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Students can Download Kerala Padavali Unit 3 Chapter 1 Pralobhanam Questions and Answers, Summary, Notes Pdf, Activity, Kerala Padavali Malayalam Standard 10 Solutions helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Padavali Malayalam Standard 10 Guide Unit 3 Chapter 1 Pralobhanam

Pralobhanam Questions and Answers, Summary, Notes

You can Download Food Through Digestive Tract Questions and Answers, Summary, Activity, Notes, Kerala Syllabus 9th Standard Biology Solutions Part 1 Chapter 2 help you to revise complete Syllabus and score more marks in your examinations.

Kerala State Syllabus 9th Standard Biology Solutions Chapter 2 Food Through Digestive Tract

Food Through Digestive Tract Textual Questions and Answers

Kerala Syllabus 9th Standard Biology Notes Chapter 2 Question 1.
What are the nutrients we get from food?
Answer:
Carbohydrate, Protein, Fat, Minerals, vitamins & water.

Food Through Digestive Tract Class 9 Notes Kerala Syllabus Question 2.
Complete the table given below.

Answer:

Kerala Syllabus 9th Standard Biology Notes Chapter 2 English Medium Question 3.
Illustrate & identify the different parts of the digestive system.

Answer:

Food Through Digestive Tract Class 9 Kerala Syllabus Question 4.
What are the functions performed by the nutrients in our body – Prepare a table?

Answer:

Food Inside Mouth

Kerala Syllabus 9th Standard Biology Notes Question 5.
State true or false
a) Vitamin A is required to the healthy eyesight
b) Incisor helps to bite and cut the food
c) Molar helps to tear the food
Answer:
a) True
b) True
c) False

Kerala Syllabus 9th Standard Biology Notes Malayalam Medium Chapter 2 Question 6.
Complete the Illustration

Answer:
Canine: Helps to tear the food
Premolar: Helps to chew at the food
Molar: Helps to chew the food

9th Class Biology Chapter 2 Notes Kerala Syllabus Question 7.
What do you mean by digestion?
Answer:
Digestion is the process of conversion of complex food materials into simple absorbable forms.

Kerala Syllabus 9th Standard Biology Notes English Medium Question 8.
…………. helps to tear the food?
Answer:
Canine

Kerala Syllabus Biology 9th Standard Question 9.
Molar helps to the food
Answer:
Chew

9th Biology Notes Kerala Syllabus Question 10.
The process of digestion begins from the.
Answer:
Mouth

9th Class Biology Book Chapter 2 Kerala Syllabus Question 11.
……….. helps to chew the food
Answer:
Premolar

Kerala Syllabus 9th Standard Biology Notes Pdf Question 12.
……… helps to bite and cut the food
Answer:
Incisor

Question 13.
Define enamel.
Answer:
Enamel is the hardest part in our body. It is white in color. It is a dead tissue seen in the out layer of our teeth.

Question 14.
What is the role of the tongue in the digestive system?
Answer:
The tongue mixes food items with saliva and helps the teeth to masticate it. It taste buds in the tongue also help us to sense taste.

Question 15.
………. is the living tissue which forms the tooth.
Answer:
Dentine.

Question 16.
……… is a calcium-containing connective tissue that holds the tooth in the socket of the gum.
Answer:
Cementum

Question 17.
………….. is the soft connective tissue seen in the pulp cavity.
Answer:
Pulp

Question 18.
Complete the word relation
Enamel: dead tissue
……….: living tissue
Answer:
Dentine

Saliva And Digestion

Question 19.
Where is saliva produced?
Answer:
Saliva is produced in the Salivary glands.

Question 20.
Write a note on the significance of salivary glands?
Answer:
There are three pairs of salivary glands in the mouth. The saliva secreted from the salivary glands contains mucus and enzymes like salivar amylase & lysozyme.

Question 21.
……… makes the food slimy, so that it can be swallowed.
Answer:
Mucus

Question 22.
………….. helps to destroy the germs that enter the body through food.
Answer:
Lysozyme

Question 23.
……….. partially converts starch to maltose?
Answer:
Salivary amylase

Question 24.
What are the components of saliva?
Answer:
Mucus and enzymes like salivary amylase and lysozyme

Question 25.
Complete the word relation.
Salivary amylase: ………….
Lysozyme: destroy germs
Answer:
Maltose

Question 26.
When iodine added to starch color appears.
Answer:
Blue

Food Through Oesophagus

Question 27.
Complete the illustration?

Answer:
a) Uvula
b) Pharynx
c) Epiglottis
d) Oesophagus

Question 28.
Trachea begins from the
Answer:
Pharynx

Question 29.
From the mouth, food enters the………. through the pharynx
Answer:
Oesophagus

Question 30.
Prepare a flow chart regarding the swallowing of food?
Answer:
Mouth → buccal cavity → pharynx → Oesophagus → food into the stomach.

Question 31.
Observe the illustration and write down the questions below.

1. What is the role of uvula?
2 compresses the food into balls with the help of plate?
3. State whether true or false?
The trachea tilts up and it is closed by the epiglottis
Answer:

1. Uvula doses the nasal cavity that opens to the pharynx
2. Tongue
3. True

Question 32.
How does the food we swallowed enter the esophagus properly without entering the trachea? Explain?
Answer:
The Tongue compresses the food into balls with the help of the palate. That time Ovula closes the nasal cavity that opens to the pharynx and the trachea tilts up and it is closed by the epiglottis.

Food Inside The Stomach

Question 33.
Food reaches the stomach by
Answer:
Peristalsis

Question 34.
What do you mean by peristalsis?
Answer:
Peristalsis is the wave-like movement of the esophagus, stomach, and intestines.

Question 35.
What is the role of peristalsis in the process of digestion?
Answer:
Peristalsis in the stomach converts foods into a pastelike form.

Question 36.
What are the changes that happen to food while it is in the stomach?
Answer:
Peristalsis in the stomach converts food into a paste-like form. Special kind of circular muscles present in the posterior part of stomach retains food for a specific period. Different components in the gastric juice, secreted by the glands in the stomach wall also play a very important role in the process of digestion.

Question 37.
Complete the illustration

Answer:
a) Pepsin – Converts protein to peptones partially
b) Hydrochloric acid
c) Mucus: Protects the stomach wall from the action of digestive Juices

Question 38.
What is the role of Hydrochloric acid in the gastric juice?
Answer:
Hydrochloric acid in the gastric juice kills germs in the food. It also regulates pH for the digestion in the stomach.

Question 39.
………….. protects the stomach wall from the action of digestive juices.
Answer:
Mucus

Question 40.
………….. converts protein to peptones partially
Answer:
Pepsin

Question 41.
……………. regulates pH for the digestion in stomach.
Answer:
Hydrochloric acid

Food In The Small Intestine

Question 42.
Define Liver and its main function?
Answer:
Liver is the largest solid organ in the body situated in the upper part of the abdomen on the right side. The main function of liver is to filter the blood coming from the digestive tract, before passing it to the rest of the body.

Question 43.
What is the role of gall bladder?
Answer:
The excess bile secreted by the Liver is stored in the gall bladder.

Question 44.
………… secretes pancreatic juice
Answer:
Pancreas

Question 45.
Complete the table given below.

Answer:

Question 46.
Complete the word relation.
Liver: …………….
Pancreas: Pancreatic juice
Answer:
Bile

Question 47.
Pancreatic juice contains the enzymes …………. & ……………
Answer:
Amylase, lipase, trypsin

Question 48.
Prepare a flow chart showing the role of pancreas in the process of digestion?
Answer:

Question 49.
Complete the word relation.
Starch: Maltose
Protein: ……….
Answer:
Peptides

Question 50.
Peptidase converts peptides to …………..
Answer:
Amino acids.

Question 51.
………. converts lactose to glucose & galactose.
Answer:
Lactase

Question 52.
Prepare a flow chart showing the digestion within the small intestine?
Answer:
Small Intestine → Intestinal glands →
Intenstinal juice → Peptidase → Peptides → AminoAcids

Question 53.
Explain the action of disaccharidases?
Answer:
Disaccharidases like Maltose converts maltose to glucose, Lactase converts lactose to glucose and galactose and sucrase converts sucrose to glucose and fructose.

Question 54.
Which are the end products formed after digestion? Write in table.
Answer:

Question 55.
Which are the nutrients that do not undergo digestion?
Answer:

• Water
• Minerals
• Vitamins

Absorption Begins

Question 56.
Which are the simple components formed by the digestion of protein, fat, and carbohydrate?
Answer:
Protein: amino acids and glycerol
Fat: fatty acid and glycerol
Carbohydrate: Monosasacchrides (glucose, fructose, galactose).

Question 57.
The small intestine of humans is about ………… long.
Answer:
5 to 6 meters.

Question 58.
illustrate the structure & position of villus?
Answer:

Question 59.
State whether true or false.
a) Movement of food through the small intestine is very fast.
b) Many foldings are seen in the inner wall of small intestine.
Answer:
a) False
b) True

Question 60.
Small intestine is seen in the
Answer:
Abdominal cavity.

Question 61.
What are Villi?
Answer:
Villas are small finger-like projections seen in the walls of the intestine.

Question 62.
Fatly acids and glycerol are absorbed to the ………… of villus.
Answer:
Lacteal

Question 63.
……… are small finger-like projections seen on the walls of the intestine.
Answer:
Villi

Question 64.
What is the function of villi? Write down your interference?
Answer:
Villi increase the area of absorption of nutrients to a great extent within the small intestine. They also contain blood capillaries & lacteals, the lymph capillaries. Absorption of nutrients & 90% of water absorption take place in the villi.

Question 65.
……….. are the lymph capillaries?
Answer:
Lacteals

Question 66.
Villi are covered with ……………
Answer:
Single-layer of cells

Behind Absorption

Question 67.
‘Diffusion does not require energy’ Kalyani said to Ishan. Do you agree with Kalyani’s opinion? Why? )
Answer:
Yes. Diffusion is the movement of molecules from a region of higher concentration to a region of lower concentration. By diffusion, molecules move across the cell through the cell membrane. This process continues till the concentration becomes equal in both sides of the membrane. So this process does not require any energy.

Question 68.
Absorption of fatty acids and glycerol into lacteals is the example of
Answer:
Diffusion

Question 69.
What do you mean by facilitated diffusion?
Answer:
Diffusion of certain molecules with the help of protein molecules in the cell membrane is called facilitated diffusion.

Question 70.
Asha stated that “Absorption of water in the small intestine and the large intestine is an example of Osmosis” Do you agree? Substantiate your answer by explaining the term osmosis?
Answer:
Osmosis is the movement of water molecules from a region of higher concentration to a region of lower concentration across a semi-permeable mebrane. This process continues till the concentration becomes equal. It can be stated that in small intestine and large intestine water molecules move from a region of higher concentration to a region on lower concentration.

Question 71.
Explain the process of Active Transport?
Answer:
The process by which molecules are absorbed with the help of carrier Proteins against the concentration gradient is called active transport.

Question 72.
Absorption of glucose and salt are examples of
Answer:
Active Transport

Question 73.
Complete the word relation:
Osmosis: absorption of water
…………: absorption of amino acid.
Answer:
Facilitated diffusion

Question 74.
Which are the process that help in the transport and substances in cells?
Answer:
Diffusion & Osmosis

Question 75.
Differences and similarities between Diffusion and Osmosis – Prepare a table.
Answer:

Question 76.
How does diffusion differ from facilitated diffusion?
Answer:
Diffusion is the movement of molecules from a region of higher concentration to a region of lower concentration but facilitated diffusion is the diffusion of certain molecules with the help of protein molecules in the cell membrane.

Question 77.
What is the difference noticed in active transport when compared to other processes?
Answer:
In Active transport energy is needed by other process energy is not needed.

In And Out Of Large Intestine

Question 78.
The digestive wastes left after the absorption of nutrients move towards the …………
Answer:
Large intestine

Question 79.
Bacteria residing in the large intestine produced ………….
Answer:
Vitamin K

Question 80.
Absorption of vitamin K takes place in the ………….
Answer:
Large intestine

Question 81.
What are the main ideas that can include in the seminar relationship between food and health?
Answer:

• Importance of roughage for a healthy digestive system.
• Health issues created by junk food and fast food.
• Harmful chemical substances added to food to enhance its taste and color.

Let Us Assess

Question 82.
Identify the correct statement with regard to bile.
a) Secreted in liver
b) Enzymes are seen
c) Secreted into the stomach
d) Converts fat into tiny particles
Answer;
a) Secreted in liver

Question 83.
Complete the table related to the process of digestion in humans.

Answer:

Food Through Digestive Tract Additional Question and Answers

Question 84.
Illustrate the process of Osmosis
Answer:

Question 85.
How much time is required for the completion of digestion?
Answer:
4 to 5 hours

Question 86.
“You should take food only after an interval of 4 hours” – said Arun to Archa. What is your opinion?
Answer:
The process of digestion is completed through many complex actions. It requires 4 to 5 hours. Hence it is necessary to arrange the intake of food accordingly keeping an interval of four hours between the intake.

Question 87.
Doctor advised Minnu who had a complaint of stomach pain to avoid cool drinks like cola &junk food. What can be the reason for this advice? Point out your opinion?
Answer:
The nutrients required for our health are derived from our food. If we choose food only on the basis of taste, we may not get all the required nutrients. Regular use of colo drinks & junk foods are not good for our health. Therefore try to take all types of food instead of giving priority to cola & junk food.

Question 88.
Prepare a poster on ‘Good food habits’
Answer:

• Eat plenty of fruits & vegetables every day
• Eat less unhealthy food
• Balance your food choices over time. (Draw a suitable picture using these ideas).

You can Download Redox Reactions and Rate of Chemical Reactions Questions and Answers, Summary, Activity, Notes, Kerala Syllabus 9th Standard Chemistry Solutions Part 1 Chapter 3 help you to revise complete Syllabus and score more marks in your examinations.

Kerala State Syllabus 9th Standard Chemistry Solutions Chapter 3 Redox Reactions and Rate of Chemical Reactions

Redox Reactions and Rate of Chemical Reactions Textual Questions and Answers

Kerala Syllabus 9th Standard Chemistry Notes Chapter 3 Activity -1

Given below is a table showing the mass of the reactants and the products when hydrogen combines with chlorine to form hydrogen chloride in two situations.

HSSlive chemistry redox reactions Question 1.
Write down the total mass of the reactants and also the total mass of product in the above experiment.
a) Situation 1: …………………
b) Situation 2: ……………….
Answer:
a) Total mass of reactants 73g products 73g
b) Reactants 146g products 146 g

Class 9 Chemistry Chapter 3 Notes Kerala Syllabus Activity-2

Given below is a table showing the mass of the reactants and the products when hydrogen combines with oxygen to form water, in two situations.

Kerala Syllabus 9th Standard Chemistry Chapter 3 Question 2.
Write down the total mass of the reactants and the total mass of product in the above experiment.
a) Situation 1:
b) Situation 2:
Answer:
a) Reactants 18 g, Product 18 g
b) Reactants 36 g, Products 36 g

Redox Reaction And Rate Of Chemical Reaction Kerala Syllabus 9th Question 3.
What is the relation between the total mass of the reactants and the total mass of products?
Answer:
Both are equal.

State The Law Of Conservation Of Mass

In a chemical reaction mass is neither created nor destroyed. This is the law of conservation of mass.
This law was proposed by the scientist Antoine Lavoisier. That is, the total mass of the reactants will be equal to the total mass of the products.

Activity-3

Kerala Syllabus 9th Standard Chemistry Chapter 3 Notes Question 4.
A piece of magnesium is burned in air. What do you observe?
Answer:
It burns with sparkling light

Redox Reactions And Rate Of Chemical Reactions Kerala Syllabus 9th Question 5.
What is the white powder formed?
Answer:
Magnesium oxide (MgO)

Hss Live Guru 9th Chemistry Kerala Syllabus  Question 6.
Which are the reactants here?
Answer:
Mg and O₂

Chemistry 9th Class Notes Kerala Syllabus Question 7.
Which is the product?
Answer:
MgO

9th Class Chemistry Chapter 3 Kerala Syllabus Question 8.
Note down the number of atoms in the reactant side and the number of atoms in the product side in the table below.

Answer:

9th Class Chemistry Chapter 3 Notes Kerala Syllabus Question 9.
Is the number of atoms of each element equal on both sides?
Answer:
No

Kerala Syllabus 9th Standard Chemistry Notes Question 10.
The number of which atom is not equal on both sides?
Answer:
O

Chemistry Class 9 Kerala Syllabus Question 11.
How many product molecules are needed to equalize the number of oxygen atoms on both sides?
Answer:
2

Kerala Syllabus 9th Standard Chemistry Notes Pdf Question 12.
How will you represent two molecules of magnesium oxide?
Answer:
2 MgO

Hss Live Class 9 Chemistry Kerala Syllabus Question 13.
Now, is the number of magnesium atoms equal on both sides?
Answer:
No

Chemistry Notes For Class 9 Kerala Syllabus Question 14.
How many magnesium atoms are needed in the reactant side to equalize the number of magnesium atoms on both sides?
Answer:
2

Chemistry 9th Class Chapter 3 Kerala Syllabus Question 15.
Then how can you rewrite the above equation?
Answer:
2 Mg + O₂ → 2MgO

Question 16.
Is the total number of atoms of each element in the molecules present in the reactant side and that in the product side equal in this equation?
Answer:
Yes

Question 17.
What is balancing of equations?
Answer:
Equalizing the number of atoms of each element in molecules in the reactant side and that in the product side is called balancing of equation.
Zn + HCl → ZnCl₂ + H₂
Tabulate the total number of atoms of each elements in the reactant side and that in the product side of the above reaction.

Question 18.
How many Zn atoms are there in the reactant side and in the product side?
Answer:
1 each

Question 19.
Which are the atoms showing a difference in their number?
Answer:
H and Cl

Question 20.
In order to make them equal on both sides how many molecules of HCI should be taken as reactant.
Answer:
2
Now rewrite the equation
Zn + HCl → ZnCl₂ + H₂

Question 21.
Balance the chemical equation H₂ + O₂ → H₂O
Answer:
Step I: H₂+ O₂ → H₂O
Step II: 2H₂ + O₂ → 2H₂O

Question 22.
Balance the chemical equation Al + O₂ → Al₂O₂
Answer:
Step I: 2Al + O₂ → Al₂O₃
Step II: 2Al+ 3O₂ → 2Al₂O₃

Question 23.
Balance the chemical equation H₂ + O₂ → H₂O
Answer:
Step I: H₂ + O₂ → 2H₂O
Step II: 2H₂ + O₂ → 2H₂O

Question 24.
Some chemical equations are given below. Note down the number of reactant atoms and that of product atoms in the table given below.
1. C + O₂ → CO₂
2. N₂ + H₂ → NH₃
3. 2H₂ O₂ → 2H₂O + O₂
4. SO₂ + O₂ → SO₃
5. BaCl₂ + H₂SO₄ → BaSO+2HCl

Balance the equations which are unbalanced
Answer:
1. N₂ + 3H₂ → 2NH₃
2. 2SO₂ + O₂ → 2SO₃

Oxidation And Reduction

Question 25.
The electronic configuration of magnesium and chlorine are 2, 8, 2 and 2, 8, 7 respectively. How many electrons does a magnesium atom donate? What charge will it get?
Answer:
2, two positive (2+)

Question 26.
Let us complete the equation for this process,
Mg → Mg²⁺ + ……………
Answer:
Mg → Mg²⁺ + 2e^–

Question 27.
How many electrons are accepted by each chlorine atom? What will be the charge acquired by each atom?
Answer:
One 1^– Cl^1-

Question 28.
Complete the equation of this process.
Cl + 1e^– →
Answer:
Cl + 1e^– → Cl^1-

Question 29.
What are oxidation and reduction?
Answer:
Oxidation is the process of loss of electrons. Reduction is the process of gain of electrons. The atom which loss electron is called the reducing agent and the atom which gains electron is called the oxidizing agent.

Question 30.
In the above chemical reaction, which atom is oxidized?
Answer:
Sodium

Question 31.
Which atom is reduced?
Answer:
Chlorine

Question 32.
Which is the oxidizing agent in this chemical reaction?
Answer:
Chlorine (Cl)

Question 33.
Which is the reducing agent in this chemical reaction?
Answer:
Sodium (Na)

Question 34.
Analyze the following equations and list the oxidized atom, reduced atom, oxidizing agent and reducing agent.
a) Mg + F₂ → MgF₂
b) 2Na + Cl → NaCl
Answer:
a) Oxidized atom — Mg
Equation of oxidation — Mg → Mg²⁺ + 2e^–
Reduced atom — F
Equation of reduction — F + e^– → F^–
Oxidizing agent — F
Reducing agent — Mg

b) Oxidized atom — Na
Equation of oxidation — Na → Na + 1e^–
Reduced atom — Cl
Equation of reduction — Cl+ 1e^– → Cl^–
Oxidizing agent — Na
Reducing agent — Cl

Question 35.
Analyse the following equations and complete the Table given below.
1. Mg → Mg²⁺ + 2e^–
F+ le^– → F^–
2. Na → Na⁺+1e^–
Cl + 1e^– → Cl^–
3. Fe → Fe²⁺+ 2e^–
O + 2e^– → O^2–

Answer:

Oxidation Number

Oxidation number of an atom in a molecule is the formal charge assigned on the atom if all the bonds in the substance arc considered to be ionic.

Question 36.
Consider the equation H₂ +Cl₂ → 2HCl What is the oxidation number of hydrogen in H₂?
Answer:
O

Question 37.
What is the oxidation number of chlorine in Cl₂?
Answer:
O

Question 38.
In this reaction, does the oxidation number of hydrogen increase or decrease?
Answer:
Increases

Question 39.
What change takes place in the oxidation number of chlorine?
Answer:
Decreases

Question 40.
What are oxidation and reduction on the basis of change in oxidation number?
Answer:
The process in which the oxidation number increases is called oxidation.
The process in which the oxidation number decreases is called reduction.

Question 41.
During the formation of hydrogen chloride, which atom was oxidized?
Answer:
H

Question 42.
Which is the reducing agent?
Answer:
Cl

Question 43.
Which atom was reduced, during this reaction?
Answer:
Cl

Question 44.
Which is the oxidizing agent?
Answer:
H

Question 45.
Analyze oxidation numbers in the given equation and list the oxidizing agent and reducing agent in the table given below.

Answer:
Oxidizing agent – O
Reducing agent-C

Question 46.
Analyze the oxidation number and note down the oxidizing agent and reducing agent in the following reaction.

a) Oxidation number of which atom is increased?
b) The oxidized atom is
c) Oxidation number of which atom is decreased?
d) The reduced atom is
e) Oxidizing agent
f) Reducing agent
Answer:
a) Na
b) Na
c) Cl
d) Cl
e) Na
f) Cl

Question 47.
Analyze the following equation fill-up the blanks.

Question 48.
The oxidation number of zinc increases/decreases from … to…
Answer:
0 to +2

Question 49.
The oxidized atom is…
Answer:
Zn

Question 50.
The oxidation number of hydrogen increases/decreases from …. to
Answer:
+1 to 0

Question 51.
The reduced atom is …
Answer:
H
Here HCI is the oxidizing agent and Zn is the reducing agent. „

Question 52.
How do you determine the oxidation number of sulfur in H₂ SO₄?
Answer:
Oxidation state of hydrogen = +1
Oxidation state of oxygen = -2
Let the oxidation state of sulphur be ‘x’ We know the sum of oxidation states of all atoms in a compound is zero. Therefore,
[2×(+1)] + x + (4x – 2) = 0
(+2) + x + (-8) = 0
x – 6 = 0
x = +6

Question 53.
Find the oxidation number of Mn in KMnO₄ (oxidation number of K is +1, oxidation number of O is -2)
ANswer:
Oxidation state of potassium = +1
Oxidation state of oxygen = -2
Let the oxidation state of Mn be ‘x’.
1 x (+1) + x + 4(-2) = 0
(+1) + x + (-8) = 0
x – 7 =0
x = +7

Question 54.
Find the oxidation number of Mn in MnO₂, Mn₂O₃ and Mn₂O₇
Answer:
MnO2
Mn + 2x -2 = 0
Mn + 4 = 0
Mn = +4

Mn2O3
2Mn + 2x -2 = 0
2Mn + -4 = 0
2 Mn = +4
Mn = +2

Mn2O7
2Mn + -2×7 = 0
2Mn + -14 = 0
2Mn = +14
Mn = +7

Question 55.
What is Redox reaction?
Answer:
The process of oxidation and reduction take place simultaneously. Hence these two reactions together are known as redox reaction.
Examples:
H₂ + Cl₂ → 2HCl
Mg + F2 → MgF₂
2Na + Cl₂ → 2NaCl

Question 56.
What are the methods usually adopted to make firewood burn faster? ‘
Answer:
1. Provide more air
2. Split up into small pieces
3. Make firewood dry

Question 57.
Describe an experiment to prove that nature of the reactants affects the rate of chemical reaction.
Answer:
Materials required for the experiment.
Zn, Mg, dil. HCl arid test tubes.
Procedure:
Take equal volume of dil. HCl in two test tubes. Add Zn to one and Mg of same mass to the other. Hydrogen gas is produced in both the test tubes. Rate of reaction is faster in the test tube containing Mg.

Question 58.
Write an experiment to prove that concentration of reactants affect the rate of reactions.
Answer:
Materials required: Mg, dil. HCl, Con. HCl and test tubes.
Procedure: Take magnesium ribbons of equal mass in two test tubes. Add concentrated HCl to one test tube and dilute HCl to the other in equal volume

Question 59.

Write your observation
Test tube 1: ……………
Test tube 2: …………..
Test tube 1: Reaction is faster in con. HCl
Test tube 2: Reaction rate is slow

Question 60.
Why rate of reaction increases when concentration increases?
Answer:
As the concentration of reactants increases, the number of molecules per unit volume and the number of effective collisions increase. Consequently the rate of reaction increases.

Question 61.
What is the relation between rate of reaction and surface area? Write an experiment to prove it.
Answer:
Take equal volume of dil. HCI in two beakers. Add a small piece of marble into one and marble powder of equal mass into the other. Reaction rate is greater when marble powder is used. Rate of reaction increases when surface area increases

Question 62.

Is there any difference in the rate of reaction in the two beakers?
Answer:
Reaction rate is greater when powdered marble is used.

Question 63.
What about the concentration of acid in both the reactions?
Answer:
Same

Question 64.
Is there any difference in the mass of the marble?
Answer:
No

Question 65.
What about the surface area of marble?
Answer:
Different

Question 66.
In which case is the chance for greater number of acid molecules to get in contact with marble, in a given time?
Answer:
If marble is powdered

Question 67.
What is the change in the rate of collision when surface area increases?
Answer:
When surface area increases rate of reaction also increases.

Question 68.
What will happen to the rate of this reaction if marble is further crushed or powdered?
Answer:
Will increase

Question 69.
Why rate of reaction increases when surface area increases?
Answer:
When solids are made into small pieces or powder, their surface area increases. As a result the number of molecules undergoing effective collision also increases. Hence the rate of reaction increases.

Question 70.
Write an experiment to prove the relation between temperature and rate of reaction.
Answer:
Materials required: Sodium thiosulphate, hydrochloric acid, water, boiling tube, spirit lamp. Procedure: Prepare dilute solution of sodium thiosulphate in a beaker. Take equal volumes of this solution in two boiling tubes. Heat one boiling tube for some time. Add dilute hydrochloric acid in equal amounts in both the boiling tubes.
Observation: Reaction is faster in heated test tube.

Question 71.
In which of the boiling tubes is the precipitate formed faster?
Answer:
In heated test tube

Question 72.
What is the color of the precipitate formed?
Answer:
Pale yellow

Question 73.
What is Threshold Energy?
Answer:
To take part in a chemical reaction, molecules should attain certain minimum kinetic energy. This energy is called threshold energy.

Question 74.
Write an experiment to prove the influence of catalysts in a chemical reaction.
Answer:
Take some hydrogen peroxide solution in a test tube. Show a glowing incense stick into the test tube.
What is the observation? Is there any difference occurring in the way in which the incense stick bums? No . ‘
Now add some manganese dioxide (MnO₂) into the test tube. Again show the glowing incense stick. Observation:
Glowing incense stick flares up now.

It indicates that when manganese dioxide is added, the rate of reaction increases and oxygen is formed faster. Filter the solution using a filter paper when the reaction is completed.

The substance remaining in the filter paper is manganese dioxide itself When examined carefully it becomes clear that there is no change in its amount or property. The presence of manganese dioxide has increased the rate of the reaction. Manganese dioxide acts as a catalyst in this reaction.

Question 75.
What are catalysts?
Answer:
Catalysts are substances which alter the rate of chemical reactions without themselves undergoing any permanent chemical change.

Redox Reactions and Rate of Chemical Reactions Additional Questions and Answers

Magnesium combines with chlorine to form magnesium chloride. The equation is given below
Mg + Cl₂ → MgCl₂

Question 1.
Write down the electronic configuration of magnesium and chlorine
Answer:
Mg – 2, 8, 2
Cl – 2, 8,7

Question 2.
How many electrons are donated by magnesium? Write the chemical equation for this process
Answer:
2, Mg → Mg²⁺ +2e^–

Question 3.
How many electrons are accepted by chlorine?
Answer:
1, charge – ve

Question 4.
Write the chemical equation.
Answer:
Cl + 1e^– → cl^–

Question 5.
Explain oxidation, reduction, oxidizing agent and reducing agent?
Answer:

• Oxidation is the process by which the removal of electrons.
• Reduction is the process by which the addition of electrons.
• In the above process, magnesium reduces chlorine by donating electrons to it hence magnesium is the reducing agent. In this process since chlorine oxidizes magnesium by accepting electrons it is considered as the oxidizing agent.

Question 6.
From the given chemical equation identify the oxidizing agent and the reducing agent by writing the chemical equation of oxidation and reduction
(i) Mg + F₂ → MgF₂
(ii) 2Na + Cl₂ → 2NaCl
Answer:
(i) Mg → Mg²⁺ + 2e^– (Oxidation)
F + 1e^– → F^– (Reduction)
Here magnesium is the reducing agent and fluorine is the oxidising agent.
(ii) Na → Na⁺ + 1e^– (Oxidation)
Cl + 1e → Cl^– (Reduction)
Here sodium is the reducing agent and chlorine is the oxidizing agent.

Question 7.

In the formation of hydrogen chloride does the oxidation number of hydrogen increase or decrease?
Answer:
The oxidation number of hydrogen increases from 0 to +1

Question 8.
Whether the oxidation number of chlorine decrease or increase?
Answer:
The oxidation number of chlorine decreases from 0 to — 1.

Question 9.
Based on oxidation number which is the oxidizing agent and reducing agent?
Answer:
H₂ is the reducing agent and Cl₂ is the oxidizing agent.

Question 10.
What is meant by Redox reaction?
Answer:
A process in which the increase in oxidation number is the oxidation and decrease in oxidation number is the reduction. A process in which both oxidation and reduction takes place is the redox reaction. The molecule in which the atom whose oxidation number decreases during the process is the oxidizing agent and that in which oxidation number of an atom increase is the reducing agent.

Question 11.
In the following chemical reactions which is the oxidizing agent which is the reducing agent? Analyze the oxidation number and find out?

Reducing agent – C
Oxidising agent – Cl₂

Question 12.
Given below is the equation of the reaction between zinc and hydrochloric acid also indicating the oxidation number.

Analyze and find the following:
Answer:
In this process, oxidation number of zinc increases from 0 to +2.
Oxidation number of hydrogen decrease from +1 to 0 The reducing agent is zinc and oxidising agent is HCl.

Question 13.
Calculate the oxidation number of‘S’ in H₂ SO₄?
Answer:
Oxidation number of hydrogen = +1
Oxidation number of oxygen = -2
Let the oxidation number of ‘S’ be x
The sum of the oxidation numbers of all the Elements in a compound is zero,
Hence
[2x (+1] + x + 4 x (-2] = 0
2 + x – 8 = 0
x = +8 – 2
x = +6
ie., oxidation number of ‘S’ in H₂ SO₄ is +6.

Question 14.
Find the oxidation number of the ions in ionic compound?
The charge of ions in ionic compound is the oxidation number. Eg. In FeCl₂ the oxidation number of Fe is +2 and FeCl3 is +3.

Let Us Assess

Some chemical equations are given below.
C + O₂ → CO₂
CH₄ + 2O₂ → CO₂ + 2H₂O
N₂ + O₂ → NO
CaCO₂ → CaO + CO₂
H₂ + l₂ → Hl
Fe + HCl → FeCl₂ + H₂
CO₂ + C → CO
a) Which of these are balanced equations?
b) Balance the unbalanced equations.
c) Which among these are redox reactions?
Answer:
a) C + O₂ → CO₂
CH₄ + 2O₂ → CO₂ +2 H₂O
CaCO₃ → CaO +CO₂
b) N₂ + O₂ → 2NO
H₂ + l₂ → 2Hl
Fe + 2HCl → FeCl₂ + H₂
CO₂ + C₂CO

Question 2.
The chemical reaction between marble and dilute HCl is given.
CaCO₃ + 2HCl → CaCl₂ + H₂O +CO₂
a) Which gas is formed here? How can you identify this gas?
b) Suggest any two ways you would choose to increase the rate of this chemical reaction. Explain the reason.
Answer:
a) Carbon dioxide (CO₂). Show a burning splinter in the gas. It will get extinguished.
or
Show a glass rod dipped in clear lime water into the gas. The lime water will turn milky
b) 1) Use powdered marble
2) Use concentrated HCl
3) Heat the mixture.

Question 3.
Sulfur pieces do not react with cold concentrated nitric acid. But sulfur powder reacts.
a) Explain the reason why the rate of chemical reaction is increased here?
b) Suppose you want to increase the rate of reaction again. Which way you would choose? Give reason.
Answer:
a) When surface area increases rate of effective collision increases. So the rate of reaction increases.
b) Heat the mixture.
When temperature increases more molecules will get threshold energy. So rate of effective collision and rate of reaction increases.

Question 4.
Small amounts of phosphoric acid is usually added to hydrogen peroxide to prevent its decomposition?
a) What is the function of phosphoric acid here?
b) By which name are these type of substances known?
c) Which substance would you add to increase the rate of decomposition of hydrogen peroxide?
Answer:
a) Slow down the rate of decomposition of hydrogen peroxide
b) Negative catalyst
c) Manganese dioxide

Extended Activities

Question 1.
Find the oxidation number of the elements which are underlined in the compounds given below. Among these find out the elements which show variable oxidation numbers.
MnO₂, Mn₂O₇, K₂Cr₂O₇, KCrO₃, MnCl₂, MgO, MgCl₂, Al₂O₃,AlCl₃
(Hint. Oxidation number 0 = -2, Cl = -1, K = +1)
Answer:
MnO₂ Let x be the oxidation number of Mn

Question 2.
Some apparatus and chemicals are given.
Zn, Mg, dilute HCl, CaCO₃, test tube, water.
a) Design an experiment to prove that the nature of reactants can influence the rate of reaction.
b) Write the equations for the chemical reactions.
c) Write the expression for the rate of the reaction.
a) Take equal volume of dil HCl in two test tubes. Add a piece of Mg m to one of them. Add a piece of Zn of equal mass to the other.
Observation:- Mg reacts faster with dil. HCl than Zn. This is due to the difference in the chemical nature of Mg and Zn.
b) Mg + 2HCl → MgCl₂ +H₂
Zn + 2HCl → ZnCl₂ + H₂
c) Rate of a chemical reaction \(=\frac{\text { amount of reactants used up }}{\text { time }}\)
= \(\frac{\text { amount of product formed }}{\text { time }}\)

Question 3.
The experiments conducted by two students are given below.
Experiment 1: 2 mL of sodium thiosulphate solution is taken in a test tube, heated and to it 2 mL of HG solution is added.
Experiment 2:2 mL of sodium thiosulphate solution is taken in a test tube and to it 2 mL of HC1 solution is added.
a) In which experiment is the precipitate formed quickly? Justify your answer.
b) Write the balanced equation for the reaction.
Answer:
a) ln heated test tube.
When temperature increases more molecules get threshold energy. So rate of effective collision increases and rate of reaction increases.
b) Na₂ S₂O₃ + 2HCl → 2NaCl + SO₂ + S

Question 4.
Some materials available in the laboratory are given below. Magnesium ribbon, marble powder, marble pieces, dilute HCl, concentrated HCl.
a) Which materials will you choose for the preparation of more CO₂ in less time?
b) Write the balanced chemical equation of the reaction.
Answer:
a) Marble powder and concentrated HCl CaCO₃ + 2 HCl → CaCl₂ + H₂O + CO₂

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बीरबहूटी Text Book Questions and Answers

बीरबहूटी विश्लेषणात्मक प्रश्न

Beerbahuti Hindi Chapter Notes Kerala Syllabus 10th Standard प्रश्ना 1.
बादल को देखकर घड़े को नहीं ढुलाना चाहिए।’ दुकानदार ने ऐसा क्यों कहा?.

उत्तर:
साहिल ने स्याही भरवाने का निश्चय किया। तो उसने कलम की बची हुई स्याही ज़मीन पर छिड़क दी। दुकान पहुँचने पर वहाँ स्याही नहीं थी। तब दुकानदार ने ऐसा कहा। कहने का मतलब है- किसी बात पर केवल अंदाज़ा लेकर काम करना ठीक नहीं है। असलियत को पहले पहचानना चाहिए।

Beerbahuti Hindi Chapter Kerala Syllabus 10th Standard प्रश्ना 2.
जब वह उसके पास आकर बैठी उससे नज़र नहीं मिला पाई।’ क्यों?

उत्तर:
बेला साहिल को बहुत प्यार करती थी। उसके सामने वह लज्जित होना नहीं चाहती थी। लेकिन माटसाब का व्यवहार साहिल की उपस्थिति में था। इससे उसे बहुत दुख हुआ। इसलिए बेला साहिल से नज़र नहीं मिला पाई।

Beerbahuti Hindi Chapter Questions And Answers Kerala Syllabus 10th Standard प्रश्ना 3.
“इन बच्चों को अपने चारों ओर खेलते देखकर गांधीजी की मूर्ति ऐसी दिखाई पड़ती जैसे और समय से कुछ अधिक मुस्करा रही हो।” इसका मतलब क्या है?

उत्तर:
बच्चे हमेशा बच्चे ही हैं। उन्हें हमेशा खुश रहना चाहिए। उनकी खुशी देखनेवालों को भी खुश रखती है। यहाँ गांधीजी की मूर्ति तक बच्चों की खुशी देखकर मुस्करा रही है।

Beerbahuti Hindi Chapter Summary In Hindi Kerala Syllabus 10th Standard प्रश्ना 4.
‘यह बारिश से पहले की बारिश का एक दिन था। कहानी के प्रसंग में यह कैसे सार्थक होता है?

उत्तर:
यहाँ बारिश एक प्रतीक है। उसी प्रकार बादल भी। बेला और साहिल का दुख बादल के समान छाया हुआ है। साहिल की आँखों से पानी बरस रहा है। यहाँ कथाकार ने प्रकृति की रोनी सूरत और बच्चों की रोनी सूरत दोनों को दर्शाया है।

बीरबहूटी Text Book Activities & Answers

बीरबहूटी अभ्यास के प्रश्न

Beerbahuti Hindi Chapter Summary In Malayalam Kerala Syllabus 10th Standard प्रश्ना 1.

उत्तर:
साहिल की आँखें — बीरबहूटी की तरह लाल
चलती बीरबहूटियाँ — चलती-फिरती खून की प्यारी-प्यारी बूंदें
साहिल के आँसू — बारिश की बूंदें
साहिल की चोट — बीरबहूटी का रंग

Beerbahuti Hindi Chapter Summary In Malayalam Pdf Kerala Syllabus 10th Standard प्रश्ना 2.
प्रत्येक की तुलना किसके साथ की गई है? लिखें।

i. साहिल की लाल आँखों की तुलना बीरबहूटी से की गई है।
ii. ……………………………………
iii. …………………………………
iv. ………………………………….
उत्तर:
i. साहिल की लाल आँखों की तुलना बीरबहूटी से की गई है।
ii. चलती बीरबहूटियों की तुलना खून की प्यारी बूंदों से की गई है।
iii. साहिल के आँसुओं की तुलना बारिश की बूंदों से की गई है।
iv. साहिल की चोट के रंग की तुलना बीरबहूटी के रंग से की गई है।

Beerbahuti Hindi Chapter Summary Kerala Syllabus 10th Standard प्रश्ना 3.
कहानी की घटनाओं को सूचीबद्ध करें।

i. गीली ज़मीन पर बेला और साहिल का बीरबहूटियों को खोजना।
ii. पैन में स्याही भरना।
iii.
iv.
उत्तर:
i. गीली ज़मीन पर बेला और साहिल का बीरबहूटियों को खोजना।
ii. पैन में स्याही भरना।
iii. सुरेंद्रजी माटसाब बेला के बालों पर पंजा फँसाना।
iv. दीपावली के छुट्टी के बाद बेला के सिर पर सफ़ेद पट्टी बाँधे देखना।
v. साहिल की पिंडली में कील का चुभना।
vi.पाँचवीं का रिज़ल्ट आना।

बीरबहूटी  विधात्मक प्रश्न

Beerbahuti Hindi Chapter Notes Pdf Kerala Syllabus 10th Standard प्रश्ना 4.
घटनाओं के आधार पर पटकथा तैयार करें।

उत्तर:
बीरबहूटी:
सीन – 1
कस्बे से स्कूल जानेवाले रास्ते के बगल का खेत। सबेरे के नौ बज गए हैं।
(खेतों से भरा इलाका। दूर-दूर तक खेत दिख रहे हैं। लगभग 10-11 साल के दो बच्चे- बेला और साहिल खेत की मिट्टी में कुछ खोज रहे हैं। उनके पीठ पर बस्ता है। वेश से लगता है दोनों स्कूल जा रहे हैं।)
साहिल : बेला, देखो इस बीरबहूटी का रंग तुम्हारे रिबन जैसा लाल है।
बेला : दिखाओ तो। हाँ ठीक है। (स्कूल से घंटी बजने की आवाज़ आती है)
साहिल : (घबराकर) तुमने कुछ सुना बेला? ।
बेला : हाँ, सुना। पहली घंटी लग गई है। चलो देर हो जाएगी।
साहिल : लेकिन मुझे पेन में स्याही भरवानी, दुकान से।
बेला . : तो चलो जल्दी। (खेत की ज़मीन से उठकर दोनों बच्चे स्कूल के रास्ते पर आगे बढ़ते हैं।)

सीन – 2
गाँव की स्टेशनरी की दुकान। सबेरे के दस बज गए हैं। (बेला और साहिल दुकान के सामने खड़े हैं। दुकानदार उनसे कुछ बात कर रहे है।)
दुकानदार : क्या चाहिए?
साहिल : (कलम दिखाकर) इसमें स्याही भर दीजिए।
दुकानदार : (खेद से) अब क्या करूँ। स्याही खतम है। कल ही मिलेगी।
बेला : लेकिन इसने तो पैन में जो स्याही थी उसे ज़मीन पर छिड़क दिया।
दुकानदार : (हँसते हुए) बादल को देखकर घड़े को नहीं ढुलाना चाहिए।
बेला : (घबराकर) अब क्या करेंगे?
साहिल : चलो, कुछ करेंगे। किसी से उधार लेंगे। (दोनों बच्चे स्कूल के रास्ते पर आगे बढ़ते हैं।)
पटकथा तैयार करने के बाद इस चेकलिस्ट में ✓ करें।
दृश्य का वर्णन है। — ☐
समय का उल्लेख है। — ☐
पात्रों का उल्लेख है। — ☐
स्वाभाविक और पात्रानुकूल संवाद है। — ☐

Beerbahuti Hindi Notes Kerala Syllabus 10th Standard प्रश्ना 5.
अपनी किसी दोस्ती की याद पर टिप्पणी लिखें।
उत्तर:
जब मैं प्राथमिक पाठशाला में पढ़ता था तब मेरा एक दोस्त था। नाम था उसका संजू। संजू बहुत अच्छा लड़का था। उसका घर गाँव के दूसरी तरफ़ था। स्कूल आते समय सड़क पर हम मिलते थे। फिर हम साथ -साथ स्कूल चलते थे। कक्षा में साथ-साथ ही बैठते थे। और खाना भी बँटकर खाते थे। उसकी माँ से बनी खाना मुझे बहुत अच्छा लगता था। वह पढ़ाई में मेरी मदद करता था। चौथी तक हम एक साथ रहे। पाँचवीं में आने पर वह दूसरा स्कूल चला गया। अब मैं उसे मिल नहीं पा रहा है। प्राथमिक पाठशाला की हमारी वह दोस्ती मेरे मन में अब भी ताज़ा है।

बीरबहूटी Orakkum Questions and Answers

गतिविधि – 1

बीरबहूटी Question Answer Kerala Syllabus 10th Standard प्रश्ना 1.
बीरबहूटी किसकी कहानी है?
उत्तर:
प्रभात की।

Beerbahuti Notes Kerala Syllabus 10th Standard प्रश्ना 2.
इस में किनकी दोस्ती के बारे में कहा गया है?
उत्तर:
साहिल और बेला की।

गतिविधि – 2

सूचना : कहानी यह अंश पढ़े।
पैन में कुछ स्याही बची थी, उसे साहिल ने ज़मीन पर छिडक दिया। नई स्याही भरवाने केलिए दोनों दुकान पर पहूँचे।
“एक पैन स्याही भर दो।” साहिल से पहले ही बेलाने दुकानवाले से कहा।
“बेटा स्याही की बोतल अभी – अभी खाली हो गई है। अब तो कल ही मिल पाएगी।”
“लेकिन इसने तो पैन में जो स्याही थी उसे भी ज़मीन पर छिड़क दिया।” बेला बोली।
“बादल को देखकर घड़े को नहीं ढुलाना चाहिए।” दुकानवाले भैया ने कहा और पूछा “कौन-सी में पढते हो?”
“पाँचवीं में।” साहिल ने ऐसे बूरे मन से बताया जैसे पाँचवीं पढ़ना पाप हो।
“दोनों?” दकानवाले भैया ने कहा।
“हाँ दोनों, और हम दोनों का सैक्शन भी एक ही है – ए।
बेला ने ऐसे खुश होकर बताया जैसे यह कोई बहुत बड़ी बात हो।

बीरबहूटी Chapter Summary Kerala Syllabus 10th Standard प्रश्ना 1.
इसके पात्र कौन – कौन हैं?
उत्तर:
साहिल, बेला और दुकानदार ।

Beerbahuti Hindi Chapter Pdf Kerala Syllabus 10th Standard प्रश्ना 2.
साहिल और बेला कहाँ गए हैं? क्यों?
उत्तर:
साहिल और बेला दुकान पर गए। पैन में स्याही भरने केलिए।

Beerbahuti Hindi Chapter Questions And Answers Pdf Kerala Syllabus 10th Standard प्रश्ना 3.
इस दृश्य की पटकथा तैयार करें।
उत्तर:
पटकथा –

Beerbahuti Hindi Summary Kerala Syllabus 10th Standard प्रश्ना 4.
वाक्य – पिरामिड की पूर्ति करें।

उत्तर:
दोनों दूकान पहूँचे।
नई स्याही भरने दोनों दूकान पहूँचे।

गतिविधि – 3

सुचना : कहानी का यह अंश पढे और अनुबद्ध, प्रश्नों के उत्तर लिखें।
साहिल बेला का रिपोर्ट कार्ड देख रहा था और बेला साहिल का। आज आखिरी बारी वे एक दुसरे की कोई चीज़ को छूकर देख रहे थे। “तुम्हारी आँख में आँसु क्यों आ रहे हैं बेला?” “मुझे क्या पता।” बेला ने डबडबाई आँखों से हँसते हुए कहा। साहिल की आँखें बीरबहूटी की तरह लाल होने लगी थीं और उनमें बारिश की बूंदों-सा पानी भर गया था।

Beerbahuti Chapter Summary Kerala Syllabus 10th Standard प्रश्ना 1.
कहानी के अंश के आधार पर सही प्रस्ताव चुनकर लिखें।
क) साहिल और बेला बहुत खुश थे।
ख) साहिल और बेला रो रहे थे।
ग) साहिल और बेला को कोई दुख नहीं था।
घ) साहिल और बेला बिछुड़ना चाहते थे।
उत्तर:
साहिल और बेला रो रहे थे।

Beerbahuti Hindi Chapter Question Answer Kerala Syllabus 10th Standard प्रश्ना 2.
‘मुझे’ में निहित सर्वनाम कौन-सा हैं? (तुम, वे, मैं)
उत्तर:
मैं

10th Class Hindi First Chapter Beerbahuti Kerala Syllabus 10th Standard प्रश्ना 3.
बेला से बिछुड़ने के कारण साहिल बहुत दुखी है। साहिल अपने विचारों को डायरी में लिखता हैं। साहिल की उस दिन की डायरी लिखें।
उत्तर:
15.6.2017, गुरुवार
आज पाँचवीं के रिज़ल्ट का दिन था। मैं और बेला हम दोनों पास हो गए। लेकिन मन उदास है। कल से बेला से मिन न पाऊँगा। अगले साल बेला राजकीय कन्या पाठशाला में पढेगी। घरवाले मुझे अजमेर भेज देंगे। घर से दूर, होस्टल में अकेला रहना पडेगा।

आज तक बहुत खुशी के साथ बीता। मैं बेला के साथ बारिश में बीरबहूटियों को खोजकर कितने दिन बिताए। कल से मैं किस के साथ लंगड़े का खेल खेलूँ? बेला को भी बहुत दुख होगा। क्या वह मुझे याद करेगी? मेरा रिपोर्ट कार्ड देखते समय उसकी आँखों में आँसू भर गए। वह अपनी आँखों के आँसू छिपाने की कोशिश की। हम दोनों की दोस्ती उतनी सख्त थी।

गतिविधि – 4

सूचना : कहानी का अंश पढे और 1 से 3 तक के प्रश्नों के उत्तर लिखें।
वे एक-दूसरे के बहुत नज़दीक रहकर, बल्कि कहना चाहिए बिलकुल सटकर बीरबहूटियाँ खोजते थे। उन्हें देखने केलिए वे बारिश की गंध भरी भूरी ज़मीन पर बैठ जाया करते थे। “बेला, देखो इस बीरबहूटी का रंग तुम्हारे रिबन के जैसा लाल हैं।” साहिल ने कहा।
“तुमने कुछ सुना बेला?”
“हाँ, सुना। पहली घंटी लग गई हैं।”
“लेकिन मुझे पैन में स्याही भी भरवानी है, दुकान से।”

Beer Bahuti Story In Malayalam Kerala Syllabus 10th Standard प्रश्ना 1.
सही क्रिया रूप चुनकर वाक्य की पूर्ति करके लिखें।
साहिल पैन में स्याहि ……………..।
क) भरवाएंगे।
ख) भरवाएगा।
ग) भरवाएगी।
घ) भरवाएँगा।
उत्तर:
साहिल पैन में स्याही भरवाएगा।

10th Class Hindi Beerbahuti Question Answer Kerala Syllabus 10th Standard प्रश्ना 2.
साहिल और बेला बडे दोस्त हैं। इसकी सूचना देनेवाला एक वाक्य इस अंश से चुनकर लिखें।
उत्तर:
“बेला, देखो इस बीरबहूटी का रंग तुम्हारे रिबन के जैसा लाल हैं।”

Beerbahuti Questions And Answers Kerala Syllabus 10th Standard प्रश्ना 3.
इस प्रसंग के आधार पर पटकथा का एक दृश्य लिखें।
उत्तर:
पटकथा

बीरबहूटी SCERT Question Pool Questions and Answers

गतिविधि – 1

सूचना : ‘बीरबहूटी’ कहानी का यह अंश पढे और अनुबद्ध प्रश्नों के उत्तर लिखें।
बेला का मन बहुत खराब हो गया, माटसाब चाहे मुझे पीट लेते मगर साहिल के सामने नहीं। वह साहिल के सामने खुद को शर्मिदा महसूस कर रही थी क्योंकि वह जानती थी कि वह साहिल
की नज़र में बहुत अच्छी है। जब वह उसके पास आकर बैठी उससे नज़र नहीं मिला पाई।

प्रश्ना 1.
कहानी के अंश के आधार पर सही प्रस्ताव चुनकर लिखें।
क) बेला बहुत खुश थी।
ख) बेला साहिल से नाराज़ थी।
ग) बेला लज्जित थी।
घ) बेला को माटसाब का व्यवहार अच्छा लगा।
उत्तर:
बेला लज्जित थी।

प्रश्ना 2.
बेला खुद को शर्मिंदा महसूस कर रही थी। क्यों?
क) माटसाब ने बेला के बालों में पंजा फँसाया।
ख) साहिल के सामने माटसाब ने बेला के बालों में पंजा फंसाया।
ग) बालों में पंजा फँसाने से दर्द हुआ।
उत्तर:
साहिल के सामने माटसाब ने बेला के बालों में पंजा फँसाया।

प्रश्ना 3.
‘उससे’ में निहित सर्वनाम कोन-सा हैं? (तुम, वह, मैं)
उत्तर:
वह

प्रश्ना 4.
बेला साहिल से नज़र नहीं मिला पाई। क्यों?
उत्तर:
बेला साहिल के सामने खुद को शर्मिदा महसूस कर रही थी, क्यों कि वह साहिल की नज़र में बहुत अच्छी हैं।

प्रश्ना 5.
माटसाब के बुरे व्यवहार से बेला बहुत दुखी हैं। बेला अपने विचारों को डायरी में लिखती है। बेला की उस दिन की डायरी लिखें।
उत्तर:
24.7.2017
बुधवार
ओह… आज का दिन… मैं कैसे भूलूँ? इतना बुरा दिन जिंदगी में पहली बार आया है। गणित का पीरियड था। क्लास में आते ही माटसाब काँपी जाँचने लगे। कॉपी जाँचते समय मास्टरजी की नज़र मूझ पर पडी। मैं ने तो कॉपी लिखी थी। फिर भी मैं भय से काँप रही थी। बिना कुछ कहे माटसाब मेरे बाल पकड़कर फेंका। सब बच्चों की नज़र मुझपर पड़ी। मेरे भयभीत चेहरे को देखकर साहिल बुरी तरह उट गया था। मुझे ऐसा लगा कि मैं अभि गिरजाऊँगी। कुछ समय के बाद माटसाब ने कॉपी मेरे बैठने के स्थान पर फेंकी और मुझसे बैठने को कहा। मुझे अब भी पता नहीं कि मेरी गलती क्या थी? एसा अनुभव जीवन में कभी नहीं हुआ है।

प्रश्ना 6.
क्लास में हुए बुरे अनुभव का जिक्र करते हुए बेला ने अपनी सहेली स्मिता के नाम पत्र लिखा। बेला का पत्र लिखें।
उत्तर:
स्थान
9-3-18 प्रिय मित्र स्मिता नमस्कार तुम कैसे हो? ठीक है न? स्मिता मुझे कल कक्षा में बुरे अनुभव हुआ। गणित का पीरियड माटसाब क्लास में आते ही काँपी जाँचने लगे। काँपी जाँचते समय मास्टरजी की नज़र मुझपर पडी। मैंने तो काँपी लिखी थी, फिर भी मैं भय से काँप रही थी। माटसाब बिना कुछ कहे मेरे बाल पकड़कर फेंका। सब बच्चों की नज़र मुझपर पड़ी। कुछ समय के बाद माटसाब ने काँपी मेरे बैठने के स्थान पर फेंकी और मुझ से बैठने को कहा। मुझे अब भी पता नहीं कि मेरी गलती क्या थी? इतना बुरा अनुभव जिंदगी में कभी नहीं हुआ। स्मिता अभी भी मुझे बहुत दुख है। अगले छुट्टी के दिनों में देखेगा।
तुम्हारा मित्र

बीरबहूटी Additional Questions and Answers

बीरबहूटी आशयग्रहण के प्रश्न

प्रश्ना 1.
‘बादल बहुत बरस लिए थे।’ पेड़-पौधों में इसके क्या निशान थे?

उत्तर:
पेड़ों के तने गीले थे। खेतों में छोटा-छोटा बाजरा उगा था। बाजरे के लंबे पतले पातों में पानी की बूंदें अटकी हुई थीं।

प्रश्ना 2.
बीरबहूटियों की क्या-क्या विशेषताएँ थीं?

उत्तर:
बीरबहूटियाँ सुर्ख, मुलायम और गदबदी थीं। उन्हें देखने पर धरती पर चलती-फिरती खून की बूंदें लगती थीं।

प्रश्ना 3.
साहिल और बेला स्कूल के लिए घर से कुछ समय पहले निकल आते थे। क्यों?

उत्तर:
साहिल और बेला को बीरबहूटियाँ बहुत प्रिय थीं। कस्बे से सटे खेतों में वे बीरबहूटियाँ खोजा करते थे।

प्रश्ना 4.
लेखक के मत में आज का फुलेरा जंक्शन उन्नीस सौ इक्कीस में किन-किन बातों में भिन्न होगा?

उत्तर:
आज जहाँ-तहाँ मीठी घंटियाँ बजाते फेरीवाले नहीं होंगे। गधों की खुरों की टापों की आवाज़ भी शायद ही सुनेंगी। गधे के पीछे चलनेवाले बदन उघाड़े कुम्हार को आज नहीं मिलेगा। स्कूली बच्चे पैन में स्याही नहीं भरते, बल्कि बॉल पैन से काम चलाते होंगे। आज स्टेशनरी की दुकानवाले ड्रॉपर से पैन में स्याही नहीं भरा देते होंगे।

प्रश्ना 5.
‘गणित का माटसाब सुरेंदर जी का पीरियड खेल घंटी के बाद आता था। बच्चे उनसे काँपते थे।’ -बच्चों के डर का कारण क्या है?

उत्तर:
खेल घंटी के बाद के पीरियड में सुरेंदर जी कॉपी जाँचते थे। ज़रा-सी गलती पर बच्चों को इधर उधर फेंक देते थे या झापड़ मारते थे।

बीरबहूटी GRAMMAR Questions and Answers

बीरबहूटी व्याकरण के प्रश्न

बेला के पाँव अभी भी काँप रहे हैं।
स्याही की बोतल अभी-अभी खाली हो गई है।
पानी की बूंदें अटकी हुई थीं।

प्रश्ना 1.
ऐसे परसर्गयुक्त वाक्य कहानी से चुनकर लिखें।

उत्तर:

• मेघों की छायाओं में गीली हवाएँ इधर-उधर घूम रही थीं।
• पेड़ों के तने अभी भी गीले थे।
• मूंगफलियों के हरे खेतों में पीले फूल अभी भी गीले थे।
• बाजरे के लंबे पतले पातों में पानी की बूंदें अटकी हुई थीं।

सामान्य भविष्यत काल:
सूचना : तालिका की पूर्ति करके लिखें।


सूचना : तालिका की पूर्ति करके लिखें।

प्रश्ना 1.
कर्ता का लिंग/वचन के अनुसार क्रिया बदल जाता है।
उत्तर:

भविष्यत्काल के वाक्यों में क्रिया की अन्विति कर्ता के लिंग और वचन के अनुसार होती हैं। लिंग और वचन के अनुसार क्रिया के आठ रूप बनते हैं.
जैसे,
आएगा, आएँगे, आएगी, आएँगी, आऊँगा, आऊँगी, आओगे, आओगी। लिखेगा, लिखेंगे, लिखेगी, लिखेंगी, लिखूगा, लिलूँगी, लिखोगे, लिखेगी।

बीरबहूटी Summary in Malayalam and Translation

बीरबहूटी बीरबहूटी शब्दार्थ 

Students can Download Adisthana Padavali Unit 2 Chapter 3 Koliyum Kilaviyum Questions and Answers, Summary, Notes Pdf, Activity, Adisthana Padavali Malayalam Standard 10 Solutions helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Adisthana Padavali Malayalam Standard 10 Guide Unit 2 Chapter 3 Koliyum Kilaviyum

Koliyum Kilaviyum Questions and Answers, Summary, Notes

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Adisthana Padavali Malayalam Standard 9 Guide Unit 1 Chapter 2 Haritha Mohanam

Haritha Mohanam Questions and Answers, Summary, Notes

Students can Download Kerala Padavali Unit 2 Chapter 2 Priyadarshanam Questions and Answers, Summary, Notes Pdf, Activity, Kerala Padavali Malayalam Standard 10 Solutions helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Padavali Malayalam Standard 10 Guide Unit 2 Chapter 2 Priyadarshanam

Priyadarshanam Questions and Answers, Summary, Notes