Kerala SSLC IT Theory Questions and Answers Chapter 2 Publishing

You can Download Publishing Questions and Answers, Kerala SSLC 10th IT Theory Questions and Answers Chapter 2 help you to revise complete Syllabus and score more marks in your examinations.

Kerala Syllabus SSLC IT Theory Questions and Answers Chapter 2 Publishing

Publishing Questions & Answers

Question 1.
Clickthrough Insert → fields → more fields in writer software. We get a field window contains utility.
a) File
b) Edit
c) Database
d) None
Answer:
c) Database

HSSLive.Guru

Question 2.
Formattings of a text is copped to another text is using tool
a) Clone formatting
b) style
c) Paragraph formatting
d) styles and formatting
Answer:
a) Clone formatting

Question 3.
Which is the Clone formatting tool?
Kerala SSLC IT Theory Questions and Answers Chapter 2 Publishing 1
Answer:
Kerala SSLC IT Theory Questions and Answers Chapter 2 Publishing 2

Question 4.
A word can define headings, subheadings and para-graph separately is called
a) Style
b) Insert
c) Formatting
d) Clone
Answer:
a) Style

Question 5.
In which menu lies the Index and Tables
a) File
b) Insert
c) Edit
d) Data
Answer:
b) Insert

Question 6.
Where does contain the table of contents in your text?
a) Middle of the text
b) Not entered
c) At the beginning
d) At the end
Answer:
c) At the beginning

Question 7
The Software developed by Leslie Lamport is
a) Linux
b) Windows
c) Android
d) LaTex
Answer:
d) LaTex

Question 8.
The program for type setting technical documents is developed by Donald Knuth is
a) LaTex
b) Tex.
c) Linux
d) Windows
Answer:
b) Tex

Question 9.
If you click at the word preface on the table of contents in writer. What message appears?
a) Ctrl-click to follow link
b) Click to follow link
c) Follow link
d) Click to follow link to close the window
Answer:
a) Ctrl-click to follow link

Question 10.
Which menu lies the field’s utility?
a) Edit
b) Insert
c) File
d) formatting
Answer:
b) Insert

HSSLive.Guru

Question 11.
Which software having the mail merge facility?
a) Libre office writer
b) Python
c) Firefox
d) Calculator
Answer:
a) Libre office writer

The Full form of DSLR is Digital Single Lens Reflex Cameras.

Question 12.
To include the names and address one by one in a table in the letters using a feature called
a) Style
b) Mail merge
c) Database
d) Indexable
Answer:
b) Mail merge

Question 13.
Which style is used to the headings more attractive?
a) Character style
b) Page style
c) Paragraph style
d) List style
Answer:
c) Paragraph style

Question 14.
Anu was prepared a style named main head. Then he selects the all headings in a report and clicks on the style named main head. What happens for the headings?
a) All headings are changed to same type
b) No change to the headings
c) Headings are changed to different sizes
d) Headings are seen in different colors
Answer:
a) AI1 headings are changed to same type

Question 15.
The use of organizer tab in styles and formattings window for creating a new style is?
a) No use at all
b) To applying the style
c) Giving the name for the style
d) Don’t give a name for the style
Answer:
c) Giving the name for the style

Questions 16.
Which software includes the styles and formattings utility
a) Cale
b) Python
c) Writer
d) Sun clock
Answer:
c) Writer

Question 17.
Pick out the correct statement related to a frame
a) Can’t able to type inside the frame
b) Frame can move at any place on the page
c) Frame can’t move on the page
d) Can’t able to insert an image in a frame
Answer:
b) Frame can move at any place on the page

Question 18.
Where did you get the fields window?
a) Insert →Fields → More fields
b) Insert → Media → Fields
c) Format → More fields
d) Tools → More fields
Answer:
a) Insert → Fields → More fields

Question 19.
A correct statement related to clone formatting is
a) Use clone formatting for a large report
b) Formattings of headings can be changed by changing the formatting of each heading separately
c) Formattings of headings can be changed by changing the formatting of one heading
d) Formattings of heading cannot be copped to another
b) Formattings of headings can be changed by changing the formatting of each heading separately

Section – II

Question 20.
Right-click on the heading (styles name) on a paragraph style, we get the utilities
a) Modify
b) Colour
c) New
d) Pattern
Answer:
a) Modify

Question 21.
Libre office writer file prepared in Malayalam fonts and English fonts, on which fonts are changed to change the styles of the files?
a) If the file is in Malayalam fonts, then change the CTL font
b) If the file is in English fonts, then change the CTL font
c) If the file is in Malayalam fonts, then change western text font
d) If the file is in English fonts, then change the Western text font
Answer:
a and b

Question 22.
Select the correct statements
a) The styles in a writer are changed and use them
b) The styles in a writer cannot be changed
c) New styles cannot be created
d) New styles can prepared in a writer.
Answer:
a and d

Question 23.
Select two correct statements related to a frame
a) Can’t move from one part of a page
b) To place text or images within a document separated from the main contents
c) To place anywhere in the page
d) Not separated from the main contents
Answer:
b and c

Question 24.
Participant’s cards are prepared by mail merge utility and select print from file menu. Then you get a window to select two utilities to save the output file what are they?
a) Save as single document
b) Save as image
c) Save as individual documents
d) Save picture as
Answer:
a and c

Question 25.
Using mail merge to preparing the letters for the parents about the Youth Festival. What are the preparations we make for this?
a) Making a list of parents address in Libre Office writer
b) Making a list of parents addresses in Libre Office Calc
c) Preparing the letters to the parents in Libre office writer
d) Preparing the letters to the parents in Libre office calc
Answer:
b and c

HSSLive.Guru

Question 26.
Why did scientific articles and research reports are prepared by LaTex Software?
a) Facility to use English fonts
b) Facility to use Malayalam fonts
c) Several features for typesetting Symbols
d) Several features for typesetting equations.
Answer:
c and d

Question 27.
What are the difficulties to prepare a text /document using clone formatting?
a) Separate formattings the contents of a text is difficult
b) Formattings of heading can be changed by changing the formattings of each heading separately
c) Formattings of headings/ paragraph can be changed by changing one
d) One by one formatting is very easy
Answer:
a and b

Question 28.
The order of preparing a table of contents to the school report are following. Select one from each set.

Set -1

a) Close the report
b) Type the school report
c) Correct the report
d) Open the prepared school report
Answer:
d) Open the prepared school report

Set – II

a) Click on the last page of the report
b) Click on the place where the table of contents to be inserted
c) Insert the table of contents on the cover page
d) Click on the blank space of the report
Answer:
b) Click on the place where the table of contents to be inserted

Set – III

a) Select Index and Tables from Insert Menu
b) Select fields from Insert menu
c) Select modify
d) Select styles and formatting from insert menu
Answer:
a) Select Index and Tables from Insert Menu

Set – IV

a) Close the window
b) A new window appears, give a heading and background color for the table of contents and click OK.
c) Click cancel on the new window
d) Leave the window without any change
Answer:
b) A new window appears, give a heading and background color for the table of contents and click OK.

Question 29.
What are the styles included in styles and formatting window?

Set -1

a) Paragraph style
b) Western-style
c) Formatting style
d) More style
Answer;
a) Paragraph style

Set – II

a) Apply style
b) Character styles
c) Style Box
d) Clone formatting
Answer:
b) Character styles

Set – III

a) Heading style
b) Report style
c) Frame style
d) Life style
Answer:
c) Frame style

Set-IV

a) Page style
b) Heading 1
c) Head
d) Address
Answer:
a) Page style

Question 30.
The uses of mail merge utility in LibreOffice writer.

Set-I

a) Preparing Notice
b) Preparing the letter for parents about youth festival
c) Writing the mark list
d) To prepare address
Answer:
b) Preparing the letter for parents about youth festival

Set – II

a) Creating a style
b) Taking a print
c) To taking a copy
d) To prepare participant’s card
Answer:
d)To prepare participant’s card

Set – III

a) To prepare certificate
b) To prepare a letter to a friend
c) To prepare a document
d) To prepare a study report
Answer:
a) To prepare certificate

Set – IV

a) To calculate the achievement
b) To prepare electricity bill
c) To apply style
d) To prepare the table of contents
Answer:
b) To prepare electricity bill

HSSLive.Guru

Question 31.
Which are the styles we are using from paragraph style? Make a list using from each set

Set – I

a) Table
b) Report
c) Heading
d) Contents
Answer:
c) Heading

Set – II

a) Caption
b) Font
c) Footer
d) Color
Answer:
a) Caption

Set-III

a) Find
b) Link
c) Object
d) Index
Answer:
d) Index

Set-IV

a) Body
b) Media
c) Text body
d) Frame
Answer:
c) Text body

Kerala Syllabus 9th Standard Biology Solutions Chapter 7 Division for Growth and Reproduction

You can Download Division for Growth and Reproduction Questions and Answers, Summary, Activity, Notes, Kerala Syllabus 9th Standard Biology Solutions Part 2 Chapter 7 help you to revise complete Syllabus and score more marks in your examinations.

Kerala State Syllabus 9th Standard Biology Solutions Chapter 8 Division for Growth and Reproduction

Division for Growth and Reproduction Textual Questions and Answers

Division For Growth And Reproduction Class 9 Question 1.
The phase at which a cell prepares for division is called
Answer:
Interphase

9th Standard Biology Notes Kerala Syllabus Question 2.
………. takes place after karyokinesis
Answer:
Cytokinesis

Kerala Syllabus 9th Standard Biology Notes Question 3.
………… begins after interphase
Answer:
Cell division

Hss Live Guru 9th Biology Kerala Syllabus Question 4.
What are changes that take place during interphase?
Answer:
a) Division of nucleus (Karyokinesis)
b) Division of Cytoplasm (Cytokinesis)

Hss Live Biology Class 9 Kerala Syllabus Question 5.
State whether true or false
Cytokinesis takes place after karyokinesis
Answer:
True

Kerala Syllabus 9th Standard Biology Notes Pdf Question 6.
Main stages of cell division
Answer:
Interphase, Division of nucleus, Division of cytoplasm

Hss Live Guru Biology 9 Kerala Syllabus Question 7.
What are the important changes that take place during interphase?
Answer:

  • Number of cell organelles increase
  • Quantity of cytoplasm increases
  • Cell size increases
  • Genetic material duplicate

Cell cycle

A cell attains its complete growth during interphase. The fully grown cell undergoes division and becomes daughter cells. As the interphase and the division phase get repeated in a cyclic manner, they together constitute cell cycle.

UML full form, stands for, meaning, what is, description, example, explanation, acronym for, abbreviation, definitions, full name.

9th Biology Notes Kerala Syllabus Question 8.
…………..is brought about by cell division and cell growth
Answer:
Growth of the body

Kerala Syllabus Biology 9th Standard Question 9.
What are the two types of cell division?
Answer:
Mitosis and meiosis.

Biology Class 9 Kerala Syllabus Question 10.
What do you mean by mitosis?
Answer:
A parent cell divides to form two daughter cells are called mitosis.

Karyokinesis

Question 11.
Point out the phases taken place in the changes in nucleus?
Answer:
Prophase, metaphase, anaphase and telophase

Question 12.
In which phase does the chromatin reticulum become chromosomes?
Answer:
Prophase

Question 13.
What changes occurs in telophase?
Answer:
In telophase chromosomes that moved to the poles become chromatin reticulum and daughter nuclei are formed.

Question 14.
State whether true or false in prophase chromosomes become chromatin reticulum.
Answer:
False

Question 15.
Complete the table of stages of nuclear division
Answer:

PhasesChanges
Prophase1. Chromatin reticulum become chromosomes
2. Duplicated chromosomes.
3. Formation of spindle fibers
4. Nucleolus and nuclear membrane get disappeared
MetaphaseChromosomes have moved to the middle of the cell and, chromo­somes doubled.
Anaphase1. Chromatids are starting to separate from each other.
2. Formation of two sets of daughter chromosomes
Telophase1. Formation of daughter nuclei
2. Two daughter nuclei are formed.
3. There will be no change in chromosome number in each daughter nucleus

Cytokinesis (Division Of Cytoplasm)

Question 16.
The division of the cytoplasm is taken place in plant is entirely different. Give reason?
Answer:
Because it is due to the presence of the cell wall in plant cell.

Question 17.
What is the significance of mitosis?
Answer:
The significance of mitosis is that there is no change in the number of chromosomes.

Question 18.
Mitosis helps ………… & ……….
Answer:
For the repair of tissues and growth.

Question 19.
Which condition leads to cancer?
Answer:
Mitosis is a controlled process. A disruption in this controlled process leads to the excessive division of a cell and its proliferation. This condition leads to cancer.

Different Stages Of Growth

Question 20.
List out the different stages in the growth of human beings.
Answer:

  • Zygote
  • Infancy
  • Old age
  • Embryo
  • Childhood
  • Fetus
  • Adolescence
  • Youth

Question 21.
What are the physical peculiarities of old age?
Answer:
Rate of cell division decreases, Availability of oxygen to the cells decreases, Deterioration of cells increase Muscles shrink, Production of energy decrease

Question 22.
The elders should be cared. Do you agree with this statement? Why?
Answer:
Old age is inevitable in life. The aged who worked for the welfare of their family and society during their younger age deserve special consideration.

Question 23.
What are the differences between the growth in plants and animals? Draw a comparison and complete table
Answer:

AnimalsPlants
Animals grow only up to a certain stage Animals do not have localized centers of growthPlants can grow through­out their lives Growth in plants is localized only at certain parts

Question 24.
Plants grow due to the rapid division and differentiation of cells.
Answer:
Meristematic cells

Question 25.
What do you mean by meristematic cells?
Answer:
Meristematic cells are special types of cells that have the capacity for continuous division.

Question 26.
Plants can grow throughout their life due to the presence of
Answer:
Meristematic cells

Question 27.
……… helps to increase the length of root and stem.
Answer:
Apical meristem

Question 28.
……… helps to increase the girth of the stem.
Answer:
Lateral meristem

Question 29.
Name the meristematic cells which help to increase the length of the stem.
Answer:
Intercalary meristem

Question 30.
Where do you find intercalary meristem?
Answer:
It seen above the nodes of monocot plants.

Question 31.
The stem of monocots increases in length faster than dicots. Why?
Answer;
Because the intercalary meristem is visible only in the monocot plants.

Question 32.
Dicot plants: Lateral meristem
……………..: Intercalary meristem
Answer:
monocot plants

Question 33.
The stem of monocots does not increase its girth beyond an extent. Why?
Answer:
Because lateral meristem is absent in monocot plants.

Growth In Unicellular Organisms

Question 34.
Does cell division in unicellular organisms lead to growth or reproduction?
Kerala Syllabus 9th Std Biology Solutions
Answer:
Mitosis leads to reproduction in unicellular organisms.

Meiosis

Question 35.
What do you mean by meiosis? Explain.
Answer:
Meiosis is the mode of cell division in which gametes are formed. Meiosis occurs in the germinal cells of the reproductive organs. Human beings have 46 chromosomes. Germinal cells with 46 chromosomes divide continuously two times. These divisions in meiosis are known as meiosis I and meiosis II. Two daughter cells “with half the number of chromosomes (23 chromosomes) are formed in meiosis I. Each daughter cell again divides in meiosis II. There is no change in the chromosome number in this division. Hence meiosis II is similar to. mitosis. As a result of meiosis, four daughter cells, each with 23 chromosomes, are formed from a germinal cell.

Question 36.
What do you mean by polar body?
Answer:
When meiosis occurs in the female germinal cell, a large ovum and three small cells are formed. The smaller cells are the polar bodies. These sterile cells get destroyed.

Question 37.
Complete the illustration
Kerala Syllabus 9th Standard Biology Notes Malayalam Medium
Answer:
a = 46
b = 23
c= 23
d = 23
e = 23
f = 23
g = 23

Question 38.
What is the number of chromosomes in germinal cells?
Answer:
46

Question 39.
What is the number of chromosomes in the daughter cells formed after meiosis I?
Answer:
23

Question 40.
What is the peculiarity of meiosis II?
Answer:
Each daughter cell again divides in meiosis II. There is no change in the chromosome number in this division. Hence meiosis II is similar to mitosis.

Question 41.
What are the kinds of cell division occur in sexually reproducing organisms?
Answer:
There are two kinds of cell division occur in sexually reproducing organisms that are mitosis and meiosis.

Question 42.
What are the different stages in the growth of human being?
Answer:
Infancy, childhood, adolescence, youth and old age.

Question 43.
Differentiate mitosis and Meiosis
9th Class Biology Notes Kerala Syllabus
Answer:

DifferencesMitosisMeiosis
Type of reproductionAsexualSexual
Genetically Chromosome NumberSimilar Remains sameDifferent Reduced by half
Takes place inSomatic cellsGerm cells
Number of daughters2 diploid4 haploid
cells producedcellscells

Let Us Assess

Question 1.
The stage of karyokinesis at which daughter nuclei are formed
A. Prophase
B. Metaphase
C. Anaphase
D. Telophase
Answer:
Telophase

Question 2.
List the meristems in various parts of the plant and list their functions
Answer:

MeristemFunction
Apical meristemIncrease the length of root and stem
Lateral meristemHelps to increases the girth of stem
Intercalary meristemHelps to increase the length of the stem of monocot plants

Question 3.
In females, only a single ovum is formed from a germinal cell, whereas in males, more than one sperm is formed. Give reason.
Answer:
When meiosis occurs in the female germinal cell, a large ovum and three small cells are formed. The smaller cells are the polar bodies. These sterile cells get destroyed. So only a single ovum is formed from a germinal cell. But in males, after meiosis, four sperms having 23 chromosomes are formed form one germinal cell.

Question 4.
Observe the figures
Biology Kerala Syllabus 9th Standard
a) Which stages of mitosis are indicated in the figures?
b) What are the changes that occur in the chromosomes during these stages?
Answer:
a) Metaphase
b) Chromosomes get aligned at the equator of the cell.

Kerala Syllabus 9th Standard Maths Solutions Chapter 12 Proportion

You can Download Proportion Questions and Answers, Activity, Notes, Kerala Syllabus 9th Standard Maths Solutions Chapter 12 help you to revise complete Syllabus and score more marks in your examinations.

Kerala State Syllabus 9th Standard Maths Solutions Chapter 12 Proportion

Proportion Textual Questions and Answers

Textbook Page No. 182

Hss Live Guru 9th Maths Kerala Syllabus Question 1.
A person invests 10000 rupees and 15000 rupees in two different schemes. After one year, he got 900 rupees as interest for the first amount and 1200 rupees as interest for the second amount.
i. Are the interests proportional to the investments?
ii. What is the ratio of the interest to the amount invested in the first scheme? What about the second?.
iii. What is the annual rate of interest in the first scheme? And in the second?
Answer:
i. The ratio between the amounts invested = 10000:15000 = 2 : 3
The ratio between the interests = 900 : 1200 = 3 : 4
Since the ratios are different. So, interests will be not proportional to the investments.

ii. The ratio between the amount invested and interest in scheme 1
= 10000 : 900= 100 : 9
The ratio between the amount invested and interest in scheme 2
= 15000 : 1200 = 25 : 2

iii. Rate of interest in the first scheme
= 900/10000 × 100 = 9%
Rate of interest in the second scheme =
1200/15000 × 100 = 8%

Make use of this free RSD calculator online that is specifically designed to calculate relative deviation of a data set.

Kerala State Class 9 Maths Solutions Question 2.
The area of A0 paper is one square metre. Calculate the lengths of the sides of A4 paper correct to a millimetre, using a calculator.
Answer:
The area of A1 paper is half of the area of A0 paper. The area of A2 paper is half of the area of A1 paper. Let con-sider the area of the A0 paper be 1 square metre, the area of A1 paper is
1/2 square metre , the area of A2 paper is 1/4 square metre , the area of A3 paper is 1/8 square metre , and the area of A4 paper is 1/16 square metre ,
If the length of A4 paper is √2 x and breadth x
length of A4 paper : breadth = √2 : 1
Area of A4 paper = length x breadth
√2x × x = √2x2
This is 1/16 m2, therefore √2 x2 = 1/16
Hss Live Guru 9th Maths Kerala Syllabus

Hsslive Guru 9th Maths Kerala Syllabus Question 3.
In calcium carbonate, the masses of calcium, carbon and oxygen are in the ratio 10 : 3: 12 . When 150 grams of a compound was analysed, it was found to contain 60 grams of calcium, 20 grams of carbon and 70 grams of oxygen. Is it calcium carbonate?
Answer:
The ratio between calcium, carbon and oxygen in calcium carbonate = 10 : 3: 12 The ratio of calcium, carbon and oxygen in the given compound = 60 : 20: 70 = 6 : 2: 7
Since this ratio is not equal to the ratio of calcium, carbon and oxygen in calcium carbonate, it is not calcium carbonate.

Textbook Page No. 185

Hss Live 9 Maths Kerala Syllabus Question 1.
For each pair of quantities given below, check whether the first is proportional to the second. For proportional quantities, calculate the constant of proportionality.
i. Perimeter and radius of circles.
ii. Area and radius of circles.
iii. The distance travelled and the number of rotations of a circular ring moving along a line.
iv. The interest got in a year and the amount deposited in a scheme in which interest is compounded annually.
v. The volume of water poured into a hollow prism and the height of the water level.
Answer:
i. The perimeter of a circle is n times its diameter. That is 2n times the radius.
∴Perimeter = 2πr
∴ The perimeter and radius are proportional.
The constant of proportionality is 2π

ii. The area of a circle is π times the square of the radius.
∴ Area = πr2
∴ Area and radius are not proportional.

iii. When the ring rotates once, the distance travelled is equal to its perimeter. When it rotates twice the distance travelled is twice its perimeter. When it rotates ‘n’ times, the distance travelled is ‘n ‘ times the perimeter of the ring.

iv. If the amount deposited is P and the rate of interest is R.
Annual interest = I = PNR,
I = P × R (N = 1)
The amount and interest are propor-tional.
Constant of proportionality is rate of interest, R.

v. Volume of a hollow prism
= base × height
Volume, of water and height of water level, are proportional. Constant of proportionality is the base area.

Kerala Syllabus 9th Standard Maths Notes Question 2.
During rainfall, the volume of water falling in each square metre may be considered equal.
i. Prove that the volume of water falling in a region is proportional to the area of the region.
ii. Explain why the heights of rainwater collected in different sized hollow prisms kept near one another are equal.
Answer:
i. The volume of water falling in each square metre are equal.
Let the volume of the rain falling on the 1 square metre be k The volume of the rain falling on the 2 square metre = 2k
The volume of the rain falling on the 3 square metre = 3k
The volume of the rain falling on the x square metre y = kx Here x and y are proportional.

ii. Let x be the base area of the vessel and h be the height of the water collected, then the volume of water y = xh.
y/x =h
The volume of water collected is different in hollow prisms having different base area.

But \(\frac { volume }{ Area }\) is always equal to the height of water level. So the height at which rainwater collected is same.

Hsslive Guru Maths 9th Kerala Syllabus Question 3.
When a weight is suspended by a spring, the extension is proportional to the weight. Explain how this can be used to mark weights on a spring balance.
Kerala State Class 9 Maths Solutions
Answer:
Mark the pointer when no weight is hanging on it. Then mark the point when a constant weight is hanging on it. For example when we hang 1 kg on it a 2 cm extension is made. So we mark 1, 2, 3, 4 from the points marked first, i.e.,
2, 4, 6 and 8.
These distances are divided into 10 equal parts, then we can mark the points 1.1 kg and 2.4 kg etc.

Hss Live Guru 9 Maths Kerala Syllabus Question 4.
In the angle shown below, for different points on the slanted line, as the distance from the vertex of the angle changes, the height from the horizontal line also changes.
Hsslive Guru 9th Maths Kerala Syllabus
i. In the picture, perpendicular to the horizontal lines are drawn from points on the slanted line.
Δ ABP, Δ ACQ, Δ ADRand Δ AES are similar triangles. (Because these are a right-angled triangle with is common to all)
∴ Ratio of their sides are equal. That is sides are proportional.
Kerala Syllabus 9th Standard Maths Solutions Chapter 12 Proportion 4
Let k be the constant of proportionality
PB = k × AB, QC = k × AC
RD = k × AD, SE = k × AE ,
i.e., the change in height is proportional to the distance.

Hss Live 9 Maths Kerala Syllabus
Kerala Syllabus 9th Standard Maths Notes

An online geometric sequence calculator helps you to find geometric Sequence, first term, common ratio calculator, and the number of terms.

Textbook Page No. 189

Class 9 Maths Chapter 12 Kerala Syllabus Question 1.
i. Prove that for equilateral triangles, area is proportional to the square of the length of aside. What is the constant of proportionality?
ii For squares, is area proportional to square of the length of a side? If so, what is the constant of proportionality?
Answer:
i. Δ ABC is an equilateral triangle
Consider their sides are ‘a’,
Draw a perpendicular line CD to AB
from C. In right-angled triangle ADC, according to the Pythagoras theorem AD2 + DC2 = AC2
DC2 = AC2 – AD2
Hsslive Guru Maths 9th Kerala Syllabus

ii. If x be the one side of a square then its area y = x2
Area of the square is proportional to the square of their sides.
Constant of proportionality = 1

Hsslive Guru Class 9 Maths Kerala Syllabus Question 2.
In rectangles of area one square metre, as the length of one side changes, so does the length of the other side. Write the relation between the lengths as an algebraic equation. How do we say this in the language of proportions?
Answer:
Area of the rectangle is the sum product of length and breadth.
Let × be the length and y be the breadth, then
x × y = 1 m2
Hss Live Guru 9 Maths Kerala Syllabus
x = 1/y = m
Example when y = 3 m
x = 1/3 meter
when y = 4 m
x = 1/4 meter
The algebraic equation is x = 1/y
i.e., length of rectangle is proportional to the reciprocal of the breadth, i.e., length of rectangle is proportional to its breadth.

Chapter 12 Maths Class 9 Kerala Syllabus Question 3.
In triangles of the same area, how do we say the relation between the length of the longest side and the length of the perpendicular from the opposite vertex? What if we take the length of the shortest side instead?
Answer:
Let ‘a’ be the large side, h be the length of perpendicular from opposite vertices, ‘A’ be the area, then
Kerala Syllabus 9th Standard Maths Solutions Chapter 12 Proportion 9
Length of larger side is inversely proportional to the length of perpendicular from the opposite vertex.
i.e., The length of small side is inversely proportional to the length of perpendicular line from the vertex of small side.

Hss Live Guru Class 9 Maths Kerala Syllabus Question 4.
In regular polygons, what is the relation between the number of sides and the degree measure of an outer angle? Can it be stated in terms of proportion?
Answer:
The sum of the exterior angles of all polygon is 360°. If ‘n’ is the number of sides.
Measure of an exterior angle = \(\frac{\text { Sum of exterior angles }}{\text { No. of sides }}\)
One outer angle = 360/n
(n = number of sides)
If the measure of an exterior angle is ‘x’.
x= \(\frac{1}{n} \times 360^{0}\)
One outer angle and number of sides are inversely proportional. The constant of proportionality is 1/n.

Hsslive Guru Maths Kerala Syllabus 9th Question 5.
A fixed volume of water is to flow into a rectangular water tank. The rate of flow can be changed by using different pipes. Write the relations between the following quantities as an algebraic equation and in terms of proportions.
i. The rate of water flow and the height of the water level.
ii The rate of water flow and the time taken to fill the tank.
Answer:
i. Let x be the rate of water flowing, y be the height of water in the tank and A be the base area of the tank, then
x = Ay
Height of the water level in the tank is proportional to the rate of the water flowing.

ii. If C is the volume of the tank, V be the volume of water flowing per second, the volume of water in ‘t’ second is given by
C = V × t
\(V=\frac{C}{t}=C \times \frac{1}{t}\)
That is the rate of water flow and the time taken for filling the tank are inversely proportional. C is the constant of proportionality.

Proportion Exam oriented Questions and Answers

Hsslive 9th Maths Kerala Syllabus Question 1.
the weight of 6 spheres of same size made of the same metal is 14 kg. When 9 more spheres are added the weight is 35 kg. Check whether the number of spheres and their weights are proportional.
Answer:
Weight of 6 spheres = 14kg
Ratio of number and weight = 6 : 14 = 3 : 7
Total number of sphers are added = 15
Total weight = 35kg
Ration of number and weight = 15 : 35 = 3 : 7
Since the ratios are equal, the number of sphers and their weights are propor-tional.

Question 2.
Raghu invested Rs. 60000 and Nazar Rs. 100000 and started a business. Within one month a profit of Rs. 4800 was obtained. Raghu took 1800 and Nazar took Rs. 3000 out of the profit obtained. What is the ratio of the investment? Is the investment and the profit divided proportionally?
Answer:
Ratio of investments = 60000 : 100000 = 6 : 10 = 3 : 5
Ratio of profit divided
1800 : 3000 = 18 : 30 = 3 : 5
Ratio of investments and Ratio of profit divided are equal. Hence they are proportional.

Question 3.
The two sides of a triangle having perimeter 10 m are 2\(\frac { 1 }{ 2 }\) m and 3 \(\frac { 1 }{ 2 }\) m.
What is the ratio of the length of the three sides of triangles?
Answer:
Perimeter of triangle = 10 m
First side = 3\(\frac { 1 }{ 2 }\) m = \(\frac { 5 }{ 2 }\) m
Second side = 3\(\frac { 1 }{ 2 }\) m = \(\frac { 7 }{ 2 }\) m
Third side = 4 m Ratio of three sides of a triangle
\(=\frac{5}{2}: \frac{7}{2}: 4 = 5: 7: 8\)

Question 4.
150 litres of water is flowing through a pipe in 6 minutes. If 200 litres of water flows through it in 8 minutes check whether the quantity of water and time of flow are proportional ?
Answer:
Quantity of water flowing in 6 minutes = 150 litres
Ratio between the quantity of water and timeofflow= 150: 6 = 25: 1
Quantity of water flowing in 8 minutes = 200 litres
Ratio between quantity of water and times of flow = 200 : 8 = 25: 1
Since the radios are equal, the amount of water flowing and the time of flow are proportional.

Question 5.
Unniyappam was made using 1 kg rice, 250 g plantain and 750g jaggery. Find the ratio between the ingredients.
Answer:
Rice = 1
kg= 1000g
Plantain = 250 g, Jaggery = 750 g.
Ratio between the ingredients
= 1000 : 250 : 750 = 4 : 1 : 3

Question 6.
Sathyan got Rs. 500 after working for 6 hours. Gopi got Rs. 400 after working for 4\(\frac { 1 }{ 2 }\) hours. Are the wages obtained proportional to the working time ?
Answer:
Ratio of working hours = 6 : 4 \(\frac { 1 }{ 2 }\)
= 12 : 9 = 4 : 3
Ratio of wages = 800 : 600 = 8 : 6 = 4 : 3
Since the ratios are equal, the working hours are proportional to the wages.

Question 7.
Are the length and breadth of a square having same perimeter inversely proportional?
Answer:
for a square the perimeter is 20 cm. so,
length + breadth = 10.
Let x be the length and y be the breadth then possible values of x and y are
x — y
9 — 1
8 — 2
7 — 3
Here xy is not a constant term i.e. the changes in the x and y is not in the firm of xy = kept
hence length and breadth are not in inversely proportional.

Question 8.
The weight of an object having mass 5 kg is 49 Newton. The weight of another object having mass 15 kg is 147 Newton. Check whether the mass and weight are proportional ? What is the constant of proportionality? What is the weight of an object having mass 8 kg ?
Answer:
Weight of 5 kg object = 49 N
Ratio between mass and weight = 5 : 49
Weight of 15 kg massed object = 147N
Ratio between mass and weight = 15:147 = 5:49
Mass and weight are proportional.
Weight of 8 kg massed object = 8 × 9.8 = 78.4N
Kerala Syllabus 9th Standard Maths Solutions Chapter 12 Proportion 10
Constant of proportionality = 9.8

Question 9.
The perimeter of a triangle is 60 cm. Sides are in the ratio 3: 4: 5. Then j find the length of the sides.
Answer:
Ratio of sides = 3 : 4 : 5
Therefore, the sides are the \(\frac { 3 }{ 12 }\), \(\frac { 4 }{ 12 }\) and \(\frac { 5 }{ 12 }\) part of the perimeter .
The perimeter is 60 cm, then the length of sides are
Kerala Syllabus 9th Standard Maths Solutions Chapter 12 Proportion 11
\(60 \times \frac{5}{12}=25 \mathrm{cm}\)

Question 10.
Will the dye which contains 10 L blue colour and 15 L white colour and another dye which contain 12L blue colour and 17 L white colour have j the same colour? Why?
Answer:
In the first dye , blue colour: white colour = 10 : 15 = 2 : 3
In the second dye, blue colour: white colour = 12: 17
The ratios are not same. Hence the both will not have same colour.

Question 11.
The face perimeter of some vessels in the shape of square prisms are equal. 12 litres of water can be filled in the vessel having height 15 cm. 16 litres of water can be filled in the vessel having height 20 cm. Check whether the volumes of the vessel and height are proportional. What is the constant of proportionality?
Answer:
Since the face perimeters are equal,
Volume = face perimeter × height
Volume of the vessel having height 15 cm = 12 litres.
Ratio of height to volume =15 : 12 = 5 : 4 Volume of the vessel having height 20 cm = 16 litres
Ratio of height to volume =20 : 16 = 5 : 4 Since the ratios are equal, height and volume are proportional.
\(\frac { volume }{ height }\) = \(\frac { 4 }{ 5 }\) constant of proportionality
Volume of the vessel having height 35 cm
= 35 × \(\frac { 4 }{ 5 }\) = 28 liters.

Question 12.
The ratio of carbon, sulphur and potassium nitrate to make gun powder is 3 : 2: 1. How much quantity of each is required to make 1.2 kg of gun powder ?
Answer:
Kerala Syllabus 9th Standard Maths Solutions Chapter 12 Proportion 12

Question 13.
Raju got Rs. 400 after working for 8 hours. Damu worked for 6 hours and got Rs. 300. Are the wages obtained proportional to the work time?
Answer:
Ramu working hours = 8 hour
Wages Raju obtained = Rs. 400
Damu working hours = 6 hour
Wages obtained by Damu = Rs. 300
Kerala Syllabus 9th Standard Maths Solutions Chapter 12 Proportion 13
∴ Wages obtained are proportional to the work time.

Question 14.
150 L of water flows through a pipe for 6 minutes. 200 L of water flows for 8 minutes through the same pipe. Are the time and amount of water flowing proportional?
Answer:
Ratio of quantity of water
= 150 : 200 = 15 : 20 = 3 : 4
Ratio oftime =6 : 8 = 3 : 4
The ratios are same , hence they are proportional.

Question 15.
A car with 5L of petrol travels a distance of 75 km. What is the proportionality constant between the distance travelled and the quantity of petrol? How much petrol is needed for travelling 180 km?
Answer:
Taking the distance travelled as x and quantity of petrol as y, then the constant of proportionality
Kerala Syllabus 9th Standard Maths Solutions Chapter 12 Proportion 14
The quantity of petrol needed to travel 180 km= 12 litre

Question 16.
The angles of a triangle are in the ratio 1 : 3: 5. How much is each angle of the triangle?
Answer:
Sum of the angles of a triangle = 180°
The angles of the traingle are \(\frac { 1 }{ 9 }\), \(\frac { 3 }{ 9 }\) and \(\frac { 5 }{ 9 }\)
parts of 180° , hence the angles are
Kerala Syllabus 9th Standard Maths Solutions Chapter 12 Proportion 15

Plus Two Economics Chapter Wise Questions and Answers Chapter 2 National Income Accounting

Students can Download Chapter 2 National Income Accounting Questions and Answers, Plus Two Economics Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations

Kerala Plus Two Economics Chapter Wise Questions and Answers Chapter 2 National Income Accounting

Plus Two Economics National Income Accounting One Mark Questions and Answers

Question 1.
GNP – depreciation is called
(a) GDP
(b) NNP
(c) PCI
(d) PI
Answer:
(b) NNP

Question 2.
The GDP deflator is equal to
i) Real GDP-Nominal GDP
Plus Two Economics Chapter Wise Questions and Answers Chapter 2 National Income Accounting img1
Answer:
iii) \(\frac{{ No minal GDP }}{\text { Real GDP }} \times 100\)

Question 3.
NFIA is included in:
(a) NNPFC
(b) NDPFC
(c) GDPFC
(d) All the above
Answer:
(a) NNPFC

Question 4.
Which among the following in a flow concept?
(a) export
(b) wealth
(c) capital
(d) foreign exchange reserve
Answer:
(a) export

HSSLive.Guru

Question 5.
When does net factor income from abroad become negative?
(a) NDP < NNP
(b) NNP < NDP
(c) NDP = NNP
(d) none of the above
Answer:
(b) NNP < NDP

Question 6.
When does GDP and GNP of an economy become equal?
(a) When net factor income from abroad is positive
(b) When net factor income from abroad is negative
(c) When net factor income from abroad is zero
(d) None ofthe above.
Answer:
(c) When net factor income from abroad is zero

Plus Two Economics National Income Accounting Two Mark Questions and Answers

Question 1.
Same job is done by a servant and housewife, whose service is included in the national income calculation? Why?
Answer:
Service of a servant is included in the national income calculation, whereas, the service of housewife is not included in the national income. This is because the housewife is not paid for the service she does.

Question 2.
From the following, classify the material into final goods and intermediary goods. Wheat, Bench, Bread, Wood, Rubber, Tyre.
Answer:

Final GoodsIntermediary goods
BenchWheat
BreadWood
TyreRubber

Question 3.
Distinguish between real flow and money flow?
Answer:
Flow of goods and services from firms to households is called real flow. Factors of production receive reward for their services in the form of money. Households use this money to buy goods and services produced by firms. This flow of money from firms to households and back to firms is called money flow.

HSSLive.Guru

Question 4.
Some variables are given below. Classify them into Stock and Flow

  1. Wealth
  2. Income of a household
  3. Consumption
  4. Capital
  5. Money Supply
  6. Capital formation
  7. Inventories
  8. Saving of a household

Answer:
a. Stock

  • Wealth
  • Inventories
  • Capital
  • Money supply

b. Flow

  • Income of a household
  • Consumption
  • Capital formation
  • Saving of a household

Question 5.
GDP = C + I + G + (X – M) = C + S + T Derive the Budget Deficit and Trade Deficit equations from the above identity.
Answer:
GDP = C + I + G + (X – M) = C + S + T
Budget deficit = G – T
Trade deficit = M – X

Plus Two Economics National Income Accounting Three Mark Questions and Answers

Question 1.
“Transfer payments are not included in the national income calculation”. Do you agree? Justify your answer.
Answer:
Yes. Transfer payments like pension, old age pension, etc. are not included in the national income. This is because they are transfer earnings not generated by any economic activity. These payments are usually made by the government out of tax revenue collected from the public. Since these generated incomes are already included in national income calculation there is no need to include transfer payment in the national income calculation again.

Question 2.
State whether the following are included or excluded in the national income.

  1. purchase of second hand goods
  2. operating surplus
  3. production for self-consumption
  4. interest
  5. windfall gains and loses

Answer:

  1. Purchase of second hand goods – excluded
  2. operating surplus – included
  3. old age pension – excluded
  4. Production for self consumption – excluded
  5. interest – included
  6. windfall gains and loses – excluded

Question 3.
Provide appropriate term.
Plus Two Economics Chapter Wise Questions and Answers Chapter 2 National Income Accounting img2
Answer:

  1. Value added
  2. GNP
  3. NNP
  4. NNPFC

HSSLive.Guru

Question 4.
Point out any 3 uses of national income accounting.
Answer:
The uses of national income accounting are given below.

  1. It shows the distribution of national income among the various factors of production.
  2. National income statistics indicate the contribution of different sectors in the economy.
  3. Structural changes in the economy can be assessed by the national income accounting.

Uniform Distribution Calculator is an online tool that helps to calculate the probability distribution for the given values.

Question 5.
Classify the following under proper heads.
Flow of teacher services, Flow of subsidies and taxes, Flow of factor rewards, flow of finished goods, Flow of consumption expenditure, Flow of import goods.
Plus Two Economics Chapter Wise Questions and Answers Chapter 2 National Income Accounting img3
Answer:

Real FlowMoney Flow
Flow of teacher servicesFlow of subsidies and taxes
Flow of finished goodsFlow of factor rewards
Flow of import goodsFlow of consumption

Question 6.

  • Does not includes prices of imported goods
  • Weights are different
  • It includes all goods and services
  • Includes prices of imported goods
  • Weights are constant
  • Does not include all goods and services

Answer:
a. Consumer price index

  • Includes prices of imported goods
  • Weights are constant
  • Does not include all goods and services

b. GDP deflator

  • Does not include prices of imported goods
  • Weights are different
  • It includes all goods and services

HSSLive.Guru

Question 7.
Assume that there are three goods produced in an economy and they are sold at different prices in dif-ferent years. Calculate GDP Deflator.
Plus Two Economics Chapter Wise Questions and Answers Chapter 2 National Income Accounting img4
Answer:
Plus Two Economics Chapter Wise Questions and Answers Chapter 2 National Income Accounting img5

Question 8.
Calculate Depreciation, Net Indirect Tax and NNPFC from the below data.
GDPMP = 11300
NDPMP = 10300
NDPFC = 10000
NFIA = 1500
Answer:
1. Depreciation = GDPMP – NDPMP
= 11300 – 10300
= 1000

2. Net Indirect tax = NDPMP – NDPFC
= 10300 – 10000 = 300

3. NNPFC = NDPFC + NFIA
= 10000 + 1500
= 11500

Plus Two Economics National Income Accounting Five Mark Questions and Answers

Question 1.
Find the odd one out. Justify your answer.

  1. GNP, NNP, CSO, GDP
  2. Salary, bonus, GPF, free housing, saving
  3. Smuggling, production of wheat, sale of second-hand goods, services of housewives
  4. Services of teacher, services of engineer, services of lawyer, services of housewife
  5. Unemployment allowances, scholarships, old age pension, support price.

Answer:

  1. C.S.O. Others are national income concepts.
  2. Saving. Others come under compensation to employees
  3. Production of wheat. Others are excluded from national income
  4. Services of housewife. Others are included in the national income calculation.
  5. Support price. Others are transfer payments.

Question 2.
Match the following.

AB
NNPGDP – net factor income from abroad
GNPPersonal income – direct taxes
Value addedGNP-depreciation
GDP at market pricesvalue of output – intermediate consumption
Disposable incomeGDP at factor cost – net indirect tax

Answer:

AB
NNPGNP – depreciation
GNPGDP – net factor income from abroad
Value addedValue of output- intermediate consumption
GDP at market pricesGDP at factor cost – net indirect tax
Disposable incomePersonal income – direct taxes

Question 3.
Categorize the following into stocks and flows, wealth, salary, food grain stock, foreign exchange reserves, export, gross domestic saving, capital, change in money supply, quantity of money, capital formation.
Answer:

StockFlow
WealthExport
Foreign exchange reservesSalary
Food grain stockGross domestic saving
CapitalChange in money supply
Quantity of moneyCapital formation

HSSLive.Guru

Question 4.
The phase of circular flow of income in a two sector economy is given below.
Plus Two Economics Chapter Wise Questions and Answers Chapter 2 National Income Accounting img6

  1. Complete the diagram.
  2. Explain the process of circular flow

Answer:

1.

Plus Two Economics Chapter Wise Questions and Answers Chapter 2 National Income Accounting img7
2. Circular flow of income:
The concept that the aggregate value of goods and services produced in an economy is going around in a circular way. Either as factor payments, or as expenditures on goods and services, or as the value of aggregate production.

Question 5.
Suppose that in a two sector economy the value of finished goods is equal to ₹100 crore and the income generated as factor rewards is also equal to ₹100 crore. The households spend only ₹80 crore.

  1. What will happen to the circular flow?
  2. Which system can be introduced to correct the circular flow?
  3. Name the leakages and injections.

Answer:

  1. There will be a mismatch between the real flow and money flow in the circular flow. In other words, the flow will be broken.
  2. As a corrective measure, the financial system can be introduced.
  3. The leakages is the difference between the income generates and household spending.

This is saving. The injection are the savings that the households, firms and the government take from the financial institutions as borrowings.

HSSLive.Guru

Question 6.
1. Estimate the NI of India and Pakistan from the data given below.
Plus Two Economics Chapter Wise Questions and Answers Chapter 2 National Income Accounting img8
2. Which method is used here?
3. What are the other methods of measuring national income?
Answer:

  1. National income of India = ₹2885 crore
    National income of Pakistan = ₹1860 crore
  2. The method used here is the product method or value added method.
  3. Income method and expenditure method are the other two method of measuring national income.

Question 7.
What do you mean by GDP deflator? How far GDP deflator differs from Consumer Price Index?
Answer:
The ratio of nominal to real GDP is a well known index of prices. This is called GDP Deflator. GDP deflator differs from Consumer Price Index. The major points of difference are given below.

1. The goods purchased by consumers do not represent all the goods which are produced in a country. GDP deflator takes into account all such goods and services.

2. CPI includes prices of goods consumed by the representative consumer; hence it includes prices of imported goods. GDP deflator does not include prices of imported goods.

3. The weights are constant in CPI – but they differ according to production level of each good in GDP deflator.

Question 8.
Write down some of the limitations of using GDP as an index of welfare of a country.
Answer:
GDP is the sum total of value of goods and services created within the geographical boundary of a country in a particular year. It gets distributed among the people as incomes. So we may be tempted to treat higher level of GDP of a country as an index of greater well-being of the people of that country. But there are at least three reasons why this may not be correct. They are discussed below.

1. Distribution of GDP – how uniform is it:
If the GDP of the country is rising, the welfare may not rise as a consequence. This is because the rise in GDP may be concentrated in the hands of very few individuals or firms. For the rest, the income may, in fact, have fallen.

In such a case the welfare of the entire country cannot be said to have increased. If we relate welfare improvement in the country to the percentage of people who are better off, then surely GDP is not a good index.

2. Non-monetary exchanges:
Many activities in an economy are not evaluated in monetary terms. For example, the domestic services women perform at home are not paid for. The exchanges which take place in the informal sector without the help of money are called barter exchanges.

This is a case of underestimation of GDP. Hence GDP calculated in the standard manner may not give us a clear indication of the productive activity and well-being of a country.

3. Externalities:
Externalities refer to the benefits (or harms) a firm or an individual causes to another for which they are not paid (or penalized). Externalities do not have any market in which they can be bought and sold. Therefore, if we take GDP as a measure of welfare of the economy we shall be overestimating the actual welfare.

This was an example of negative externality. There can be cases of positive externalities as well. In such cases, GDP will underestimate the actual welfare of the economy.

HSSLive.Guru

Question 9.
Assume that GDP in the year 2007 was ₹1,200 which rose to ₹1,800 in 2008. Calculate GDP deflator.
Answer:
GDP deflator = Current year GDP / Base year GDP x 100
= 1800/1200 × 100
= 1.5 × 100
= 1.5 (in percentage terms 150)

Question 10.
Relate and complete the identities/equations in column A with column B.
Plus Two Economics Chapter Wise Questions and Answers Chapter 2 National Income Accounting img9
Answer:
Plus Two Economics Chapter Wise Questions and Answers Chapter 2 National Income Accounting img10

Question 11.
Estimate the Gross National Product at market price and GNP at factor cost through the expenditure method.

ItemAmount (in Crores)
Inventory investment15
Net factor income from abroad10
Personal consumption expenditure475
Gross residential construction investment48
Exports25
Government purchase of goods and services175
Gross public investment15
Gross business fixed investment38
Imports12
Net indirect tax8

Answer:
GNPMP = private consumption expenditure + govt, final consumption expenditure( gross fixed capital formation + change in stock or inventory investment) + net export + net factor income from abroad
= 475 + 175 + 101 (i.e., 48 + 15 + 38) + 15 + 13
= ₹779 crores.
GNPC = GNPUD – net indirect taxes
= 779 – 8 = ₹771 crores

Question 12.
Suppose that in a two sector economy, the value o finished goods is equal to ₹200 crore and the income generated as factor rewards is equal to ₹200 crore. The households spend only ₹180 crore. The remaing 20 crore economy saved then.

  1. Is ₹20 (saving) included in the circular flow?
  2. Which system can be introduced to correct the circular flow?
  3. Is saving leakage or injection.

Answer:

  1. No, saving (₹20) is excluded in the circular flow.
  2. Financial system can be introduced to correct the circular flow.
  3. Yes, saving is a leakage.

Question 13.
Fill in the blanks

  1. GNPMP – ……….. = NNPMP
  2. NNPMP – ………… = NNPFC
  3. GDPFC+ – ………… = GDPMP
  4. GDP + -………….. = GNP

Answer:

  1. GNPMP – depreciation = NNPMP
  2. NNPMP – net indirect tax = NNPFC
  3. GDPFC + net indirect tax = GDPMP
  4. GDP + net factor income from aborad = GNP

HSSLive.Guru

Question 14.
Write down the 3 identities of calculating the GDP of a country by the 3 methods. Also briefly explain why each of those should give us the same value of GDP.
Answer:
Gross National Product (GNP) equals Gross National Income equals Gross National Expenditure, i.e.
GNP = GNI = GNE
These are equal because national income is a circular flow of income. Aggregate expenditure is equal to aggregate output which in turn, is equal to aggregate income. However each method has some different items, yet they show exactly identical results.

Their identity can be shown in the following manner:
Reconciling Three Methods of Measuring Gross

Plus Two Economics Chapter Wise Questions and Answers Chapter 2 National Income Accounting img11

Question 15.
The economic recession of 2008 affected the market economics in general and the US in particular. Thou-sands of Indians working abroad lost their job especially in IT and banking sectors and they returned to India. Evaluate its consequences on Indian economy with regard to the following macro variables.

  1. The value of GNP
  2. Gneral unemployment level
  3. Foreign exchange rate

Answer:

  1. The value of GNP decreases due to reduction in NFIA.
  2. General unemployment level increases.
  3. Foreign exchange rate increases.

Plus Two Economics National Income Accounting Eight Mark Questions and Answers

Question 1.
Given below some macro economic indicators. Derive the equations of the following terms:

  1. GNP
  2. NNP
  3. NNP at factor cost
  4. Personal income
  5. Personal disposable income
  6. Private Income
  7. National Disposable Income

Answer:
1. GNP = GDP + Factor income earned by the domestic factors of production employed in the rest of the world – Factor income earned by the factors of production of the rest of the world employed in the domestic economy

2. NNP = GNP – Depreciation

3. NNP at factor cost = National Income (NI) = NNP at market prices – (Indirect taxes – Subsidies)

4. Personal income (PI) = NI – Undistributed profits – Net interest payments made by households – Corporate tax + Transfer payments to the households from the government and firms.

5. Personal Disposable Income (PDI) = PI – Personal tax payments – Non-tax payments.

6. Private Income = Factor income from net domestic product accruing to the private sector + National debt interest + Net factor income from abroad + Current transfers from government + Other net transfers from the rest of the world

7. National Disposable Income = Net National Product at market prices + other current transfers from the rest of the world

HSSLive.Guru

Question 2.
Prepare a seminar report on the topic ‘Measurement of National Income’.
Answer:
Measurement of National Income Respected teachers and dear friends,
The topic of my seminar paper is ‘measurement of national income or the methods of measuring national income’. The concept of national income occupies an important place in economic theory.

National income is the aggregate money value of all goods and services produced in a country during an accounting year. In this seminar paper, I would like to present various methods of measuring national income.

Content:
National income can be measured in different ways. Generally there are three methods for measuring national income. They are

  1. Value-added method
  2. Expenditure method
  3. Income method

1. Value-added method:
The term that is used to denote the net contribution made by a firm is called its value-added. We have seen that the raw materials that a firm buys from another firm which are completely used up in the process of production are called ‘intermediate goods’.

Therefore the value-added of a firm is the value of production of the firm – value of intermediate goods used by the firm. The value-added of a firm is distributed among its four factors of production, namely, labor, capital, entrepreneurship, and land.

Therefore wages, interest, profits, and rents paid out by the firm must add up to the value-added of the firm. Value-added is a flow variable.

2. Expenditure Method:
An alternative way to calculate the GDP is by looking at the demand side of the products. This method is referred to as the expenditure method. The aggregate value of the output in the economy by expenditure method will be calculated.

In this method we add the final expenditures that each firm makes. Final expenditure is that part of expenditure which is undertaken not for intermediate purposes.

3. Income Method:
As we mentioned in the beginning, the sum of final expenditures in the economy must be equal to the incomes received by all the factors of production taken together (final expenditure is the spending on final goods, it does not include spending on intermediate goods).

This follows from the simple idea that the revenues earned by all the firms put together must be distributed among the factors of production as salaries, wages, profits, interest earnings, and rents.
That is GDP = W + P + In + R

Conclusion:
Thus it can be concluded that there are three methods for measuring national income. These methods are value-added method, income method and expenditure method. Usually in estimating national income, different methods are employed for different sectors and sub sectors.

HSSLive.Guru

Question 3.
From the following data, calculate personal income and personal disposable income (₹in Crores).

  1. NDPFC – 8,000
  2. net factor income from abroad – 200
  3. Undistributed profit – 1,000
  4. Corporate tax – 500
  5. Interest received by households – 1,500
  6. Interest paid by households – 1,200
  7. Transfer income – 300
  8. Personal Tax – 500

Answer:
Personal income = NDPfc + Net factor income from abroad – undistributed profits – corporate taxes + transfer payments + net interest received from households.
= 8000 + 200-1000 – 500 + 300 (1500 -1200)
= 7,300 crores
Personal disposable income = Personal income – personal tax
= 7,300 – 500 = 6,800 crores

Question 4.
Production generates income. Prove this statement with the help of a simple two sector model of circular flow of income.
Answer:
circular flow of income:
It is a pictorial representation of interdependence or interrelationship between the various sectors of the economy. It is a concept associated with income earning and spending. The circular flow of income in a simple economy works on the basis of certain assumptions.
They are as follows:

  1. Households and firms are the only two sectors in an economy (2 sector model)
  2. Households supply factor services to firms.
  3. Firms hire factor services households
  4. Household spends their entire income on consumption and thereby no savings are left with them.
  5. Firms sell their entire products to the households
  6. There is no government in the economy.
  7. The economy is not related to any other economies or the economy is a ‘closed’ system. As a result, there is no export or imports from the economy.

In such an economy, there would be two types of markets.
They are:

  1. product-market for goods and services
  2. factor markets for buying and selling various factor services.

The relationship between the sectors of an economy can be explained with the help of a diagram.

Plus Two Economics Chapter Wise Questions and Answers Chapter 2 National Income Accounting img12

The households own the factors of production such as land, labour, capital, and organization. The households sell these factors of production to the firms for producing goods and services are known as real flow. The rewards for factors of production are rent to land, interest to capital, wage to the labour and profit to the entrepreneur is known as the money flow.

Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics

Kerala State Board New Syllabus Plus One Maths Chapter Wise Previous Questions and Answers Chapter 15 Statistics.

Kerala Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics

Plus One Maths Statistics 3 Marks Important Questions

Question 1.
Consider the numbers 4,7,8,9,10,12,13,17 (MARCH-2010)
i) Find the mean of the numbers.
ii) Find the mean deviation about the mean.
iii) Find the standard deviation.
Answer:
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 1
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 2

Question 2.
Consider the following data; 35,49,30,32,50,41,34,45,36 (MARCH-2013)
i) Find its median.
ii) Find its mean deviation about median
Answer:
i) 30, 32, 34, 35, 36, 41, 45, 49, 50
Median is the 5th observation when the data is arranged in ascending order. Hence median = 36
ii)
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 3

Question 3.
The mean and standard deviation of marks obtained by 50 students of 50 students in a class in two subjects mathematics are given below:  (IMP-2014)
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 4
Which one of the subject shows highest variability in marks? Why?
Answer:
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 5
Thus Accountancy with highest CV shows highest variability and Mathematics with lowest CV shows lowest variability.

Plus One Maths Statistics 4 Marks Important Questions

Free Online Polynomial in Ascending Order Calculator helps people to rearrange the given polynomial expression in ascending order in a fraction of seconds.

Question 1.
A public Opinion polling agency surveyed 200 government employees. The following table shows the ages of the employees interviewed: (MARCH-2011)
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 6
i) Calculate the mean age of the employees interview.
ii) Compute the mean deviation of the ages about the mean age.
Answer:
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 7
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 8

The frequency distribution calculator helps you find the distribution frequency of the numbers in the data set.

Question 2.
Consider the following frequency table. (IMP-2011)
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 46
i) Find the mean.
ii) Find the mean deviation about mean.
Answer:
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 9

Question 3.
Consider the following data in respect of marks of 50 students in Mathematics and Physics. (IMP-2011)
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 10
i) Find coefficient of variation of Mathematics and Physics.
ii) Which subject shows more variability?
iii) Which subject shows more consistent?
Answer:
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 11
ii) Greater CV more variability; therefore Mathematics is more variable than Physics.
iii) Less CV more consistent, therefore Physics is more consistent.

Question 4.
Find the Standard deviation for the following data: (IMP-2012)
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 12
Answer:
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 13

Question 5.
Consider the frequency distribution. (MARCH-2013)
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 14
i) Find the mean.
ii) Calculate the variance and the standard deviation.
Answer:
i)
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 15
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 16
ii)
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 17

Question 6.
Consider the frequency distribution. (MARCH-2013)
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 18
i) Find the mean.
ii) Calculate the variance and standard deviation.
Answer:
i)
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 19
ii)
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 20

Question 7.
Consider the following frequency table (MARCH-2014)
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 21
i) Find the mean.
ii) Find the mean deviation about the mean.
Answer:
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 22

Question 8.
Find the standard deviation of the data: (IMP-2014)
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 23
Answer:
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 24

Plus One Maths Statistics 6 Marks Important Questions

Question 1.
The scores of two batsmen A and B in 5 innings during a certain match are as follows: (IMP-2010)
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 25
Find:
i) Mean score of each batsman.
ii) Standard deviation of the scores of each batsman.
iii) Which of the batsman is more consistent?
Answer:
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 26
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 27

Question 2.
Calculate mean, variance and standard deviation for the following distribution. (IMP-2012)
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 28
Answer:
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 29
Standard Deviation = √20100 = 141.8

Question 3.
Calculate the median and Mean deviation about median for the following data. (IMP-2012)
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 30
Answer:
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 31
Median class is the class in which the \(\left(\frac{50}{2}=25\right)^{t h}\) observation lies. Therefore median class is 20 – 30.
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 32

Question 4.
Consider the following distribution; (MARCH-2012)
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 33
i) Calculate the mean of the distribution.
ii) Calculate the standard deviation of the distribution.
Answer:
i)
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 34
ii)
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 35

Question 5.
Consider the following distribution. (IMP-2012)
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 36
i) Find the mean.
ii) Find the standard deviation.
iii) Find the coefficient of variation of marks.
Answer:
i)
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 16
ii)
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 15
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 17
iii)
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 37

Question 6.
Consider the frequency distribution (MARCH-2014)
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 38
i) Find the mean.
ii) Calculate the variance and the standard deviation.
Answer:
i)
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 39
ii)
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 40

Question 7.
i) If \(overline { x }\) is the mean and a is the standard deviation of a distribution, then the coefficient of variation is ……… (MARCH-2015)
a) \(\frac{\bar{x}}{\sigma} \times 100\)
b) \(\frac{\sigma}{\bar{x}}\)
c) \(\frac{\sigma}{\bar{x}} \times 100\)
d) \(\frac{\bar{x}}{\sigma} \times 50\)
ii) Find the standard deviation for the following data:
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 41
Answer:
i)
\(\frac{\bar{x}}{\sigma} \times 100\)
ii)
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 13

Question 8.
i) The sum of all the deviations of the observations of a data from its A.M. is …………. (IMP-2013)
a) Zero
b) Maximum
c) Minimum
d) Negative number
ii) Calculate the Mean. Variance and Standard deviations of the following frequency distribution.
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 42
Answer:
i) a) zero
ii)
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 15
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 17
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 37

Question 9.
i) Suppose the mean of certain number of observation is 50 and the sum of all the observations is 450. Write down the number of observations (MARCH-2016)
ii) Find the mean deviation about mean for the following data:
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 43
Answer:
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 47

Question 10.
i) If the variance of a certain distribution is 8, write its standard deviation. (MAY-2017)
ii) Find the mean, standard deviation and coefficient of variation for the following frequency distribution.
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 48
Answer:
i) √8
ii)
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 15
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 17
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 37

Question 11.
i) Find the variance for the observations 2,4,6,8 and 10. (MARCH-2017)
ii) Consider the frequency distribution
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 44
Answer:
i)
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 45
ii)
Plus One Maths Chapter Wise Previous Questions Chapter 15 Statistics 49

Plus One Maths Notes Chapter 6 Linear Inequalities

Kerala State Board New Syllabus Plus One Maths Notes Chapter 6 Linear Inequalities.

Kerala Plus One Maths Notes Chapter 6 Linear Inequalities

Two real numbers or two algebraic expressions related by the symbols <, >, ≤ or ≥ form an inequality. In this unit we study linear inequalities in one and two variables, their formation and solution graphically.

Solve inequality calculator or quadratic inequalities with our free step-by-step algebra calculator.

I. Linear Inequalities in One Variable
The solution of an inequality in one variable is a value of the variable ‘x’ which makes it a true statement.

Equal numbers can be added or subtracted from both sides of the inequation.

If we multiply or divide both sides of an inequation by a positive number, the inequality sign will not be changed.

If we multiply or divide both sides of an inequation by a negative number, the inequality sign will be reversed.

To represent x < a (or x > a) on a number line, put a circle on the number ‘a’ and a dark line to the left (or right) of the number ‘a’.

To represent x ≤ a (or x ≥ a) on a number line, put a dark circle on the number ‘a’ and a dark line to the left (or right) of the number ‘a’.

II. Linear Inequalities in two Variables
The region containing all the solutions of an inequality is called the solution region.

In order to identify the half-plane represented by inequality, it is just sufficient to take any point (a, b) [say point (0, 0)] not on the line and check whether it satisfies the inequality or not. If it satisfies, then the inequality represents the half-plane and shade the region which contains the point, otherwise, the inequality represents that half-plane which does not contain the point within it.

If the inequality is of the type ax + by ≥ c or ax + by ≤ c, then the point on the line ax + by = c is also included in the solution. So draw a dark line in the solution region.

If the inequality is of the type ax + by > c or ax + by < c, then the point on the line ax + by = c are not to be included in the solution. So draw a broken or dotted line in the solution region.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Students can Download Chapter 1 Review of C++ Programming Questions and Answers, Plus Two Computer Application Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Plus Two Computer Application Review of C++ Programming One Mark Questions and Answers

Question 1.
IDE means ______
IDE _______.
Answer:
Integrated Development Environment.

Question 2.
We know that C++ is a high level language. From the following which statement is true.
(a) C++ contains English like statements.
(b) C++ contains mnemonics
(c) C++ contains only 0 and 1
(d) None of these
Answer:
(a) C++ contains English like statements.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 3.
C++ is a_____language.
(a) High level
(b) Low level
(c) Middle level
(d) None of these
Answer:
(a) High level.

Question 4.
C++ was developed at_______.
(a) AT & T Bell Laboratory
(b) Sanjose Laboratory
(c) Kansas University Lab
(d) None of these
Answer:
(a) AT & T Bell Laboratory.

Question 5.
C++ is a successor of______language.
(a) C#
(b) C
(c) Java
(d) None of these
Answer:
(b) C.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 6.
The most adopted and popular approach to write programs is_______.
Answer:
Structured programming.

Question 7.
From the following which uses OOP concept.
(a) C
(b) C++
(c) Pascal
(d) Fortran
Answer:
(b) C++.

Question 8.
_____is the smallest individual unit.
Answer:
Token

Question 9.
Pick the odd one out
(a) float
(b) void
(c) break
(d) Alvis
Answer:
(d) Alvis, the others are keywords.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 10.
Reserved words for the compiler is_______.
(a) Literals
(b) Identifier
(c) Keywords
(d) None of these
Answer:
(c) Key words.

Question 11.
Pick an identifier from the following.
(а) auto
(b) age
(c) float
(d) double
Answer:
(b) age.

Question 12.
Pick the invalid identifier
(a) name
(b) Date of birth
(c) age
(d) joining_time
Answer:
(b) Date of birth, because it contains space.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 13.
Pick the octal integer from the following.
(a) 217
(b) 0 × 217
(c) 0217
(d) None of these
Answer:
(c) 0217, an octal integer precedes 0.

Question 14.
Pick the hexa decimal integer from the following.
(а) 217
(b) 0 × 217
(c) 0217
(d) None of these
Answer:
(b) 0 × 217, an hexa decimal integer precedes Ox.

Question 15.
From the following pick a character constant.
(a) ’A’
(b) ‘ALL’
(c) ‘AIM’
(d) None of these
Answer:
(a) ‘A’, a character enclosed between single quote.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 16.
Non graphic symbol can be represented by using______
Answer:
Escape Sequence.

Question 17.
Manish wants to write a program to produce a beep sound. Which escape sequence is used to get an alert (sound).
(a) \a
(b) \d
(c) \s
(d) None of these
Answer:
(a) \a.

Question 18.
Ajo wants to print a matter in a new line. Which es-cape sequence is used for this?
(a) \a
(b) \n
(c) \s
(d) None of these
Answer:
(b) \n.

Question 19.
To represent null character______is used
(a) \n
(b) \0
(c) \f
(d) \s
Answer:
(b) \0.

Question 20.
State True/False a string is automatically appended by a null character.
Answer:
True.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 21.
From the following pick a string constant.
(a)  ‘a’
(b) “abc”
(c) ‘abc’
(d) None of these
Answer:
(b) “abc”, a character constant must be enclosed between double quotes.

Question 22.
C++ was developed by______
(a) Bjarne Stroustrup
(b) James Gosling
(c) Pascal
(d) None of these
Answer:
(a) Bjarne Stroustrup.

Question 23.
From the following which is not a character constant.
а) ‘c’
b) ‘e’
c) ‘d’
d) “c”
Answer:
(d) “c”, It is a string constant the others are character constant.

Question 24.
From the following which is a valid declaration.
(a) int 91;
(b) int x;
(c) int 9x;
(d) int “x”;
Answer:
(b) int x;

Question 25.
Symbols used to perform an operation is called_______
(a) Operand
(b) Operator
(c) Variable
(d) None of these
Answer:
(b) Operator.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 26.
Consider the following. C = A + B. Here A and Bare called______
(a) Operand
(b) Operator
(c) Variable
(d) None of these
Answer:
(b) Operand.

Question 27.
The. execution of a program starts at_______function.
Answer:
main()

Question 28.
The execution of a program ends with______function
Answer:
main()

Question 29.
______USed to write single line comment
(a) //
(b) /*
(c) */
(d) None of these
Answer:
(a) //

Question 30.
const k = 100 means const k = 100
(a) const float k = 100
(b) const double k = 100
(c) const int k = 100
(d) const chark = 100
Answer:
(c) const int k = 100

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 31.
Each and every statement in C++ must be end with_____
(а) Semi colon
(b) Colon
(c) full stop
(d) None of these
Answer:
(a) Semi colon

Question 32.
From the following select the input operator.
(a) >>
(b) <<
(c) >
(d) <
Answer:
(a) >>

Question 33.
From the following select the output operator.
(a) >>
(b) <<
(c) >
(d) <
Answer:
(b) <<

Question 34.
In while loop, the loop variable should be updated?
(a) along with while statement
(b) after the while statement
(c) before the while statement
(d) inside the body of while
Answer:
(d) Inside the body of while

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 35.
Adeline wrote a C++ program namely sum.cpp and she compiled the program successfully with no error. Some files are generated. From the following which file is a must to run the program
(a) sum.exe
(b) sum.obj
(c) sum.vbp
(d) sum.htm
Answer:
(a) sum.exe

Question 36.
Adeline wrote a C++ program namely sum.cpp and she compiled the program successfully with no error. Some files are generated namely sum.obj and sum.exe. From this which file is not needed to run the program
Answer:
sum.obj is not needed and can be deleted.

Question 37.
To terminate a program, from the following which is used.
(a) break
(b) continue
(c) end()
(d) exit()
Answer:
(d) exit()

Question 38.
To write a C++ program, from the following which statement is a must.
(a) sum()
(b) main()
(c) #include
(d) #include
Answer:
(b) main(). A C++ program must contains at least one main() function.

Question 39.
State True / False. Comment statements are ignored by the compiler
Answer:
True.

Question 40.
More than one input / output operator in a single statement is called______.
Answer:
Cascading of I/O operator.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 41.
From the following which is ignored by the compiler.
(a) statement
(b) comments
(c) loops
(d) None of these
Answer:
(b) comments

Question 42.
From the following which is known as string terminator
(a) ‘\0’
(b) ‘\a’
(c) *\s*
(d) ‘\t’
Answer:
(a) ‘\0’

Question 43.
______is the main activity carried out in computers.
Answer:
Data processing.

Question 44.
The data used in computers are different. To differentiate the nature and size of data______is used.
Answer:
Data types.

Question 45.
Classify the following data types.

  1. int
  2. array
  3. function
  4. char
  5. pointer
  6. void
  7. float
  8. double
  9. structure

Answer:

Fundamental data typesDerived data types
intarray
floatfunction
doublepointer
voidstructure
char

Question 46.
Sheela wants to store her age. From the following which is the exact data type.
(a) void
(b) char
(c) int
(d) double
Answer:
(c) int

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 47.
Integer data type uses_____bytes of memory
(a) 5
(b) 2
(c) 3
(d) 4
Answer:
(b) 2

Question 48.
char data type uses______bytes of memory
(a) 1
(b) 3
(c) 7
(d) 8
Answer:
(a) 1

Question 49.
From the following which data type uses 4 bytes of memory
(a) float
(b) short
(c) char
(d) double
Answer:
(a) float

Question 50.
Full form of ASCII is______.
Answer:
American Standard Code for Information Interchange.

Question 51.
Ramu wants to store the value of From the following which is correct declaration
(а) char pi = 3.14157
(b) int pi = 3.14157
(c) float pi = 3.14157
(d) long pi = 3.14157
Answer:
(c) float pi = 3.14157.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 52.
From the following which is not true, to give a variable name.
(a) Starting letter must be an alphabet
(b) contains digits
(c) Cannot be a key word
(d) special characters can be used
Answer:
(d) special characters can be used

Question 53.
Pick a valid variable name from the following
(а) 9a
(b) float
(c) age
(d) date of birth
Answer:
(c) age

Question 54.
To perform a unary operation how many number of operands needed?
(a) 2
(b) 3
(c) 1
(d) None of these.
Answer:
(c) 1 (Unary means one)

Question 55.
To perform a binary operation how many number of operands needed?
(a) 2
(b) 3
(c) 1
(d) None of these.
Answer:
(a) 2 (binary means two)

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 56.
To perform a ternary operation how many number of operands needed?
(a) 2
(b) 3
(c) 1
(d) None of these.
Answer:
(b) 3(eg: ternary means three)

Question 57.
In C++ 13 % 26 =_______
(a) 26
(b) 13
(c) 0
(d) None of these
Answer:
13. % is a mod operator i.e. it gives the remainder. Here the remainder is 13.

Question 58.
In C++ 41/2 =______
(a) 20.5
(b) 20
(c) 1
(d) None of these
Answer:
(b) 20. (The actual result is 20.5 but both 41 and 2 are integers so .5 must be truncated).

Question 59.
++ is a_____operator
(a) Unary
(b) Binary
(c) Ternary
(d) None of these
Answer:
(a) Unary.

Question 60.
Conditional operator is______operator
(a) Unary
(b) Binary
(c) Ternary
(d) None of these
Answer:
(c) Ternary

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 61.
% is a_____operator
(a) Unary
(b) Binary
(c) Ternary
(d) None of these
Answer:
(b) Binary

Question 62.
State True/False

  1. Multiplication, division, modulus have equal priority
  2. Logical and (&&) has less priority than logical or ()

Answer:

  1. True
  2. False

Question 63.
______is composed of operators and operands
(a) expression
(b) Key words
(c) Identifier
(d) Punctuators
Answer:
(a) expression

Question 64.
Supply value to a variable at the time of declaration is known as______.
Answer:
Initialisation.

Question 65.
From the following which is initialisation
(a) int k;
(b) int k = 100;
(c) int k[10];
(d) None of these
Answer:
(b) int k= 100;

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 66.
State True/False
In an expression, aH the operands having lower size are converted(promoted) to the data type of the highest sized operand.
Answer:
True

Question 67.
Classify the following as arithmetic / Logical expression.
(a) x + y * z
(b) x < y && y > z
(c) x/y
(d) x > 89 || y < 80
Answer:
(a) and (c) are Arithmetic
(b) and (d) are Logical

Question 68.
Suppose x = 5 and y = 2 then what will be count << (float) x/y.
Answer:
2.5 The integer x is converted to float hence the result.

Question 69.
Considerthe following ,
a = 10; a* = 10;
Then a =______
(a) a = 100
(b) a = 50
(c) a = 10
(d) a = 20
Answer:
(a) a = 100, This short hand means a = a * 10

Question 70.
Consider the following a = 10; a+ = 10; Then a =_____
(a) a = 30
(b) a = 50
(c) a = 10
(d) a = 20
Answer:
(d) a = 20. This short hand means a = a + 10.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 71.
Pick the odd one out
(a) structure
(b) Array
(c) Pointer
(d) int
Answer:
(d) int, it is fundamental data type the others are derived data types.

Question 72.
From the following select not a character of C++ language
(a) A
(b) 9
(c) \
(d) @
Answer:
(d) @

Question 73.
Consider the following float x = 25.56; cout << (int)x;
Here the data type of the variable is converted. What type of conversion is this?
(a) type promotion
(b) type casting
(c) implicit conversion
(d) None of these
Answer:
(b) type casting (explicit conversion);

Question 74.
From the following which is ignored by the compiler
(a) statement
(b) comments
(c) loops
(d) None of these
Answer:
(b) comments

Question 75.
Multi line comment starts with____and ends with_____
(a) /’ and ‘/
(b) */ and /*
(c) /* and */
(d) ‘/ and /’
Answer:
(c) /* and */

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 76.
Single line comment starts with_____
(a) **
(b) @@
(c) */
(d) //
Answer:
(d) //

Question 77.
Alvin wants to store the value of π From the following which is correct declaration
(a) char pi = 3.14157
(b) const int pi = 3.14157
(c) const float pi = 3.14157
(d) long pi = 3.14157
Answer:
(c) const float pi = 3.14157

Question 78.
To store 70000 which modifier is used with int.
(a) long
(b) short
(c) big
(d) none of these
Answer:
(a) long

Question 79.
To store 60000 which modifier is used with int.
(a) unsigned
(b) short
(c) big
(d) none of these
Answer:
(a) unsigned

Question 80.
Consider x++(post fix form). Select the correct definition from the following
(a) The operation is performed after the value is used
(b) The operation is performed before the value is used
(c) First change then use
(d) None of these
Answer:
(a) The operation is performed after the value is used

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 81.
Consider ++x(pre fix form). Select the correct definition from the following
(a) The operation is performed after the value is used
(b) The operation is performed before the value is used
(c) First use then change
(d) None of these
Answer:
(b) The operation is performed before the value is used

Question 82.
Consider the following int a = 10; float b = 4; cout << a/b; We know that the result is 2.5 a float. What type of conversion is this?
(a) type promotion
(b) type casting
(c) explicit coversion
(d) None of these
Answer:
(a) type promotion (implicit conversion);

Question 83.
From the following which has the major priority?
(а) ++
(b) =
(c) ==
(d) &&
Answer:
(a) ++

Question 84.
One of your friend told you that post increment (eg:x++) has more priority than pre increment (eg: ++x). State True/False
Answer:
It is true.

Question 85.
Raju declared a variable as follows. unsigned number;
So he can a store a number in the range______
(a) 0 to 65535
(b) -32768 to 32767
(c) 0 to 65536
(d) 0 to 95536
Answer:
(a) 0 to 65535. Unsigned uses only 2 bytes of memory but no negative numbers can store.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 86.
Considerthe following declaration. signed number;
So we can a store a number in the range______
(a) 0 to 65535
(b) -32768 to 32767
(c) 0 to 65536
(d) 0 to 95536
Answer:
(b) -32768 to 32767

Question 87.
Pick the odd one out
(a) long
(b) short
(c) unsigned
(d) int
Answer:
(d) int. It is fundamental type modifiers.

Question 88.
Memory size and sign can be changed using______with fundamental data types.
Answer:
Type modifiers.

Question 89.
“Its value does not change during execution”. What is it?
Answer:
Constant.

Question 90.
“BVMHSS” is called______
(a) integer constant
(b) float constant
(c) string constant
(d) None of these
Answer:
(c) string constant

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 91.
The address of a variable is called______
Answer:
L-value (Location value) of a variable.

Question 92.
The content of a variable is called_______
Answer:
R-value (Read value) of a variable.

Question 93.
Suppose the address of a variable age is 1001 and the content i.e. age = 33. Then what is R-value and L-value?
Answer:
R-value is 33 and L-value is 1001.

Question 94.
A total of 65535 single window +1 application forms are sold in a district. To store the application form, from the following which is valid?
(a) unsigned app_no;
(b) intapp_no;
(c) signed app_no;
(d) none of these
Answer:
(a) unsigned app_no;

Question 95.
is it possible to declare a variable as and when a need arise. What kind of declaration is this?
Answer:
Yes. It is known as Dynamic declaration.

Question 96.
Emerin wants to store a constant value. Which key word is used for this?
Answer:
constant.

Question 97.
Suppose x = 5. Then cout << x++ displays_____
Answer:
5. Here post increment first use the value then incremented.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 98.
Suppose x = 5. Then cout << ++x displays_____
Answer:
6. Here pre increment first incremented and then use the value.

Question 99.
An if statement contains another if statement completely. Then it is known as______
Answer:
Nested if

Question 100.
From the following which is not optional with switch statement.
Answer:
(a) break
(b) default
(c) case
(d) none of these
Answer:
(c) case.

Question 101.
To exit from a switch statement______is used
(a) quit
(b) exit
(c) break
(d) none of these
Answer:
(c) break

Question 102.
From the following which statement is true for switch statement
(a) switch is used to test the equality
(b) switch is used to test relational or logical expression
(c) switch can handle real numbers case data
(d) none of these
Answer:
(a) switch is used to test the equality

Question 103.
Sonet wants to execute a statement more than once. From the following which is exactly suitable.
(a) if
(b) loop
(c) switch
(d) if-else if ladder
Answer:
(b) loop

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 104.
Odd one out
(a) for
(b) if
(c) switch
(d) if-else if ladder
Answer:
(a) for. It is a loop the others are branching statement

Question 105.
Odd one out
(a) for
(b) if
(c) while
(d) do while
Answer:
(b) if. It is a branching statement and the others are loops.

Question 106.
From the following which loop does the three things, initialisation, checking, and updation.
(a) while
(b) do while
(c) for
(d) none of these
Answer:
(c) for

Question 107.
Predict the output for(i=1;i<=10;i++); cout<<i;
(a) 10
(b) 1 to 10.
(c) 11
(d) None of these
Answer:
(c) 11.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 108.
From the following which is exit controlled loop
(a) for
(b) while
(c) do while
(d) None of these
Answer:
(c) do while

Question 109.
_____statement is used for unconditional jump from one location to another.
Answer:
goto.

Question 110.
Sunitha wants to skip one iteration. From the following which will help her?
(a) continue
(b) break
(c) for
(d) case
Answer:
(a) continue.

Question 111.
Pick the odd one out from the following. Give reason
1. (a) for
(b) while
(c) do____while
2. (a) if
(b) switch
(c) for
Answer:

  1. do_____while . It is an exit controlled loop others are entry controlled loop
  2. for. It is a loop while others are branching statements.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 112.
Identify the error in the following C++ statement and correct it. short population = 68000;
Answer:
The maximum number that can store in short type is less than 32767. So to store 68000 we have to use long data type.

Question 113.
What would be the appropriate data type to store the following?

  1. Number of students in a classroom
  2. Age of a student
  3. Average mark of a student
  4. A question mark (?)

Answer:

  1. short or int
  2. short or int
  3. float
  4. char

Question 114.
Pick odd one out from the following loops. Give the reasons.
(a) for
(b) while
(c) do___while
Answer:
(c) do while. This is an exit controlled loop others are entry controlled loop.

Question 115.
Which of the following data types of C++ has no type modifier?
(a) void
(b) int
(c) char
(d) short
Answer:
(a) void

Plus Two Computer Application Review of C++ Programming Two Mark Questions and Answers

Question 1.
Mr. Dixon declared a variable as follows
int 9 age. Is it a valid identifier. If not briefly explain the rules for naming an identifier.
Answer:
It is not a valid identifier because it violates the rule 1. The rules for naming an identifier is as follows.

  • It must be start with a letter(alphabet)
  • Underscore can be considered as a letter
  • White spaces and special characters cannot be used.
  • Key words cannot be considered as an identifier

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 2.
Rose wants to print as follows \n is used for New Line
Write down the C++ statement for the same.
Answer:
# include
using namespace std;
{
cout<<“\\n is used for New Line”;
}

Question 3.
Alvis wants to give some space using escape sequence as follows
Welcome to C++
Write down the C++ statement for the same
Answer:
# include
using namespace std;
int main()
{
cout<<“welcome to \t C++”;
}

Question 4.
How many bytes used to store ‘\a’.
Answer:
To store ‘\a’ one byte is used because it is an escape sequence. An escape sequence is treated as one character. To store one character one byte is used.

Question 5.
How many bytes used to store “\abc”.
Answer:
A string is automatically appended by a null character.
Here one byte for \a(escape sequence).
One byte for character b.
One byte for character c.
And one byte for null character.
So a total of 4 bytes needed to store this string.

Question 6.
How many bytes used to store “abc”.
Answer:
A string is automatically appended by a null character.
Here one byte for a.
One byte for character b.
One byte for character c.
And one byte for null character.
So a total of 4 bytes needed to store this string.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 7.
We know that the value of pi = 3.14157, a constant (literal). What is a constant? Explain it?
Answer:
A constant ora literal is a data item its value doe not change during execution.

1. Integer literals:
Whole numbers without fractional parts are known as integer literals, its value does not change during execution. There are 3 types decimal, octal, and hexadecimal.
Eg. For decimal 100,150,etc
For octal 0100,0240, etc
For hexadecimal 0 × 100, 0 × 1 A, etc

2. Float literals:
A number with fractional parts and its value does not change during execution is called floating-point literals.
Eg. 3.14157,79.78,etc.

3. Character literal:
A valid C++ character enclosed in single.

Question 8.
Write a program to print the message “TOBACCO CAUSES CANCER” on screen.
Answer:
#include
using namespace std;
int main()
{
cout<<“TOBACCO CAUSES CANCER”;
}

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 9.
Consider the following code
int main()
{
cout<<“welcome to C++”;
}
After you compile this program there is an error called prototype error. Why it is happened? Explain Answer:
Here we used the output operator cout<<. It is used to display a message “welcome to C++” to use this operator the corresponding header file must be included and using namespace std; is also include. We didn’t included the header file hence the error.

Question 10.
You are supplied with a list of tokens in C++ program, Classify and Categorise them under proper headings. Explain each category with its features. tot_mark, age, M5,_____break,(), int, _pay, ; , cin
Answer:
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 1

Question 11.
In C++ the size of the string “book” is 5 and that of “book\n” is 6. Check the validity of the above statement. Justify your answer.
Answer:
A string is automatically added by a null character(\0). The null character is treated as one character. So the size of string “book” is 5. Similarly, a null character (\0) is also added to “book\n”. \n and \0 is treated as single characters. Hence the size of the string “book\n” is 6.

Question 12.
Is 0 × 85B a valid integer constant in C++? If yes why?
Answer:
Yes. It is a hexa decimal number.

Question 13.
Pick the odd man out. Justify
TOTSAL, TOT_SAL, totsal5, Tot5_sal, SALTOT, tot.sal
Answer:
tot.sal. Because it contains a special character dot(.). An identifier cannot contain a special character. So it is not an identifier. The remaining satisfies the rules of naming identifier. So they are valid identifier.

Question 14.
Write a C++ statement to print the following sentence. Justify “\ is a special character”
Answer:

  1. cout<<“\\ is a special character”
  2. \\ is treated as an escape sequence.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 15.
A student type a C++ program and saves it in his personal folder as Sample.cpp. After getting the output of the program, he checks the folder and finds three files namely Sample.cpp, Sample.obj and Sample.exe. Write the reasons for the generation of the two files in the folder.
Answer:
After the compilation of the program sample.cpp, the operating system creates two files if there is no error. The files are one object file (sample.obj) and one executable file(sample.exe). Now the source file(sample.cpp) and object file(sample.obj) are not needed and can be deleted. To run the program sample.exe is only needed.

Question 16.
Write a program to print the message “SMOKING IS INJURIOUS TO HEALTH” on screen.
Answer:
#include
using namespace std;
int main()
{
cout<<” SMOKING IS INJURIOUS TO HEALTH”;
}

Question 17.
Consider the following
short number;
number = 76543;
Is it valid. Explain?
Answer:
It is not valid. Because the data type int uses only two bytes(16 bits) of memory. That is we can store a total of 216 = 65536 integers. There are 2 types of integers negative integers and positive integers, i.e. 32768 each.

So we can store a number in between -32768 to +32767 (0 included in the positive section). The number 76543 is bigger than this range. Hence there is an error overflow. To store this number declare the variable is as follows.
long number;

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 18.
Consider the following declaration.
const int bp;
bp = 100;
Is it valid? Explain it?
Answer:
This is not valid. This is an error. A constant variable cannot be modified. That is the error and a constant variable must be initialised. So the correct declaration is as follows, const int bp = 100;

Question 19.
Consider the following statements in C++

  • cout<<41/2;
  • cout<<41/2.0;

Are this two statements give same result? Explain?
Answer:
This two statements do not give same results. The first statement 41/2 gives 20 instead of 20.5. The reason is 41 and 2 are integers. If two operands are integers the result must be integer, the real part must be truncated.

To get floating result either one of the operand must be float. So the second statement gives 20.5. The reason is 41 is integer but 2.0 is a float.

Question 20.
If mark = 70 then what will be the value of variable result in the following result = mark > 50? ‘P’: ‘F’;
Answer:
The syntax of the conditional operator is given below Condition? Value if true: Value if false; Here the conditional operator first checks the condition i.e.,70 > 50 it is true. So ‘P’ is assigned to the variable result. So the result is d ‘P’;

Question 21.
Is it possible to initialise a variable at the time of execution. What kind of initialisation is this? Give an example.
Answer:
Yes it is possible. This is known as Dynamic initialisation. The example is given below
Eg: int a=10, b=5;
int c = a*b;
here the variable c is declared and initialised with the value 10*5.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 22.
Boolean data type is used to store True / False in C++. Is it true? Is there any data type called Boolean in C++?
Answer:
No there is no data type for storing boolean value true /false. But in C++ non -zero (either negative or positive) is treated as true and zero is treated as false.

Question 23.
Consider the following
n=-15;
if (n)
cout<<“Hello”;
else
cout<<“hai”;
What will be the output of the above code?
Answer:
The output is Hello, because n = -15 a non zero number and it is treated as true hence the result.

Question 24.
Is it possible to declare a variable in between the program as and when the need arise? Then what is it?
Answer:
Yes it is possible to declare a variable in between the program as and when the need arise. It is known as dynamic initialisation.
Eg. int x=10, y=20;
_____
_____
int z=x*y;

Question 25.
charch;
cout<<“Enter a character”; cin>>ch;
Considerthe above code, a user gives 9 to the variable ‘ch’. Is there any problem? Is it valid?
Answer:
There is no problem and it is valid since 9 is a character. Any symbol from the key board is treated as a character.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 26.
“With the same size we can change the sign and range of data”. Comment on this statement.
Answer:
With the help of type modifiers we can change the sign and range of data with same size. The important modifiers are signed, unsigned, long and short.

Question 27.
Write short notes about C++ short hands?
Answer:
x = x + 10 can be represented as x+=10, It is called short hands in C++. It is faster. This is used with all the arithmetic operators as follows.

Arithmetic Assignment ExpressionEquivalent Arithmetic Expression
x+ = 10x = x + 10
x- = 10x = x -10
x* = 10x = x * 10
x/ = 10x = x /10
x% = 10x = x % 10

Question 28.
What is the role of ‘const’ modifier?
Answer:
This ‘const’ key word is used to declare a constant. Eg. const int bp = 100; By this the variable bp is treated as constant and cannot be possible to change its value during execution.

Question 29.
Specify the most appropriate data type for handling the following data.

  1. Rollno. of a student.
  2. Name of an employee.
  3. Price of an article.
  4. Marks of 12 subjects

Answer:

  1. short Rollno;
  2. charname[20];
  3. float price;
  4. short marks[12];

Question 30.
Write C++ statement for the following.

  1. The result obtained when 5 is divided by 2.
  2. The remainder obtained when 5 is divided by 2.

Answer:

  1. 5/2
  2. 5%2

Question 31.
Predict the output of the following code. Justify.
int k = 5, b = 0;
b = k++ + ++k;
cout<<b; (2 Scores)
Answer:
Output is 12. In this statement first it take the value of k in 5 then increment it K++. So first operand for + is 5. Then it becomes 6. Then ++k makes it 7. This is the second operand. Hence the result is 12.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 32.
Predict the output.

  1. int sum = 10, ctr= 5;
    sum = sum + ctr __;
    cout<<sum;
  2. int sum = 10, ctr = 5;
    sum = sum + ++ctr; court<<sum;

Answer:

  1. 15
  2. 16

Question 33.
Predict the output
int a;
float b;
a = 5;
cout<<sizeof(a + b/2);
Answer:
Output is 4. Result will be the memory size of floating point number.

Question 34.
Predict the output.
int a, b, c;
a = 5; b = 2;
c = a/b;
cout<<c;
Answer:
Output is 2. Both operands are integers. So the result will be an integer.

Question 35.
Explain cascading of i/o operations.
Answer:
The multiple use of input or output operators in a single statement is called cascading of i/o operators. Eg: To take three numbers by using one statement is as follows cin>>x>>y>>z; To print three numbers by using one statement is as follows. cout<<x<<y<<z;

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 36.
Trace out and correct the errors in the following code fragments

  1. cout<<“Mark=”45;
  2. cin<<“HellowWorld!”;
  3. cout>>”X + Y;
  4. Cout<<‘Good'<<‘Moming’

Answer:

  1. cout<<“Mark=45”;
  2. cout<<“HellowWorld!”;
  3. cout<<X + Y
  4. Cout<<“Good Morning”;

Question 37.
What do you mean by preprocessor directive?
Answer:
A C++ program starts with the preprocessor directive i.e., #include, #define, #undef, etc, are such a preprocessor directives. By using #include we can link the header files that are needed to use the functions. By using #define we can define some constants.
Eg. #definex100. Here the value of x becomes 100 and cannot be changed in the program.

Question 38
Write a program to print a message as ” Hello, Welcome to C++”.
Answer:
#include
using namespace std;
int main()
{
cout<<” Hello, Welcome to C++”;
}

Question 39.
Write a program to generate the following table.

2013100%
201299.9%
201195.5%
201090.81%
200985%

Use a single cout statement for output
Answer:
# include
using namespace std;
int main ()
{
cout<<“2013\t 100%\n2012\t99.9%\n2011\t95.5%\n2010\t90.81%\n2009\t85%”;
}

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 40.
Determine the data type of the following expression If a is an int, b is a float, c is a long int and d is a double
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 2
Answer:
In type promotion the operands with tower data type will be converted to the highest data type in the expression. So consider the following,
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 3
= double + long
= double (Which is the highest data type).

Question 41.
White writing a program Geo uses while loop but forgets to update the loop variable. What will happen?
Answer:
The loop variable inside the while loop must be updated otherwise the loop will not be terminated. The loop will be work infinitely.

Question 42.
Draw the flow chart of if statement.
Answer:
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 4

Question 43.
Draw the flow chart of if else statement.
Answer:
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 5

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 44.
Write a while loop that display numbers from 500 to 550.
Answer:
int i=500
while (i<=550)
{
cout<<i;
i=i+1;
}

Question 45.
Compare if else and conditional operator?
Answer:
We can use conditional operator as an alternative of if-else statement. The conditional operator is a ternary operator.
The syntax of if-else
if (expression 1)
expression 2;
else
expression 3;
First expression 1 is evaluated if it is true expression 2 will be executed otherwise expression 3 will be executed. Instead of this, we can be written as follows using conditional operator Expression 1? expression 2: expressions;

Question 46.
Draw the flow chart of for loop.
Answer:
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 6

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 47.
Find out the error in syntax if any and correct it? esm<oi!Bl
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 7
Answer:
a) No need of semi colon. The corrected loop is given below
while (test condition)
{
}

b) In do____white loop the while must be end with; semicoion.
do (condition)
{
}while;

c) switch contains expression instead of condition switch(expression)
{
Case 1:
Case 2:
Case 3:
Case 4:
}

Question 48.
State whether the following statements are True or False. In either case Justify your answer

  1. Break statements essential in switch
  2. For loop is an entry controlled loop
  3. Do____white loop is an entry controlled loop
  4. Switch is a selection statement

Answer:

  1. False. It is not essential in single case statement
  2. True. Because it will first check the condition. If it is true then only the body will be executed.
  3. False. It is an exit controlled loop.
  4. True.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 49.
Given a code segment for(i=1; i<10; i++) cout<<i;

  1. Rewrite the code using do____while loop
  2. What will be the output when i=0? Give reason.

Answer:
1. i=1;
do{
cout<<i;
i++;
}while(i<10);

2. When i=0, it will execute one more time. ie. the for loop execute 9 times but here this loop executes 10 times.

Question 50.
Write the equivalent code for the following statement R=(P<Q?P: Q)
Answer:
if(P<Q)
R=P;
else
R=Q;

Question 51.
Examine the following code snippet and find out the output? What will happen if the statement int ch; is replaced char ch;
int ch;
for(ch=’A’;ch<=’Z’;++ch)
cout<<ch<<”;
Answer:
This code snippet will print 65, 66, 67, ______,90. If the statement int ch; is replaced by char ch; it prints A, B, C,_____,Z.

Question 52.
Your friend usee the following identifiers in a program. Find out the invalid identifiers with reason if not valid, basic pay area, data-of-birth, B3, 9A, switch
Answer:
basic pay – Invalid because white space is not allowed.
area – valid
date-of-birth – Invalid because hyphen(-) is not allowed.
B3 – Valid
9A – Invalid because should not begin with number.
switch – Invalid because keywords not allowed.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 53.
int x=5;
int y=10;
cout<<(x+y)%2;
Answer:
(x+y) % 2 = (5+10)%2 = 15% 2 =1 It prints 1.

Question 54.
Classify the following C++ tokens in accordance to the table given below.
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 8
Answer:
keyword: int, do
Identifier: digit, cin(pre defined identifier, eg. int cin; is possible);
Literal: “break”(string literal), 25.6(float literal).
Operator: %(Mod operator), = (assignment operator).

Question 55.
Rewrite the following C++ code using conditional operator.
if (a>b)
max=a;
else
max=b;
Answer:
max=(a>b)?a:b;

Question 56.
Write the C++ expression to calculate the value of the following expression.

  1. x = \(\frac{\left(b^{2}-4 a c\right)}{2 a}\)
  2. y = a2 + 2ab + b2

Answer:

  1. x= (b*b – 4*a*c)/(2*a);
  2. y= a*a + 2*a*b + b*b;

Question 57.
Consider the following code and predict the output. Justify your answer.
for(int i=i;i<10;++i)
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 9
Answer:
The output is 1 2 3 4 5 6 7. This loop is used to print 1 to 10 but this loop will terminate when the value of i becomes 8. Hence it prints 1 to 7.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 58.
Predict the output for the following program code.
for(i=1;i<=10;++i)
{
if (i==7)
coutinue;
cout<<“\t”;
cout<< i;
}
Answer:
The output is 1 2 3 4 5 6 8 9 10.
This loop is used to print 1 to 10 but this loop will by pass one iteration when the value of i becomes 7. Hence it prints 1 to 10 except 7.

Question 59.
How many times the following loop will be executed?
int s = 0, i = 0;
do
{
S+= i;
i++;
} while(i < = 5);
Answer:
This loop will be executed 6 times. The value of i becomes 1 to 6.

Plus Two Computer Application Review of C++ Programming Three Mark Questions and Answers

Question 1.
In a panchayath or municipality, all the houses have a house number, house name, and members. Similar situation is in the case of memory. Explain.
Answer:
The named memory locations are called variable. A variable has three important things

  1. variable name: A variable should have a name
  2. Memory address: Each and every byte of memory has an address. It is also called location (L) value
  3. Content: The value stored in a variable is called content.lt is also called Read(R) value.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 2.
Briefly explain constants
Answer:
A constant or a literal is a data item its value doe not change during execution. The keyword const is used to declare a constant. Its declaration is as follows
const data type variable name=value;
eg.const int bp = 100;
const float pi = 3.14157;
const char ch = ‘a’;
const char[] = “Alvis”;

1. Integer literals:
Whole numbers without fractional parts are known as integer literals, its value does not change during execution. There are 3 types decimal, octal, and hexadecimal.
Eg. For decimal 100,150,etc
For octal 0100,0240, etc
For hexadecimal 0 × 100, 0 × 1A,etc.

2. Float literals:
A number with fractional parts and its value does not change during execution is called floating point literals.
Eg. 3.14157,79.78,etc.

3. Character literal:
A valid C++ character enclosed in single quotes, its value does not change during execution.
Eg. ‘m’, ‘f, etc.

4. String literal:
One or more characters enclosed in double quotes is called string constant. A string is automatically appended by a null charater(‘\0’)
Eg. “Mary’s”,”India”,etc.

Question 3.
Considerthe following statements
int a=10, x=20;
float b=49000.34, y=56.78;

  1. a=b;
  2. y=x;

Is there any problem for the above statements? What do you mean by type compatibility?
Answer:
Assignment operator is used to assign the value of RHS to LHS. Following are the two chances

  1. The size of RHS is less than LHS. So there is no problem and RHS data type is promoted to LHS. Here it is compatible.
  2. The size of RHS is higher than LHS. Here comes the problem sometimes LHS cannot possible to assign RHS. There may be a chance of wrong answer. Here it is not compatible.
    Here

    • a=b; There is an error since the size of LHS is 2 but the size of RHS is 4.
    • y=x; There is no problem because the size of LHS is 4 and RHS is 2.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 4.
A company has decided to give incentives to their salesman as per the sales. The criteria is given below.
If the total sales exceeds 10,000 the incentive is 10%

  1. If the total sales >=5,000 and total sales <10,000, the incentive is 6 %
  2. If the total sales >=1,000 and total sales <5,000, the incentive is 3 %

Write a C++ program to solve the above problem and print the incentive after accepting the total sales of a salesman. The program code should not make use of if statement.
Answer:
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 10

Question 5.
A C++ program code is given below to find the value of X using the expression
X = \(\frac{a^{2}+b^{2}}{2 a}\) where a and b are variables 2a
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 11
Pre did the type of errors during compilation, execution, and verification of the output. Also write the output of two sets of input values

  1. a=4, b=8
  2. a=0, b=2

Answer:
This program contains some errors and the correct program is as follows.
#include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 12
The output is as follows

  1. a=4 and b= 8 then the output is 10
  2. a=0 and b= 2 then the output is an error divide by zero error(run time error).

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 6.
We know that a program has a structure. Explain the structure of C++ program.
Answer:
A typical C++ program would contain four sections as shown below.
Include files
Function declarations
Function definitions
Main function programs
Eg.
# include
using namespace std;
int sum(int x, int y)
{return (x+y);}
int main()
{
cout<<sum(2,3);
}
}

Question 7.
Write a program to read two numbers and find its sum.
Answer:
#include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 13

Question 8.
Write a program to read three scores and find the average.
Answer:
#include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 14
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 15

Question 9.
Write a program to find the area and perimeter of a circle.
Answer:
#include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 16

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 10.
Write a program to find the simple interest
Answer:
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 17

Question 11.
Write a program to convert temperature from Celsius to Fahrenheit.
Answer:
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 18

Question 12.
Write a program to read weight in grams and convert it into Kilogram.
Answer:
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 19

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 13.
Write a program to read your height in meter and cm convert it into Feet and inches
Answer:
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 20

Question 14.
Write a program to find the area of a triangle.
Answer:
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 21

Question 15.
Write a program to

  1. print ASCII for a given digit.
  2. print ASCII for backspace.

Answer:
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 22

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 16.
Write a program to read time in seconds and convert it into hours, minutes and seconds.
Answer:
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 23

Question 17.
Two pairs C++ expressions are given below.

  1. a=10, a==10
  2. b=a++, b=++a
    • How do they differ?
    • What will be the effect of the expression

Answer:
1. = is an assignment operator that assigns a value 10 to the LHS (Left Hand Side)variable a But == is equality operator that checks whether the LHS and RHS are equal or not. If it is equal it returns a true value otherwise false

2. In a++,++is a post(means after the operand) increment operator and in ++a, ++ is a pre(means before the operand) increment operator. They are entirely different.

Post increment:
Here first use the value of ‘a’ and then change the value of ‘a’.
Eg: if a= 10 then b=a++. After this statement b= 10 and a=11

Pre increment:
Here first change the value of a and then use the value of a.
Eg: if a=10 then b=++a. Afterthis statement b=11 and a=11.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 18.
Consider the following
int a=45.65;
cout<<a;
What is the output of the above. Is it possible to convert a data type to another type? Explain.
Answer:
The output of the code is 45, the floating-point number is converted into integer. It is possible to convert a data type into another data type. Type conversions are two types.

1. Implicit type conversion:
This is performed by C++ compiler internally. C++ converts all the lower sized data type to the highest sized operand. It is known as type promotion. Data types are arranged lower size to higher size is as follows, unsigned int(2 bytes), int(4 bytes), long(4 bytes), unsigned long(4 bytes), float(4 bytes), double(8 bytes), long double(10 bytes).

2. Explicit type conversion:
It is known as type casting. This is done by the programmer. The syntax is given below.
(data type to be converted) expression
Eg.int x=10;
(float) x; This expression converts the data type of the variable from integer to float.

Question 19.
Your friend Arun asked you that is there any loop that will do three things, initialization, testing, and updation. What is your answer? Explain?
Answer:
Yes. There is only one loop namely for loop that will do this three things. The other loops will do the checking only, initialisation must be do before the loop and updation must be inside the loop.
The syntax of for loop is given below
For(initialisation; testing; updation)
{
Body of the for loop;
}

Question 20.
Distinguish between exit(0) function and return statement
Answer:
Both are used to terminate the program but both are different. Return is a keyword and exit(O) is a function. The difference is, we can use more than one exit(0) function but we can use only one return statement in a scope. To use exit(0), the header file cstdlib should be used.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 21.
Rewrite the program following program using if else
#include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 24
Answer:
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 25

Question 22.
Rewrite the following using nested switch construct.
#include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 26
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 27
Answer:
#include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 28

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 23.
Consider the following output and write down the code for the same.
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 29
Answer:
include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 30

Question 24.
Consider the following output and write down the code for the same.
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 31
Answer:
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 32

Question 25.
Consider the following output and write down the code for the same.
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 33
Answer:
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 34

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 26.
Consider the following output and write down the code for the same.
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 35
Answer:
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 36

Question 27.
Consider the following output and write down the code for the same.
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 37
Answer:
#include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 38

Question 28.
Consider the following output and write dawn the code for the same.
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 39
Answer:
#include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 40

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 29.
Write a program to print the sum of first n natural numbers
Answer:
# include
using namespace std;
int main()
int n,i,sum=0;
cout<<“Entera value torn”; cin>>n;
for(i=1;i<=n;i++)
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 41

Question 30.
Write a program to read a number and check whether it is palindrome or not
Answer:
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 42

Question 31.
Write a program to print the factorial of a number.
Answer:
#include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 43

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

This Fibonacci calculator will generate a list of Fibonacci numbers from start and end values of n.

Question 32.
Write a program to print the Fibonacci series Fibonacci
Answer:
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 44
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 45

Question 33.
Write a program to read a number and check whether the given number is Armstrong or not
Answer:
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 46

Question 34.
Distinguish between entry controlled loop and exit controlled loop
Answer:
An entry controlled loop first checks the condition and execute(or enters in to) the body of loop only if it is true. But exit control loop first execute the body of the loop once even if the condition is false then check the condition. The for loop and while loop are entry controlled loops but do-while loop is an exit controtted loop.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 35.
Write a program to find the largest of 3 numbers
Answer:
#include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 47

Question 36.
Check whether a given number is prime or not
Answer:
#include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 48

Question 37.
Write a program to read number and display its factors.
Answer:
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 49

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 38.
You are given the heights of 3 students. Write the relevant code segment to find the maximum height?
Answer:
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 50

Question 39.
Write the easiest code snippet for printing your name 1000 times. Explain
Answer:
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 51

Question 40.
Whenever a string is entered the inverse of that string is displayed( eg: if we enter ‘CAR’ the output is ‘RAC’). Write a suitable programme for the output.
Answer:
#include
#include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 52

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 41.
Write a C++ program to display as follows
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 53
Answer:
#include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 54

OR

#include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 55

Question 42.
Consider the following code The new line.character is \n. The output of the following code does not contain the \n. Why it is happened? Explain.
Answer:
\n is a character constant and it is also known as escape sequence. This is used to represent the non graphic symbols such as carriage return key(enter key), tab key, back space, space bar, etc. It con¬sists of a back slash symbol and one more characters.

Escape sequenceNon-graphic character
\aAudible bell
\bback space
\nfor new line
\rcarnage return
\thorizontal tab
\vvertical tab
\\to print \
\’to print ‘
\”to print ”
\?To print?
\0null character

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 43.
The Maths teacher gives the following problem to Riya and Raju.
x= 5 + 3 * 6. Riya got x = 48 and Raju got x = 23. Who is right and why it is happened? Write down the operator precedence in detail?
Answer:
Here the answer is x = 23. It is because of precedence of operators. The order of precedence of operators are given below.
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 56
Here multiplication has more priority than addition.

Question 44.
Rewrite the following code using while and do..while loop.
for(i=1;i<5;++i)
{
cout<<“\n”<<i;
}
Answer:
1. using while loop
i=1;
while(i<=5)
{
cout<<“\n”<<i;
i++;
}

2. using do while loop
i=1;
do
cout<<“\n”<<i;
i++;
}while(i<=5);

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 45.
Rewrite the following C++ code using switch
statement.
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 57
Answer:
switch(choice)
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 58

Question 46.
Considerthe following code and predict the output
int a=5, b=6, c=7;
if (a<b) || b>c)
cout<<“\nOne”;
if (a<b&&b>c)
cout<<“\nTwo”; if (! *a>b)
cout<<“\nThree”;
Answer:
case 1:
if(ac)
cout<<“\nOne”;
here ac
5<6 || 6>7
True || False = True.
This condition returns True
Hence it prints One.

case 2:
if(ac)
cout<<“\nTwo”;
here ac
5<6 && 6>7
True && False = False
This condition returns False
Hence it prints nothing.

Case 3:
if(! (a>b))
cout<<“\nThree”); here !(a>b)
! (5 >6)
! (False)
This condition returns True
Hence it prints Three.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 47.
Match the following

NameSymbol
Modulus operator+ +
Logical operator= =
Relational operator=
Assignment operator?=
Increment operator%
Conditional operator&&

Answer:

NameSymbol
Modulus operator%
Logical operator&&
Relational operator= =
Assignment operator=
Increment operator+ +
Conditional operator?=

Question 48.
Write a C++ program to calculate the simple interest SI, by accepting the value principal amount P, rate of interest R and number of years N using the equation SI = PNR/100.
Answer:
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 59

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 49.
Rewrite the following conditional statement with ‘if statement in C++.
min=(a<b) ? (a<c? a:c) : (b<c? b:c);
Answer:
if(a<b && a<c)
min=a;
else if(b<c) min=b; else min=c;

Plus Two Computer Application Review of C++ Programming Five Mark Questions and Answers

Question 1.
Define operator and explain operators in detail. Operators
Answer:
An operator is a symbol that performs an operation. The data on which operations are carried out are called operands. Following are the operators.
1. Input(>>) and output(<<) operators are used to perform input and output operation. Eg. cin>>n; cout<<n;

2. Arithmetic operators:
It is a binary operator. It is used to perform addition(+), subtraction (-), division (/), multiplication (*) and modulus (%-gives the remainder) operations.
Eg. If x=10 and y=3 then
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 60
x/y = 3, because both operands are integer. To get the floating point result one of the operand must be float.

3. Relational operator:
It is also a binary operator. It is used to perform comparison or relational operation between two values and it gives either true(1) or false(O). The operators are <,<=,>,>=,== (equality)and !=(not equal to)
Eg. If x=10 and y=3 then
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 61

4. Logical operators:
Here AND(&&), OR (||) are binary operators and NOT (!) is a unary operator. It is used to combine relational operations and it gives either true (1) or false (0).
If x=1 and y=0 then
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 90
Both operands must be true to get a true value in the case of AND (&&) operation
If x=1 and y=0 then
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 62
Either one of the operands must be true to get a true value in the case of OR(||) operation
If x=1 and y=0 then
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 63

5. Conditional operator:
It is a ternary operator hence it needs three operands. The operator is?: Syntax: expression? value if true: value if false. First evaluates the expression if it is true the second part will be executed otherwise the third part will be executed.
Eg. If x=10 and y=3 then
x>y? cout<< Here the output is 10.

6. sizeof():
This operator is used to find the size used by each data type.
Eg. sizeof(int) gives 2.

7. Increment and decrement operator:
These are unary operators.

  • Increment operator (++): It is used to increment the value of a variable by one i.e., x++ is equivalent to x=x+1;
  • Decrement operator (–): It is used to decrement the value of a variable by one i.e., x- is equivalent to x = x-1.

8. Assignment operator (=):
It is used to assign the value of a right side to the left side variable.eg. x=5; Here the value 5 is assigned to the variable x.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 2.
A list of data items are given below
45, 8.432, M, 0.124, 8, 0, 8.1X 1031, 1010, a, 0.00025, 9.2 × 10120, 0471, -846, 342.123E03

  1. Categorise the given data under proper headings of fundamental data types in C++
  2. Explain the specific features of each data type. Also mention any other fundamental data type for which sample data is not given

Answer:
1.
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 64

2.
(i) int data type:
It is used to store whole numbers without fractional (decimal point) part. It can be either negative or positive. It consumes 4 bytes (32 bits) of memory. i.e. 232 numbers. That is 231 negative numbers and 231 positive numbers (0 is considered as +ve) So a total of 232 numbers. We can store a number in between -231 to + 231-1.

(ii) char data type:
Any symbol from the key board, eg. ‘A’,’?’, ‘9’,___It consumes one byte( 8 bits) of memory. It is internally treated as integers, i.e. 28 = 256 characters. Each character is having a ASCII code, ‘a’ is having ASCI I code 97 and zero is having ASCII code 48.

(iii) float data type:
It is used to store real numbers i.e. the numbers with decimal point. It uses 4 bytes(32 bits) of memory. Eg. 67.89, 89.9 E-15.

(iv) double data type:
It is used to store very large real numbers. It uses 8 bytes(64 bits) of memory.
void data type:- void means nothing. It is used to represent a function returns nothing.

Question 3.
Write valid reasons after reading the following statements in C++ and comment on their correctness by give reasons.

  1. char num = 66;
  2. char num – B’;
  3. 35 and 35L are different
  4. The number 14,016 and OxE are one and the same
  5. Char data type is often said to be an integer type
  6. To store the value 4.15 float data type is preferred over double

Answer:

  1. The ASCII number of B is 66. So it is equivalent.
  2. 35 is of integer type but 35L is Long
  3. The decimal number 14 is represented in octal is 016 and in hexadecimal is OxE.
  4. Internally char data type stores ASCII numbers.
  5. To store the value 4.15 float data type is better because float requires only 4 bytes while double needs 8 bytes hence we can save the memory.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 4.
Suggest most suitable derived data types in C++ for storing the following data items or statements

  1. 0 Age of 50 students in a class
  2. Address of a memory variable
  3. A set of instructions to find out the factorial of a number
  4. An alternate name of a previously defined variable
  5. Price of 100 products in a consumer store
  6. Name of a student

Answer:

  1. Integer array of size 50
  2. Pointer variable
  3. Function
  4. Reference
  5. Float array of size 100
  6. Character array

Question 5.
Considering the following C++ statements. Fill up the blanks

  1. lf p=5 and q=3 then q%p is _____
  2. If E1 is true and E2 is False then E1 && E2 will be_____
  3. If k=8, ++k <= 8 will be______
  4. If x=2 then (10* ++x) % 7 will be_____
  5. If t=8 and m=(n=3,t-n), the value of m will be______
  6. If i=12 the value i after execution of the expres¬sion i+=i– + –i will be______

Answer:

  1. 3
  2. False
  3. False(++k makes k=9. So 9<=8 is false)
  4. 2(++x becomes 3, so 10 * 3 =30%7 =2)
  5. 5( here m=(n=3,8-3)=(n=3,5), so m=5, The maximum value will take)
  6. Here i=12

i + = i– + –i
here post decrement has more priority than pre decrement. So i — will be evaluated first. Here first uses the value then change so it uses the value 12 and i becomes 11
i + =12 + –i
now i =11.
Here the value of i will be changed and used so i– becomes 10
i + = 12 + 10
= 22
So i = 22 + 10
i = 32
So the result is 32.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 6.
Analyses the following statements and write Time or False. Justify

  1. There is an Operator in C++ having no special character in it
  2. An operator cannot have more than 2 operands
  3. Comma operator has the lowest precedence
  4. All logical operators are binary in nature
  5. It is not possible to assign the constant 5 to 10 different variables using a single C++ expression
  6. In type promotion the operands with lower data type will be converted to the highest data type in expression

Answer:

  1. True (sizeof operator)
  2. False( conditional operator can have 3 operands
  3. True
  4. False
  5. False(Multiple assignment is possible, eg: a=b=c=___=5)
  6. True

Question 7.
Match the following numbers and data types in C++ to form the most suitable pairs.

1. 142789a. Signed
2. 240b. Double
3. -150c. Long int
4. 8.4 × 10-4000d. Float
5. 0e. Long double
6. 0.0008f. Unsigned short
7. -127g. Short int
8. 2.8 × 10308h. Signed char

Answer:

1. 142789a.  Long int
2. 240b. Short int
3. -150c.  Signed
4. 8.4 × 10-4000d.  Long double
5. 0e.  Unsigned short
6. 0.0008f.   Float
7. -127g.  Signed char
8. 2.8 × 10308h.  Double

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 8.
#include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 65
Rewrite the above code using if else if ladder.
Answer:
#include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 66
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 67

Question 9.
Consider the following code
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 68
Is it possible to rewrite the above program using switch statement? Distinguish between switch and if else if ladder. Answer:
No. It is not possible to write the above code using switch statement. Following are the difference between switch and if else if ladder.

  1. Switch can test only for equality but if can evaluate a relational or logical expression
  2. If else is more versatile
  3. If else can handle floating values but switch can not
  4. If the test expression contains more variable if else is used
  5. Testing a value against a set of constants switch is more efficient than if else

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 10.
Write down the code for the following output using while loop.
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 69
Answer:
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 70

Question 11.
“We know that the execution of a program is sequential”. Is it possible to change this sequential manner and explain different jump statements in detail.
Answer:
The execution of a program is sequential but we can change this sequential manner by using jump statements. The jump statements are
1. goto statement:
By using goto we can transfer the control anywhere in the program without any condition. The syntax is goto label; Eg. # include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 71

2. break statement:
It is used to skip over a part of the code i.e. we can premature exit from a loop such as while, do-while, for or switch. Syntax:
while (expression)
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 72
The output is
1
2
3
4
5.

3. continue statement:
It bypasses one iteration of the loop.
Syntax:
while (expression)
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 73
The output is
1
2
3
4
5
6
7
8
9
10.

4. exit(O) function:
It is used to terminate the program. For this the header file cstdlib must be included.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 12.
Write a program to print the prime numbers less than 100
Answer:
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 74

Question 13.
Write a program to print the Armstrong numbers less than 1000
Answer:
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 75

Question 14.
Given the total mark of each student in SSLC examination. Write a C++ code fragment to find the grades.
Answer:
# include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 76

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 15.
You are about to study the fundamentals of C++ programming Language. Do a comparative study of the basics of the new language with that of a formal language like English or Malayalam to familiarize C++?. Provide sufficient explanations for the compared items in C++ Language.
Answer:
Character set:
To study a language first we have to familiarize the character set. For example to study English language first we have to study the alphabets. Similarly here the characterset includes letters(A to Z & a to z), digits(0 to 9), special characters(+,-,?,*,/,___) white spaces(non printable) etc. Token: It is the smallest individual units similar to a word in English or Malayalam language. C++ has 5 tokens
1. Keywords:
These are reserved words for the compiler. We can’t use for any other purposes
Eg: float is used to declare variable to store numbers with decimal point. We can’t use this for any other purpose

2. Identifier:
These are user defined words.
Eg: variable name, function name, class name, object name etc….

3. Literals (Constants):
Its value does not change during execution
Eg: In maths pi = 3.14157 and boiling point of water is 100.

4. Punctuators:
In English or Malayalam language punctuation mark are used to increase the read ability but here it is used to separate the tokens.
Eg:{.}.(.)…..

5. Operators:
These are symbols used to perform an operation(Arithmetic, relational, logical,etc…)code, the middle button displays the object and the right button toggles the folder.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 16.
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 77
Consider the above data, we know that there are different types of data are used in the computer. Explain different data types used in C++.
Answer:
1. int data type:
It is used to store whole numbers without fractional (decimal point) part. It can be either negative or positive. It consumes 2 bytes(16 bits) of memory.i.e. 216 = 65536 numbers. We can store a number in between -32768 to + 32767.

2. char data type:
Any symbol from the keyboard, eg. ‘A’,’9′,…. It consumes one byte( 8 bits) of memory. It is internally treated as integers, i.e. 28 = 256 characters. Each character is having a ASCII code, ‘a’ is having ASCII code 97 and zero is having ASCII code 48.

3. float data type:
It is used to store real numbers i.e. the numbers with decimal point. It uses 4 bytes(32 bits) of memory. Eg. 67.89, 89.9 E-15.

4. double data type:
It is used to store very large real numbers. It uses 8 bytes(64 bits) of memory.

5. void data type:
void means nothing. It is used to represent a function returns nothing.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 17.
Explain conditional statements in detail?
Answer:
1. Simple if:
The syntax is given below
if(expression)
statement;
or
if(expression)
{
Block of statements
}
First expression evaluates if it is true then only statement will be executed.
Eg. if (n>0)
cout<<n<<” is positive”;

2. if else:
The syntax is given below.
if (expression)
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 78
First expression evaluates if it is true statement block 1 will be executed otherwise statement block 2 will be executed. Only one block will be executed at a time so it is called branching statement.
Eg.
if (n>0)
cout<<n<<” is positive”;
else
cout<<n<<” is negative”;

3. if else if ladder:
The syntax will be given below
if (expression 1)
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 79
Here first expression 1 will be evaluated if it is true only the statement block 1 will be executed otherwise expression 2 will be executed if it is true only the statement block2 will be executed and soon. If all the expression evaluated is false then only statement block n will be evaluated.
Eg.
If(mark>=90)
cout«<<“Your grade is A+”;
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 80

4. conditional operator:
It is a ternary operator and it is an alternative for if else construct. The syntax is given below. expression 1? expression 2: expression 3; or expression 1? Value if true: value if false; Here expression 1 will be evaluated if it true ex¬pression 2 will be executed otherwise expression 3 will be executed. Eg. n>0?cout<<n<<” is positive”:cout<<n<<” is negative”;

5. Switch:
It is a multiple branch statement. Its syntax is given below.
switch(expression)
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 81
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 82

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 18.
Explain different loops in detail?
Answer:
1. For loop:
The syntax of for loop is
for(initialization; checking ; update loop variable)
{
Body of loop;
}
First part, initialization is executed once, then checking is carried out if it is true the body of the for loop is executed. Then loop variable is updated and again checking is carried out this process continues until the checking becomes false. It is an entry controlled loop.
Eg. for(i=1 ,j=1 ;i<=10;i++,j++)
cout<<i<<” * “<<j<<” = “<<i*j;

2. While loop:
It is also an entry controlled loop
The syntax is given below
Loop variable initialised
while(expression)
{
Body of the loop;
Update loop variable;
}
Here the loop variable must be initialised out side the while loop. Then the expression is evaluated if it is true then only the body of the loop will be executed and the loop variable must be updated inside the body. The body of the loop will be executed until the expression becomes false.
Eg.
i=1;
j=1;
while(i<=10)
{
cout<<i<<” * “<<j<<” = “<<i*j;
i++;
j++;
}

3. do While loop:
It is an exit controlled loop.
The syntax is given below
do
{
Statements
}while(expression);
Here the body executes atleast once even if the condition is false. After executing the body it checks the expression if it false it quits the body otherwise the process will be continue.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 19.
Write a program to find simple interest and compound interest.
Answer:
#include<iostream>
#include<cmath>
using namespace std;
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 83

Question 20.
Mr. X wants to get an output 9 when inputting 342 and he also wants to get 12 when inputting 651. Write the program and draw a suitable flowchart for X?
Answer:
Flow chart
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 84
#include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 85

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 21.
Differentiate break and continue statements with suitable examples.
Answer:
1. break statement:
It is used to skip over a part of the code i.e. we can premature exit from a loop such as while, do-while, for or switch.
Syntax:
while (expression)
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 86
The output is
1
2
3
4
5.

2. continue statement:
It bypasses one iteration of the loop.
Syntax :
while (expression)
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 87
The output is
1
2
3
4
5
6
7
8
9
10.

Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Question 22.
Write a C++ program to print to get the following output.
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 88
Answer:
#include
using namespace std;
int main()
Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming - 89

Plus One Maths Notes Chapter 9 Sequences and Series

Kerala State Board New Syllabus Plus One Maths Notes Chapter 9 Sequences and Series.

Kerala Plus One Maths Notes Chapter 9 Sequences and Series

I. Sequence and Series
A sequence can be regarded as a function whose domain is the set of natural numbers or some subset of it of the type {1, 2, 3, ….., k}.
Generally denoted by a1, a2, …….., an, ………
Let a1, a2, …….., an, …….. be a sequence. Then the expression a1 + a2 + ……. + an + …….. is called the series associated with the given sequence.

II. Arithmetic Progression (AP)
A sequence a1, a2, ……, an, …….. is called an arithmetic sequence or arithmetic progression if an+1 = a2 + d, n ∈ N, where a1 is called the first term and the constant term d is called the common difference of the AP.

Standard form of an AP:
a, a + d, a + 2d, …….. where a is the first term and d is a common difference.

If a constant is added to each term of an AP, the resulting sequence is also an AP.

If a constant is subtracted to each term of an AP, the resulting sequence is also an AP.

If each term of an AP is multiplied by a constant k, the resulting sequence is also an AP. But the resulting AP will have a common difference kd.

If each term of an AP is divided by a constant k, the resulting sequence is also an AP. But the resulting AP will have a common difference \(\frac{d}{k}\).

nth term, an = a + (n – 1)d

Sum of n terms, Sn = \(\frac{n}{2}\) [2a + (n – 1)d]

Sn = \(\frac{n}{2}\) [t1 + tn]

Arithmetic mean between a and b is \(\frac{a+b}{2}\)

III. Geometric Progression (GP):
A sequence a1 + a2 + ……… + an + …….. is called Geometric sequence or Geometric progression if \(\frac{a_{k+1}}{a_{k}}=r\), k ≥ 1, where a1 is called the first term and the constant term r is called the common ratio of the AP.

Standard form of a GP:
a, ar, ar2,…… where a is the first term and r is a common difference.

nth term, tn = arn-1

Sum of n terms,
Plus One Maths Notes Chapter 9 Sequences and Series 1

Geometric mean between a and b is √ab

Arithmetic mean ≥ Geometric mean.

Infinite G.P, and its Sum G. P. of the form a + ar + ar2 + ar3 + …… ∞ is called infinite G.P.
S = \(\frac{a}{1-r}\); |r| < 1

Infinite Series Calculator‘ is an online tool that helps to calculate the summation of infinite series for a given function.

IV. Special Series
Plus One Maths Notes Chapter 9 Sequences and Series 2

Plus One Maths Notes Chapter 8 Binomial Theorem

Kerala State Board New Syllabus Plus One Maths Notes Chapter 8 Binomial Theorem.

Kerala Plus One Maths Notes Chapter 8 Binomial Theorem

Binomial theorem gives the expansion of (a + b)n for a rational number ‘n’. In this Unit, we study the binomial theorem for positive integral indices only.

Expanding Binomial Calculator is a free online tool.

I. Binomial Theorem
The expansion of a binomial for any positive integral ‘n’ is given by the binomial theorem.
Plus One Maths Notes Chapter 8 Binomial Theorem 1
There are (n + 1) terms in the expansion of (a + b)n.

The sum of the indices of ‘a’ and ‘b’ in every term of the expansion is ‘n’.

The general term in the expansion is tr+1 = nCr an-r br

Middle term in the expansion:
1. If ‘n’ is even, \(\left(\frac{n}{2}+1\right)^{t h}\) term.

2. If ‘n’ is odd, \(\left(\frac{n+1}{2}\right)^{t h}\) and \(\left(\frac{n+1}{2}+1\right)^{b_{t}}\) term.

Plus One Economics Chapter Wise Questions and Answers Chapter 4 Presentation of Data

Students can Download Chapter 4 Presentation of Data Questions and Answers, Plus One Economics Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations

Kerala Plus One Economics Chapter Wise Questions and Answers Chapter 4 Presentation of Data

Plus One Economics Presentation of Data One Mark Questions and Answers

Plus One Economics Chapter Wise Questions And Answers Pdf Question 1.
Which of the following comes under geometric diagram?
(a) Histogram
(b) Bar diagram
(c) Ogives
(d) Frequency polygon
Answer:
(b) Bar diagram

Plus One Economics Chapter Wise Questions And Answers Question 2.
Which of the following comes under frequency diagrams?
(a) Bar diagram
(b) Histogram
(c) Pie diagram
(d) All the above
Answer:
(b) Histogram

Plus One Economics Chapter Wise Questions And Answers Malayalam Question 3.
To draw time-series graph, time is presented on:
(a) X-axis
(b) Y-axis
(c) any of two
Answer:
(a) X-axis

Plus One Statistics Chapter Wise Questions And Answers Question 4.
Name the types of graphs.
Answer:

  1. One dimensional graph
  2. Two-dimensional graph
  3. Three-dimensional graph
  4. Pictograms

Plus One Economics Chapter Wise Questions And Answers Pdf Download Question 5.
State whether true or false.

  1. The width of bars in a bar diagram need not be equal.
  2. The width of rectangles in a histogram should essentially be equal.
  3. Histograms can only be formed with continuous classification of data.
  4. Histogram and column diagram are the same method of presentation of data.
  5. Mode of a frequency distribution can be drawn graphically with the help of histogram,
  6. The median of a frequency distribution cannot be drawn from the Ogive.

Answer:

  1. true
  2. false
  3. true
  4. true
  5. true
  6. true

Plus One Economics Presentation of Data Two Mark Questions and Answers

Hsslive Economics Plus One Chapter Wise Questions And Answers Question 1.
Which of the following is a cumulative frequency curve?
Answer:
(a) Bar diagram
(b) Histogram
(c) Ogive
(d) Pie diagram
Answer:
(c) Ogive

Plus One Economics Questions And Answers Question 2.
Distinguish between captions and stubs.
Answer:
Captions refers to the column headings and stubs refers to the row heading.

Histogram And Frequency Polygon Questions With Answers Question 3.
Match the following.

AB
Source noteRow headings
CaptionsGives origin of data
StubsExplains the specific feature
FootnoteColumn Headings

Answer:

AB
Source noteGives origin of data
CaptionsColumn Headings
StubsRow Headings
FootnoteExplains the specific feature

Plus One Economics Presentation of Data Three Mark Questions and Answers

Presentation Of Data Class 11 Question 1.
What kind of diagrams are more effective in representing the following?

  1. Monthly rainfall in a year
  2. Composition of the population of Delhi by religion
  3. Components of cost in a factory

Answer:

  1. Simple bar diagram
  2. Sub-divided or component bar diagram
  3. Pie diagram

Pie Chart Class 11 Economics Question 2.
Name different types of diagrams.
Answer:
The different types of diagrams are:
1. Geometric diagram

  • Bar diagrams
  • Pie diagram

2. Frequency diagram

  • Histogram
  • Frequency polygon
  • Frequency curve -Ogive

3. Arithmetic line graph

Question 3.
“Diagrams and graphs help us visualize the whole meaning of numerical complex data at a single glance”. Comment.
Answer:
One of the most convincing and appealing ways in which statistical results may be presented is through diagrams and graphs. The special feature of graphs and diagrams is that they do away with figures altogether. Diagrams and graph is a statistical method which can be used for simplifying the complexity of quantitative data and t make them easily intelligible.

It presents dry and uninteresting statistical facts in the shape of attractive and appealing pictures and charts. They are important methods of visual aids and are appealing t the eye and mind of the observer.

Question 4.
“There are generally three forms of diagrammatic presentation of data” explain.
Answer:
There are various methods to present data. But generally, three forms of presentation of data are there
which are noted below:

  1. Geometric diagram
  2. Frequency diagram
  3. Arithmetic line graph

1. Geometric Diagram:
Bar diagram and pie diagram come in the category of geometric diagram for presentation of data. The bar diagrams are of three types-simple, multiple and component bar diagrams.

2. Frequency Diagram:
Data in the form of grouped frequency distributions are generally represented by frequency diagrams like histogram, frequency polygon, frequency curve, and ogive

3. Arithmetic Line Graph:
An arithmetic line graph is also called time-series graph and is a method of diagrammatic presentation of data. A line graph by joining these plotted points, thus, obtained is called arithmetic line graph or time-series graph.

Question 5.
Explain Ogive?
Answer:
Cumulative frequency of any class is equal to the sum of the frequencies of all the classes preceding that class and its own frequency e.g., frequencies are 10, 7, 12, 17 and 22. Cumulative frequencies are 10, 10 + 7 = 17, 17 + 12 = 29, 29 + 17 = 46 and 46 + 22 = 68.
Cumulative frequency of the last class = Total frequency.

For drawing an Ogive, cumulative frequency (i.e. number of values) is taken on the Y-axis and limits of class intervals on the X-axis.
Ogive is of two types:

  1. less than
  2. more than

In a “less than” type Ogive, we plot the upper limit of each class along the X-axis and in a “more than” type Ogive, we plot the lower limit of each class along the X-axis. Along the Y-axis, we plot the cumulative frequencies at the end of each class. Ogive can be drawn even if the class interval are unequal or open end. Ogives are performed over frequency curves for comparative study.

Question 6.
Illustrate how classes can be formed while presenting the data?
Answer:
Classes can be formed in two ways:

  1. Exclusive type
  2. Inclusive type

1. Exclusive Type:
When the class intervals are so fixed that the upper limit of one class is the lower limit of the new class, it is known as exclusive method of classification.

Marks (Percentage)No. of students
0-1015
10-2017
20-3022
30-4030
40-5039
50-6045

In this method, higher value of the variable in the class is not included in that class i.e.,

Marks (Percentage)No. of students
0 and more but less than 1015
10 and more but less than 2017
20 and more but less than 3022
30 and more but less than 4030
40 and more but less than 5039
50 and more but less than 6045

2. Inclusive Type:
In this method, the students getting say 39% marks will be included in class 30 – 39 itself i.e.,

Marks (Percentage)No. of students
0-95
10-198
20-297
30-3913
40-4925

Plus One Economics Presentation of Data Four Mark Questions and Answers

Question 1.
Choose the correct answer
a. Bar diagram is a

  1. one-dimensional diagram
  2. two-dimensional diagram
  3. diagram with no dimension
  4. none of the above

b. Data represented through a histogram can help in finding graphically the

  1. mean
  2. mode
  3. median
  4. all the above

c. Ogives can be helpful in locating graphically the

  1. mode
  2. mean
  3. median
  4. none of the above

d. Data represented through arithmetic line graph help in understanding

  1. long term trend
  2. cyclicity in data
  3. seasonality in data
  4. all the above

Answer:
a. 1. one-dimensional diagram
b. 3. mode
c. 3. median
d. 1. long term trend

Question 2.
Point out major parts of a statistical table.
Answer:

  1. Table number
  2. Title
  3. Headnote
  4. Stub
  5. Box head or caption
  6. Body or field
  7. Footnote
  8. Source note

Question 3.
Give the rules for constructing tables.
Answer:
The rules of constructing diagrams are:

  • Every diagram should be titled.
  • It should suit the size of the paper
  • It should be neat and attractive
  • It should be neatly indexed
  • It should contain footnotes
  • The details in diagram should be self-explanatory

Plus One Economics Presentation of Data Five Mark Questions and Answers

Question 1.
Explain the advantages of diagrammatic presentation.
Answer:
The advantages of diagrammatic presentation are given below.

  1. Diagram give a clear picture of data
  2. Comparison can be made easy
  3. Diagrams can be used university at any place
  4. It saves time and energy
  5. The data can be remembered easily

Question 2.
Show how pie diagram is drawn for the following data?

ItemsProduction in K.G.
Tea3260
Coffee1850
Cocoa900
Total6010

Answer:
Plus One Economics Chapter Wise Questions and Answers Chapter 4 Presentation of Data img1

Question 3.
Give steps in the preparation of pie diagram.
Answer:
A pie diagram is also a component diagram, but unlike a component bar diagram, a circle whose area is proportionally divided among the components it represents. It is also called a pie chart. The circle is divided into as many parts as there are components by drawing straight lines from the centre to the circumference.

The following steps in the preparation of pie diagram are given below:

  • Convert each component as percentage of the total.
  • Multiply the percentage by 360/100 = 3.6 to convert into degree.
  • Starting with the twelve o’clock position on the circle draw the largest component circle
  • Draw other components in clockwise succession in descending order of magnitude except for each all components

Like all others and miscellaneous which are shown last:

  • Use different columns or shades to distinguish between different components
  • Explain briefly the different components either within the components in the figure or outside by arrow.

Plus One Economics Presentation of Data Eight Mark Questions and Answers

Question 1.
Write short notes on the following

  1. pie diagrams
  2. frequency curves
  3. frequency polygon
  4. ogive
  5. arithmetic line graph

Answer:
1. Pie Diagram:
A pie diagram is also a component diagram, but unlike a component bar diagram, a circle whose area is proportionally divided among the components it represents. It is also called a pie chart. The circle is divided into as many parts as there are components by drawing straight lines from the centre to the circumference. Pie charts usually are not drawn with absolute values of a category.

The values of each category are first expressed as percentage of the total value of all the categories. A circle in a pie chart, irrespective of its value of radius, is thought of having 100 equal parts of 3.6° (3607100) each. To find out the angle, the component shall subtend at the centre of the circle, each percentage figure of every component is multiplied by 3.6°.

2. Frequency Polygon:
A frequency polygon is a plane bounded by straight lines, usually four or more lines. Frequency polygon is an alternative to histogram and is also derived from histogram itself. A frequency polygon can be fitted to a histogram for studying the shape of the curve. The simplest method of drawing a frequency polygon is to join the midpoints of the topside of the consecutive rectangles of the histogram.

3. Frequency Curve:
The frequency curve is obtained by drawing a smooth freehand curve passing through the points of the frequency polygon as closely as possible. It may not necessarily pass through all the points of the frequency polygon but it passes through them as closely as possible

4. Ogive:
Ogive is also called cumulative frequency curve. As there are two types of cumulative frequencies, for example, less than type and more than type, accordingly there are two ogives for any grouped frequency distribution data. Here in place of simple frequencies as in the case of frequency polygon, cumulative frequencies are plotted along y-axis against class limits of the frequency distribution.

For less than give the cumulative frequencies are plotted against the respective upper limits of the class intervals whereas for more than ogives the cumulative frequencies are plotted against the respective lower limits of the class interval. An interesting feature of the two ogives together is that their intersection point gives the median

5. Arithmetic Line Graph:
An arithmetic line graph is also called time-series graph and is a method of diagrammatic presentation of data. Init, time (hour, day/date, week, month, year, etc.) is plotted along x-axis and the value of the variable (time series data) along y-axis. A line graph by joining these plotted points, thus, obtained is called arithmetic line graph (time series graph). It helps in understanding the trend, periodicity, etc. in a long term time series data.

Question 2.
3 Forms of presentation of data

  1. Textual
  2. Tabular
  3. Diagrams & graphs Prepare a flow chart.

Answer:
Plus One Economics Chapter Wise Questions and Answers Chapter 4 Presentation of Data img2

Plus One Physics Notes Chapter 5 Law of Motion

Students can Download Chapter 5 Law of Motion Notes, Plus One Physics Notes helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus One Physics Notes Chapter 5 Law of Motion

Summary
Laws Of Motion Class 11 Notes Chapter 5 Introduction
In this chapter we are going to learn about the laws that governs the motion of bodies.
Inertia:
The inability of a body to change by itself it’s state of rest or uniform motion along a straight line is called inertia.
Examples of inertia:
1. When a fast moving bus is suddenly stopped, a standing passenger tends to fall in the forward direction.
Explanation
The passenger has the same velocity as that of the bus. When the bus stops suddenly the lower part of his body is brought to rest suddenly because of the friction between his feet and floor of the bus. But the upper part continues to move because of its inertia.

2. When a bus suddenly takes off, a standing passenger tends to fall in the backward direction. This is because the lower part of the body gets a speed when the bus picks up speed and upper part continues to be at rest because of its inertia.

3. Consider a person sitting inside a stationary train and tossing a coin. The coin falls into his own hand. If he repeats the experiment when the train is moving with uniform speed, then also the coin falls into his own hand.

4. Cleaning a carpet by beating is in accordance with law of inertia.

5. Rabbit chased by a dog runs in zigzag manner. This is to take advantage of the large inertia of the massive dog.

6. A person chased by an elephant runs in a zigzag manner or in a circle. This is to take the advantage of the large inertia of the massive elephant.

Newton’s Laws:
Newton built on Galileo’s ideas and laid the foundation of mechanics in terms of three laws.

  • Newtons first law
  • Newtons second law
  • Newtons third law

Laws Of Motion Class 11 Notes Pdf Chapter 5 Newton’s First Law Of Motion
Everybody continues in its state of rest or of uniform motion along a straight line unless it is compelled by an external unbalanced force to change that state:
Note: Newton’s first law of motion brings the idea of inertia. Inertia of a body is measured by the mass of the body. Heavier the body, greater is the force required to change its state and hence greater is its inertia.

Class 11th Physics Chapter 5 Notes  Newton’s Second Law Of Motion
Linear Momentum (\(\vec{p}\)):
Momentum of a body is defined as the product of its mass m and velocity \(\vec{v}\)
Plus One Physics Notes Chapter 5 Law of Motion 1
Explanation
Momentum of a body can be produced or destroyed by the application of force on it. Therefore, momentum of a body is measured by the force required to stop the body in unit time.
Force required to stop a moving body depends upon

  1. mass of the body
  2. velocity of the body.

1. Mass of the body:
When a ball and a big stone are allowed to fall from the same height, we find that a greater force is required to stop the big piece of stone than the ball. Thus larger the mass of a body, greater is its linear momentum.

2. Velocity of the body:
A bullet thrown with the hand can be stopped easily than the same bullet fired from the gun. Therefore, langerthe velocity of a body, greater is its linear momentum.
Note: Momentum is a vector quantity. Its unit is Kgms-1
Newton’s Second Law of motion:
The rate of change of momentum of a body is directly proportional to the applied force and takes place in the direction in which the force acts. Mathematically this can be written as
Plus One Physics Notes Chapter 5 Law of Motion 2

Laws Of Motion Class 11 Notes Pdf Download Chapter 5 Question 1.
Derive F = ma from Newton’s Second law.
Answer:
Consider a body of mass ‘m’ moving with a momentum \(\vec{p}\). Let \(\vec{F}\) be the force acting on it for time internal Dt. Due to this force the momentum is changed from \(\vec{p}\) to p + Dp. Then according to Newtons second law, we can write
Plus One Physics Notes Chapter 5 Law of Motion 3
Where K is a constant proportionality. When we take the limit ∆t → 0, we can write
Plus One Physics Notes Chapter 5 Law of Motion 4

Unit of force:
Unit of force is newton. 1N = 1Kgms-2
Force in terms of the components:
We know force is a vector, Hence we can write as
Plus One Physics Notes Chapter 5 Law of Motion 5
Plus One Physics Notes Chapter 5 Law of Motion 6
Impulsive force:
The forces which act on bodies for short time are called impulsive forces.
Example:

  • In hitting a ball with a bat
  • In firing a gun

Impulse:
An impulse force does not remain constant, but changes from zero to maximum. This impulsive force is not easy to measure, because it changes with time. In such a case, we measure the total effect of the force called impulse.

The impulse of a force is the product of the average force and the time for which it acts.
Plus One Physics Notes Chapter 5 Law of Motion 7
Relation between impulse and momentum:
We know from Newtons second law
F = \(\frac{\Delta p}{\Delta t}\)
Plus One Physics Notes Chapter 5 Law of Motion 8
R.H.S. is the impulse and L.H.S. is change of momentum ie; change of momentum = impulse.

Laws Of Motion Notes Class 11 Chapter 5 Question 2.
When we jump to hard soil there is greater discomfort than when we jump to loose soil. Why?
Answer:
F = \(\frac{\Delta p}{\Delta t}\). When we jump to hard soil, Dt is small and F is large. When we jump to loose soil it takes more time for the body to come to rest. Therefore, Dt is large and F will be small.

Plus One Physics Laws Of Motion Chapter 5 Question 3.
A cricketer draws his hand while catching a cricket ball. Why?
Answer:
When cricketer draws his hand, the Dt will increase. Hence F acting on the hand will decrease.

Newtons Third Law Of Motion
Statement:
To every action, there is always an equal and opposite reaction.
Explanation: When a book is placed on the table, the weight of the book acts on the table downwards. The table exerts an equal force on the book in the upward direction. If the force applied by the book on the table is action, the force applied by the table on the book is reaction.

Newton’s Laws Of Motion Class 11 Notes Chapter 5 Question 4.
If action and reaction are equal and opposite, why they do not cancel?
Answer:
Though action and reaction are equal and opposite, they do not cancel each other because action is on one body and reaction is on another body.
Consider a pair of bodies A and B. According to the
third law FAB = – FBA
(force on A by B) = – (force on B by A).

Plus One Physics Laws Of Motion Notes Chapter 5 Conservation Of Momentum
Second law and third law lead to conservation of linear momentum.
Statement:
When there is no external force on a body (or system), the total momentum remains constant.

Proof in the case of a single body:
According to Newtons second law, F = \(\frac{d p}{d t}\). if F = 0, we get p = constant. Which means that momentum of a body remains constant, if there is no external force acting on it.

Conservation of momentum in the case of firing a gun:
Consider a gun of mass M and bullet of mass ‘m’ at rest. On firing the gun exerts a force F on the bullet and bullet exerts an equal force -F in the opposite direction. Because of this action and reaction (due to firing), the gun acquires a momentum Pg and bullet acquires a momentum Pb.
Momentum before firing
The bullet and gun are at rest. Hence momentum before firing = M × 0 + m × 0
Momentum before firing = 0 ________(1)
Momentum after firing
According to Newtons second law, the change in
momentum of bullet. ∆Pb = Pb – 0 = F∆t ______(2)
Since initially both are rest,
Dp = final momentum – initial
momentum Similarly the change in momentum of gun
∆pg = pg – 0 = -F∆t _______(3)
∴ Total momentum after firing = pb + pg
= F∆t + – F∆t.
Total momentum after firing = 0 _______(4)
from eq (1) and eq (4), we get,
Total momentum before firing = Total momentum after firing.

Conservation of momentum in the case of two colliding bodies:
Plus One Physics Notes Chapter 5 Law of Motion 9
Consider two bodies A and B with initial momenta PA and PB. After collision, they acquire momenta P1A and P1g respectively.
According to Newton’s second law, the change in momentum of A due to the collision with B,
Plus One Physics Notes Chapter 5 Law of Motion 10
Similarly the change in momentum of B due to the collision with A, FBA∆t = P1B – PB
Plus One Physics Notes Chapter 5 Law of Motion 11
[Where Dt is time for which the two bodies are in contact].
According Newton’s third law, we can write
FAB = -FBA
Plus One Physics Notes Chapter 5 Law of Motion 12
Total momentum before collision = Total momentum after collision.
Note: Conservation linear momentum is always satisfied for elastic collision and inelastic collision.

Class 11 Physics Chapter 5 Notes Equilibrium Of A Particle
Equilibrium of a particle in mechanics refers to the situation, when the net external force on the particle is zero.

Common Forces In Mechanics
There are two types of forces commonly used in mechanics,

  1. Contact forces
  2. Non contact forces

1. Contact forces:
A contact force on an object arises due to contact with some other object. Example : Friction, viscosity, air resistance etc.

2. Non contact forces:
A non contact force on an object arises due to non contact with some other object
Example: Gravitational force

Friction:
Friction is the force that develops at the surfaces of contact of two bodies and impedes (opposes) their relative motion.
There are different types of friction.
Laws Of Motion Class 11 Notes Chapter 5

  • Static friction: The opposing force that comes into play when one body tends to move over the surface of another (but the actual motion has yet not started)
  • Limiting friction (fs): The maximum value of static friction is called limiting friction.
  • Kinetic friction (fk)(or) dynamic friction: Kinetic friction or dynamic friction is the opposing force that comes into play when one body is actually moving’overthe surface of another body.
  • Sliding friction: The opposing force that comes into play when one body is actually sliding over the surface of the other body is called sliding friction.
  • Rolling friction: The opposing force that comes into play when one body is actually rolling over the surface of the other body is called rolling friction.

Laws of static Friction:

  • The force of maximum static friction is directly proportional to the normal reaction
  • The force of static friction is opposite to the direction in which the body tends to move.
  • The force of static friction is parallel to the surfaces in contact.
  • The force of maximum static friction is independent of the area of contact (as long as the normal reaction remains constant).
  • The force of static friction depends only on the nature of surfaces in contact.

a. Laws of Kinetic friction:

  1. The force of Kinetic friction is proportional to normal reaction.
  2. The force of Kinetic friction is opposite to the dh rection in which the body moves.
  3. The force of Kinetic friction is parallel to the surfaces in contact.
  4. The force of Kinetic friction is independent of the area contact (as long as the normal reaction remains constant)
  5. The force of Kinetic friction depends on the nature of surface.
  6. Force of Kinetic friction is almost independent of the speed.
  7. Force of Kinetic friction is less than force of static friction.

b. Coefficient of static friction:
The force of static friction (fs)max is directly proportional to the normal reaction N
(fs)max α N
Plus One Physics Notes Chapter 5 Law of Motion 14
Where ms is called coefficient of static friction.
Definition of ms
Coefficient of static friction is the ratio of the force of the maximum static friction to the nprmal reaction.

c. Coefficient of Kinetic friction:
The force of kinetic friction is directly proportional to the normal reaction N.
i e (fk)max α N
Plus One Physics Notes Chapter 5 Law of Motion 15
Where µk is called coefficient of Kinetic friction.
Definition of µk
Coefficient of Kinetic friction is the ratio of the force of Kinetic friction to the normal reaction.

d. Angle of friction:
Angle of friction is the angle whose tangent gives the coefficient of friction.
Plus One Physics Notes Chapter 5 Law of Motion 16

Proof:
Consider a body placed on a surface. Let N be the normal reaction and flimit is the limiting friction. Let ‘θ’ be the angle between Resultant vector and normal reaction. From the triangle OBC,
Plus One Physics Notes Chapter 5 Law of Motion 17
∴ tanθ = µ
Angle of repose:
The angle of repose is the angle of the inclined plane at which a body placed of it just begins to slide.
Explanation
considers body placed on a inclined plane. Gradually increase the angle of inclination till the body placed on its surface just begins to slide down. If α is the inclination at which the body just begins to slide down, then α is called angle of repose.
Plus One Physics Notes Chapter 5 Law of Motion 18
The limiting friction F acts in upward direction along the inclined plane. When the body just begins to move, we can write
F = mg sin α ______(1)
from the figure normal reaction,
N = mg cos α ______(2)
dividing eq (1) by eq (2)
Plus One Physics Notes Chapter 5 Law of Motion 19
Note: Angle of repose is equal to angle of friction.
Rolling friction:
Why rolling friction is less than kinetic friction?
When a body rolls over a plane, there is just one point of contact between the body and plane. The relative motion between point and plane is zero. Hence in this ideal situation, kinetic friction becomes zero.
Advantages of friction

  • Friction helps us to walk on the ground.
  • Friction helps us to hold objects.
  • Friction helps in striking matches.
  • Friction helps in driving automobiles.
  • Friction is helpful in stopping a vehicle etc.

Disadvantages of friction

  • Friction produces wear and tear.
  • Friction leads to wastage of energy in the form of heat.
  • Friction reduces the efficiency of the engine etc.

Steps to reduce friction

  • Polishing the surfaces in contact
  • Use of lubricants
  • Ball bearing placed between moving parts of machine.

Circular Motion
When a body moves along circumstances of a circle, there is an acceleration towards it’s centre. This acceleration is called centripetal acceleration. The force providing this acceleration is called centripetal force.
Centripetal force f = \(\frac{\mathrm{mv}^{2}}{\mathrm{R}}\)

  1. For a stone rotated in a circle by a string, the centripetal force is provided by the tension in the string.
  2. The centripetal force for motion of a planet around the sun is the gravitational force on the planet due to sun.
  3. For a car on circular road, the centripetal force is provided by the friction between tire and road.

1. Motion of a car on a level road:
Plus One Physics Notes Chapter 5 Law of Motion 20
Consider a vehicle moving overa level curved road. The two forces acting on it are

  • Weight (mg) vertically down
  • The reaction (N)

The normal reaction can’t produce sufficient centripetal force required for circular motion. The centripetal force for circular motion is provided by friction. This friction opposes the motion of the car moving away from the circular road. Hence condition for circular motion can be written as Centripetal force ≤ force of friction
Plus One Physics Notes Chapter 5 Law of Motion 21
The maximum speed of circular motion of the car
vmax = \(\sqrt{\mu_{s} \mathrm{rg}}\)

Question 5.
Why surface of the road is kept inclined to the horizontal?
Answer:
Consider a vehicle moving along a level curved road. The vehicle will have a tendency to slip outward. This outward slip is prevented by frictional force. But friction causes unnecessary wear and tear. More over, for typical value of µ and R the maximum speed v = \(\sqrt{\mu_{s} \mathrm{rg}}\) rg will be very small.

These defects can be avoided if we raise the outer edge of the road slightly above the inner edge. This process is called banking of curve. The angle made by the surface of the road with the horizontal is called the angle of banking.

2. Motion of a car on a banked road:
Plus One Physics Notes Chapter 5 Law of Motion 22
Plus One Physics Notes Chapter 5 Law of Motion 23
Consider a vehicle along a curved road with angle of banking q. Then the normal reaction on the ground will be inclined at an angle q with the vertical.

The vertical component can be divided into N Cosq (vertical component) and N sinq (horizontal component). Suppose the vehicle has a tendency to slip outward. Then the frictional force will be developed along the plane of road as shown in the figure. The frictional force can be divided into two components. Fcosq (horizontal component) and F sinq (vertical component).
From the figure are get
N cos q = F sinq + mg
N cosq – F sinq = mg ______(1)
The component Nsinq and Fsinq provide centripetal force. Hence
Plus One Physics Notes Chapter 5 Law of Motion 24
Dividing both numerator and denominator of L.H.S by N cosq. We get
Plus One Physics Notes Chapter 5 Law of Motion 25
This is the maximum speed at which vehicle can move over a banked curved road.

Optimum speed:
Optimum speed is the speed at which a vehicle can move over a curved banked road without using unnecessary friction.
When a car is moved with optimum speed Vo, m can be taken as zero.
putting m = 0 in the above equation we get
Plus One Physics Notes Chapter 5 Law of Motion 26

Plus One Maths Chapter Wise Questions and Answers Chapter 5 Complex Numbers and Quadratic Equations

Students can Download Chapter 5 Complex Numbers and Quadratic Equations Questions and Answers, Plus One Maths Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus One Maths Chapter Wise Questions and Answers Chapter 5 Complex Numbers and Quadratic Equations

Plus One Maths Complex Numbers and Quadratic Equations Three Mark Questions and Answers

Plus One Maths Chapter Wise Questions And Answers Pdf Chapter 5 Question 1.
If z1 = 2 – i, z2 = 1 + i

  1. Find | z1 + z2 + 1| and |z1 – z2 + i| (2)
  2. Hence find \(\left|\frac{z_{1}+z_{2}+1}{z_{1}-z_{2}+i}\right|\) (1)

Answer:
1. |z1 + z2 + 1| = |2 – i + 1 + i + 1| = 4
|z1 – z2 + i| = |2 – i – 1 – i + i| = |1 – i|
\(=\sqrt{1+1}=\sqrt{2}\)

2.
Plus One Maths Chapter Wise Questions And Answers Pdf Chapter 5

Hsslive Maths Textbook Answers Plus One Chapter 5 Question 2.
Find the square root of -15 – 8i.
Answer:
Let x + iy = \(\sqrt{-15-8 i}\)
Then (x + iy)2 = -15 – 8i
⇒ x2 – y2 + 2xyi = – 15 – 8i
Equating real and imaginary parts, we have
x2 – y2 = -15 ______(1)
2xy = – 8
We know the identity
(x2 + y2)2 = (x2 – y2)2 + (2xy)2
= 225 + 64
= 289
Thus, x2 + y2 = 17 _______(2)
From (1) and (2), x2 = 1 and y2 = 16 or x = ±1 and y = ±4
Since the product xy is negative, we have
x = 1, y = -4 or, x = -1, y = 4
Thus, the square roots of -15 – 8i are 1 – 4i and -1 + 4i.

Plus One Maths Complex Numbers and Quadratic Equations Four Mark Questions and Answers

Plus One Maths Questions And Answers Chapter 5 Question 1.
Consider the complex number \(\frac{i-1}{\cos \frac{\pi}{3}+i \sin \frac{\pi}{3}}\)

  1. Express in a + ib form. (2)
  2. Convert into polar form. (2)

Answer:
1.
Hsslive Maths Textbook Answers Plus One Chapter 5

2.
Plus One Maths Questions And Answers Chapter 5
The complex number lies in the first quadrant;
⇒ θ = α = \(\frac{5 \pi}{12}\)
Plus One Maths Chapter Wise Questions And Answers Chapter 5

Plus One Maths Chapter Wise Questions And Answers Chapter 5 Question 2.

  1. Express the complex number \(\frac{2-i}{(1-i)(1+2 i)}\) in the form a + ib (2)
  2. Solve the equation 27x2 – 10x + 1 = 0 (2)

Answer:
1.
Complex Numbers Class 11 Extra Questions Chapter 5

2. 27x2 – 10x + 1 = 0
Complex Numbers And Quadratic Equations Chapter 5

Complex Numbers Class 11 Extra Questions Chapter 5  Question 3.

  1. For what value of x and y 4x + i(3x – y) = 3 – 6i (2)
  2. Solve the equation 21x2 – 28x + 10 = 0 (2)

Answer:
1. Given; 4x + i(3x – y) = 3 – 6i
⇒ 4x = 3; 3x – y = -6
Complex Numbers And Quadratic Equations Class 11 Pdf

2. 21x2 – 28x + 10 = 0
Complex Numbers And Quadratic Equations Class 11 Solutions

Complex Numbers And Quadratic Equations Chapter 5 Question 4.
Consider the complex number z = \(\frac{1+i}{1-i}\)
1. Write z in a + ib form.
2.
Complex Numbers And Quadratic Equations Class 11 Notes
In the figure radius of the circle is 1. Write the polar form of the complex number represent by the points P and Q. (2)
3. Find the square root of i. (2)
Answer:
1.
Plus One Maths Complex Numbers And Quadratic Equations

2. Polar form of the point P is \(1\left(\cos \frac{\pi}{2}+i \sin \frac{\pi}{2}\right)\)
Polar form of the point Q is \(1\left(\cos \frac{\pi}{4}+i \sin \frac{\pi}{4}\right)\)

3. i = 0 + i ⇒ \(\sqrt{i}\) = x + iy ⇒ i = x2 + y2 + 2xyi x2 + y2 = 0; 2xy = 1
(x2 + y2)2 = (x2 – y2)2 + 4x2y2
(x2 + y2)2 = 0 + (1)2 = 1
x2 + y2 = 1; x2 + y2 = 0
Complex Numbers Class 11 Questions Chapter 5

Plus One Maths Complex Numbers and Quadratic Equations Six Mark Questions and Answers

Complex Numbers And Quadratic Equations Class 11 Pdf Question 1.

  1. Express the complex number \(\frac{3-\sqrt{-16}}{1-\sqrt{-9}}\) in the form a + ib (2)
  2. Represent the complex number \(\frac{5+i \sqrt{3}}{-4+2 \sqrt{3 i}}\) in the polar form. (2)
  3. Solve the equation ix2 – x + 12i = 0 (2)

Answer:
1.
Plus One Maths Complex Numbers and Quadratic Equations Four Mark Questions and Answers 12

2.
Plus One Maths Complex Numbers and Quadratic Equations Four Mark Questions and Answers 13

The complex number lies in the third quadrant;
Plus One Maths Complex Numbers and Quadratic Equations Four Mark Questions and Answers 14

3. ix2 – x + 12i = 0
Plus One Maths Complex Numbers and Quadratic Equations Four Mark Questions and Answers 15

Plus One Maths Complex Numbers and Quadratic Equations Practice Problems Questions and Answers

Complex Numbers And Quadratic Equations Class 11 Solutions Question 1.
Express each of the following in a + ib form. (1 score each)

  1. (2 – 4i) + (5 + 3i)
  2. (1 – i) – (-1 + 6i)
  3. 3(7 + 7i) + i(7 + 7i)
  4. \(\left(\frac{1}{5}+i \frac{2}{5}\right)-\left(4+\frac{5}{2} i\right)\)

Answer:
1. (2 – 4i) + (5 + 3i) = (2 + 5) + (-4 + 3)i = 7 – i

2. (1 – i) – (-1 + 6i) = 1 – i + 1 – 6i = 2 – 7i

3. 3(7 + 7i) + i(7 + 7i) = 21 + 21i + 7i – 7 = 14 + 28i

4.
Plus One Maths Complex Numbers and Quadratic Equations Four Mark Questions and Answers 16

Question 2.
Express each of the following in a + ib form. (1 score each)

  1. (-5i)(\(\frac{1}{8}\)i)
  2. (-i)(2i)(-\(\frac{1}{8}\)i)3
  3. i99
  4. i111 + i222 + i333
  5. (7 – i)(2 + 7i)
  6. (-1 – i)(4 + 2i)
  7. (5 – 3i)2
  8. (\(\frac{1}{3}\) + 3i)3

Answer:
1.
Plus One Maths Complex Numbers and Quadratic Equations Four Mark Questions and Answers 17

2.
Plus One Maths Complex Numbers and Quadratic Equations Four Mark Questions and Answers 18

3. i99 = i96 + 3 = i96i3 = -i

4. i111 + i222 + i333 + i108 + i220 + 2 + i332 + 1
= i3 + i2 + i1 = -i – 1 + i = -1

5. (7 – i)(2 + 7i) = 7 × 2 – 2i + 7 × 7i – i × 7i
= 14 – 2i + 49i + 7 = 21 + 47i

6. (-1 – i)(4 + 2i) = -4 – 4i – 2i + 2 = – 2 – 6i

7. (5 – 3i)2 = 52 – 2 × 5 × 3i + (3i)2
= 25 – 30i – 9 = 16 – 30i

8.
Plus One Maths Complex Numbers and Quadratic Equations Four Mark Questions and Answers 19

Question 3.
Find the multiplicative inverse of the following; (1 score each)

  1. 3 – 4i
  2. 2 – 3i
  3. \(\sqrt{5}\) + 3i

Answer:
1. Multiplicative inverse = \(\frac{1}{3-4 i}\)
Plus One Maths Complex Numbers and Quadratic Equations Four Mark Questions and Answers 20

2. Multiplicative inverse = \(\frac{1}{2-3 i}\)
Plus One Maths Complex Numbers and Quadratic Equations Four Mark Questions and Answers 21

3. Multiplicative inverse = \(\frac{1}{\sqrt{5}+3 i}\)
Plus One Maths Complex Numbers and Quadratic Equations Four Mark Questions and Answers 22

Question 4.
Express each of the following in a + ib form. (2 score each)
Plus One Maths Complex Numbers and Quadratic Equations Four Mark Questions and Answers 23
Answer:
Plus One Maths Complex Numbers and Quadratic Equations Four Mark Questions and Answers 24
Plus One Maths Complex Numbers and Quadratic Equations Four Mark Questions and Answers 25
Plus One Maths Complex Numbers and Quadratic Equations Four Mark Questions and Answers 26
Plus One Maths Complex Numbers and Quadratic Equations Four Mark Questions and Answers 27

Plus One Maths Complex Numbers and Quadratic Equations Four Mark Questions and Answers 28

Question 5.
Convert the following into polar form. (2 score each)

  1. 1 + i
  2. -1 + i
  3. \(\sqrt{3}\) – i
  4. \(\frac{5-\sqrt{3} i}{4+2 \sqrt{3} i}\)

Answer:
1. Given; 1 + i = r(cosθ + isinθ)
r = \(\sqrt{1+1}=\sqrt{2}\)
tanα = \(\left|\frac{1}{1}\right|\) = 1 ⇒ α = \(\frac{\pi}{4}\)
The complex number lies in the first quadrant;
Plus One Maths Complex Numbers and Quadratic Equations Four Mark Questions and Answers 29

2. -1 + i = r(cosθ + isinθ)
r = \(\sqrt{1+1}=\sqrt{2}\)
tanα = \(\left|\frac{1}{-1}\right|\) = 1 ⇒ α = \(\frac{\pi}{4}\)
The complex number lies in the second quadrant;
Plus One Maths Complex Numbers and Quadratic Equations Four Mark Questions and Answers 30

3.
Plus One Maths Complex Numbers and Quadratic Equations Four Mark Questions and Answers 31
The complex number lies in the fourth quadrant;
Plus One Maths Complex Numbers and Quadratic Equations Four Mark Questions and Answers 32

4.
Plus One Maths Complex Numbers and Quadratic Equations Four Mark Questions and Answers 33
The complex number lies in the fourth quadrant;
Plus One Maths Complex Numbers and Quadratic Equations Four Mark Questions and Answers 34

Plus One Economics Notes Chapter 1 Indian Economy on the Eve of Independence

Students can Download Chapter 1 Indian Economy on the Eve of Independence Notes, Plus One Economics Notes helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus One Economics Notes Chapter 1 Indian Economy on the Eve of Independence

Low level of economic development under the colonial rule:
The British rule started in India in 1757 and came to an end in 1947. The Indian economy underwent rapid changes under British rule. The economic policies pursued by the colonial government in India were concerned more with the protection and promotion of the economic interests of their home country than the development of the Indian economy. The twin objectives of British rule in India were

  1. To use India as a supplier of raw materials for British Industries.
  2. To convert India into a market for the finished products produced in Britain.

Plus One Economics Notes Chapter 1 Agricultural Sector:
Agricultural Sector was the backbone of the Indian economy.
During the British colonial rule India remained fundamentally an agrarian economy. Around eighty percent of India’s population lived in villages. Agriculture was stagnant and it was the main source of livelihood of the population. People depended directly or indirectly on agriculture and its productivity was very slow. The agricultural sector stagnated during British rule.
Major reasons for agricultural stagnation were:

  1. The exploitative land settlement system followed by British rulers
  2. Use of low level of technology
  3. Rural indebtedness
  4. Low agricultural productivity
  5. Use of limited chemical fertilizer
  6. Inadequate irrigation facilities

Economics Plus One Notes Chapter 1 Industrial Sector:
India’s industrial sector could not make progress during British rule. Their aim was to collect raw materials from India and sell their final products in India.

By the second half of the nineteenth century, modem industry began to take root in India. Initially, cotton industries in Maharashtra and Gujarat (Bombay presidency) and the jute industry in Bengal were established. Then industries of fertilizers, rayon, rubber, cement, sugar, pepper, etc., were established in some regions of the country. The setting up of Tata Iron and Steel Company (TISCO) in 1907 was a landmark in the industrialization of India. Jemshedji Tata established TISCO in Jamshedpur in Bihar. During the British rule hardly any capital goods industries were established in the country.

Plus One Economics Chapter 1 Foreign Trade:
Though India exported value-added products before the British period, we started exporting primary products during their rule. Consequently, India became an exporter of primary products such as raw silk, cotton, wool, sugar, indigo, jute, etc. and an importer of finished consumer goods like cotton, silk and woollen clothes and capital goods like light machinery produced in the factories of Britain.
The most important characteristic of India’s foreign trade, throughout the colonial period was the generation of a large export surplus.

Plus One Economics Chapter 1 Notes Demographic Condition:
Various details about the population of British India were first collected through a census in 1881. Through Suffering from certain limitations, it revealed the unevenness in India’s population growth. Subsequently, every ten years such census operations were carried out. Before 1921, India was in the first stage of demographic transition. The second stage of transition began after 1921.

Economics Notes Plus One Chapter 1 Occupational Structure:
Occupational structure refers to the distribution of working persons across different industries and sectors. Broadly we divide occupations into three types. Agriculture, animal husbandry, forestry, fisheries, etc., are collectively known as ‘primary’ activities. Manufacturing industries, both small and large scale, are known as ‘secondary’ activities. Transport, communication, banking, financial services, etc., are ‘tertiary’ activities.

Hsslive Economics Plus One Chapter 1 Infrastructure:
Infrastructural facilities developed in India during the British period. Infrastructure means some kind of permanent installation, which are used over a long period of time for the supply of basic inputs like railway lines, roads, dams, canal systems, power stations, pipelines, hospitals, educational institutions like schools, colleges, etc. Basic infrastructure facilities such as railways, ports, water transport, and telegraph did develop during the British rule. The real intention behind such a development was to serve the various colonial interests of Britain.

Plus One Accountancy Notes Chapter 3 Recording of Transactions – I & II

Students can Download Chapter 3 Recording of Transactions – I & II Notes, Plus One Accountancy Notes helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus One Accountancy Notes Chapter 3 Recording of Transactions – I & II

Summary:
Plus One Accountancy Chapter 3 Meaning of source documents:
Various business documents such as invoice, bills, cash memos, vouchers, which form the basis and evidence of a business transaction recorded in the books of account are called source documents.

Hsslive Plus One Accountancy Notes Meaning of accounting equation:
A statement of equality between debits and credits signifying that the assets of a business are always equal to the total liabilities and capital.

Plus One Accountancy Notes Rules of debit and credit:
An account is divided into two sides. The left side of an account is known as debit and the credit. The rules of debit and credit depend on the nature of an account. Debit and Credit both represent either increase or decrease, depending on the nature of an account.

These rules are summarised as follows:
Plus One Accountancy Chapter 3

Accountancy Class 11 Chapter 3 Notes Books of original entry:
The transactions are first recorded in these books in a chronological order. Journal is one of the books of original entry. The process of recording entries in the journal is called journalising.

Format of Journal
Hsslive Plus One Accountancy Notes

Chapter 3 Accounts Class 11 Notes Ledger:
A book containing all accounts to which entries are transferred from the books of original entry. Posting is process of transferring entries from books of original entry to the ledger.

Accountancy Class 11 Chapter 3 Solutions Journalising Format of a Ledger
Plus One Accountancy Notes

Plus One Accountancy Chapter 3 Notes Special Journals:
Special journals are also called day books or subsidiary books. Transactions that cannot be recorded in any special journal are recorded in journal is called the “Journal Proper.”

The special-purpose journals are:

  • Cash Book
  • Petty Cash Book
  • Purchase Book
  • Purchase Return Book
  • Sales Book
  • Sales Return Book
  • Journal Proper

(a) Cash Book
A book used to record all cash receipts and payments. Cash book may be single column cash book, doulbe column cash book and three column cash book.

Single Column Cash book
This is cash book containing only one column for cash and prepared as cash account in ledger.

Format of Single Column Cash Book
Accountancy Class 11 Chapter 3 Notes

Double Column Cash book:
This is cash book containing one more column for bank along with the cash column, it serves the purpose of cash and bank account.

Format of Double Column Cash Book
Chapter 3 Accounts Class 11 Notes

(b) Petty Cash Book:
A book used to record small cash payments

(c) Purchase Book / Purchase Journal:
A special journal in which only credit purchases are recorded.

Accounts Class 11 Chapter 3 Notes Format of Purchase Day Book
Accountancy Class 11 Chapter 3 Solutions Journalising

(d) Purchase Return Book:
A book in which return of purchased goods on credit is recorded.

Accounts Chapter 3 Class 11 Notes Format of Purchase Return Book
Plus One Accountancy Chapter 3 Notes

(e) Sales Book / Sales Journal:
A special journal in which only credit sales are recorded.

Format of Sales Day Book
Plus One Accountancy Notes Chapter 3 Recording of Transactions - I & II img 8

(f) Sales Return Book:
A special book in which return of goods sold on credit is recorded.

Format of Sale Return Book
Plus One Accountancy Notes Chapter 3 Recording of Transactions - I & II img 9

Balancing the Accounts:
Accounts in the ledger are periodically balanced, generally at the end of the accounting period with the object of ascertaining the net position of each amount.

Balancing of an account means that the two sides are totaled and the difference between them is shown on the side which is shorter in order to make their totals equal. The words ‘balance carried down (c/d)’ are written against the amount of the difference between the two sides.

The amount of balance is brought down (b/d) in the next accounting period indicating that it is a continuing account until finally settled or closed. In case the debit side exceeds the credit side.

The difference is written on the side, if the credit side exceeds the debit side, the difference between the two appears on the debit side and is called debit and credit balance respectively. The accounts of expenses losses, gains and revenues are not balanced but are closed by transferring to trading and profit and loss account.

Plus One Botany Chapter Wise Questions and Answers Chapter 1 Biological Classification

Students can Download Chapter 1 Biological Classification Questions and Answers, Plus One Botany Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations

Kerala Plus One Botany Chapter Wise Questions and Answers Chapter 1 Biological Classification

Plus One Botany Biological Classification One Mark Questions and Answers

Plus One Botany Chapter Wise Questions And Answers Pdf Question 1.
In Whit takers, five-kingdom classification eukaryotes are distributed among
(a) two kingdoms
(b) three kingdoms
(c) four kingdoms
(d) all the five kingdoms
Answer:
(c) four kingdoms

Plus One Botany Chapter Wise Questions And Answers Question 2.
Cyanobacteria are classified under which of the following kingdoms?
(a) Monera
(b) Protista
(c) Plantae
(d) Algae
Answer:
(a) Monera

Plus One Botany Questions And Answers Question 3.
Main component of cell wall of fungi is
(a) cellulose
(b) chitin
(c) pectin
(d) silica
Answer:
(b) chitin

Plus One Botany Chapter Wise Previous Questions And Answers Question 4.
Dinoflagellates are mostly
(a) marine and saprophytic
(b) freshwater and saprophytic
(c) marine and photosynthetic
(d) terrestrial and
Answer:
(c) marine and photosynthetic

Plus One Biology Chapter Wise Questions And Answers Pdf Question 5.
Which of the following kingdoms do viruses belong to
(a) monera
(b) Protista
(c) fungi
(d) none of these
Answer:
(d) none of these

Hsslive Plus One Botany Chapter Wise Questions And Answers Question 6.
Observe the relationship between the first pair and fill up the blanks.

  1. Thermoacidophiles: Archaebacteria in hot spring
  2. Ripening of fruits: …………….

Answer:
Ethylene.

Plus One Botany Chapter Wise Previous Year Questions And Answers Question 7.
Fill in the blanks.

  1. Rhizopus: Phycomycetes
    Yeast: ………..
  2. Holdfast: Anchorage
    Heterocyst: ……….

Answer:

  1. Ascomycetes
  2. N2 fixation

Plus One Botany Chapter Wise Questions And Answers Hsslive Question 8.
Who proposed Five kingdom classification?
Answer:
R .H. Whittaker

Plus One Botany Previous Questions Chapter Wise Pdf Question 9.
Find out the correct sequence of taxonomical category.

  1. Order → Kingdom → species → phylum
  2. species → genus → order → phylum

Answer:
2. species → genus → order → phylum

Biological Classification Important Questions Question 10.
In the five-kingdom system of Whittaker, how many kingdoms are eukaryotes?
Answer:
Four kingdoms

Plus One Botany Previous Question Papers Chapter Wise Question 11.
Observe the relationship between the first pair and fill up the blanks.

  1. Nostoc : Eubacteria:: methanogens: ………….
  2. Yeast: ………………..:: Rhizopus: Phycomycetes :

Answer:

  1. Archaebacteria
  2. Ascomycetes

Biology Classification Questions And Answers Question 12.
Find out the odd one.
a. Diatom, Gonyaulax, Yeast, Euglena, Plasmodium
Answer:
Yeast

Hsslive Botany Previous Questions And Answers Question 13.
Vinod observed blooms in a polluted water body, his friend Kumar said that it might be nitrogen-fixing Nostoc or Anabaena. Can you suggest which type of cell can fix atmospheric nitrogen in these organisms?
Answer:
Heterocyst

Botany Chapter Wise Questions And Answers Question 14.
Observe the relationship of the terms in the first pair and fill in the blanks:

  1. Vibrio: Comma shaped
    ……….: Rod-shaped
  2. Agaricus: Basidiomycetes
    Penicillium: ………….

Answer:

  1. Bacillus
  2. Ascomycetes

Biological Classification Previous Year Questions Question 15.
Difference between Virus and Viroid.
(a) Absence of protein coat in viroid but present in virus
(b) Presence of low molecular weight RNA in virus but absent in viroid
(c) Both a and b
(d) None of the above
Answer:
(a) Absence of protein coat in viroid but present in virus

Question 16.
Viruses are non-cellular organisms but replicate themselves once they infect the host cell. To which of the following kingdom do viruses belong to?
(a) Monera
(b) Protista
(c) Fungi
(d) None of the above
Answer:
(d) None of the above

Question 17.
A virus is considered as a living organism and an obligate parasite when inside a host cell. But virus is not classified along with bacteria or fungi. What are the characters of virus that are similar to nonliving objects?
Answer:
Viruses are acellular and can be crystallized.

Plus One Botany Biological Classification Two Mark Questions and Answers

Question 1.
The seven taxonomic categories are given below. Arrange them in the correct sequence starting from the smallest taxon.
Class → species → kingdom → order → family → division → genus.
Answer:
Species → genus → family → order → class → division → kingdom.

Question 2.
“Two kingdom classification is inadequate one”. Comment on it.
Answer:

  1. It does not include organisms showing both plant and animal character.
  2. It does not take into the consideration of nature of nucleus.

Question 3.
Five-kingdom classification of organism was given by R.H.Whittaker. State the criteria followed by Whittaker for his classification.
Answer:

  1. Nature of cell
  2. Nature of nucleus
  3. Mode of nutrition

Question 4.
Name the following;

  1. A protist which can live both as an autotroph and as a heterotroph.
  2. Name a protist group which consists of saprophytes.

Answer:

  1. Euglena
  2. Slime mould

Question 5.
State two economic importance of

  1. Heterotrophic bacteria
  2. Archaebacteria

Answer:

  1. Major decomposers that help in the curdling of milk, production of antibiotic, fixing nitrogen and cause diseases like tetanus, typhoid, cholera etc.
  2. Archaebacteria: production of biogas.

Question 6.
What is the nature of cell walls of diatoms?
Answer:
Cell walls are made up of silica with two overlapping shells fit together like a soapbox.

Question 7.
Find out what do the terms algal blooms and red tides signify?
Answer:

  • Algal bloom: Excessive growth of blue-green algae causes pollution of water bodies with characteristic odour.
  • Red tide: Dinoflagellates like gonyaulax are red in colour which imparts red colour to seawater.

Question 8.
Find out what do the terms ‘algal bloom’ and ‘red tides’ signify.
Answer:
1. Algal bloom’: When colour of water changes due to profuse growth of coloured phytoplanktons, it is called algal bloom.

2. ‘Red tides: Redness of the red sea is due to the luxuriant growth of Trichodesmium erythrium, a member of cyanobacteria (blue-green algae)’

Question 9.
How are viroids different from virus?
Answer:
Viroids are free RNA without protein coat. Viruses have protein coat which encloses either RNA or DNA.

Question 10.
Justify the physiological relationship between the algal and fungal component of lichen.
Answer:
The fungus holds water, provides protection and ideal housing to the alga. The alga supplies carbohydrate food for the fungus. If the alga is capable of fixing nitrogen, it supplies fixed nitrogen to fungus. This association is called symbiosis.

Question 11.
Bacteria reproduce by various methods. Mention the type of reproduction given in the diagram. What are the other methods of reproduction occur in bacteria?
Plus One Botany Chapter Wise Questions And Answers Pdf
Answer:
Binary fission
The other methods are sporulation and sexual reproduction.

Question 12.
Biological classification is essential. Comment.
Answer:
The animals and plants vary greatly in their form, structure and mode of life. To find out an organism of known characters from the vast number of organism is simply impossible. So classification is important to divide into groups and subgroups.

Question 13.
Match the following:

a. Produces a plant diseasep. Saccharomyces cere visae
b. is edible- light blight of potato.q. Phytophthora infestans
c. is a source of antibioticr. Agaricus campestris
d. is used in the manufacture of ethanols. Penicillium notatum

Answer:

  • a – Phytophthora infestans – light blight of potato.
  • b- Agaricus campestris
  • c – Penicillium notatum
  • d – Saccharomyces cere visae

Question 14.
Plants are autotrophs. Can you think of some plants that are heterotrophs?
Answer:
Generally all plants are autotrophs but plants like loranthus and cuscuta absorbs water & nutrients from other plants so they are called as heterotrophs.

Question 15.
What are the characteristic features of Euglenoides?
Answer:
They have protein sheath is called pellicle instead of cell wall. They have two flagella – One long and other short. They are photosynthetic in the presence of light and behave as heterotrophs in the absence of sunlight.

Question 16.
Give 4 difference between Ascomycetes and Basidiomycetes:
Answer:

AscomycetesBasidiomycetes
1. Mycelium consists of branched multicellular septate hyphae.1. Mycelium may be primary, secondary (or) tertiary
2. The fruiting bodies are ascocarps2. Fruiting bodies are basidiocarps.
3. Sexual reproduction leads to the formation of ascus3. Formation of basidia formation of ascus.

Question 17.
Observe the cyanobacteria given below and answer the following.

  1. Name the cyanobacteria, and the kingdom it belongs.
  2. Label’s ‘P’ and mention its functions.

Plus One Botany Chapter Wise Questions And Answers
Answer:

  1. Nostoc-kingdom-Monera
  2. Heterocyst – To fix nitrogen from the atmosphere.

Question 18.
What do the terms phycobiont and mycobiont signify?
Answer:
Algal component of lichen is called phycobiont. It prepares food for fungus. Fungal partner is called mycobiont. It provides shelter and absorbs mineral nutrients for algae.

Question 19.
Prepare a comparative account of different classes of kingdom fungi by considering following statements.
Answer:

  1. Mode of nutrition
  2. Mode of reproduction

Question 20.
The two-kingdom classification is introduced by Linnaeus. Why is the two kingdom classification inadequate?
Answer:
There was no place of viruses and bacteriophages which can neither be considered as prokaryotes not eukaryotes.

In this classification, eukaryotes were put together with prokaryotes and non-photosynthetic fungi along with photosynthetic plants.

Question 21.
How is the five-kingdom classification advantageous over the two kingdom classification?
Answer:
In this classification main criteria used by R H Whittaker include cell structure, thallus organisation, mode of nutrition, reproduction and phylogenetic relationships. These characters were not considered in two kingdom classification.

Question 22.
Are chemosynthetic bacteria-autotrophic or heterotrophic?
Answer:
Autotrophic, because they get energy from the oxidation of inorganic compounds. So the released energy is stored in the ATP molecules.

Question 23.
Cyanobacteria and some other photosynthetic bacteria don’t have chloroplasts. How do they conduct photosynthesis?
Answer:
Cyanobacteria and other photosynthetic bacteria have thylakoids suspended freely in the cytoplasm (i.e., they are not enclosed in membrane), and they have bacteriochlorophyll

Question 24.
With respect to fungal sexual cycle, choose the correct sequence of events.
Answer:

  1. Karyogamy, Plasmogamy and Meiosis
  2. Meiosis, Plasmogamy and Karyogamy
  3. Plasmogamy, Karyogamy and Meiosis
  4. Meiosis, Karyogamy and Plasmogamy

Question 25.
What is the principle underlying the use of cyanobacteria in agricultural fields for crop improvement?
Answer:
It is due to the presence of special nitrogen-fixing cell called heterocyst present between the filaments. So it helps to increase N2 content in the soil.

Question 26.
Methane is the main component of biogas and it is produced by bacteria.

  1. Name the bacteria.
  2. Identify the group in which it belongs.

Answer:

  1. Methanogens
  2. Archaebacteria

Question 27.
Based on the relationship, fill in the blanks.

  1. Sac fungi: Ascomycetes
    Imperfect fungi: …………
  2. Thermoacidophiles: Archaebacteria in hot springs
    …………………: Archaebacteria in Salty areas

Answer:

  1. Deuteromycetes
  2. Halophiles

Question 28.
Name the kingdom in which euglena belongs. Give the special type nutrition.
Answer:
Kingdom Protista, Mixotrophic nutrition (ie, both autotrophic and heterotrophic).

Question. 29
Some bacteria are different from others and they have the ability to survive in extreme conditions. Name it.
Answer:
Archaebacteria (halophiles, thermoacidophiles and methanogens).

Question 30.
Mycoplasma are included in five kingdom classification but not viruses. Why?
Answer:
Because mycoplasmas are living cellular organisms but viruses are acellular particles.

Question 31.
In which division of protista chief producers in ocean belongs. Give the cell wall composition of such organisms.
Answer:
Chrysophytes, silicified cell wall.

Question 32.
Nitrobactor and nitrosomonas are free living nitrogen fixers and chemoautotrophs but their functions are different. Do you agree. Give reasons.
Answer:
Yes. Nitrobactor converts nitrite into nitrate while nitrosomonas converts ammonia into nitrites.

Question 33.
Name the classes fungi shows exogenous and endogenous spore production. In which fruiting bodies they are found.
Answer:

  • Exogenous-Basidiomycetes. Its fruiting body is basidiocarp.
  • Endogenous-Ascomycetes. Its fruiting body is ascocarp.

Question 34.
Rust and smut diseases are caused by the members of basidiomycetes. Name it.
Answer:
Smut disease- Ustilago, Rust disease-Puccinia.

Question 35.
What are the events takes place in slime mould during favourable and unfavourable season?
Answer:
During favourable condition the cells aggregate and form plasmodium while in unfavourable season plasmodium differentiates and produce fruiting bodies that bear spores at tip.

Question. 36
Suppose you accidentally find an old preserved permanent slide without a label. In your effort to identify it, you place the slide under microscope and observe the following features

  1. Unicellular
  2. Well defined nucleus
  3. Biflagellate-one flagellum lying longitudinally and the other transversely.

What would you identify it as? Can you name the kingdom it belongs to?
Answer:
Dinoflagellates, Kingdom protista

Question. 37
What would you identify it as? Can you name the kingdom it belongs to?
Answer:
Dinoflagellates, Kingdom protista

Question. 38
Why lichens are called as dual organisms?
Answer:
Lichens are said to be dual organisms because they show a symbiotic association between a fungus and alga.

Question 39.
Name the asexual, reproductive structure of penicillium and yeast.
Can penicilium reproduce through sexual method? If the yes or no Give reason.
Answer:
Conidia – penicilium, buds – yeast
Yes, It is done by the production of ascospores in asci of Ascocarp.

Question 40.
Organise a discussion in your class on the topic virus. Are viruses living or non-living?
Answer:
They are filterable and may becrystalised. They are inert outside their specific host and able to reproduce inside the living host cell, so they are considered as living. They use the protein synthesising machinery of the host.
Eg. AIDS virus, mumps virus etc.

Question 41.
How are viroids different from viruses?
Answer:

VirusViroid
1. Their size is smaller than bacteria1. Their size is smaller than viruses
2. Protein coat is Present2. Protein coat is absent
3. Genetic material may be DNA or RNA3. Genetic material is only RNA
4. They cause AIDS, smallpox etc.4. They cause potato spindle tuber diseases

Question 42.
Some bacteria are specialised and live in extreme habitat.

  1. Name the types of bacteria are specified in the above statement.
  2. Which is the part of bacteria modified to live in that condition?

Answer:
1. Types of bacteria

  • Methanogens
  • Halophiles
  • Thermo acidophiles

2. Ceil wall structure

Question 43.
The two nuclei per cell can be seen in fungal cell but it later fuse in some members.

  1. Name such type of fungal hyphae or mycelium.
  2. Identify the classes of fungi.

Answer:

  1. Dikaryotic mycelium
  2. Ascomycetes, Basidiomycetes

Question 44.
Classify the pathogenic microorganisms and disease in different groups based on the following symptoms mosaic disease, citrus canker .potato spindle tuber disease, sleeping sickness, malaria.
Answer:
mosaic disease-virus, citrus canker-Bacteria, potato spindle tuber disease -viroids, sleeping sickness- Trypanosoma, malaria-Plasmodium vivax.

Plus One Botany Biological Classification Three Mark Questions and Answers

Question 1.
Describe briefly the four major groups of protozoa.
Answer:
Protozoans are heterotrophs act either as predators
or parasites. They are of four groups

  1. Amoeboid protozoans: They capture their prey by using pseudopodia. They live in freshwater. Some are parasites eg: entamoeba.
  2. Flagellated protozoans: They are free-living or parasites. They cause diseases, eg: Trypanosoma-sleeping sickness.
  3. ciliated protozoans: They possess cilia in their body surface for locomotion. They have gullet for food intake. Eg: Paramecium
  4. Sporozoans: They are spore-producing organism that causes diseases eg: plasmodium causing malaria.

Question 2.
Different types of fungi are given
1. Classify them into their specific classes.

GroupsFungi
PhycomycetesTrichoderma
AscomycetesNeurospora
BasidiomycetesAlbugo
DeuteromycetesMucor
Agaricus
Ustilago
Alternaria
Claviceps

2. Write the distinguishing characters of ascomycetes and basidiomycetes
3. The characteristic features of members of monera are given below.

Organisms lack cell wall, live without oxygen, smallest living cell and causes diseases. Identify the organism by analysing the above characters.
Answer:
1. specific classes.

  • Phycomycetes – Mucor, Albugo
  • Ascomycetes – Neurospora, Claviceps
  • Basidiomycetes-Agaricus, Ustilago
  • Deuteromycetes – Altemaria, Trichoderma.

2. In ascomycetes, Asexual mode of reproduction is prominent by conidiospores. In Basidiomycetes asexual spores are not found. Sexual spores are arranged in ascus with Ascospores in ascomycetes, whereas sexual spores are arranged in basidium in basidiomycetes.

3. Mycoplasma

Question 3.
Give a brief account of virus with respect to their structure and nature of genetic material. Also, name four common viral diseases?
Answer:
Viruses are organism having inert crystalline structure outside the living cell. They have genetic material RNA or DNA.which is either single-stranded/double-stranded. It is enclosed by protein capsid with subunits called capsomeres.

The viral genetic material takes control over the host cell mechanism during infection. Some common viral diseases are mumps, herpes, smallpox and influenza in animals and mosaic disease in plants.

Question. 4
In which groups are the following found- Sporangiophore, Conidia, zygospore and ascospore.
Answer:

  • Conidia are spores found in ascomycetes.
  • These are haploid asexual spores produced in chains exogenously.
  • Zygospores are the diploid resting spores found in mucor.
  • Ascospores are haploid sexual spores found in sac-like structure (ascus).
  • Sporangiophore is an aerial branch produced by hyphae in mucor that bear sporangia.

Plus One Botany Biological Classification NCERT Questions and Answers

Question 1.
What is the nature of cell walls in diatoms?
Answer:
The cell walls in diatoms are embedded with silica, which makes them indestructible. They form two thin overlapping shells which fit together as in a soapbox. Thus diatoms have left behind large amounts of cell wall deposits in their habitat.

Question 2.
How are viroids different from viruses?
Answer:
Viroids are free RNAs without the protein coat, while virus have a protein coat encapsulating the RNA.

Question 3.
Describe briefly the four major groups of Protozoa.
Answer:
Four major groups of Protozoa are as given below:
1. Amoeboid Protozoa:
They are found in freshwater, seawater or moist soil. They have pseudopodia, like amoeba, hence the name ameoboid protozoa.

2. Flagellated Protozoans:
They have flagella helps in locomotion. Some are parasite. Eg. Trypanosoma causes sleeping sickness.

3. Ciliated Protozoa:
They have thousands of cilia present all over the body. The cilia helps in locomotion and steering of food into the gullet.

4. Sporozoans:
Many protozoans have an infectious spore-like stage in the life cycle. The spore-like stage helps them get transferred from one host to another host.

Question. 4
Plants are autotrophic. Can you think of some plants that are partially heterotrophic?
Answer:
Certain insectivorous plants, like bladderwort and venus fly trap, are partially heterotrophic.

Question. 5
What do the terms phycobiont and mycobiont signify?
Answer:
Lichens are good examples of symbiotic life of algae and fungi. Phycobiont is the name of the part composed of algae and Mycobiont is the name of the part composed of fungi. Fungi provide minerals and support to the alage, while algae provide nutrition to the fungi.

Question 6.
What are the characteristic features of Euglenoids?
Answer:
Features of Euglenoids.

  • No cell wall.
  • Protein-rich layer, called pellicle, which makes flexible body.
  • Two flagella of different lengths.
  • Autotrophs in sunlight, heterotrophs in the absence of sunlight. Example: Euglena.

Question 7.
Give a brief account of viruses with respect to their structure and nature of genetic material. Also name four common viral diseases.
Answer:
Virus Structure:
Outside a host cell, virus is a crystalline structure, composed of protein. Inside the crystal, there is genetic material, which can be either RNA or DNA. No virus has both RNA and DNA. Viruses, infecting plants, have single-stranded RNA. Viruses, infecting animals, have either single or double-stranded RNA or double-stranded DNA.

The protein coat is called capsid. Capsid is made of smaller subunits, called capsomeres, it protects nucleic acid. Diseases caused by Virus; AIDS, Mumps, Influenza, Herpes.

Question 8.
Find out what do the terms ‘algal bloom’ and ‘red tides’ signify.
Answer:
Dinoflagellates can be of different colours depending on the type of pigment present. The red dinoflagellate sometimes multiplies at a very rapid rate. This is called as algal bloom. This gives a red appearance to the part of affected sea. This is also known as ‘red tide’. Toxins released by them can kill other marine species.

Plus One Botany Biological Classification Multiple Choice Questions and Answers

Question 1.
The life form used as indicators of pollution
(A) Lichens
(B) Protozoa
(C) Algae
(D) Agaricus
Answer:
(A) Lichens

Question 2.
Kingdom monera comprises
(A) Amoeba, Bacteria,Trypanosoma
(B) Bacteria, Viruses,Virolds
(C) Archaebacteria, Eubacteria, Mycoplasma
(D) Mycoplasma, Viruses, Bacteria
Answer:
(C) Archaebacteria, Eubacteria, Mycoplasma

Question 3.
Who discovered two-kingdom classification
(A) Ivanowsky
(B) Stanley
(C) leuwernhoek
(D) Linnaeus
Answer:

Question 4.
Asexual reproduction takes place by Zoospores in
(A) Pythium
(B) Agaricus
(C) Rhizopus
(D) Ustilago
Answer:
(D) Ustilago

Question 5.
Identify the organism used as bioweapon
(A) Bacillus thuringiensis
(B) Bacillus anthracis
(C) Pseudomonas citri
(D) Rhizobium tumefacient
Answer:
(B) Bacillus anthracis

Question 6.
Reserve food in the form of glycogen and cell wall made up of chitin are characteristic of
(A) Protists
(B) bacteria
(C) Fungi
(D) protozoa
Answer:
(C) Fungi

Question 7.
The fruiting body of club fungi is
(A) Basidium
(B) Ascus
(C) Ascocarp
(D) Basidiocarp
Answer:
(D) Basidiocarp

Question 8.
RNA without protein coat are found in
(A) bacteria
(B) protozoa
(C) viruses
(D) viroides
Answer:
(D) viroides

Question 9.
The phycobiont and mycobiont are found in
(A) bacteria
(B) lichen
(C) viroides
(D) fungi
Answer:
(B) lichen

Question 10.
The organism which causing sleeping sickness belongs to
(A) Protists
(B) bacteria
(C) Fungi
(D) viruses
Answer:
(A) Protists

Question 11.
In which of the following groups are neurospora and Penicillium included?
(A) Phycomycetes
(B) Basidiomycetes
(C) Zygomycetes
(D) Ascomycetes
Answer:
(D) Ascomycetes

Question 12.
Occurrence of Dikaryon phase is characteristic feature of
(A) Bacteria
(B) Fungus
(C) Slime moulds
(D) Cyanobacteria
Answer:
(B) Fungus

Question13.
Methane producers are belongs to
(A) Archaebacteria
(B) Cyanobacteria
(C) Eubactenia
(D) Actinomycetes
Answer:
(A) Archaebacteria

Question 14.
Heterocyst are found in
(A) Nitrosomonas
(B) cyanobacteria
(C) fungi
(D) protozoa
Answer:
(B) cyanobacteria

Question 15.
Colletotrichum falcatum is a fungus causing the following disease
(A) Smut of wheat
(B) Wilt disease of cotton
(C) Red rot of sugar cane
(D) Late blight of potato
Answer:
(C) Red rot of sugar cane