Plus One Maths Notes Chapter 16 Probability

Kerala State Board New Syllabus Plus One Maths Notes Chapter 16 Probability.

Kerala Plus One Maths Notes Chapter 16 Probability

I. Random Experiments
An experiment is called a random experiment if it satisfies the following two conditions:

  • It has more than one outcome.
  • It is not possible to predict the outcome in advance.

Sample space: The set of all possible outcomes of a random experiment is called sample space. Generally denoted by S.

Event: Any subset E of a sample space S is called an event.

Types of Events:
1. Impossible event and sure event: The empty set φ and the sample space S describe the impossible event and sure event respectively.

2. Simple event: An event E having only one sample point of a sample space.

3. Compound event: An event having more than one sample point of a sample space.

Algebra of events:

  1. Event ‘not A’ = A’
  2. Event ‘A or B’ = A ∪ B
  3. Event ‘A and B’ = A ∩ B
  4. Event ‘A but not B’ = A ∩ \(\bar{B}\) = A – B

If A ∩ B = φ, then A and B are mutually exclusive events or disjoint events.

If E1 ∪ E2 ∪ E3 ∪ …… ∪ En = S, then we say that E1, E2, E3, …….., En are exhaustive events.

If E1 ∪ E2 ∪ E3 ∪ …… ∪ En = S, and Ei ∩ Ej = φ, i ≠ j then we say that E1, E2, E3,…….., En are mutually exclusive events and exhaustive events.

II. Probability of an Event
Let S is a sample space and E be an event, such that n(S) = n and n(E) = m. If each outcome is equally likely, then it follows that P(E) = \(\frac{m}{n}\).

P(Impossible event) = 0 and P(Sure event) = 1, hence 0 ≤ P(E) ≤ 1.

If A and B are any two events, then P(A ∪ B) = P(A) + P(B) – P(A ∩ B)

If A and B are mutually exclusive events, then P(A ∪ B) = P(A) + P(B)

If A is any events, then P(A’) = 1 – P(A)

P(A ∩ \(\bar{B}\)) = P(A) – P(A ∩ B)

Plus One Maths Notes Chapter 15 Statistics

Kerala State Board New Syllabus Plus One Maths Notes Chapter 15 Statistics.

Kerala Plus One Maths Notes Chapter 15 Statistics

Statistics deals with data collected for specific purposes and making decisions about the data by analyzing and interpreting it.

I. Measure of Dispersion
This gives a measure of the dispersion of the observation around the measure of central tendency of the data collected.

1. Range = Maximum value – Minimum value.
2. Mean Deviation.
Plus One Maths Notes Chapter 15 Statistics 1
Where,
xi – observations
a – Any measure of central tendency.
Plus One Maths Notes Chapter 15 Statistics 2
Grouped data:
i. Discrete frequency distribution.
ii. Continuous frequency distribution.
Plus One Maths Notes Chapter 15 Statistics 3
Where,
xi – Observations/midpoints of class intervals
a – Any measure of central tendency.
Plus One Maths Notes Chapter 15 Statistics 4
Median class is the class in which the \(\left(\frac{N}{2}\right)^{t h}\) observation lies.
Plus One Maths Notes Chapter 15 Statistics 5
l – The lower limit of the median class.
f0 – Cumulative frequency of the class preceding the median class.
f1 – Frequency of the median class.
C – Width of the class interval.
Plus One Maths Notes Chapter 15 Statistics 6
3. Variance and Standard Deviations.
Standard Deviation (σ) = √Variance
Ungrouped data:
Plus One Maths Notes Chapter 15 Statistics 7
Where, xi – observations
\(\bar{x}\) – Mean
n – number of observations

Grouped data:
i) Discrete frequency distribution.
ii) Continuous frequency distribution.
Plus One Maths Notes Chapter 15 Statistics 8
Where,
xi – Observations/mid points of class intervals.
\(\bar{x}\) – Mean
fi – Frequency.

Short cut method of finding variance and standard deviation:
Let A be the assumed mean and the scale be reduced to \(\frac{1}{h}\) times (h being the width of class intervals). Let the new value be yi and prepare the required tables using yi. i.e; yi = \(\frac{x_{i}-A}{h}\)
Find the variance and standard deviation of yi using the above-mentioned method, let it
Plus One Maths Notes Chapter 15 Statistics 10

II. Coefficient of Variation
Plus One Maths Notes Chapter 15 Statistics 9
The distribution having greater CV has more variability around the central value than the distribution having a smaller value of the CV.

Less the CV more consistent is the data.

For distributions with equal means, the distribution with lesser standard deviation is more consistent or less scattered.

Plus One Maths Notes Chapter 14 Mathematical Reasoning

Kerala State Board New Syllabus Plus One Maths Notes Chapter 14 Mathematical Reasoning.

Kerala Plus One Maths Notes Chapter 14 Mathematical Reasoning

I. Statement
The basic unit involved in mathematical reasoning is a mathematical sentence.

A sentence is called a mathematically acceptable statement if it is either true or false but not both. Usually denoted by small letters p, q, r, ……..

Denial of a statement is called the negation of the statement. While forming the negation of a statement, phrases like, “It is not the case” or “it is false that” are also used. The negation of a statement p is denoted by ~p.

II. Compound Statement
Many mathematical statements are obtained by combining one or more statements using some connective words like “and”, “or”, etc.
Plus One Maths Notes Chapter 14 Mathematical Reasoning 1

Contrapositive statement: the contrapositive of a statement p ⇒ q is the statement ~q ⇒ ~p.

Converse of a statement: Converse of a statement p ⇒ q is the statement q ⇒ p.

III. Validity of Statement
A statement is said to be valid or invalid according to it is true or false.
Plus One Maths Notes Chapter 14 Mathematical Reasoning 2

Plus One Maths Notes Chapter 13 Limits and Derivatives

Kerala State Board New Syllabus Plus One Maths Notes Chapter 13 Limits and Derivatives.

Kerala Plus One Maths Notes Chapter 13 Limits and Derivatives

Calculus is that branch of mathematics which mainly deals with the study of change in the value of a function as the points in the domain changes.

I. Limit
Limit of a function f(x) at x = a is the behaviors of f(x) at x = a.

x → a: Means that ‘x’ takes values less than ‘a’ but not ‘a’.

x → a+: Means that ‘x’ takes values greater than ‘a’ but not ‘a’.

x → a: Read as ‘x’ tends to ‘a’, means that ‘x’ takes values very close to ‘a’ but not ‘a’.

\(\lim _{x \rightarrow a^{-}} f(x)=A\): Read as left limit of f(x) is ‘A’, means that f(x) → A as x → a. To evaluate the left limit we use the following substitution \(\lim _{x \rightarrow a^{-}} f(x)=\lim _{h \rightarrow 0} f(a-h)\)

\(\lim _{x \rightarrow a^{+}} f(x)=B\): Read as right limit of f(x) is ‘B’, means that f(x) → B as x → a+. To evaluate the left limit we use the following substitution \(\lim _{x \rightarrow a^{+}} f(x)=\lim _{h \rightarrow 0} f(a+h)\).

If left limit and right limit of f(x) at x = a are equal, then we say that the limit of the function f(x) exists at x = a and is denoted
by lim \(\lim _{x \rightarrow a} f(x)\). Otherwise we say that \(\lim _{x \rightarrow a} f(x)\) does not exist.

II. Evaluation Methods

  1. Direct substitution method
  2. Factorisation method
  3. Rationalisation method
  4. Using standard results.

III. Algebra of Limits:
For functions f and g the following holds;
Plus One Maths Notes Chapter 13 Limits and Derivatives 1
Plus One Maths Notes Chapter 13 Limits and Derivatives 2

IV. Standard Results

\(\lim _{x \rightarrow a} k=k\), where k is constant.

\(\lim _{x \rightarrow a} f(x)=f(a)\), if f(x) is a polynomial function.

1. \(=\frac{0}{0}\), if possible we can factorise the numerator and denominator and then, cancel the common factors and again put x = a. This factorization method is not possible in all cases so we are studying some standard limits.
Plus One Maths Notes Chapter 13 Limits and Derivatives 3

V. Derivatives
A derivative of f at a: Suppose f is a real-valued function and a is a point in its domain of definition. The derivative of f at a is defined by \(\lim _{h \rightarrow 0} \frac{f(a+h)-f(a)}{h}\)
Provided this limit exists. A derivative of f (x) at a is denoted by f'(a).
Derivative of f at x. Suppose f is a real-valued function, the function defined by \(\lim _{h \rightarrow 0} \frac{f(x+h)-f(x)}{h}\)

Wherever this limit exists is defined as the derivative of f at x and is denoted by f”(x) |\(\frac{d y}{d x}\)| |y1| y’. This definition of derivative is also called the first principle of the derivative.

VI. Algebra of Derivatives
For functions f and g are differentiable following holds;
Plus One Maths Notes Chapter 13 Limits and Derivatives 4

VII. Standard Results
Plus One Maths Notes Chapter 13 Limits and Derivatives 5

Plus One Maths Notes Chapter 12 Introduction to Three Dimensional Geometry

Kerala State Board New Syllabus Plus One Maths Notes Chapter 12 Introduction to Three Dimensional Geometry.

Kerala Plus One Maths Notes Chapter 12 Introduction to Three Dimensional Geometry

Introduction
To refer to a point in space we require a third axis (say z-axis) which leads to the concept of three-dimensional geometry. In this chapter, we study the basic concept of geometry in three-dimensional space.

I. Octant
Consider three mutually perpendicular planes meet at a point O. Let these three planes intercept along three lines XOX’, YOY’ and ZOZ’ called the x-axis, y-axis, and z-axis respectively. These three planes divide the entire space into 8 compartments called Octants. These octants could be named as XOYZ, XOYZ’, XOYZ, X’OYZ, XOY’Z’, X’OYZ, X’OYZ’, X’OYZ’.
Plus One Maths Notes Chapter 12 Introduction to Three Dimensional Geometry 1

Plus One Maths Notes Chapter 12 Introduction to Three Dimensional Geometry 2
Distance between two points: The distance between the points (x1, y1, z1) and (x2, y2, z2) is Plus One Maths Notes Chapter 12 Introduction to Three Dimensional Geometry 3

Section formula:
1. Internal: The coordinate of the point R which divides the line segment joining the points (x1, y1, z1) and (x2, y2, z2) internally in the ratio l : m is Plus One Maths Notes Chapter 12 Introduction to Three Dimensional Geometry 4

2. External: The coordinate of the point R which divides the line segment joining the points (x1, y1, z1) and (x2, y2, z2) externally in the ratio l : m is Plus One Maths Notes Chapter 12 Introduction to Three Dimensional Geometry 5

3. Midpoint: The coordinate of the point R which is the midpoint of the line segment joining the points (x1, y1, z1) and (x2, y2, z2) is Plus One Maths Notes Chapter 12 Introduction to Three Dimensional Geometry 6

4. Centroid: The coordinate of the centroid of a triangle whose vertices are given by the points (x1, y1, z1), (x2, y2, z2) and (x3, y3, z3) is Plus One Maths Notes Chapter 12 Introduction to Three Dimensional Geometry 7

Plus One Maths Notes Chapter 11 Conic Sections

Kerala State Board New Syllabus Plus One Maths Notes Chapter 11 Conic Sections.

Kerala Plus One Maths Notes Chapter 11 Conic Sections

I. Circle
A circle is the set of all points in a plane that are equidistant from a fixed point in the plane. The fixed point is the centre and the fixed distance is the radius.
Equation of a circle with centre origin and radius r is x2 + y2 = r2.

Equation of a circle with centre (h, k) and radius r is (x – h)2 + (y – k)2 = r2.

General form of the equation of a circle is x2 + y2 + 2gx + 2fy + c = 0 with centre (-g, -f) and radius \(\sqrt{g^{2}+f^{2}-c}\).

II. Conic
A conic is the set of all points in a plane which moves so that the distance from a fixed point is in a constant ratio to its distance from a fixed-line. The fixed point is the focus and fixed line is directrix and the constant ratio is eccentricity, denoted by ‘e’.

III. Parabola (e = 1)

y2 = 4ax
Plus One Maths Notes Chapter 11 Conic Sections 1
Vertex: (0, 0)
Focus(S): (a, 0)
Length of Latusrectum: (LL’) = 4a
Equation of directrix (DD’) is x = -a

y2 = -4ax
Plus One Maths Notes Chapter 11 Conic Sections 2
Vertex: (0, 0)
Focus(S): (-a, 0)
Length of Latusrectum (LL’) = 4a
Equation of directrix (DD’) is x = a

x2 = 4ay
Plus One Maths Notes Chapter 11 Conic Sections 3
Vertex: (0, 0)
Focus(S): (0, a)
Length of Latusrectum (LL’) = 4a
Equation of directrix (DD’) is y = -a

x2 = -4ay
Plus One Maths Notes Chapter 11 Conic Sections 4
Vertex: (0, 0)
Focus(S): (0, -a)
Length of Latusrectum (LL’) = 4a
Equation of directrix (DD’) is y = a

IV. Ellipse (e < 1)

\(\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1\), a > b
Plus One Maths Notes Chapter 11 Conic Sections 5
1. Eccentricity, e = \(\frac{\sqrt{a^{2}-b^{2}}}{a}\)
(ae)2 = a2 – b2 ⇒ c2 = a2 – b2
2. b2 = a2(1 – e2)
3. Length of Latusrectum (LL’) = \(\frac{2 b^{2}}{a}\)
4. Focii, S(ae, 0) and S'(-ae, 0) or S(c, 0), S'(-c, 0)
5. Centre (0, 0)
6. Vertices A(a, 0) and A'(-a, 0)
7. Equation of directrix (DD’) is x = \(\frac{a}{e}\) and x = \(-\frac{a}{e}\)
8. Length of major axis (AA’) = 2a
9. Length of minor axis'(BB’) = 2b

\(\frac{x^{2}}{b^{2}}+\frac{y^{2}}{a^{2}}=1\), a > b
Plus One Maths Notes Chapter 11 Conic Sections 6
1. Eccentricity, e = \(\frac{\sqrt{a^{2}-b^{2}}}{a}\)
(ae)2 = a2 – b2 ⇒ c2 = a2 – b2
2. b2 = a2(1 – e2)
3. Length of Latus rectum (LL’) = \(\frac{2 b^{2}}{a}\)
4. Focii, S(0, ae) and S'(0, -ae) or S(0, c), S'(0, -c)
5. Centre (0, 0)
6. Vertices A(0, a) and A'(0, -a)
7. Equation of directrix (DD’) is y = \(\frac{a}{e}\) and y = \(-\frac{a}{e}\)
8. Length of major axis (AA’) = 2a
9. Length of minor axis (BB’) = 2b

V. Hyperbola (e > 1)

\(\frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=1\)
Plus One Maths Notes Chapter 11 Conic Sections 7
1. Eccentricity, e = \(\frac{\sqrt{a^{2}+b^{2}}}{a}\)
(ae)2 = a2 + b2 ⇒ c2 = a2 + b2
2. b2 = a2(e2 – 1)
3. Length of Latus rectum (LL’) = \(\frac{2 b^{2}}{a}\)
4. Focii, S(ae, 0) and S'(-ae, 0) or S(c, 0), S'(-c, 0)
5. Centre (0, 0)
6. Vertices A(a, 0) and A'(-a, 0)
7. Equation of directrix (DD’) is x = \(\frac{a}{e}\) and x = \(-\frac{a}{e}\)

\(\frac{y^{2}}{a^{2}}-\frac{x^{2}}{b^{2}}=1\)
Plus One Maths Notes Chapter 11 Conic Sections 8
1. Eccentricity, e = \(\frac{\sqrt{a^{2}+b^{2}}}{a}\)
(ae)2 = a2 + b2 ⇒ c2 = a2 + b2
2. b2 = a2(e2 – 1)
3. Length of Latus rectum (LL’) = \(\frac{2 b^{2}}{a}\)
4. Focii, S(0, ae) and S'(0, -ae) or S(0, c), S'(0, -c)
5. Centre (0, 0)
6. Vertices A(0, a) anti A'(0, -a)
7. Equation of directrix (DD’) is y = \(\frac{a}{e}\) and y = \(-\frac{a}{e}\)

Plus One Maths Notes Chapter 10 Straight Lines

Kerala State Board New Syllabus Plus One Maths Notes Chapter 10 Straight Lines.

Kerala Plus One Maths Notes Chapter 10 Straight Lines

I. Slope of Line
The slope of a line is the ‘tan’ of the angle the line makes with the positive direction of the x-axis. If θ is the angle then, slope = tan θ.

The slope of the x-axis is zero and that of the y-axis is not defined.

Parallel lines have the same slope.

The product of the slopes of perpendicular lines is -1.

The slope is positive if θ < 90°. The slope is negative if θ > 90°.

The slope of a line passing through two points (x1, y1) and (x2, y2) is \(\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\)

If three points A, B, and C are collinear, then AB and BC have the same slope.

If m1 and m2 be slopes of two lines then, θ the angle between is given by tan θ = \(\left|\frac{m_{2}-m_{1}}{1+m_{1} m_{2}}\right|\), 1 + m1m2 ≠ 0

II. Equation of a Line
Equation of x-axis is y = 0.

Equation of y-axis is x = 0.

The equation of a horizontal line is y = a. If ‘a’ is positive then the line is above the x-axis and if negative it will be below the x-axis.

The equation of a vertical line is x = a. If ‘a’ is positive then the line is to the right of the x-axis and if negative it will be to the left of the x-axis.

Point-slope form: y – y1 = m(x – x1), where ‘m’ is the slope and (x1, y1) is a point on the line.

Two-Point form:
y – y1 = \(\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\) (x – x1) where (x1, y1) and(x2, y2) are two point on the line.

Slope intercept form:
1. y = mx + c, where ‘m’ is the slope and ‘c’ is the y-intercept.
2. y = m(x – d), where ‘m’ is the slope and ‘d’ is the x-intercept.

Intercept form: \(\frac{x}{a}+\frac{y}{b}=1\) = 1, where ‘a’ and ‘b‘ are x and y intercept respectively.

Normal form: x cos θ + y sin θ = p, where ‘p’ is the length of the normal from the origin to the line and ‘θ’ is the angle the normal makes with the positive direction of the x-axis.

General equation of a Line: ax + by + c = 0, where a, b and c are real constants.
1. Slope of the line ax + by + c = 0 is \(-\frac{a}{b}\)

2. Parallel lines differ in constant term, i.e; a line parallel to ax + by + c = 0 is ax + by + k = 0.

3. A line perpendicular to ax + by + c = 0 is bx – ay + k = 0.

4. The equation of the family of lines passing through the intersection of the lines a1x + b1y + c1 = 0 and a2x + b2y + c2 = 0 is of the form a1x + b1y + c1 + k(a2x + b2y + c2) = 0.

5. The perpendicular distance of a point (x1, y1) from the line ax + by + c = 0 is \(\left|\frac{a x_{1}+b y_{1}+c}{\sqrt{a^{2}+b^{2}}}\right|\)

6. The distance between the parallel lines ax + by + c = 0 and ax + by + k = 0 is \(\left|\frac{c-k}{\sqrt{a^{2}+b^{2}}}\right|\)

7. Normal form of the equation ax + by + c = 0 is x cos θ + y sin θ = p;
Where cos θ = \(\pm \frac{a}{\sqrt{a^{2}+b^{2}}}\); sin θ = \(\pm \frac{b}{\sqrt{a^{2}+b^{2}}}\) and p = \(\pm \frac{c}{\sqrt{a^{2}+b^{2}}}\)

Proper choice of signs is made so that p should be positive.

III. Shifting of Origin
An equation corresponding to a set of points with reference to a system of coordinate axes by shifting the origin is shifted to a new point is called a translation of axes.

Let us take a point P (x, y) referred to the axes OX and OY. Let (h, k) be the coordinates of origin and P(X, Y) be the coordinate of P(x, y) with respect to the new axis. Then, the transformation relation between the old coordinates (x, y) and the new coordinates (X, Y) are given by X = x + h and Y = y + k.

Plus One Maths Notes Chapter 7 Permutation and Combinations

Kerala State Board New Syllabus Plus One Maths Notes Chapter 7 Permutation and Combinations.

Kerala Plus One Maths Notes Chapter 7 Permutation and Combinations

I. Fundamental Principle of Counting
If an event can occur in ‘m’ different ways, following which another event can occur in ‘n’ different ways, then the total number of occurrences of the events in the given order is m × n.

II. Permutation
A permutation is the arrangement of some or all of a number of different objects.

Factorial notation: The notation n! represents the product of first n natural numbers,
ie; n! = n(n – 1 )(n – 2) ….. 3.2.1
1. 1! = 1
2. 0! = 1

The number of permutation of ‘n’ different objects taken ‘r’ at a time, where the objects do not repeat is n(n – 1)(n – 2)……(n – r + 1) which is denoted by nPr.
Plus One Maths Notes Chapter 7 Permutation and Combinations 1
The number of permutation of ‘n’ different objects taken ‘r’ at a time, where repetition is allowed is nr.

Permutation when all the objects are not distinct.
1. The number of permutations of ‘n’ objects, where ‘p’ objects are of the same kind and rest all different = \(\frac{n !}{p !}\)

2. The number of permutations of ‘n’ objects, where ‘p1’ objects are of one kind, ‘p2’ objects are of the second kind, …….., ‘pk‘ objects are of a kth kind and rest all different = \(\frac{n !}{p_{1} ! p_{2} ! \ldots p_{k} !}\)

III. Combinations
A combination is a selection of some or all of a number of different objects (the order of selection is not important). The number of selection of ‘n’ things taken ‘r’ at a time is nCr.
Plus One Maths Notes Chapter 7 Permutation and Combinations 2

Plus One Maths Notes Chapter 5 Complex Numbers and Quadratic Equations

Kerala State Board New Syllabus Plus One Maths Notes Chapter 5 Complex Numbers and Quadratic Equations.

Kerala Plus One Maths Notes Chapter 5 Complex Numbers and Quadratic Equations

we have studied linear equations in one and two variables and quadratic equations in one variable. We have seen that the equation x2 + 1 = 0 has no real solution since the root of a negative number does not exist in a real number. So, we need to extend the real number system to a larger number system to accommodate such numbers.

I. Complex Numbers
A number of the form a + ib, where a and b are real numbers and i = √-1.
Usually, a complex number is denoted by z, a is the real part of z denoted by Re(z) and b is the imaginary part of z denoted by Im(z).

II. Algebra of Complex Numbers

Addition: Let z1 = a + ib and z2 = c + id be two complex numbers. Then the sum z1 + z2 is obtained by adding the real and imaginary parts.

1. z1 + z2 = z2 + z1, commutative.
2. z1 + (z2 + z3) = (z1 + z2) + z3, associative.
3. 0 + i0 is the identity element.
4. -z is the inverse of z.

Multiplication: Let z1 = a + ib and z2 = c + id be two complex numbers.
Then the product z1z2 is defined as follows:
z1z2 = (ac – bd) + i(ad + bc).

1. z1z2 = z2z1, commutative.
2. z1(z2z3) = (z1z2)z3, associative.
3. 1 + i0 is the identity element.
4. \(\frac{1}{z}\) is the inverse of z.
5. z1(z2 + z3) = z1z2 + z1z3, distributive law.

Power of ‘i’: i3 = -i, i4 = 1
In general i4k = 1, i4k+1 = i, i4k+2 = -1, i4k+3 = -i

Identities:
Plus One Maths Notes Chapter 5 Complex Numbers and Quadratic Equations 1
Plus One Maths Notes Chapter 5 Complex Numbers and Quadratic Equations 2

The Modulus and Conjugate of a complex number:
Consider a complex number z = a + ib . Then, the conjugate of z is denoted by \(\bar{z}\), defined as \(\bar{z}\) = a – ib and the modulus of z is denoted by |z|, defined as \(\sqrt{a^{2}+b^{2}}\).

Properties:
Plus One Maths Notes Chapter 5 Complex Numbers and Quadratic Equations 3

III. Representation of Complex Number

Argand Plane:
Plus One Maths Notes Chapter 5 Complex Numbers and Quadratic Equations 4
A complex number z = a + ib which corresponds to the ordered pair (a, b) can be represented geometrically as the unique point P(a, b) in the XY-plane, where the real part is taken along the x-axis and the imaginary part along the y-axis. Such a plane is called the Argand Plane or Complex plane.

Polar Form:
Plus One Maths Notes Chapter 5 Complex Numbers and Quadratic Equations 5
Let the point P represent the non-zero complex number z = x + iy. Let the directed line segment OP be of length ‘r’ and be the angle which OP makes with the positive direction of the x-axis. Then, P is determined by the unique ordered pair of a real number (r, θ) called polar coordinate of the point P, where x = r cos θ, y = r sin θ and therefore the polar form of z can be represented as z = r(cos θ + i sin θ).
The principle argument of z is value ‘θ’ such that -x ≤ θ ≤ π, denoted by arg z.
To find the principle argument, we find tan α = |\(\frac{y}{x}\)|, 0 ≤ α ≤ \(\frac{\pi}{2}\)

The quadrant on which ‘P’ liesarg z =
Iα
IIπ – α
IIIα – π
IV
Positive real axis0
Negative real axisπ
Positive imaginary axis\(\frac{\pi}{2}\)
Negative imaginary axis\(-\frac{\pi}{2}\)

Plus One Maths Notes Chapter 4 Principle of Mathematical Induction

Kerala State Board New Syllabus Plus One Maths Notes Chapter 4 Principle of Mathematical Induction.

Kerala Plus One Maths Notes Chapter 4 Principle of Mathematical Induction

Induction means the generalization from a particular case or facts. In contrast to deductive reasoning, inductive depends on working with each case and developing a conjecture by observing incidences till we have observed each and every case. In algebra or in another discipline of mathematics, there are certain results or statements that are formulated in terms of n, where n is a positive integer. To such statements, the well-suited principle that is based on the specific technique is known as the principle of mathematical induction.

The Principle of Mathematical Induction:
Suppose there is a statement P(n) involving the natural number n such that

1. The statement is true for n = 1, i.e; P(1) is true, and

2. If the statement is true for n = k (where k is some positive integer), then the statement is also true for n = k + 1, i.e; the truth of P(k) implies the truth of P(k+1). Then, P(n) is true for all natural numbers n.

Plus One Maths Notes Chapter 3 Trigonometric Functions

Kerala State Board New Syllabus Plus One Maths Notes Chapter 3 Trigonometric Functions.

Kerala Plus One Maths Notes Chapter 3 Trigonometric Functions

I. Angles
The measure of an angle is the amount of rotation performed to get the terminal side from the initial side.

1. Degree measure: If a rotation from the initial side to terminal side is \(\left(\frac{1}{360}\right)^{t h}\) of a revolution, the angle is said to have a measure of one degree, written as 1°. 1° = 60′ and f = 60″.

2. Radian measure: An angle subtended at the center by an arc of length 1 unit in a unit circle is said to be of 1 radian. Radian measure is a real number corresponding to degree measure.

180° = π radians

Radian measure = \(\frac{\pi}{180}\) × Degree measure

Degree measure = \(\frac{180}{\pi}\) × Radian measure

l = rθ, where l = arc length, r = radius of the circle and θ = angle in radian measure.

II. Trigonometric Function
Consider a unit circle with centre at the origin of the coordinate axis.
Let P (a, b) be any point on the circle which makes an angle θ° with the x-axis. Let x be the corresponding radian measure of the angle θ°, i.e; x is the arc length corresponding to θ°.

Plus One Maths Notes Chapter 3 Trigonometric Functions 1

From the ∆OMP’m the figure we get;
sin θ = sin x = \(\frac{b}{1}\) = b and cos θ = cos x = \(\frac{b}{1}\) = a
This means that for each real value of x we get corresponding unique ‘sin’ and ‘cosine’ value which is also real. Hence we can define the six trigonometric functions as follows.

1. f : R → [-1, 1] defined by f(x) = sin x
Plus One Maths Notes Chapter 3 Trigonometric Functions 2

2. f : R → [-1, 1] defined by f(x) = cos x
Plus One Maths Notes Chapter 3 Trigonometric Functions 3

3. f : R – {nπ, n ∈ Z} → R – (-1, 1) defined by f(x) = \(\frac{1}{\sin x}\) = cosec x
Plus One Maths Notes Chapter 3 Trigonometric Functions 4

4. f : R – {(2n + 1) \(\frac{\pi}{2}\)} → R – (-1, 1) defined by f(x) = \(\frac{1}{\cos x}\) = sec x
Plus One Maths Notes Chapter 3 Trigonometric Functions 5

5. f : R – {(2n + 1)π, n ∈ Z} → R defined by f(x) = \(\frac{\sin x}{\cos x}\) = tan x
Plus One Maths Notes Chapter 3 Trigonometric Functions 6

6. f : R – {nπ, n ∈ Z} → R defined by f(x) = \(\frac{\cos x}{\sin x}\) = cot x
Plus One Maths Notes Chapter 3 Trigonometric Functions 7

Sign of trigonometric functions in different quadrants;
Plus One Maths Notes Chapter 3 Trigonometric Functions 8
For odd multiple of \(\frac{\pi}{2}\) trignometric functions changes as given below.
sin → cos
cos → sin
sec → cosec
cosec → sec
tan → cot
cot → tan

The value of trigonometric functions for some specific angles;
Plus One Maths Notes Chapter 3 Trigonometric Functions 9

III. Compound Angle Formula

sin(x + y) = sin x cos y + cos x sin y

sin(x – y) = sin x cos y – cos x sin y

cos(x + y) = cos x cos y – sin x sin y

cos(x – y) = cos x cos y + sin x sin y
Plus One Maths Notes Chapter 3 Trigonometric Functions 10
sin(x + y) sin(x – y) = sin2 x – sin2 y = cos2 x – cos2 y

cos(x + y) cos(x – y) = cos2 x – sin2 y
Plus One Maths Notes Chapter 3 Trigonometric Functions 11

IV. Multiple Angle Formula

cos2x = cos2 x – sin2 x
= 1 – 2sin2 x
= 2 cos2 x – 1
= \(\frac{1-\tan ^{2} x}{1+\tan ^{2} x}\)

Plus One Maths Notes Chapter 3 Trigonometric Functions 12

V. Sub-Multiple Angle Formula
Plus One Maths Notes Chapter 3 Trigonometric Functions 13

Plus One Maths Notes Chapter 3 Trigonometric Functions 14

VI. Sum Formula
Plus One Maths Notes Chapter 3 Trigonometric Functions 16

VII. Product Formula

2 sin x cos y = sin(x + y) + sin(x – y)

2 cos x sin y = sin(x + y) – sin(x – y)

2 cos x cos y = cos(x + y) + cos(x – y)

2 sin x sin y = cos(x – y) – cos(x + y)

VIII. Solution of Trigonometric Equations

sin x = 0 gives x = nπ, where n ∈ Z

cos x = 0 gives x = (2n + 1)π, where n ∈ Z

tanx = 0 gives x = nπ, where n ∈ Z

sin x = sin y ⇒ x = nπ + (-1)n y, where n ∈ Z

cos x = cos y ⇒ x = 2nπ ± y, where n ∈ Z

tan x = tan y ⇒ x = nπ + y, where n ∈ Z

Principal solution is the solution which lies in the interval 0 ≤ x ≤ 2π.

IX. Sine and Cosine formulae

Let ABC be a triangle. By angle A we mean the angle between the sides AB and AC which lies between 0° and 180°. The angles B and C are similarly defined. The sides AB, BC, and CA opposite to the vertices C, A, and B will be denoted by c, a, and b, respectively.

Theorem 1 (sine formula): In any triangle, sides are proportional to the sines of the opposite angles. That is, in a triangle ABC
\(\frac{\sin A}{a}=\frac{\sin B}{b}=\frac{\sin C}{c}\)

Theorem 2 (Cosine formulae): Let A, B and C be angles of a triangle and a, b and c be lengths of sides opposite to angles A, B, and C, respectively, then
a2 = b2 + c2 – 2bc cos A
b2 = c2 + a2 – 2ca cos B
c2 = a2 + b2 – 2ab cos C

A convenient form of the cosine formulae, when angles are to be found are as follows:
Plus One Maths Notes Chapter 3 Trigonometric Functions 15

Plus One Maths Notes Chapter 2 Relations and Functions

Kerala State Board New Syllabus Plus One Maths Notes Chapter 2 Relations and Functions.

Kerala Plus One Maths Notes Chapter 2 Relations and Functions

I. Cartesian Product or Cross Product:
The Cartesian product between two sets A and B is denoted by A × B is the set of all ordered pairs of elements from A and B.
ie; A × B = {(a, b): a ∈ A, b ∈ B}

Properties:

  1. In general A × B ≠ B × A, but if A = B, A × B = B × A.
  2. n(A × B) = n(A) × n(B)
  3. n(A × B) = n(B × A)

II. Relations:
A relation R from a non-empty set A to a non-empty set B is a subset of the Cartesian product A × B.

Representation of a relation:

  1. Roster form
  2. Set builder form
  3. Arrow diagram.

Universal relation from A to B is A × B.

Empty relation from A to B is empty set φ.

A relation in A is a subset of A × A.

The number of relation that can be written from A to B if n(A) = p, n(B) = q is 2pq.

Domain: It is the set of all first elements of the ordered pairs in a relation.

Range: It is the set of all second elements of the ordered pairs in a relation.
If R: A → B, then R(R) ⊆ B.

Co-domain: If R: A → B, then Co-domain of R = B.

III. Functions:
A relation f from A to B (f : A → B) is said to be a function if every element of set A has one and only one image in set B.

If f : A → B is a function defined by f(x) = y.

  1. The image of x = y
  2. The pre-image of y = x
  3. Domain of f = {x ∈ A : f(x) ∈ B}
  4. Range of f = {f(x) : x ∈ D(f)}
  5. If f : A → B, then n(f) = n(B)n(A)

IV. Some Important Functions

Identity function: A function f : R → R defined by f(x) = x. Here D(f) = R, R(f) = R.
The graph of the above function is a straight line passing through the origin which makes 45 degrees with the positive direction of the x-axis.

Constant function: A function f : R → R defined by f(x) = c, where c is a constant.
Here D(f ) = R, R(f) = {c}.
The graph of the above function is a straight line parallel to the x-axis.

Polynomial function: A function f : R → R defined by
f(x) = a0 + a1x + ….. + anxn, where n is a no-negative integer and a0, a1, …., an ∈ R.

Rational function: A function f: R → R defined by \(f(x)=\frac{p(x)}{q(x)}\), where p(x), q(x) are functions of x defined in a domain, where q(x) ≠ 0

Modulus function: A function f: R → R
Plus One Maths Notes Chapter 2 Relations and Functions 1
Here D(f) = R, R(f) = [0, ∞).
The graph of the above function is ‘V’ shaped with a corner at the origin.

Signum function: A function f: R → R
Plus One Maths Notes Chapter 2 Relations and Functions 2
Here D(f) = R, R(f) = {-1, 0, 1}.
The graph of the above function has a break at x = 0.

Greatest integer function f: R → R defined by
Plus One Maths Notes Chapter 2 Relations and Functions 3
Here D(f) = R, R(f) = Z.
The graph of the above function has broken at all integral points.

V. Algebra of Functions

Let f : X → R and g : X → R be any two real functions, where X ⊂ R. Then, we define (f + g) : X → R by (f + g)(x) = f(x) + g(x) for all x ∈ X

Let f : X → R and g : X → R be any two real functions, where X ⊂ R. Then, we define (f – g) : X → R by (f – g)(x) = f(x) – g(x) for all x ∈ X

Let f : X → R be a real-valued function and k be a scalar. Then, the product kf : X → R by (kf)(x) = kf (x) for all x ∈ X

Let f : X → R and g : X → R be any two real functions, where X ⊂ R . Then, we define fg : X → R by fg(x) = f(x) × g(x) for all x ∈ X

Let f : X → R and g : X → R be any two real functions, where X ⊂ R. Then, we define \(\frac{f}{g}\) : X → R by
\(\left(\frac{f}{g}\right)(x)=\frac{f(x)}{g(x)}\) for all x ∈ X

Plus One Maths Notes Chapter 1 Sets

Kerala State Board New Syllabus Plus One Maths Notes Chapter 1 Sets.

Kerala Plus One Maths Notes Chapter 1 Sets

I. Sets
Set is a well-defined collection of distinct objects.
Examples of sets.

  • N: Set of Natural numbers.
  • Z: Set of Integers.
  • Q: Set of Rational numbers.
  • R: Set of Real numbers.
  • Z+: Set of Positive Integers numbers.
  • Q+: Set of Positive Rational numbers.
  • R+: Set of Positive Real numbers.

Representation of Sets:

  1. Roster Form: All elements are listed, are separated by commas, and closed using brackets.
  2. Set-builder Form: All elements of a set possess a single common property which is not possessed by any elements outside the set.
  3. Venn Diagram: Here sets are represented by diagrams. These diagrams consist of rectangles and closed curves usually circles. The universal et is represented by a rectangle and its subsets by circles.

II. Types of Sets:

Empty set: Set contains no element, φ or {}.

Singleton set: Set containing one element.

Finite set: Set containing a definite number of elements.

Infinite set: Set containing an infinite number of elements..

Equivalent set: Sets containing an equal number of elements.

Equal set: Sets containing identical elements.

Subset: If every element of A is an element of B, denoted by A ⊂ B. For any set A, the set A and Empty set is a subset of A. If a set A has n elements, then it has 2n subsets.

Superset: B is a superset if A is a subset of B, denoted by B ⊃ A.

Proper Subset: If A ⊂ B and A ≠ B.

Power set: The set of all subsets of a set A, denoted by P(A). If n(A) = n, then n(P(A)) = 2n

Universal set: The superset of all subsets under discussion.

Intervals as subset of R:

  1. [a, b] = {x : a ≤ x ≤ b}, closed interval.
  2. (a, b] = {x : a < x ≤ b]
  3. [a, b) = {x : a ≤ x < b}
  4. (a, b) = {x : a < x < b}, open interval.

III. Operations on Sets

Union of Sets: The union of A and B is the set which consists of all elements of A and all elements of B except the common elements. In symbol we write as A ∪ B = {x : x ∈ A or x ∈ B}.
Venn diagram representation:
Plus One Maths Notes Chapter 1 Sets 1
Properties:

  1. A ∪ B = B ∪ A, Commutative.
  2. (A ∪ B) ∪ C = A ∪ (B ∪ C), Associative
  3. A ∪ φ = A, φ is the identity.
  4. A ∪ A = A
  5. U ∪ A = U

Intersection of Sets: The intersection of A and B is the set of common elements of both A and B.
In symbol, we write as A ∩ B = {x : x ∈ A and x ∈B}.
Venn diagram representation:
Plus One Maths Notes Chapter 1 Sets 2
Properties:

  1. A ∩ B = B ∩ A, Commutative.
  2. (A ∩ B) ∩ C = A ∩ (B ∩ C), Associative
  3. A ∩φ = φ
  4. A ∩ A = A
  5. U ∩ A = A
  6. A ∩ (B ∪ C) = (A ∩ B) ∪ (A ∩ C)
  7. n(A ∪ B) = n(A) + n(B) – n(A ∩ B)
  8. If A and B are disjoint, then n(A ∪ B) = n(A) + n(B)
  9. n(A ∪ B ∪ C) = n(A) + n(B) + n(C) – n(A ∩ B) – n(B ∩ C) – n(C ∩ A) + n(A ∩ B ∩ C)

Difference of Sets: The difference of the sets A and B in this order is the set of elements which belongs to A but not to B, denoted by A – B = {x : x ∈ A and x ∉ B}
Venn diagram representation:
Plus One Maths Notes Chapter 1 Sets 3
Property: A – B ≠ B – A

Complement of a Set: The complement of a set A is the set of all elements of U which are not in A, denoted by
A’ = {x : x ∈ U and x ∉ A}
Venn diagram representation:
Plus One Maths Notes Chapter 1 Sets 4
Properties:

  1. A’ ∪ A = U, Commutative.
  2. A’ ∩ A = φ, Associative
  3. (A ∩ B)’ = A’ ∪ B’
  4. (A ∪ B)’ = A’ ∩ B’
  5. U’ = φ
  6. φ’ = U
  7. (A)’ = A
  8. A – B = A ∩ B’
  9. n(A – B) = n(A ∩ B’)
  10. n(A) = n(A ∩ B’) + n(A ∩ B)
  11. n(A ∪ B) = n(A ∩ B’) + n(A’ ∩ B) + n(A ∩ B)

Plus One Hindi Textbook Answers Unit 4 Chapter 15 कहना नहीं आता

Kerala State Board New Syllabus Plus One Hindi Textbook Answers Unit 4 Chapter 15 कहना नहीं आता Text Book Questions and Answers, Summary, Notes.

Kerala Plus One Hindi Textbook Answers Unit 4 Chapter 15

निम्नलिखित कवितांश पढ़ें और प्रश्नों के उत्तर लिखें।

कहना नहीं आता
तुम्हें कहना नहीं आता
कहने क्यों चले आए
पहले कहना सीखो
फिर अपनी बात कहना

जिनके पास कहने को है
जो कहना चाहते हैं
जिन्हें कहना नहीं आता
मैं उनमें से एक हूँ।

प्रश्न 1.
‘तुम्हें कहना नहीं आता’
‘तुम्हें’ किन-किनका प्रतिनिधित्व करते हैं?
उत्तर:
भारत के शोषित और उपेक्षित लोगों का प्रतिनिधित्व करते हैं।

प्रश्न 2.
‘पहले कहना सीखो
फिर अपनी बात कहना’
ऐसा कौन कह रहा है?
उत्तर:
समाज का शक्तिशाली शोषक वर्ग

प्रश्न 3.
‘मैं उनमें से एक हूँ’
‘मैं’ किन-किनका प्रतिनिधि है?
उत्तर:
भारत में हाशिए पर छोडे गये शोषित और उपेक्षित जनता का प्रतिनिधि है।

प्रश्न 4.
कविता की आस्वादन-टिप्पणी लिखें।
उत्तरः
निशब्द जनता
‘कहना नहीं आता’ एक प्रतीकात्मक कविता है। यह आधुनिक काव्य-शैली की कविता है। इसके कवि सुप्रसिद्ध हिंदी कवि पवन करण हैं।

भारतीय समाज के लगभग 80 प्रतिशत लोग हाशिए पर जीनेवाले हैं। वे शोषित और उपेक्षित हैं। वे अपनी पीड़ा और व्यथा मौन सहती हैं। वे अपनी बात कहना चाहते हैं, लेकिन उसे कहने का अवसर नहीं दिया जाता है। वे अपने संघर्ष कहने की कोशिश करते हैं, तो दुत्कारते हुए कहा जाता है ‘तुम्हें कहना कहाँ आता है।’ उनसे यह चेतावनी दी जाती है ‘जाओ पहले कहना सीखकर आओ। तब आकर अपनी बात कहना।’ कवि कहते हैं कि कवि भी इन बेचारों में से एक है जो कहना चाहते हैं, लेकिन चुप रहते हैं।

‘कहना नहीं आता’ भारत के विविधता भरे समाज के एक बड़ा भाग, जो शोषित और उपेक्षित है, उसका प्रतिनिधित्व करती है। कविता की भाषा सरल है, लेकिन प्रतीकात्मकता के कारण सशक्त है। छोटी कविता द्वारा बड़े यथार्थ को कवि ने प्रस्तुत किया है। भाषा प्रवाहमयी एवं साधारण जनता की समझ की है। कविता प्रासंगिक है। शीर्षक अत्यन्त प्रभावमय है।

Plus One Hindi कहना नहीं आता Important Questions and Answers

प्रश्न 1.
‘हाशिएकृत नारी’ संगोष्ठी संबन्धी बातें;
उत्तरः
विषयः भगवान ने मनुष्य को नर और नारी दोनों की सृष्टि की। नर और नारी परस्पर पूरक हैं। एक के बिना दूसरे का अस्तित्व नहीं है। लेकिन संसार में समय की गति में नारी तिरस्कृत अवस्था में पड़ गयी। संसार-भर यह दुरवस्था लोक-सृष्टि के आरंभ से उपस्थित है। परिवर्तन तो ज़रूर हुए हैं। लेकिन आज भी नारी तिरस्कृत अवस्था में है। इस अवस्था को चर्चा के मुख्य विषय बनाकर संगोष्ठी चलाना सचमुच उचित है।

उपविषय -1 नारी की पार्श्ववत्कृत अवस्था का ऐतिहासिक दृष्टिकोण में।
उपविषय -2 नारी की पर्श्ववत्कृत अवस्था भारतीय दृष्टिकोण में।
उपविषय -3 धार्मिक ग्रन्थों में नारी संबंधी सिद्धान्त।
उपविषय -4 भारत की कुछ आदर्श महिलाएँ।
उपविषय -5 नारी ही नारी का शत्रु है।

उपसंहार : कुछ ऐसी महिलायें भारत में और अन्य देशों में ज़रूर हैं जो समाज की मुख्यधारा में श्रद्धेय हो गयी हैं। लेकिन बड़े पैमाने पर विशेषकर भारत में अधिकांश नारियाँ हाशिए पर ही है। आयोजनाएँ अनेक तो हो रही हैं, जिनसे नारी की अवस्था सुधर जाये । नारी के पार्श्ववत्कृत अवस्था से मोचित कराने के लिए हम साथ दें। नारी को अपने ही पैरों पर खड़ी रहने के लिए हम सदा साथ दें। ‘How old are you’ जैसी फिल्मों में प्रस्तुत निरुपमा जैसी नारियों की ओर आगे बढ़ने के लिए नारी सत्ता को हम जगायें। नारी होना अभिशाप नहीं, वरदान है। नारी हाशिए पर नहीं, मुख्यधारा में उपस्थित होनी चाहिए।

संगोष्ठीः आलेख
भागवान ने मनुष्य को नर और नारी के रूप में सृष्टि की। नर और नारी बराबर के हैं। वे परस्पक पूरक हैं। एक के अलावा दुसरे का अस्तित्व नहीं है।

संसार के विकास के आरंभ से ही नारी तिरस्कृत अवस्था में है। भारत में नारी को ‘देवी माँ’ समझा जाता है। ‘मनुस्मृति’ में नारी के बारे में विकल दृष्टिकोण रखने पर भी भारतीय संस्कृति में नारी ज़रूर बड़े महत्वपूर्ण स्थान में है। फिर भी, दुनिया में सबसे पार्श्ववत्कृत नारीगण भारत में ही है। रानी लक्ष्मी बाई, कल्पना चौला, मदर तेरेसा जैसी अनेक आदर्श महिलाओं को भारत ने ही जन्म दिया है। फिर भी, कुटुंब, समाज, रोज़गार आदि सभी क्षेत्रों में भारत के नारीगण बड़े पैमाने पर पार्श्ववत्कृत अवस्था में ही है। बालिका भ्रूणहत्या, अशिक्षित स्त्री संख्या, बालिका विवाह, नारी आत्महत्या, दहेज-प्रथा आदि अनेक क्षेत्र हैं, जिनसे हमें मालूम होता है कि भारतीय नारी तिरस्कृत और उपेक्षित अवस्था में फँस गयी है।

नारी को विशेषकर भारतीय नारी को पार्श्ववत्कृत अवस्था से उठायें। नारी कभी भी नारी का शत्रु न बन जाये। स्त्री सत्ता की खूबियों से भारत का भविष्य उज्ज्वल बनायें।

निम्नांकित गद्यांश पढ़ें और नीचे दिए प्रश्नों के उत्तर लिखें।

एक दिन विष्णुजी के पास गए नारदजी। उसने विष्णुजी से पूछा, ‘मर्त्यलोक में वह कौन है भक्त तुम्हारा प्रधान?’
विष्णुजी ने कहा, ‘एक सज्जन किसान है, प्राणों से प्रियतम।’ नारद ने कहा, ‘मैं उसकी परीक्षा लूंगा’। यह सुनकर विष्णु हँसे और कहा कि, ‘ले सकते हो।’ नारदजी चल दिए। पहूँचे भक्त के यहाँ।

उसने देखा – हल जोतकर आया दुपहर को एक किसान को । किसान अपने घर के दरवाज़े पहूँ च क र रामजी का नाम लिया; स्नान-भोजन करके फिर चला गया काम पर ।

शाम को फिर वह आया दरवाज़े, फिर नाम लिया; प्रातःकाल चलते समय एक बार फिर उसने राम का मधुर नाम स्मरण किया। ‘बस केवल तीन बार!’ नारद चकरा गए- “दिवारात जपते हैं नाम ऋषि-मुनि लोग किंतु भगवान को किसान ही यह याद आया।”

प्रश्न 1.
‘मानव की दुनिया’ इस अर्थ में प्रयुक्त शब्द कौन-सा हैं।
उत्तर:
मर्त्यलोक

प्रश्न 2.
नारदजी के आश्चर्य का क्या कारण था?
उत्तर:
ऋषि-मुनि लोग दिवारात भगवान का नाम जपते हैं।
लेकिन, भगवान को किसान की याद आती है।

प्रश्न 3.
गद्यांश के आधार पर नारदजी और विष्णुजी के बीच के वार्तालाप लिखें।
उत्तर:
नारद : जय हो!
विष्णु : कहिए नारदजी।
नारद विष्णु : मर्त्यलोक में …..
विष्णु : हाँ… आगे कहिए……
नारद : आप का प्रधान भक्त कौन है?
विष्णु : किसान है।
नारद : यह तो आश्चर्य की बात है।
विष्णु : मेरा नाम जपते हैं।
नारद : कौन-कौन?
विष्णु : दिवारात ऋषि-मुनि।
नारद : हाँ…. हाँ
विष्णु : लेकिन मैं केवल…..
नारद : केवल?
विष्णु : किसान को याद करता हूँ।
नारद : यह क्यों?
विष्णु : किसान अन्नदाता है।
नारद : ओहो! यह तो महान बात है।

कहना नहीं आता Summary in Malayalam

Plus One Hindi Textbook Answers Unit 4 Chapter 15 कहना नहीं आता 1
Plus One Hindi Textbook Answers Unit 4 Chapter 15 कहना नहीं आता 2
Plus One Hindi Textbook Answers Unit 4 Chapter 15 कहना नहीं आता 3
Plus One Hindi Textbook Answers Unit 4 Chapter 15 कहना नहीं आता 4
Plus One Hindi Textbook Answers Unit 4 Chapter 15 कहना नहीं आता 5

Plus One Hindi Textbook Answers Unit 4 Chapter 14 समय के साथ हम भी

Kerala State Board New Syllabus Plus One Hindi Textbook Answers Unit 4 Chapter 14 समय के साथ हम भी Text Book Questions and Answers, Summary, Notes.

Kerala Plus One Hindi Textbook Answers Unit 4 Chapter 14 समय के साथ हम भी

प्रश्न 1.
मिलान करके लिखें।
Plus One Hindi Textbook Answers Unit 4 Chapter 14 समय के साथ हम भी 1
उत्तर:
Resource = संसाधन
Trash = कूड़ेदान
Computer = संगणक
Search = खोज
Editing = ईक्षण
Keyboard = कुंजी पटल
Save = सहजें
Public = सार्वजनिक

Plus One Hindi समय के साथ हम भी Important Questions and Answers

प्रश्न 1.
सही मिलान करके लिखें।
उत्तर:
Internet = बहिर्पात
Computer = अनचाहा
Spam = अंतर्जाल
Output = संगणक

प्रश्न 2.
कोष्ठक से सही हिंदी शब्द चुनकर मिलान करें।
(बातचीत, संचिका, मंडलिया, श्रेणियाँ, महत्वपूर्ण, अतंर्पात, ईक्षण)
i. Important
ii. Chats
iii. Categories
iv. File
v. Input
vi. Editing
उत्तर:
i. Important = महत्वपूर्ण
ii. Chats = बातचीत
iii. Categories = श्रेणियाँ
iv. File = संचिका
v. Input = अतंर्पात
vi. Editing = ईक्षण

प्रश्न 3.
कोष्ठक से सही हिंदी शब्द चुनकर मिलान करें।
(संसाधन, बर्हिपात, विषयहीन, गोपनीयता, अगला चरण, अधिक जानें, कुडेदान, खोज)
उत्तर:
i. Trash = कुडेदान
ii. Next Step = अगला चरण
iii. Search = खोज
iv. Output = बर्हिपात
v. Privacy = गोपनीयता
vi. Resource = संसाधन

प्रश्न 4.
कोष्ठक से सही हिंदी शब्द चुनकर मिलान करें।
(संसाधन, अंतर्जाल, प्रारूप, सार्वजनिक, प्रस्थान, खोज़, सचिका)
उत्तर:
i. Public = सार्वजनिक
i. Format = प्रारूप
iii. Sign out = प्रस्थान
iv. Internet = अंतर्जाल
v. File = सचिका
vi. Resource = संसाधन

प्रश्न 5.
कोष्ठक से सही हिंदी शब्द चुनकर मिलान करें।
(कूड़ेदान, संसाधन, संकेत, प्रक्रम, बातचीत, प्रस्थान, ख़ोज़, महत्वपूर्ण, सचिका)
उत्तर:
i. Symbol = संकेत
ii. Important = महत्वपूर्ण
iii. Resource = संसाधन
iv. Chats = बातचीत
v. Programme = प्रक्रम
vi. Trash = कूड़ेदान

प्रश्न 6.
कोष्ठक से सही हिंदी शब्द चुनकर मिलान करें।
(अगला चरण, सार्वजनिक, साझा करें, प्रारूप, कूड़ेदान, संकेत, बातचीत, प्रस्थान)
उत्तर:
i. Chats = बातचीत
ii. Public = सार्वजनिक
iii. Trash = कूड़ेदान
iv. Next Step = अगला चरण
v. Share = साझा करें
vi.Format = प्रारूप

प्रश्न 7.
सही मिलान करें।
Plus One Hindi Textbook Answers Unit 4 Chapter 14 समय के साथ हम भी 2
उत्तर:
Plus One Hindi Textbook Answers Unit 4 Chapter 14 समय के साथ हम भी 3

प्रश्न 8.
सही मिलान करें।
Plus One Hindi Textbook Answers Unit 4 Chapter 14 समय के साथ हम भी 4
उत्तर:
Plus One Hindi Textbook Answers Unit 4 Chapter 14 समय के साथ हम भी 5
Plus One Hindi Textbook Answers Unit 4 Chapter 14 समय के साथ हम भी 6

समय के साथ हम भी Previous Years Questions and Answers

प्रश्न 1.
सूचनाःनिम्नलिखित 1 से 6 तक के प्रश्नों का उचित .. हिंदी शब्द कोष्ठक से चुनकर मिलान कीजिए।
(खोज, रद्द करें, प्रस्थान, ईक्षण, गोपनीयता, संचिका, कूड़ेदान)
1. Cancel
2. Editing
3. File
4. Trash
5. Privacy
6. Search
उत्तर:
1. Cancel – रद्द करें
2. Editing – ईक्षण
3. File – संचिका
4. Trash – कूड़ेदान
5. Privacy – गोपनीयता
6. Search – खोज

प्रश्न 2.
सूचनाःनिम्नलिखित 1 से 6 तक के प्रश्नों का उचित हिंदी शब्द कोष्ठक से चुनकर मिलान कीजिए।
(संचिका, गोपनीयता, खोज, बातचीत, ईक्षण, संकेत, साझा करे)
1. Chats
2. Editing
3. File
4. Search
5. Symbol
6. Privacy
उत्तर:
1. Chats – बातचीत
2. Editing – ईक्षण
3. File – संचिका
4. Search – खोज
5. Symbol – संकेत
6. Privacy – गोपनीयता

प्रश्न 3.
सूचनाः निम्नलिखित 1 से 6 तक के प्रश्नों का उचित हिन्दी शब्द चुनकर मिलान कीजिए।
(अगला चरण, सार्वजनिक, साझा करें, बातचीत, प्रारूप, कूड़ेदान, संकेत)
1. Chats
2. Public
3. Trash
4. Next Step
5. Share
6. Format
उत्तर:
1. Chats = बातचीत
2. Public = सार्वजनिक
3. Trash = कूड़ेदान
4. Next Step = अगला चरण
5. Share = साझा करें
6. Format = प्रारूप

प्रश्न 4.
सुचना: निम्नलिखित 1 से 6 तक के प्रश्नों का उचित हिंदी शब्द कोष्ठक से चुनकर मिलान कीजिए।
(गोपनीयता, रद्द करें, अंतर्जाल, प्रक्रिया, खोज, खाता जोड़ें, बाचचीत)
1. Cancel
2. Chats
3. Internet
4. Privacy
5. Process
6. Sign in
उत्तर:
1. Cancel : रद्द करें
2. Chats : बातचीत
3. Internet : अंतर्जाल
4. Privacy : गोपनीयता
5. Process : प्रक्रिया
6. Sign in : खाता जोड़ें

प्रश्न 5.
कोष्ठक से उचित हिंदी शब्द चुनकर मिलान कीजिए।
(संसाधन, तारांकित, ईक्षण, प्रक्रम, बहिपति, गोपनीयता, सहेजें)
Editing :
Output :
Save :
Resource :
Programme :
Privacy :
उत्तर:
Editing : ईक्षण
Output : बहिर्पात
Save : सहेजें
Resource : संसाधन
Programme : प्रक्रम
Privacy : गोपनीयता

समय के साथ हम भी Summary in Malayalam

Plus One Hindi Textbook Answers Unit 4 Chapter 14 समय के साथ हम भी 7

समय के साथ हम भी Glossary

Plus One Hindi Textbook Answers Unit 4 Chapter 14 समय के साथ हम भी 8
Plus One Hindi Textbook Answers Unit 4 Chapter 14 समय के साथ हम भी 9
Plus One Hindi Textbook Answers Unit 4 Chapter 14 समय के साथ हम भी 10