Plus Two Computer Application Chapter Wise Previous Questions Chapter 7 Web Hosting

Kerala State Board New Syllabus Plus Two Computer Application Chapter Wise Previous Questions and Answers Chapter 7 Web Hosting.

Kerala Plus Two Computer Application Chapter Wise Previous Questions Chapter 7 Web Hosting

Plus Two Computer Application Web Hosting 1 Mark Important Questions

Question 1.
Identify the odd : (MARCH-2016)
Answer:
a) Word Press
b) FileZilla
c) Joomal
d) Drupal

Question 2.
______ provides an easy way to design and manage attractive websites. (MAY-2016)
a) free hosting
b) CMS
c) WHOIS
d) FTP
Answer:
b)CMS

Plus Two Computer Application Web Hosting 2 Marks Important Questions

Question 1.
What type of homing package is suitable for a multinational online shopping site? Mention any two advantages of the package. (MARCH-2016)
Answer:
Dedicated hosting
a) Dedicated Hosting
b) A web server and its resources are exclusively for one website that has a large volume of traffic means a large volume of requests by visitors. Some Govt, departments or large organizations require uninterrupted services for that round the clock power supply is needed. It is too expensive but it is more reliable and provides good service to the public.
Eg : It is similar to living in an Our own house. All the resources in your house are only for you. No one else’s account resides on the computer and would not be capable of tapping into your resources.

Question 2.
What is SFTP? (MAY-2016)
Answer:
FTP (File Transfer Protocol) client software
When a client requests a website by entering the website address. Then FTP client software helps to establish a connection between the client computer and the remote server computer. Unauthorised access is denied by using user name and password hence secure our website files for that SSH(Secure Shell) FTP simply SFTP is used. Instead of http://, it uses ftp://.
By using FTP client s/w we’ can transfer(upload) the files from our computer to the web server by using the ‘drag and drop’ method. The popular FTP client software is FileZilla, CuteFTP, SmartFTP, etc.

Question 3.
Differentiate shared and dedicated web hosting. (MAY-2017)
Answer:

Shared Dedicated
The resources areThe resources are
sharednot shared
Suitable for smallSuitable for websites
websites with lesswith large volume of
traffictraffic
It is cheapIt is highly expensive
It is slowerIt is faster

Plus Two Computer Application Web Hosting 3 Marks Important Questions

Question 1.
What is the need of registering a domain name for a website? Explain the procedure of domain name registration. (MARCH-2016)
Answer:
Millions of websites are available over the Internet so that our website must be registered with a suitable name. Domain Name registration is used to identify a website over the Internet. A domain name must be unique(i.e. no two websites with the same name are available). So you have to check the availability of do¬main name before you register it, for this will help. If the domain name entered is available then we can register it by paying the Annual registration fees online. Consider a Post Office, it has two addresses one string address (Irinjalakuda) and one numeric(pin) code (680121). Just like this, the website has also two addresses a string address for example www.agker.cag.gov.in, and a numeric address (http:/ /210.212.239.70/). We are following a string address, hence this domain name has to be connected to the corresponding IP address of the webserver. This is done by using ‘A record’(Address record) of the domain. ‘A record’ is used to store the IP address and the corresponding domain name.

Question 2.
Compare shared hosting and VPS. (MAY-2016)
Answer:
Types of web hosting: Various types of web hosting services are available. We can choose the web hosting services according to our needs depends upon the storage space needed for hosting, the number of visitors expected to visit, etc.

1) Shared Hosting: This type of hosting shares resources, like memory, disk space, and CPU hence the name shared. Several websites share the same server. This is suitable for small websites that have less traffic and it is not suitable for large websites that have large bandwidth, large storage space, and have a large volume of traffic.
Eg: Shared hosting is very similar to living in an Apartment(Villas) complex. All residents are in the same location and must share the available resources(Car parking area, Swimming pool, Gymnasium, playground, etc) with everyone.

2) Dedicated Hosting: A web server and its resources are exclusively for one website that has a large volume of traffic means a large volume of requests by the visitors. Some Govt, departments, or large organizations require uninterrupted services for that round the clock power supply is needed. It is too expensive but it is more reliable and provides good service to the public.
Eg: It is similar to living in an Our own house. All the resources in your house is only for you. No one else’s account resides on the computer and would not be capable of tapping into your resources.

3) Virtual Private Server (VPS): A VPS is a virtual machine sold as a service by an Internet hosting Service. A VPS runs its own copy of an OS (Operating System) and customers have super level access to that OS instance, so they can install almost any s/w that runs on that OS. This type is suitable for websites that require more features than shared hosting but less features than dedicated hosting.
Eg: It is similar to owning a Condo

Question 3.
Amita wanted to get the name ‘www. smartproducts.com’ for her newly designed website. How it is possible? (MARCH-2017)
Answer:
Millions of websites are available over the Internet so that our website must be registered with a suitable name. Domain Name registration is used to identify a website over the Internet. A domain name must be unique (i.e. no two websites with the same name is available). So you have to check the availability of the domain name before you register it, for this www.whois.net website will help. If the domain name entered is available then we can register it by paying the Annual registration fees online.

Question 4.
Ajith created a website using the software ‘Joomla’. What is the peculiarity of this software and write any four advantages of using this software? (MARCH-2017)
Answer:
Joomla is an example of a Content Management System.CMS is a collection of programs that are used to create, modify, update, and publish website content. CMS can be downloaded freely and is useful to design and manage attractive and interactive websites with the help of templates that are avail¬able in CMS. WordPress, Joomla, etc are examples of CMS.

Question 5.
Explain responsive web design. (MAY-2017)
Answer:
The home page is displayed differently according to the screen size of the browser window(different screen sized devices -mobile phone, palmtop, tablet, laptop, and desktop) we used. The website is designed dynamically(flexibly) that suit the screen size of a different device introduced by Ethan Marcotte. Before this, companies have to design different websites for different screen sized devices. By responsive web design, companies have to design only one website that suitably displayed according to the screen size of the devices.
It is implemented by using a flexible grid layout, images, and media queries.

Plus Two Computer Application Chapter Wise Previous Questions Chapter 6 Client-Side Scripting Using Java Script

Kerala State Board New Syllabus Plus Two Computer Application Chapter Wise Previous Questions and Answers Chapter 6 Client-Side Scripting Using Java Script.

Kerala Plus Two Computer Application Chapter Wise Previous Questions Chapter 6 Client-Side Scripting Using Java Script

Plus Two Computer Application Client-Side Scripting Using Java Script Using HTML 3 Marks Important Questions

Question 1.
Develop a webpage to display the following login screen. (MARCH-2016)
Plus Two Computer Application Chapter Wise Previous Questions Chapter 6 Client-Side Scripting Using Java Script 1
Write JavaScript do the following validation:
a) The application number should be int he ranges 10000 to 99999
b) The password should contain atleast 8 characters.
Answer:
<html>
<head>
<title>
Javascript – login
</title>
<script language =”Javascript”>
function showValid ( )
{
var appno,pas;
appno=document. frmlogin.txtappno. value;
pas=document.frmlogin.txtpass. value;
if (appno<10000|| appno>99999)
{
alert (“The number should be in the range 10000 to 99999. Try again”);
return;
}
if (pas.length <8)
{
alert (” The password must contain atleast 8 characters. Try again”);
return;
}
</SCRIPT>
</HEAD>
<Body bgcolor = “Cyan”>
<Form Name = “frmlogin”>
<Center>
Application No.
<inputtype= “text” name = “txtappno”>
<br> <br> password
<input type = “password” Name = “txtpass”> <br> <br>
<input type= “button” value = “show” onClick = “showValid()”>
</center>
</Form>
</body>
</html>

Question 2.
Design the following web page enter the mark of a student: (MAY-2016)
Plus Two Computer Application Chapter Wise Previous Questions Chapter 6 Client-Side Scripting Using Java Script 2
a) Write HTML code forthe website.
b) Provide validations for the text box using JavaScript. The mark should be in the range of 0 to 100 and should up a number. The text box should not be empty.
Answer:
<html>
<head>
<title>
student details
</title>
<SCRIPT Language=”JavaScript”>
function showValid()
{
varmark;
mark=document.frmcheck.txtmark.value;
if(mark<0 || mark >100)
{
alert(“The mark should be in the range 0 to 100”);
return;
}
if (isNaN(mark))
{
alert (“The mark should be a number”);
return;
}
if(mark == ” “)
{
alert (“please enter a valid mark”); return;
}
}
</SCRIPT>
<BODY BGLOLOR= “Red”>
<Form Name = “frmcheck”>
<Center>
Mark
<input type= “text” name = “txtmark”>
<br><br>
<input type= “button” Value= “Check” onClick=”showValid ( )”>
</center>
</FORM>
</body>
</htm>

Question 3.
Develop a webpage to display the following screen: (MARCH-2017)
Plus Two Macroeconomics Chapter Wise Previous Questions Chapter 6 Open Economy Macroeconomics 11
The user can enter a name in the textbox. On checking the ‘show’ button the name entered in the textbox should be changed into uppercase. Include JavaScript code in the HTML for doing this.
Answer:
<HTML>
<head>
<title>
check
</title>
<SCRIPT Language=”JavaScript”>
function convert( )
{
var str1
str1=document.frmconvert.txtname.value;
document.fimconvert.txtname.value=str1.toUpperCase( );
}
</SCRIPT>
<BODY>
<form name=”frmconvert”>
Enter Name
<input type=”text” name=”txtname”>
<br>
<br>
<inputtype=”button” value=”show” onClick-’convert( )”> </form>
</BODY>
</HTML>

Question 4.
Write a JavaScript which inputs the name, rollno, and date of birth of a student. Date of birth contains month, day and year. The month should be selected from a drop-down list. (MAY-2017)
Answer:
<html>
<head>
<Script Language=”JavaScript”>
function get( )
{
}
</Script>
</head>
</body bgcolor=”cyan”>
<form name=”frm”>
Enter your name
<input type=”text” name=”txtname”>
<br>
Enter your rollno
<input type=”text”name=”txtroll”>
<br>
Entr your Date of Birth
<br>
Day
<input type=”text” name=”txtroll”>
month
<select size=”1″ name=”cbomth”>
<option>January</option>
<option>Februry</option>
<option>March</option>
<option>April</option>
<option>May</option>
<option>June</option>
<option>July</option>
<option>August</option>
<option>September</option>
<option>October</option>
<option>November</option>
<option>December</option>
</select>
Year
<input type=”text” name=”txtyr”>
<br>
<input type=”button” value=”submit”
onClick=”get( )”>
</form>
</body>
</html>

Plus Two Computer Application Chapter Wise Previous Questions Chapter 5 Web Designing Using HTML

Kerala State Board New Syllabus Plus Two Computer Application Chapter Wise Previous Questions and Answers Chapter 5 Web Designing Using HTML.

Kerala Plus Two Computer Application Chapter Wise Previous Questions Chapter 5 Web Designing Using HTML

Plus Two Computer Application Web Designing Using HTML 1 Mark Important Questions

Question 1.
Write HTML tag to set the colour of hyperlink to red. (MARCH-2016)
a) < A colour=”red”?
b) <A colour=”#FF0000″>
c) <BODY LINK = “Red”>
d) <BODYALINK-‘Red”>
Answer:
c) <BODY LINK= “Red”>

Question 2.
Consider the following list created using HTML. (MARCH-2016)
D. Laptop
E. Desktop
F. Printer
a) START= “D” TYPE = “A”
b) START =”4″ TYPE = “A”
c) START = “4” TYPE = “I”
d) START = “D” TYPE =”l”
Answer:
d) START = “D” TYPE =”l”

Question 3.
Nila wanted to set the picture “sky.jpg” as the background of his web page. Choose the correct tag for doing this. (MAY-2016)
IMG SRC = “sky.jpg”>
b) <BODY SRC= “sky.jpg”>
c) <IMG BACKGROUND= “sky.jpg”>
d) <BODY BACKGROUD = “sky.jpg”>
Answer:
d) <BODY BACKGROUD = “sky.jpg”>

Question 4.
_______ attribute of <frame>tag is used to prevent users from resizing the border of a specific frame by dragging it. (MAY-2016)
a) scrolling
b) No resize
c) margin width
d) margin height
Answer:
b) No resize

Question 5.
Write the complete HTML tag that links the text “PSC” to the website www.keralapsc.org (MARCH-2017)
Answer:
<A HREF=”www.keralapsc.org”>PSC</A>

Question 6.
_______ tag in HTML is used to create a drop-down list. (MAY-2017)
a) SELECT
b) OPTION
c) INPUT
d) LIST
Answer:
a) SELECT

Plus Two Computer Application Web Designing Using HTML 2 Marks Important Questions

Question 1.
Write the HTML code to create the following table: (MARCH-2017)
Plus Two Computer Application Chapter Wise Previous Questions Chapter 5 Web Designing Using HTML 1
Answer:
Sp <html>
<head>
<title>
table creation </title>
</head>
<body bgcolor=”cyan”>
<table border=”1″>
<tralign=”center>
<th colspan=”2″>No. of Students</th>
</tr>
<tralign=”left”>
<th>Science</th>
<td>55</td>
</tr>
<tralign=”left”>
<th>Commerce</th>
<td>60</td>
</tr>
<tr align=”left”>
<th>Humanities</th>
<td>58</td>
</tr>
</table>
</body>
</html>

Plus Two Computer Application Web Designing Using HTML 3 Marks Important Questions

Question 1.
Explain the HTML tag <table> and its attributes. (MARCH-2016)
Answer:

  1. Border: It specifies the thickness of the borderlines around the table
  2. Border color: It specifies the colour for borderlines
  3. Align: It specifies the table alignment, the values can be left, right or center
  4. Bgcolor: It specifies the background colour for the table.
  5. Cellspacing: It specifies the space between two table cells
  6. Cellpadding: It specifies the space between cell border and content
  7. Cols: It specifies the number of columns
  8. Width: It determines the table width
  9. Frame: It specifies the border lines around the table, values are void, border, box, above, below,…

Question 2.
Explain <OL> tag with suitable example (MAY-2016)
Answer:
Ordered list (<OI>)- This tag is used to display items with follwing type values
Type=1 for 1,2,3,
Type =i for i,ii,iii,
Type = I for I,II,III
Type = a for a,b,c,…,
Type = A for A,B,C,….
Eg:-<OLType=”1″>
<li>Apple
<li>Orange
<li>Grapes
</OL>

Question 3.
Explain nesting of framesets with an example. (MARCH-2017)
Answer:
Nesting of framesets
A <frameset> tag contains another <frameset> tag
Eg:
<frameset cols=”30%,*”>
<frame src=”page1.html”>
<frameset rows=”33%,33%,*”>
<frame src=”page2.html”>
<frame src=”page3.htmr>
<frame src=”page4.html”>
</frameset>
</frameset>

Question 4.
Write an HTML code to create the following table. (MAY-2017)

PAY-ROLL
EMPNONAMESALARY
101ABIN15,000
102SINI25,000
103ANU20,000

Answer:
<html>
<head>
<title>
table
</title>
</head>
<body bgcolor=”cyan”>
<table border=”1″>
<tralign=”center”>
<th colspan=”3″>PAY ROLL</th>
</tr>
<tralign=”center”>
<th>EMPNO</th>
<th>NAME</th>
<th>SALARY</th>
</tr>
<tralign=”center”>
<td>101 <br>102<br>103</td>
<td>ABIN<br>SINI<br>ANU</td>
<td>15,000<br>25,000<br>20,000</td>
</tr>
</table>
</body>
</html>

Plus Two Computer Application Chapter Wise Previous Questions Chapter 4 Web Technology

Kerala State Board New Syllabus Plus Two Computer Application Chapter Wise Previous Questions and Answers Chapter 4 Web Technology.

Kerala Plus Two Computer Application Chapter Wise Previous Questions Chapter 4 Web Technology

Plus Two Computer Application Web Technology 1 Mark Important Questions

Question 1.
The default port number of http is (MARCH-2016)
a) 20
b) 80
c) 110
d) 53
Answer:
b) 80

Question 2.
_______ tag is used to make the size of the text smaller than current text in HTML.  (MAY-2016)
a) <b>
b) <small>
c) <sub>
d) <sup>
Answer:
b) <small>

Question 3.
A designed website has to be uploaded into a to make it available to internet users all over the world. (MARCH-2017)
Answer:
Webserver

Question 4.
______ is a server that acts as a bridge between the merchant server and the bank server. (MARCH-2017)
Answer:
Payment gateway

Question 5.
The port no. for HTTP protocol is ______ (MAY-2017)
a) 20
b) 80
c) 110
d) 53
Answer:
b) 80

Question 6.
Pick the odd one out: (MAY-2017)
a) BODY
b) HTML
c) HEAD
d) ALIGN
Answer:
d) ALIGN

Question 7.
DNS stands for _____ (MAY-2017)
Answer:
Domain Name System

Plus Two Computer Application Web Technology 2 Marks Important Questions

Question 1.
A webpage is created to display the result of the engineering entrance examination. (MARCH-2016)
a) What type of webpage it is?
b) Mention any two features of it.
Answer:
a) Dynamic web page
b) 1) Content and layout is not fixed
2) It uses databases
3) It runs as the server-side application program
4) interactive

Question 2.
Compare client-side scripting and server-side scripting. (MAY-2016)
Answer:

Client-Side ScriptingServer Side Scripting
Script is copied to client browserto the webserver
Executed by the clientExecuted by the server and result gets back to the browser window
Used for Client level validationConnect to the database in the server
It is possible to block by the userCannot possible
Client side scripts depends the type and version of the browserIt does not depend the type and version of the browser

Question 3.
Every web browser has default colors to display text and hyperlink. How can we change this default colour? (MARCH-2017)
Answer:
Attribute of BODY tag is used for this.
1) TEXT-Specifies the color of the text content of the page
Eg. <BODY TEXT= “Red”>
2) LINK- Specifies colour of the hyperlinks that are not visited by the user
3) ALINK-Specifies the colour of hyperlinks
4) VLINK-Specifies the color of hyperlinks which are a I ready visited by the viewer.
Eg. < BODYALINK= “Cyan” LINK-’ Magenta” VLINK= “Orange”>

Question 4.
Differentiate static and dynamic web page. (MAY-2017)
Answer:

Static web pagesDynamic web pages
Content and layout is fixedContent and layout are changed frequently
Never use databaseDatabase is used
Run by browserIt runs on the server and the result get back to the client (browser)
Easy to developNot at all easy

Plus Two Computer Application Web Technology 3 Marks Important Questions

Question 1.
Compare static and dynamic web pages (MARCH-2017)
Answer:

Static web pagesDynamic web pages
Content and layout is fixedContent and layout is changed frequently
Never use databaseDatabase is used
Run by browserIt runs on the server and the result get back to the client(browser)
Easy to developNot at all easy

Question 2.
Compare Client-side scripting and Server-side scripting languages. (MARCH-2017)
Answer:

Client-Side ScriptingServer Side Scripting
Script is copied to client browserto the webserver
Executed by the clientExecuted by the server and result gets back to the browser window
Used for Client level validationConnect to the database in the server
It is possible to block by the userCannot possible
Client side scripts depends the type and version of the browserIt does not depend the type and version of the browser

Plus Two Computer Application Chapter Wise Previous Questions Chapter 3 Functions

Kerala State Board New Syllabus Plus Two Computer Application Chapter Wise Previous Questions and Answers Chapter 3 Functions.

Kerala Plus Two Computer Application Chapter Wise Previous Questions Chapter 3 Functions

Plus Two Computer Application Functions 1 Mark Important Questions

Question 1.
function is used to check whether a character is alphanumeric. (MAY-2016)
a) isdigit( )
b) inalnum( )
c) isupper( )
d) islower( )
Answer:
b) isalnum( );

Question 2.
char s1 [10]=”hello”,s2[10]; (MAY-2017)
strcpy (s2, s1);
cout<<s2;
What will be the output?
Answer:
a) hello

Plus Two Computer Application Functions 2 Marks Important Questions

Question 1.
Consider the followjjig code: (MARCH-2016)
char S1[ ] = “program”
char S2[ ] = “PROGRAM” int n;
n=strcmpi (S1, S2)
What is the value of n?
a) n=0
b) n=1
c) n>1
d) n<0
Answer:
a) n =0

Question 2.
Explain two stream functions for input operation for example. (MARCH-2017)
Answer:
Input functions: The input functions like get( )(to read a character from the keyboard) and getline( ) (to read a line of characters from the keyboard) is used with cin and dot(.) operator.

Question 3.
Explain how allocation of string takes place in memory. (MAY-2017)
Answer:
A string is automatically appended by a null character(‘\0’). The null character is treated as one character. charname[20];
Here we can store a name with character up to 19.

Question 4.
Explain gets( ) and puts ( ) functions (MAY-2017)
Answer:
gets( ) function is used to get a string from the key board including spaces.
puts( ) function is used to print a string on the screen. To use gets( ) and puts ( ) function the header file cstdio must be included.

Plus Two Computer Application Functions 3 Marks Important Questions

Question 1.
Explain any three stream function for I/O operation.(MARCH-2016)
Answer:
Stream functions for I/O operation are given below
1) get ( ):- To read a character from the key board
eg: cin.get(ch);

2) getline ( ):- To read a line of characters from the keyboard
eg: cin.getline(str, len);

3) put( ):- To print a characters on the screen
eg:cout.put(‘A’);

4) write ( ):- To print a line of characters on the screen
eg: cout.write (str, len);

Question 2.
Write a code to do the following: (MARCH-2016)
a) A function named largest accept two integer numbers and return the largest number.
b) Use this function to find the largest of two numbers.
Answer:
a) int largest (int a, int b)
{
if (a>b)
return a;
else
return b;
}

b) void main ( )
{
int x, y;
cout<<“Enter 2 numbers”; cin>>x>>y;
cout<< “The largest among these is”
<< largest (x,y);
}

Question 3.
Explain any three string function with example. (MAY-2016)
Answer:
Functions in C++
Some functions that are already available in C++ are called pre-defined or built in functions.
In C++, we can create our own functions for a specific job or task, such functions are called user defined functions.
A C++ program must contain a main( ) function. A C++ program may contain many lines of statements(including so many functions) but the execution of the program starts and ends with main( ) function.
Predefined functions
To invoke a function that requires some data for performing the task, such data is called parameter or argument. Some functions return some value back to the called function.
String functions
To manipulate string in C++ a header file called string.h must be included.
a) strlen( )- to find the number of characters in a string(i.e. string length).
Syntax: strlen(string);
Eg- cout<<strlen(“Computer”); It prints 8.

b) strcpy( )- It is used to copy second string into first string.
Syntax: strcpy(string1 ,string2);
Eg. strcpy(str,”BVM HSS”); cout<<str; It prints BVM HSS.

c) strcat( )- It is used to concatenate second string into first one.
Syntax: strcat(string1 ,string2)
Eg. strcpy(str1,’’Hello”); strcpy(str2,” World”); strcat(str1,str2);
cout<<str1; It displays the concatenated string “Hello World”

d) strcmp( )- it is used to compare two strings and returns an integer.
Syntax: strcmp (string1 ,string2)
if it is 0 both strings are equal.
if it is greater than 0(i.e. +ve) string1 is greater than string2
if it is less than 0(i.e. -ve) string2 is greater than string1
Eg.
include
#include using namespace std; int main()
{
char str1 [10],str2[10];
strcpy(str1 ,”Kiran”);
strcpy(str2,”Jobi”);
cout<<strcmp(str1 ,str2);
}
It returns a +ve integer.

e) strcmpi( )- It is same as strcmp( ) but it is not case sensitive. That means uppercase and lowercase are treated as same.
Eg. “ANDREA” and “Andrea” and “andrea” are the same.
# include
#include
using namespace std;
int main( )
{
char str1 [10],str2[10];
strcpy(str1,”Kiran”);
strcpy(str2,”KIRAN”);
cout<<strcmpi(str1 ,str2);
}
It returns 0. That is both are same.

Question 4.
Write a function that accept 3 numbers of type float as argument and return the average of three numbers. Write program which use this function to find the average of three numbers using C++. (MAY-2016)
Answer:
# include
using namespace std;
float avg(float n1, float n2, float n3)
{
return ((n1 +n2+n3)/3);
}
int main( )
{
float x, y, z;
cout <<“Enter 3 nos”; cin>> x>>y>>z;
cout <<“the average is”<<avg(x,y,z);
}

Question 5.
“Initialized formal arguments are called default arguments.” Using this concept write the function prototype and definition of a user-defined function Sum() which accepts two or three integer numbers and returns their sum. (MARCH-2017)
Answer:
#include
using namespace std;
int sum(int x=100,int y=50,int z=10)
{
retum(x+y+z);
}
int main( )
{
cout<<sum( )<<endl; cout<<sum(1)<<endl;
cout<<sum(1,2)<<endl;
cout<<sum(1,2,3)<<endl;
}

Question 6.
Write the output of the following code segment. (MARCH-2017)
char S1[25]=” Computer”;
char S2[15]=” Applications”;
strcat(S1 ,S2);
cout<<S1;
Answer:
The output is “ComputerApplicatios”. That is the second string is concatenated to the first string.

Question 7.
Explain three string functions in C++. (MAY-2017)
Answer:
a) strlen( )- to find the number of characters in a string(i.e. string length).
Syntax: strlen(string);
Eg. cout<<strlen(“Computer”);
It prints 8.

b) strcpy( )- It is used to copy second string into first string.
Syntax: strcpy(string1, string2);
Eg. strcpy(str,”BVM HSS”);
cout<<str;
It prints BVM HSS.

c) strcat( )- It is used to concatenate second string into first one.
Syntax: strcat(string1,string2)
Eg. strcpy(str1,’’Hello”);
strcpy(str2,” World”);
strcat(str1 ,str2);
cout<<str1;
It displays the concatenated string “Hello World”

Question 8.
Write a program using a function to interchange the value of two variables. (Use call by reference method for passing arguments.) (MAY-2017)
Answer:
#include
using namespace std;
void swap(int &x,int &y)
{
int temp; temp=x;
x=y;
y=temp;
}
intmain()
{
intx=100,y=200;
cout<<“values before swap”<<endl;
cout<<“x=”<<x<<“,y=”<<y<<“\n”;
swap(x,y);
cout<<“values after swap”<<endl;
cout<<“x=”<<x<<“,y-‘<<y<<“\n”;

Plus Two Computer Application Chapter Wise Previous Questions Chapter 2 Arrays

Kerala State Board New Syllabus Plus Two Computer Application Chapter Wise Previous Questions and Answers Chapter 2 Arrays.

Kerala Plus Two Computer Application Chapter Wise Previous Questions Chapter 2 Arrays

Plus Two Computer Application Arrays 1 Mark Important Questions

Question 1.
Write C++ initialization statement to initialize an integer array name ‘MARK’ with the values 70,80,85,90. (MARCH-2017)
Answer:
MARK[4] = {70,80,85,90};
MARK[ ] = {70,80,85,90};
MARK[0] = 70;
MARK[1] = 80;
MARK[2] = 85;
MARK[3] = 90;

Plus Two Computer Application Arrays 2 Mark Important Questions

Question 1.
How memory is allocated for a float array? (MARCH-2016)
Answer:
Memory allocated for the float data type is 4.
Total byte = size of array *4
eg. float n[10];
Here total byte = 10*4
That means 40 bytes.

Question 2.
How can we initialize an integer array? Give an example. (MARCH-2016)
Answer:
Array elements can be initialised at the time of declaration and values are included in braces,
eg: ing n[5]={10,20, 30,40, 50};

Question 3.
Answer any of the following questions 4(a) or 4(b). (MARCH-2016)
a) Define an array. Give an example of an integer array declaration.
b) Consider the following C++ code char text [20]; cin>>text;
If the input string is “Computer Programming”, what will be the output? Justify your answer.
Answer:
a) An array is a collection of elements with the same data type.
eg:- int n[100]; This is an array namely n. We can store 100 elements. The index of the first element is 0 and the last is 99.
b) The output is “Computer”. This is because of c in reads the characters up to space. That means space is the delimiter, The character after space is truncated.

Plus Two Computer Application Arrays 3 Mark Important Questions

Question 1.
Write a C++ program to input 10 numbers into an integer array and find the sum of numbers which are an exact multiple of 5. (MARCH-2017)
Answer:
#include <iostream>
using namespace std;
int main()
{
int n[10],i,sum=0;
for(i=0;i<10;i++)
{
cout<<“Enter value for number”<<i+1
cin>>n[i];
if(n[i]%5==0)
sum+=n[i];
}
cout<<“The sum of numbers which are exact multiple of 5 is“<<sum;
V;
}

Plus Two Computer Application Arrays 5 Mark Important Questions

Question 1.
Write a C++ program to accept a string and count the number of words and vowels in that string. (MARCH-2016)
Answer:
(a) #include(iostream>
# include <cstdio>
# include<cctype>
using namespace std;
void main ()
{
int i, vowel =0, words=1; ,
charstr[80];
cout<< “Enter a string \n”;
gets (str);
for (i=0, str[i]! = ‘\0’; i++)
{
if (str [i] ==32) words ++;
’ switch (to lower(str[i]))
{
case ‘a’: case ‘e’: case ‘i’: case ‘O’: case ‘u’: vowel ++;
}
count<<“The number of words is” <<words; count<<“\n the number of vowels is”<<vowel;
}

Question 2.
Write a C++ program to accept N integer numbers and find the sum and average of even numbers. (MARCH-2016)
Answer:
# include <iostream>
using namespace std;
void main ()
{
float avg, sum = 0.0;
int N, i, no;
cout <<“Enter how many numbers”;
cin>>N;
for(i=0; i<N; i++)
{
cout<< “Enter number”<<i+1; cin >> no; if (no % 2 == 0) sum+=no;
}
avg=sum/N;
cout<< “The sum of even numbers is”<<sum; cout<<“\n the average of even numbers is” <<avg;
}

Question 3.
Answer any of the following questions 8(a) or 8(b). (MAY-2016)
a) Write a C++ program to accept a string and find the length of the string without using built in function. Use a character array to store the string.
b) Write a program to input ‘N’ numbers into an integer array and find the largest number in the array.
Answer:
a) # include <iostream>
# include <cstdio>
using namespace std;
int main ()
{
charstr [80]; int i;
cout <<“Enter a string:”;
gets(str);
for(i=o;str[i]!= ‘\0’;i++)
cout <<“The length of the string is “<<i;
}
OR

b) # include <iostream>
using namespace std;
int main ()
{
int N, no[50], i, largest = 0;
cout<< “Enter how many numbers”;
cin>>N;
for (i=0; i<N; i++)
{
cout <<“Enter number”<<i+1;
cin>>no[i];
if (no[i]> largest)
largest = no[i];
}
cout <<“The largest number is” <<largest;
}

Question 4.
Write a C++ program to enter 10 numbers into an array and find the second largest element. (MAY-2016)
Answer:
#include<iostream>
using namespace std;
int main()
{
int i,j,n[10],temp;
for(i=0;i<10;i++)
{
cout<<“Enter a value for number”<<i+1 cin>>n[i];
}
for(i=0;i<9;i++)
{
for(j=i+1;j<10;j++)
if(n[i]<n[j])
{
temp=n[i];
n[i]=n[j];
n[j]=temp;
}
}
cout<<“The second largest number is “<<n[1];
}

Question 5.
Write a C++ program to convert all lowercase alphabets stored in a string to uppercase. (MAY-2016)
Answer:
#include<cstdio>
using namespace std;
int main()
{
charline[80];
int i;
puts(“Enter the string to convert”);
gets(line);
for(i=0;line[i]!=’\0′;i++)
if (line[i]>=97 && line[i]<=122)
line[i]=line[i] – 32;
puts(line);
}

Plus Two Computer Application Chapter Wise Previous Questions Chapter 1 Review of C++ Programming

Kerala State Board New Syllabus Plus Two Computer Application Chapter Wise Previous Questions and Answers Chapter 1 Review of C++ Programming.

Kerala Plus Two Computer Application Chapter Wise Previous Questions Chapter 1 Review of C++ Programming

Plus Two Computer Application Review of C++ Programming 1 Mark Important Questions

Question 1.
_______ is an exit control loop. (MAY-2016)
a) for loop
b) while loop
c) do-while loop
d) break
Answer:
do-while loop

Question 2.
Which among the following is an Insertion Operator? (MARCH-2016)
a) <<
b) >>
c) <
d) >
Answer:
a) <<

Question 3.
Which among the following is equivalent to the statement series b=a, a = a +1? (MARCH-2017)
a) b + = a
b) b = a++
c) b = ++a
d) b + = a + b
Answer:
b) b = a++

Question 4.
A ______ statement in a loop force the termination of that loop. (MARCH-2017)
Answer:
break

Question 5.
_______ operator is the arithmetic assignment operator. (MAY-2017)
a) >>
b) ==
c) +=
d) =
Answer:
c) +=

Plus Two Computer Application Review of C++ Programming 2 Marks Important Questions

Question 1.
How does a ‘goto’ statement work? (MAY-2016)
Answer:
The execution of a program is sequential but we can change this sequential manner by using jump statements. The jump statements are
1) goto statement By using goto we can transfer the control anywhere in the program without any condition. The syntax is goto label;
Eg.
# include<iostream>
using namespace std;
int main()
{
float a,b;
cout<<“Enter 2 numbers”;
cin>>a>>b;
if(b==0)
goto end;
cout<<“The quotient is “<< a/b;
return 0;
end:
cout<<“Division by zero error”;
}

Question 2.
What are the main components of a looping statement? (MARCH-2016)
Answer:
The main components are initialization expression, test expression, update expression, and looping body
eg: for (i=1; i<=10; i++)
cout << i;

Question 3.
Identify the following C++ tokens. (MAY-2017)
a) “welcome”
b) int
c) >=
d) ++
Answer:
a) “welcome” String Literal
b) int-Keyword
c) >= Operator
d) ++-: Operator

Plus Two Computer Application Review of C++ Programming 3 Marks Important Questions

Question 1.
Explain switch statement with an example (MAY-2016)
Answer:
cin >> pcode;
switch (pcode)
{
case ‘C’:
cout <<“Computer”;
break;
case ‘M’:
cout << “Mobile Phone”;
break;
case ’L’:
cout << “Laptop”;
break;
default:
cout << “lnvalid code”;

Question 2.
Rewrite the following C++ code using ‘switch’ statement (MARCH-2017)
cin >> pcode;
if (pcode == ‘C’)
cout << “Computer”;
else if (pcode == ‘M’)
cout<<“Mobile Phone”;
else if(pcode == ‘L’)
cout<<“Laptop
else
cout<<“lnvalid code”;
Answer:
cin >> pcode;
switch(pcode)
{
case ‘C’:
cout << “Computer”;
break;
case ‘M’:
cout << “Mobile Phone”;
break;
case ’L’:
cout << “Laptop”;
break;
default:
cout << “lnvalid code”;

Question 3.
How do continue and break statements differ in a loop? Explain with an example. (MARCH-2016)
Answer:
Break is used to terminate a loop. But continue is used for skipping (bypassing) a part of the code, eg: for (i=1, i<10; i++)
{
if (i%2==0) continue; cout<<i << “, “;
}
Here the output is 1,3, 5, 7, 9
eg: for (i=1; i<10; i++)
{
if (i% 2==0) break;
cout<<i<<“,”;
}
Here the output is 1, that is the loop is quit when i=2.

Question 4.
Explain break and continue statements with examples. (MAY-2017)
Answer:
break statement:- It is used to skip over a part of the code i.e. we can premature exit from a loop such as while, do-while, for or switch, continue statement:- It bypasses one iteration of the loop.
break statement:- It is used to skip over a part of the code i.e. we can premature exit from a loop such as while, do-while, for, or switch.
Syntax:
while (expression)
if (condition) break;
}
Eg.
#include<iostream>
using namespace std;
int main()
{
int i=1;
while(i<10)
{
cout<<i<<endl;
if(i==5)
break;
i++;
}
}
The output is
1
2
3
4
5
continue statement: It bypasses one iteration of the loop.
Syntax:
while (expression)
{
if (condition) break;
}
Eg.
#include<iostream>
using namespace std;
int main()
{
int i=0;
while(i<10)
{
i++;
if(i==5) continue;
cout<<i<<endl;
}
}
The output is
1
2
3
4
5
6
7
8
9
10

Plus Two Maths Chapter Wise Previous Questions Chapter 12 Linear Programming

Kerala State Board New Syllabus Plus Two Maths Chapter Wise Previous Questions and Answers Chapter 12 Linear Programming.

Kerala Plus Two Maths Chapter Wise Previous Questions Chapter 12 Linear Programming

Plus Two Maths Linear Programming 4 Marks Important Questions

Question 1.
Consider the linear programming problem;
Maximise; Z = x +y , 2x + y – 3< 0, x – 2y + 1 < 0, y < 3, x < 0, y < 0
(i) Draw its feasible region.
(ii) Find the corner points of the feasible region.
(iii) Find the corner at which Z attains its maximum. (March – 2012)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 12 Linear Programming 1
(ii) In the figure the shaded region ABC is the feasible region. Here the region is bounded. The corner points are A(1, 1), B(5, 3), C(O, 3).
(iii) Given; Z = x + y

Corner pointsValue of Z
AZ = (l)+(1) = 2
BZ = (5)+(3) = 8
CZ = (0)+(3) = 3

Since maximum value of Z occurs at B, the soluion is Z = (5) + (3) = 8.

Question 2.
Consider the LPP Minimise; Z = 200 k + 500y, x + 2y > 10, 3x + 4y < 24, x > 0, y > 0
(i) Draw the feasible region.
(ii) Find the co-ordinates of the comer points of the feasible region.
(iii) Solve the LPP. (May – 2012)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 12 Linear Programming 2
(ii) In the figure the shaded region ABC is the feasible region. Here the region is bounded. The corner points are 4(4, 3), 5(0, 6), C(0, 5)
(iii) Given; Z = 200x + 500y

Corner pointsValue of Z
AZ = 200(4)+500(3) = 2300
BZ = 200(0)+500(6) = 3000
CZ = 200(0)+500(5) = 2500

Since minimum value of Z occurs at A, the soluion is Z = 200(4) + 500(3) = 2300.

Question 3.
Consider the LPP
Maximise; Z = 5x + 3y
Subject to; 3x + 5y < 15, 5x + 2y < 10x, y > 0
(i) Draw the feasible region.
(ii) Find the corner points of the feasible region.
(iii) Find the corner at which Z attains its maximum. (March – 2013)
Answer:
In the figure, the shaded region OABC is the feasible region. Here the region is bounded.
The corner points are
Plus Two Maths Chapter Wise Previous Questions Chapter 12 Linear Programming 3
Given; Z = 5x + 3y

Corner pointsValue of Z
OZ = 0
AZ = 5(2)+3(0) = 10
B\(Z=5\left(\frac{20}{19}\right)+3\left(\frac{45}{19}\right)=\frac{235}{19}\)
CZ = 5(0)+3(3) = 9

Since maximum value of Z occurs at B, the soluion is Z =

Question 4.
Consider the linear programming problem: Minimize Z = 3x + 9y Subject to the constraints: x + 3y < 60 x + y > 10, x < y, x > 0, y > 0
(i) Draw its feasible region.
(ii) Find the vertices of the feasible region
(iii) Find the minimum value of Z subject to the given constraints. (March-2014, SAY-2016)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 12 Linear Programming 4
(ii) The feasible region is ABCD.
Solving x + y = 10, x = y we get B(5, 5)
Solving x + 3y = 60, x = y we get C(15, 15)
Hence the comer points are A(0, 10) , B(5, 5), C(15, 15), D(0, 20)
(iii) Given; Z = 3x + 9y

Corner pointsValue of Z
AZ = 3(0)+9(10) = 90
BZ = 3(5)+9(5) = 60
CZ = 3(15)+ 9(15) = 190
DZ = 3(0)+9(20) = 180

Form the table, minumum value of Z is 6 O at B(5, 5).

Question 5.
Consider the linear inequalities 2x + 3y < 6; 2x + y < 4; x, y < 0
(a) Mark the feasible region.
(b) Maximise the function z = 4x + 5y subject to the given constraints. (March – 2014)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 12 Linear Programming 5
(b) 15.2x + 3y = 6

X02
Y40

2x + y = 4

X03
Y20
Corner pointsz = 4x + 5y
0(0, 0)z = 0
A(2, 0)8 + 0 = 8
B(1.5, 1)6 + 5 = 11
C(0, 2)0 + 10 = 10

Maximum at x = 1.5, y = 1
Maximum value is Z = 11

Question 6.
Consider the linear programming problem: Minimise Z = 4x + 4y Subject to x + 2y < 8; 3x + 2y < 12x, y < 0
(a) Mark its feasible region.
(b) Find the comer points of the feasible region.
(c) Find the corner at which Z attains its minimum. (May – 2014)
Answer:
(a) x + 2y = 8,

X08
y40

3x + 12y = 12

X04
y60

Plus Two Maths Chapter Wise Previous Questions Chapter 12 Linear Programming 6

The comer points are 0(0, 0), A(4, 0), B(2, 3), C(0, 4)

(c)

Corner pointZ = -3x + 4y
0 (0, 0)Z = 0 + 0 = 0
A (4, 0)Z = -12 + 0 = -12
B (2, 3)Z = -6 + 12 = 6
C (0, 4)Z = 0 + 16 = 16

Z attains minimum at (4, 0).

Question 7.
Consider the linear programming problem: Maximum z = 4x + y
Subject to constraints: x + y < 50, 3x + y < 9x, y < 0
(a) Draw the feasible region
(b) Find the corner points of the feasible region
(c) Find the corner at which ‘z’ attains its maximum value. (May – 2015)
Answer:
(a) x + y = 50,

X050
y500

3x + y = 90

X030
y900

Plus Two Maths Chapter Wise Previous Questions Chapter 12 Linear Programming 7
(b) Solving the equations we get the points as
O(0, 0) A(30, 0); B(20, 30); C(0, 50)

(c)

VerticesZ
0(0,0)0
A(30,0)120 maximum
B(20,30)110
C(0,50)50

Z attains maximum at A(30, 0)

Question 8.
Consider the LPP
Maximise z = 3x + 2y
Subject to the constraints: x + 2y < 10, 3x + y < 15; x, y < 0
(a) Draw its feasible region
(b) Find the corner points of the feasible region
(c) Find the maximum value of Z. (March – 2016)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 12 Linear Programming 8
(b) The corner points 0(0,0), A(5,0), B(4,3), C(0, 5)
Z is maximum at B(4, 3), z = 18.

(c)

o(0,0)Z = 3(0)+ 2(0) = 0
A(5,0),Z= 3(5)+ 2(0) = 15
B(4,3),Z= 3(4)+ 2(3) = 18
C(0,5)Z= 3(0) + 2(5) = 10

Question 9.
Consider the linear programming problem: Maximum z = 50x + 40y
Subject to constraints:
x + 2y < 10; 3x + 4y < 24; x, y < 0
(i) Draw the feasible region
(ii) Find the comer points of the feasible region
(iii) Find the maximum value of z. (March – 2017)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 12 Linear Programming 9
(ii) In the figure the shaded region ABC is the feasible region. Here the region is bounded. The corner points are A(4, 3), B(0, 6), C(0, 5)
(iii) Given; Z = 50x + 40y

Corner pointsValue of Z
AZ = 50(4)+ 40(3) = 320
BZ= 50(0)+ 40(6) = 240.
CZ= 50(0)+ 40(5) = 200

Since minimum value of Z occurs at A, the soluion is Z = 50(4) + 4(3) = 320.

Plus Two Maths Linear Programming 6 Marks Important Questions

Question 1.
A furniture dealer sells only tables and chairs. He has Rs. 12,000 to invest and a space to store 90 pieces. A table costs him Rs. 400 and a chair Rs. 100. He can sell a table at a profit of Rs. 75 and a chair at a profit of Rs. 25. Assume that he can sell all the items. The dealer wants to get maximum profit.
(i) By defining suitable variables, write the objective function.
(ii) Write the constraints.
(iii) Maximise the objective function graphically. (March – 2010)
Answer:
(i) Let x be the number of Tables and y be the number of Chairs. Then; Maximise; z = 75x + 25y
(ii) Furniture constraints x + y < 90
Investment constraint 400x + 100y < 12000
Therefore;Maximise; Z = 75x + 25y, x + y < 90, 4x + y < 120, x<0, y<0
(iii) In the figure the shaded region OABC is the feasible region. Here the region is bounded. The corner points are O(0, 0), A(30, 0) B(10, 80), C(0, 90).
Plus Two Maths Chapter Wise Previous Questions Chapter 12 Linear Programming 10
Given; Z = 75x + 25y

Corner pointsValue of Z
OZ =75(0) +25(0) = 0
AZ= 75(30)+ 25(0) = 2250
BZ= 75(10)+ 25(80) = 2750
CZ= 75(0)+ 25(90) = 2250

Since minimum value of Z occurs at B, the soluion is Z = 2750.

Question 2.
A company produces two types of cricket balls A and B. The production time of one ball of type B is double type A (time in units). The company has the time to produce a maximum of 2000 balls per day. The supply of raw materials is sufficient for the production of 1500 balls (both A and B) per day. The company wants to make maximum profit by making a profit of Rs. 3 from a ball of type A and Rs. 5 from type B.

Then,
(i) By defining suitable variables write the objective function.
(ii) Write the constraints.
(iii) How many balls should be produced in each type per day in order to get maximum profit? (May – 2010)
Answer:
(i) Let x be the number of balls of type A and y be the number of balls of type B. Then Maximise profit is Z = 3x + 5y
(ii) Balls constraints 2x + y < 2000 investment constraint x + y < 1500
Therefore; Maximise; Z = 3x + 5y, 2x + y < 2000, x + y < 1500, x < 0, y < 0
Plus Two Maths Chapter Wise Previous Questions Chapter 12 Linear Programming 11
(iii) In the figure the shaded region OABC is the fesible region. Here the region ¡s bounded. The corner points are O(0, 0), A(1000, 0) B(500, 1000), C(0, 1500). Given; Z = 3x + 5y

Comer pointsValue of Z
OZ = 3(0)+ 5(0) = 0
AZ = 3(1000) + 5(0) = 3000
BZ= 3(500) + 5(1000) = 6500
CZ= 3(0) + 5(1500) = 7500

Since maximum value of Z occurs at C, the soluion is Z = 3(0) + 5(1500) = 7500.

Question 3.
The graph of a linear programming problem is given below. The shaded region is the feasible region. The objective function is Maximise; Z = px + qy
Plus Two Maths Chapter Wise Previous Questions Chapter 12 Linear Programming 12
(i) What are the co-ordinates of the corners of the feasible region?
(ii) Write the constraints.
(iii) If the Max. Z occurs at A and B, what ¡s the relation between p and q?
(iv) If q = 1, write the objective function.
(v) Find Max. Z. (March – 2011)
Answer:
(i) From the figure the feasible region is OABC.
Then the comer points are;
A is (5, 0), B is (3, 4), C is (0, 5) and O (0, 0)
(ii) The constraints are 2x + y < 10, x + 3y < 15, x < 0, y < 0
(iii) Given; Z = px + qy

Corner pointsValue of Z
OZ=p(0)+q(0) = 0
AZ = p(5) + q(Q) = 5p
BZ = p( 3)+g(4) = 3p+4q
CZ = p(0)+q(5) = 5q

Since maximum at A and B we have;
⇒ 3p + 4q = 5p ⇒ 2p = 4q ⇒ p = 2q
(iv) When q = 1, then p ⇒ 2q ⇒ p = 2
Objective function is; Z = 2x + y
(v) We have; Z px + qy at B Z has maximum ⇒ Z = 2(3) + 4 = 10

Question 4.
A manufacturer produces nuts and bolts. It takes 1 hour of work on machine A and 3 hours on machine B to produce a package of nuts. It takes 3 hours on machine A and I hour on machine B to produce a package of bolts. He earns a profit of Rs. 17.50 per package on nuts and Rs. 7.00 per package on bolts. How many packages of each should be produced each day so as to maximise his profit, if he produced each day so as to maximise the profit if he operates his machines for at the most 12 hours a day?
(i) By suitable defining the variables write the objective function of the problem.
(ii) Formulate the problem as a linear programming problem(LPP)
(iii) Solve the LPP graphically and find the number of packages of nuts and bolts to be manufactured. (May -2011)
Answer:
(i) Let x be the number of packages of nuts produced and y be the number of packages of bolts produced. Then;
Maximise profit is; Z = 17. 5x + 7y
(ii) Time constraint for Machine A; x + 3y < 12
Time constraint for Machine B; 3x + y < 12
Therefore; Maximise; Z = 17.5x + 7y, x + 3y < 12, 3x + y < 12, x < 0, y < 0
(iii) In the figure the shaded region OABC is the visible region. Here the region is bounded. The corner points are 0(0,0), A (4, 0) B(3, 3), C(0, 4).
Plus Two Maths Chapter Wise Previous Questions Chapter 12 Linear Programming 13
Given; Z = 17.5x + 7y

Comer pointsValue of Z
OZ =17.5(0) +7(0) = 0
AZ =17.5(4)+ 7(0) = 70
BZ= 17.5(3)+ 7(3) = 73.5
CZ= 17.5(0)+7(4) = 28

Since maximum value of Z occurs at B, the soluion is Z = 17.5(3) + 7(3) = 73.5.

Question 5.
A bakery owner makes two types of cakes A and B. Three machines are needed for this purpose. The time (in minutes) required for making each type of cakes in each machine is given below;

MachineTypes of cakes
1126
II180
III69

Each machine is available for almost 6 hours per day. Assume that all cakes will be sold out every day. The bakery owner wants to make a maximum profit per day by making Rs. 7.5 from type A and Rs. 5 from type B.
(i) Write the objective function by defining suitable variables.
(ii) Write the constraints.
(iii) Find the maximum profit graphically. (May- 2013, EDUMATE – 2017)
Answer:
(i) Number of cake of type A: x
Number of cake of type B: y
Then profit function is Maximise: Z = 75x + 5y

(ii) 12x + 6y < 360; 18x + 0y < 360
6x + 9y < 360; x > 0, y > 0
Simplifying we get;
2x – i – y < 60………..(1)
x < 20………..(2)
2x + 3y < 120………..(3)
x > 0, y > 0

Plus Two Maths Chapter Wise Previous Questions Chapter 12 Linear Programming 14

The feasible region is OABCDO
Solving (1) and (2) we get the point B- (2020)
Solving (1) and (3) we get the point C- (15,30)
A-(20,0), O-(0,0), D-(0,40)
Given; Z = x + y

Corner pointsValue of Z
OZ = 7.5(0) +5(0) = 0
AZ =150
BZ = 250
CZ =112.5
DZ = 200

Since maximum value of Z occurs at B, the soluion is Z = 250 (20, 20).

Question 6.
In a factory, there are two machines A and B producing toys. They respectively produce 60 and 80 units in one hour. A can run a maximum of 10 hours and B a maximum of 7 hours a day. The cost of their running per hour respectively amounts to 2,000 and 2,500 rupees. The total duration of working these machines cannot exceed 12 hours a day. If the total cost cannot exceed Rs. 25,000 per day and the total daily production is at least 800 units, then formulate the problem mathematically. (March – 2014)
Answer:
Let x be the running time for machine A and y be the running time for machine B.
Since machines cannot work more than 12 hours x + y < 12
Since maximum production of two machines is 800 units.
60x + 80y < 800
Maximum cost of production is 25000, 2000x + 2500y < 25000
0 < x < 10, 0 < y < 7

Plus Two Maths Chapter Wise Previous Questions Chapter 11 Three Dimensional Geometry

Kerala State Board New Syllabus Plus Two Maths Chapter Wise Previous Questions and Answers Chapter 11 Three Dimensional Geometry.

Kerala Plus Two Maths Chapter Wise Previous Questions Chapter 11 Three Dimensional Geometry

Plus Two Maths Three Dimensional Geometry 3 Marks Important Questions

Question 1.
(i)Find the equation of the Plane with intercepts 2, 3, 4 on X, Y, Z axes respectively.)
(ii) Find the distance of the point (- 1, – 2,3) from the Plane \(\bar{r}\)(2i – 3 j + 4k) = 4 (March – 2011)
Answer:
(i) The equation of the plane is \(\frac{x}{2}+\frac{y}{3}+\frac{z}{4}=1\)
(ii) The equation of the plane is 2x – 3y + 4z = 4
Hence the distance \(=\frac{2(-1)-3(-2)+4(3)-4}{\sqrt{4+9+16}}\)
\(=\frac{-2+6+12-4}{\sqrt{4+9+16}}=\frac{12}{\sqrt{29}}\)

Question 2.
Consider the points A(2,2, – 1), B(3,4,2), C(7,0,6)
(i) FindAB.
(ii) Find the Cartesian and vector equation the plane passing through these points. (March – 2011)
Answer:
(i) \(A B=\sqrt{1+4+9}=\sqrt{14}\)
(ii) Cartesian Equation of the plane is
Plus Two Maths Chapter Wise Previous Questions Chapter 11 Three Dimensional Geometry 1
Vector equation is \(\bar{r}\)(5i + 2j – 3k) = 17

Question 3.
Consider the points A(3, – 4, – 5) and 5(2, – 3,1)
(i) Find the vector and Cartesian equation of the Line passing through the points A and B.
(ii) Find the point where the line crosses the XY Plane. (March – 2012)
Answer:
Let \(\bar{a}\) = 3i – 4j – 5k, b = 2i – 3j + k
(i) Vector Equation is \(\bar{r}\) = \(\bar{a}\) + λ(\(\bar{b}\) – \(\bar{a}\)) \(\bar{r}\) = 3i – 4j – 5k + λ( – i + j + 6k)
Cartesian Equation is \(\frac{x-3}{-1}=\frac{y+4}{1}=\frac{z+5}{6}\)

(ii) Let the point be (x, y, 0)
\(\begin{array}{l}
\Rightarrow \frac{x-3}{-1}=\frac{y+4}{1}=\frac{5}{6} \\
\Rightarrow x=\frac{13}{6}, y=\frac{-19}{6}
\end{array}\)
Then the point on the XY Plane is \(\left(\frac{13}{6}, \frac{-19}{6}, 0\right)\)

Question 4.
(i) Find the Cartesian equation of the plane passing through the point (1, 2, -3) perpendicular to the vector 2i – j + 2k.
(ii) Find the angle between the above \(\frac{x-1}{2}=\frac{y-3}{3}=\frac{z}{6}\) (March – 2012)
Answer:
(i) The equation of the Plane is
2(x – 1) – 1(y, -2) + 2(z+3) = 0
⇒ 2x – 2 – y + 2 + 2z + 6 = 0
⇒ 2x – y + 2z + 6 – 0

(ii) Angle between the line and the Plane is
Plus Two Maths Chapter Wise Previous Questions Chapter 11 Three Dimensional Geometry 2

Question 5.
(i) Find the angle between the lines having direction ratios 1, 1, 2 and \(\sqrt{3}-1,-\sqrt{3}-1,4\)
(ii) If the lines \(\frac{x-1}{3}=\frac{y-1}{2 \lambda}=\frac{z-3}{2}\) and \(\frac{x-1}{3 \lambda}=\frac{y-1}{1}=\frac{z-6}{-5}\) are perpendicular, find the value of λ. (May – 2012)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 11 Three Dimensional Geometry 3
(ii) Since they are perpendicular
a1a2 + b1b2 + c1c2 = 0
⇒ 3 x 3λ + 2λ x 1 + 2x – 5 = 0
⇒ 9λ + 2λ – 10 = 0
⇒ 11λ + 10 ⇒ 2 = \(\frac{-10}{11}\)

Question 6.
(i) Find the equation of the Plane passing through the points (3, -1, 2), (5, 2, 4), ( -1, -1, 6)
(ii) Find the perpendicular distance from the point (6, 5, 9) to this plane. (March – 2013)
Answer:
(i) Cartesian Equation of the plane is
Plus Two Maths Chapter Wise Previous Questions Chapter 11 Three Dimensional Geometry 4
(ii) Perpendicular distance
Plus Two Maths Chapter Wise Previous Questions Chapter 11 Three Dimensional Geometry 5

Question 7.
Consider the vector equation of the planes r.(2i + j+k) – 3 and r.(i – j – k) = 4
(i) Find the vector equation of any of the plane at the intersection of the above two planes.
(ii) Find the vector equation of the planes through the intersection of the above two planes and the point (1, 2, -1). (May – 2013)
Answer:
(i) 2x + y + z – 3 + λ(x – y – z – 4) = 0
⇒ (2 + λ)x + (1 – λ)y + (1 – λ)z – 3 – 4λ = 0
Vector equation is
\(\bar{r}\).(2 + λ)i + (1 – λ)y + (1 – λ)k – (3 + 4)λ = 0

(ii) Since passing through (1,2, – 1) we have;
⇒ (2 + λ)1 + (1 – λ)2 + (1 – λ)( -1) – 3 – 4λ = 0
⇒ 2 + λ + 2 – 2λ – 1 + 1 – 3 – 4λ = 0
⇒ 0 – 4λ – 0
⇒ λ = 0

\(\bar{r}\).(2i + j + k) = 3 is required plane. Since the point (1, 2, -1) is a point on the first plane.

Question 8.
Consider the planes2x + y – 2z = 5 and 3x – 6y – 2z = 7
(a) Find their normal vectors.
(b) Find the angle between these two planes. (May – 2014)
Answer:
(a) Normal vectors are 2i + i – 2k; 3i – 6j – 2k
(b) Angle =
Plus Two Maths Chapter Wise Previous Questions Chapter 11 Three Dimensional Geometry 6

Question 9.
(a) If a1, b1, c1 and a2, b2, c2 are the direction ratios of two lines, then write the condition of its perpendicularity.
(b) Find the angle between the lines \(\frac{x+3}{3}=\frac{y-1}{5}=\frac{z+3}{4}\) and \(\frac{x+1}{1}=\frac{y-4}{1}=\frac{z-5}{2}\)
Answer:
(a) a1a2 + b1b2 + c1c2 = 0
Plus Two Maths Chapter Wise Previous Questions Chapter 11 Three Dimensional Geometry 7

Question 10.
Find the shortest distance between the lines \(\bar{r}\) = i + j + λ(2i – j + k) and \(\bar{r}\) = 2i + j – k + µ(3i – 5 j + 2k) (March – 2016)
Answer:
From the given lines we have;
Plus Two Maths Chapter Wise Previous Questions Chapter 11 Three Dimensional Geometry 8

Question 11.
(i) The equation of the line which passes through the point(1,2,3) and parallels to the vector 3i + 2j – 2k is
(a) \(\bar{r}\) = 3i + 2j – 2k + λ(/ + 2j + 3k)
(b) \(\bar{r}\) = 2i – 5k + λ(3/ + 2j – 2k)
(c) \(\bar{r}\) = i + 2j + 3k + λ(-2i + 4j – 2k)
(d) \(\bar{r}\) = i + 2j + 3k + λ(3i + 2j – 2k)
(ii) Find the angle between the pair lines
\(\bar{r}\) = 2i – 5j + k + λ(3i + 2j + 6k) and \(\bar{r}\) = li – 6k + µ(i + 2j + 2k) (May – 2016)
Answer:
(i) (d) \(\bar{r}\) = i + 2j + 3k + λ(3i + 2j – 2k)
(ii) \(\bar{a}\) = 3i + 2j + 6k; \(\bar{b}\) = i + 2j + 2k
\(\cos \theta=\frac{\bar{a} \cdot \bar{b}}{|\bar{a} \| \bar{b}|}=\frac{19}{7 \times 3}=\frac{19}{21}\)

Plus Two Maths Three Dimensional Geometry 4 Marks Important Questions

Question 1.
Consider the lines \(\frac{x-3}{2}=\frac{y-1}{5}=\frac{z+3}{4}\) and \(\frac{x+5}{1}=\frac{y+2}{1}=\frac{z-3}{2}\)
(i) Find the angle between them.
(ii) Find the shortest distance between them. (March – 2011)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 11 Three Dimensional Geometry 9

Question 2.
(i) Find the vector equation of the Plane Passing through the intersection of the Planes \(\bar{r}\).(i + j + k) = 6 and \(\bar{r}\)(2i + 3j + 4k) = – 5 and through the point (1, 1, 1).
(ii) Express the vector equation \(\bar{r}\).(5i + 3j + 4k) = 0 of a Plane in Cartesian form and hence find its perpendicular distance from the origin. (May – 2011)
Answer:
(i) The Cartesian equation of the given planes are x + y + z – 6 = 0 and 2x + 3 – y + 4z + 5 = 0
The family of such planes is x + y + z – 6 + λ(2x + 3y+ 4z + 5) = 0  …..(1)
Since it passes through (1, 1, 1)
Plus Two Maths Chapter Wise Previous Questions Chapter 11 Three Dimensional Geometry 10
Vector Equation is \(\bar{r}\).(20i + 23j + 26k) = 69

(ii) Cartesian Equation is ⇒ 5x + 3y + 4z = 0 Perpendicular distance from origin is
\(=\left|\frac{5 \times 0+3 \times 0+4 \times 0}{\sqrt{25+9+16}}\right|=0\)

Question 3.
Given the Plane 5x – 2y + 4z – 9 = 0
(i) Find the foot of the perpendicular drawn from the origin to the Plane.
(ii) Write the vector and Cartesian equation of this perpendicular. (May – 2011)
Answer:
(i) The equation of the perpendicular line to the given plane 5x – 2y + 4z – 9 = 0 and passing through the origin is
\(\begin{array}{l}
\frac{x-0}{5}=\frac{y-0}{-2}=\frac{z-0}{4}=\lambda \\
\Rightarrow \frac{x}{5}=\frac{y}{-2}=\frac{z}{4}=\lambda
\end{array}\)
Hence any point on this line is (5λ, – 2λ, 4λ). Let this point be on the given plane then
⇒ 5(5λ) – 2( – 2λ) + 4(4λ) – 9 = 0
⇒ λ = 1/5
Then the foot of the perpendicular is
\(\left(5 \times \frac{1}{5},-2 \times \frac{1}{5}, 4 \times \frac{1}{5}\right) \Rightarrow\left(1,-\frac{2}{5}, \frac{4}{5}\right)\)
Since the line is perpendicular to the Plane and passes through the point \(\left(1,-\frac{2}{5}, \frac{4}{5}\right)\)
The Cartesian equation is \(\frac{x}{5}=\frac{y}{-2}=\frac{z}{4}\)
The Vector equation is \(\bar{r}\) = \(\bar{0}\) + λ(5i – 2j + 4k)

Question 4.
(i) The foot of the perpendicular from the origin to a Plane is P(4, – 2,5). Write \(\overline{O P}\)
(ii) Find the equation of the Plane in vector and Cartesian form. (May – 2012)
Answer:
(i) \(\overline{O P}\) = 4i – 2j + 5k
(ii) Then is perpendicular unit vector to the required plane is \(\frac{\overline{O P}}{\overline{O P} \mid}=\frac{4 i-2 j+5 k}{\sqrt{16+4+25}}=\frac{4 i-2 j+5 k}{\sqrt{45}}\)

The perpendicular distance from the origin is \(\sqrt{16+4+25}=\sqrt{45}\)
Vector equation of the Plane can be written as
\(\begin{array}{l}
\vec{r} \cdot \bar{m}=d \Rightarrow \bar{r} \cdot \frac{4 i-2 j+5 k}{\sqrt{45}}=\sqrt{45} \\
\Rightarrow \bar{r} .4 i-2 j+5 k=45
\end{array}\)
Cartesian from is 4x – 2y + 5z = 45

Question 5.
Consider the lines \(\frac{x-3}{3}=\frac{y-8}{-1}=\frac{z-3}{1}\) and \(\frac{x+3}{3}=\frac{y+7}{2}=\frac{z-6}{4}\)
(i) Express the equation to the lines into vector form.
(ii) Find the shortest distance between the lines. (March – 2013)
Answer:
(i) The vector equation;
Plus Two Maths Chapter Wise Previous Questions Chapter 11 Three Dimensional Geometry 11

Question 6.
Consider the Cartesian equation of a line
\(\frac{x-3}{2}=\frac{y+1}{3}=\frac{z-5}{-2}\)
(i) Find its vector equation.
(ii) Find the intersecting point with the plane 5x + 2y – 6z – 7 = 0 (May – 2013)
Answer:
(i) Vector equation of the line is
\(\bar{r}\) = (3i – 1j + 5k) + λ(2i + 3j – 2k)

(ii) Any point on the line is of the form
Plus Two Maths Chapter Wise Previous Questions Chapter 11 Three Dimensional Geometry 12

Question 7.
The foot of the perpendicular drawn from origin to a Plane is (4, -2, 5).
(i) How far is the plane from the origin?
(ii) Find a unit vector perpendicular to that Plane.
(iii) Obtain the equation of the Plane in a general form. (March – 2014)
Answer:
(i) \(\overline{O P}\) = 4i – 2j + 5k
(ii) Then is perpendicular unit vector to the required plane is \(\frac{\overline{O P}}{\overline{O P} \mid}=\frac{4 i-2 j+5 k}{\sqrt{16+4+25}}=\frac{4 i-2 j+5 k}{\sqrt{45}}\)

The perpendicular distance from the origin is \(\sqrt{16+4+25}=\sqrt{45}\)
Vector equation of the Plane can be written as
\(\begin{array}{l}
\vec{r} \cdot \bar{m}=d \Rightarrow \bar{r} \cdot \frac{4 i-2 j+5 k}{\sqrt{45}}=\sqrt{45} \\
\Rightarrow \bar{r} .4 i-2 j+5 k=45
\end{array}\)
Cartesian from is 4x – 2y + 5z = 45

Question 8.
(a) Equation of the plane with intercepts 2, 3, 4 on the x, y, z-axis respectively is
(i) 2x + 3y + 4z = 1
(ii) 2x + 3y + 4z = 12
(iii) 6x + 4y + 3z = 1
(iv) 6x + 4y + 3z = 12

(b) Find the Cartesian equation of the plane passing through the points A(2, 5, -3), B(-2, -3, 5), and C(5, 3, -3). (March – 2016)
Answer:
(a) (iv) 6x + 4y + 3z = 12
(b) Equation of the plane is
Plus Two Maths Chapter Wise Previous Questions Chapter 11 Three Dimensional Geometry 13

Question 9.
(i) The distance of the plane from the point(1, 1, 1)is
(a) 4 units
(b) \(\frac{1}{\sqrt{3}}\) units
(c) \(\frac{4}{\sqrt{3}}\) units
(d) \(\frac{1}{4 \sqrt{3}}\) units

(ii) Find the equation of the plane passing through (1, 0. -2) and perpendicular to each of the planes 2x + y – z = 2 and x – y – z = 3 (May – 2016)
Answer:
(i) (c) \(\frac{4}{\sqrt{3}}\) units
(ii) Equation of the plane passing through (1, 0, -2) is a(x – 1) + b(y – 0) + c(z + 2) = 0……………..(1)
Plane (1) is perpendicular to the given planes
2a + b – c = 0 ……………..(2)
a – b – c = 0 ……………..(3)
Solving (2) and (3) we get;
Plus Two Maths Chapter Wise Previous Questions Chapter 11 Three Dimensional Geometry 14

Question 10.
(i) The linesx – l = y = z is perpendicular to the line
\(\begin{array}{l}
\text { (a) } \frac{x-2}{1}=\frac{y-1}{2}=\frac{z}{-3} \\
\text { (b) } x-2=y-2=z \\
\text { (c) } \frac{x-2}{1}=\frac{y-1}{2}=\frac{z}{3} \\
\text { (d) } x=y=\frac{z}{2}
\end{array}\)

(ii) Find the shortest distance between the lines \(\bar{r}\) = i + 2j + 3k + λ(i + j + k) and \(\bar{r}\) – i + j + k + µ(i + j + k) (March – 2017)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 11 Three Dimensional Geometry 15

Plus Two Maths Three Dimensional Geometry 6 Marks Important Questions

Question 1.
(i) Find the shortest distance between the line \(\frac{x+1}{7}=\frac{y+1}{-6}=\frac{z+1}{1}\) and \(\frac{x-3}{1}=\frac{y-5}{-2}=\frac{z-7}{1}\)
(ii) Find the equation of the Plane passing through one point(-1, 3, 2) and ± r to the planes x + 2y + 3z = 5 and 3x + 3y + z = 0 (March – 2010)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 11 Three Dimensional Geometry 16
(ii) Let the equation of the plane be ax + by + cz + d = 0….(1)
Since (1) is perpendicular to 3x + 2y + 3z = 5, a + 2b + 3c = 0
Since (1) is perpendicular to 3x + 3y + z = 0
3a + 3b + c = 0
Using (2) and (3) we have;
\(\frac{a}{2-9}=\frac{-b}{1-9}=\frac{c}{3-6} \Rightarrow \frac{a}{-7}=\frac{b}{8}=\frac{c}{-3}\)
(1) = -7x + 8y – 3z + d = 0
Since (1) passes through (-1, 3, 2) we have;
⇒ -7 (-1) + 8(3) – 3(2) + d = 0
⇒ 7 + 24 – 6 + d = 0 = d = -25
Therefore the equation of the plane is
(1) ⇒ -7x + 8y – 3z – 25 = 0

Question 2.
(i) (a) A line makes equal angles with the coordinate axis. Find the direction cosines.
(b) Find the equation of the Plane Passing through (1, 1, -1),(2, 3, 5) an (1, 4, -5)
(ii) Find p and q, if the plane x + py + qz = 0 is perpendicular to the plane 3x + 2y + z = 0 and the line \(\frac{x-3}{2}=\frac{y-2}{3}=\frac{z-1}{1}\) (March – 2010)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 11 Three Dimensional Geometry 17
(ii) Since the Plane x + py + qz = 0 is perpendicular to the Line \(\frac{x-3}{2}=\frac{y-2}{3}=\frac{z-1}{1}\) we have their direction ratios proportional. Plane dr’s is 1, p, q and dr’s of Line is 2, 3, 1.
\(\Rightarrow \frac{1}{2}=\frac{p}{3}=\frac{q}{1} \Rightarrow p=\frac{3}{2}, q=\frac{1}{2}\)

Question 3.
Given the straight lines
\(\bar{r}[latex] = 3i + 2j – 4k + 2(i + 2j + 2k) and [latex]\bar{r}[latex] = 5i – 2k + µ(3i + 2j + 6k)
(i) Find the angle between the lines.
(ii) Obtain the unit vector perpendicular to both the lines.
(iii) From the equation of the line perpendicular to the given lines and passing through the point (1, 1, 1). (March – 2014)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 11 Three Dimensional Geometry 18
Plus Two Maths Chapter Wise Previous Questions Chapter 11 Three Dimensional Geometry 19

Question 4.
(a) Write the Cartesian equation of the straight line through the points (1, 2, 3) and along the vector 3i + j +2k
(b) Write a general point on this straight line.
(c) Find the point of intersection of this straight line with the plane 2x + 3y – z + 2 = 0
(d) Find the distance from (1, 2, 3) to the plane 2x + 3y – z + 2 = 0 (March – 2015)
Answer:
(a) Cartesian equation is [latex]\frac{x-x_{1}}{a}=\frac{y-y_{1}}{b}=\frac{z-z_{1}}{c}\), \(\frac{x-1}{3}=\frac{y-2}{1}=\frac{z-3}{2}\)

(b) Let \(\frac{x-1}{3}=\frac{y-2}{1}=\frac{z-3}{2}=\lambda\)
x = 3λ + 1, y = λ + 2, z = 2λ + 3 are the general point of the line.

(c) Equation of the plane is 2x + 3y – z + 20….(1)
putting the values of x, y, z in (1) is
2(3λ + 1) – 3(λ + 2) – (2λ + 3) + 2 = 0
7λ + 7 = 0 ⇒ λ = -1
∴ Point of intersection is x = -3 + 1 = -2; y= -1 + 2 = 1, z= -2 + 3 = 1
ie; (-2, 1, 1)

(d) Distance = \(\frac{2(1)+3(2)-3+2}{\sqrt{4+9+1}}=\frac{7}{\sqrt{14}}\)

Question 5.
Consider a plane passing through the point (5, 2, -4) and perpendicular to the line
\(\bar{r}\) = (i + j) + λ(2i + 3j – k)
(a) Write the equation in cartesian form.
(b) Find its distance from the point (1, 2, -1).
(c) Find the angle made by it with line \(\frac{x-1}{2}=\frac{y-2}{1}=\frac{z-3}{-2}\) (May – 2015)
Answer:
(a) The equation of a plane passing through the point (5, 2, 4) and perpendicular direction ratios 2, 3, -1 is
Plus Two Maths Chapter Wise Previous Questions Chapter 11 Three Dimensional Geometry 20

Plus Two Computer Science Previous Year Question Paper Say 2018

Kerala State Board New Syllabus Plus Two Computer Science Previous Year Question Papers and Answers.

Kerala Plus Two Computer Science Previous Year Question Paper Say 2018 with Answers

BoardSCERT
ClassPlus Two
SubjectComputer Science
CategoryPlus Two Previous Year Question Papers

Time: 2 Hours
Cool off time: 15 Minutes

General Instructions to candidates

  • There is a ‘cool off-time’ of 15 minutes in addition to the writing time of 2 hrs.
  • You are not allowed to write your answers nor to discuss anything with others during the ‘cool off time’.
  • Use the ‘cool off time’ to get familiar with the questions and to plan your answers.
  • Read questions carefully before you answering.
  • All questions are compulsory and the only internal choice is allowed.
  • When you select a question, all the sub-questions must be answered from the same question itself.
  • Calculations, figures, and graphs should be shown in the answer sheet itself.
  • Malayalam version of the questions is also provided.
  • Give equations wherever necessary.
  • Electronic devices except non-programmable calculators are not allowed in the Examination Hall.

Part – A

Answer all questions from 1 to 5. Each carries 1 score. (5 × 1 = 5)

Question 1.
The ability of data to be processed in more than one form is called ________
Answer:
polymorphism

Question 2.
Each node in a linked list has a ________ to the next node.
Answer:
pointer

Question 3.
NORESIZE is an attribute of ________ tag.
Answer:
<frame>

Question 4.
In client-side scripting, processing is done by ________
Answer:
browser

Question 5.
VPS stands for ________
Answer:
Virtual Private Server

Answer any 9 questions from 6 to 16. Each carries 2 scores. (9 × 2 = 18)

Question 6.
What is the self-referential structure?
Answer:
Self Referential Structures: A structure contains an element that is a pointer to the same structure.
Eg:
struct date
{
int dd, mm, yyyy;
date *ptr;
};

Question 7.
What is the difference between the two declaration statements given below:
(a) int*ptr= new int(10);
(b) int*ptr = new int[10];
Answer:
(a) Dynamic initialization with value 10.
(b) Dynamic array of size 10.

Question 8.
Differentiate static and dynamic data structures. Give an example for each.
Answer:
The main memory can be allocated in two methods.
i) Static memory allocation
ii) Dynamic memory allocation
When the amount of memory to be allocated is known in advance and memory is allocated during compilation itself, it is referred to as static memory allocation.
int x=10;

When the amount of memory to be allocated is not known in advance and it is required to allocate memory as and when required during run time, it is known as dynamic memory allocation.
‘new’ operator is used for dynamic allocation of memory syntax.
datatype *pointer variable = new datatype;
eg: int *ptr=new int;

Question 9.
Categorize the following tags in HTM L appropriately.
<br>, <hl>, <img>, <table>
Answer:

Empty tagcontainer tag
<br><h1>
<img><table>

Question 10.
Explain any two data types in JavaScript.
Answer:
Data types in JavaScript
Unlike C++ it uses only three basic data types
1. Number: Any number (whole or fractional) with or without a sign.
Eg: +1977, -38.0003, -100, 3.14157, etc.
2. String: It is a combination of characters enclosed within double-quotes.
Eg: “BVM”, “[email protected]”, etc.
3. Boolean: We can store either true or false. It is case sensitive. That means can’t use TRUE OR FALSE.

Question 11.
Write the JavaScript code to display “Welcome to Kerala” inside the <hl>, tag as shown in the HTML page.
<HTML>
<Body>
<Script lang= “javascript”>
<hl> …………. </hl>
</Body>
</Script>
</HTML>
Answer:
document.write(“Welcome to Kerala”);

Question 12.
Explain any two components of DBMS.
Answer:
Components of DBMS

  • Databases – It is the main component.
  • Data Definition Language (DDL) – It is used to define the structure of a table.
  • Data Manipulation Language (DML) – It is used to add, retrieve, modify and delete records in a database.
  • Users – With the help of programs users interact with the DBMS.

Question 13.
Consider the following table:

S.No.NameAgeTotal
1.Albert5090
2.Einstein6095
3.Kalam7094
4.Raman9098
5.Babbage9599

(a) Identify the degree and cardinality of the given table.
(b) Identify a suitable primary key for the given table.
Answer:
(a) Degree 4
Cardinality 5
(b) SI. No is the primary key

Question 14.
Write the output of the following PHP code fragment.
function justA fun ($num)
{
$num = $num * 5 + ($num + 6);
return $num;
}
echo justA fun(100);
Answer:
5*100 + (100 + 6)
= 500 + 106
= 106
Hence the output is 606

Question 15.
Compare serial and parallel computing.
Answer:

Serial computingParallel computing
A single processor is usedMultiple processors are used with shared memory
A problem is divided into a series of instructionsA problem is divided into smaller ones that can be solved simultaneously
Instructions executed sequentiallyInstructions executed simultaneously
One instruction is executed on a single processor at any momentMore than one instruction is executed on multiple processors at any moment in time.

Question 16.
How does ICT help students in learning?
Answer:
Advantages of E-Learning:

  • It can offer various courses to a large number of students from distant locations.
  • It saves journey time and money, instructor fees, etc.
  • People can enjoy e-Learning at a lower cost.
  • It enables people to do courses conducted by national or international institutions.

Answer any 9 questions from 17 to 27. Each carries 3 scores. (9 × 3 = 27)

Question 17.
What is a Pointer in C++? Declare a pointer and initialize with the name of your country.
Answer:
Pointer is a variable which points to memory location of some other variable
Syntax:
data_type ‘variable;
#include<iostream>
using namespace std;
intmain()
{
char*ptr=newchar[10]; .
ptr=”India”;
cout<<ptr;
delete ptr;
}

Question 18.
What is Procedural Oriented Programming? What are the disadvantages of Procedural Oriented Programming?
Answer:
A program in procedural language consists of a list of instructions.
Following are the disadvantages of procedural language:
a) Data is undervalued: Here the importance is on doing things rather than the data. The data has the least importance. That is, data is exposed to all and there is a chance to access or destroy this data accidentally or intentionally by many functions on a program.

b) Adding new data requires modifications to all/many functions: A program may contain many functions and these functions may access different data used in different locations. If we add new data items, we will need to modify all the functions that access the data. This is a laborious task.

c) Creating new data types is difficult: In procedural languages, some built-in data types such as int, float, double, and character are available. Extensibility is the ability to create new data types without major rewriting of codes in its basic architecture. Some programming languages are extensible but procedural languages are not extensible.

d) Provides poor real-world modeling: Procedural programming paradigm treats data and functions are different not a single unit. In this Real-life simulations are not possible.

Question 19.
Write an algorithm to add a new item into a queue.
Answer:
An algorithm is given below
Step 1: If front = 1 and rear=N or front=rear + 1
Then print “OVERFLOW” and return
Step 2: If front = Null then
Set front = 1 and rear =1
Else if rear = N then set rear = 1
Else
Set rear = rear +1
End if
Step 3: Set Queue[rear]=item
Step 4: stop

Question 20.
List and explain any three attributes of the INPUT tag in HTML.
Answer:
<Input> It is used to create input controls. Its type of attribute determines the control type.
The main values of type attributes are given below.

  1. Text-To creates a text box.
  2. Password – To create a password text box.
  3. Checkbox – To create a check box.
  4. Radio – To create a radio button.
  5. Reset – To create a Reset button.
  6. Submit – To create a submit button.
  7. Button – To create a button

Question 21.
Consider a string “Gandhiji” Write JavaScript code fragment to do the following tasks:
(a) Convert the string to upper case.
(b) Find the length of the string.
(c) Display the 3rd letter in the string.
Answer:
(a) var x=”Gandhiji”;
alert(x.toUpperCase());

(b) var x=”Gandhiji”;
alert(“The number of characters is “+ x.length);

(c) var x=”Gandhiji”;
alert(x.charAt(2));

Question 22.
What is an FTP client software? Differentiate FTP and SFTP.
Answer:
FTP (File Transfer Protocol) client software:
When a client requests a website by entering the website address. Then FTP client software helps to establish a connection between the client computer and the remote server computer. Unauthorised access is denied by using username and password hence secure our website files for that SSH (Secure Shell) FTP simply SFTP is used. Instead of http.//, it uses ftp.//:

By using FTP client s/w we can transfer(upload)the files from our computer to the web server by using the ‘drag and drop’ method. The popular FTP client software are FileZilla, CuteFTP, SmartFTP, etc.

Question 23.
List and explain different database users in DBMS.
Answer:
Users of Database

  • Database Administrator – It is a person who has central control over the DBMS.
  • Application Programmer – These are computer professionals who interact with the DBMS through programs.
  • Naive users – He is an end-user. He does not know the details of DBMS.

Question 24.
Differentiate DELETE and DROP in SQL. Write the syntax of DELETE and DROP.
Answer:

DeleteDrop
It is a DML commandIt is a DDL command
Used to delete rows in a TABLEUsed to delete the whole TABLE
Here Table exists and we can insert rowsBut here Table does not exist, so not possible to insert rows

Syntax:
Delete from <Table Name> where condition;
DropTable <Table Name>;

Question 25.
Name the different types of arrays in PHP. Explain with an example.
Answer:
Arrays in PHP: In PHP array is a collection of key and value pairs. Unlike C++, in PHP we can use either nonnegative integers or strings as keys.
Different types of arrays in PHP
Indexed arrays
Associate arrays
Multidimensional arrays.

Indexed arrays: The elements in an array can be distinguished as first or second or third etc. by the indices and the index of the first element is zero. In PHP the function array() is used to creating an array.
Syntax: $array_name=array(value1, value2, …….);
OR
$array_variable[key]=value;
Eg:$mark=array(60, 70, 80);
$course=array(“Science”, “Commerce”, “Humanities”);

Associative arrays: Arrays with named keys and string indices are called associative arrays.
Syntax:
$varibale_name=array(key1=>value1, key2=>value2,etc);
Eg:
$course=array (“Computer Science”=>”05”, “Commerce”=>”39”, “Science”=>”01”);

Question 26.
Discuss any three information security laws for protecting information shared over cyberspace.
Answer:
Guidelines for using computers over the internet

  • Emails may contain Viruses so do not open any unwanted emails.
  • Download files from reputed sources (sites).
  • Avoid clicking on pop-up Advt.
  • Most of the Viruses spread due to the use of USB drives so use cautiously.
  • Use a firewall on your computer
  • Use anti-virus and update regularly
  • Use spam blocking software
  • Take backups in regular time intervals
  • Use strong passwords, i.e a mixture of characters (a-z & A-Z), numbers, and special characters.
  • Do not use bad or rude language in social media and emails.
  • Untick ‘Remember Me’ before login.

Question 27.
Briefly explain any three applications of computational intelligence.
Answer:
Computational Intelligence is the ability to make a computer to face and solve real-life problems just like an intelligent man do it. It includes Artificial Neural Networks (ANN), Evolutionary Computation (EC), Swarm Intelligence (SI), and Fuzzy Systems (FS).

A) Artificial Neural Networks (ANN): The brain is a complex, nonlinear and parallel computer with the ability to perform tasks such as recognise the pattern, perception, and motor control. ANN is the method of simulate biological neural systems to learn, memorise, and generalize like human beings. A human brain cortex consists of 10-500 billion neurons with 60 trillion synapses(a synapse is a structure that permits a neuron to pass electrical).

B) Evolutionary Computation (EC): It is the simulation of the natural evolution, i.e. survival of the fittest. In the surrounding, we can see that the stronger must win and others will lose. EC applied for data mining, fault diagnosis, classification, scheduling, etc.

C) Swarm Intelligence (SI): Swarm Intelligence is the study of behaviour of colonies or groups of social animals, birds, insects, ants, etc. How they communicate and create and manage their own colonies beautifully.

D) Fuzzy Systems: Human beings use common sense while facing a problem, just like human beings fuzzy systems can also use common sense and behave like a human being. Fuzzy systems is used to control gear transmission and raking systems, control lifts, home appliances, controlling traffic signals, etc.

Answer any 2 questions from 28 to 30. Each carries 5 scores. (2 × 5 = 10)

Question 28.
(a) Name and explain any two attributes of the FORM tag. (2)
(b) Check the given HTML code. Fill the missing code to generate an output as shown in the figure. (3)
<HTML>
<body>
<form name= ‘loginForm’>
username:
<input type = “text”>
password:
………………………………
<input type = “………… ” value = “Login”>
………………………………
</form>
</body>
</html>
Answer:
a) <Form> attributes
1. Action – Here we give the name of the program (including the path) stored in the Webserver.
2. Method – There are 2 types of methods get and post.
3. Target – Specifies the target window for displaying the result. Values are given below.
_blank – Opens in a new window
_self – Opens in the same frame
_parent – Opens in the parent frameset
_top – Opens in the main browser window
name – Opens in the window with the specified name.

b) <inputtype=”password”>
<inputtype=”submit”>
<inputtype=”reset”>

Question 29.
(a) What are scripts in web programming? (2)
(b) Differentiate Client-side Scripting and Server-side Scripting. (3)
Answer:
a) Scripts are small programs embedded in the HTML pages, to write scripts <SCRIPT> tag is used.
Two types of scripts
1. Client scripts: These are scripts executed by the browser(client) hence reduces network traffic and workload on the server.
2. Server scripts: These are scripts executed by the server and the results as a webpage returned to the client browser.

b)

Client-Side ScriptingServer Side Scripting
Script is copied to the client browserScript is copied to the webserver
Executed by the clientExecuted by the server and result gets back to the browser window
Used for Client level validationConnect to the database in the server
It is possible to block by the userCannot possible
Client-side scripts depend on the type and version of the browserIt does not depend on the type and version of the browser

Question 30.
Write SQL queries based on the table PRODUCT given below:

PIDNameProductPrice
P1LukraSeafood4000
P5Exotic LiquidsMineral water7000
K1Tokyo TradersSoft drink5000
R3ChangIron8000
W5Tokyo TradersSoft drink3000
  1. Set PID as a primary key.
  2. Display the Name, Price of the product having the highest price.
  3. Change the Name of Supplier ‘Exotic Liquids’ to ‘Singapore Foods.’
  4. Delete all products of supplier ‘Tokyo Traders’.
  5. Display Pname and Supplier of all products in the ascending order of price.

Answer:
create table student(name varchar(20) primarykey, roll no int, marks int);

  1. Create table PRODUCT (PID varchar(2) primarykey, Name varchar(20), Product varchar(20), Price dec(8, 2));
  2. Select Name, Price from PRODUCT where Price=(Select max(Price) from PRODUCT);
  3. Update PRODUCT set Name=”Singapore Foods” where Name=”Exotic Liquids”;
  4. Delete from PRODUCT where-Name=”Tokyo Traders”;
  5. Select Name, Product from PRODUCT order by Price asc;

Plus Two Computer Science Previous Year Question Paper March 2019

Kerala State Board New Syllabus Plus Two Computer Science Previous Year Question Papers and Answers.

Kerala Plus Two Computer Science Previous Year Question Paper March 2019 with Answers

BoardSCERT
ClassPlus Two
SubjectComputer Science
CategoryPlus Two Previous Year Question Papers

Time: 2 Hours
Cool off time : 15 Minutes

General Instructions to candidates

  • There is a ‘cool off time’ of 15 minutes in addition to the writing time of 2 hrs.
  • You are not allowed to write your answers nor to discuss anything with others during the ‘cool off time’.
  • Use the ‘cool off time’ to get familiar with the questions and to plan your answers.
  • Read questions carefully before you answering.
  • All questions are compulsory and the only internal choice is allowed.
  • When you select a question, all the sub-questions must be answered from the same question itself.
  • Calculations, figures, and graphs should be shown in the answer sheet itself.
  • Malayalam version of the questions is also provided.
  • Give equations wherever necessary.
  • Electronic devices except non-programmable calculators are not allowed in the Examination Hall.

Part – A

Answer all questions from 1 to 5. Each carries 1 score. (5 × 1 = 5)

Question 1.
The wrapping up of data end functions into a single unit is called ______
Answer:
Data Encapsulation

Question 2.
In a linked list, the linked part of the last node contains ________ data.
Answer:
Null Pointer

Question 3.
Give the full form of VPS.
Answer:
Virtual Private Server

Question 4.
The number of rows in a relation is called ________
Answer:
Cardinality

Question 5.
In PHP, arrays that use string keys are called ________
Answer:
Associative array

Answer any 9 questions from 6 to 16. Each carries 2 scores. (9 × 2 = 18)

Question 6.
Define a structure named ‘Time’ with elements hour, minute, and second.
Answer:
struct time
{
int h, m, s;
};

Question 7.
Read the following C++code:
int a[5] = {10, 15, 20, 25, 30};
int *p = a;
Write the output of the following statements:
(a) cout < < * (p + 2); .
(b) cout << * p + 3;
Answer:
(a) 20(Third element)
(b) *p is 10(First element)
So *p+3 = 10 + 3 = 13.

Question 8.
List the different operations performed on data structures.
Answer:
The operations are Traversing, Searching, Inserting(Push), Deleting(Pop), Sorting and Merging

Question 9.
Write HTML tag for the following:

  1. Hyperlink to the website http://WWW.dhsekerala.gov.in
  2. [email protected]

Answer:

  1. <a href=”http://www.dhsekerala.gov.in”>
  2. <a href=mailto:”[email protected]”>

Question 10.
Describe the use of ‘action’ and ‘method’ attributes of <FQRM> tag.
Answer:
<Form> attributes

  1. Action – Here we give the name of the program (including the path) stored in the Webserver.
  2. Method – There are 2 types of methods get and post.
Get methodPost method
1. Faster1. Slower
2. To send the small volume of data2. To send a large volume of data
3. Less secure3. More secure
4. Data visible during submission4. Data not visible during submission

Question 11.
Explain the two purposes of the ‘+’ operator used in JavaScript.
Answer:
‘+’ if the operands are numbers then it adds and if one of the operands is a string then it concatenates the string.
eg. 5+3=8
“BVM”+8172=”BVM8172”

Question 12.
The Javascript function given below is used to display the sum of digits of a given number. Fill in the blanks to complete the function.
<Script language = “JavaScript”>
………. sum digit( )
{var n, s;
n = document.frm.txt1. …………;
for (s = 0; ……….; n = n/10)
s = s + ………..;
document.frm.txt2.value = s;
}
</script>
Answer:
function sum digit()
n=document.frm.txt1.value;
for(s=0; n>0: n=n/10)
s=s+n%10;

Question 13.
Explain any two constraints used in SQL.
Answer:
Constraints are used to ensure database integrity.

  1. Not Null – It ensures that a column can never have NULL values.
  2. Unique – It ensures that no two rows have the same value in a column.
  3. Primary key – Similar to unique but it can be used only once in a table.
  4. Default – We can set a default value.
  5. Auto_increment – This constraint is used to perform auto_increment the values in a column. That automatically generates serial numbers. Only one auto_increment column per table is allowed.

Question 14.
List the core data types in PHP.
Answer:
Data types are Integer, Float/Double, Boolean, and String.

Question 15.
What is meant by GIS? Give an example.
Answer:
Geographic Information System (GIS) technology is developed from the digital cartography and Computer-Aided Design (CAD) database management system. GIS as the name implies capturing, storing for future reference, checking, and displaying data related to various positions on the earth’s surface. GIS can be applied in many areas such as soil mapping, agricultural mapping, forest mapping, e-Governance, etc.

Question 16.
Define Infringement.
Answer:
Infringement (Violation): Unauthorized copying or use of Intellectual property rights such as Patents, Copyrights, and Trademarks are called intellectual property Infringement (violation). It is a punishable offense.

  • Patent Infringement
  • Trademark Infringement
  • Copy right Infringement.

Answer any 9 questions from 17 to 27. Each carries 3 scores. (9 × 3 = 27)

Question 17.
What are the different memory allocations used in C++? Explain.
Answer:
The main memory can be allocated in two methods.

  1. Static memory allocation
  2. Dynamic memory allocation

When the amount of memory to be allocated is known in advance and memory is allocated during compilation itself, it is referred to as static memory allocation.

When the amount of memory to be allocated is not known in advance and it is required to allocate memory as and when required during run time, it is known as dynamic memory allocation.

‘new’ operator is used for dynamic allocation of memory syntax,
datatype*pointer variable = new datatype;
eg: int *ptr = new int;

Question 18.
What is polymorphism? Give an example.
Answer:
Polymorphism is the ability for a message or data to be processed in more than one form. This is achieved by function overloading, operator overloading, and dynamic binding.
There are two types of polymorphism.

a) Compile time (early binding/static) polymorphism. It is the ability of the compiler to relate or bind a function call with the function definition during compilation time itself.
Examples are Function overloading and operator overloading.
Function overloading: Functions with the same name and different signatures (the number of parameters or data types are different).

Operator overloading: It gives new meaning to an existing C++ operator.
Eg: we know that + is used to add two numbers, Operator overloading assigns + to a new job such as it concatenates two strings into one string.

b) Run time (late binding/dynamic) polymorphism. It is the ability of the compiler to relate or bind a function call with the function definition during run time. It uses the concept of pointers and inheritance.

Question 19.
Write an algorithm to insert a new item into a Queue.
Answer:
The algorithm is given below:
Step 1: If front = 1 and rear=N or front = rear + 1.
Then print “OVERFLOW” and return
Step 2: If front = Null then
Set front = 1 and rear = 1
Else if rear = N then set rear = 1
Else
Set rear = rear+1
End if
Step 3: Set Queue[rear] = item
Step 4: stop

Question 20.
Differentiate between a static web page and a dynamic web page.
Answer:

Static web pagesDynamic web pages
Content and layout is fixedContent and layout are changed frequently
Never use databaseDatabase is used
Run by the browserIt runs on the server and the result gets back to the client(browser)
Easy to developNot at all easy

Question 21.
Briefly explain the different ways in which a JavaScript code can be inserted into a web page.
Answer:
Ways to add scripts to a web page.
1. Inside <BODY> section
Scripts can be placed inside the <BODY> section.

2. Inside<HEAD> section: Scripts can be placed inside the <HEAD> section. This method is a widely accepted method.

3. External (another) JavaScript file: We can write scripts in a file and save it as a separate file with the extension js. The advantage is that this file can be used across multiple HTML files and can be enhanced the speed of the page loading.

Question 22.
Distinguish between shared hosting and dedicated hosting.
Answer:
1. Shared Hosting: This type of hosting shares resources, like memory, disk space, and CPU hence the name shared. Several websites share the same server. This is suitable for small websites that have less traffic and it is not suitable for large websites that have large bandwidth, large storage space, and have a large volume of traffic.

E.g.: Shared hosting is very similar to living in an Apartment (Villas) complex. All residents are in the same location and must share the available resources (Car parking area, Swimming pool, Gymnasium, playground, etc) with everyone.

2. Dedicated Hosting: A web server and its resources are exclusively for one website that has a large volume of traffic mean a large volume of requests by the visitors. Some Govt, departments, or large organizations require uninterrupted services for that round a clock power supply is needed. It is too expensive but it is more reliable and provides good service to the public.

E.g.: It is similar to living in an Our own house. All the resources in your house is only for you. No one else’s account resides on the computer and would not be capable of tapping into your resources.

Question 23.
Explain different levels of data abstraction in DBMS.
Answer:
Database Abstraction: Abstraction means hiding, it hides certain details of how data is stored and maintained.
Levels of Database Abstraction

  1. Physical Level (Lowest Level) – It describes how the data is actually stored in the storage medium.
  2. Logical Level (Next Higher Level) – It describes what data are stored in the database.
  3. View Level (Highest level) – It is closest to the users. It is concerned with the way in which the individual users view the data.

Question 24.
Describe the ‘union’ and ‘intersection’ operations in relational algebra with suitable examples.
Answer:
Union Operation (∪) – All tuples appearing in either or both of two relations.
Intersection operation (∩) – All tuples appearing in both relations.

Question 25.
Write PHP code to display all even numbers below 100.
Answer:
<?php
echo”All even numbers below 100″;
echo”<br>=================”;
for($i=2; $i<=100; $i=$i+2)
{
echo”<br>”.$i; ‘
}

Question 26.
Explain the cloud service models.
Answer:
Cloud service models (3 major services)
1. Software as a Service (SaaS): A SaaS provider company provides more services on demand such as they allow to access both resources and applications.
Examples are Google Docs, Adobe creative cloud, Microsoft Office 365, Facebook.com, etc.

2. Platform as a Service (PaaS): A PaaS provider company provides subscribers access to the components that they require to develop and operate applications over the Internet.
Example: LAMP platform (Linux, Apache Server, MySQL, and PHP), ASP.NET, PHP, and Python, Google’s App Engine, Microsoft Azure, Force.com, etc.

3. Infrastructure as a Service (IaaS): It provides basic storage devices and computing capabilities as standardized services over the network.
Example: Amazon Web Services, Joyent, AT&T, GoGrid, etc.

Question 27.
List and explain any three e-learning tools.
Answer:
e-Learning tools
a) Electronic books reader (eBooks): With the help of a tablet or portable computer or arty another device we can read digital files by using an s/w is called electronic books reader.

b) e-text: The electronic format of textual data is called e-Text.

c) Onlinechat: Real-time exchange of text or audio or video messages between two or more people over the Internet.

d) e-Content: The data or information such as text, audio, video, presentations, images, animations, etc, are stored in electronic format.

e) Educational TV channels: TV channels dedicated only for the e-Learning purpose.
Eg.: VICTERS (Virtual Classroom Technology on Edusat for Rural Schools OR Versatile ICT Enabled Resources for Students).

Answer any 2 questions from 28 to 30. Each carries 5 scores. (2 × 5 = 10)

Question 28.
Explain the various attributes of the <BODY> tag.
Answer:
Attributes of <body> tag
1. BGCOLOR – Specifies the background color for the document body
Eg. <BODY BGCOLOR = ”RED”>

2. BACKGROUND – Sets the image as the background for the document body
Eg. <BODY BACKGROUNG= “C:\result.jpg”>.

3. TEXT-Specifies the color of the text content of the page.
Eg. <BODY TEXT= “Red”>

4. Link – Specifies colour of the hyperlinks that are not visited by the user.

5. ALINK – Specifies the colour of hyperlinks.

6. VLINK – Specifies the color of hyperlinks which are already visited by the viewer. ‘
Eg. < BODY ALINK= “Cyan” LINK-’ Magenta”
VLINK= “Orange”>.

7. Leftmargin and Right margin-Sets margin from the left and top of the document window.

Question 29.
Write HTML code to display the following table in a web page:
Result of ABC school

YearStudentsPass Percentage
RegisteredPassed
201420013065
201520015075
201620016080

Answer:

<html>
<head>
<title>Table
</title>
<body bgcolor=”cyan”>
<h1 align=”center”>Result of ABC school</h1>
<tableborder=”1"align=”center">
<tralign=”center”> •
<th rowspan=”2">Year</th>
<th colspan=”2">Students</th>
<th rowspan=”2">Pass<br>Percentage</th>
</tr>
<tr align=”center”>
<th>Registered</th>
<th>Passed</th>
</tr>
<tr align="center”>
<td>2014</td>
<td>200</td>
<td> 130</td >
<td>65</td>
</tr>
<tralign=”center”>
<td>2015</td>
<td>200</td>
<td>150</td>
<td>75</td>
</tr><tralign=”center”>
<td>2016</td>
<td>200</td>
<td > 160</td >
<td>80</td>
</tr>
</table>
</body>
</html>

Question 30.
A table named ‘student’ with fields Roll no, Name, Batch, Mark, Grade is given. Write SQL statements for the following:

  1. To display the details of all students in the ‘Science’ batch.
  2. To display the details of these students having grade A or A+.
  3. To count the number of students in each batch.
  4. To change the grade of the student to A+ whose Roll no. is 50.
  5. Remove the details of the student whose Roll no. is 10.

Answer:

  1. select * from student where Batch=”Science”;
  2. select * from student where Grade in(“A”,”A+”);
  3. select Batch,count(*) from student group by Batch;
  4. update student set Grade =”A+”; where Roll_no=50;
  5. delete from student where Roll_no =10;

Plus Two Maths Chapter Wise Previous Questions Chapter 10 Vector Algebra

Kerala State Board New Syllabus Plus Two Maths Chapter Wise Previous Questions and Answers Chapter 10 Vector Algebra.

Kerala Plus Two Maths Chapter Wise Previous Questions Chapter 10 Vector Algebra

Plus Two Maths Vector Algebra 3 Marks Important Questions

Question 1.
(i) With help of a suitable figure for any three vectorsa,bandc show that \((\bar{a}+\bar{b})+\bar{c}=\bar{a}+(\vec{b}+\bar{c})\)
(ii) If \(\bar{a}\) = i – j + k and \(\bar{b}\) = 2i – 2j – k. What is the projection of a on b? (March – 2011)
Answer:
(i) Answered in previous years questions
No. 1(ii) (6 Mark question)
(ii) Projection of \(\bar{a} \text { on } \bar{b}=\frac{\bar{a} \cdot \bar{b}}{|\bar{b}|}=\frac{2+2-1}{\sqrt{4+4+1}}=1\)

Question 2.
(i) If \(\bar{a}\) = 3i – j – 5k and \(\bar{b}\) = i – 5j + 3k Show that \(\bar{a}\) + \(\bar{b}\) and a bare perpendicular.
(ii) Given the position vectors of three points as A(i – j + k); B(4i + 5j + 7k) C(3i + 3j + 5k)
(a)Find \(\bar{AB}\) and \(\bar{BC}\)
(b) Prove that A,B and C are collinear points. (March – 2011)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 10 Vector Algebra 1

Question 3.
(i) Write the unit vector in direction of i + 2j – 3k.
(ii) If \(\overline{P Q}\) = 31 + 2j — k and the coordinate of P are(1, -1,2) , find the coordinates of Q. (May – 2012)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 10 Vector Algebra 2

Question 4.
(a) The angle between the vectors \(\bar{a}\) and \(\bar{b}\) such that \(|\vec{a}|=|\bar{b}|=\sqrt{2}\)
\(\bar{a}\).\(\bar{b}\) = 1 is
\(\begin{array}{lll}
\text { (i) } \frac{\pi}{2} & \text { (ii) } \frac{\pi}{3} & \text { (iii) } \frac{\pi}{4} & \text { (iv) } 0
\end{array}\)
(b) Find the unit vector along \(\bar{a}-\bar{b}\) where \(\bar{a}\) = i + 3j – k and \(\bar{b}\) 3i + 2j + k (March -2016)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 10 Vector Algebra 3

Plus Two Maths Vector Algebra 4 Marks Important Questions

Question 1.
Consider the vectors \(\bar{a}\) = 21+ j – 2k and \(\bar{b}\) = 6i – 3j + 2k.
(i) Find \(\bar{a} \bar{b}\) and \(\bar{a} \times \bar{b}\).
(ii) Verity that \(|\bar{a} \times \bar{b}|=|\vec{a}|^{2}|\bar{b}|^{2}-(\bar{a} \cdot \bar{b})^{2}\) (March – 2012)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 10 Vector Algebra 4

Question 2.
(i) For any three vectors \(\bar{a}, \bar{b}, \bar{c}\), show that \(\bar{a} \times(\bar{b}+\bar{c})+\bar{b} \times(\bar{c}+\bar{a})+\bar{c} \times(\bar{a}+\bar{b})=0\)
(ii) Given A (1, 1, 1), B (1, 2, 3), C (2, 3, 1) are the vertices of MBCa triangle. Find the area of the ∆ABC (May – 2012)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 10 Vector Algebra 5

Question 3.
Consider A (2, 3, 4) , B (4, 3, 2) and C (5, 2, -1) be any three points
(i) Find the projection of \(\overline{B C}\) on \(\overline{A B}\)
(ii) Find the area of triangle ABC (March – 2013)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 10 Vector Algebra 6

Question 4.
(i) Find the angle between the vectors \(\bar{a}\) =3i + 4j + k and \(\bar{b}\) = 2i + 3j – k
(ii) The adjacent sides of a parallelogram are \(\bar{a}\) = 3i + λj + 4k and \(\bar{b}\) = i – λj + k
(a) Find \(\bar{a} \times \bar{b}\)
(b) If the area of the parallelogram is square units, find the value of A (May – 2013)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 10 Vector Algebra 7

Question 5.
Let \(\bar{a}\) = 2i – j + 2k and \(\bar{b}\) = 6i + 2j + 3k
(i) Find a unit vector in the direction of \(\bar{a}\) + \(\bar{b}\)
(ii) Find the angle between a and b (March – 2014)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 10 Vector Algebra 8

Question 6.
Consider the triangle ABC with vertices A(1, 1, 1) , B (1, 2, 3) and C (2, 3, 1)
(i) Find \(\overline{A B}\) and \(\overline{A C}\)
(ii) Find \(\overline{A B}\) x \(\overline{A C}\)
(iii) Hence find the area of the triangle (March – 2014)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 10 Vector Algebra 9

Question 7.
Consider the vectors \(\bar{a}\) = i – 7j + 7k; \(\bar{b}\) = 3i – 2j + 2k
(a) Find \(\bar{a b}\).
(b) Find the angle between \(\bar{a}\) and \(\bar{b}\).
(c) Find the area of parallelogram with adjacent sides \(\bar{a}\) and \(\bar{b}\). (May – 2014)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 10 Vector Algebra 10

Question 8.
(a) If the points A and B are (1, 2, -1) and (2, 1, -1) respectively, then is
(i) i + J
(ii) i – J
(iii) 2i + j – k
(iv) i + j + k
(b) Find the value of for which the vectors 2i – 4j + 5k, i – λj + k and 3i + 2j – 5k are coplanar.
(c) Find the angle between the vectors a = 2i + j – k and b = i – j + k (March – 2016)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 10 Vector Algebra 11

Question 9.
(i) \((\bar{a}-\bar{b}) \times(\bar{a}+\bar{b})\) is equaito
\(\begin{array}{lll}
\text { (a) } \bar{a} & \text { (b) }|\bar{a}|^{2}-|\bar{b}|^{2} & \text { (c) } \bar{a} \times \bar{b} \text { (d) } 2(\bar{a} \times \bar{b})
\end{array}\)

(ii) If \(\bar{a}\) and \(\bar{b}\) are any two vectors, then
\((\bar{a} \times \bar{b})^{2}=\left|\begin{array}{ll}
\bar{a} \cdot \bar{a} & \bar{a} \cdot \bar{b} \\
\bar{a} \cdot \bar{b} & \bar{b} \bar{b}
\end{array}\right|\)

(iii) Using vectors, show that the points A(1, 2, 7), B(2, 6, 3), C(3, 10, -i) are collinear. (May – 2016)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 10 Vector Algebra 12

Plus Two Maths Vector Algebra 6 Marks Important Questions

Question 1.
(i) Find a vector in the direction of \(\bar{r}\) = 3E – 4j that has a magnitude of 9.
(ii) For any three vectors \(\bar{a,b}\) and \(\bar{c}\), and Prove that \((\bar{a}+\bar{b})+\bar{c}=\bar{a}+(\bar{b}+\bar{c})\).
(iii) Find a unit vector perpendicular to \(\bar{a}+\bar{b}\) and \(\bar{a}-\bar{b}\), where \(\bar{a}\) = i – 3j + 3k and \(\bar{b}\) and \(/bar{c}\) = 3E—3j+2k. (March – 2010)
Answer:
(i) Unit vector of magnitude 9
Plus Two Maths Chapter Wise Previous Questions Chapter 10 Vector Algebra 13

Question 2.
Let A(2, 3, 4), B(4, 3, 2) and C(5, 2, -1) be three points
(i) Find \(\overline{A B}\) and \(\overline{B C}\)
(ii) Find the projection of \(\overline{B C}\) on \(\overline{A B}\)
(iii) Fiñd the area of the triangle ABC. (May – 2010)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 10 Vector Algebra 14

Question 3.
ABCD s a parallelogram with A as the origin, \(\bar{b}\) and \(\bar{d}\) are the position vectors of B and D respectively.
Plus Two Maths Chapter Wise Previous Questions Chapter 10 Vector Algebra 15
(i) What is the position vector of C?
(ii) What is the angle between \(\bar{AB}\) and \(\bar{AD}\)?
(iii) If \(|\overrightarrow{A C}|=|\overrightarrow{B D}|\), show that ABCD is a rectangle. (May – 2011)
Answer:
(i) Since ABCD is a parallelogram with A as the
Plus Two Maths Chapter Wise Previous Questions Chapter 10 Vector Algebra 16

Question 4.
(a) If \(\bar{a}, \bar{b}, \bar{c}, \bar{d}\) respectively are the position vectors representing the vertices A,B,C,D of a parallelogram, then write \(/bar{d}\) in terms of \(\bar{a}, \bar{b}, \bar{c}\).
(b) Find the projection vector of \(/bar{b}\) = i + 2j + k along the vector \(/bar{a}\) = 21 – i – j + 2k. Also write \(/bar{b}\) as the sum of a vector along \(/bar{a}\) and a perpendicular to \(/bar{a}\).
(C) Find the area of a parallelogram for which the vectors 21 + j, 31 + j +4k are adjacent sides. (March – 2015)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 10 Vector Algebra 17

Question 5.
(a) Write the magnitude of a vector \(/bar{a}\) in terms of dot product.
(b) If \(\bar{a}, \bar{b}, \bar{a}+\bar{b}\) are unit vectors, then prove that the angle between \(/bar{a}\) and \(/bar{b}\) is \(\frac{2 \pi}{3}\)
(c) If 2i + j – 3k and mi + 3j – k are perpendicular to each other, then find ‘m’.
Also find the area of the rectangle having these two vectors as sides. (March – 2015)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 10 Vector Algebra 18

Question 6.
Consider the triangle ABC with vertices A(1, 2, 3), B(-1, 0, 4), C(0, 1, 2)
(a) Find \(\overline{A B}\) and \(\overline{A C}\)
(b) Find \(\angle A\)
(c) Find the area of triangle ABC. (May – 2015)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 10 Vector Algebra 19

Plus Two Maths Chapter Wise Previous Questions Chapter 9 Differential Equations

Kerala State Board New Syllabus Plus Two Maths Chapter Wise Previous Questions and Answers Chapter 9 Differential Equations.

Kerala Plus Two Maths Chapter Wise Previous Questions Chapter 9 Differential Equations

Plus Two Maths Differential Equations 3 Marks Important Questions

Question 1.
Form a differential equation of the family of circles having a centre on y-axis and radius 3 units. (May -2013)
Answer:
The equation of the circle passing through the point (O,k)and radius 3 is of the form
Plus Two Maths Chapter Wise Previous Questions Chapter 9 Differential Equations 1

Question 2.
Consider the Differential equation
\(\frac{d^{2} y}{d x^{2}}+y=0\)
(i) Write the order and degree.
(ii) Verify that y = a cos x + b sin x where a,b ∈ R is a solution of the given DE. (March – 2014)
Answer:
(i) Order = 2; Degree = I
(ii) Given; y = acosx + bsin x
y1 = – asin x + bcos x
y2 = – acos x – bsin x
We have; y2 = – (a cos x + b sin x)
⇒ y2 = -y ⇒ y2 + y = 0

Plus Two Maths Differential Equations 4 Marks Important Questions

Question 1.
If cosx\(\frac{d y}{d x}\) + y sin x = tan2 x is a DE then
(i) Find its order and degree.
(ii) Find its general solution. (May -2010)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 9 Differential Equations 2

Question 2.
(i) Write the order and degree of the DE
\(\left[\frac{d y}{d x}\right]^{2}+\frac{d y}{d x}-\sin ^{2} y=0\)
(ii) Solve the \(\frac{d y}{d x}+2 y \tan x=\sin x\) (May-2011)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 9 Differential Equations 3

Question 3.
(i) The general solution of the DE \(\frac{d y}{d x}=e^{x-y} \text { is }\)
(a) ey + ex = c
(b) ey ex = c
(c) e-y + e-x = c
(d) e-y – ex = c
(ii) Solve the DE \(\frac{d y}{d x}=\frac{2 x y}{1+x^{2}}+x^{2}+2\) (March – 2013)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 9 Differential Equations 4

Question 4.
(a) Consider the family of all circles having their centre at the point (1,2). Write the equation of the family. Write the corresponding differential equation.
(b) Write the integrating factor of the differential equation
\(\cos x \frac{d y}{d x}+y=\sin x, \quad 0 \leq x<\frac{\pi}{2}\) (March – 2015)
Answer:
(a) The equation of the circle ¡s
Plus Two Maths Chapter Wise Previous Questions Chapter 9 Differential Equations 5

Question 5.
(a) Write the order and degree of the differential equations.
\(x y\left(\frac{d^{2} y}{d x^{2}}\right)^{2}+x\left(\frac{d y}{d x}\right)^{3}-y \frac{d y}{d x}=0\)

(b) Find the general solution of the differential equation ylog ydx – xdy = 0
(c) Find the integrating factor of the differential equation \(x \frac{d y}{d x}-y=2 x^{2}\) (May -2015)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 9 Differential Equations 6
Plus Two Maths Chapter Wise Previous Questions Chapter 9 Differential Equations 7

Question 6.
(a) y = a cosx +b sin x is the solution of the differential equation
Plus Two Maths Chapter Wise Previous Questions Chapter 9 Differential Equations 8
(b) Find the solution of the differential equation \(x \frac{d y}{d x}+2 y=x^{2}, \quad(x \neq 0)\) given that y = 0 when x=1. (March – 2016)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 9 Differential Equations 9

Plus Two Maths Differential Equations 6 Marks Important Questions

Question 1.
(i) Form the DE corresponding to the Function y = aex + be2x
(ii) State the order and degree of the above DE.
(iii) Solve \(x \frac{d y}{d x}=x+y\) (March – 2009)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 9 Differential Equations 10
Plus Two Maths Chapter Wise Previous Questions Chapter 9 Differential Equations 11

Question 2.
(i) Form the DE corresponding to the function Xy = C2
(ii) Consider the DE (x2 + y2 ) dx = 2xydy
(a) Write the DE in the ton \(\frac{d y}{d x}=g\left[\frac{y}{x}\right]\)
(b) Solve the DE completely (May -2009, May -2013)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 9 Differential Equations 12

Question 3.
(i) Equation of a circle touching the y-axis at origin is x2 + y– 2ax = 0. Find the DE of all such circles.
(ii) SolvetheDE \(\left(1+x^{2}\right) \frac{d y}{d x}+y=\tan ^{-1} x\) (March – 2010)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 9 Differential Equations 13
Plus Two Maths Chapter Wise Previous Questions Chapter 9 Differential Equations 14

Question 4.
(i) Solution of the DE y – y = 0 is y = ………….
(ii) Solve the DE \(\Rightarrow \frac{d y}{d x}+y \sec x=\tan x\)
(iii) Form the DE of the family of ellipse having foci on the x-axis and centre at the origin. (March-2011)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 9 Differential Equations 15
Plus Two Maths Chapter Wise Previous Questions Chapter 9 Differential Equations 16

Question 5.
Consider the DE \(x d y-y d x=\sqrt{x^{2}+y^{2}} d x\)
(i) Express it in the form \(\frac{d y}{d x}\) = F(x, y)
(ii) Find the general solution. (March -2012; Edumate -2017)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 9 Differential Equations 17
Plus Two Maths Chapter Wise Previous Questions Chapter 9 Differential Equations 18

Question 6.
(i) Prove that the DE is (3xy + y2) dx + (x2 + xy) dy = 0 a homogeneous DE of degree 0.
(ii) Solve the DE (3xy + y2) dx + (x2 + xy) dy = 0 (May —2012, Edumate -2017)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 9 Differential Equations 19
Plus Two Maths Chapter Wise Previous Questions Chapter 9 Differential Equations 20
Plus Two Maths Chapter Wise Previous Questions Chapter 9 Differential Equations 21

Question 7.
Consider the differential equation \(\frac{d y}{d x}-3 \cot x y=\sin 2 x\)
(a) Find its integrating factors.
(b) Fînd its solution, given that y = 2 When x = \(\frac{\pi}{2}\). (May-2014)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 9 Differential Equations 22
Plus Two Maths Chapter Wise Previous Questions Chapter 9 Differential Equations 23

Plus Two Maths Chapter Wise Previous Questions Chapter 8 Application of Integrals

Kerala State Board New Syllabus Plus Two Maths Chapter Wise Previous Questions and Answers Chapter 8 Application of Integrals.

Kerala Plus Two Maths Chapter Wise Previous Questions and Answers Chapter 8 Application of Integrals

Plus Two Maths Application of Integrals 4 Marks Important Questions

Question 1.
(i) The area bounded by the curve y = f(x) x-axis and the line x= a and x= b is……
(ii) Find the area enclosed between the Parabola y = x2 and the straight line 2x – y + 3 = 0 (March – 2010)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 8 Application of Integrals 1

Question 2.
Find the area enclosed between the curve x2 = 4y and the line x = 4y – 2 (March -2011)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 8 Application of Integrals 2
Plus Two Maths Chapter Wise Previous Questions Chapter 8 Application of Integrals 3

Question 3.
(i) Area of the shaded portion in the figure is equal to
Plus Two Maths Chapter Wise Previous Questions Chapter 8 Application of Integrals 4
(ii) Consider the curves y = x2, x = 0, y = 1, y = 4.
Draw a rough sketch and shade the region bounded by these curves, Find area of the shaded region.
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 8 Application of Integrals 5

Question 4.
Consider the following figure:
Plus Two Maths Chapter Wise Previous Questions Chapter 8 Application of Integrals 6
(i) Find the point of Intersection P of the circle x2 + y2 = 32 and the line y = x.
(ii) Find the area of the shaded region. (EDUCATE – 2017; March – 2013; March – 2014)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 8 Application of Integrals 7

Question 5.
(a) The area bounded by the curve, above the x-axis, between x = a and x = b is
Plus Two Maths Chapter Wise Previous Questions Chapter 8 Application of Integrals 8
(b) Find the area of the circle x2 + y2 = 4 using integration. (March – 2016)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 8 Application of Integrals 9
Plus Two Maths Chapter Wise Previous Questions Chapter 8 Application of Integrals 10

Question 6.
(i) The area bounded by y = 2cosx , the x-axis from x = 0 to x = \(\frac{\pi}{2}\) is
(a) 0
(b) 1
(c) 2
(d) -1
(ii) Find the area of the region bounded by the y2 = 4ax and x2 = 4ay, a > 0 (March – 2017)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 8 Application of Integrals 11
When x = 4a, y = 4a and x = 0, y = 0.
Therefore the point is (0, 0) and (4a, 4a).
Plus Two Maths Chapter Wise Previous Questions Chapter 8 Application of Integrals 12.

Plus Two Maths Application of Integrals 6 Marks Important Questions

Question 1.
Consider the circle x2 + y2 = 16 and the straight line \(y=\sqrt{3} x\) as shown ¡n the figure
Plus Two Maths Chapter Wise Previous Questions Chapter 8 Application of Integrals 13
(i) Find the points A and B as shown in the figure.
(ii) Find the area of the shaded region in the figure using definite integral. (May -2010)
Answer:
(i) The point of intersection of x2 + y= l6 and
Plus Two Maths Chapter Wise Previous Questions Chapter 8 Application of Integrals 14

Question 2.
(i) Draw the rough sketch of \(\frac{x^{2}}{4}+\frac{y^{2}}{9}=1\)
(ii) Find the area bounded by the above curve using integration. (May – 2011)
Answer:
(i) The curve is an ellipse.
Plus Two Maths Chapter Wise Previous Questions Chapter 8 Application of Integrals 15
Plus Two Maths Chapter Wise Previous Questions Chapter 8 Application of Integrals 16

Question 3.
(i) Find the area enclosed between the curve y2 = x, x = 1, x = 4 and x-axis.
(ii) Using ntegration, find the area of the region bounded by the triangle whose vertices are (1, 0), (2, 2) and (3, 1). (March-2012)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 8 Application of Integrals 17
Required area ΔABC = Area ΔAB2
+ Area 2BC3 – Area ΔAC3
Equation AC is y = 2(x – 1)
Equation BC is y = 4 – x
Equation AB is y = 1/2 (x – 1)
Plus Two Maths Chapter Wise Previous Questions Chapter 8 Application of Integrals 18

Question 4.
Plus Two Maths Chapter Wise Previous Questions Chapter 8 Application of Integrals 19
Using the above figure
Find the equation of AB.
Findthe point P.
Find the area of the shaded region by integration. (May – 2013)
Answer:
(i) The equation of a line passing through (0,2)
Plus Two Maths Chapter Wise Previous Questions Chapter 8 Application of Integrals 20

Question 5.
Consider the ellipse \(\frac{x^{2}}{9}+\frac{y^{2}}{4}=1\) and the line \(\frac{x}{3}+\frac{y}{2}=1\).
(a) Find the points where the line intersects the ellipse?
(b) Shade the smaller region bounded by the ellipse and the line.
(c) Find the area of the shaded region. (May – 2014)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 8 Application of Integrals 21
Plus Two Maths Chapter Wise Previous Questions Chapter 8 Application of Integrals 22
Plus Two Maths Chapter Wise Previous Questions Chapter 8 Application of Integrals 23

Question 6.
Consider the function f(x) = |x| + 1; g(x) = 1 – |x|
(a) Sketch the graph and shade the enclosed region between them.
(b) Find the area of the shaded region. (March – 2015)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 8 Application of Integrals 24
(b) The equation of the line through AB is
Plus Two Maths Chapter Wise Previous Questions Chapter 8 Application of Integrals 25

Question 7.
Using the given figure answer the following questions.
Plus Two Maths Chapter Wise Previous Questions Chapter 8 Application of Integrals 26
Define the equation of the given curve.
Find the area of the enclosed region.
Find the area when a = lo and b = 5. (March – 2011; May – 2015; March – 2017)
Answer:
(i) The figure represents an ellipse with equation
Plus Two Maths Chapter Wise Previous Questions Chapter 8 Application of Integrals 27
Ellipse is symmetric w.r.t coordinate axles. Therefore the area of the enclosed region is same as four times area enclosed by the curve in first quadrant.
Plus Two Maths Chapter Wise Previous Questions Chapter 8 Application of Integrals 28

Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals

Kerala State Board New Syllabus Plus Two Maths Chapter Wise Previous Questions and Answers Chapter 7 Integrals.

Kerala Plus Two Maths Chapter Wise Previous Questions and Answers Chapter 7 Integrals

Plus Two Maths Application of Derivatives 3 Marks Important Questions

Question 1.
Find the following integrals. (May -2011)
\(\begin{array}{l}
\text { (i) } \int x^{2} e^{2 x} d x \\
\text { (ii) } \int e^{x} \sin x d x
\end{array}\)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 1

Question 2.
(i) \(\int e^{x} \sec x(1+\tan x) d x=\ldots \ldots\)
(a) ex cosx + c (b) ex sec x + c
(C) ex tanx + c (d) ex sin x + c
(ii) Find \(\int \sin 2 x \cos 3 x d x\) (March – 2014)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 2

Question 3.
Find the following integrals.
(i) \(\begin{array}{l}
\text { (i) } \int \frac{1}{(x+1)(x+2)} d x \\
\text { (ii) } \int \frac{2 x-1}{(x-1)(x+2)^{2}} d x
\end{array}\) (March – 2014)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 3

Plus Two Maths Application of Derivatives 4 Marks Important Questions

Question 1.
Consider the integral \(I=\int_{0}^{\pi} \frac{x \sin x}{1+\cos ^{2} x} d x\)
(i) Express \(I=\frac{\pi}{2} \int_{0}^{\pi} \frac{\sin x}{1+\cos ^{2} x} d x\)
(ii) Show that \(I=\frac{\pi^{2}}{4}\) (March – 2012)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 4

Question 2.
(i) Evaluate: \(\int_{2}^{3} \frac{x}{x^{2}+1} d x\)
(ii) Evaluate: \(\int_{0}^{\pi} \frac{x}{1+\sin x} d x\) (March – 2014)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 5
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 6

Question 3.
(a) What is the value of \(\int_{0}^{1} x(1-x)^{9} d x\) If the
\(\begin{array}{llll}
\text { (i) } \frac{1}{10} & \text { (ii) } \frac{1}{11} & \text { (iii) } \frac{1}{90} & \text { (iv) } \frac{1}{110}
\end{array}\)
(b) Find \(\int_{0}^{1}(2 x+3) d x\) of a sum. (March – 2015)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 7

Question 4.
Evaluate \(\int_{0}^{x} \log (1+\cos x) d x\)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 8

Question 5.
Find \(\int_{0}^{5}(x+1) d x \text { as limit of a sum. }\)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 42

Question 6.
Evaluate \(\int_{0}^{4} x^{2} d x\) as the limit of a sum. (March – 2017)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 10

Plus Two Maths Application of Derivatives 6 Marks Important Questions

Question 1.
(i) Fill in the blanks; \(\int \frac{1}{x} d x=\)_____
(ii) Evaluate \(\int \frac{5 x+1}{x^{2}-2 x-35} d x\)
(iii) Integrate with respect to x. \(\sqrt{x^{2}+4 x+8}\) (March – 2010)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 11
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 12

Question 2.
(i) Evaluate \(\int-\frac{\cos e c^{2} x}{\sqrt{\cot ^{2} x+9}} d x\)
(ii) Evaluate \(\int\left(\cos ^{-1} x\right)^{2} d x\) (May -2010)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 13

Question 3.
(i) Evaluate \(\int_{0}^{\pi} \frac{x \sin x}{1+\cos ^{2} x} d x\)
(ii) Evaluate \(\int_{0}^{2} e^{x} d x \text { as limit of a sum. }\) (May -2010)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 14
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 15

Question 4.
(i) Fill in the blanks \(\int \cot x d x=\)_____
(ii) Evaluate the integrals
\(\begin{array}{l}
\text { (a) } \int \sin 2 x \cos 4 x d x \\
\text { (b) } \int \frac{x}{(x+1)(x+2)} d x
\end{array}\) (March -2011)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 16

Question 5.
(i) Evaluate \(\int_{0}^{1} x d x\) as the limit of a sum.
(ii) Evaluate \(\int_{0}^{1} x(1-x)^{n} d x\) (March – 2011)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 17

Question 6.
(i) Evaluate \(\int_{1}^{2} \frac{1}{x(1+\log x)^{2}} d x\)
(ii) Evaluate \(\int_{0}^{3}\left(2 x^{2}+3\right) d x\) as the limit of a sum. (May – 2011)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 18
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 19

Question 7.
(i) What is \(\int \frac{1}{9+x^{2}} d x=?\)
(ii) Evaluate the integrals \(\int \frac{1}{1+x+x^{2}+x^{3}} d x\) (May – 2012)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 20
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 21

Question 8.
(i) Evaluate \(\int_{0}^{3} f(x) d x\)
where \(f(x)=\left\{\begin{array}{ll}
x+3, & 0 \leq x \leq 2 \\
3 x, & 2 \leq x \leq 3
\end{array}\right.\)

(ii) Prove that \(\int_{0}^{1} \log \left(\frac{x}{1-x}\right) d x=\int_{0}^{1} \log \left(\frac{1-x}{x}\right) d x\) Find the value of \(\int_{0}^{1} \log \left(\frac{x}{1-x}\right) d x\) (May – 2012)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 22

Question 9.
(i) Find \(\int \cot x d x=\ldots \ldots\)
(ii) Find \(\int x \log x d x\)
(iii) Find \(\int \frac{x-1}{(x-2)(x-3)} d x\) (March – 2013)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 23

Question 10.
Evaluate
\(\text { (i) } \int \frac{x+3}{\sqrt{5-4 x-x^{2}}} d x\)
\(\text { (ii) } \int_{\pi / 6}^{\pi / 3} \frac{d x}{1+\sqrt{\tan x}}\) (May – 2013)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 24
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 25
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 26

Question 11.
Evaluate
\(\begin{array}{l}
\text { (i) } \int x^{2} \tan ^{-1} x d x \\
\text { (ii) } \int_{-1}^{2} x^{3}-x d x
\end{array}\) (May – 2013)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 27
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 28
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 29

Question 12.
Evaluate \(\int_{0}^{\pi / 4} \log (1+\tan x) d x\) (March – 2013)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 30

Question 13.
(a) The value of \(\int_{\frac{-\pi}{2}}^{\frac{\pi}{2}} \cos x d x\) (May – 2014)
(b) Prove that \(\int_{0}^{\pi} \frac{x}{a^{2} \cos ^{2} x+b^{2} \sin ^{2} x} d x=\frac{\pi^{2}}{2 a b}\)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 31
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 32

Question 14.
(a) \(\int \frac{1}{x^{2}+a^{2}} d x=\)
(b) Find \(\int \frac{1}{9 x^{2}+6 x+5} d x\)
(c) Find \(\int \frac{x}{(x-1)^{2}(x+2)} d x\) (May – 2014)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 33
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 34

Question 15.
Integrate the following
\(\begin{array}{l}
\text { (a) } \frac{x-1}{x+1} \\
\text { (b) } \frac{\sin x}{\sin (x-a)} \\
\text { (c) } \frac{1}{\sqrt{3-2 x-x^{2}}}
\end{array}\) (March – 2015)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 35

Question 16.
(a) Prove that \(\int \cos ^{2} x d x=\frac{x}{2}+\frac{\sin 2 x}{4}+c\)
(b)Find \(\int \frac{1}{\sqrt{2 x-x^{2}}} d x\)
(c) Find \(\int x \cos x d x\) (May – 2015)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 36

Question 17.
Find the following:
\(\begin{array}{l}
\text { (i) } \int \frac{1}{x\left(x^{7}+1\right)} d x \\
\text { (ii) } \int_{1}^{4}|x-2| d x
\end{array}\)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 37
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 38

Question 18.
Find \(\int_{0}^{\frac{\pi}{2}} \log \sin x d x\)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 39
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 40

Question 19.
Find the following: \(\begin{array}{l}
\text { (i) } \int \cot x \log (\sin x) d x \\
\text { (ii) } \int \frac{1}{x^{2}+2 x+2} d x \\
\text { (iii) } \int x e^{9 x} d x
\end{array}\) (May – 2017)
Answer:
Plus Two Maths Chapter Wise Previous Questions Chapter 7 Integrals 41