10

Plus Two Maths Chapter Wise Questions and Answers Chapter 13 Probability

Question 2.
A box of oranges is inspected by examining three randomly selected oranges drawn without replacement. If all the three oranges are good, the box is approved for sale, otherwise, it is rejected. Find the probability that a box containing 15 oranges out of which 12 are good and 3 are bad ones will be approved for sale.
Answer:
For the box to be approved all the three oranges should be selected from the 12 good ones. Since the events are executed without replacement the number for good oranges and total oranges reduce by one on each draw.
O1: ‘getting a good orange in the first draw.’
O2: ‘getting a good orange in the second draw.’
O3: ‘getting a good orange in the third draw.’
P(good orange in the first draw) =P(O1)= \(\frac{12}{15}\) = \(\frac{4}{5}\),
P(good orange in the second) = p(O2/O1) = \(\frac{11}{14}\),
P(good orange in the third)
= P(O3/(O1 ∩ O2)) = \(\frac{10}{13}\)
Therefore the required probability
= P(O1 ∩ O2 ∩ O3)
= P(O1)P(O2/O1)P(O3/(O1 ∩ O2))
\(=\frac{4}{5} \times \frac{11}{14} \times \frac{10}{13}=\frac{44}{91}\).

Question 3.
Let two independent events A and B such that P(A) = 0.3, P(B) = 0.6. Find

  1. P(A and B)
  2. P(A and not B)
  3. P(A or B)
  4. P (neither A nor B)

Answer:
1. P(A and B) = P(A ∩ B) = P(A) × P(B)
= 0.3 × 0.6 = 0.18.

2. P(A and not B) = P(A ∩ \(\bar{B}\)) = P(A) × P(\(\bar{B}\))
= 0.3 × 0.4 = 0.12.

3. P(A or B) = P(A ∪ B)
= P(A) + P(B) – P(A ∩ B)
= P(A) + P(B) – P(A) × P(B)
= 0.3 + 0.6 – 0.3 × 0.6 = 0.72.

4. P(neither A nor B) = \(P(\bar{A} \cap \bar{B})\)
= P(\(\bar{A}\)) × P(\(\bar{B}\)) = 0.7 × 0.4 = 0.28.

Plus Two Maths Chapter Wise Questions and Answers Chapter 13 Probability

Question 4.
Two balls are drawn at random with replacement from a box containing 10 black and 8 red balls. Find the probability that

  1. both balls are red.
  2. the first ball is a black and the second is red
  3. one of them is black and the other red.

Answer:
Describe the events as follows.
Black-B and Red-R.n(S) = 18,
P(B) = \(\frac{10}{18}\) = \(\frac{5}{9}\) and P(R) = \(\frac{8}{18}\) = \(\frac{4}{9}\)
Since the event is executed with replacement, is independent.
1. P( both ball is red) = P(R) × P(R)
= \(\frac{4}{9} \times \frac{4}{9}=\frac{16}{81}\).

2. P( first black and second red) = P(B) × P(R)
= \(\frac{5}{9} \times \frac{4}{9}=\frac{20}{81}\).

3. P( one of them is a black and the other red)
= P(B) × P(R) + P(R) × P(B)
\(=\frac{5}{9} \times \frac{4}{9}+\frac{4}{9} \times \frac{5}{9}=\frac{40}{81}\).

Question 5.
Bag 1 contains 3 red and 4 black balls while another Bag II contains 5 red and 6 black balls. One ball is drawn at random from one of the Bags and it is found to be red. Find the probability that it was from Bag II.
Answer:
Describe the events as follows.
A: ‘getting a defective ball’.
E1: ‘choosing Bag I.’
E2: ‘choosing Bag II.’
P(E1) = P(E2) = \(\frac{1}{2}\)
P(A/E1) = P (drawing a red ball from Bag I) = \(\frac{3}{7}\)
P(A/E2) = P (drawing a red ball from Bag II) = \(\frac{5}{11}\)
P (a ball from Bag II, being given that it is red)
Plus Two Maths Probability 4 Mark Questions and Answers 11

Plus Two Maths Chapter Wise Questions and Answers Chapter 13 Probability

Question 6.
A Bag contains 4 red and 4 black balls, another bag contains 2 red and 6 black balls. One ball of the two Bag is drawn at random and the ball is drawn the Bag is found to be red. Find the probability that the ball is drawn from first Bag.
Answer:
Describe the events as follows.
A: ‘getting a red ball’.
E1: ‘choosing Bag I.’
E2: ‘choosing Bag II.’
P(E1) = P(E2) = \(\frac{1}{2}\)
P(A/E1) = P (a red ball from Bag I) = \(\frac{4}{8}\) = \(\frac{1}{2}\)
P(A/E2) = P (a red ball from Bag II) = \(\frac{2}{8}\) = \(\frac{1}{4}\)
P (a ball from Bag II, being given that it is red)
Plus Two Maths Probability 4 Mark Questions and Answers 12

Question 7.
In a factory which manufactures blots, machines A, B, and C manufacture respectively 25%, 35%and 40% of the bolts. Of their outputs 5%, 4% and 2%are defective bolts. A bolt is drawn at random from the product and is found to be defective. What is the probability that it is manufactured by the machine B?
Answer:
Describe the events as follows.
A: ‘getting a defective bolt’.
E1: ‘choosing machine A.’
E2: ‘choosing machine B.’
E3: ‘choosing machine C.’
P(E1) = 0.25, P(E2) = 0.35, P(E3) = 0.4
P(A/E1) = P
(a defective bolt from machine A)
= 5% = 0.05
P(A/E2) = P
(a defective bolt from machine B)
= 4% = 0.04
P(A/E3) = P
(a defective bolt from machine C)
= 2% = 0.02
P (a bolt from machine B, being given that it is defective)
= P(E2/A)
Plus Two Maths Probability 4 Mark Questions and Answers 13

Plus Two Maths Chapter Wise Questions and Answers Chapter 13 Probability

Question 8.
Suppose 5% of men and 0.25% of women have hair grey hair. A grey haired person is selected at random. What is the probability of this person being male? Assume there are equal number males and females.
Answer:
Describe the events as follows.
A: ‘person is grey haired’.
E1: ‘choosing man.’
E2: ‘choosing woman.’
P(E1) = P(E2) = \(\frac{1}{2}\)
P(A/E1) = P (a grey haired person from men)
= 5% = 0.05
P(A/E2) = P (a grey haired person from women) = 0.25% = 0.0025
P(selecting a male, being given that it is grey haired)
Plus Two Maths Probability 4 Mark Questions and Answers 14

Question 9.
An Insurance company insured 2000 scooter drivers, 4000 car drivers, and 6000 truck drivers. The probabilities of an accident are .01, 0.03 and 0.15 respectively. One of the insured persons meets with an accident. What is the probability that he is a scooter driver?
Answer:
Describe the events as follows.
A: ‘accident happens’.
E1: ‘choosing Scooter driver.’
E2: ‘choosing Car driver.’
E3: ‘choosing Truck driver.’
Total drivers = 2000 + 4000 + 6000 = 12000
Plus Two Maths Probability 4 Mark Questions and Answers 15
P(A/E1) = P
(accident of a Scooter driver) = 0.01
P(A/E2) = P
(accident of a Car driver) = 0.03
P(A/E3) = P
(accident of a Truck driver) = 0.15
P (accident happens, given that it is a Scooter driver).
= P(E1/A)
Plus Two Maths Probability 4 Mark Questions and Answers 16

Plus Two Maths Chapter Wise Questions and Answers Chapter 13 Probability

Question 10.
A factory has two machines A and B. Past record shows that machine A produced 60% of the items of output and machine B produced 40% of the items. Further, 2% of the items produced by machine A and 1% produced by machine B were defective. All the items are put into one stockpile and then one item is chosen at random from this and is found to be defective. What is the probability that it was produced by machine B?
Answer:
Describe the events as follows.
A: ‘getting a defective item.’
E1: ‘choosing machine A.’
E2: ‘choosing machine B.’
P(E1) = 60% = 0.6, P(E2) = 40% = 0.4
P(A/E1) = P (a defective from machine A) = 2% = 0.02
P(A/E2) = P (a defective from machine B) = 1% = 0.01
P (a defective from machine B)
Plus Two Maths Probability 4 Mark Questions and Answers 17

Question 11.
Suppose a girl throws a die. If she gets a 5 or 6, she tosses a coin three times and notes the number of heads. If she gets 1, 2, 3 or 4 she tosses a coin once and notes whether a head or tail is obtained. If she obtained exactly one head, what is the probability that she threw 1, 2, 3 or 4 with the die?
Answer:
Describe the events as follows.
A: ‘getting exactly one head.’
E1: ‘she getting 5 or 6.’
E2: ‘she getting 1, 2, 3 or 4.’
When a die is thrown the sample space is{1, 2, 3, 4, 5, 6}
P(E1) = \(\frac{2}{6}\) = \(\frac{1}{3}\), P(E2) = \(\frac{4}{6}\) = \(\frac{2}{3}\)
When she gets 5 or 6, throws a coin 3 times. Then sample space is {HHH, HHT, HTH, THH, TTH, THT, HTT, TTT}
P(A/E1) = P (one head given that 5 or 6 happened)
\(\frac{3}{8}\)
When she gets 1, 2, 3 or 4, throws a coin once. Then sample space is {H, T}
P(A/E2) = P
(one head given that 1, 2, 3 or 4 happened)
\(\frac{1}{2}\)
P (She gets exactly one head threw 1, 2, 3 or 4)
Plus Two Maths Probability 4 Mark Questions and Answers 18

Plus Two Maths Chapter Wise Questions and Answers Chapter 13 Probability

Question 12.
Vineetha and Reshma are competing for the post of school leader. The probability Vineetha to be elected is 0.6 and that of Reshma is 0.4 Further if Vineetha is elected the probability of introducing a new pattern of election is 0.7 and the corresponding probability is 0.3 if Resma is elected. Find the probability that the new pattern of election is introduced by Reshma.
Answer:
Let E1 and E2 be the respectively probability that Vineetha and Reshma will be elected. Let Abe the probability that a new pattern of election is introduced.
P(E1) = 0.6; P(E2) = 0.4
P(A|E1) = 0.7; P(A|E2) = 0.3
Plus Two Maths Probability 4 Mark Questions and Answers 19

Question 13.
Find the probability of number of doublets in three throws of a pair of dice.
Answer:
Let X denotes the random variable of getting a Doublet. Possible doublets are (1, 1),(2, 2),(3, 3),(4, 4),(5, 5),(6, 6).
Then X can take values 0, 1, 2, 3.
P(getting a doublet) = \(\frac{6}{36}\) = \(\frac{1}{6}\)
P(not getting a doublet) = \(\frac{30}{36}\) = \(\frac{5}{6}\)
P(X = 0) = P(no doublet) = \(\frac{5}{6} \times \frac{5}{6} \times \frac{5}{6}=\frac{125}{216}\)
P(X = 1) = P(one doublet and 2 non-doublets)
Plus Two Maths Probability 4 Mark Questions and Answers 20
P(X = 2) = P(2 doublet and 1 non-doublets)
Plus Two Maths Probability 4 Mark Questions and Answers 21
P(X = 3) = P(3 doublet) = \(\frac{1}{6} \times \frac{1}{6} \times \frac{1}{6}=\frac{1}{216}\)
The required Probability Distribution is
Plus Two Maths Probability 4 Mark Questions and Answers 22

Plus Two Maths Chapter Wise Questions and Answers Chapter 13 Probability

Question 14.
Find the probability distribution of the number of white balls drawn when three balls are drawn one by one without replacement from a bag containing 4 white and 6 red balls.
Answer:
Let X denotes the random variable of number of white balls. Clearly X can take values 0, 1, 2, 3. Describe the events as follows.
W: ‘getting white ball.’
R: ‘getting red ball.’
P(X=0) = P(no white balls)
= P(RRR)= \(\frac{6}{10} \times \frac{5}{9} \times \frac{4}{8}=\frac{5}{30}\)
P(X=1) = P(1white, 2red balls)
= P(WRR) + P(RWR) + P(RRW)
Plus Two Maths Probability 4 Mark Questions and Answers 23
P(X=2) = P(2white, 1 red balls)
= P(WWR) + P(RWW) + P(WRW)
Plus Two Maths Probability 4 Mark Questions and Answers 24
P(X=3) = P(3white)
P(WWW) = \(\frac{4}{10} \times \frac{3}{9} \times \frac{2}{8}=\frac{1}{30}\)
The required Probability Distribution is
Plus Two Maths Probability 4 Mark Questions and Answers 25

Question 15.
Two dice are thrown simultaneously. If X denotes the number of sixes, find expectation of X. Also find the variance.
Answer:
Let X denotes the random variable of getting a 6. Clearly X can take values 0, 1, 2.
P(X = 0) = P(non-six, non-six) = \(\frac{5}{6} \times \frac{5}{6}=\frac{25}{36}\)
P(X = 1) = P((six, non-six),(non-six, six))
Plus Two Maths Probability 4 Mark Questions and Answers 26
P(X = 2) = P(six, six) = \(\frac{1}{6} \times \frac{1}{6}=\frac{1}{36}\)
The required Probability Distribution is
Plus Two Maths Probability 4 Mark Questions and Answers 27
Variance = σ2 = E(X2) – [E(X)]2
Plus Two Maths Probability 4 Mark Questions and Answers 28

Plus Two Maths Chapter Wise Questions and Answers Chapter 13 Probability

Question 16.
A random variable X has the following probability distribution
Plus Two Maths Probability 4 Mark Questions and Answers 29
Determine

  1. k
  2. P(X < 3)
  3. P(X > 6)
  4. P(0 < X < 3)

Answer:
1. We know that sum of the probabilities is = 1
0 + k + 2k + 2k + 3k + k2 + 2k2 + 7k2 + k = 1
10k2 + 9k – 1 = 0
(k + 1)(10k – 1) = 0; k= -1 or k = \(\frac{1}{10}\)
(negative value cannot be accepted).

2. P(X < 3) = P(0) + P( 1) + P(2)
0 + k + 2k + 2k = 3k = \(\frac{3}{10}\).

3. P(X < 3) = P(7) = 7k2 + k
Plus Two Maths Probability 4 Mark Questions and Answers 30

4. P(0 < X < 3) = P(1) + P(2) = k + 2k = 3k = \(\frac{3}{10}\). Question

Question 17.
(i) P(A) = \(\frac{7}{13}\); P(B) = \(\frac{9}{13}\); (A ∩ B) = \(\frac{4}{13}\), then P(A/B) is
(a)  \(\frac{9}{4}\)
(b)  \(\frac{16}{13}\)
(c)  \(\frac{4}{9}\)
(d)  \(\frac{11}{13}\)
(ii) Probability of solving a specific problem independently by A and B are \(\frac{1}{2}\) and \(\frac{1}{3}\) respectively. If both try to solve the problem independently, then
(a) Find the probability that the problem is solved. (2)
(b) Find the probability that exactly one of them solve the problem. (1)
Answer:
(i) (c) \(\frac{4}{9}\)

(ii)
Plus Two Maths Probability 4 Mark Questions and Answers 31
P(Problem is solved)
= P(A ∪ B) = P(A) + P(B) – P(A ∩ B)
Plus Two Maths Probability 4 Mark Questions and Answers 32

(iii) P(Exactly one of them solve)
Plus Two Maths Probability 4 Mark Questions and Answers 33

Plus Two Maths Probability Six Mark Questions and Answers Question

Question 1.
(i) A and B are two events such that P(A) = \(\frac{1}{5}\) and P(A ∪ B) = \(\frac{2}{5}\) Find P(B) if they are mutually exclusive
(a) \(\frac{1}{5}\)
(b) \(\frac{2}{5}\)
(c) \(\frac{3}{5}\)
(d) \(\frac{4}{5}\)
(ii) A box contains 3 red and 4 blue balls. Two balls are drawn one by one without replacement. Find the probability of getting both balls red.
(iii) Three cards are drawn successively without replacement from a pack of 52 cards. What is the probability that first two cards are queen and the third is king.
Answer:
(i) (a) \(\frac{1}{5}\).

(ii) Let A be the event that the first ball drawn is red and B be the event of drawing red ball in the second draw
P(A) = \(\frac{3}{7}\)
Probability of getting one red ball in the second draw = P(B/A) = \(\frac{2}{6}\) = \(\frac{1}{3}\). P(A ∩ B) = P(A).P(B/A)
\(=\frac{3}{7} \times \frac{1}{3}=\frac{1}{7}\).

(iii) Let Q denote the event that the card drawn is Queen and K denote the event of drawing a King
P(Q) = \(\frac{4}{52}\), P(Q/Q) = \(\frac{3}{51}\)
P(K/QQ) is the probability of drawing the third card is a king
P(K/QQ) = \(\frac{4}{50}\)
P(QQk) = P(Q)P(Q/Q)P(K/QQ)
\(=\frac{4}{52} \cdot \frac{3}{51} \cdot \frac{4}{50}=\frac{2}{5525}\).

Plus Two Maths Chapter Wise Questions and Answers Chapter 13 Probability

Question 2.
60 shirts of different colours are on sale. If one shirt is chosen at random.
Plus Two Maths Probability 4 Mark Questions and Answers 34

  1. What is the probability that it is red? (1)
  2. What is the probability that it is plain and extra-large? (1)
  3. What is the probability that it is small, given that it is blue? (2)
  4. If A is the event ‘the shirt is medium’ and B is the event ‘the shirt is blue’. Are the events A and B independent? (2)

Answer:
1. P(Red) = \(\frac{8+8+2+4}{60}=\frac{11}{30}\).

2. P (Plain and extra-large) = \(\frac{4+5}{60}=\frac{3}{20}\).

3. P(small/blue)
Plus Two Maths Probability 4 Mark Questions and Answers 35

4.
Plus Two Maths Probability 4 Mark Questions and Answers 36
∴ Not independent.

Question 3.
From a box containing balls numbered from, 1 to 100, one ball is drawn at random. The events X and Y are as follows. X: A perfect square is drawn. Y: An even number is drawn.

  1. Find P(X) and P(Y). (2)
  2. Compute P (X/Y). (2)
  3. Are X and V independent? Justify. (2)

Answer:
Perfect square numbered balls are
1, 4, 9, 16, 25, 36, 49, 64, 81, 100.
Therefore, there are 10 perfect square numbered balls, 50 even numbered balls and 5 perfect square even numbered balls.
1. P(X) = \(\frac{10}{100}=\frac{1}{10}\), P(Y) = \(\frac{50}{100}=\frac{1}{2}\)
P (Even perfect square number) = P (X ∩ Y) \(\frac{50}{100}=\frac{1}{20}\).

2. P(X/Y)
= P(Drawing a perfect square numbers from even numbers) = \(\frac{5}{50}=\frac{1}{10}\).

3. We have, P (X ∩ Y) = \(\frac{1}{20}=\frac{1}{10} \times \frac{1}{2}\)
= P(X).P(Y).
Therefore X and Y are independent events.

Plus Two Maths Chapter Wise Questions and Answers Chapter 13 Probability

Question 4.
(i) The probability of three mutually exclusive events A, B, and C are given by 2/3, 1/4, 1/6 respectively. Is this statement ________ (1)
(a) true?
(b) false?
(c) cannot be said?
(d) data not sufficient?
A husband and wife appear in an interview for two vacancies in the same post. The probability of husband’s selection is 1/7 and that of wife’s selection is 1/5. What is the probability that
(ii) Only one of them will be selected? (3)
(iii) None will be selected? (2)
Answer:
(i) (b) Probability should be less than or equal to 1.
Here A, B, C are mutually exclusive.
Then,
P(A ∪ B ∪ C) = P(A) + P(B) + P(C) = \(\frac{2}{3}+\frac{1}{4}+\frac{1}{6}=\frac{26}{24}>1\)
∴ statement is false.

(ii) H – Event of husband selected,
W – Event of wife selected
Plus Two Maths Probability 4 Mark Questions and Answers 37

(iii) P (None of them will be selected)
Plus Two Maths Probability 4 Mark Questions and Answers 38

Question 5.
(i) Find P(A∩B) if A and B are independent events with P(A) = \(\frac{1}{5}\) and P(B) = \(\frac{5}{8}\)
Plus Two Maths Probability 4 Mark Questions and Answers 39
(ii) An unbiased die is thrown twice. Let the event A be getting prime number in the first throw and B be the event of getting an even number in the second throw. Check the independence of the events A and B. (3)
(iii) The probability of solving a problem independently by A and B are \(\frac{1}{3}\) and \(\frac{1}{4}\) respectively. Find the probability that exactly one of them solves the problem. (2)
Answer:
(i) (c) \(\frac{1}{8}\).

(ii) P(A) = \(\frac{18}{36}\) = \(\frac{1}{2}\)
P(B) = \(\frac{18}{36}\) = \(\frac{1}{2}\)
P(A∩B) = P( prime number in first throw and even number in the second throw)
Plus Two Maths Probability 4 Mark Questions and Answers 40
∴ A and B are independent events.

(iii)
Plus Two Maths Probability 4 Mark Questions and Answers 41
Probability of exactly one of them solves the problem = P(A)P(B’) + P(B)P(A’)
Plus Two Maths Probability 4 Mark Questions and Answers 42

Plus Two Maths Chapter Wise Questions and Answers Chapter 13 Probability

Question 6.
(i) A set of events E1 + E2,…….En are said to be a partition of the Sample Space, then which of the following conditions is always not true (1)
(a) E1∪ E2 ∪……..∪ En = S,
(b) E1 ∩ En = Φ,
(c) P(E1) > 0,
(d) P(E1) ≥ P(En)
(ii) A person has undertaken a business. The probabilities are 0.80 that there will be a crisis, 0.85 that the business will be completed on time if there is no crisis and 0.35 that the business will be completed on time if there is a crisis. Determine the probability that the business will be completed on time. (2)
(iii) A box contains 5 red and 10 black balls. A ball is drawn at random, its colour is noted and is returned to the box. More over 2 additional balls of the colour drawn are put in the box and then a ball is drawn. What is the probability that the second ball is red? (3)
Answer:
(i) P(E1) ≥ P(En).

(ii) Let A be the event that the business will be completed on time and B be the event that there will be a crisis
P(B) = 0.80
P(no crisis) = P(B’) = 1 – P(B) = 0.20
P(A/B) = 0.35 P(A/B’) = 0.85
By theorem on total probability
P(A) = P(B)P(A/B) + P(B’)P(A/B’)
= 0.8 × 0.35 + 0.2 × 0.85 = 0.45.

(iii) Let a red ball be drawn in the first attempt P(drawing a red ball) = \(\frac{5}{15}=\frac{1}{3}\)
If two red balls are added to the box, then the box contains 7 red balls and 10 black balls
P(drawing a red ball) = \(\frac{7}{17}\)
Let a black ball be drawn in the first attempt P(drawing a black ball) = \(\frac{10}{15}=\frac{2}{3}\)
If two black balls are added to the box, then the box contains 5 red and 12 black balls
P(drawing a red ball) = \(\frac{5}{17}\)
Probability of drawing the second ball red is
Plus Two Maths Probability 4 Mark Questions and Answers 43

Question 7.

  1. Bag I contains 5 red and 6 black balls. Bag II contains 7 red and 5 black balls. One ball is drawn at random from one of the bags and it is found to be red. Find the probability that it was drawn from bag I. (3)
  2. A card from a pack of 52 cards is lost. From the remaining cards of the pack, two cards are drawn and are found to be both diamonds. Find the probability of the lost card being diamond. (3)

Answer:
1. Let E1 be the event of choosing Bag I and E2 be the event of choosing Bag II
A be the event of drawing a red ball
Plus Two Maths Probability 4 Mark Questions and Answers 44

2. Let E1 be the event of choosing a diamond and E2 be the event of choosing a non diamond card
A be the event that a card is lost
Plus Two Maths Probability 4 Mark Questions and Answers 45
When a diamond card is lost, there are 12 diamond cards in 52 cards. Then
Plus Two Maths Probability 4 Mark Questions and Answers 46
When a non diamond card is lost, there are 13 diamond cards in 51 cards. Then
Plus Two Maths Probability 4 Mark Questions and Answers 47

Plus Two Maths Chapter Wise Questions and Answers Chapter 13 Probability

Question 8.
(i) If X denotes number of heads obtained in tossing two coins. Then which of the following is false (1)
(a) X(HH) = 2
(b) X(HT) = 1
(c) X(TH)= 0
(d) X(TT) = 0
(ii) Find the probability distribution of the number of tails in the simultaneous toss of two coins. (2)
(iii) A coin is tossed so that the head is 3 times as likely to occur as tail. If the coin is tossed twice, find the probability distribution of number of tails. (3)
Answer:
(i) (c) X(TH)= 0.

(ii) Sample space is S = {HH, HT, TH, TT}
Let X denote the number of tails, then
X(HH) = 2, X(HT) = 1, X(TH) = 1, X(TT) = 0
Therefore X can take the values 0, 1 or 2
P(HH) = P(HT) = P(TH) = P(TT) = \(\frac{1}{4}\)
P(X = 0) = \(\frac{1}{4}\) P(X = 1) = \(\frac{1}{2}\) P(X = 2) = \(\frac{1}{4}\)
Then the Probability distribution is
Plus Two Maths Probability 4 Mark Questions and Answers 48

(iii) Let the probability of getting a tail in the biased coin be x.
P(T) = x P(H) = 3x
P(T) + P(H) = 1 ⇒ x + 3x = 1 x = \(\frac{1}{4}\)
P(T) = \(\frac{1}{4}\) P(H) = \(\frac{3}{4}\)
Let X denote the random variable representing the number of tails
P(X = 0) = P(HH) = P(H).P(H) = \(\frac{9}{16}\)
P(X = 1) = P(HT) + P(TH)
Plus Two Maths Probability 4 Mark Questions and Answers 49
P(X = 2) = P(TT) = P(T).P(T) = \(\frac{1}{16}\)
Then the Probability distribution is
Plus Two Maths Probability 4 Mark Questions and Answers 50

Question 9.
If a fair coin is tossed 10 times, find the probability of

  1. Exactly 6 heads. (2)
  2. At least 6 heads. (2)
  3. At most 6 heads. (2)

Answer:
Let X denotes the random variable of number of heads in an experiment of 10 trials.
Clearly X has a Binomial Distribution with
n = 10 and p = \(\frac{1}{2}\) ⇒ P(x) = nCxqn-x Px
Plus Two Maths Probability 4 Mark Questions and Answers 51
1. P(x = 6)
Plus Two Maths Probability 4 Mark Questions and Answers 52

2. P(at least 6 heads) = P(X ≥ 6)
= P(X = 6) + P(X = 1)+P(X = 8)
Plus Two Maths Probability 4 Mark Questions and Answers 53

P(at most 6 heads) = P(X ≤ 6)
= P(X = 6) + P(X = 5) + P(X = 4) + P(X = 3) + P(X = 2) + P(X = 1) + P(X = 0)
Plus Two Maths Probability 4 Mark Questions and Answers 54
Plus Two Maths Probability 4 Mark Questions and Answers 55

Plus Two Maths Chapter Wise Questions and Answers Chapter 13 Probability

Question 10.
Five cards are drawn successively with a replacement from a pack of 52 cards. What is the probability that

  1. All the 5 cards are spades? (2)
  2. only 3 cards are spade? (2)
  3. none is a spade? (2)

Answer:
Let X denotes the random variable of number of spades cards in an experiment of 5 trials. Clearly X has a Binomial Distribution with n = 5
Plus Two Maths Probability 4 Mark Questions and Answers 56
1. P(all 5 are spades) = P(X = 5)
Plus Two Maths Probability 4 Mark Questions and Answers 57

2. P(3 are spades) = P(X = 3)
Plus Two Maths Probability 4 Mark Questions and Answers 58

3. P(non-spade) = P(X = 0) =
Plus Two Maths Probability 4 Mark Questions and Answers 59

Question 11.
Find the probability distribution, Mean and Variance of the number of success in two tosses of a die, where a success is defined as

  1. number greater than 4. (3)
  2. 6 appears on at least on die. (3)

Answer:
1. Let X denotes the random variable of getting a 5, 6. Clearly X can take values 0, 1, 2.
When number 1, 2, 3, 4 appears in both die. Number of such cases = 4 × 4 = 16
P(X=0) = P(no success) = \(\frac{16}{36}=\frac{4}{9}\)
When 5, 6 in one die and other with 1, 2, 3, 4 and visa versa.
Number of such cases is 2 × 4 + 4 × 2 = 16.
P(X= 1) = P(1 success and 1 no success) = \(\frac{16}{36}=\frac{4}{9}\)
When number 5, 6 appears in Jjoth die. Number Hof such cases = 2 × 2 = 4.
P(success) = \(\frac{4}{36}=\frac{1}{9}\)
The required Probability Distribution is
Plus Two Maths Probability 4 Mark Questions and Answers 60

2. Let X denotes the random variable of getting at least 6 on one die. Clearly X can take values 0, 1.
No success means 1, 2, 3, 4, 5 appears on both die. Number of such cases is 5 × 5 = 25.
P(X=0) = P(no success) = \(\frac{25}{36}\)
When 6 in one die and other with 1, 2, 3, 4, 5 and visa versa. Number of such cases is 1 × 5 + 5 × 1 = 10
When both the die is 6. Number of such case is 1. Therefore total cases is 1 + 10 = 11
P(X=1) = P(1 success) = P(at least 1 six) = \(\frac{11}{36}\)
The required Probability Distribution is
Plus Two Maths Probability 4 Mark Questions and Answers 61

Plus Two Maths Chapter Wise Questions and Answers Chapter 13 Probability

Question 12.
(i) If A and B are two events such that A ⊂ B and P(A) ≠ 0 then P(A/B) is (1)
Plus Two Maths Probability 4 Mark Questions and Answers 62
(ii) There are two identical bags. Bag I contains 3 red and 4 black balls while Bag II contains 5 red and 4 black balls. One ball is drawn at random from one of the bags.
(a) Find the probability that all the ball drawn are red. (3)
(b) If the balls drawn is red what is the probability that it was drawn from Bag I? (2)
Answer:
(i) Describe the events as follows.
A: ‘getting a red ball’.
E1: ‘choosing Bag I.’
E2: ‘choosing Bag II.’
P(E1) = P(E2) = \(\frac{1}{2}\)
P(A/E1) = P
(drawing a red ball from Bag I) = \(\frac{3}{7}\)
P(A/E2) = P
(drawing a red ball from Bag II) = \(\frac{5}{9}\)
P (All the balls drawn is red)
= P(A) = P(E1)P(A/E1) + P(E2)P(A/E2)
Plus Two Maths Probability 4 Mark Questions and Answers 63
Plus Two Maths Probability 4 Mark Questions and Answers 64

Question 13.
Consider the following probability distribution of a random, variable X.
Plus Two Maths Probability 4 Mark Questions and Answers 65

  1. Find the value of k. (2)
  2. Determine the Mean and Variance of X. (4)

Answer:
(i) We have; Σpi = 1
Plus Two Maths Probability 4 Mark Questions and Answers 66

(ii)
Plus Two Maths Probability 4 Mark Questions and Answers 67

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 8 Sources of Business Finance

Students can Download Chapter 8 Sources of Business Finance Questions and Answers, Plus One Business Studies Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examination

Kerala Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 8 Sources of Business Finance

Plus One Sources of Business Finance One Mark Questions and Answers

Question 1.
Equity shareholders are called
(a) Owners of the company
(b) Partners of the company
(c) Executive of the company
(d) Guardians of the company
Answer:
(a) Owners of the company

Question 2.
Fund required for purchasing current assets is an example of __________
Answer:
Working capital

Question 3.
Under the lease agreement, the lessee get the rights to __________
Answer:
Use the asset for a specified period.

Question 4.
Under the factoring agreement, the factor
Answer:
Collects the client’s debt or account receivables.

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 8 Sources of Business Finance

Question 5.
Internal sources of capital are those that are
Answer:
generated within the business.

Question 6.
Preference shares abd equity shares are called ____________ securities.
Answer:
Ownership Securities

Question 7.
Equity shareholders are called
(a) Owners of the company
(b) Partners of the company
(c) Executives of the company
(d) Guardians of the company
Answer:
(a) Owners of the company

Question 8.
Equity share capital is called ________ capital
Answer:
Risk

Question 9.
Which of the following is not a characteristic of equity shares?
(a) Voting rights
(b) Ownership security
(c) Fixed rate of return
(d) Residual owners
Answer:
(c) Fixed rate of return

Question 10.
Which source is called as permanent source of capital?
Answer:
Equity Share Capital

Question 11.
__________ shareholders have the right to control the company.
Answer:
Equity Shareholders

Question 12.
Which source is called as permanent source of capital?
Answer:
Equity Share Capital

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 8 Sources of Business Finance

Question 13.
Sumesh an NRI is interested to invest in companies, but he is not ready to take up more risk. Which type of security he should buy?
Answer:
Preference shares.

Question 14.
_________ shareholders have the right to get dividend at a fixed rate .
Answer:
Preference shareholders

Question 15.
This source of finance is called ‘internal source of financing’ and ‘self financing’. Identify the source of finance and mention its three merits.
Answer:
Ploughing back of profit

Question 16.
Retained earnings are parts of __________ capital.
Answer:
Ownership Capital

Question 17.
Employment of corporate savings use of accumulated saving in the business in the form of reserves is called
Answer:
Ploughing back of profits

Question 18.
___________ are the cheapest source of finance.
Answer:
Retained earnings

Question 19.
___________ are called creditorship securities
Answer:
Debentures

Question 20.
Debentures which are secured by a charge on the assets of the company are called _________
Answer:
Secured debentures

Question 21.
Debentures which can be converted in equity shares are called _________
Answer:
Convertable debentures

Question 22.
Debenture issued without the name of owner is __________ debenture.
Answer:
Unregistered or naked

Question 23.
Which of the following is not a characterstics features of debentures?
(a) Ownership security
(b) Generally secured
(c) Participate in the surplus profit
(d) Guarantee of returms
Answer:
(c) Participate in the surplus profit

Question 24.
An Indian Company can now raise funds not only from India but also through foreign equity participation. How is it possible?
Answer:

  1. GDRs
  2. ADRs
  3. FDI

Question 25.
Expand the term GDR
Answer:
Global Depositors Receipts.

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 8 Sources of Business Finance

Question 26.
Expand the term ADR
Answer:
American Depository Receipt

Question 27.
ADRs are issued in
(a) Canada
(b) China
(c) India
(d) USA
Answer:
(d) USA

Question 28.
Identify the type of financial services belonged to each cash explain its features.

  1. Acquired a machinery for monthly rental basis from an outside agency.
  2. Gives the right for collecting their accounts receivable to a specialised agency.
  3. An organization which collects and pools funds from public and invests in securities.

Answer:

  1. Leasing
  2. Factoring
  3. Mutual fund

Question 29.
A company decided to raise its funds by selling its account receivables to an agency. Which type of financial service is maintaining here.
Answer:
Factoring

Question 30.
I render specialized services to companies in the collection of their accounts receivables.
Answer:
Factoring

Question 31.
State the appropriate term to denote the arrangement of acquiring the right to use an asset without actually owning it.
Answer:
Leasing

Plus One Sources of Business Finance Two Mark Questions and Answers

Question 1.
What is business finance? Why do businesses need funds? Explain. (2)
Answer:
Nature of Business Finance:

1. Fixed capital requirements:
In order to start a business funds are needed to purchase fixed assets like land and building, plant and machinery. This is called fixed capital requirement.

2. Working Capital requirements:
A business needs funds for its day to day operation. This is known as working Capital requirements. Working capital is required for purchase of raw materials, to pay salaries, wages, rent and taxes.

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 8 Sources of Business Finance

Question 2.
These are shares which carry preferential rights over the equity shares. Being a commerce student, identify this type of share. And state its 2 preferential rights. (2)
Answer:
Preference shares.
Their preferential rights are:

  1. The right to get a fixed rate of divided
  2. The right to claim repayment of capital in the event of winding up of the company.

Question 3.
Match the following

  1. Equity share – Fixed percentage of interest
  2. Debenture – International source of finance
  3. Preference share – Real owner
  4. American depository – No voting right receipt

Answer:

  1. Equity share – Real owner
  2. Debenture – Fixed percentage of interest
  3. Preference share – No voting right
  4. American depository receipt – International source of finance

Question 4.
An Indian company can expand not only through the fund in India but also from foreign equity participation. How is it possible? (2)
Answer:
FDI. It refers to direct subscription to the equity capital of an Indian company by a multinational corporation. It includes Establishment of a new enterprise in a foreign.

Plus One Sources of Business Finance Three Mark Questions and Answers

Question 1.
An Indian company can now raise funds not only from India, but also through foreign equity participation. How is it possible? Explain
Answer:
GDR: Global Depository Receipts are issued by an Indian company to an intermediary abroad called an Overseas Depository Bank. They are issued and traded in European capital market.

ADR: American Depository receipts are issued and traded in U.S.A.

Question 2.
List sources of raising long-term and short-term finance. (3)
Answer:
Long Term Sources:
The amount of funds required by a business for more than five years is called long-term finance. Generally this type
of finance is required for the purchase of fixed assets like land and building, plant and machinery furniture, etc. It include sources such as shares and debentures, long-term borrowings and loans from financial institutions.

Short Term Sources:
Short-term funds are those which are required for a period not exceeding one year. These sources include Trade credit, loans from commercial banks and commercial papers etc. Short-term finance is used for financing of current assets such as accounts receivable and inventories.

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 8 Sources of Business Finance

Question 3.
Name any three special financial institutions and state their objectives. (3)
Answer:
Financial Institutions:
The state and central government have established many financial institutions to provide finance to companies. These institutions aim at promoting the industrial development of a country, these are also called ‘development Bank’. These are IFCI, ICICI, IDBI and LIC, UTI.

This source of financing is considered suitable when large funds for longer duration are required for expansion, reorganisation and modernisation of an enterprise.
Merits:

  1. Financial Institution provide long term finance which is not provided by Commercial Bank
  2. These institutions provide financial, managerial and technical advice and consultancy to business firms.
  3. It increases the goodwill of the borrowing company in the capital market.
  4. As repayment of loan can be made in easy installments, it does not prove to be much of a burden on the business.
  5. The funds are made available even during periods of depression, when other sources of finance are not available.

Limitations:

  1. The procedure for granting loan is time consuming due to rigid criteria and many formalities.
  2. Financial Institution place restrictions on the powers of the borrowing company.
  3. Financial institutions may have their nominees on the Board of Directors of the borrowing company thereby restricting the autonomy of the company.

Question 4.
While presenting a seminar paper on different sources of business finance, your friend Vineeth, pointed out that “ownership capital is the risk capital of the business”. Can you explain why it is called risk capital? (3)
Answer:
Equity shareholders are the real owners of the company. Equity shareholders will get their dividend only after dividend is paid to preference shareholders. They can claim back their capital only on winding up after discharging all other liabilities of the company. So we can say that ownership capital is the risk capital of the business.

Question 5.
“ADR & GDR serves the same purpose whenever shares are issued abroad by Indian companies”. Then why can’t we call them by the same name? (3)
Answer:
The important differences between ADR and GDR are:

ADRGDR
They are issued and traded in USAThey are issued and traded in European capital market
Both individual and institutional investors can make investmentOnly institutional investors can invest
It can be converted into shares and shares into ADROnce converted into shares, it cannot be converted back.
Legal and accounting costs are highLegal and accounting costs are comparatively less

Plus One Sources of Business Finance Four Mark Questions and Answers

Question 1.
What is the difference between internal and external sources of raising funds?
Answer:

Internal sourcesExternal Sources
Funds are generated from within the organisationFunds are generated from outside the organization
Fulfill limited needs of the businessFulfill long term needs f the business
It is not costlyIt is costly as compared to internal sources of fund
No need to mortgage the assets of the company to obtain fund from internal sourcesNeed to mortgage the assets of the company to obtain fund from internal sources

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 8 Sources of Business Finance

Question 2.
What is the difference between GDR and ADR? (4)
Answer:

ADRGDR
They issued and traded in USAThey issued and traded in European capital market
Both individual and institutional investors can make investmentOnly institutional investors can make investment
It can be converted into shares and shares into ADROnce converted into shares, it cannot be converted back
Legal and accounting costs are highLegal and accounting costs are less

Question 3.
Discuss the financial instruments used in international financing. (4)
Answer:
International Financing:

1. Commercial Banks:
Commercial banks all over the world extend foreign currency loans for business purposes. Standard chartered is a major source of foreign currency loan to the Indian industry.

2. International Agencies and Development Banks:
A number of international agencies and development banks provide long and medium term loans and grants to promote the development of economically backward areas in the world. Eg. International Finance Corporation (IFC), EXIM Bank and Asian Development Bank.

3. International Capital Markets:

a. Global Depository Receipts (GDR’s):
Under GDR, shares of the company are first converted into depository receipts by international banks. These depository receipts are denominated in US dollars. Then these depository receipts are offered for sale globally through foreign stock exchanges. GDR is a negotiable instrument and can be traded freely like any other security.

The holder of GDRs are entitled for dividend just like shareholders. But they do not enjoy the voting rights. Many Indian companies like ICICI, Wipro etc. have raised foreign capital through issue of GDRs.
Feature of GDR:

  • GDR can be listed and traded on a stock exchange of any foreign country other than America.
  • It is negotiable instrument.
  • A holder of GDR can convert it into the shares.
  • Holder gets dividends
  • Holder does not have voting rights.
  • Many Indian companies such as Reliance, Wipro and ICICI have issue GDR.

b. American Depository Receipts (ADR’s):
The depository receipts issued by a company in the USA are known as American Depository Receipts.
Feature of ADR:

  • It can be issued only to American Citizens.
  • It can be listed and traded is American stock exchange.
  • Indian companies such as Infosys, Reliance issued ADR

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 8 Sources of Business Finance

Question 4.
Explain different types of Preference shares. (4)
Answer:
Types of Preference Shares:

a. Cumulative and Non-cumulative Preference Share:
in cumulative preference shares, the unpaid dividends are accumulated and carried forward for payment in future years. On the other hand, in non- cumulative preference share, the dividend is not accumulated if it is not paid out of the current year’s profit.

b. Participating and Non-participating Preference Share:
Participating preference shares have a right to share the profit after making payment to the equity shares. The non-participating preference shares do not enjoy such a right.

c. Convertible and Non-convertible Preference Share:
The preference shares which can be converted into equity shares after a specified period of time are known as convertible preference share. Non-convertible shares cannot be converted into equity shares.

d. Redeemable and Irredeemable Preference Share:
Redeemable preference shares are those where the company undertakes to repay it after a specified period. Where the amount of the preference shares is refunded only at the time of liquidation, are known an irredeemable preference shares.

Merits:

  1. Preference shares provide reasonably steady income in the form of fixed rate of return and safety of investment.
  2. Preference shares are useful for those investors who want fixed rate of return with comparatively low risk

Limitations:

  1. Preference shareholders have no voting right.
  2. The dividend paid is not deductible from profit for income tax.

Plus One Sources of Business Finance Five Mark Questions and Answers

Question 1.
What is a commercial paper? What are its advantages and limitations. (5)
Answer:
Commercial Paper (CP):
It is an unsecured promissory note issued by a firm to raise funds for a short period. The maturity period of commercial paper usually ranges from 90 days to 364 days. Being unsecured, only firms having good credit rating can issue the CP and its regulation comes under the purview of the Reserve Bank of India.
Merits:

  1. A commercial paper does not contain any restrictive conditions.
  2. As it is a freely transferable instrument, it has high liquidity.
  3. A commercial paper provides a continuous source of funds.
  4. They are cheaper than a bank loan.

Limitations:

  1. Only financially sound and highly rated firms can raise money through commercial papers
  2. The size of money that can be raised through commercial paper is limited
  3. Commercial paper is an impersonal method of financing. Extending the maturity of a CP is not possible.
  4. Issue of commercial paper is very closely regulated by the RBI guidelines.

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 8 Sources of Business Finance

Question 2.
Mr. Ganesh, a sole trader, acquired a machinery on a monthly rental basis from an outside agency. Identify the type of financial service in which he entered into. Explain it. (5)
Answer:
Lease Financing:
A lease is a contractual agreement whereby the owner of an asset (lessor) grants the right to use the asset to the other party (lessee). The lessor charges a periodic payment for renting of an asset for some specified period called lease rent.
Merits:

  1. It enables the lessee to acquire the asset with a lower investment;
  2. Lease rentals paid by the lessee are deductible for computing taxable profits;
  3. It provides finance without diluting the ownership or control of business
  4. The lease agreement does not affect the debt raising capacity of an enterprise;
  5. Simple documentation makes it easier to finance assets.

Limitations:

  1. A lease arrangement may impose certain restrictions on the use of assets.
  2. The normal business operations may be affected in case the lease is not renewed.
  3. The lessee never becomes the owner of the
    asset.

Question 3.
Both Equity shares and Preference shares are ownership funds of a company. But there is significant difference between these two funds. Can you identify the same. (5)
Answer:

Equity SharesPreference Shares
It is compulsory to issue these shares.It is not compulsory to issue these shares
Rate of dividend varies according to the profits of the companyRate of dividend is fixed
Face value is lowerFace value is higher
No priority in dividend and repayment of capitalPriority in dividend and repayment of capital
It cannot be redeemedIt can be redeemed
Risk is highRisk is low
They have voting rightsThey do not have voting rights
They can participate in the managementThey can not participate in the management

Plus One Sources of Business Finance Eight Mark Questions and Answers

Question 1.
“The issue of debentures provides wide options to the company as well as investors in terms of its features”. Can you substantiate the statement from the point of view of its classification? (8)
Answer:
Debentures:
A debenture is a document issued by a company under its seal to acknowledge its debt. Debenture holders are, therefore, termed as creditors of the company. Debenture holders are paid a fixed rate of interest.
Types of Debentures:

a. Secured and Unsecured Debentures:
Secured (Mortgaged) debentures are debentures which are secured by a charge on the assets of the company. Unsecured (Simple or naked) debentures do not carry any charge or security on the assets of the company.

b. Registered and Bearer Debentures:
In the case registered debentures, the name, address and other details of the debenture holders are entitled in the books of the company. The debentures which are transferable by mere delivery are called bearer (Unsecured) debentures.

c. Convertible and Non-convertible Debentures:
Convertible debentures are those debentures that can be converted into equity shares after the expiry of a specified period. On the other hand, non¬convertible debentures are those which cannot be converted into equity shares.

d. First and Second:
Debentures that are repaid before other debentures are repaid are known as first debentures. The second debentures are those which are paid after the first debentures have been paid back.

Merits:

  1. It. is preferred by investors who want fixed income at lesser risk
  2. Debenture holder do not have voting right
  3. Interest on Debentures is a tax deductable expense
  4. It does not dilute control of equity shareholders on management
  5. Debentures are less costly as compared to cost of preference shares.
  6. They guarantee a fixed rate of interest
  7. It enables the company to take the advantage of trading on equity.
  8. The issue of debentures is suitable when the sales and earnings are relatively stable

Limitations:

  1. It is not suitable for companies with unstable future earnings.
  2. The company has to mortgage its assets to issue debentures.
  3. Debenture holders do not enjoy any voting rights.
  4. In case of redeemable debentures, the company has to make provisions for repayment on the specified date, even during periods of financial difficulty.
  5. With the new issue of debentures, the company’s capability to further borrow funds reduces.

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 8 Sources of Business Finance

Question 2.
Distinguish between Shares and Debentures. (8)
Answer:

SharesDebentures
Shareholders are the owners of the companyDebenture holders are the creditors of the company
Shareholders get dividendsDebenture holders get interest
Shareholders have voting rightDebenture holders have no voting right
No security is required to issue sharesGenerally debentures are secured
Shares are not redeemableDebentures are redeemable
Share capital is payable after paying all outside liabilitiesDebenture holders have the priority of repayment over shareholders

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 7 Formation of a Company

Students can Download Chapter 7 Formation of a Company Questions and Answers, Plus One Business Studies Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examination

Kerala Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 7 Formation of a Company

Plus One Formation of a Company One Mark Questions and Answers

Question 1.
Application for approval of name of a company is to be made to
Answer:
Registrar of companies.

Question 2.
A prospectus is issued by
Answer:
Public company

Question 3.
Preliminary contracts are signed
Answer:
Before the incorporation

Question 4.
At which stage in the formation of a company does it interact with SEBI
Answer:
Capital subscription

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 7 Formation of a Company

Question 5.
The first stage in the formation of a company is __________
Answer:
Promotion

Question 6.
“I undertake to form a new company and carry out all the preliminary work in connection with its establishment” Who am I?
Answer:
Promoter

Question 7.
Preliminary Contracts are signed
1. Before the incorporation
2. After incorporation but before capital subscription
3. After incorporation but before of commencement of business
4. After commencement business
Answer:
1. Before the incorporation

Question 8.
Spot the odd one and state the reason
1. Memorandum of Association
2. Articles of Association
3. Certificate of incorporation
4. Certificate of commencement of business
Answer:
5. Certificate of commencement of business

Question 9.
_____________ is the magnacarta of the company.
Answer:
Memorandum of Association

Question 10.
_____________ is the birth certificate of a company.
Answer:
Certificate of incorporation

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 7 Formation of a Company

Question 11.
The procedure for conducting company meetings, voting, quorum, poll and proxy will be mentioned in the
1. Prospectus
2. Memorandum of Association
3. Articles of Association
Answer:
3. Articles of Association

Question 12.
The provision regarding the internal management of a company will appear in its
Answer:
Articles of Association

Question 13.
Public Companies need __________ to commence the business.
Answer:
Certificate of commencement of business

Question 14.
Directors of a public Ltd. Co. decided to give advertisement in all newspapers for subscribing their shares. Identify the document given below
1. table A
2. memorandum of association
3. prospectus
Answer:
3. Prospectus

Question 15.
This clauses is the form of a declaration, it states that the subscribers express the willingness and agreement to form a company. Name the clause of memorandum of association.
Answer:
Association Clause

Question 16.
This clause specifies the name of the state where the registered office of the Co. is situated. Identify the clause.
Answer:
Situation clause

Question 17.
This clause specifies the name of the company.
Answer:
Name clause

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 7 Formation of a Company

Question 18.
Identify the document in which the following information about a company can be found.

  1. Object with which the company is formed.
  2. Rules and regulations of internal management
  3. Investing deposits from the public
  4.  Acknowledgement of debt in a company

Answer:

  1. Memorandum of Association
  2. Articles of Association
  3. Mutual fund
  4. Debenture

Question 19.
TABLE A is a model of _________ given in companies Act.
Answer:
Articles of Association

Question 20.
Identify the documents in which following information about a company is found.

  1. Authorized capital
  2.  Rules and regulation for internal management.
  3.  Date of opening and closing of subscription list.

Answer:

  1. Memorandum of Associaiton
  2. Articles of Association
  3. Prospectus

Question 21.
Identify the relevant clauses in the memorandum of association in which the following information can be included.

  1. The registered office is in Kerala.
  2. Statutory declaration by members
  3. Ram Limited
  4. The scope of activities of company

Answer:

  1. Situation clause
  2. Association clause
  3. Name clause
  4. Object clause

Question 22.
State the odd item in the case of a private limited company.
1. memorandum of association
2. articles of association
3. certificate of incorporation
4. certificate of commencement of business
Answer:
4. Certificate of Commencement of business

Question 23.
Mention the name of the certificates/documents relating to following activities / formalities

  1. The certificate issued by the Registrar of companies certifying that the company has come into existence.
  2. The document, which contains the various rules and regulations that govern the management of the company.
  3. The document that defines the objectives of the company.

Answer:

  1. Certificate of Incorporation
  2. Articles of Association
  3. Memorandum of Association

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 7 Formation of a Company

Question 24.
Name the following documents.

  1. The document issued by the company to the public to invite them to subscribe its share capital.
  2. The document that binds a member with the company, company with members and members with members.
  3. The document that contains rules for internal management of the company.
  4. The document that specifies the aims of the company.
  5. The document issued by the public company which does not want to issue a prospectus.

Answer:

  1. Prospectus
  2. Articles of Association
  3. Articles of Association
  4. Memorandum of Association
  5. Statement in lieu of Prospectus

Plus One Formation of a Company Two Mark Questions and Answers

Question 1.
Name the stages in the formation of a company?
Answer:

  1. Promotion
  2. Incorporation
  3. Capital subscription
  4. Commencement of business (2)

Question 2.
Name the stages in the formation of a company. (2)
Answer:

  1. Promotion
  2. Incorporation
  3. Commencement of business

Question 3.
What do you mean by promotion? (2)
Answer:
The identification of business opportunities, analysis of its prospects and initiating steps to form a joint stock company is called promotion.

Question 4.
For incorporating a private limited company, Deepthi Pvt. Ltd., the directors submit all relevant documents to the registrar of company except Articles of Association. But the registrar insists that, registration will not be granted without filing Articles of Association. But the directors of Deepthi Pvt. Ltd., argue that the provisions of ‘Table A’ can be adopted in the absence of Articles of Association. Whose argument is correct? Justify your answer. (2)
Answer:
The argument of the Company Registrar is right because filing of Articles of association is compulsory for Pvt. Ltd company by shares.

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 7 Formation of a Company

Question 5.
Arya Ltd. commences its business immediately on getting the certificate of incorporation. The registrar of companies serves a notice to them for remitting a fine of ₹500 for everyday of its operation. Is it legally enforceable? Give your suggestion. (2)
Answer:
Yes. Public Ltd. Company can commence business only after getting the certificate of commencement of business.

Question 6.
It is proposed to conduct a seminar on the topic ‘important documents in the formation of joint stock company’ in your class. You are selected as the leader of one of the groups and are directed to submit a seminar paper for the same. Suggest valuable points that should be included in the paper. (2)
Answer:

  1. Memorandum of Association
  2. Articles of Association
  3. Prospectus

Question 7.
What do you mean by Minimum Subscription? (2)
Answer:
Minimum subscription is the minimum amount of shares that must be subscribed by the public. This amount is stated in the prospectus. A company can allot shares only after receiving minimum subscription.

Question 8.
I lay down the charter or the constitution of the company. I define the object and powers of the company.

  1. Identify who am I?
  2. Also name my companion who provides rules and regulations for the internal management of the company. (Both are two documents). (2)

Answer:

  1. Memorandum of Association
  2. Articles of Association

Plus One Formation of a Company Three Mark Questions and Answers

Question 1.
Is it necessary for a public company to get its shares listed on a stock exchange? What happens if a public company fails to get the permission from stock exchange? (3)
Answer:
Yes. A public company must list its shares with at least any one of the stock exchange for the allotment of shares. Therefore, the promoters must apply in a stock exchange for permission to deal in its shares or debentures. If permission is not granted before the expiry of ten weeks from the date of Closure of subscription list, the allotment shall become void and the application money must be returned to the applicants within eight days.

Question 2.
State the difference between certificate of incorporation and certificate of commencement of business. (3)
Answer:
Certificate of Incorporation gives legal status to the company. It is also known as birth certificate of the company. But certificate of commencement of business allows to start the operation.

These two certificates are required by the public limited company, but in case of private limited company only certificate of Incorporation is required to start the operation.

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 7 Formation of a Company

Question 3.
Nisha, Shani and Sheena are promoters of a public company. But they do not want to raise capital by approaching the public. They decide to raise capital by issuing shares to a few persons. Is it possible? If yes, what document is used for raising capital? (3)
Answer:
Yes. They can raise capital by issuing shares to a few persons. For this they can issue Statement in lieu of prospectus.

Plus One Formation of a Company Four Mark Questions and Answers

Question 1.
Identify the documents required for commencing business for the following companies. (4)

  1. Athira Pvt. Ltd.
  2. Aditya Ltd.

Answer:
1. Athira Pvt. Ltd – A private company must file the following documents for commencing business

  • Certificate of incorporation
  • Statutory declaration duly verified by one of the directors.

2. Aditya Ltd., a public company, must file the following documents for commencing business.

  • Certificate of incorporation
  • Certificate of commencement of business
  • Prospectus
  • Statutory declaration duly verified by one of the directors.

Question 2.
The details of a proposed private company having limited liability is given below. You are required to identify as to which clauses in the Memorandum of Association have to be rightly inserted. (4)
Proposed names:
Mahatma Gandhi Khadi – Company
Premier Mills (P) Ltd.
Kerala Government Khadi Company
Sobha Co-operative Company
Maximum capital which can be collected is 20 lakhs rupees
Nature of shares
Equity shares at Rs. 10/- share

Address:
Pushpa Nivas Kodunganoor (P.O)
Thiruvananthapuram 13
Kerala State
India.

Nature of business:
To produce Khadi clothes through machine To stitch Khadi ready wears Name of the persons who are wishing to form the company
P. Sudarsanan
K. Muraleedharan Nair
S. Renjith
Answer:

  1. Name clause
  2. Capital clause
  3. Situation clause
  4. Object clause
  5. Association clause

Plus One Formation of a Company Five Mark Questions and Answers

Question 1.
“Promoter would be personally liable for the preliminary contracts, if they are not ratified by the company after incorporation. Analyse the statement. (5)
Answer:
Promotion:
Promotion is the first stage in the formation of a company. The identification of business opportunities, analysis of its prospects and initiating steps to form a joint stock company is called promotion. The person who undertakes to form a company is called promoter.

Functions of a Promoter:

1. Identification of business opportunity:
The first and foremost activity of a promoter is to identify a business opportunity.

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 7 Formation of a Company

2. Feasibility studies:
After identifying a business opportunity, the promoters undertake some feasibility studies to determine the viability and profitability of the proposed activity.

  • Technical feasibility – To determine whether the raw materials or technology is easily available
  • Financial feasibility – To determine the total estimated cost of the project
  • Economic feasibility – To determine the I profitability of the proposed project

3. Name approval:
After selecting the name of company the promoters submit an application to the Registrar of companies for its approval. The selected name is not the same or identical to an existing company.

4. Fixing up signatories to the Memorandum of Association:
Promoters have to decide about the members who will be signing the Memorandum of Association of the proposed company.

5. Appointment of professional:
Promoters appoint merchant bankers, auditors etc. to assist them in the preparation of necessary documents.

6. Preparation of necessary documents:
The promoters prepare certain legal documents which are to be submitted to the Registrar of companies. They are

  • Memorandum of Association
  • Articles of Association,
  • Consent of proposed Directors
  • Agreement, if any, with proposed managing or whole time director
  • Statutory declaration

Position of Promoters:
The promoter is neither an agent nor a trustee of the company. The promoter stands in the fiduciary relationship with the company. He should not make any secret profits out of the dealings. Any, such gains are to be disclosed. The promoter must act honestly, in good faith and in the best interest of the company.

The promoter is personally liable for all the preliminary contracts with the other parties before incorporation. The promoter is also liable for any omission of facts or false statements in the prospectus.

Question 2.
Memorandum of Association is the charter or magna carta of the company. Elucidate the statement. (5)
Answer:
Memorandum of Association:
It is the charter or magnacarta of the company. It defines the objects of the company and provides the framework beyond which the company cannot operate. It lays down the relationship of the company with outside world.

Memorandum of Association must be printed, divided into paragraphs, numbered consecutively. The Memorandum of Association must be signed by at least seven persons in case of a public company and by two persons in case of a private company.

Contents of Memorandum of Association
Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 7 Formation of a Company 1
1. The name clause:
Under this clause the name of the company is mentioned. A company can select any name subject to the following restrictions.

  • The proposed name should not be identical with the name of another company
  • A name which can mislead the public
  • In case of a public company the name should end with the word ‘Limited’ and in case of a private company the name should end with the word ‘Private Limited’
  • The name must not directly or indirectly imply any participation of the Central or State Govt.
  • The name must not suggest any connection or patronage of a national hero
  • It should not include the word cooperative.

2. Registered office clause:
This clause contains the name of the state, in which the registered office of the company is proposed to be situated. It must be informed to the Registrar within thirty days of the incorporation of the company.

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 7 Formation of a Company

3. Objects clause:
This is the most important clause of the memorandum. It defines the purpose for which the company is formed. A company is not legally entitled to undertake an activity, which is beyond the objects stated in this clause.

4. Liability clause:
It states that the liability of members is limited to the face value of shares held by them or the amount guaranteed to be paid on winding up.

5. Capital clause:
This clause specifies the maximum capital which the company will be authorised to raise through, the issue of shares.

6. Association clause:
In this clause, the signatories to the Memorandum of Association state their intention to be associated with the company and also give their consent to purchase qualification shares.

Question 3.
Explain the contents of prospectus. (5)
Answer:
Prospectus:
Prospectus is a document issued by the public companies inviting the public to subscribe for shares or debentures of the company. It contains all information regarding the company’s affairs and its future prospects. A prospectus must be dated and signed by all the directors. A copy of the prospectus must be filed with Registrar before it is issued to public.

Contents of prospectus

  1. Name and address of the registered office of the company.
  2. Main objects of the company.
  3. Classes of shares and debentures.
  4. Name, address and occupation of the signatories to the memorandum.
  5. Details of the borrowing powers of the company.
  6. Name, address and occupation of the directors and managing director.
  7. Name and address of the promoters.
  8. Minimum subscription.
  9. Time of opening and closing of subscription.
  10.  The amount payable on application and allotment of each class of shares.
  11.  Name of underwriters.
  12.  Details of preliminary expenses.
    Companies which do not want to issue a prospectus may submit a statement in lieu of prospectus to the Registrar of Companies. It is a copy of the prospectus but is not issued to the public.

Question 4.
The details of a proposed limited company are given below. You are required to identify them as to which clause of the memorandum of association they have to be inserted. (5)

  1. Proposed name: Jnana Construction Company Ltd
  2. Maximum Capital: ₹10,00,000
  3. Registered office: Kollam
  4. Nature of liability: Limited
  5. Nature of Business: Construction company
  6. Names of promoters: Jnana, Akshara, Pooja, Ajay

Answer:

  1. Name clause
  2. Capital clause
  3. Situation / Domicile clause
  4. Liability clause
  5. Object clause
  6. Association clause

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 7 Formation of a Company

Question 5
A public company can commence business only after getting the certificate of commencement of business. Abhijith, a plus two student wants to know the conditions to be fulfilled to obtain the certificate of commencement of business.
Answer:
Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 7 Formation of a Company 2
Commencement of Business:
A public company can commence business only after getting certificate of commencement of business from the Registrar. The company must file the following documents to obtain the certificate of commencement of business.

  1. Declaration that the minimum subscription has been received in cash to allot shares.
  2. A declaration that all directors have taken up and paid for their qualification shares
  3. A statutory declaration stating that necessary legal formalities have been complied with has to be filed.

The Registrar shall examine these documents. If these are found satisfactory, a ‘Certificate of Commencement of Business’ will be issued. This certificate is conclusive evidence that the company is entitled to do business. With the grant of this certificate the formation of a public company is complete and the company can legally start doing business.
Documents used in the formation of a company

Plus One Formation of a Company Six Mark Questions and Answers

Question 1.
I govern the internal affairs of the company. Explain who am ‘I’? List out my contents.
OR
For the purpose of registering a new company, the promoter requires a document containing the rules and regulations governing its internal affairs. (6)

  1. What is that document? Explain.
  2. State the contents of this statement.

Answer:
Articles of Association:
The Articles of Association is the second important document of a company. The Articles define the rights, duties and powers of the officers and the Board of directors. It contains the rules regarding internal management of the company. It shows the relationship between the company and its members.

Contents of Articles of Association:

  1. The share capital of the company and its division.
  2. Rights of each class of shareholders.
  3. Details of contracts made with different parties.
  4. Procedure for making allotment of shares.
  5. Procedure for issuing share certificate.
  6. Procedure for transfer and transmission of shares.
  7. Procedure for forfeiture and reissue of shares.
  8. Procedure for conducting meetings, voting, proxy and poll
  9. Procedure for appointing, removal and remuneration of directors.
  10. Procedure for declaration of and payment of dividend.
  11. Keeping books of account and audit of the company.
  12. Procedure regarding alteration of share capital.
  13. Procedure regarding winding up of the company.

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 7 Formation of a Company

Table A:
A public limited company may adopt Table A which is a model set of articles given in the Companies Act. Table A is a document containing rules and regulations for the internal management of a company. If a company adopts Table A, there is no need to prepare separate Articles of Association.

Question 2.
Vishnu, a promoter of a public company, approaches you to get information relating to raising of capital from public. As a commerce student mention the document required for inviting the public to purchase or subscribe to its shares and debentures. Explain. (6)
Answer:
Prospectus:
Prospectus is a document issued by the public companies inviting the public to subscribe for shares or debentures of the company. It contains all information regarding the company’s affairs and its future prospects. A prospectus must be dated and signed by all the directors. A copy of the prospectus must be filed with Registrar before it is issued to public.

Contents of prospectus:

  1. Name and address of the registered office of the company.
  2. Main objects of the company.
  3. Classes of shares and debentures.
  4. Name, address and occupation of the signatories to the memorandum.
  5. Details of the borrowing powers of the company.
  6. Name, address and occupation of the directors and managing director.
  7. Name and address of the promoters.
  8. Minimum subscription.
  9. Time of opening and closing of subscription.
  10. The amount payable on application and allotment of each class of shares.
  11. Name of underwriters.
  12. Details of preliminary expenses.

Companies which do not want to issue a prospectus may submit a statement in lieu of prospectus to the Registrar of Companies. It is a copy of the prospectus but is not issued to the public.

Question 3.
It is often said that Memorandum of Association and Articles of Association are the first and second important documents of a company. As a commerce student can you differentiate between these two documents? (6)
Answer:

Memorandum of AssociationArticles of Association
It defines the object for which the company is formedThey are rules of internal management of the company. They indicate how the objectives of the company are to be achieved
It is the main document of the companyIt is a subsidiary document of the Memorandum of Association
It defines the relationship of the company with outsidersIt defines the relationship of the company with members
Acts beyond the Memorandum of Association are invalid and cannot be ratified.Acts beyond the Articles of Association can be ratified by the members. But they do not violate memorandum
Filing of Memorandum is compulsoryFiling of Articles is not compulsory for public company
Alteration of Memorandum is very difficultIt can be altered by passing a special resolution

Plus One Formation of a Company Eight Mark Questions and Answers

Question 1.
Explain the steps in the incorporation of a company. (8)
Answer:
Incorporation:
A company comes into existence only when it is registered with the Registrar of Companies. For this purpose the promoter has to take the following steps:
Steps for Incorporation

1. Application for incorporation:
Promoters make an application for the incorporation of the company to the Registrar of companies.

2. Filing of documents:
The following documents must be filed with the Registrar of Companies for incorporation.

  • The Memorandum of Association duly stamped, signed and witnessed
  • Articles of Association duly stamped, signed and witnessed
  • Written consent of the proposed directors
  • Agreement, if any, with proposed managing or whole time director
  • A copy of the Registrar’s letter approving the name of the company.
  • Statutory declaration
  • A notice about the exact address of the registered office.
  • Documentary evidence of payment of registration fees.

The Registrar verifies the entire document submitted. If he is satisfied then he enters the name of the company in his Register. After the registration, the Registrar issues a Certificate called Certificate of Incorporation. This is called the birth certificate of the company. With effect from November 1, 2000, the Registrar of Companies allots a CIN (Corporate Identity Number) to the Company.

Effect of the Certificate of Incorporation:
Certificate of Incorporation is the conclusive evidence of the legal existence of the company. A private company can commence its business after receiving Certificate of Incorporation. The certificate of incorporation is the birth certificate of the company.

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 7 Formation of a Company

Question 2.
Explain the contents of Memorandum of Association.

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 7 Formation of a Company 1
Answer:
Memorandum of Association: It is the charter or magnacarta of the company. It defines the objects of the company and provides the framework beyond which the company cannot operate. It lays down the relationship of the company with outside world.

Memorandum of Association must be printed, divided into paragraphs, numbered consecutively. The Memorandum of Association must be signed by at least seven persons in case of a public company and by two persons in case of a private company.

Contents of Memorandum of Association:

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 7 Formation of a Company 1
1. The name clause:
Under this clause the name of the company is mentioned. A company can select any name subject to the following restrictions.

  • The proposed name should not be identical with the name of another company
  • A name which can mislead the public
  • In case of a public company the name should end with the word ‘Limited’ and in case of a private company the name should end with the word ‘Private Limited’
  • The name must not directly or indirectly imply any participation of the Central or State Govt.
  • The name must not suggest any connection or patronage of a national hero
  • It should not include the word co operative.

2. Registered office clause:
This clause contains the name of the state, in which the registered office of the company is proposed to be situated. It must be informed to the Registrar within thirty days of the incorporation of the company.

3. Objects clause:
This is the most important clause of the memorandum. It defines the purpose for which the company is formed. A company is not legally entitled to undertake an activity, which is beyond the objects stated in this clause.

4. Liability clause:
It states that the liability of members is limited to the face value of shares held by them or the amount guaranteed to be paid on winding up.

5. Capital clause:
This clause specifies the maximum capital which the company will be authorised to raise through, the issue of shares.

6. Association clause:
In this clause, the signatories to the Memorandum of Association state their intention to be associated with the company and also give their consent to purchase qualification shares.

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 7 Formation of a Company

Question 3.
Mr. Hemand, a Gulf returnee, intends to start a business in the form of private limited company. But he lias no clear idea about the business opportunities in Kerala and the formalities to be followed in the formation of company. (8)

  1. As a commerce student can you suggest a specialised person who would undertake all activities for the formation of a company?
  2. Explain the functions of those specialised persons.

Answer:

Promotion:
Promotion is the first stage in the formation of a company. The identification of business opportunities, analysis of its prospects and initiating steps to form a joint stock company is called promotion. The person who undertakes to form a company is called promoter.

Functions of a Promoter:

1. Identification of business opportunity:
The first and foremost activity of a promoter is to identify a business opportunity.

2. Feasibility studies:
After identifying a business opportunity, the promoters undertake some feasibility studies to determine the viability and profitability of the proposed activity.

  • Technical feasibility – To determine whether the raw materials or technology is easily available
  • Financial feasibility – To determine the total estimated cost of the project
  • Economic feasibility – To determine the I profitability of the proposed project

3. Name approval:
After selecting the name of company the promoters submit an application to the Registrar of companies for its approval. The selected name is not the same or identical to an existing company.

4. Fixing up signatories to the Memorandum of Association:
Promoters have to decide about the members who will be signing the Memorandum of Association of the proposed company.

5. Appointment of professional:
Promoters appoint merchant bankers, auditors, etc. to assist them in the preparation of necessary documents.

6. Preparation of necessary documents:
The promoters prepare certain legal documents which are to be submitted to the Registrar of companies. They are

  • Memorandum of Association
  • Articles of Association,
  • Consent of proposed Directors
  • Agreement, if any, with proposed managing or whole time director
  • Statutory declaration

Position of Promoters:
The promoter is neither an agent nor a trustee of the company. The promoter stands in the fiduciary relationship with the company. He should not make any secret profits out of the dealings. Any, such gains are to be disclosed. The promoter must act honestly, in good faith and in the best interest of the company.

The promoter is personally liable for all the preliminary contracts with the other parties before incorporation. The promoter is also liable for any omission of facts or false statements in the prospectus.

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 6 Social Responsibilities of Business and Business Ethics

Students can Download Chapter 6 Social Responsibilities of Business and Business Ethics Questions and Answers, Plus One Business Studies Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examination

Kerala Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 6 Social Responsibilities of Business and Business Ethics

Plus One Social Responsibilities of Business and Business Ethics One Mark Questions and Answers

Question 1.
Identify which of the following is not a social responsibility of business _________
1. Offering goods and services at reasonable price.
2. Keeping environment pollution free
3. Giving reasonable pay to workers
4. Help in nation building activities
Answer:
3. Giving reasonable pay to workers

Question 2.
State Bank of India gives scholarship to bright students each year. This is a part of their __________
1. Sales promotion
2. Social responsibility
3. Charity work
4. Business ethics
Answer:
2. Social responsibility

Question 3.
Application of general ethics and principles in business practice is ____________
Answer:
Business ethics

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 6 Social Responsibilities of Business and Business Ethics

Question 4.
It is the belief in what is right, proper and just. Identify it.
Answer:
Business ethics

Question 5.
______________ is the code of conduct followed and performed by businessmen.
Answer:
Business ethics

Question 6.
Which among the following is not a case for an ethical activity.
1. child labour
2. equal pay for equal work
3. dumbing of waste in river
4. high usage of preservatives in products.
Answer:
2. Equal pay for equal work

Plus One Social Responsibilities of Business and Business Ethics Two Mark Questions and Answers

Question 1.
Roy and Rejitha joined in a factory as peons on the same day. Both of them are doing 8 hrs work a day. Roy is paid ₹100 while Rejitha ₹80 per day. Do you think the owner of the factory is fair to Rejitha? If not, give your opinion. (2)
Answer:
No. The owner of the factory is not fair to Rejitha. It is the social and moral responsibility of the business to offer equal pay for equal work without considering any caste, sex, etc.

Question 2.
Explain the need for pollution control. (2)
Answer:
Need for Pollution Control:

1. Reduction of health hazard:
Pollution control measures can check diseases like cancer, heart attack & lung complications and support a healthy life on earth.

2. Reduced Risk of Liability:
It is a sound business policy to install pollution control devices in its premises to reduce the risk of liability of paying compensation to the affected people.

3. Cost Saving:
An effective pollution control programme is needed to save costs of operating business.

4. Improved Public Image:
A firm that adopts pollution control measures enjoys a good reputation as a socially responsible enterprise.

5. Other social benefits:
Pollution control results in many other benefits like clearer visibility, cleaner buildings, better quality of life, and the availability of natural products in a purer form.

Plus One Social Responsibilities of Business and Business Ethics Three Mark Questions and Answers

Question 1.
George is working in a manufacturing industry. The manager compels him to do 10hrs work continuously without giving any additional benefits. Do you agree with the manager? Give your suggestions. (3)
Answer:
No. We cannot agree with the decision of the manager. It is against the social responsibility of the business. George has to work only 8 hours a day. Compelling to do 10 (without any additional benefits) hours is a violation of human right. Managers cannot ask a worker to do work continuously without giving remuneration. It is also a violation of human rights.

Plus One Social Responsibilities of Business and Business Ethics Four Mark Questions and Answers

Question 1.
Match column A with columns B and C
Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 6 Social Responsibilities of Business and Business Ethics 1
Answer:

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 6 Social Responsibilities of Business and Business Ethics 2

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 6 Social Responsibilities of Business and Business Ethics

Question 2.
Jaleel, owner of a fish stall, usually sells damaged and decayed fish by pouring chemicals, ice, along with sea sand for creating an impression in the minds of consumers that it is newly caught. Is it justifiable from the point of view of business ethics? How will it affect the reputation of the business? (4)
Answer:
Business ethics refer to the socially determined moral principles which should govern business activities.
A few examples of business ethics are

  • charging fair prices from customers
  • providing quality products
  • using fair weights for measurement of commodities
  • giving fair treatment to workers & earning only reasonable profits.

Ethical business behaviour improves public image, earns people’s confidence and trust, and leads to greater success. Selling damaged and decayed fish is unethical.

It will affect the reputation of the business and finally it leads to business loss. He must not goods of low quality for personal gain. No business can make progress without adopting ethical values.

Plus One Social Responsibilities of Business and Business Ethics Five Mark Questions and Answers

Question 1.
Anchu, a stationery dealer distributed good quality products at low price by suffering huge losses, in order to eliminate the competition from Chinju, another stationery dealer, in the same locality. When Chinju stopped her business, Anchu started to supply low quality products at high price. (5)

  1. Can you justify Anchu’s action from point of view of the society?
  2. Give a few undesirable practices which a business follow in a real life situation.

Answer:
1. No. We cannot justify Anchu’s action. It is against business ethics. Business ethics refers to moral values which should be followed in business activities.

2. Examples of unethical practices are

  • Providing low quality products at high prices.
  • Making misleading advertisements.
  • Creating artificial scarcity to increase demand.
  • Keeping false accounts to avoid paying taxes.
  • Acceptance of bribe for personal benefits.
  • Manufacture and sale of adulterated goods.
  • Polluting the environment.
  • Exploiting workers.

Plus One Social Responsibilities of Business and Business Ethics Six Mark Questions and Answers

Question 1.
What steps can an enterprise take to protect the environment from the dangers of pollution? (6)
Answer:
Role of Business in Environmental Protection:

1. A definite commitment by top management to create a work culture for environmental protection

2. Ensuring that commitment of environmental protection is shared throughout the enterprise by all divisions and employees.

3. Developing clear cut policies and programmes for purchasing good quality raw materials, introducing superior technology, using scientific techniques of disposal of waste and developing employee skills for pollution control

4. Complying with the laws and regulations enacted by the Government for prevention of pollution.

5. Participation in government programs relating to management of hazardous substances, cleaning up of polluted rivers, plantation of trees, and checking deforestation.

6. Periodical assessment of pollution control programmes in terms of costs and benefits with a view to improve them.

7. Arranging educational workshops and training materials to share technical information with everyone involved in pollution control.

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 6 Social Responsibilities of Business and Business Ethics

Question 2.
Explain the elements of business ethics. (6)
Answer:
Business Ethics:
Ethics is concerned with what is right and what is wrong in human behavior. Business ethics refer to the socially determined moral principles which should govern business activities.

Business ethics is the code of conduct followed and performed by every business. Ethical business behavior improves public image earn’s public confidence and leads to greater success.
Examples of Business Ethics:

  1. Charging fair prices from customers
  2. Using fair weights for measurement of commodities
  3. Giving fair treatment to workers
  4. Earning reasonable profits.
  5. Avoiding adulteration, hoarding etc.
  6. Using environmentally friendly products

Elements of Business Ethics:

1. Top management commitment:
The Chief Executive Officer and higher level managers must give continuous leadership for developing and upholding the moral values of the organisation.

2. Publication of a Code:
‘Code’ refers to a formal written document of the principles, values and standards that guide a firm’s actions. It may cover the areas of fundamental honesty and adherence to laws, product safety and quality, health and safety in the workplace, etc.

3. Establishment of Compliance Mechanism:
A suitable mechanism should be developed to comply with the ethical standards of the enterprise.

4. Employees Involvement:
To make ethical business a reality, employees at all levels must be involved.

5. Measuring Results:
Ethical results must be verified and audited that how far work is being carried according to ethical standards.

Plus One Social Responsibilities of Business and Business Ethics Eight Mark Questions and Answers

Question 1.
Build up arguments for and against social responsibilities. (8)
Answer:
Arguments in favour of Social Responsibility:

1. Justification for Existence and Growth:
The prosperity and growth of business is possible only through continuous service to society.

2. Long term Interest of the firm:
A firm can improve its image and builds goodwill in the long run when its highest goal is to serve the society.

3. Avoidance of government regulations:
Business can avoid the problem of government regulations by voluntarily assuming social responsibilities.

4. Maintenance of society:
Law alone can’t help out people with all the difficulties they face. A socially responsible business can contribute something for social peace and harmony.

5. Availability of resources with business:
Business has valuable financial and human resources which can be effectively used for solving problems of the society.

6. Better environment for doing business:
Social responsibility creates better environment for business operations as it improves quality of life and standard of living of the people.

7. Contribution to social problems:
Some of the social problems have been created by business firms themselves such as pollution, unsafe workplaces, discrimination, etc. Therefore, it is the moral obligation of business to solve such social problems.

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 6 Social Responsibilities of Business and Business Ethics

Arguments Against Social Responsibility:

1. Violation of profit maximization objective:
According to this argument, business exists only for the maximum profit to its shareholders and do not have responsibility to the society as a whole.

2. Burden on consumers:
Involvement of business in social responsibilities involve a lot of expenditure which will ultimately be borne by the customers.

3. Lack of Social Skills:
The business firms and managers are not expert to tackle the social problems like poverty, overpopulation etc.

4. Lack of public support:
Business cannot fulfill social responsibility because of lack of public confidence & cooperation.

Question 2.
Mr. Biju, a readymade garment manufacturer, is of the view that “different interest groups always claim some sort of protection from the business as such. These interest groups, no doubt consist of persons connected with business in one way or other, such as shareholders, employees, society and so on”. Do you agree with this statement? Explain. (8) 

OR

“Business is a social institution having responsibilities towards different interest group.” Do you agree. Explain the responsibility towards each group.
Answer:
Social Responsibility towards different interest groups

1. Responsibility towards share holders or owners:

  1. Provide a fair and regular return on the investment of shareholders.
  2. Provide regular and accurate information on the financial position of the firm.
  3. To ensure the safety of their investment.

2. Responsibility Towards the workers:

  1. Providing fair wages
  2. Providing good working conditions and welfare amenities.
  3. Respect democratic rights of workers to form
    unions.

3. Responsibility toward consumers:

  1. Supply right quality and quantity of goods and services at reasonable prices.
  2. Avoiding unfair trade practices like adulteration, poor quality, misleading advertisement etc.
  3. Inform them about new products, its features, uses and other matters relating to the products.
  4. To handle the customers grievance promptly.

4. Responsibility Towards Government:

  1. Respect the laws of the country
  2. Pay taxes regularly and honestly.
  3. act according to the well accepted values of the society.

5. Responsibility towards community:

  1. Make employment opportunities
  2. Protect the environment from pollution.
  3. To uplift the weaker sections of society

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 6 Social Responsibilities of Business and Business Ethics

Question 3.
Prosperity and higher living standards are the hallmarks of industrial development for any nation. But during this course, it equally causes damages to the environment. (8)

  1. Explain the different types of pollution.
  2. Substantiate the above statement with regard to various types of pollution.

Answer:
Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 6 Social Responsibilities of Business and Business Ethics 3

Business & Environmental Protection Causes of Pollution: Many industrial organisations have been responsible for causing air, water, land and noise pollution.

1. Air Pollution:
Air pollution is mainly due to Carbon monoxide emitted by automobiles and smoke and other chemicals from manufacturing plants. It has created a hole in the ozone layer leading to global warming.

2. Water pollution:
Water becomes polluted primarily from chemical and waste dumping. It has led to the death of several animals and posed a serious problem to human life.

3. Land Pollution:
Dumping of toxic wastes reduces the quality of land and making it unfit for agriculture or plantation.

4. Noise Pollution:
Noise caused by the running of factories and vehicles create a serious health hazard such as loss of hearing, malfunctioning of the heart and mental disorders.

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 6 Social Responsibilities of Business and Business Ethics

Question 4.
Explain the role of business in environmental protection. (8)
Answer:
Role of Business in Environmental Protection:

  1. A definite commitment by top management to create a work culture for environmental protection
  2. Ensuring that commitment of environmental protection is shared throughout the enterprise by all divisions and employees.
  3. Developing clear cut policies and programmes for purchasing good quality raw materials, introducing superior technology, using scientific techniques of disposal of waste and developing employee skills for pollution control
  4. Complying with the laws and regulations enacted by the Government for prevention of pollution.
  5. Participation in government programs relating to management of hazardous substances, cleaning up of polluted rivers, plantation of trees, and checking deforestation.
  6. Periodical assessment of pollution control programmes in terms of costs and benefits with a view to improve them.
  7. Arranging educational workshops and training materials to share technical information with everyone involved in pollution control.

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 5 Emerging Modes of Business

Students can Download Chapter 5 Emerging Modes of Business Questions and Answers, Plus One Business Studies Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations

Kerala Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 5 Emerging Modes of Business

Plus One Emerging Modes of Business One Mark Questions and Answers

Question 1.
Carrying business activity through internet is popularly known as _______
Answer:
E-commerce

Question 2.
____________ refers to illegal entry into the web site of an enterprise and thereby damaging data input there.
Answer:
Hacking

Question 3.
____________ are programmes designed to corrupt data in a system.
Answer:
Viruses

Question 4.
Mr. Arun, a retailer pays tax online. Identify this E-Commerce Transaction
Answer:
C2G

Question 5.
Which of the following helps to purchase goods and services without making spot payments and zero balance in the account?

  1. ATM card
  2. credit card
  3. debit card
  4. Kisan card

Answer:
2. credit card

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 5 Emerging Modes of Business

Question 6.
The advancement of technology helps people for shopping goods for cash without holding cash or making any deposits with banks. How is it possible explain the identified term?
Answer:
Credit card

Plus One Emerging Modes of Business Two Mark Questions and Answers

Question 1.
What do you mean by cryptography? (2)
Answer:
It refers to the art of protecting information by transforming it into an unreadable format called ‘cyphertext’. Only those who processes a secret key can decrypt the message into plaintext.

Question 2.
What are the ethical concerns involved in outsourcing? (2)
Answer:
In the name of cost cutting, unlawful activities such as child labour, wage discrimination, etc. may be encouraged in other countries.

Plus One Emerging Modes of Business Three Mark Questions and Answers

Question 1.
Anish, an NRI businessman, sends money to his wife, Nisha. She in turn deposits all this money in her bank account. She is very thankful to the technology and can withdraw money whenever she is in need of money even after banking hours. What type of technology she might be using? Explain. (3)
Answer:
ATM. From the ATM, customers can withdraw cash from the account by using ATM card. ATM card is a plastic card bearing a number for each customer. The card is to be entered into the machine and enter the PIN. This opens the account and we can deposit cash into it or withdraw from it at any time.

Question 2.
The advancement of technology facilitates shopping -goods for cash without holding cash or making any deposit with banks. How is it possible? (3)
Answer:
It is possible through credit card. A credit card is an instrument issued by a bank in the name of the customer providing for credit up to a specified amount. The sellers get cash from the bank and the buyers have to pay for the purchase within the credit period.

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 5 Emerging Modes of Business

Question 3.
Majority of people in India, even internet users, hesitate shopping through internet. Can you cite a few reasons for their hesitation for buying online? (3)
Answer:
The important reasons forthe hesitation of shopping through internet are:

  1. Time to deliver goods is too long.
  2. Disclosure of credit card details is not safe.
  3. Choices are not very interesting.

Plus One Emerging Modes of Business Four Mark Questions and Answers

Question 1.
Elaborate the steps involved in online trading. (4)
Answer:
Online Transactions:
Online transaction means receiving information about goods, placing an order, receiving delivery and making payment through medium of internet.

Buying / Selling Process:
Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 5 Emerging Modes of Business 1

Steps involved in online purchase:
1. Register with the online vendor by filling-up a registration form.

2. Place the order for the items put by customer in his virtual shopping cart, an online record of what has been picked up while browsing the Online store.

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 5 Emerging Modes of Business

3. Payment for the purchases through online shopping may be done in a number of ways: i.e Cash on delivery, cheque, net banking transfer, debit/credit card.

Question 2.
Name the resources required for E-commerce. (4)
Answer:
Resources Required for Successful e-Business Implementation:

  1. Computer system
  2. Internet connection and technically qualified workforce
  3. A well developed web page
  4. Effective telecommunication system
  5. A good system for making payment using credit instruments.

Question 3.
Explain any 4 types of outsourcing services. (4)
Answer:

  1. Financial services.
  2. Advertising services
  3. Courier services
  4. Customer support services

Plus One Emerging Modes of Business Five Mark Questions and Answers

Question 1.
List two examples each for B2B, B2C, B2G and B2E transactions (5)
Answer:
B2B:

  • Transactions between businessmen
  • Collaboration
  • Placing order with suppliers
  • Forming joint ventures
  • Transfer of goods between branches
  • Transfer of goods between suppliers

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 5 Emerging Modes of Business

B2C:

  • Business offering services to customers
  • Consumer placing order online
  • Electronic payment
  • Consumers seeking clarification on price, terms etc. (any two)

B2G:

  • Payment of taxes
  • Application for licence
  • Seeking government clearance

B2E:

  • Employees salary payments
  • Operation of welfare schemes
  • Information to employees on business process
  • Seeking employees suggestions online

Question 2.
Sankar and Co is a leading can manufacturing company. They are not concentrating on their advertisement due to lack of time. In orderto boost up the sales they made a contract with an advertising agency to make an advertisement which can be released through the media. Analyze this situation. Do you favour this activity of the company? Can you identify the concept and brings out its merit? (5)
Answer:
Business Process Outsourcing (BPO)

Plus One Emerging Modes of Business Six Mark Questions and Answers

Question 1.
State any three differences between e-business and traditional business.
Answer:

Traditional businesse-business
Its formation is difficultIts formation is easy
Investment is very highInvestment is low
Physical presence is requiredPhysical presence is not required
Location is importantLocation is not important
Operating cost is highOperating cost is low
Contact with suppliers and customers is through intermediariesDirect contact with the suppliers and customers
Business process cycle is longBusiness process cycle is shorter
Inter personal touch is highPersonal touch is less
Limited market coverageAccess to the global market
Communication is in hierarchical orderCommunication is in non hierarchical order
Transaction risk is lessTransaction risk is high

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 5 Emerging Modes of Business 3
Outsourcing or Business Process Outsourcing (BPO):
Outsourcing is a management strategy by which an organisation contracts out its major non-core functions to specialized service providers with a view to benefit from their expertise, efficiency and cost effectiveness, and allow managers to concentrate on their core activities.

Merits of outsourcing:

  1. It provides an opportunity to the organisation to concentrate on areas in which it has core competency or strength.
  2. It helps better utilisation of its resources as the management can focus its attention on selected activities and attain higher efficiency.
  3. It helps the organisation to get an expert and specialised service at competitive prices. It helps in improved service and reduction in costs.
  4. It facilitates inter-organisational knowledge sharing and collaborative learning.
  5. It enables expansion of business as resources saved from outsourcing can be used for expanding the production capacity and diversified products.

Limitations of outsourcing:

  1. It reduces confidentiality as outsourcing involves sharing a lot of information with others.
  2. It may be opposed by labour unions who feel threatened by possible reduction in their employment.
  3. In the name of cost cutting, unlawful activities such as child labour, wage discrimination maybe encouraged in other countries.
  4. The organisation hiring others may face the problem of loss of managerial control because it is more difficult to manage outside service providers than managing one’s own employees.
  5. It causes unemployment in the home country.

Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 5 Emerging Modes of Business

Question 2.
Evaluate the need for outsourcing and discuss its limitations. (6)
Answer:
Outsourcing or Business Process Outsourcing (BPO):
Outsourcing is a management strategy by which an organisation contracts out its major non-core functions to specialized service providers with a view to benefit from their expertise, efficiency and cost effectiveness, and allow managers to concentrate on their core activities.

Merits of outsourcing:

  1. It provides an opportunity to the organisation to concentrate on areas in which it has core competency or strength.
  2. It helps better utilisation of its resources as the management can focus its attention on selected activities and attain higher efficiency.
  3. It helps the organisation to get an expert and specialised service at competitive prices. It helps in improved service and reduction in costs.
  4. It facilitates inter-organisational knowledge sharing and collaborative learning.
  5. It enables expansion of business as resources saved from outsourcing can be used for expanding the production capacity and diversified products.

Limitations of outsourcing:

  1. It reduces confidentiality as outsourcing involves sharing a lot of information with others.
  2. It may be opposed by labour unions who feel threatened by possible reduction in their employment.
  3. In the name of cost cutting, unlawful activities such as child labour, wage discrimination maybe encouraged in other countries.
  4. The organisation hiring others may face the problem of loss of managerial control because it is more difficult to manage outside service providers than managing one’s own employees.
  5. It causes unemployment in the home country.

Question 3.
What is online transactions? Explain its steps. (6)
Answer:
On line Transactions:
On line transaction means receiving information about goods, placing an order, receiving delivery and making payment through medium of internet.

Buying / Selling Process:
Plus One Bussiness Studies Chapter Wise Questions and Answers Chapter 5 Emerging Modes of Business 1
Steps involved in online purchase:

  1. Register with the online vendor by filling-up a registration form.
  2. Place the order for the items put by customer in his virtual shopping cart, an on-line record of what has been picked up while browsing the On-line store.
  3. Payment for the purchases through online shopping may be done in a number of ways: i.e Cash on delivery, cheque, net banking transfer, debit/credit card.