Plus One Economics Notes Chapter 14 Presentation of Data

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Kerala Plus One Economics Notes Chapter 14 Presentation of Data

Presentation of Data
The most common form of presenting the data are textual or descriptive presentation, tabular presentation and diagrammatic presentation.

Textual Presentation of Data: This is the method of presenting data in text form. This method of presentation is possible only when the quantity of data is not too large. Following are the two examples of presenting the data in a textual format appeared in news papers.

Tabular Presentation of Data: Tabular presentation is the systematic arrangement of data in rows and columns. In other words, tabulation is a layout of figures in rectangular form with appropriate heading to explain different rows and columns.

Diagrammatic and Graphical Representation of Data: It is the more attractive and eye-catching method of presenting data. This provides the quickest understanding of the actual situation to be explained by data in comparison to tabular or textual presentations. The diagrams are broadly divided into three namely geometric diagrams, frequency diagram and arithmetic line graph. Again, geometric diagrams are classified into bar diagram and pie diagram.

Parts of a Table
A good table should have the following parts.
i) Table Number: Table number is essential for identifying the table; especially when more than one table is presented. It is the table numberthat distinguishes one table from the other. For easy reference, they are numbered according to their order of appearance in the text. It may be placed at the top or at the bottom)

ii) Title: Every table should contain a title, because it narrates about the contents of the table. Just like the table number, the title can also be placed at the top or bottom of the table. The title should be clear, brief, carefully worded, unambiguous and complete. It should be capable of giving the clear idea about the table.

iii) Captions: It is also called the column heading, which gives a designation to the column. It is given as the top row. Under each column head, there may be subheads. In table-14.4 above, there are three captions: rank, name of country and production of wheat.

iv) Stubs: It is also called the row heading, which gives a designation to the row. It is given as the left column and that column is called the stub column.

v) Body of the Table: It is the most important part of the table. It contains the actual data. The body is arranged generally from left to right in rows and from top to bottom in columns.

vi) Unit of Measurement: The units of measurement of the figures in the data should always be given in the table. It can be given with the title if the same unit is used in the whole table. If different units are used for different columns, they should be given with the respective column headings; and if different units are used for different rows, they should be given with the respective row headings.

vii) Source: It is a brief statement indicating the source from where the data is taken. If more than one source, all of them should be written there. This will help the reader to check the figures and gather more information if required. It also helps in indicating the authenticity of data. Generally, source is written in the bottom of the table.

Various Kinds of Diagrams
There are various kinds of diagrams in common use. Amongst them the important ones are the following:
1. Geometric diagram
2. Frequency diagram
3. Arithmetic line graph

Geometric Diagram: Bardiagram and pie diagram come in the category of geometric diagram for the presentation of data. The bar diagrams are of three types- simple, multiple and component bar diagrams.

i) Bar Diagram
Simple Bar Diagram: Bardiagram comprises a group of Equi-spaced and equi-width rectangular bars for each class or category of data. The height or length of the bar reads the magnitude of data.

Multiple Bar Diagram: Multiple bar diagrams are used for comparing two or more sets of data, for example, import and export for different years, marks obtained in different subjects in different classes, etc.

Component Bar Diagram: Component bar diagrams or charts also called sub-diagrams are very useful in comparing the sizes of different component parts and also for throwing light on the relationship among these integral parts.

ii) Pie Diagram
A pie diagram is also a component diagram, but unlike a component bar diagram, a circle whose area is proportionally divided among the components it represents. It is also called a pie chart. The circle is divided into as many parts as there are components by drawing straight lines from the centre to the circumference. Pie charts usually are not drawn with absolute values of a category. The values of each category are first
expressed as a percentage of the total value of all the categories.

It may be interesting to note that data represented by a component^bar diagram can also be represented equally well by a pie chart, the only requirement being that absolute values of the components have to be converted into percentages before they can be used for a pie diagram.

Graphical Presentation
Data in the form of grouped frequency distributions are generally represented by frequency diagrams like histogram, frequency polygon, frequency curve and ogive.

a) Histogram: A histogram is a two-dimensional diagram. It is a set of rectangles with bases as the intervals between class boundaries (along X- axis) and with areas proportional to the class frequency. If the class intervals are of equal width, which they generally are, the area of the rectangles are proportional to their respective frequencies. However, in some type of data, it is convenient, at times necessary, to use varying width of class intervals. The width in a histogram is as important as its height. We can have a bar diagram both for discrete and continuous variables, but histogram is drawn only for a continuous variable. Histogram also gives value of mode of the frequency distribution graphically.

b) Frequency Polygon: A frequency polygon is a plane bounded by straight lines, usually four or more lines. Frequency polygon is an alternative to histogram and is also derived from histogram itself. A frequency polygon can be fitted to a histogram for studying the shape of the curve. The simplest method of drawing a frequency polygon is to join the midpoints of the topside of the consecutive rectangles of the histogram.

c) Frequency Curve: The frequency curve is obtained by drawing a smooth freehand curve passing through the points of the frequency polygon as closely as possible. It may not necessarily pass through all the points of the frequency polygon but it passes through them as closely as possible.

d) Ogive: Ogive is also called cumulative frequency curve. As there are two types of cumulative frequencies, for example less than type and more than type, accordingly there are two ogives for any grouped frequency distribution data. Here in place of simple frequencies as in the case of frequency polygon, cumulative frequencies are plotted along y-axis against class limits of the frequency distribution. For less than give the cumulative frequencies are plotted against the respective upper limits of the class intervals whereas for more than ogives the cumulative frequencies are plotted against the respective lower limits of the class interval. An interesting feature of the two ogives together is that their intersection point gives the median.

Plus One Economics Notes Chapter 13 Organisation of Data

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Kerala Plus One Economics Notes Chapter 13 Organisation of Data

Classification of Data
The groups or classes of classification can be done in various ways. The way you want to classify them would depend on your requirement. Likewise, the raw data could be classified in various ways depending on the purpose at hand.

1. Chronological Classification: They can be grouped according to time. Such a classification is known as a Chronological Classification. In such a classification, data are classified either in ascending or in descending order with reference to time such as years, quarters, months, weeks, etc. The variable ‘population’ is a Time Series as it depicts a series of values for different years.

2. Spatial Classification: In Spatial Classification the data are classified with reference to geographical locations such as countries, states, cities, districts, etc.

3. Qualitative Classification: Sometimes you come across characteristics that cannot be expressed quantitatively. Such characteristics are called Qualities or Attributes. For example, nationality, literacy, religion, gender, marital status etc. They cannot be measured. Yet these attributes can be classified on the basis of either the presence or the absence of a qualitative characteristic. Such a classification of data on attributes is called a qualitative classification.

4. Quantitative Classification: Characteristics like height, weight, age, income, marks of students, etc. are quantitative in nature. When the collected data of such characteristics are grouped into classes, the classification is a Quantitative Classification.

Continuous and discrete variable
A variable is that characteristic whose value is capable of changing from unit to unit. Variables can be continuous or discrete. A continuous variable is that which can take any value in a specified interval. Whereas discrete variables are those which can assume only certain values.

Exclusive and Inclusive Methods
Exclusive Method: Under the method, the upper-class limit is excluded but the lower class limit of a class is included in the interval. Thus an observation that is exactly equal to the upper-class limit, according to the method, would not be included in that class but would be included in the next class. On the other hand, if it were equal to the lower class limit then it would be included in that class.

Inclusive Method: There is another method of forming classes and it is known as the Inclusive Method of classification. In comparison to the exclusive method, the Inclusive Method does not exclude the upper-class limit in a class interval. It includes the upper class in a class. Thus both class limits are parts of the class interval.

Frequency Array
For a discrete variable, the classification of its data is known as a Frequency Array. Since a discrete variable takes values and not intermediate fractional values between two integral values, we have frequencies that correspond to each of its integral values.

Frequency Distribution
A frequency distribution is a comprehensive way to classify raw data of a quantitative variable. It shows how the different values of a variable are distributed in different classes along with their corresponding class frequencies.

Each class in a frequency distribution table is bounded by Class Limits. Class limits are the two ends of a class. The lowest value is called the Lower Class Limit and the highest value the Upper-Class Limit.

Class Interval or Class Width is the difference between the upper-class limit and the lower class limit. For class 60-70, the class interval is 10 (upper-class limit minus lower class limit).

The Class Midpoint or Class Mark is the middle value of a class. It lies halfway between the lower class limit and the upper-class limit of a class and can be ascertained in the following manner:

Class Midpoint or Class Mark = (Upper-Class Limit + Lower Class Limit)/2

The classmark or mid-value of each class is used to represent the class. Once raw data are grouped into classes, individual observations are not used in further calculations. Instead, the classmark is used. Frequency Curve is a Graphic representation of a frequency distribution.

Plus One Economics Notes Chapter 12 Collection of Data

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Kerala Plus One Economics Notes Chapter 12 Collection of Data

Sources of Data
Statistical data can be obtained from two sources. The enumerator may collect the data by conducting an inquiry or an investigation. Such data are called Primary Data, as they are based on first-hand information.
If the data have been collected and processed by some other agency, they are called Secondary Data. Generally, the published data are secondary data.

Methods of Collecting Primary Data
There are three basic ways of collecting data:

  1. Personal Interviews
  2. Mailing (questionnaire) Surveys
  3. Telephone Interviews

1. Personal Interviews: This method is used when the researcher has access to all the members. The researcher conducts face to face interviews with the respondents. Personal contact is made between the respondent and the interviewer. The interviewer has the opportunity of explaining the study and answering any query of the respondents.

2. Mailing Questionnaire: When the data in a survey are collected by mail, the questionnaire is sent to each individual by mail with a request to complete and return it by a given date. The advantages of this method are that it is less expensive. It allows the researcher to have access to people in remote areas too, who might be difficult to reach in person or by telephone. It does not allow the influence of the respondents by the interviewer. It also permits the respondents to take sufficient time to give thoughtful answers to the questions.

3. Telephone Interviews: In a telephone interview, the investigator asks questions overthe telephone. The advantages of telephone interviews are that they are cheaper than personal interviews and can be conducted in a shorter time. They allow the researcher to assist the respondent by clarifying the questions. The telephone interview is better in the cases where the respondents are reluctant to answer certain questions in personal interviews.

Collection of Secondary Data
Secondary data are those which are available in published or unpublished records. Once a decision is taken to collect secondary data, the question of sources of data arises. There are two sources for the collection of secondary data, namely, published sources and unpublished sources.
Published Sources:

  • Official publications of the central, state, and local governments.
  • Official publications of international agencies like the United Nations Organization and its subsidiaries.
  • Reports and publications of trade associations, chambers of commerce, banks, etc.
  • Reports of committees and commissions.
  • Reports published in technical trade journals.
  • Reports submitted by researchers, economists, etc.

Unpublished Sources:

  • Unpublished materials found with research institutes, trade associations, chamber of commerce, etc.

Census Survey and Sample Survey
Under census method, we collect information from each and every unit of population relating to the problem under investigation. On the other hand, the under-sample method, rather than collecting information about all the units of population, we collect information from a few selected items from the population.

Methods of Sampling
There are various methods of selecting samples from a population. These are called sampling techniques.
The two types of sampling techniques are random sampling and non-random sampling.

Random Sampling Methods
Random sampling is a technique of drawing a sample from the population in which each and every unit of the population has an equal chance of being included in the sample. It is further divided into simple random sampling and restricted random sampling.

a) Simple random sampling: In this method, the sample is taken from the population without making any division or classification of the population. Hence, every unit of the population has an equal chance of being selected in the sample. Simple random sampling may be done either by using lottery method or by Table of random numbers.

b) Restricted random sampling: Restricted random sampling is of mainly three types. Stratified sampling, systematic sampling and cluster sampling.

1. Stratified sampling: When the population is heterogeneous, stratified sampling method is used. Under this method the whole population is divided into various groups or strata of units, such that the units in each class possess similar characteristics. For example, suppose you are studying about the consumption pattern of students in your school. The population comprises the whole students studying in various standards of your school. A student studying in standard-5 and a student studying in standard-9 may have different consumption patterns. That is, for this characteristic, the population is heterogeneous. Hence, different standards can be selected as different groups or strata. Then sample is drawn from each stratum at random.

2. Systematic sampling: A systematic sampling is formed by selecting one at random and then selecting the rest at evenly spaced intervals until the sample size has been reached. Suppose that in the nature club of your school, there are 100 members and you want to make a core group of 10. First you number the 100 students of the club from 1 to 100. By lottery method or by random table method you select one student from the first ten. Let it be the 7th student. Then take an appropriate interval and select the rest 9 students. If the interval you had taken is 10, then the second student in the sample is the 17th student, the third student in the sample is the 27th student, etc.

3. Cluster sampling: This type of sampling is carried out in several stages. Suppose we are studying about the employment of households in Kerala. In the first stage, Kerala is divided into three or four zones. Then each zone is divided into districts. Then each district is divided into villages. From each district, sample of villages may be taken at random. From each selected village, households of required size are also taken at random. Since several stages involve in cluster sampling, it is also known as multi-stage sampling.

Non-Random Sampling
In this method of sampling the investigator himself makes the choice of sample from the population according to his own discretion which he thinks to be the best. Here, all the units in the population do not have equal chance of being selected in to the sample.

Sampling Errors and Non-Sampling Errors:
Sampling Errors
The purpose of the sample is to take an estimate of the population. Sam^g error refers to the differences between the sample estimate and the actual value of a characteristic of the population. It is the error that occurs when you make an observation from the sample taken from the population. Thus, the difference between the actual value of a parameter of the population and its estimate is the sampling error.

Non-Sampling Errors
Non-sampling errors are more serious than sampling errors because a sampling error can be minimized. But errors due to mistakes while framing tables and data entry will affect the final result. They are non-sampling errors.

Plus One Economics Notes Chapter 11 Introduction

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Kerala Plus One Economics Notes Chapter 11 Introduction

Statistics
Statistics deals with the collection, classification analysis, and interpretation of numerical data. In our daily language, the word ‘Statistics’ is used in two distinct senses: singular and plural. In the plural sense, ‘statistics’ means ‘numerical facts systematically collected’ as described by the Oxford Dictionary. Thus, the simple meaning of statistics in the plural sense is data.

Functions of Statistics

  • It simplifies the complexity of data: Complex numerical data are simplified through statistical methods.
  • It reduces the bulk data: Huge data can be reduced to a few figures and thus, easily understandable.
  • It adds precision in thinking: It actually sharpens one’s thinking faculty.
  • It helps comparison of different sets of figures: e.g. import and export of two countries can be compared.
  • It indicates trends and tendencies: Helps in making future plans.
  • It helps in studying relationships between different factors: With the help of statistical methods, one can study the relation between two or more variables.
  • It guides in the formulation of policies and helps in planning: Planning and policies of the government are based on statistical data.

Limitations of Statistics
The limitations of statistics are given below.

  • Statistical laws are true only on average.
  • Statistics can be misused.
  • Statistics deals only with quantitative data.
  • Statistical results lack mathematical accuracy.
  • Statistical facts are collected for a pre-determined purpose.

Plus One Economics Notes Chapter 10 Comparative Development Experience of India with its Neighbours

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Kerala Plus One Economics Notes Chapter 10 Comparative Development Experience of India with its Neighbours

Development Path – A Snapshot View
India, Pakistan, and China have many similarities in their developmental strategies. India, China, and Pakistan became independent and started initiating their developmental strategies at almost the same time. India and Pakistan became independent in 1947 and China in 1949. All three countries adopted the planning strategy for economic growth and development. India’s five-year plan started in 1951, Pakistan’s in 1956 (called medium-term plan), and China’s in 1953. Government and the public sector played a major role in these economies. However, with the introduction of economic reforms in tune with globalisation the role of market was redefined. Till the 1980s, all the three economies had almost similar growth rate and other economic indicators.

China
After the establishment of the People’s Republic of China under one-party rule, all the critical sectors of the economy, enterprises, and lands owned and operated by individuals were brought under government control. The Great Leap Forward (GLF) campaign initiated in 1958 aimed at industrializing the country on a massive scale. People were encouraged to set up industries in their backyards. In rural areas, communes were started. Under the Commune system, people collectively cultivated lands.

In 1958, there were 26,000 communes covering almost all the farm population. GLF campaign met with many problems. A severe drought caused havoc in China killing about 30 million people. When Russia had conflicts with China, it withdrew its professionals who had earlier been sent to China to help in the industrialization process.

In 1965, Mao introduced the Great Proletarian Cultural Revolution (1966-76) under which students and professionals were sent to work and learn from the countryside. The present-day fast industrial growth in China can be traced back to the reforms introduced in 1978.

Pakistan
Pakistan followed the mixed economy model with, co-existence of the public sector and private sector. Pakistan also followed a protectionist policy in international trade. The introduction of the Green Revolution resulted in a rise in the production of food grains. In the 1970s, the nationalization of the capital goods industry took place. In the late 1970s and 1980stherewasashift in the economic policy in favor of de-nationalization and encouragement to the private sector.

Pakistan got substantial financial support from western nations. There was an increase in the number of emigrants and their remittance to their home country. The remittance and Western nation’s support helped the country in stimulating economic growth. In 1988 more reforms were introduced. FDI was encouraged, direct taxes were reduced and many areas of the economy were opened to private and foreign investment.

Demographic Indicators
Demographic indicators of India, China, and Pakistan can be summarised as follows:
Plus One Economics Notes Chapter 10 Comparative Development Experience of India with its Neighbours 1

The table shows the population growth as being highest in Pakistan, followed by India and China. Scholars point out the one-child norm introduced in China in the late 1970s as the major reason for low population growth. They also state that this measure led to a decline in the sex ratio, the proportion of females per 1000 males. However, from the table, you will notice that the sex ratio is low and biased against females in all three countries. Scholars cite son preference prevailing in all these countries as the reason. In recent times, all three countries are adopting various measures to improve the situation.

The One-child norm and the resultant arrest in the growth of the population also have other implications. For instance, after a few decades, in China, there will be more elderly people in proportion to young people. This will force China to take steps to provide social security measures with fewer workers. The fertility rate is also low in China and very high in Pakistan. Urbanization is high in both Pakistan and China with India having 28 percent of its people living in urban areas.

Indicators of Human Development
The HDI (Human Development Index) developed by UNDP (United Nations Development Programme) is an index which has universal acceptance as a good measure of the quality of human life. Since 1990 the UNDP has been publishing information related to HDI. This report ranks countries on the basis of their HDI. The following table presents some of the selected indicators of development.
Plus One Economics Notes Chapter 10 Comparative Development Experience of India with its Neighbours 2
Source: Human Development Report, 2014

Plus One Economics Notes Chapter 9 Environment Sustainable Development

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Kerala Plus One Economics Notes Chapter 9 Environment Sustainable Development

Environment
The environment is defined as the total planetary inheritance and the totality of all resources. It includes all the biotic and abiotic factors that influence each other. While all living elements – the birds, animals and plants, forests, fisheries, etc. are biotic elements and abiotic elements include air, water, land, etc. Rocks and sunlight are all examples of abiotic elements of the environment. A study of the environment then calls for a study of the interrelationship between these biotic and abiotic components of the environment.

Functions of the Environment
The environment performs four vital functions

  • It supplies resources: resources here include both renewable and non-renewable resources.
    Renewable resources are those which can be used without the possibility of the resource becoming depleted or exhausted. That is, a continuous supply of the resource remains available.
  • It assimilates waste
  • It sustains life by providing genetic and bio-diversity
  • It also provides aesthetic services like scenery, etc.

Global Warming and Ozone Depletion
Two important issues faced by our environment is global warming and ozone depletion.

Global warming: Global warming is a gradual increase in the average temperature of the earth’s lower atmosphere as a result of the increase in greenhouse gases since the Industrial Revolution. Much of the recent observed and projected global warming is human-induced. It is caused by man-made increases in carbon dioxide and other greenhouse gases through the burning of fossil fuels and deforestation.

Ozone Depletion: Ozone depletion refers to the phenomenon of reductions in the amount of ozone in the stratosphere The problem of ozone depletion is caused by high levels of chlorine and bromine compounds in the stratosphere The origins of these compounds are chlorofluorocarbons (CFC), used as cooling substances in airconditioners and refrigerators, or as aerosol propellants, and bromo fluorocarbons (halons), used in fire extinguishers. As a result of depletion of the ozone layer, more ultraviolet (UV) radiation comes to Earth and causes damage to living organisms. UV radiation seems responsible for skin cancer in humans; it also lowers production of phytoplankton and thus affects other aquatic organisms. It can also influence the growth of terrestrial plants.

State of India’s Environment
India has abundant natural resources in terms of rich quality of soil, hundreds of rivers and tributaries, lush green forests, plenty of mineral deposits beneath the land surface, vast stretch of the Indian Ocean, ranges of mountains, etc. The black soil of the Deccan Plateau is particularly suitable for the cultivation of cotton, leading to a concentration of textile industries in this region. The Indo-Gangetic plains – spread from the Arabian Sea to the Bay of Bengal – are one of the most fertile, intensively cultivated and densely populated regions in the world.

India’s forests, though unevenly distributed, provide green cover for a majority of its population and natural cover for its wildlife. Large deposits of iron ore, coal and natural gas are found in the country. India alone accounts for nearly 20% of the world’s total iron-ore reserves. Bauxite, copper, chromate, diamonds, gold, lead, lignite, manganese, zinc, uranium, etc. are also available in different parts of the country. However, the developmental activities in India have resulted in pressure on its finite natural resources, besides creating impacts on human health and well-being.

The threat to India’s environment poses a dichotomy -threat of poverty-induced environmental degradation and, at the same time, threat of pollution from affluence and a rapidly growing industrial sector. Air pollution, water contamination, soil erosion, deforestation and wildlife extinction are some of the most pressing environmental concerns of India.
The priority issues identified are :

  • land degradation
  • biodiversity loss
  • air pollution with special reference to vehicular pollution in urban cities
  • management of fresh water and
  • Solid waste management. Land in India suffers from varying degrees and types of degradation stemming mainly from unstable use and inappropriate management practices.

Sustainable Development
The concept of sustainable development was emphasized by the United Nations Conference on Environment and Development (UNCED), which defined it as: ‘Development that meets the need of the present generation without compromising the ability of the future generation to meet their own needs’.

Strategies for sustainable development
Strategies for sustainable development include the following.

  • Use of Non-conventional Sources of Energy: LPG, Gobar Gas in Rural Areas:
  • CNG in Urban Areas
  • Wind Power
  • Solar Power through Photovoltaic Cells
  • Mini-hydel Plants
  • Traditional Knowledge and Practices
  • Bio-composting
  • Bio-pest Control

Plus One Economics Notes Chapter 8 Infrastructure

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Kerala Plus One Economics Notes Chapter 8 Infrastructure

Infrastructure
Infrastructure means some kinds of permanent installation, which are used over a long period of time for the supply of basic inputs like railway lines, schools, colleges, universities, hospitals, etc. Infrastructural facilities are often referred to as economic and social overheads.

  1. The economic infrastructure consists of energy, transport, communication
  2. The social infrastructure consists of education, health, and housing.

Relevance of Infrastructure
Infrastructure plays important role in economic growth and development. Developed nations have good record of social and economic infrastructure. The contributions of infrastructure are:
• It invites investment which leads to growth.
• It enhances productivity.
• It improves the quality of life of people.

State of Infrastructure in India
Two important infrastructures in India are energy and health. We shall examine their details below:

Energy: Energy is very vital for rapid economic growth. There is a big gap between consumer demand and the supply of electricity in India. Energy is a critical aspect of the development process of a nation. It is, of course, essential for industries. Now it is used on a large scale in agriculture and related areas like the production and transportation of fertilizers, pesticides, and farm equipment. It is required in houses for cooking, household lighting, and heating.

Sources of Energy: There are commercial and non-commercial sources of energy. Commercial sources are coal, petroleum, and electricity as they are bought and sold. Non-commercial sources of energy are firewood, agricultural waste, and dried dung. These are non-commercial as they are found in nature/ forests. While commercial sources of energy are generally exhaustible, non-commercial sources are generally renewable.

Non-conventional Sources of Energy: Both commercial and non-commercial sources of energy are known as conventional sources of energy. There are three other sources of energy which are commonly termed as non-conventional sources – solar energy, wind energy and tidal power.

Power/Electricity: The most visible form of energy, which is often identified with progress in modern civilization, is power, commonly called electricity; it is one of the most critical components of infrastructure that determines the economic development of a country.

Health: Health is an essential element of human resource development. Health is a holistic process related to the overall growth and development of the nation. WHO defines health as Economists judge the health conditions of the people of a country by looking at the following indicators.

  • Infant mortality
  • Maternal mortality
  • Life expectancy
  • Nutritional levels
  • Incidence of communicable and non-communicable diseases
  • Health infrastructures

Health System in India: India’s health infrastructure consists of a three-tier system such as primary, secondary, and tertiary. Primary health care includes health education, health problems, prevention and control of diseases, promotion of nutrition, issues relating to potable water and sanitation, maternal and child health care, immunization against major infectious diseases like Polio, T.B, diphtheria, promotion of mental health and provision of essential drugs, etc.

Primary health care is provided through, sub-centers catering to a population of about 5000, Primary health care centres (PHCs) at block level and community health centres (CHCs) at the district level. The primary health care centres have only limited facilities. When the patient need advanced health care they are referred to secondary or tertiary hospitals.

Secondary care institutions are those which have facilities for clinical investigations like X-ray, clinical laboratory, scanning, etc., specialist doctors like a surgeon, gynecologists, pediatricians, etc. It is mostly available in district headquarters and big towns and cities.

Tertiary health care institutions these are health care institutions at the top of the three-tier system, devoted in health care, health education and research: Medical colleges, super-specialty hospitals and multi-specialty hospitals. All India Institute of Medical Sciences (AIIMS) Delhi, National Institute of Mental Health and Neuro Sciences (NIMHANS) Bangalore, Sree Chithra Institute of Medical Science (SCIM) Trivandrum, etc., are tertiary health care institutions.

Indian Systems of Medicine (ISM): Natural systems of medicine have to be explored and used to support public health. There is a great scope of advancement of medical tourism in India. It includes six systems: Ayurveda, Yoga, Unani, Siddha, Naturopathy and Homeopathy (AYUSH). At present, there are 3,004 ISM hospitals, 23,028 dispensaries and as many as 6,11,431 registered practitioners in India. But little has been done to set up a framework to standardize education orto promote research. ISM has huge potential and can solve a large part of our health care problems because they are effective, safe and inexpensive.

Plus One Economics Notes Chapter 7 Employment-Growth, Informalisation and Related Issues

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Kerala Plus One Economics Notes Chapter 7 Employment-Growth, Informalisation and Related Issues

Workers and Employment
Those activities that contribute to Gross National Product (GNP) or national income are known as economic activities. When farmers work in a field or a labour work in a factory, or doctor works in a hospital they produce goods or services. All those who are engaged in economic activities including self-employed are called workers. The employment situation is diverse and complex in India. It is due to the developing nature of the economy and the socio-economic and demographic factors that influence it.

Participation of People in Employment
The worker-population ratio is an important indicator of the employment situation in an economy.
Worker population-ratio refers to the ratio of workers to the population. It is computed by dividing the number of workers(W) by the total population (P) and express it in terms of percentage (W/P)*100. This ratio is useful in knowing the proportion of the population actively contributing to the production of goods and services in a country. The worker-population ratio in India for 2011 was 39.3%.

Employment in Firms, Factories, and Offices
In the course of the economic development of a country, labour flows from agriculture and other related activities to industry and services. Generally, we divide all economic activities into eight different industrial divisions. They are:

  1. Agriculture
  2. Mining and quarrying
  3. Manufacturing
  4. Electricity, gas and water supply
  5. Construction
  6. Trade
  7. Transport and storage
  8. Services.

For simplicity, all the working persons engaged in these divisions can be clubbed into three major sectors, viz.

  • Primary sector includes (1) and (2)
  • Secondary sector which includes (3), (4), and (5)
  • Service sector which includes divisions (6), (7), and (8).

Unemployment and Types of Unemployment
The unemployment situation in India is highly complex. There are different types of unemployment in our country like open unemployment, disguised unemployment, seasonal unemployment, etc. Unemployment is a situation in which people are willing to work at the prevailing wage rate, but do not get any work.

Open Unemployment: Open unemployment is the situation in which people above a certain age who are able to work and willing to work at the prevailing wage remain unemployed. Open unemployment is involuntary in nature. They are willing to work, but employment opportunities are not available to them. People standing in some selected areas waiting to be recruited as the hired worker is a case of open unemployment.

Disguised Unemployment: When more persons are working in a job than actually required, the situation is termed as disguised unemployment or hidden unemployment. If some workers are withdrawn from work, either total production or productivity falls. This type of unemployment is prominent in Indian agriculture.

Seasonal Unemployment: The type of unemployment caused by a change in seasons is termed as seasonal unemployment. This is normally found in the agricultural sector of India. Agriculture normally provides only seasonal employment and people are employed during the busy sowing and harvesting seasons. Seasonal unemployment could also be found in agro-based industries such as sugar mills, rice mills, cotton-spinning mills, etc.

Plus One Economics Notes Chapter 6 Rural Development

Students can Download Chapter 6 Rural Development Notes, Plus One Economics Notes helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus One Economics Notes Chapter 6 Rural Development

Rural Development
Rural development is quite a comprehensive term but it essentially means a plan of action for the development of areas which are lagging behind in socio-economic development. It essentially focuses on the action for the development of areas that are lagging behind in the overall development of the village economy. Some of the areas which are challenging and need fresh initiatives for development in India include:

  • Development of human resources including- literacy, more specifically, female literacy, education, and skill development-health, addressing both sanitation and public health
  • Land reforms
  • Development of the productive resources of each locality
  • Infrastructure development like electricity, irrigation, credit, marketing, transport facilities including construction of village roads and feeder roads to nearby highways, facilities for agriculture research and extension, and information dissemination
  • Special measures for alleviation of poverty and bringing about significant improvement in the living conditions of the weaker sections of the population emphasizing access to productive employment opportunities.

Credit and Marketing in Rural Areas
Credit: Growth of rural economy depends primarily on the infusion of capital, from time to time, to realize higher productivity in agriculture and non-agriculture sectors. As the time gestation between crop sowing and realization of income after production is quite long, farmers borrow from various sources to meet their initial investment on seeds, fertilizers, implements and other family expenses of marriage, death, religious ceremonies.

A major change occurred after 1969 when India adopted social banking and a multi-agency approach to adequately meet the needs of rural credit. Later, the National Bank for Agriculture and Rural Development (NABARD) was set up in1982 as an apex body to coordinate the activities of all institutions involved in the rural financing system.

The institutional structure of rural banking today consists of a set of multi-agency institutions, namely, commercial banks, regional rural banks (RRBs), co-operatives and land development banks. Recently, Self-Help Groups (henceforth SHGs) have emerged to fill the gap in the formal credit system because the formal credit delivery mechanism has not only proven inadequate but has also not been fully integrated into the overall rural social and community development. By March end 2003, more than seven lakh SHGs had reportedly been credit linked. Such credit provisions are generally referred to as micro-credit programmes.

Agricultural Market System
Agricultural marketing is a process that involves the assembling, storage, processing, transportation, packaging, grading and distribution of different agricultural commodities across the country. Let us discuss four such measures that were initiated to improve the marketing aspect.

1. The first step was regulation of markets to create orderly and transparent marketing conditions.

2. Second component is provision of physical infrastructure facilities like roads, railways, warehouses, godowns, cold storages and processing units.

3. Co-operative marketing, in realizing fair prices for farmers’ products, is the third aspect of a government initiative.

4. The fourth element is the policy instruments like

  • assurance of minimum support prices (MSP) for 24 agricultural products
  • maintenance of buffer stocks of wheat and rice by Food Corporation of India and
  • distribution of food grains and sugar through PDS.

These instruments are aimed at protecting the income of the farmers and providing food grains at subsidized rate to the poor.

Diversification into Productive Activities
Diversification of farm products has two aspects: The first one relates to the diversification of crop production. The second one relates to the shift of the workforce from agriculture to other allied activities such as livestock, poultry, fishers, etc., and to non-farm sectors like food processing. Diversification of agriculture helps to provide alternative employment opportunities in the non-farm sector and will minimize the risk of depending exclusively on agriculture. These activities related to diversification are given below:

  • Animal husbandry
  • Fisheries
  • Horticulture

Sustainable Development and Organic Farming
In recent years, awareness of the harmful effect of chemical-based fertilizers and pesticides on our health is on a rise. Conventional agriculture relies heavily on chemical fertilizers and toxic pesticides, etc., which enter the food supply, penetrate the water sources, harm the livestock, deplete the soil and devastate natural eco-systems. Efforts in evolving technologies which are eco-friendly are essential for sustainable development and one such technology which is eco-friendly is organic farming.

Benefits of Organic Farming:
1. Organic agriculture offers a means to substitute costlier agricultural inputs (such as HYV seeds, chemical fertilizers, pesticides, etc.) with locally produced organic inputs that are cheaper and thereby generate good returns on investment.

2. Organic agriculture also generates income through international exports as the demand for organically grown crops is on a rise.

3. Studies across countries have shown that organically grown food has more nutritional value than chemical farming thus providing us with healthy foods.

4. Since organic farming requires more labour input than conventional farming, India will find organic farming an attractive proposition.

5. Finally, the produce is pesticide-free and produced in an environmentally sustainable way.

Plus One Economics Notes Chapter 4 Poverty

Students can Download Chapter 4 Poverty Notes, Plus One Economics Notes helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus One Economics Notes Chapter 4 Poverty

Poverty and Poverty Line
Poverty is a multi-dimensional concept. It is defined as a situation in which a section of society is unable to fulfill even the basic necessities of life or deprived of basic necessities of life. Poverty is measured on the basis of the poverty line. One way is to determine it by the monetary value (per capita expenditure) of the minimum calorie intake that was estimated at 2,400 calories for a rural person and 2,100 for a person in the urban area.

Causes of Poverty
Important causes of poverty in India are:

  • Low income
  • Lack of assets
  • Unemployment
  • Inequality
  • Exploitation
  • Population explosion
  • Undesirable economic growth
  • Inflation
  • Absence of industrialisation.

Poverty Eradication Programmes
Poverty eradication programmes in India are classified as follows:

Self-employment Programmes
Integrated Rural Development Programme (IRDP): The IRDP was introduced in 2nd October 1980. This programme has been renamed as
Swarnajayanthi Grama Swarojgar Yojana (SGSY) from 1st April 1999. The SGSY is a very holistic programme compared to IRDP. SGSY is developed by merging various programmes such as TRYSEM (Training of Rural Youth for Self-employment), DWCRA (Development of Women and Children in Rural Areas), GKY (Ganga Kalyan Yojana), MSW (Million Well Scheme), and SITRA (Supply of Improved Tool Kits to Rural Artisans). It forms SHG’s (Self-Help Groups) of poor people and formulates self-employment programmes under their leadership. It includes development of infrastructure, technology, credit and marketing managements, etc. Unlike other programmes, the priority of the employment programme can be fixed by the beneficiaries.

Wage Employment Programmes
1. National Rural Emptoyment Programme (NREP): NREP was the new name given to Food for Work Programme. It was launched in 1980 as a centrally sponsored scheme with state and central governments sharing equal amounts. The aim of this programmer the development of community assets like drinking water wells, irrigation wells, rural roads, schools, etc.

2. The Rural Landless Employment Guarantee Programme (RLEGP): This programme was launched on 15th August 1983 to supplement NREP. This is a centrally sponsored scheme with 100 percent fund by the union government.

3. Jawahar Rozgar Yojana (JRY) and Nehru Rozgar Yojana (NRY): NREP and the RLEGP were merged and renamed into a single rural employment programme known as Jawahar Rozgar Yojana. JRY came into effect from 1st April 1999. The aim of the programme was to provide gainful employment for unemployed rural areas. The urban version of JRY is known as Nehru Rozgar Yojana (NRY).

4. The Million Well Scheme (MWS) was to provide open irrigation well, free of cost, to poor small and marginal farmers belonging to SC/ST category.

5. Indira Awas Yojana (IAY) was introduced for providing houses, free of cost to SC/ST families. Now this facility is extended to other poor families too.

6. Pradan Manthri Gramodaya Yojana: Gramin Awas (PMRY)
The PMRY: GAwas launched on 1st April, 2000. The programme aims at providing the housing needs of the rural people.

7. National Rural Employment Guarantee Programme (NREGP) 2005: In August 2005, the Parliament has passed a new Act known as National Rural Employment Guarantee Act 2005. The act provides guaranteed wage employment to every household whose adult volunteer is to do unskilled manual work for a minimum of 100 days in a year. Thj act came into force from 2nd February 2006 and implemented in India’s 200 most backward districts. Later on it was extended to all over the country in two phases. The programme was later on renamed as Mahatma Gandhi National Rural Employment Guarantee Programme (MGNREGP) or commonly called Employment Assurance Scheme.

Social Security Programmes: There are not many programmes for the social security of the poor. However, there are some centrally sponsored schemes. They are as follows:

  • Old-age pension for the elderly who are without support.
  • Financial support in the event of the death of the breadwinner.
  • Support for women of poor households on pregnancy.

Food Security Programmes: It is essential to ensure food security to the masses. As we know, though there js sufficient production of food grains, millions of people are starving in the country. The problem is mainly of distribution. To overcome these several measures are taken by the government. They are as follows:

1. Public distribution system (PDS): Foodgrains are made available at cheaper prices and distributed through Fair Price Shops, ration shops, Maveli Stores, Neethi Stores etc.

2. Targeted Public Distribution System (TPDS): The TPDS initiated in June 1997 aims at ensuring the availability of food grains to BPL families.

3. Integrated Child Development Schemes (ICDS): A nutrition programme meant for children below 6 years of age, pregnant and lactating women.

4. Mid-day Meal at School: Mid-day Meal at School is in operation in several states. The programme was launched in all India level on 15th August 1995.

5. Annapurna Scheme: This programme was commenced from 2000-01. Poor old people who are not getting old-age pensions are covered under this scheme.

6. Antyodaya Anna Yojana: This scheme is launched for the poorest of the poor. Under this scheme, food grains are made available to very poor families at a highly subsidised price.

Plus Two Physics Previous Year Question Paper Say 2018

Kerala State Board New Syllabus Plus Two Physics Previous Year Question Papers and Answers.

Kerala Plus Two Physics Previous Year Question Paper Say 2018 with Answers

BoardSCERT
ClassPlus Two
SubjectPhysics
CategoryPlus Two Previous Year Question Papers

Time: 2½ Hours
Cool off time : 15 Minutes

General Instructions to candidates

  • There is a ‘cool off time’ of 15 minutes in addition to the writing time of 2½ hrs.
  • Your are not allowed to write your answers nor to discuss anything with others during the ‘cool off time’.
  • Use the ‘cool off time’ to get familiar with the questions and to plan your answers.
  • Read questions carefully before you answering.
  • All questions are compulsory and only internal choice is allowed.
  • When you select a question, all the sub-questions must be answered from the same question itself.
  • Calculations, figures and graphs should be shown in the answer sheet itself.
  • Malayalam version of the questions is also provided.
  • Give equations wherever necessary.
  • Electronic devices except non programmable calculators are not allowed in the Examination Hall.

You may use following Physical constants wherever necessary.

Mass of proton 1.66 × 10-27 kg
Mass of Electron 9.11 × 10-31 kg
Elementary charge, e = 1.6 × 10-19 C
Velocity of light in vacuum c = 3 × 10m/s
Permittivity of free space ε0 = 8.85 × 10-12 F/m

Question Nos. 1 to 7 carry 1 score each. Answer 6 questions. (6 × 1 = 6)

Question 1.
Write the physical quantities having the following SI unit.
i) cm
ii) Ωm
Answer:
i) Electric dipole moment
ii) Electrical resistivity

Question 2.
A uniform wire of resistance 40Ω is cut into four equal parts and they are connected in parallel. The effective resistance of the combination is
i) 40Ω
ii) 10Ω
iii) 2.5Ω
iv) 4Ω
Answer:
Plus Two Physics Previous Year Question Paper Say 2018, 1

Question 3.
A particle of charge q is moving through a uniform magnetic field of intensity B with a velocity v. Write an expression for the force acting on the particle in vector form.
Answer:
\(\overrightarrow{\mathrm{F}}=\mathrm{q}(\overrightarrow{\mathrm{v}} \times \overrightarrow{\mathrm{B}})\)

Question 4.
The minimum distance between the object and its real image for a concave mirror of focal length f is
i) f
ii) 2f
iii) 4f
iv) zero
Answer:
iv) zero

Question 5.
Variation of photocurrent with collector plate potential for different intensities I1, I2, and I3 of incident radiation is shown below.
Plus Two Physics Previous Year Question Paper Say 2018, 2
Arrange these intensities in the accending order.
Answer:
I3 > I2 > I1

Question 6.
An electron is revolving around the nucleus of a hydrogen atom in an orbit of radius nine times the radius of the first orbit. Angular momentum of the electron in this orbit is.
i) \(\frac{h}{2 \pi}\)
ii) \(\frac{9 h}{2 \pi}\)
iii) \(\frac{3 h}{\pi}\)
iv) \(\frac{3 h}{2 \pi}\)
Answer:
radius of the nucleus r = n2r0
In this case
∴ n2 = 9, n= 3
Angular momentum L = \(\frac{\mathrm{nh}}{2 \pi}\)
for third orbit L = \(\frac{3 h}{2 \pi}\)

Question 7.
The voltage-current characteristics of an optoelectronic junction device is shown below.
Plus Two Physics Previous Year Question Paper Say 2018, 3
Identify the device.
Answer:
Solar cell

Question Nos. 8 – 15 carry 2 scores each. Answer any 7 questions. (7 × 2 = 14)

Question 8.
What is the radius of the circular path of an electron moving at a speed of 3 × 107 m/s in a magnetic field of 6 × 10-4 T perpendicular to it?
Answer:
radius r = \(\frac{m v}{q B}\)
v = 3 × 107 m/s, m = 9.1 × 10-31kg
B = 6 × 10-4, q = 1.6 × 10-19
r = \(\frac{9.1 \times 10^{-37} \times 3 \times 10^{7}}{1.6 \times 10^{-19} \times 6 \times 10^{-4}}\) = 0.285 m

Question 9.
a) “Parallel currents attract, and antiparallel currents repel”. State whether this statement is true or false.
b) Define the SI unit of current in terms of force between two current-carrying conductors.
Answer:
a) True
b) Ampere is defined as that current which is maintained in two straight parallel conductors of infinite length placed one meter apart in the vacuum will produce between a force of 2 × 10-7 Newton per meter length.

Question 10.
A circular metallic loop and a current-carrying conductor are placed as shown in the figure.
Plus Two Physics Previous Year Question Paper Say 2018, 4
If the current through the conductor is increasing from A to B, find the direction of the induced current the loop.
Answer:
Current flows in a clockwise direction

Question 11.
a) The electric field vector of an electromagnetic wave is represented as Ex = Em Sin(kz – ωt). Write the equation for the magnetic field vector.
b) The ratio of the intensity of the magnetic field to intensity of the electric field has the dimensions of
i) velocity
ii) acceleration
iii) reciprocal of velocity
iv) reciprocal of acceleration
Answer:
a) By = Bm Sin (Kz – ωt)
b) reciprocal of velocity

Question 12.
Write the equations for the following nuclear reactions:
a) β+decay of \({ }_{6}^{11} c\) to Boron (B)
b) β decay of \({ }_{15}^{32} c\) to Sulphur (S)
Answer:
Plus Two Physics Previous Year Question Paper Say 2018, 5

Question 13.
Write the truth table of the circuit shown below.
Plus Two Physics Previous Year Question Paper Say 2018, 6
Answer:

ABY
000
011
101
111

Question 14.
A TV transmitting antenna is 100 m tall. How much service area can it cover if the receiving antenna is at the ground level? Radius of earth is 6400 km.
Answer:
Hight of antenna, h = 100 m = 0.1 km
Radius of earth = 6400 km
Transmission range d = \(\sqrt{2 R h}\)
∴ Maximum area covered A = πd2
= π(\(\sqrt{2 R h}\))2
= 3.14 × 2 × 6400 × 0.1
= 4019 km2

Question 15.
Two magnetic dipoles P and Q are placed in a uniform magnetic field \(\vec{B}\) gas shown.
Plus Two Physics Previous Year Question Paper Say 2018, 7
a) Both the dipoles do not experience any torque. Why?
b) Identify the dipole which is in most stable equilibrium.
Answer:
a) Dipole moment is parallel to magnetic field.
b) Dipole Q

Question Nos. 16 to 22 carry 3 scores each. Answer any 6 questions. (6 x 3 = 18)

Question 16.
The experimental setup for the comparison of two resistances is shown below.
Plus Two Physics Previous Year Question Paper Say 2018, 8
a) The working principle of the above device is
i) Ohm’s law
ii) Kirchhoffs second law
iii) Wheatstone’s principle
iv) Point Rule
b) In figure, Let X is the effective resistance of series combination of two 3Ω resistors and R is the effective of a parallel combination of two 3Ω resistors. The balance point is obtained at C. If the length AB is 100 cm. find the length AC of the wire.
Answer:
a) Wheatston’s principle
b) x = 6 Ω
R = 1.5 Ω
Plus Two Physics Previous Year Question Paper Say 2018, 9

Question 17.
A magnetic needle has a magnetic moment 6.7 × 10-7 Am2 and moment of inertia 7.5 × 10-6 kgm2. In a uniform magnetic field, it performs 10 complete oscillations in 6.70s. What is the magnitude of the magnetic field?
Answer:
magnetic moment m = 6.7 × 10-2 Am2
moment of inertria, I = 7.5 × 10-6 kgm2
Plus Two Physics Previous Year Question Paper Say 2018, 10

Question 18.
With the help of a ray diagram, show the formation of image of a point object by refraction of light at a spherical surface separating two media of refractive indices n1 and n2. Using the diagram derive the relation
\(\frac{n_{2}}{v}-\frac{n_{1}}{u}=\frac{n_{2}-n_{1}}{R}\)
Answer:
Plus Two Physics Previous Year Question Paper Say 2018, 11
Consider a convex surface XY, which separates two media having refractive indices n1 and n2. Let C be the centre of curvature and P be the pole. Let an object is placed at ‘O’, at a distance ‘u’ from the pole. I is the real image of the object at a distance ‘V’ from the surface. OA is the incident ray at angle ‘i’ and AI is the refracted ray at an angle ‘r’. OP is the ray incident normally. So it passes without any deviation. From snell’s law,
sin i/sin r = \(\frac{\mathrm{n}_{2}}{\mathrm{n}_{1}}\)
If ‘i’ and ‘r’ are small, then sin i » i and sin r » r.
Plus Two Physics Previous Year Question Paper Say 2018, 12
From the Δ OAC, exterior angle = sum of the interior opposite angles
i.e., i = α + θ ………(2)
Similarly, from Δ IAC,
α = r + β
r = α – β ………..(3)
Substituting the values of eq(2) and eq(3)in eqn.(1)
we get,
n1(α + θ) = n2(α – β)
n1α + n1θ = n2α – n2β
n1θ + n2β = n2α – n1α
n1θ + n2β = (n2 – n1)α ………..(4)
From OAP, we can write,
Plus Two Physics Previous Year Question Paper Say 2018, 13
According to New Cartesian sign convection, we can write,
OP = -u, PI = +v and PC = R
Substituting these values, we get
Plus Two Physics Previous Year Question Paper Say 2018, 14

Question 19.
a) Draw a graph showing the variation of stopping potential with the frequency of incident radiation. Mark the threshold frequency in the figure.
b) Using Einstein’s photoelectric equation, show that photoelectric emission is not possible if the frequency of incident radiation is less than the threshold frequency.
Answer:
a)
Plus Two Physics Previous Year Question Paper Say 2018, 15
b) According to Einsten’s Equation
hν = hν0 + KE
if = ν < ν0, kinetic energy of electron becomes negative.

Question 20.
a) The energy levels of an atom are as shown in the figure.
Plus Two Physics Previous Year Question Paper Say 2018, 16
Which transition corresponds to emission of radiation of maximum wavelength?
b) Sketch the energy level diagram for hydrogen atom and mark the transitions corresponding to Balmer series.
Answer:
a) In between 0 to -2ev
b)
Plus Two Physics Previous Year Question Paper Say 2018, 17

Question 21.
The decay rate of a radioactive ample is called its activity.
a) What is the SI unit of activity?
b) The half life of \({ }_{92}^{238} U\) against alpha decay is 1.5 × 10-17 s. Calculate the activity of a sample of \({ }_{92}^{238} U\) having 25 × 1020 atoms.
Answer:
a) becquerel
b) N = 25 × 1020, half life T1/2 = 1.5 × 1017s
activity, R = λN
R = \(\frac{0.693}{\mathrm{~T}_{1 / 2}} \times \mathrm{N}=\frac{0.693}{1.5 \times 10^{17}} \times 25 \times 10^{20}\)
R = 11550 Bq

Question 22.
a) Draw the circuit diagram where a zener diode is used as a direct voltage regulator.
b) In a zener regulated power supply a zener diode with zener voltage 4V is used for regulation. The load current is to be 4 m A and zener current is 20 mA. If the unregulated input is 10V, What should be the value of resistor that is to be connected in series with the diode?
Answer:
a)
Plus Two Physics Previous Year Question Paper Say 2018, 18
b) Zener voltage
V2 = 4V, IL = 4 × 10-3 A, I2= 20 × 10-3 A
Unregulated input = 10 v
Voltage across resister = 10 – 4 = 6v
Current through the resister = IL+ I2
= (4 + 20) mA
= 24 × 10-3 A
∴ resistance R = \(\frac{V}{I}\)
R = \(\frac{6}{24 \times 10^{-3}}\) = 250 Ω

Question Nos. 23 to 26 carry 4 scores each. Answer any 3 questions. (3 × 4 = 12)

Question 23.
Coulomb’s Law is a quantitative statement about the force between two point charges.
a) Write the mathematical expression of the above law.
b) Two ions carrying equal charges repel with a force of 1.48 × 10-8 N when they are separated by a distance of 5 × 10-10 m. How many electrons have been removed from each iron?
Answer:
Plus Two Physics Previous Year Question Paper Say 2018, 19

Question 24.
a) Potential energy of a system of charges is directly proportional to the product of charges and inversely to the distance between them.
a) Prove the above statement.
b) Two-point charges 3 × 10-8 C and -2 × 10-8 C are separated by a distance of 15cm. At what point on the line joining the charges the potential is zero?
Answer:
a) Potential of a system is the work done to assemble the system,
∴ w = qV
= \(\mathrm{q}_{1} \times \frac{1}{4 \pi q_{0}} \frac{\mathrm{q}_{2}}{\mathrm{r}}\)
In the above equation it is dear that energy is di-rectly proportial to charges and inversely proportional to the distance between them.
b) q1 = 3 × 10-8
Plus Two Physics Previous Year Question Paper Say 2018, 20

Question 25.
The circuit shown can be analysed using Kirchhoff’s rules.
Plus Two Physics Previous Year Question Paper Say 2018, 21
a) Apply Kirchhoffs first law to the point B.
b) State Kirchhoffs second law.
c) Apply Kirchhoffs second lawtothe mesh ABFGA.
Answer:
a) At the point B,
I1 = I2 = I3
b) In any closed circuit emf is eqaual to sum of potential drops.
c) -I2 R3 – I1 R2 – I1R1 + E1 = 0

Question 26.
Biot – Savart’s law relates current with the magnetic field produced by it.
a) Write the mathematical expression of the above law in vector form.
b) Using the law derive an expression for intensity of magnetic field at a point at distance x from the centre and on the axis of a circular current loop.
Answer:
Plus Two Physics Previous Year Question Paper Say 2018, 22
Consider a circular loop of radius ‘a’ and carrying current “I’. Let P be a point on the axis of the coil, at distance x from A and r from ‘O’. Consider a small length dl at A.
The magnetic field at ‘p’ due to this small element dI,
Plus Two Physics Previous Year Question Paper Say 2018, 23
The dB can be resolved into dB cos Φ (along with Py) and dBsinΦ (along with Px).
Similarly consider a small element at B, which produces a magnetic field ‘dB’ at P. If we resolve this magnetic field we get.
dB sinΦ (along px) and dB cosΦ (along py1)
dBcosΦ components cancel each other because they are in opposite direction. So only dB sinΦ components are found at P, so the total filed at P is
Plus Two Physics Previous Year Question Paper Say 2018, 24
Let there be N turns in the loop then,
B = \(\frac{\mu_{0} \text { NIa }^{2}}{2\left(\mathrm{r}^{2}+\mathrm{a}^{2}\right)^{3 / 2}}\)

Question Nos. 27 to 29 carry 5 scores each. Answer any 2 questions. (2 × 5 = 10)

Question 27.
A series LCR circuit shows the phenomenon called resonance.
a) Write the condition for resonance and obtain an equation for resonant frequency.
b) Obtain the Q value of a series LCR circuit with L = 2.0 H, c = 32µ F and R = 10 Ω.
c) Complete the following table using the suitable words from the bracket for two series LCR circuits.
(Current and applied voltage are in the same phase, currently leads the applied voltage, currently lags the applied voltage)
Plus Two Physics Previous Year Question Paper Say 2018, 25
Answer:
a) Condition for resonance XL = XC
Plus Two Physics Previous Year Question Paper Say 2018, 26
c) i) Cuurrent lags the applied voltage
ii) Current and applied voltage are in same phase.

Question 28.
Telescope is used to provide angular magnification of distant objects.
a) If f0 is the focal length of the objective and fe that of the eyepiece, the length of the telescope tube is ………..
b) Draw the ray diagram of a refracting type telescope when it is in normal adjustment.
c) Write any two advantages of reflecting type telescope over refracting type telescopes.
Answer:
a) f0 + fe
b)
Plus Two Physics Previous Year Question Paper Say 2018, 27
c) i) There is no chromatic aberration
ii) There is no spherical aberration

Question 29.
A wavefront is defined as a surface of constant phase.
a) The energy of the wave travels in a direction …….. to the wavefront.
b) Explain the Huygen’s principle.
c) Using Huygen’s Principle, prove that angle of incidence is equal to angle of reflection.
Answer:
a) Perpendicular

b) 1) Every point in a wavefront acts as a source of secondary wavelets.
2) The secondary wavelets travel with the same velocity as the original value.
3) The envelope of all these secondary wavelets gives a new wavefront.

c)
Plus Two Physics Previous Year Question Paper Say 2018, 28
AB is the incident wavefront and CD is the reflected wavefront. T is the angle of incidence and Y is the angle of reflection. Let c, be the velocity of light in the medium. Let PO be the incident ray and OQ be the reflected ray.

The time taken for the ray to travel from P to Q is
Plus Two Physics Previous Year Question Paper Say 2018, 29
Plus Two Physics Previous Year Question Paper Say 2018, 30
O is an arbitrary point. Hence AO is a variable. But the time to travel for a wavefront from AB to CD is a constant. So eq.(2) should be independent of AO. i.e., the term containing AO in eq.(2) should be zero.
∴ \(\frac{A O}{C_{1}}\) (sin i – sin r) = 0
sin i – sin r = 0
sin i = sin r
i = r
This is the law of reflection.

Plus Two Physics Previous Year Question Paper March 2019

Kerala State Board New Syllabus Plus Two Physics Previous Year Question Papers and Answers.

Kerala Plus Two Physics Previous Year Question Paper March 2019 with Answers

BoardSCERT
ClassPlus Two
SubjectPhysics
CategoryPlus Two Previous Year Question Papers

Time: 2½ Hours
Cool off time: 15 Minutes

General Instructions to candidates

  • There is a ‘cool off-time’ of 15 minutes in addition to the writing time of 2½ hrs.
  • You are not allowed to write your answers nor to discuss anything with others during the ‘cool off time’.
  • Use the ‘cool off time’ to get familiar with the questions and to plan your answers.
  • Read questions carefully before you answering.
  • All questions are compulsory and the only internal choice is allowed.
  • When you select a question, all the sub-questions must be answered from the same question itself.
  • Calculations, figures, and graphs should be shown in the answer sheet itself.
  • Malayalam version of the questions is also provided.
  • Give equations wherever necessary.
  • Electronic devices except non-programmable calculators are not allowed in the Examination Hall.

The given value of constants can be used wherever necessary.

Charge of proton = 1.6 x 10-19C
Mass of proton = 1.67 x 10-27kg

Answer any three questions from 1 to 4. Each carries 1 score. (3 × 1 = 3)

Question 1.
A charged particle enters a uniform magnetic field at an angle of 40°. It’s path becomes …………
Answer:
Helical

Question 2.
Figure shows the symbolic representation of ……….
Plus Two Physics Previous Year Question Paper March 2019, 1
i) OR gate
ii) NAND gate
iii) NOR gate
iv) NOT gate
Answer:
iii) NOR gate

Question 3.
Write the unit of mobility.
Answer:
Plus Two Physics Previous Year Question Paper March 2019, 2

Question 4.
If ‘h’ is Planck’s constant, the momentum of a photon of wavelength 1 A° is
i) h
ii) 10-10
iii) 1010 h
iv) 10 h
Answer:
Plus Two Physics Previous Year Question Paper March 2019, 3

Answer any six questions from 5 to 11. Each carries 2 scores. (6 × 2 = 12)

Question 5.
a) The ratio of electric field on the equatorial point and at the axial point at equal distances from the centre of a short electric dipole is ………..
b) A closed surface encloses an electric dipole. What is the electric flux through the surface?
Answer:
Plus Two Physics Previous Year Question Paper March 2019, 4

Question 6.
A series LCR circuit connected to an ac source is shown below:
Plus Two Physics Previous Year Question Paper March 2019, 5
a) Write an expression for impedance offered by its circuit.
b) Under what condition this circuit is used for tuning radio?
Answer:
a) Impedence Z = \(\sqrt{R^{2}+\left(x_{L}-x_{C}\right)^{2}}\)
b) at XL = XC this circuit is used as tuner circuit.

Question 7.
Which electromagnetic waves are used for the following purposes?
i) Diagnostic tool in medicine.
ii) Kill germs in water purifiers.
iii) Cellular phones.
iv) In remote switches of household electronic systems.
Answer:
i) X-rays
ii) Uv rays
iii) Radio Waves
iv) IR rays

Question 8.
Calculate the effective capacitance between ’a’ and ‘b’ from the figure given below:
C1 = C3 = 100 µF, C2 = C4 = 200 µF
Plus Two Physics Previous Year Question Paper March 2019, 6

Question 9.
Write any two uses of polaroids.
Answer:

  1. Polaroids are used in sunglasses
  2. Polaroids are used to produce 3D motion films

Question 10.
The temperature dependence of resistivity of a material is shown below:
Plus Two Physics Previous Year Question Paper March 2019, 7
a) Identify the type of material.
b) Write the relation between resistivity and average collision time for electron.
Answer:
a) Semi conductor
b) ρ = \(\frac{\mathrm{m}}{\mathrm{ne}^{2} \tau}\)

Question 11.
What is meant by the half-life of a radioactive substance? Write its relation with a decay constant.
Answer:
Half-life is the time taken for a radioactive substance to reduce half of its initial value.
\(T_{1 / 2}=\frac{0.693}{\lambda}\)

Answer any six questions from 12 to 18. Each carries 3 scores. (6 × 3 = 18)

Question 12.
A spherical shell of radius R’ is uniformly charged with charge +q. By Gauss’stheorem, find the electric field intensity at a point ‘p’.
a) Outside the spherical shell and
b) Inside the spherical shell.
Answer:
Field Due To A Uniformly Charged Thin Spherical Shell: Consider a uniformly charged hollow spherical conductor of radius R. Let ‘q’ be the total charge on the surface.
Plus Two Physics Previous Year Question Paper March 2019, 8
To find the electric field at P (at a distance r from the centre), we imagine a Gaussian spherical surface having radius ‘r’.

Then, according to Gauss’s theorem we can write,
\(\int \overrightarrow{\mathrm{E}} \cdot \mathrm{d} \overrightarrow{\mathrm{s}}=\frac{1}{\varepsilon_{0}} \mathrm{q}\)
The electric field is constant,at a distance T. So we can write,
Plus Two Physics Previous Year Question Paper March 2019, 9
b) E = 0.

Question 13.
The equipotential surface through a point is normal to the electric field at that point.
a) What is meant by equipotential surface?
b) What is the work done to move a charge on an equipotential surface?
c) Draw the equipotential surfaces for a uniform electric field.
Answer:
a) The surface over which potential is constant is equipotential surface.
b) Workdone = pd × charge
= 0 × q = 0
c)
Plus Two Physics Previous Year Question Paper March 2019, 10

Question 14.
The elements of earth’s magnetic field at a place are declination, dip and horizontal intensity.
a) A magnetic needle free to move in horizontal plane is shown below:
Plus Two Physics Previous Year Question Paper March 2019, 11
Which element of earth’s magnetic field is represented by θ in the figure?
b) The vertical component of earth’s magnetic field at a given place is \(\sqrt{3}\) times its horizontal component. If total intensity of earth’s magnetic field at the place is 0.4 G find the value of horizontal component of earth’s magnetic field.
Answer:
a) Declination
b) tan θ = \(\frac{B_{V}}{B_{H}}=\sqrt{3}\)
∴ θ = 60°
BH = B cos θ, B = 0.4 G
BH = 0.4 × cos 60 = 0.2 G
= 0.2 × 10-4 T

Question 15.
A transformer is used to change the alternating voltage to a high or low value.
a) What is the principle of a transformer?
b) A power transmission line feeds input power of 2300 V to a stepdown transformer with its primary windings having 4000 turns. What should be the number of turns in the secondary in order to get output power at 230 V?
Answer:
a) Mutual Induction
b) Vp = 2300 v, Np = 4000 turns
Vs = 230 v
Plus Two Physics Previous Year Question Paper March 2019, 12

Question 16.
Describe Young’s double-slit experiment and derive an expression for the bandwidth of the interference band.
Answer:
Expression for bandwidth
Plus Two Physics Previous Year Question Paper March 2019, 13
S1 and S2 are two coherent sources having wave length λ. Let ‘d’ be the distance between two coherent sources. A screen is placed at a distance D from sources. ‘O’ is a point on the screen equidistant from S1 and S2.

Hence the path difference, S1O – S2O = 0
So at ‘O’ maximum brightness is obtained.
Let ‘P’ be the position of nth bright band at a distance xn from O. Draw S1A and S2B as shown in figure.
From the right angle ΔS1AP
Plus Two Physics Previous Year Question Paper March 2019, 14
But we know constructive interference takes place at P, So we can take
(S2P – S1P) = nλ
Hence eq (1) can be written as
Plus Two Physics Previous Year Question Paper March 2019, 15
Let xn + 1 be the distance of (n + 1)th bright band from centre O, then we can write
Plus Two Physics Previous Year Question Paper March 2019, 16
This is the width of the bright band. It is the same for the dark band also.

Question 17.
The schematic diagram of an experimental setup to study the wave nature of electron is shown below:
Plus Two Physics Previous Year Question Paper March 2019, 17
a) Identify the experiment.
b) Explain how this experiment verified the wave nature of electrons.
Answer:
a) Davisson and Germer Experiment
b)
Plus Two Physics Previous Year Question Paper March 2019, 18
Experimental setup: The Davisson and Germer Experiment consists of filament ‘F’, which is connected to a low tension battery. The Anode Plate (A) is used to accelerate the beam of electrons. A high voltage is applied in between A and C. ’N’ is a nickel crystal. D is an electron detector. It can be rotated on a circular scale. Detector produces current according to the intensity of incident beam.

Working: The electron beam is produced by passing current through filament F. The electron beam is accelerated by applying a voltage in between A (anode) and C. The accelerated electron beam is made to fall on the nickel crystal. The nickel crystal scatters the electron beam to different angles. The crystal is fixed at an angle of Φ = 50° to the incident beam. The detector current for different values of the accelerating potential ‘V’ is measured. A graph between detector current and voltage (accelerating) is plotted. The shape of the graph is shown in figure.

Analysis of graph:
Plus Two Physics Previous Year Question Paper March 2019, 19
The graph shows that the detector current increases with accelerating voltage and attains maximum value at 54V and then decreases. The maximum value of current at 54 V is due to the constructive interference of scattered waves from nickel crystal (from different planes of the crystal). Thus wave nature of electrons is established.

The experimental wavelength of electron: The wavelength of the electron can be found from the formula
2d sinθ = nλ …….. (1)
From the figure, we get
θ + Φ + θ = 180°
2θ = 180 – Φ, 2θ = 180 – 50°
θ = 65°
for n = 1
equation (1) becomes
λ = 2d sinθ ……….. (2)
for Ni crystal, d = 0.91 A°
Substituting this in eq. (2), we get
wavelength λ = 1.65 A°

The theoretical wavelength of the electron:
The accelerating voltage is 54 V
Energy of electron E = 54 × 1.6 × 10-19 J
Plus Two Physics Previous Year Question Paper March 2019, 20

Discussion: The experimentally measured wave-length is found in agreement with de-Broglie wavelength. Thus wave nature of electron is confirmed.

Question 18.
The energy required to separate all the nucleons inside a nucleus is called binding energy of the nucleus.
a) Write an expression for binding energy in terms of mass defect.
b) Draw the graph showing the variation of binding energy per nucleon as a function of mass number.
c) Which nucleus possess maximum binding energy per nucleon?
Answer:
a) BE = Δ mc2 or
BE = (Zmp + (A – Z) mn – M)c2
b) Graph
Plus Two Physics Previous Year Question Paper March 2019, 21
c) Fe (nucleus of iron)

Answer any three questions from 19 to 22. Each carries 4 scores. (3 × 4 = 12)

Question 19.
Niels Bohr made certain modification in Rutherford’s model by adding the ideas of quantum hypothesis.
a) State Bohr’s second postulate of quantisation of angular momentum.
b) Derive an expression for the radius and energy of the electron in the nth orbit of hydrogen atom.
Answer:
a) The orbital angular momentum of electron is an integral multiple of \(\frac{\mathrm{h}}{2 \pi}\)

b) Radius of the hydrogen atom: Consider an electron of charge ‘e’ and mass m revolving round the positively charged nucleus in circular orbit of radius ‘r’.
The force of attraction between the nucleus and the electron is
Plus Two Physics Previous Year Question Paper March 2019, 22
This force provides the centripetal force for the orbiting electron
Plus Two Physics Previous Year Question Paper March 2019, 23
According to Bohr’s second postulate, we can write
Angular momentum, mvr = \(\frac{\mathrm{nh}}{2 \pi}\)
i.e., v = \(\frac{\mathrm{nh}}{2 \pi \mathrm{mr}}\)
Substituting this value of V in equation (2), we get
Plus Two Physics Previous Year Question Paper March 2019, 24
Energy of the hydrogen atom:
The K.E. of revolving electron is
Plus Two Physics Previous Year Question Paper March 2019, 25
Substituting the value of equation (5) in equation (9)
we get
Plus Two Physics Previous Year Question Paper March 2019, 26

Question 20.
Two long co-axial solenoids of same length are shown below:
Plus Two Physics Previous Year Question Paper March 2019, 27
a) Define mutual inductane of the pair of coils.
b) Derive an expression for mutual inductance of two co-axial solenoids.
c) Write the dimension of mutual inductance.
Answer:
a) Φ = MI, when I = 1 A, Φ = M
The mutual inductance of a pair of coils is numerically equal to the magnetic flux linked with one coil when unit current flows through the other.

b) Consider a solenoid (air core) of cross sectional area A and number of turns per unit length n. Another coil of total number of turns N is closely wound over the first coil. Let I be the current flow through the primary.
Flux density of the first coil B = μ0nI
Flux linked with second coil, Φ = BAN
Φ = μ0nIAN ………. (1)
But we know Φ = MI ………. (1)
From eq (1) and eq (2) weget
∴ MI = μ0nIAN
M = μ0nAN
If the solenoid is covered over core of relative per-meability μr
then M = μrμ0nAN
c) ML2T-2A-2

Question 21.
A small telescope has an objective lens of focal length 140 cm and an eyepiece of focal length 5 cm. What is the magnifying power of the telescope for viewing distant objects when
a) the telescope is in normal adjustment?
b) the final image is formed at the least distance of distinct vision.
Answer:
Plus Two Physics Previous Year Question Paper March 2019, 28

Question 22.
In Amplitude Modulation, the amplitude of the carrier wave is varied in accordance with the information signal.
a) What is meant by modulation index?
b) A message signal of frequency 10 kHz and peak value of 10 V used to modulate a carrier of frequency 1 MHz and peak voltage of 20 V. Determine the modulation index.
c) The block diagram of a transmitter is shown below. Identify the elements labelled X and Y.
Plus Two Physics Previous Year Question Paper March 2019, 29
Answer:
a) Modulation index, μ = \(\frac{A_{m}}{A_{c}}\)
b) Am = 10 V, Ac = 20 V
∴ μ = \(\frac{A_{m}}{A_{c}}=\frac{10}{20}\) = 0.5

Answer any three questions from 23 to 26. Each carries 5 scores. (3 × 5 = 15)

Question 23.
The cyclotron is a device used to accelerate charged particles.
a) With a suitable diagram briefly explain the working of a cyclotron and obtain an expression for cyclotron frequency.
b) Acyclotron oscillator frequency is 10 MHz. What should be the operating magnetic field for accelerating protons?
Answer:
a) Principles: Cyclotron is based on two facts

  1. An electric field can accelerate a charged particle.
  2. A perpendicular magnetic field gives the ion a circular path.

Constructional Details: Cyclotron consists of two semicircular dees D1 and D2, enclosed in a chamber C. This chamber is placed in between two magnets. An alternating voltage is applied in between D1 and D2. An ion is kept in a vacuum chamber.

Working: At certain instant, let D1 be positive and D2 be negative. Ion (+ve) will be accelerated towards D2 and describes a semicircular path (inside it). When the particle reaches the gap, D1 becomes negative and D2 becomes positive. So ion is accelerated towards D1 and undergoes a circular motion with larger radius. This process repeats again and again.

Thus ion comes near the edge of the dee with high K.E. This ion can be directed towards the target by a deflecting plate.
Plus Two Physics Previous Year Question Paper March 2019, 30

Mathematical expression: Let ‘v’ be the velocity of ion, q the charge of the ion and B the magnetic flux density.
If the ion moves along a semicircular path of radius Y, then we can write
Plus Two Physics Previous Year Question Paper March 2019, 31
Eq. (2) shows that time is independent of radius and velocity.

Resonance frequency (cyclotron frequency): The condition for resonance is half the period of the accelerating potential of the oscillator should be ‘t’. (i.e., T/2 = t or T = 2t). Hence period of AC
T = 2t
Plus Two Physics Previous Year Question Paper March 2019, 32
Plus Two Physics Previous Year Question Paper March 2019, 33

Question 24.
The experimental set up to find an unknown resistance using a metre bridge is shown below:
Plus Two Physics Previous Year Question Paper March 2019, 34
a) What is the principle of a metre bridge?
b) If the balance point is found to be at 39.5 cm from the end ‘A’, the resistor ‘S’ is of 12.5 Ω. Determine the resistance ‘R’. Why are the connections between resistors in a metre bridge made of thick copper strips?
c) If the galvanometer and cell are interchanged at the balance point of the bridge would the galvanometer show any current?
Answer:
Plus Two Physics Previous Year Question Paper March 2019, 35
The resistors in metre bridge are made of thick copper strips to minimise the resistance of connection.
c) No. The galvanometer will not show any current.

Question 25.
The circuit used to change alternating voltage to direct voltage is called rectifier.
a) With a neat diagram, explain the working of a full wave rectifier having two diodes.
b) What is the output frequency of a full wave rectifier if the input frequency is 50 Hz?
c) Draw the output wave form across the load resistance connected in the full wave rectifier circuit.
Answer:
a) Full wave rectifier:
Circuit details
Plus Two Physics Previous Year Question Paper March 2019, 36
Full wave rectifier consists of transformer, two diodes and a load resistance RL. Input a.c signal is applied across the primary of the transformer. Secondary of the transformer is connected to D1 and D2. The output is taken across RL.

Working: During the +ve half cycle of the a.c signal at secondary, the diode D1 is forward biased and D2 is reverse biased. So that current flows through D1 and RL.

During the negative half cycle of the a.c signal at secondary, the diode D1 is reverse biased and D2 is forward biased. So that current flows through D1 and RL. Thus during both the half cycles, the current flows through RL in the same direction. Thus we get a +ve voltage across RL for +ve and -ve input. This process is called full wave rectifcation.

b) 100 Hz

Plus Two Physics Previous Year Question Paper March 2019, 37

Question 26.
A ray of light parallel to the principal axis of a spherical mirror falls at a point M as shown in the figure below:
Plus Two Physics Previous Year Question Paper March 2019, 38
a) Identify the type of mirror used in the diagram.
b) By drawing a suitable ray diagram, obtain the mirror equation.
c) If the mirror is immersed in water, its focal length ………….
Answer:
a) Concave mirror

b)
Plus Two Physics Previous Year Question Paper March 2019, 39
Let points P, F, C be pole, focus and centre of curvature of a concave mirror. Object AB is placed on the principal axis. A ray from AB incident at E and then reflected through F. Another ray of light from B incident at pole P and then reflected. These two rays meet at M. The ray of light from point B is passed through C. Draw EN perpendicular to the principal axis.
Δ IMF and Δ ENF are similar.
Plus Two Physics Previous Year Question Paper March 2019, 40
but IF = PI – PF and NF = PF (since aperture is small)
hence eq. (1) can be written as
Plus Two Physics Previous Year Question Paper March 2019, 41
This is called mirror formula or mirror equation,

c) Remain the same

Plus One Botany Notes Chapter 11 Plant Growth and Development

Students can Download Chapter 11 Plant Growth and Development Notes, Plus One Botany Notes helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus One Botany Notes Chapter 11 Plant Growth and Development

Growth
Growth is defined as an irreversible permanent increase in the size of an organ or its parts of an individual cell.
It is accompanied by metabolic processes (both anabolic and catabolic), that occur at the expense of energy.
Eg: expansion of a leaf.

Plant Growth Generally is Indeterminate
Plant growth is unlimited growth due to the presence of meristems.
Root apical meristem and the shoot apical meristem are responsible for the primary growth of the plants and contribute to the elongation of the plants along their axis.

Role of lateral meristem in plants
In dicotyledonous plants and gymnosperms, the lateral meristems, (vascular cambium and cork-cambium) cause an increase in the girth of the organs. This is known as secondary growth.
Plus One Botany Notes Chapter 11 Plant Growth and Development 1

Growth is Measurable

  • Growth is measured in terms of increase in fresh weight, dry weight, length, area, volume, and cell number.
  • One single maize root apical meristem can give rise to more than 17,500 new cells per hour, cells in a watermelon increase in size by up to 3,50,000 times.
  • In the former, growth is expressed as an increase in cell number.
    latter expresses growth as an increase in the size of the cell.
  • While the growth of a pollen tube is measured in terms of its length, an increase in surface area denotes the growth in a dorsiventral leaf.

Phases of Growth
The period of growth is generally divided into three phases.

  1. Meristematic: The constantly dividing cells, both at the root apex and the shoot apex, represent the meristematic phase of growth.
  2. Elongation: The cells proximal to the meristematic zone represent the phase of elongation.
  3. Maturation: Proximal to the phase of elongation represents the phase of maturation.

 

Plus One Botany Notes Chapter 11 Plant Growth and Development 2

Growth Rates
The increased growth per unit time is termed as growth rate. The growth rate may be

  1. Arithmetic
  2. Geometrical

 

Plus One Botany Notes Chapter 11 Plant Growth and Development 3

On plotting the length of the organ against time, a linear curve is obtained, it is expressed as
Plus One Botany Notes Chapter 11 Plant Growth and Development 4

Lt = L0 + rt
Lt = length at time ‘t’
L0 = length at time ‘zero’.
r = growth rate/elongation per unit time.

Different phases of the Sigmoid curve

  1. lag phase
  2. log or exponential phase
  3. stationary phase

In most systems, the initial growth is slow (lag phase), and it increases rapidly at an exponential rate (log or exponential phase)
In the end, due to the limited nutrient supply, the growth slows down leading to a stationary phase. It is the typical sigmoid or S-curve.
Plus One Botany Notes Chapter 11 Plant Growth and Development 5
The exponential growth can be expressed as
W1 = W0 e rt
W1 = final size (weight, height, number etc.)
W0 = initial size at the beginning of the period
r = growth rate
t = time of growth
e = base of natural logarithms

Quantitative comparisons between the growth of a living system can also be made in two ways:

  • Measurement and the comparison of total growth per unit time is called the absolute growth rate.
  • The growth of the given system per unit time expressed on a common basis.

 

Plus One Botany Notes Chapter 11 Plant Growth and Development 6
In Figure two leaves, A and B, are drawn that are of different sizes but show an absolute increase in area in the given time to give leaves, A1 and B1.

Conditions for Growth
Water, oxygen, and nutrients as very essential elements for growth.
The plant cells grow in size by cell enlargement it requires water.
Turgidity of cells helps in extension growth. Water also provides the medium for enzymatic activities
Oxygen helps in releasing metabolic energy essential for growth activities.
Nutrients (macro and micro essential elements) are required by plants for the synthesis of protoplasm and act as a source of energy.
An optimum temperature range is best suited for plant growth.
Environmental signals such as light and gravity also affect certain phases/stages of growth.

Differentiation, Dedifferentiation, and Redifferentiation
1. The cells derived from root apical and shoot-apical meristems and cambium differentiate and mature to perform specific functions. This is termed as differentiation.
For example, during differentiation, tracheary elements lose their protoplasm and develop a very strong, elastic, lignocellulosic secondary cell wall, to carry water too long distances.

2. The living differentiated cells, that have lost the capacity to divide can regain the capacity of division This phenomenon is termed dedifferentiation.
For example, interfascicular cambium and cork cambium is formed from fully differentiated parenchyma cells.

3. Meristems are able to divide and produce cells that once again lose the capacity to divide but mature to perform specific functions. This is called a redifferentiation.
For example, secondary tissues develop from vascular cambium and cork cambium

Development
It is the stage of the life cycle in which germination of the seed to senescence.
Plus One Botany Notes Chapter 11 Plant Growth and Development 7
The plant shows a response to the environment to form different kinds of structures. This ability is called plasticity
Heterophylly is an example of plasticity

Types of Heterophylly
1. The leaves of the juvenile plant are different in shape from those in mature plants.
e.g cotton, coriander, and larkspur.
2. Shapes of submerged leaves are different from those produced in the air.
Eg buttercup.
Plus One Botany Notes Chapter 11 Plant Growth and Development 8
Development is considered as the sum of growth and differentiation.
Development in plants is under the control of intrinsic and extrinsic factors.

A) Intrinsic factors

  1. Intracellular (genetic)
  2. Intercellular factors (chemicals such as plant growth regulators)

B) Extrinsic factors
Light, temperature, water, oxygen, nutrition, etc.

Plant Growth Regulators

Characteristics
The plant growth regulators (plant hormones or phytohormones) include

  1. Indole compounds (indole-3-acetic acid, IAA);
  2. Adenine derivatives (N6-furfurylamino purine, kinetin),
  3. Derivatives of carotenoids (abscisic acid, ABA);
  4. Terpenes (gibberellic acid, GA3) or
  5. Gases (ethylene, C2H4).

The PGRs are divided into two groups based on their functions in a living plant body.
One group of PGRs are involved in growth-promoting activities, e.g., auxins, gibberellins, and cytokinins.
The other group mainly involved in growth-inhibiting activities such as dormancy and abscission. Eg-abscisic acid and ethylene.
Plus One Botany Notes Chapter 11 Plant Growth and Development 9

The Discovery of Plant Growth Regulators
1. Auxin
At first, Charles Darwin and his son Francis Darwin observed that the coleoptiles of canary grass responded to unilateral illumination by growing towards the light source.
After a series of experiments, it was concluded that the tip of the coleoptile was the site of transmittable influence that caused the bending of the entire coleoptile.
Auxin was isolated by F. W. Went from tips of coleoptiles of oat seedlings.

2. Gibberellin
The ‘balance’ (foolish seedling) disease of rice seedlings, was caused by a fungal pathogen Gibberalla fujikuroi.
In this experiment, the uninfected rice seedlings were treated with sterile filtrates of the fungus. It led to the development of the disease. The active substance was gibberellic acid.
It was demonstrated by E. Kurosawa.

3. Cytokinin
The internodal segments of tobacco stems- the callus proliferated in the presence of auxins along with the extracts of vascular tissues, yeast extract, coconut milk or DNA.
Skoog and Miller later identified and crystallized the cytokinesis promoting active substances that they termed kinetin.

4. Abscisic acid(ABA)
During the mid-1960s inhibitory hormones were identified: inhibitor-B, abscission II and dormin.
Later all the three were named abscisic acid (ABA).

5. Ethylene
Ripened oranges that hastened the ripening of stored unripened bananas. Later this volatile substance was identified as ethylene, a gaseous PGR.

Physiological Effects of Plant Growth Regulators
Auxins
Auxins were first isolated from human urine.
They are generally produced by the growing apices of the stems and roots, from where they migrate to the regions of their action.

Two types of auxins

  1. Natural (IAA and indole butyric acid (IBA)
  2. Synthetic. NAA (naphthalene acetic acid) and 2, 4-D (2, 4-dichlorophenoxyacetic)

Plus One Botany Notes Chapter 11 Plant Growth and Development 10

  1. They help to initiate rooting in stem cuttings
  2. Auxins promote flowering e.g. in pineapples.
  3. They help to prevent fruit and leaf drop at early stages but promote the abscission of older mature leaves and fruits.
  4. In most higher plants, the growing apical bud inhibits the growth of the lateral (axillary) buds, a phenomenon called apical dominance.
  5. Removal of shoot tips (decapitation) usually results in the growth of lateral buds Hence it is widely applied in tea plantations, hedge-making, etc.
  6. Auxins also induce parthenocarpy.
  7. They are widely used as herbicides. 2, 4-D is used to kill dicotyledonous weeds, So it is used to prepare weed-free lawns by gardeners.
  8. Auxin controls xylem differentiation and helps in cell division.

Gibberellins
Gibberellic acid (GA3) was one of the first gibberellins to be discovered and remains the most intensively studied form.
GA3 is acidic.

  1. GA3 causes an increase in the length of grapes stalks. .
  2. Gibberellins, cause fruits like apple to elongate and improve its shape
  3. They delay senescence. Hence the fruits are keeping as fresh.
  4. GA3 is used to speed up the malting process in the brewing industry.
  5. Spraying sugarcane crop with gibberellins increases the length of the stem, thus increasing the yield by as much as 20 tonnes per acre.
  6. Spraying juvenile conifers with GAs hastens the maturity period, thus leading to early seed production.
  7. Gibberellins also promote bolting(internode elongation just prior to flowering) in beet, cabbages and many plants with rosette habit.

Cytokinins
Cytokinins were discovered as kinetin (a modified form of adenine, a purine) from the autoclaved herring sperm DNA.
Naturally occurring cytokinin-zeatin was isolated from corn-kernels and coconut milk.
Natural cytokinins are synthesised in regions where rapid cell division occurs, for example, root apices, developing shoot buds, young fruits, etc.

  1. It helps to produce new leaves, chloroplasts in leaves, lateral shoot growth and adventitious shoot formation.
  2. Cytokinins help to overcome apical dominance.
  3. They promote nutrient mo8/+9bilisation which helps in the delay of leaf senescence.

Ethylene
The most widely used compound as a source of ethylene is ethephon.
It is readily absorbed and transported within the plant and releases ethylene slowly.
Ethephon hastens fruit ripening in tomatoes and apples and accelerates abscission in flowers and fruits

  1. Ethylene is a gaseous hormone that promotes senescence and ripening fruits.
  2. It promotes horizontal growth of seedlings, swelling of the axis, and apical hook formation in dicot seedlings.
  3. Ethylene promotes senescence and abscission of plant organs, especially of leaves and flowers.
  4. Ethylene is highly effective in fruit ripening. It enhances the respiration rate during the ripening of the fruits (respiratory climactic).
  5. Ethylene breaks seed and bud dormancy and initiates germination in peanut seeds, sprouting of potato tubers.
  6. Ethylene promotes rapid internode/petiole elongation in deepwater rice plants.
  7. Ethylene also promotes root growth and root hair formation, thus helping the plants to increase their absorption surface.
  8. Ethylene is used to initiate flowering and fruit-set in pineapples.
  9. It also induces flowering in mango.
  10. It promotes female flowers in cucumbers

Abscisic acid

  1. It promotes abscission and dormancy.
  2. It acts as an inhibitor of plant metabolism.
  3. ABA inhibits seed germination.
  4. ABA stimulates the closure of stomata and increases the tolerance of plants to various kinds of stresses. Hence it is called the stress hormone.
  5. ABA plays an important role in seed development, maturation, and dormancy.
  6. ABA helps the seeds to withstand desiccation
  7. ABA acts as an antagonist to GA3.

Photoperiodism
It is the phenomenon of relative day and night length for the initiation of flowering.
Plus One Botany Notes Chapter 11 Plant Growth and Development 11

Based on the exposure to photoperiod there are three types of plants

  1. Long day plants: They require exposure to light for a period greater than critical duration (12 hr).
  2. Short-day plants: They require less than critical duration before flowering.
  3. Day-neutral plants: In this type, there is no such correlation between exposure to light duration and induction of flowering response.

Which is the organ of a plant perceives light for photoperiodism?
The site of perception of light/dark duration is the leaves. After receiving the required photoperiod, the hormonal substance migrates from leaves to shoot apices for inducing flowering. The shoot apices become changed into flowering apices prior to flowering.

Vernalisation
It is the phenomenon of exposure of low temperature for the initiation of flowering
Some important food plants, wheat, barley, rye have two kinds of varieties: winter and spring varieties.

Nature of spring and winter varieties
The ‘spring’variety are normally planted in the spring and come to flower and produce grain before the end of the growing season.
Winter varieties, planted in spring fail to flower or produce mature grain within a span of a flowering season.
If they are planted in autumn .they germinate and overwinter come out as small seedlings, resume growth in the spring, and are harvested usually around mid-summer.

Biennials and low-temperature treatment
Biennials are monocarpic plants that normally flower and die in the second season. Biennial plants are subjected to a cold treatment, it stimulates photoperiodic flowering response. Sugarbeet, cabbages, carrots are some of the common biennials.

NCERT Supplementary Syllabus

Seed Germination
The seeds germinate under favourable conditions after the period of dormancy.
After dormancy embryo becomes metabolically active and starts growing. This process is known as seed germination.
The conditions necessary for seed germination are the availability of water and oxygen.

A physiological phenomenon in seed germination
The physical phenomenon associated with seed germination is imbibition. It causes the swelling of seed then rupturing of the seed coat, through which radical emerges out.
It develops into a root system but the shoot system arises from the plumule of another end of the embryonal axis.
The metabolic activities require oxygen for breaking down the food reserves such as polysaccharides, proteins and lipid.
It is converted into soluble materials with the help of enzymes and mobilized to the embryonal axis.
The growth of radical and plumule is due to cell extension, cell division, and several biochemical processes.
The seed also needs a suitable temperature (optimum between 25 to35). The rate of respiration increases rapidly during seed germination.

What is the Viviparous type of germination?
Vivipary is the germination of a seed while it is still attached to the parent plant and is nourished by it. The plants grow in marshy land such as Rhizophora and Sonneratia (halophytes)show this type of germination.
During germination, radical elongates, and the weight of the germinating seed increases. As a result, the seedling separates and fail down vertically into the mud and grow into a new plant.

Seed Dormancy
It is the period of rest or a period of suspended growth due to this

  1. water content, the metabolic activities become extremely low.
  2. the seed coat becomes impermeable to oxygen and moisture and hardens.

The suspension of growth is due to exogenous (environmental conditions) or endogenous control during which metabolic activity of the seed is greatly reduced.

Causes of Dormancy

  1. Impermeable or mechanically resistant seed coats.
  2. Rudimentary or physiologically immature embryos or
  3. Due to the presence of germination inhibitors such as abscisic acid, phenolic acid, short-chain fatty acids, and coumarin.

How can overcome seed dormancy?

  1. Mechanical or chemical scarification of the seed coat (scratching of seed coat or seeds soaked in chemicals to break the dormancy)
  2. Stratification of seeds or changing environmental conditions such as temperature, light, and pressure. Stratification of seeds is subjecting the moist seeds to oxygen for variable periods of low or high temperatures.

Plus One Botany Notes Chapter 10 Respiration in Plants

Students can Download Chapter 10 Respiration in Plants Notes, Plus One Botany Notes helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus One Botany Notes Chapter 10 Respiration in Plants

How are respiration and photosynthesis-related?
Green plants and cyanobacteria can prepare their own food by the process of photosynthesis, they trap light energy and convert it into chemical energy that is stored in the bonds of carbohydrates (Macromolecules) like glucose, sucrose, and starch.
By Cellular respiration, food materials undergo breakdown that release energy and the trapping of this energy for the synthesis of ATP.

ATP is called the energy currency of the cell why?
ATP is broken down whenever (and wherever) energy needs to be utilised. Hence, ATP acts as the energy currency of the cell.

Seat of photosynthesis and respiration
Photosynthesis takes place within the chloroplasts whereas the breakdown of complex molecules to yield energy takes place in the cytoplasm and in the mitochondria (also only in eukaryotes).
The compounds that are oxidized during respiration are known as respiratory substrates.
Eg. Proteins, fats, and even organic acids.

Do Plants Breathe?
Plants require O2 for respiration and give out CO2 and H2O as end products and release energy most of which is given out as heat.

Respiration is least important to plants than animals
Roots, stems, and leaves respire at rates far lower than animals When cells photosynthesize O2 is released within the cell.
But some cells live where oxygen may or may not be available.
All living organisms retain the enzymatic machinery to partially oxidise glucose without the help of oxygen. This breakdown of glucose to pyruvic acid is called glycolysis.

Glycolysis
The term glycolysis -(Greek words, glycols for sugar, and lysis for splitting).
The scheme of glycolysis was given by Gustav Embden, Otto Meyerhof, and J. Parnas, Hence glycolysis is called an EMP pathway.
In anaerobic organisms, it is the only process in respiration.
Glycolysis occurs in the cytoplasm of the cell and is present in all living organisms.
In this process, Glucose undergoes partial oxidation to form two molecules of pyruvic acid.

Steps lead to end products of glycolysis
Plus One Botany Notes Chapter 10 Respiration in Plants 1
1. Glucose and fructose are phosphorylated to give rise to glucose-6-phosphate by the activity of the enzyme hexokinase.

2. This phosphorylated form of glucose then isomerises to produce fructose-6-phosphate.

3. In this pathway, ATP is utilised at two steps: first in the conversion of glucose into glucose 6-phosphate and second in the conversion of fructose 6-phosphate to fructose 1,6 diphosphate).

4. The fructose 1,6-diphosphate is split into dihydroxyacetone phosphate and 3 phosphoglyceraldehydes (PGAL). In this step NADH +H+ is formed from NAD+.

5. 3-phosphoglyceraldehyde (PGAL) is converted to 1,3 bisphosphoglycerate (DPGA).

6. The conversion of DPGA to 3-phosphoglyceric acid (PGA), is also an energy-yielding process; this energy is trapped by the formation of ATP.

7. 3-phosphoglyceric acid (PGA) is converted into 2 phosphoglycerates.

8. 2 phosphoglycerates are converted into 2 phosphoenol pyruvic acid. ATP is synthesized during the conversion of PEP to pyruvic acid.

9. 2 phosphoenol pyruvic acid undergoes dephosphorylation to form 2 molecule of pyruvic acid

The fate of pyruvic acid
It involves

  1. Lactic acid fermentation
  2. Alcoholic fermentation
  3. Aaerobic respiration.

Fermentation takes place under anaerobic conditions in many prokaryotes and unicellular eukaryotes.

The complete oxidation of glucose to CO2 and H2O occurs in organisms that adopt Krebs’ cycle which is also called as aerobic respiration. This requires an O2 supply.

Fermentation
In fermentation, glucose undergoes incomplete oxidation and forms CO2 and ethanol
The enzymes, pyruvic acid decarboxylase, and alcohol dehydrogenase catalyze these reactions.
Fermentation occurs in the presence of yeast
Yeasts poison themselves to death when the concentration of alcohol reaches about 13 percent. Some organisms like bacteria produce lactic acid from pyruvic acid.

The lactic acid in eukaryotic cell
In animal muscle cells during exercise, when oxygen is inadequate for cellular respiration, pyruvic acid is reduced to lactic acid by lactate dehydrogenase.
The reducing agent is NADH+H* which is re oxidised to NAD+ in both the processes.
In both lactic acid and alcohol fermentation, less than seven percent of the energy in glucose is released.
In eukaryotes second step after glycolysis take place within the mitochondria and this requires O2.
It is aerobic respiration leads to complete oxidation of carbohydrate in the presence of oxygen and releases CO2, water and a large amount of energy.
This type of respiration is most common in higher organisms.

Aerobic Respiration
The second step of Aerobic respiration takes place within the mitochondria.
The product of glycolysis- pyruvate is transported from the cytoplasm into the mitochondria.
Plus One Botany Notes Chapter 10 Respiration in Plants 2

First step of oxidation of pyruvic acid
In the mitochondrial matrix, pyruvate undergoes oxidative decarboxylation by pyruvic dehydrogenase. The reactions require the participation of several coenzymes, including NAD+ and Coenzyme A.
Plus One Botany Notes Chapter 10 Respiration in Plants 3

During this process, two molecules of NADH are produced from the metabolism of two molecules of pyruvic acid.
The acetyl CoA then enters a cyclic pathway, tricarboxylic acid cycle(Krebs’ cycle) after the scientist Hans Krebs who first elucidated it.

Tricarboxylic Acid Cycle
The TCA cycle starts with the condensation of acetyl group with oxaloacetic acid (OAA) and water to yield citric acid.
The reaction is catalysed by the enzyme citrate synthase and a molecule of CoA is released.
It is followed by two successive steps of decarboxylation, leading to the formation of alpha-ketoglutaric acid and then succinyl-CoA. In the remaining steps, Succinic acid is oxidised to OAA.
Plus One Botany Notes Chapter 10 Respiration in Plants 4

Which step of the Krebs cycle substrate-level phosphorylation occurs?
During the conversion of succinyl-CoA to succinic acid, a molecule of GTP is synthesised. This is substrate-level phosphorylation.

At three sites in the cycle where NAD+ is reduced to NADH + H+ and one site where FAD+ is reduced to FADH2.
Plus One Botany Notes Chapter 10 Respiration in Plants 5
In the mitochondrial matrix, pyruvate is broken down to release.
8 molecules of NADH + H+
2 molecules of FADH2
2 molecules of GTP and
3 molecules of CO2

Electron Transport System (ETS) and Oxidative Phosphorylation
Plus One Botany Notes Chapter 10 Respiration in Plants 6
The metabolic pathway through which the electron passes from one carrier to another is called the electron transport system (ETS).
It is present in the inner mitochondrial membrane.
Reduced coenzyme like NADH(complex) in the mitochondrial matrix is oxidised and release 2 electrons and 2protons
Electrons and protons are transferred to FMN, it reduced to FMNH2
It breaks and releases protons and electrons .protons go to intermembrane space but electrons reach ubiquinone.
Ubiquinone also receives reducing equivalents via FADH2 (complex II).
The reduced ubiquinone is then oxidised with the transfer of electrons to cytochrome c via cytochrome bc1 complex (complex III).

Electron Transport System (ETS)
Cytochrome c acts as a mobile carrier for the transfer of electrons between complex III and IV.
Complex IV refers to cytochrome c oxidase complex containing cytochromes a and a3.

Oxidation of one molecule of NADH gives rise to 3 molecules of ATP, while that of one molecule of FADH2 produces 2 molecules of ATP.
Oxygen acts as the final hydrogen acceptor.

Oxidative phosphorylation in mitochondria
In ETS the energy of oxidation-reduction is utilised for the production of proton gradient required for phosphorylation. This process is called oxidative phosphorylation.

Chemiosmosis (proposed by peter Mitchel)
The energy released during the electron transport system is utilised in synthesizing ATP with the help of ATP synthase (complex V) called chemiosmosis.
Plus One Botany Notes Chapter 10 Respiration in Plants 7
F1 – F0/exosomes
This complex consists of two major components, F1 and Fo.
The F1 headpiece is a site for synthesis of ATP from ADP and inorganic phosphate.
F0 is an integral membrane protein complex act as a channel through which protons cross the inner membrane.
For each ATP produced, 2H+ passes through F0 from the intermembrane space to the matrix down the electrochemical proton gradient.

The Respiratory Balance Sheet
How many ATP molecules are produced in Aerobic respiration?
In aerobic respiration, the number of ATP molecules produced or utilized in glycolysis, TCA cycle and ETS gives the net gain of 36 ATP molecules
Fermentation accounts for only a partial breakdown of glucose whereas in aerobic respiration it is completely degraded to CO2 and H2O.

How many ATP molecules are produced in Fermentation?
In fermentation there is a net gain of only two molecules of ATP for each molecule of glucose degraded NADH is oxidized to NAD+ rather slowly in fermentation.

Amphibolic Pathway
It involves two processes anabolism and catabolism.
For example, fats is broken down into glycerol and fatty acids. Then fatty acids degraded to acetyl CoA and enter the pathway.
Glycerol enters the pathway after being converted to PGAL.
The proteins are degraded by proteases and the individual amino acids enter the pathway at some stage within the Krebs’cycle as pyruvate or acetyl CoA.

Is it true both catabolism and anabolism occur in fat metabolism?
Fatty acids( substrate) are broken down to acetyl CoA before entering the respiratory pathway. But when the organism needs to synthesize fatty acids, acetyl CoA withdrawn from the respiratory pathway for it.
Hence, the respiratory pathway involves the breakdown and synthesis of fatty acids, i.e catabolism, and anabolism respectively. Hence it is considered as an amphibolic pathway.
Plus One Botany Notes Chapter 10 Respiration in Plants 8

Respiratory Quotient
Definition: The ratio of the volume of CO2 evolved to the volume of O2 consumed in respiration is called the respiratory quotient (RQ) or respiratory ratio.
Plus One Botany Notes Chapter 10 Respiration in Plants 9

Respiratory quotient of some respiratory substrates
1. Carbohydrates: When carbohydrates are completely oxidised, the RQ is 1, because equal amounts of CO2 and O2 are evolved and consumed, respectively
Plus One Botany Notes Chapter 10 Respiration in Plants 10

2. Fats: If fats are used in respiration, the RQ is less than 1.
Plus One Botany Notes Chapter 10 Respiration in Plants 11

3. Proteins: When proteins are respiratory substrates the ratio is 0.9.

4. Organic acids: When organic acids are respiratory substrates, the ratio is more than one.

Plus One Botany Notes Chapter 9 Photosynthesis in Higher Plants

Students can Download Chapter 9 Photosynthesis in Higher Plants Notes, Plus One Botany Notes helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus One Botany Notes Chapter 9 Photosynthesis in Higher Plants

What Do We Know?
Role of light, CO2, H2O, and Chlorophyll
Actually, chlorophyll (green pigment of the leaf), light, and CO2 are required for photosynthesis. A variegated leaf ora leaf that was partially covered with black paper, and one that was exposed to light. On testing these leaves for starch it was clear that photosynthesis occurred only in the green parts of the leaves in the presence of light.

Half leaf experiment and the importance of CO2 in photosynthesis
In this, a part of a leaf is enclosed in a test tube containing some KOH soaked cotton (which absorbs CO2), while the other half is exposed to air. The set up is then placed in light for some time. Then conducted the starch test, showed that the exposed part of the leaf tested positive for starch while the portion that was in the tube, tested negative. This showed that CO2 is required for photosynthesis.

Early Experiments

Historical aspects of photosynthesis
1. Priestley
He observed that a candle burning in a closed space – a bell jar, soon gets extinguished. Similarly, a mouse would soon suffocate in a closed space.
Plus One Botany Notes Chapter 9 Photosynthesis in Higher Plants 1
He concluded that a burning candle or an animal that breathes the air, both damage the air. But when he placed a mint plant in the same bell jar, he found that the mouse stayed alive and the candle continued to burn.
Plus One Botany Notes Chapter 9 Photosynthesis in Higher Plants 2

2. Jan Ingenhousz
He showed that sunlight is essential to the plant process that purifies the air fouled by burning candles or breathing animals. In aquatic habitat, during bright sunlight, small bubbles were formed around the green parts while in the dark they did not. Later he identified these bubbles are oxygen. So the green part of the plants could release oxygen.

3. Julius von Sachs
Glucose is usually stored as starch. He found that the green parts in plants where glucose is made.

4. T.W Engelmann
By using a prism he split light into its spectral components and then illuminated a green alga, Cladophora, placed in a suspension of aerobic bacteria. The bacteria were used to detect the sites of O2 evolution. He observed that the bacteria accumulated mainly in the region of blue and red light of the split spectrum.

An empirical equation for photosynthesis
Plus One Botany Notes Chapter 9 Photosynthesis in Higher Plants 3
[CH2O] represent a carbohydrate (e.g., glucose, a six-carbon sugar).

Hydrogen donor in bacteria and green plants
Some organisms do not release O2 during photosynthesis
When H2S, instead is the hydrogen donor for purple and green sulphur bacteria, the ‘oxidation’ product is sulphur or sulphate depending on the organism and not O2. In the green plants, the O2 evolved from H2O, not from carbon dioxide.

The modern equation for photosynthesis
Plus One Botany Notes Chapter 9 Photosynthesis in Higher Plants 4
C6H12O6 represents glucose. The O2 released is from water

Where Does Photosynthesis Take Place?
It takes place in the chloroplast of leaves that contain grana, the stroma lamellae, and the fluid stroma.

Where is the energy production site in chloroplast?
The energy-rich molecules like ATP and NADPH are synthesized in grana and stroma lamellae by light reactions.

Where is the Glucose production site in chloroplast?
In stroma by dark reactions, CO2 fixation leading to the synthesis of glucose, which in turn forms starch

Structure of chloroplast
Plus One Botany Notes Chapter 9 Photosynthesis in Higher Plants 5
Diagrammatic representation of an electron micrograph of a section of chloroplast

How Many Pigments are Involved in Photosynthesis?
Chromatographic separation of the leaf pigments shows that different types of pigments in leaves i.e
Chlorophyll a (bright or blue-green in the chromatogram)
chlorophyll b (yellow-green)
xanthophylls (yellow)
carotenoids (yellow to yellow-orange)

a) Graph showing the absorption spectrum of chlorophyll a, b, and the carotenoids.
Plus One Botany Notes Chapter 9 Photosynthesis in Higher Plants 6
b) Graph showing the action spectrum of photosynthesis.
Plus One Botany Notes Chapter 9 Photosynthesis in Higher Plants 7
c) Graph showing action spectrum of photosynthesis superimposed on the absorption spectrum of chlorophyll a.
Plus One Botany Notes Chapter 9 Photosynthesis in Higher Plants 8

Wavelengths of light absorbed by pigments
Chlorophyll pigments absorb light, at specific wavelengths of blue and the red regions while carotenoids absorb the blue and green wavelength
Chlorophyll is the major pigment responsible for trapping light, other thylakoid pigments like chlorophyll b, xanthophylls, and carotenoids, which are called accessory pigments, also absorb light and transfer the energy to chlorophyll a. but also protect chlorophyll a from photo-oxidation.

What is Light Reaction?
It is the photochemical phase include

  1. light absorption
  2. water splitting
  3. oxygen release
  4. Formation of high-energy rich molecules ATP and NADPH.

The pigments are organised into two light-harvesting complexes(LHC)

  1. Photosystem I (PS I)/P700
  2. Photosystem II (PS II)/P680

Each photosystem has single chlorophyll a molecule forms the reaction centre, all the pigments except chlorophyll-a forming a light-harvesting system also called antennae.

In PS I the reaction centre, chlorophyll a has an absorption peak at 700 nm while in PS II it has absorption maxima at 680 nm, and is called P680.
Plus One Botany Notes Chapter 9 Photosynthesis in Higher Plants 9

The Electron Transport
How does electron flow in electron carriers that connect two photosystems?
Initially, excitation of chlorophyll molecule occurs due to light, then electrons are emitted from Ps II (uphill) that are accepted by electron acceptor, electron flows through electron carriers cytochromes, (downhill) and (Loss of electrons of PSII is compensated by electrons coming from water and loss of electrons of PS I is compensated by electrons coming from PS II).
Plus One Botany Notes Chapter 9 Photosynthesis in Higher Plants 10
PS I is also excited due to light and electrons are emitted (uphill), it transfers an electron to another accepter, and finally down the hill to NADP+ causing it to be reduced to NADPH + H+ is called the Z scheme.

Result of Z-scheme

  1. production of ATP and NADPH
  2. O2 evolution

Splitting of Water
Photolysis
It is the splitting of water into H+, [O] and electrons in the presence of light and these electrons are available to PSII.
This process takes place on the inner side of the membrane of the thylakoid.
Oxygen released is one of the net products of photosynthesis.
2H2O → 4H+ + O2 + 4e

Cyclic and Non-cyclic Photo-phosphorylation
Phosphorylation
The process of which ATP from ADP and inorganic phosphate in the presence of light (in mitochondria and chloroplasts) is named phosphorylation.

Electron in a cyclic process
When only PS I is functional, the cyclic flow of electrons within the photosystem and the phosphorylation occurs in the stroma lamellae.
Cyclic photophosphorylation also occurs when only light of wavelengths beyond 680 nm are available for excitation i.e at 700 nm
Plus One Botany Notes Chapter 9 Photosynthesis in Higher Plants 11

Result of cyclic photophosphorylation
ATP is produced.

Where does the light-harvesting complex work for acyclic and noncyclic processes?
The membrane or lamellae of the grana have both PS I and PS II so a noncyclic process occurs,
The stroma lamellae membranes lack PS II as well as NADP reductase enzyme So a cyclic process occurs.

Chemiosmotic Hypothesis
It is the ATP synthesis linked to the development of a proton gradient across a membrane
In chloroplast, the proton accumulation is towards the inside of the membrane, i.e., in the lumen. In respiration, protons accumulate in the intermembrane space of the mitochondria when electrons move through the ETS.
The proton gradient develops due to,

a. Splitting of the water molecule takes place on the inner side of the membrane, the protons accumulate within the lumen of the thylakoids

b. As electrons move through the photosystems, protons are transported across the membrane moves into the lumen side of the membrane

c. The NADP reductase enzyme is located on the stromal side of the membrane. Along with electrons that come from the accepter of electrons of PS I, protons are necessary for the reduction of NADP+ to NADPH+ H+. These protons are also removed from the stroma.

In chloroplast, protons in the stroma decrease in number, while in the lumen there is an accumulation of protons. This creates a proton gradient across the thylakoid membrane The gradient is broken down due to the movement of protons across the membrane to the stroma through the transmembrane channel of the F0 of the ATP.
ATPase have a channel that allows diffusion of protons back across the membrane; this releases enough energy to activate the ATPase enzyme that catalyses the formation of ATP.
Plus One Botany Notes Chapter 9 Photosynthesis in Higher Plants 12
Where are the ATP and NADPH Used?
It is used in the biosynthetic phase of photosynthesis. This process does not directly depend on the presence of light but is dependent on the products of the light reaction, i.e., ATP and NADPH.
Melvin Calvin studied the algal photosynthesis by using radioactive 14C led to the discovery that the first CO2 fixation product was identified as 3-phosphoglyceric acid or PGA.

The Primary Acceptor of CO2
The studies showed that the accepter molecule was a 5-carbon sugar -ribulose bisphosphate (RuBP) in the Calvin cycle.

The Calvin Cycle
It involves three stages:

  1. carboxylation
  2. reduction
  3. regeneration

1. Carboxylation:
Carboxylation is the fixation of CO2 into a stable compound catalysed by the enzyme RuBisCO that results in the formation of two molecules of 3-PGA.

2. Reduction: These are a series of reactions that lead to the formation of glucose.
The steps involve the utilization of 3 molecules of ATP for phosphorylation and two NADPH for reduction per CO2 molecule fixed. For the fixation of six molecules of CO2, 6 turns of the cycle are required and one molecule of glucose is generated

3. Regeneration: Regeneration of the CO2 acceptor molecule require one ATP for phosphorylation to form RuBP.
Hence for every CO2 molecule entering the Calvin cycle, 3 molecules of ATP and molecules of NADPH are required
Plus One Botany Notes Chapter 9 Photosynthesis in Higher Plants 13
The Calvin cycle proceeds in three stages:
1. carboxylation, during which CO2 combines with ribulose- 1, 5- bisphosphate
2. reduction, during which carbohydrate is formed at the expenses of the photochemically made ATP and NADPH; and
3. regeneration during which the CO2 acceptor ribulose- 1, 5-bisphosphate has formed again so that the cycle continues
Plus One Botany Notes Chapter 9 Photosynthesis in Higher Plants 14

The C4 Pathway (Hatch and Slack Pathway)
Plants that are adapted to dry tropical regions have the C4 pathway, C4 plants have a special type of leaf anatomy. They tolerate higher temperatures. They lack a process called photorespiration and have greater productivity of biomass.

Special leaf anatomy-kranz anatomy
Large cells around the vascular bundles are centripetally arranged bundle sheath cells such anatomy is called ‘Kranz’ anatomy. Eg- maize or sorghum

Primary CO2, accepter, first stable product and Enzyme of C4 Pathway
The primary CO2 acceptor is a 3-carbon molecule- phosphoenolpyruvate (PEP) present in the mesophyll cells. The enzyme responsible for this fixation is PEP carboxylase or PEPcase.
The first stable product C4 acid OAA is formed in the mesophyll cells.
Plus One Botany Notes Chapter 9 Photosynthesis in Higher Plants 15
Diagrammatic representation of a Hatch arid Slack Pathway
OAA converted into 4-carbon compounds like malic acid or aspartic acid in the mesophyll cells .which are transported to the bundle sheath cells. In the bundle sheath cells, these C4 acids are broken down to release CO2 and a 3-carbon molecule. The 3-carbon molecule is transported back to the mesophyll where it is converted to PEP again, thus, completing the cycle.
Thus the basic pathway that results in the formation of the sugars, the Calvin pathway, is common to the C3 and C4 plants.

Photorespiration
In C3 plants, under high concentration of O2 and low CO2 concentration, RUBP binds with O2 to form one molecule of PGA and phosphoglycolate and a large quantity of CO2 is released.

Can you say photorespiration is a wasteful process?
This process utilise ATP but neither synthesis of sugars, nor of ATP. Hence photorespiration is a wasteful process.
Plus One Botany Notes Chapter 9 Photosynthesis in Higher Plants 16

The specialty of C4 plants to avoid Photorespiration
In C4 plants photorespiration does not occur because C4 acid from the mesophyll is broken down in the bundle cells to release CO2 – this results in increasing the intracellular concentration of CO2. Here RuBisCO functions as a carboxylase minimizing the oxygenase activity, productivity, and yields are better in these plants.

Factors Affecting Photosynthesis
Photosynthesis is influenced by several factors, both internal (plant) and external. The plant factors include the number, size, age, and orientation of leaves, mesophyll cells and chloroplasts, internal CO2 concentration, and the amount of chlorophyll. The external factors include the availability of sunlight, temperature, CO2 concentration, and water.

Blackman s Law of Limiting Factors
If a chemical process is affected by more than one factor, then its rate will be determined by the factor which is nearest to its minimal value: it is the factor that directly affects the process if its quantity is changed.
For example, In the green leaf, the light and CO2 conditions are optimum but the plant does not photosynthesize if the temperature is very low.

Light
The availability of light shows a direct relationship with CO2 fixation rates at low light intensities At higher light intensities the rate does not show further increase because other factors are not in optimal amount. The intensity of light beyond a point causes the breakdown of chlorophyll and a decrease in photosynthesis.
Plus One Botany Notes Chapter 9 Photosynthesis in Higher Plants 17

Carbon dioxide Concentration
The concentration of CO2 is very low in the atmosphere (between 0.03 and 0.04 percent). An increase in concentration up to 0.05 percent can cause an increase in CO2 fixation rates. The C3 and C4 plants respond differently to CO2 concentrations.

Graph of light Intensity on the rate of photosynthesis

C4 plants show saturation at about 360µL-1 while C3 responds to increased CO2 concentration and saturation is seen only beyond 450µL-1 Thus, the current availability of CO2 levels is limiting to the C3 plants.

C3 plants respond to higher CO2 concentration by showing increased rates of photosynthesis leading to higher productivity The above concept is used for some greenhouse crops such as tomatoes and bell pepper.

Temperature
The dark reactions that take place in stoma are enzymatic and temperature controlled. C4 plants respond to higher temperatures and show a higher rate of photosynthesis while C3 plants have a much lower temperature optimum.

Water
Water stress causes the closure of stomata and it is difficult to receive CO2 for photosynthesis. The stress condition also makes leaves wilt and reducing the surface area of the leaves and their metabolic activities.