Plus Two

Students can Download Chapter 2 National Income Accounting Questions and Answers, Plus Two Economics Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations

Kerala Plus Two Economics Chapter Wise Questions and Answers Chapter 2 National Income Accounting

Plus Two Economics National Income Accounting One Mark Questions and Answers

Question 1.
GNP – depreciation is called
(a) GDP
(b) NNP
(c) PCI
(d) PI
Answer:
(b) NNP

Question 2.
The GDP deflator is equal to
i) Real GDP-Nominal GDP

Answer:
iii) \(\frac{{ No minal GDP }}{\text { Real GDP }} \times 100\)

Question 3.
NFIA is included in:
(a) NNP_FC
(b) NDP_FC
(c) GDP_FC
(d) All the above
Answer:
(a) NNP_FC

Question 4.
Which among the following in a flow concept?
(a) export
(b) wealth
(c) capital
(d) foreign exchange reserve
Answer:
(a) export

Question 5.
When does net factor income from abroad become negative?
(a) NDP < NNP
(b) NNP < NDP
(c) NDP = NNP
(d) none of the above
Answer:
(b) NNP < NDP

Question 6.
When does GDP and GNP of an economy become equal?
(a) When net factor income from abroad is positive
(b) When net factor income from abroad is negative
(c) When net factor income from abroad is zero
(d) None ofthe above.
Answer:
(c) When net factor income from abroad is zero

Plus Two Economics National Income Accounting Two Mark Questions and Answers

Question 1.
Same job is done by a servant and housewife, whose service is included in the national income calculation? Why?
Answer:
Service of a servant is included in the national income calculation, whereas, the service of housewife is not included in the national income. This is because the housewife is not paid for the service she does.

Question 2.
From the following, classify the material into final goods and intermediary goods. Wheat, Bench, Bread, Wood, Rubber, Tyre.
Answer:

Question 3.
Distinguish between real flow and money flow?
Answer:
Flow of goods and services from firms to households is called real flow. Factors of production receive reward for their services in the form of money. Households use this money to buy goods and services produced by firms. This flow of money from firms to households and back to firms is called money flow.

Question 4.
Some variables are given below. Classify them into Stock and Flow

1. Wealth
2. Income of a household
3. Consumption
4. Capital
5. Money Supply
6. Capital formation
7. Inventories
8. Saving of a household

Answer:
a. Stock

• Wealth
• Inventories
• Capital
• Money supply

b. Flow

• Income of a household
• Consumption
• Capital formation
• Saving of a household

Question 5.
GDP = C + I + G + (X – M) = C + S + T Derive the Budget Deficit and Trade Deficit equations from the above identity.
Answer:
GDP = C + I + G + (X – M) = C + S + T
Budget deficit = G – T
Trade deficit = M – X

Plus Two Economics National Income Accounting Three Mark Questions and Answers

Question 1.
“Transfer payments are not included in the national income calculation”. Do you agree? Justify your answer.
Answer:
Yes. Transfer payments like pension, old age pension, etc. are not included in the national income. This is because they are transfer earnings not generated by any economic activity. These payments are usually made by the government out of tax revenue collected from the public. Since these generated incomes are already included in national income calculation there is no need to include transfer payment in the national income calculation again.

Question 2.
State whether the following are included or excluded in the national income.

1. purchase of second hand goods
2. operating surplus
3. production for self-consumption
4. interest
5. windfall gains and loses

Answer:

1. Purchase of second hand goods – excluded
2. operating surplus – included
3. old age pension – excluded
4. Production for self consumption – excluded
5. interest – included
6. windfall gains and loses – excluded

Question 3.
Provide appropriate term.

Answer:

1. Value added
2. GNP
3. NNP
4. NNP_FC

Question 4.
Point out any 3 uses of national income accounting.
Answer:
The uses of national income accounting are given below.

1. It shows the distribution of national income among the various factors of production.
2. National income statistics indicate the contribution of different sectors in the economy.
3. Structural changes in the economy can be assessed by the national income accounting.

Uniform Distribution Calculator is an online tool that helps to calculate the probability distribution for the given values.

Question 5.
Classify the following under proper heads.
Flow of teacher services, Flow of subsidies and taxes, Flow of factor rewards, flow of finished goods, Flow of consumption expenditure, Flow of import goods.

Answer:

Question 6.

• Does not includes prices of imported goods
• Weights are different
• It includes all goods and services
• Includes prices of imported goods
• Weights are constant
• Does not include all goods and services

Answer:
a. Consumer price index

• Includes prices of imported goods
• Weights are constant
• Does not include all goods and services

b. GDP deflator

• Does not include prices of imported goods
• Weights are different
• It includes all goods and services

Question 7.
Assume that there are three goods produced in an economy and they are sold at different prices in dif-ferent years. Calculate GDP Deflator.

Answer:

Question 8.
Calculate Depreciation, Net Indirect Tax and NNPFC from the below data.
GDP_MP = 11300
NDP_MP = 10300
NDP_FC = 10000
NFIA = 1500
Answer:
1. Depreciation = GDP_MP – NDP_MP
= 11300 – 10300
= 1000

2. Net Indirect tax = NDP_MP – NDP_FC
= 10300 – 10000 = 300

3. NNP_FC = NDP_FC + NFIA
= 10000 + 1500
= 11500

Plus Two Economics National Income Accounting Five Mark Questions and Answers

Question 1.
Find the odd one out. Justify your answer.

1. GNP, NNP, CSO, GDP
2. Salary, bonus, GPF, free housing, saving
3. Smuggling, production of wheat, sale of second-hand goods, services of housewives
4. Services of teacher, services of engineer, services of lawyer, services of housewife
5. Unemployment allowances, scholarships, old age pension, support price.

Answer:

1. C.S.O. Others are national income concepts.
2. Saving. Others come under compensation to employees
3. Production of wheat. Others are excluded from national income
4. Services of housewife. Others are included in the national income calculation.
5. Support price. Others are transfer payments.

Question 2.
Match the following.

Answer:

Question 3.
Categorize the following into stocks and flows, wealth, salary, food grain stock, foreign exchange reserves, export, gross domestic saving, capital, change in money supply, quantity of money, capital formation.
Answer:

Question 4.
The phase of circular flow of income in a two sector economy is given below.

1. Complete the diagram.
2. Explain the process of circular flow

Answer:

1.

2. Circular flow of income:
The concept that the aggregate value of goods and services produced in an economy is going around in a circular way. Either as factor payments, or as expenditures on goods and services, or as the value of aggregate production.

Question 5.
Suppose that in a two sector economy the value of finished goods is equal to ₹100 crore and the income generated as factor rewards is also equal to ₹100 crore. The households spend only ₹80 crore.

1. What will happen to the circular flow?
2. Which system can be introduced to correct the circular flow?
3. Name the leakages and injections.

Answer:

1. There will be a mismatch between the real flow and money flow in the circular flow. In other words, the flow will be broken.
2. As a corrective measure, the financial system can be introduced.
3. The leakages is the difference between the income generates and household spending.

This is saving. The injection are the savings that the households, firms and the government take from the financial institutions as borrowings.

Question 6.
1. Estimate the NI of India and Pakistan from the data given below.

2. Which method is used here?
3. What are the other methods of measuring national income?
Answer:

1. National income of India = ₹2885 crore
   National income of Pakistan = ₹1860 crore
2. The method used here is the product method or value added method.
3. Income method and expenditure method are the other two method of measuring national income.

Question 7.
What do you mean by GDP deflator? How far GDP deflator differs from Consumer Price Index?
Answer:
The ratio of nominal to real GDP is a well known index of prices. This is called GDP Deflator. GDP deflator differs from Consumer Price Index. The major points of difference are given below.

1. The goods purchased by consumers do not represent all the goods which are produced in a country. GDP deflator takes into account all such goods and services.

2. CPI includes prices of goods consumed by the representative consumer; hence it includes prices of imported goods. GDP deflator does not include prices of imported goods.

3. The weights are constant in CPI – but they differ according to production level of each good in GDP deflator.

Question 8.
Write down some of the limitations of using GDP as an index of welfare of a country.
Answer:
GDP is the sum total of value of goods and services created within the geographical boundary of a country in a particular year. It gets distributed among the people as incomes. So we may be tempted to treat higher level of GDP of a country as an index of greater well-being of the people of that country. But there are at least three reasons why this may not be correct. They are discussed below.

1. Distribution of GDP – how uniform is it:
If the GDP of the country is rising, the welfare may not rise as a consequence. This is because the rise in GDP may be concentrated in the hands of very few individuals or firms. For the rest, the income may, in fact, have fallen.

In such a case the welfare of the entire country cannot be said to have increased. If we relate welfare improvement in the country to the percentage of people who are better off, then surely GDP is not a good index.

2. Non-monetary exchanges:
Many activities in an economy are not evaluated in monetary terms. For example, the domestic services women perform at home are not paid for. The exchanges which take place in the informal sector without the help of money are called barter exchanges.

This is a case of underestimation of GDP. Hence GDP calculated in the standard manner may not give us a clear indication of the productive activity and well-being of a country.

3. Externalities:
Externalities refer to the benefits (or harms) a firm or an individual causes to another for which they are not paid (or penalized). Externalities do not have any market in which they can be bought and sold. Therefore, if we take GDP as a measure of welfare of the economy we shall be overestimating the actual welfare.

This was an example of negative externality. There can be cases of positive externalities as well. In such cases, GDP will underestimate the actual welfare of the economy.

Question 9.
Assume that GDP in the year 2007 was ₹1,200 which rose to ₹1,800 in 2008. Calculate GDP deflator.
Answer:
GDP deflator = Current year GDP / Base year GDP x 100
= 1800/1200 × 100
= 1.5 × 100
= 1.5 (in percentage terms 150)

Question 10.
Relate and complete the identities/equations in column A with column B.

Answer:

Question 11.
Estimate the Gross National Product at market price and GNP at factor cost through the expenditure method.

Answer:
GNP_MP = private consumption expenditure + govt, final consumption expenditure( gross fixed capital formation + change in stock or inventory investment) + net export + net factor income from abroad
= 475 + 175 + 101 (i.e., 48 + 15 + 38) + 15 + 13
= ₹779 crores.
GN_PC = GNPUD – net indirect taxes
= 779 – 8 = ₹771 crores

Question 12.
Suppose that in a two sector economy, the value o finished goods is equal to ₹200 crore and the income generated as factor rewards is equal to ₹200 crore. The households spend only ₹180 crore. The remaing 20 crore economy saved then.

1. Is ₹20 (saving) included in the circular flow?
2. Which system can be introduced to correct the circular flow?
3. Is saving leakage or injection.

Answer:

1. No, saving (₹20) is excluded in the circular flow.
2. Financial system can be introduced to correct the circular flow.
3. Yes, saving is a leakage.

Question 13.
Fill in the blanks

1. GNP_MP – ……….. = NNP_MP
2. NNP_MP – ………… = NNP_FC
3. GDP_FC+ – ………… = GDP_MP
4. GDP + -………….. = GNP

Answer:

1. GNP_MP – depreciation = NNP_MP
2. NNP_MP – net indirect tax = NNP_FC
3. GDP_FC + net indirect tax = GDP_MP
4. GDP + net factor income from aborad = GNP

Question 14.
Write down the 3 identities of calculating the GDP of a country by the 3 methods. Also briefly explain why each of those should give us the same value of GDP.
Answer:
Gross National Product (GNP) equals Gross National Income equals Gross National Expenditure, i.e.
GNP = GNI = GNE
These are equal because national income is a circular flow of income. Aggregate expenditure is equal to aggregate output which in turn, is equal to aggregate income. However each method has some different items, yet they show exactly identical results.

Their identity can be shown in the following manner:
Reconciling Three Methods of Measuring Gross

Question 15.
The economic recession of 2008 affected the market economics in general and the US in particular. Thou-sands of Indians working abroad lost their job especially in IT and banking sectors and they returned to India. Evaluate its consequences on Indian economy with regard to the following macro variables.

1. The value of GNP
2. Gneral unemployment level
3. Foreign exchange rate

Answer:

1. The value of GNP decreases due to reduction in NFIA.
2. General unemployment level increases.
3. Foreign exchange rate increases.

Plus Two Economics National Income Accounting Eight Mark Questions and Answers

Question 1.
Given below some macro economic indicators. Derive the equations of the following terms:

1. GNP
2. NNP
3. NNP at factor cost
4. Personal income
5. Personal disposable income
6. Private Income
7. National Disposable Income

Answer:
1. GNP = GDP + Factor income earned by the domestic factors of production employed in the rest of the world – Factor income earned by the factors of production of the rest of the world employed in the domestic economy

2. NNP = GNP – Depreciation

3. NNP at factor cost = National Income (NI) = NNP at market prices – (Indirect taxes – Subsidies)

4. Personal income (PI) = NI – Undistributed profits – Net interest payments made by households – Corporate tax + Transfer payments to the households from the government and firms.

5. Personal Disposable Income (PDI) = PI – Personal tax payments – Non-tax payments.

6. Private Income = Factor income from net domestic product accruing to the private sector + National debt interest + Net factor income from abroad + Current transfers from government + Other net transfers from the rest of the world

7. National Disposable Income = Net National Product at market prices + other current transfers from the rest of the world

Question 2.
Prepare a seminar report on the topic ‘Measurement of National Income’.
Answer:
Measurement of National Income Respected teachers and dear friends,
The topic of my seminar paper is ‘measurement of national income or the methods of measuring national income’. The concept of national income occupies an important place in economic theory.

National income is the aggregate money value of all goods and services produced in a country during an accounting year. In this seminar paper, I would like to present various methods of measuring national income.

Content:
National income can be measured in different ways. Generally there are three methods for measuring national income. They are

1. Value-added method
2. Expenditure method
3. Income method

1. Value-added method:
The term that is used to denote the net contribution made by a firm is called its value-added. We have seen that the raw materials that a firm buys from another firm which are completely used up in the process of production are called ‘intermediate goods’.

Therefore the value-added of a firm is the value of production of the firm – value of intermediate goods used by the firm. The value-added of a firm is distributed among its four factors of production, namely, labor, capital, entrepreneurship, and land.

Therefore wages, interest, profits, and rents paid out by the firm must add up to the value-added of the firm. Value-added is a flow variable.

2. Expenditure Method:
An alternative way to calculate the GDP is by looking at the demand side of the products. This method is referred to as the expenditure method. The aggregate value of the output in the economy by expenditure method will be calculated.

In this method we add the final expenditures that each firm makes. Final expenditure is that part of expenditure which is undertaken not for intermediate purposes.

3. Income Method:
As we mentioned in the beginning, the sum of final expenditures in the economy must be equal to the incomes received by all the factors of production taken together (final expenditure is the spending on final goods, it does not include spending on intermediate goods).

This follows from the simple idea that the revenues earned by all the firms put together must be distributed among the factors of production as salaries, wages, profits, interest earnings, and rents.
That is GDP = W + P + In + R

Conclusion:
Thus it can be concluded that there are three methods for measuring national income. These methods are value-added method, income method and expenditure method. Usually in estimating national income, different methods are employed for different sectors and sub sectors.

Question 3.
From the following data, calculate personal income and personal disposable income (₹in Crores).

1. NDPFC – 8,000
2. net factor income from abroad – 200
3. Undistributed profit – 1,000
4. Corporate tax – 500
5. Interest received by households – 1,500
6. Interest paid by households – 1,200
7. Transfer income – 300
8. Personal Tax – 500

Answer:
Personal income = NDPfc + Net factor income from abroad – undistributed profits – corporate taxes + transfer payments + net interest received from households.
= 8000 + 200-1000 – 500 + 300 (1500 -1200)
= 7,300 crores
Personal disposable income = Personal income – personal tax
= 7,300 – 500 = 6,800 crores

Question 4.
Production generates income. Prove this statement with the help of a simple two sector model of circular flow of income.
Answer:
circular flow of income:
It is a pictorial representation of interdependence or interrelationship between the various sectors of the economy. It is a concept associated with income earning and spending. The circular flow of income in a simple economy works on the basis of certain assumptions.
They are as follows:

1. Households and firms are the only two sectors in an economy (2 sector model)
2. Households supply factor services to firms.
3. Firms hire factor services households
4. Household spends their entire income on consumption and thereby no savings are left with them.
5. Firms sell their entire products to the households
6. There is no government in the economy.
7. The economy is not related to any other economies or the economy is a ‘closed’ system. As a result, there is no export or imports from the economy.

In such an economy, there would be two types of markets.
They are:

1. product-market for goods and services
2. factor markets for buying and selling various factor services.

The relationship between the sectors of an economy can be explained with the help of a diagram.

The households own the factors of production such as land, labour, capital, and organization. The households sell these factors of production to the firms for producing goods and services are known as real flow. The rewards for factors of production are rent to land, interest to capital, wage to the labour and profit to the entrepreneur is known as the money flow.

Students can Download Chapter 1 Review of C++ Programming Questions and Answers, Plus Two Computer Application Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus Two Computer Application Chapter Wise Questions and Answers Chapter 1 Review of C++ Programming

Plus Two Computer Application Review of C++ Programming One Mark Questions and Answers

Question 1.
IDE means ______
IDE _______.
Answer:
Integrated Development Environment.

Question 2.
We know that C++ is a high level language. From the following which statement is true.
(a) C++ contains English like statements.
(b) C++ contains mnemonics
(c) C++ contains only 0 and 1
(d) None of these
Answer:
(a) C++ contains English like statements.

Question 3.
C++ is a_____language.
(a) High level
(b) Low level
(c) Middle level
(d) None of these
Answer:
(a) High level.

Question 4.
C++ was developed at_______.
(a) AT & T Bell Laboratory
(b) Sanjose Laboratory
(c) Kansas University Lab
(d) None of these
Answer:
(a) AT & T Bell Laboratory.

Question 5.
C++ is a successor of______language.
(a) C#
(b) C
(c) Java
(d) None of these
Answer:
(b) C.

Question 6.
The most adopted and popular approach to write programs is_______.
Answer:
Structured programming.

Question 7.
From the following which uses OOP concept.
(a) C
(b) C++
(c) Pascal
(d) Fortran
Answer:
(b) C++.

Question 8.
_____is the smallest individual unit.
Answer:
Token

Question 9.
Pick the odd one out
(a) float
(b) void
(c) break
(d) Alvis
Answer:
(d) Alvis, the others are keywords.

Question 10.
Reserved words for the compiler is_______.
(a) Literals
(b) Identifier
(c) Keywords
(d) None of these
Answer:
(c) Key words.

Question 11.
Pick an identifier from the following.
(а) auto
(b) age
(c) float
(d) double
Answer:
(b) age.

Question 12.
Pick the invalid identifier
(a) name
(b) Date of birth
(c) age
(d) joining_time
Answer:
(b) Date of birth, because it contains space.

Question 13.
Pick the octal integer from the following.
(a) 217
(b) 0 × 217
(c) 0217
(d) None of these
Answer:
(c) 0217, an octal integer precedes 0.

Question 14.
Pick the hexa decimal integer from the following.
(а) 217
(b) 0 × 217
(c) 0217
(d) None of these
Answer:
(b) 0 × 217, an hexa decimal integer precedes Ox.

Question 15.
From the following pick a character constant.
(a) ’A’
(b) ‘ALL’
(c) ‘AIM’
(d) None of these
Answer:
(a) ‘A’, a character enclosed between single quote.

Question 16.
Non graphic symbol can be represented by using______
Answer:
Escape Sequence.

Question 17.
Manish wants to write a program to produce a beep sound. Which escape sequence is used to get an alert (sound).
(a) \a
(b) \d
(c) \s
(d) None of these
Answer:
(a) \a.

Question 18.
Ajo wants to print a matter in a new line. Which es-cape sequence is used for this?
(a) \a
(b) \n
(c) \s
(d) None of these
Answer:
(b) \n.

Question 19.
To represent null character______is used
(a) \n
(b) \0
(c) \f
(d) \s
Answer:
(b) \0.

Question 20.
State True/False a string is automatically appended by a null character.
Answer:
True.

Question 21.
From the following pick a string constant.
(a)  ‘a’
(b) “abc”
(c) ‘abc’
(d) None of these
Answer:
(b) “abc”, a character constant must be enclosed between double quotes.

Question 22.
C++ was developed by______
(a) Bjarne Stroustrup
(b) James Gosling
(c) Pascal
(d) None of these
Answer:
(a) Bjarne Stroustrup.

Question 23.
From the following which is not a character constant.
а) ‘c’
b) ‘e’
c) ‘d’
d) “c”
Answer:
(d) “c”, It is a string constant the others are character constant.

Question 24.
From the following which is a valid declaration.
(a) int 91;
(b) int x;
(c) int 9x;
(d) int “x”;
Answer:
(b) int x;

Question 25.
Symbols used to perform an operation is called_______
(a) Operand
(b) Operator
(c) Variable
(d) None of these
Answer:
(b) Operator.

Question 26.
Consider the following. C = A + B. Here A and Bare called______
(a) Operand
(b) Operator
(c) Variable
(d) None of these
Answer:
(b) Operand.

Question 27.
The. execution of a program starts at_______function.
Answer:
main()

Question 28.
The execution of a program ends with______function
Answer:
main()

Question 29.
______USed to write single line comment
(a) //
(b) /*
(c) */
(d) None of these
Answer:
(a) //

Question 30.
const k = 100 means const k = 100
(a) const float k = 100
(b) const double k = 100
(c) const int k = 100
(d) const chark = 100
Answer:
(c) const int k = 100

Question 31.
Each and every statement in C++ must be end with_____
(а) Semi colon
(b) Colon
(c) full stop
(d) None of these
Answer:
(a) Semi colon

Question 32.
From the following select the input operator.
(a) >>
(b) <<
(c) >
(d) <
Answer:
(a) >>

Question 33.
From the following select the output operator.
(a) >>
(b) <<
(c) >
(d) <
Answer:
(b) <<

Question 34.
In while loop, the loop variable should be updated?
(a) along with while statement
(b) after the while statement
(c) before the while statement
(d) inside the body of while
Answer:
(d) Inside the body of while

Question 35.
Adeline wrote a C++ program namely sum.cpp and she compiled the program successfully with no error. Some files are generated. From the following which file is a must to run the program
(a) sum.exe
(b) sum.obj
(c) sum.vbp
(d) sum.htm
Answer:
(a) sum.exe

Question 36.
Adeline wrote a C++ program namely sum.cpp and she compiled the program successfully with no error. Some files are generated namely sum.obj and sum.exe. From this which file is not needed to run the program
Answer:
sum.obj is not needed and can be deleted.

Question 37.
To terminate a program, from the following which is used.
(a) break
(b) continue
(c) end()
(d) exit()
Answer:
(d) exit()

Question 38.
To write a C++ program, from the following which statement is a must.
(a) sum()
(b) main()
(c) #include
(d) #include
Answer:
(b) main(). A C++ program must contains at least one main() function.

Question 39.
State True / False. Comment statements are ignored by the compiler
Answer:
True.

Question 40.
More than one input / output operator in a single statement is called______.
Answer:
Cascading of I/O operator.

Question 41.
From the following which is ignored by the compiler.
(a) statement
(b) comments
(c) loops
(d) None of these
Answer:
(b) comments

Question 42.
From the following which is known as string terminator
(a) ‘\0’
(b) ‘\a’
(c) *\s*
(d) ‘\t’
Answer:
(a) ‘\0’

Question 43.
______is the main activity carried out in computers.
Answer:
Data processing.

Question 44.
The data used in computers are different. To differentiate the nature and size of data______is used.
Answer:
Data types.

Question 45.
Classify the following data types.

1. int
2. array
3. function
4. char
5. pointer
6. void
7. float
8. double
9. structure

Answer:

Question 46.
Sheela wants to store her age. From the following which is the exact data type.
(a) void
(b) char
(c) int
(d) double
Answer:
(c) int

Question 47.
Integer data type uses_____bytes of memory
(a) 5
(b) 2
(c) 3
(d) 4
Answer:
(b) 2

Question 48.
char data type uses______bytes of memory
(a) 1
(b) 3
(c) 7
(d) 8
Answer:
(a) 1

Question 49.
From the following which data type uses 4 bytes of memory
(a) float
(b) short
(c) char
(d) double
Answer:
(a) float

Question 50.
Full form of ASCII is______.
Answer:
American Standard Code for Information Interchange.

Question 51.
Ramu wants to store the value of From the following which is correct declaration
(а) char pi = 3.14157
(b) int pi = 3.14157
(c) float pi = 3.14157
(d) long pi = 3.14157
Answer:
(c) float pi = 3.14157.

Question 52.
From the following which is not true, to give a variable name.
(a) Starting letter must be an alphabet
(b) contains digits
(c) Cannot be a key word
(d) special characters can be used
Answer:
(d) special characters can be used

Question 53.
Pick a valid variable name from the following
(а) 9a
(b) float
(c) age
(d) date of birth
Answer:
(c) age

Question 54.
To perform a unary operation how many number of operands needed?
(a) 2
(b) 3
(c) 1
(d) None of these.
Answer:
(c) 1 (Unary means one)

Question 55.
To perform a binary operation how many number of operands needed?
(a) 2
(b) 3
(c) 1
(d) None of these.
Answer:
(a) 2 (binary means two)

Question 56.
To perform a ternary operation how many number of operands needed?
(a) 2
(b) 3
(c) 1
(d) None of these.
Answer:
(b) 3(eg: ternary means three)

Question 57.
In C++ 13 % 26 =_______
(a) 26
(b) 13
(c) 0
(d) None of these
Answer:
13. % is a mod operator i.e. it gives the remainder. Here the remainder is 13.

Question 58.
In C++ 41/2 =______
(a) 20.5
(b) 20
(c) 1
(d) None of these
Answer:
(b) 20. (The actual result is 20.5 but both 41 and 2 are integers so .5 must be truncated).

Question 59.
++ is a_____operator
(a) Unary
(b) Binary
(c) Ternary
(d) None of these
Answer:
(a) Unary.

Question 60.
Conditional operator is______operator
(a) Unary
(b) Binary
(c) Ternary
(d) None of these
Answer:
(c) Ternary

Question 61.
% is a_____operator
(a) Unary
(b) Binary
(c) Ternary
(d) None of these
Answer:
(b) Binary

Question 62.
State True/False

1. Multiplication, division, modulus have equal priority
2. Logical and (&&) has less priority than logical or ()

Answer:

1. True
2. False

Question 63.
______is composed of operators and operands
(a) expression
(b) Key words
(c) Identifier
(d) Punctuators
Answer:
(a) expression

Question 64.
Supply value to a variable at the time of declaration is known as______.
Answer:
Initialisation.

Question 65.
From the following which is initialisation
(a) int k;
(b) int k = 100;
(c) int k[10];
(d) None of these
Answer:
(b) int k= 100;

Question 66.
State True/False
In an expression, aH the operands having lower size are converted(promoted) to the data type of the highest sized operand.
Answer:
True

Question 67.
Classify the following as arithmetic / Logical expression.
(a) x + y * z
(b) x < y && y > z
(c) x/y
(d) x > 89 || y < 80
Answer:
(a) and (c) are Arithmetic
(b) and (d) are Logical

Question 68.
Suppose x = 5 and y = 2 then what will be count << (float) x/y.
Answer:
2.5 The integer x is converted to float hence the result.

Question 69.
Considerthe following ,
a = 10; a* = 10;
Then a =______
(a) a = 100
(b) a = 50
(c) a = 10
(d) a = 20
Answer:
(a) a = 100, This short hand means a = a * 10

Question 70.
Consider the following a = 10; a+ = 10; Then a =_____
(a) a = 30
(b) a = 50
(c) a = 10
(d) a = 20
Answer:
(d) a = 20. This short hand means a = a + 10.

Question 71.
Pick the odd one out
(a) structure
(b) Array
(c) Pointer
(d) int
Answer:
(d) int, it is fundamental data type the others are derived data types.

Question 72.
From the following select not a character of C++ language
(a) A
(b) 9
(c) \
(d) @
Answer:
(d) @

Question 73.
Consider the following float x = 25.56; cout << (int)x;
Here the data type of the variable is converted. What type of conversion is this?
(a) type promotion
(b) type casting
(c) implicit conversion
(d) None of these
Answer:
(b) type casting (explicit conversion);

Question 74.
From the following which is ignored by the compiler
(a) statement
(b) comments
(c) loops
(d) None of these
Answer:
(b) comments

Question 75.
Multi line comment starts with____and ends with_____
(a) /’ and ‘/
(b) */ and /*
(c) /* and */
(d) ‘/ and /’
Answer:
(c) /* and */

Question 76.
Single line comment starts with_____
(a) **
(b) @@
(c) */
(d) //
Answer:
(d) //

Question 77.
Alvin wants to store the value of π From the following which is correct declaration
(a) char pi = 3.14157
(b) const int pi = 3.14157
(c) const float pi = 3.14157
(d) long pi = 3.14157
Answer:
(c) const float pi = 3.14157

Question 78.
To store 70000 which modifier is used with int.
(a) long
(b) short
(c) big
(d) none of these
Answer:
(a) long

Question 79.
To store 60000 which modifier is used with int.
(a) unsigned
(b) short
(c) big
(d) none of these
Answer:
(a) unsigned

Question 80.
Consider x++(post fix form). Select the correct definition from the following
(a) The operation is performed after the value is used
(b) The operation is performed before the value is used
(c) First change then use
(d) None of these
Answer:
(a) The operation is performed after the value is used

Question 81.
Consider ++x(pre fix form). Select the correct definition from the following
(a) The operation is performed after the value is used
(b) The operation is performed before the value is used
(c) First use then change
(d) None of these
Answer:
(b) The operation is performed before the value is used

Question 82.
Consider the following int a = 10; float b = 4; cout << a/b; We know that the result is 2.5 a float. What type of conversion is this?
(a) type promotion
(b) type casting
(c) explicit coversion
(d) None of these
Answer:
(a) type promotion (implicit conversion);

Question 83.
From the following which has the major priority?
(а) ++
(b) =
(c) ==
(d) &&
Answer:
(a) ++

Question 84.
One of your friend told you that post increment (eg:x++) has more priority than pre increment (eg: ++x). State True/False
Answer:
It is true.

Question 85.
Raju declared a variable as follows. unsigned number;
So he can a store a number in the range______
(a) 0 to 65535
(b) -32768 to 32767
(c) 0 to 65536
(d) 0 to 95536
Answer:
(a) 0 to 65535. Unsigned uses only 2 bytes of memory but no negative numbers can store.

Question 86.
Considerthe following declaration. signed number;
So we can a store a number in the range______
(a) 0 to 65535
(b) -32768 to 32767
(c) 0 to 65536
(d) 0 to 95536
Answer:
(b) -32768 to 32767

Question 87.
Pick the odd one out
(a) long
(b) short
(c) unsigned
(d) int
Answer:
(d) int. It is fundamental type modifiers.

Question 88.
Memory size and sign can be changed using______with fundamental data types.
Answer:
Type modifiers.

Question 89.
“Its value does not change during execution”. What is it?
Answer:
Constant.

Question 90.
“BVMHSS” is called______
(a) integer constant
(b) float constant
(c) string constant
(d) None of these
Answer:
(c) string constant

Question 91.
The address of a variable is called______
Answer:
L-value (Location value) of a variable.

Question 92.
The content of a variable is called_______
Answer:
R-value (Read value) of a variable.

Question 93.
Suppose the address of a variable age is 1001 and the content i.e. age = 33. Then what is R-value and L-value?
Answer:
R-value is 33 and L-value is 1001.

Question 94.
A total of 65535 single window +1 application forms are sold in a district. To store the application form, from the following which is valid?
(a) unsigned app_no;
(b) intapp_no;
(c) signed app_no;
(d) none of these
Answer:
(a) unsigned app_no;

Question 95.
is it possible to declare a variable as and when a need arise. What kind of declaration is this?
Answer:
Yes. It is known as Dynamic declaration.

Question 96.
Emerin wants to store a constant value. Which key word is used for this?
Answer:
constant.

Question 97.
Suppose x = 5. Then cout << x++ displays_____
Answer:
5. Here post increment first use the value then incremented.

Question 98.
Suppose x = 5. Then cout << ++x displays_____
Answer:
6. Here pre increment first incremented and then use the value.

Question 99.
An if statement contains another if statement completely. Then it is known as______
Answer:
Nested if

Question 100.
From the following which is not optional with switch statement.
Answer:
(a) break
(b) default
(c) case
(d) none of these
Answer:
(c) case.

Question 101.
To exit from a switch statement______is used
(a) quit
(b) exit
(c) break
(d) none of these
Answer:
(c) break

Question 102.
From the following which statement is true for switch statement
(a) switch is used to test the equality
(b) switch is used to test relational or logical expression
(c) switch can handle real numbers case data
(d) none of these
Answer:
(a) switch is used to test the equality

Question 103.
Sonet wants to execute a statement more than once. From the following which is exactly suitable.
(a) if
(b) loop
(c) switch
(d) if-else if ladder
Answer:
(b) loop

Question 104.
Odd one out
(a) for
(b) if
(c) switch
(d) if-else if ladder
Answer:
(a) for. It is a loop the others are branching statement

Question 105.
Odd one out
(a) for
(b) if
(c) while
(d) do while
Answer:
(b) if. It is a branching statement and the others are loops.

Question 106.
From the following which loop does the three things, initialisation, checking, and updation.
(a) while
(b) do while
(c) for
(d) none of these
Answer:
(c) for

Question 107.
Predict the output for(i=1;i<=10;i++); cout<<i;
(a) 10
(b) 1 to 10.
(c) 11
(d) None of these
Answer:
(c) 11.

Question 108.
From the following which is exit controlled loop
(a) for
(b) while
(c) do while
(d) None of these
Answer:
(c) do while

Question 109.
_____statement is used for unconditional jump from one location to another.
Answer:
goto.

Question 110.
Sunitha wants to skip one iteration. From the following which will help her?
(a) continue
(b) break
(c) for
(d) case
Answer:
(a) continue.

Question 111.
Pick the odd one out from the following. Give reason
1. (a) for
(b) while
(c) do____while
2. (a) if
(b) switch
(c) for
Answer:

1. do_____while . It is an exit controlled loop others are entry controlled loop
2. for. It is a loop while others are branching statements.

Question 112.
Identify the error in the following C++ statement and correct it. short population = 68000;
Answer:
The maximum number that can store in short type is less than 32767. So to store 68000 we have to use long data type.

Question 113.
What would be the appropriate data type to store the following?

1. Number of students in a classroom
2. Age of a student
3. Average mark of a student
4. A question mark (?)

Answer:

1. short or int
2. short or int
3. float
4. char

Question 114.
Pick odd one out from the following loops. Give the reasons.
(a) for
(b) while
(c) do___while
Answer:
(c) do while. This is an exit controlled loop others are entry controlled loop.

Question 115.
Which of the following data types of C++ has no type modifier?
(a) void
(b) int
(c) char
(d) short
Answer:
(a) void

Plus Two Computer Application Review of C++ Programming Two Mark Questions and Answers

Question 1.
Mr. Dixon declared a variable as follows
int 9 age. Is it a valid identifier. If not briefly explain the rules for naming an identifier.
Answer:
It is not a valid identifier because it violates the rule 1. The rules for naming an identifier is as follows.

• It must be start with a letter(alphabet)
• Underscore can be considered as a letter
• White spaces and special characters cannot be used.
• Key words cannot be considered as an identifier

Question 2.
Rose wants to print as follows \n is used for New Line
Write down the C++ statement for the same.
Answer:
# include
using namespace std;
{
cout<<“\\n is used for New Line”;
}

Question 3.
Alvis wants to give some space using escape sequence as follows
Welcome to C++
Write down the C++ statement for the same
Answer:
# include
using namespace std;
int main()
{
cout<<“welcome to \t C++”;
}

Question 4.
How many bytes used to store ‘\a’.
Answer:
To store ‘\a’ one byte is used because it is an escape sequence. An escape sequence is treated as one character. To store one character one byte is used.

Question 5.
How many bytes used to store “\abc”.
Answer:
A string is automatically appended by a null character.
Here one byte for \a(escape sequence).
One byte for character b.
One byte for character c.
And one byte for null character.
So a total of 4 bytes needed to store this string.

Question 6.
How many bytes used to store “abc”.
Answer:
A string is automatically appended by a null character.
Here one byte for a.
One byte for character b.
One byte for character c.
And one byte for null character.
So a total of 4 bytes needed to store this string.

Question 7.
We know that the value of pi = 3.14157, a constant (literal). What is a constant? Explain it?
Answer:
A constant ora literal is a data item its value doe not change during execution.

1. Integer literals:
Whole numbers without fractional parts are known as integer literals, its value does not change during execution. There are 3 types decimal, octal, and hexadecimal.
Eg. For decimal 100,150,etc
For octal 0100,0240, etc
For hexadecimal 0 × 100, 0 × 1 A, etc

2. Float literals:
A number with fractional parts and its value does not change during execution is called floating-point literals.
Eg. 3.14157,79.78,etc.

3. Character literal:
A valid C++ character enclosed in single.

Question 8.
Write a program to print the message “TOBACCO CAUSES CANCER” on screen.
Answer:
#include
using namespace std;
int main()
{
cout<<“TOBACCO CAUSES CANCER”;
}

Question 9.
Consider the following code
int main()
{
cout<<“welcome to C++”;
}
After you compile this program there is an error called prototype error. Why it is happened? Explain Answer:
Here we used the output operator cout<<. It is used to display a message “welcome to C++” to use this operator the corresponding header file must be included and using namespace std; is also include. We didn’t included the header file hence the error.

Question 10.
You are supplied with a list of tokens in C++ program, Classify and Categorise them under proper headings. Explain each category with its features. tot_mark, age, M5,_____break,(), int, _pay, ; , cin
Answer:

Question 11.
In C++ the size of the string “book” is 5 and that of “book\n” is 6. Check the validity of the above statement. Justify your answer.
Answer:
A string is automatically added by a null character(\0). The null character is treated as one character. So the size of string “book” is 5. Similarly, a null character (\0) is also added to “book\n”. \n and \0 is treated as single characters. Hence the size of the string “book\n” is 6.

Question 12.
Is 0 × 85B a valid integer constant in C++? If yes why?
Answer:
Yes. It is a hexa decimal number.

Question 13.
Pick the odd man out. Justify
TOTSAL, TOT_SAL, totsal5, Tot5_sal, SALTOT, tot.sal
Answer:
tot.sal. Because it contains a special character dot(.). An identifier cannot contain a special character. So it is not an identifier. The remaining satisfies the rules of naming identifier. So they are valid identifier.

Question 14.
Write a C++ statement to print the following sentence. Justify “\ is a special character”
Answer:

1. cout<<“\\ is a special character”
2. \\ is treated as an escape sequence.

Question 15.
A student type a C++ program and saves it in his personal folder as Sample.cpp. After getting the output of the program, he checks the folder and finds three files namely Sample.cpp, Sample.obj and Sample.exe. Write the reasons for the generation of the two files in the folder.
Answer:
After the compilation of the program sample.cpp, the operating system creates two files if there is no error. The files are one object file (sample.obj) and one executable file(sample.exe). Now the source file(sample.cpp) and object file(sample.obj) are not needed and can be deleted. To run the program sample.exe is only needed.

Question 16.
Write a program to print the message “SMOKING IS INJURIOUS TO HEALTH” on screen.
Answer:
#include
using namespace std;
int main()
{
cout<<” SMOKING IS INJURIOUS TO HEALTH”;
}

Question 17.
Consider the following
short number;
number = 76543;
Is it valid. Explain?
Answer:
It is not valid. Because the data type int uses only two bytes(16 bits) of memory. That is we can store a total of 216 = 65536 integers. There are 2 types of integers negative integers and positive integers, i.e. 32768 each.

So we can store a number in between -32768 to +32767 (0 included in the positive section). The number 76543 is bigger than this range. Hence there is an error overflow. To store this number declare the variable is as follows.
long number;

Question 18.
Consider the following declaration.
const int bp;
bp = 100;
Is it valid? Explain it?
Answer:
This is not valid. This is an error. A constant variable cannot be modified. That is the error and a constant variable must be initialised. So the correct declaration is as follows, const int bp = 100;

Question 19.
Consider the following statements in C++

• cout<<41/2;
• cout<<41/2.0;

Are this two statements give same result? Explain?
Answer:
This two statements do not give same results. The first statement 41/2 gives 20 instead of 20.5. The reason is 41 and 2 are integers. If two operands are integers the result must be integer, the real part must be truncated.

To get floating result either one of the operand must be float. So the second statement gives 20.5. The reason is 41 is integer but 2.0 is a float.

Question 20.
If mark = 70 then what will be the value of variable result in the following result = mark > 50? ‘P’: ‘F’;
Answer:
The syntax of the conditional operator is given below Condition? Value if true: Value if false; Here the conditional operator first checks the condition i.e.,70 > 50 it is true. So ‘P’ is assigned to the variable result. So the result is d ‘P’;

Question 21.
Is it possible to initialise a variable at the time of execution. What kind of initialisation is this? Give an example.
Answer:
Yes it is possible. This is known as Dynamic initialisation. The example is given below
Eg: int a=10, b=5;
int c = a*b;
here the variable c is declared and initialised with the value 10*5.

Question 22.
Boolean data type is used to store True / False in C++. Is it true? Is there any data type called Boolean in C++?
Answer:
No there is no data type for storing boolean value true /false. But in C++ non -zero (either negative or positive) is treated as true and zero is treated as false.

Question 23.
Consider the following
n=-15;
if (n)
cout<<“Hello”;
else
cout<<“hai”;
What will be the output of the above code?
Answer:
The output is Hello, because n = -15 a non zero number and it is treated as true hence the result.

Question 24.
Is it possible to declare a variable in between the program as and when the need arise? Then what is it?
Answer:
Yes it is possible to declare a variable in between the program as and when the need arise. It is known as dynamic initialisation.
Eg. int x=10, y=20;
_____
_____
int z=x*y;

Question 25.
charch;
cout<<“Enter a character”; cin>>ch;
Considerthe above code, a user gives 9 to the variable ‘ch’. Is there any problem? Is it valid?
Answer:
There is no problem and it is valid since 9 is a character. Any symbol from the key board is treated as a character.

Question 26.
“With the same size we can change the sign and range of data”. Comment on this statement.
Answer:
With the help of type modifiers we can change the sign and range of data with same size. The important modifiers are signed, unsigned, long and short.

Question 27.
Write short notes about C++ short hands?
Answer:
x = x + 10 can be represented as x+=10, It is called short hands in C++. It is faster. This is used with all the arithmetic operators as follows.

Question 28.
What is the role of ‘const’ modifier?
Answer:
This ‘const’ key word is used to declare a constant. Eg. const int bp = 100; By this the variable bp is treated as constant and cannot be possible to change its value during execution.

Question 29.
Specify the most appropriate data type for handling the following data.

1. Rollno. of a student.
2. Name of an employee.
3. Price of an article.
4. Marks of 12 subjects

Answer:

1. short Rollno;
2. charname[20];
3. float price;
4. short marks[12];

Question 30.
Write C++ statement for the following.

1. The result obtained when 5 is divided by 2.
2. The remainder obtained when 5 is divided by 2.

Answer:

1. 5/2
2. 5%2

Question 31.
Predict the output of the following code. Justify.
int k = 5, b = 0;
b = k++ + ++k;
cout<<b; (2 Scores)
Answer:
Output is 12. In this statement first it take the value of k in 5 then increment it K++. So first operand for + is 5. Then it becomes 6. Then ++k makes it 7. This is the second operand. Hence the result is 12.

Question 32.
Predict the output.

1. int sum = 10, ctr= 5;
   sum = sum + ctr __;
   cout<<sum;
2. int sum = 10, ctr = 5;
   sum = sum + ++ctr; court<<sum;

Answer:

1. 15
2. 16

Question 33.
Predict the output
int a;
float b;
a = 5;
cout<<sizeof(a + b/2);
Answer:
Output is 4. Result will be the memory size of floating point number.

Question 34.
Predict the output.
int a, b, c;
a = 5; b = 2;
c = a/b;
cout<<c;
Answer:
Output is 2. Both operands are integers. So the result will be an integer.

Question 35.
Explain cascading of i/o operations.
Answer:
The multiple use of input or output operators in a single statement is called cascading of i/o operators. Eg: To take three numbers by using one statement is as follows cin>>x>>y>>z; To print three numbers by using one statement is as follows. cout<<x<<y<<z;

Question 36.
Trace out and correct the errors in the following code fragments

1. cout<<“Mark=”45;
2. cin<<“HellowWorld!”;
3. cout>>”X + Y;
4. Cout<<‘Good'<<‘Moming’

Answer:

1. cout<<“Mark=45”;
2. cout<<“HellowWorld!”;
3. cout<<X + Y
4. Cout<<“Good Morning”;

Question 37.
What do you mean by preprocessor directive?
Answer:
A C++ program starts with the preprocessor directive i.e., #include, #define, #undef, etc, are such a preprocessor directives. By using #include we can link the header files that are needed to use the functions. By using #define we can define some constants.
Eg. #definex100. Here the value of x becomes 100 and cannot be changed in the program.

Question 38
Write a program to print a message as ” Hello, Welcome to C++”.
Answer:
#include
using namespace std;
int main()
{
cout<<” Hello, Welcome to C++”;
}

Question 39.
Write a program to generate the following table.

Use a single cout statement for output
Answer:
# include
using namespace std;
int main ()
{
cout<<“2013\t 100%\n2012\t99.9%\n2011\t95.5%\n2010\t90.81%\n2009\t85%”;
}

Question 40.
Determine the data type of the following expression If a is an int, b is a float, c is a long int and d is a double

Answer:
In type promotion the operands with tower data type will be converted to the highest data type in the expression. So consider the following,

= double + long
= double (Which is the highest data type).

Question 41.
White writing a program Geo uses while loop but forgets to update the loop variable. What will happen?
Answer:
The loop variable inside the while loop must be updated otherwise the loop will not be terminated. The loop will be work infinitely.

Question 42.
Draw the flow chart of if statement.
Answer:

Question 43.
Draw the flow chart of if else statement.
Answer:

Question 44.
Write a while loop that display numbers from 500 to 550.
Answer:
int i=500
while (i<=550)
{
cout<<i;
i=i+1;
}

Question 45.
Compare if else and conditional operator?
Answer:
We can use conditional operator as an alternative of if-else statement. The conditional operator is a ternary operator.
The syntax of if-else
if (expression 1)
expression 2;
else
expression 3;
First expression 1 is evaluated if it is true expression 2 will be executed otherwise expression 3 will be executed. Instead of this, we can be written as follows using conditional operator Expression 1? expression 2: expressions;

Question 46.
Draw the flow chart of for loop.
Answer:

Question 47.
Find out the error in syntax if any and correct it? esm<oi!Bl

Answer:
a) No need of semi colon. The corrected loop is given below
while (test condition)
{
}

b) In do____white loop the while must be end with; semicoion.
do (condition)
{
}while;

c) switch contains expression instead of condition switch(expression)
{
Case 1:
Case 2:
Case 3:
Case 4:
}

Question 48.
State whether the following statements are True or False. In either case Justify your answer

1. Break statements essential in switch
2. For loop is an entry controlled loop
3. Do____white loop is an entry controlled loop
4. Switch is a selection statement

Answer:

1. False. It is not essential in single case statement
2. True. Because it will first check the condition. If it is true then only the body will be executed.
3. False. It is an exit controlled loop.
4. True.

Question 49.
Given a code segment for(i=1; i<10; i++) cout<<i;

1. Rewrite the code using do____while loop
2. What will be the output when i=0? Give reason.

Answer:
1. i=1;
do{
cout<<i;
i++;
}while(i<10);

2. When i=0, it will execute one more time. ie. the for loop execute 9 times but here this loop executes 10 times.

Question 50.
Write the equivalent code for the following statement R=(P<Q?P: Q)
Answer:
if(P<Q)
R=P;
else
R=Q;

Question 51.
Examine the following code snippet and find out the output? What will happen if the statement int ch; is replaced char ch;
int ch;
for(ch=’A’;ch<=’Z’;++ch)
cout<<ch<<”;
Answer:
This code snippet will print 65, 66, 67, ______,90. If the statement int ch; is replaced by char ch; it prints A, B, C,_____,Z.

Question 52.
Your friend usee the following identifiers in a program. Find out the invalid identifiers with reason if not valid, basic pay area, data-of-birth, B3, 9A, switch
Answer:
basic pay – Invalid because white space is not allowed.
area – valid
date-of-birth – Invalid because hyphen(-) is not allowed.
B3 – Valid
9A – Invalid because should not begin with number.
switch – Invalid because keywords not allowed.

Question 53.
int x=5;
int y=10;
cout<<(x+y)%2;
Answer:
(x+y) % 2 = (5+10)%2 = 15% 2 =1 It prints 1.

Question 54.
Classify the following C++ tokens in accordance to the table given below.

Answer:
keyword: int, do
Identifier: digit, cin(pre defined identifier, eg. int cin; is possible);
Literal: “break”(string literal), 25.6(float literal).
Operator: %(Mod operator), = (assignment operator).

Question 55.
Rewrite the following C++ code using conditional operator.
if (a>b)
max=a;
else
max=b;
Answer:
max=(a>b)?a:b;

Question 56.
Write the C++ expression to calculate the value of the following expression.

1. x = \(\frac{\left(b^{2}-4 a c\right)}{2 a}\)
2. y = a2 + 2ab + b2

Answer:

1. x= (b*b – 4*a*c)/(2*a);
2. y= a*a + 2*a*b + b*b;

Question 57.
Consider the following code and predict the output. Justify your answer.
for(int i=i;i<10;++i)

Answer:
The output is 1 2 3 4 5 6 7. This loop is used to print 1 to 10 but this loop will terminate when the value of i becomes 8. Hence it prints 1 to 7.

Question 58.
Predict the output for the following program code.
for(i=1;i<=10;++i)
{
if (i==7)
coutinue;
cout<<“\t”;
cout<< i;
}
Answer:
The output is 1 2 3 4 5 6 8 9 10.
This loop is used to print 1 to 10 but this loop will by pass one iteration when the value of i becomes 7. Hence it prints 1 to 10 except 7.

Question 59.
How many times the following loop will be executed?
int s = 0, i = 0;
do
{
S+= i;
i++;
} while(i < = 5);
Answer:
This loop will be executed 6 times. The value of i becomes 1 to 6.

Plus Two Computer Application Review of C++ Programming Three Mark Questions and Answers

Question 1.
In a panchayath or municipality, all the houses have a house number, house name, and members. Similar situation is in the case of memory. Explain.
Answer:
The named memory locations are called variable. A variable has three important things

1. variable name: A variable should have a name
2. Memory address: Each and every byte of memory has an address. It is also called location (L) value
3. Content: The value stored in a variable is called content.lt is also called Read(R) value.

Question 2.
Briefly explain constants
Answer:
A constant or a literal is a data item its value doe not change during execution. The keyword const is used to declare a constant. Its declaration is as follows
const data type variable name=value;
eg.const int bp = 100;
const float pi = 3.14157;
const char ch = ‘a’;
const char[] = “Alvis”;

1. Integer literals:
Whole numbers without fractional parts are known as integer literals, its value does not change during execution. There are 3 types decimal, octal, and hexadecimal.
Eg. For decimal 100,150,etc
For octal 0100,0240, etc
For hexadecimal 0 × 100, 0 × 1A,etc.

2. Float literals:
A number with fractional parts and its value does not change during execution is called floating point literals.
Eg. 3.14157,79.78,etc.

3. Character literal:
A valid C++ character enclosed in single quotes, its value does not change during execution.
Eg. ‘m’, ‘f, etc.

4. String literal:
One or more characters enclosed in double quotes is called string constant. A string is automatically appended by a null charater(‘\0’)
Eg. “Mary’s”,”India”,etc.

Question 3.
Considerthe following statements
int a=10, x=20;
float b=49000.34, y=56.78;

1. a=b;
2. y=x;

Is there any problem for the above statements? What do you mean by type compatibility?
Answer:
Assignment operator is used to assign the value of RHS to LHS. Following are the two chances

1. The size of RHS is less than LHS. So there is no problem and RHS data type is promoted to LHS. Here it is compatible.
2. The size of RHS is higher than LHS. Here comes the problem sometimes LHS cannot possible to assign RHS. There may be a chance of wrong answer. Here it is not compatible.
   Here
   • a=b; There is an error since the size of LHS is 2 but the size of RHS is 4.
   • y=x; There is no problem because the size of LHS is 4 and RHS is 2.

Question 4.
A company has decided to give incentives to their salesman as per the sales. The criteria is given below.
If the total sales exceeds 10,000 the incentive is 10%

1. If the total sales >=5,000 and total sales <10,000, the incentive is 6 %
2. If the total sales >=1,000 and total sales <5,000, the incentive is 3 %

Write a C++ program to solve the above problem and print the incentive after accepting the total sales of a salesman. The program code should not make use of if statement.
Answer:
# include
using namespace std;
int main()

Question 5.
A C++ program code is given below to find the value of X using the expression
X = \(\frac{a^{2}+b^{2}}{2 a}\) where a and b are variables 2a
# include
using namespace std;
int main()

Pre did the type of errors during compilation, execution, and verification of the output. Also write the output of two sets of input values

1. a=4, b=8
2. a=0, b=2

Answer:
This program contains some errors and the correct program is as follows.
#include
using namespace std;
int main()

The output is as follows

1. a=4 and b= 8 then the output is 10
2. a=0 and b= 2 then the output is an error divide by zero error(run time error).

Question 6.
We know that a program has a structure. Explain the structure of C++ program.
Answer:
A typical C++ program would contain four sections as shown below.
Include files
Function declarations
Function definitions
Main function programs
Eg.
# include
using namespace std;
int sum(int x, int y)
{return (x+y);}
int main()
{
cout<<sum(2,3);
}
}

Question 7.
Write a program to read two numbers and find its sum.
Answer:
#include
using namespace std;
int main()

Question 8.
Write a program to read three scores and find the average.
Answer:
#include
using namespace std;
int main()

Question 9.
Write a program to find the area and perimeter of a circle.
Answer:
#include
using namespace std;
int main()

Question 10.
Write a program to find the simple interest
Answer:
# include
using namespace std;
int main()

Question 11.
Write a program to convert temperature from Celsius to Fahrenheit.
Answer:
# include
using namespace std;
int main()

Question 12.
Write a program to read weight in grams and convert it into Kilogram.
Answer:
# include
using namespace std;
int main()

Question 13.
Write a program to read your height in meter and cm convert it into Feet and inches
Answer:
# include
using namespace std;
int main()

Question 14.
Write a program to find the area of a triangle.
Answer:
# include
using namespace std;
int main()

Question 15.
Write a program to

1. print ASCII for a given digit.
2. print ASCII for backspace.

Answer:
# include
using namespace std;
int main()

Question 16.
Write a program to read time in seconds and convert it into hours, minutes and seconds.
Answer:
# include
using namespace std;
int main()

Question 17.
Two pairs C++ expressions are given below.

1. a=10, a==10
2. b=a++, b=++a
   • How do they differ?
   • What will be the effect of the expression

Answer:
1. = is an assignment operator that assigns a value 10 to the LHS (Left Hand Side)variable a But == is equality operator that checks whether the LHS and RHS are equal or not. If it is equal it returns a true value otherwise false

2. In a++,++is a post(means after the operand) increment operator and in ++a, ++ is a pre(means before the operand) increment operator. They are entirely different.

Post increment:
Here first use the value of ‘a’ and then change the value of ‘a’.
Eg: if a= 10 then b=a++. After this statement b= 10 and a=11

Pre increment:
Here first change the value of a and then use the value of a.
Eg: if a=10 then b=++a. Afterthis statement b=11 and a=11.

Question 18.
Consider the following
int a=45.65;
cout<<a;
What is the output of the above. Is it possible to convert a data type to another type? Explain.
Answer:
The output of the code is 45, the floating-point number is converted into integer. It is possible to convert a data type into another data type. Type conversions are two types.

1. Implicit type conversion:
This is performed by C++ compiler internally. C++ converts all the lower sized data type to the highest sized operand. It is known as type promotion. Data types are arranged lower size to higher size is as follows, unsigned int(2 bytes), int(4 bytes), long(4 bytes), unsigned long(4 bytes), float(4 bytes), double(8 bytes), long double(10 bytes).

2. Explicit type conversion:
It is known as type casting. This is done by the programmer. The syntax is given below.
(data type to be converted) expression
Eg.int x=10;
(float) x; This expression converts the data type of the variable from integer to float.

Question 19.
Your friend Arun asked you that is there any loop that will do three things, initialization, testing, and updation. What is your answer? Explain?
Answer:
Yes. There is only one loop namely for loop that will do this three things. The other loops will do the checking only, initialisation must be do before the loop and updation must be inside the loop.
The syntax of for loop is given below
For(initialisation; testing; updation)
{
Body of the for loop;
}

Question 20.
Distinguish between exit(0) function and return statement
Answer:
Both are used to terminate the program but both are different. Return is a keyword and exit(O) is a function. The difference is, we can use more than one exit(0) function but we can use only one return statement in a scope. To use exit(0), the header file cstdlib should be used.

Question 21.
Rewrite the program following program using if else
#include
using namespace std;
int main()

Answer:
# include
using namespace std;
int main()

Question 22.
Rewrite the following using nested switch construct.
#include
using namespace std;
int main()


Answer:
#include
using namespace std;
int main()

Question 23.
Consider the following output and write down the code for the same.

Answer:
include
using namespace std;
int main()

Question 24.
Consider the following output and write down the code for the same.

Answer:
# include
using namespace std;
int main()

Question 25.
Consider the following output and write down the code for the same.

Answer:
# include
using namespace std;
int main()

Question 26.
Consider the following output and write down the code for the same.

Answer:
# include
using namespace std;
int main()

Question 27.
Consider the following output and write down the code for the same.

Answer:
#include
using namespace std;
int main()

Question 28.
Consider the following output and write dawn the code for the same.

Answer:
#include
using namespace std;
int main()

Question 29.
Write a program to print the sum of first n natural numbers
Answer:
# include
using namespace std;
int main()
int n,i,sum=0;
cout<<“Entera value torn”; cin>>n;
for(i=1;i<=n;i++)

Question 30.
Write a program to read a number and check whether it is palindrome or not
Answer:
# include
using namespace std;
int main()

Question 31.
Write a program to print the factorial of a number.
Answer:
#include
using namespace std;
int main()

This Fibonacci calculator will generate a list of Fibonacci numbers from start and end values of n.

Question 32.
Write a program to print the Fibonacci series Fibonacci
Answer:
# include
using namespace std;
int main()

Question 33.
Write a program to read a number and check whether the given number is Armstrong or not
Answer:
# include
using namespace std;
int main()

Question 34.
Distinguish between entry controlled loop and exit controlled loop
Answer:
An entry controlled loop first checks the condition and execute(or enters in to) the body of loop only if it is true. But exit control loop first execute the body of the loop once even if the condition is false then check the condition. The for loop and while loop are entry controlled loops but do-while loop is an exit controtted loop.

Question 35.
Write a program to find the largest of 3 numbers
Answer:
#include
using namespace std;
int main()

Question 36.
Check whether a given number is prime or not
Answer:
#include
using namespace std;
int main()

Question 37.
Write a program to read number and display its factors.
Answer:
# include
using namespace std;
int main()

Question 38.
You are given the heights of 3 students. Write the relevant code segment to find the maximum height?
Answer:
# include
using namespace std;
int main()

Question 39.
Write the easiest code snippet for printing your name 1000 times. Explain
Answer:
# include
using namespace std;
int main()

Question 40.
Whenever a string is entered the inverse of that string is displayed( eg: if we enter ‘CAR’ the output is ‘RAC’). Write a suitable programme for the output.
Answer:
#include
#include
using namespace std;
int main()

Question 41.
Write a C++ program to display as follows

Answer:
#include
using namespace std;
int main()

OR

#include
using namespace std;
int main()

Question 42.
Consider the following code The new line.character is \n. The output of the following code does not contain the \n. Why it is happened? Explain.
Answer:
\n is a character constant and it is also known as escape sequence. This is used to represent the non graphic symbols such as carriage return key(enter key), tab key, back space, space bar, etc. It con¬sists of a back slash symbol and one more characters.

Question 43.
The Maths teacher gives the following problem to Riya and Raju.
x= 5 + 3 * 6. Riya got x = 48 and Raju got x = 23. Who is right and why it is happened? Write down the operator precedence in detail?
Answer:
Here the answer is x = 23. It is because of precedence of operators. The order of precedence of operators are given below.

Here multiplication has more priority than addition.

Question 44.
Rewrite the following code using while and do..while loop.
for(i=1;i<5;++i)
{
cout<<“\n”<<i;
}
Answer:
1. using while loop
i=1;
while(i<=5)
{
cout<<“\n”<<i;
i++;
}

2. using do while loop
i=1;
do
cout<<“\n”<<i;
i++;
}while(i<=5);

Question 45.
Rewrite the following C++ code using switch
statement.

Answer:
switch(choice)

Question 46.
Considerthe following code and predict the output
int a=5, b=6, c=7;
if (a<b) || b>c)
cout<<“\nOne”;
if (a<b&&b>c)
cout<<“\nTwo”; if (! *a>b)
cout<<“\nThree”;
Answer:
case 1:
if(ac)
cout<<“\nOne”;
here ac
5<6 || 6>7
True || False = True.
This condition returns True
Hence it prints One.

case 2:
if(ac)
cout<<“\nTwo”;
here ac
5<6 && 6>7
True && False = False
This condition returns False
Hence it prints nothing.

Case 3:
if(! (a>b))
cout<<“\nThree”); here !(a>b)
! (5 >6)
! (False)
This condition returns True
Hence it prints Three.

Question 47.
Match the following

Answer:

Question 48.
Write a C++ program to calculate the simple interest SI, by accepting the value principal amount P, rate of interest R and number of years N using the equation SI = PNR/100.
Answer:
# include
using namespace std;
int main()

Question 49.
Rewrite the following conditional statement with ‘if statement in C++.
min=(a<b) ? (a<c? a:c) : (b<c? b:c);
Answer:
if(a<b && a<c)
min=a;
else if(b<c) min=b; else min=c;

Plus Two Computer Application Review of C++ Programming Five Mark Questions and Answers

Question 1.
Define operator and explain operators in detail. Operators
Answer:
An operator is a symbol that performs an operation. The data on which operations are carried out are called operands. Following are the operators.
1. Input(>>) and output(<<) operators are used to perform input and output operation. Eg. cin>>n; cout<<n;

2. Arithmetic operators:
It is a binary operator. It is used to perform addition(+), subtraction (-), division (/), multiplication (*) and modulus (%-gives the remainder) operations.
Eg. If x=10 and y=3 then

x/y = 3, because both operands are integer. To get the floating point result one of the operand must be float.

3. Relational operator:
It is also a binary operator. It is used to perform comparison or relational operation between two values and it gives either true(1) or false(O). The operators are <,<=,>,>=,== (equality)and !=(not equal to)
Eg. If x=10 and y=3 then

4. Logical operators:
Here AND(&&), OR (||) are binary operators and NOT (!) is a unary operator. It is used to combine relational operations and it gives either true (1) or false (0).
If x=1 and y=0 then

Both operands must be true to get a true value in the case of AND (&&) operation
If x=1 and y=0 then

Either one of the operands must be true to get a true value in the case of OR(||) operation
If x=1 and y=0 then

5. Conditional operator:
It is a ternary operator hence it needs three operands. The operator is?: Syntax: expression? value if true: value if false. First evaluates the expression if it is true the second part will be executed otherwise the third part will be executed.
Eg. If x=10 and y=3 then
x>y? cout<< Here the output is 10.

6. sizeof():
This operator is used to find the size used by each data type.
Eg. sizeof(int) gives 2.

7. Increment and decrement operator:
These are unary operators.

• Increment operator (++): It is used to increment the value of a variable by one i.e., x++ is equivalent to x=x+1;
• Decrement operator (–): It is used to decrement the value of a variable by one i.e., x- is equivalent to x = x-1.

8. Assignment operator (=):
It is used to assign the value of a right side to the left side variable.eg. x=5; Here the value 5 is assigned to the variable x.

Question 2.
A list of data items are given below
45, 8.432, M, 0.124, 8, 0, 8.1X 1031, 1010, a, 0.00025, 9.2 × 10120, 0471, -846, 342.123E03

1. Categorise the given data under proper headings of fundamental data types in C++
2. Explain the specific features of each data type. Also mention any other fundamental data type for which sample data is not given

Answer:
1.

2.
(i) int data type:
It is used to store whole numbers without fractional (decimal point) part. It can be either negative or positive. It consumes 4 bytes (32 bits) of memory. i.e. 232 numbers. That is 231 negative numbers and 231 positive numbers (0 is considered as +ve) So a total of 232 numbers. We can store a number in between -231 to + 231-1.

(ii) char data type:
Any symbol from the key board, eg. ‘A’,’?’, ‘9’,___It consumes one byte( 8 bits) of memory. It is internally treated as integers, i.e. 28 = 256 characters. Each character is having a ASCII code, ‘a’ is having ASCI I code 97 and zero is having ASCII code 48.

(iii) float data type:
It is used to store real numbers i.e. the numbers with decimal point. It uses 4 bytes(32 bits) of memory. Eg. 67.89, 89.9 E-15.

(iv) double data type:
It is used to store very large real numbers. It uses 8 bytes(64 bits) of memory.
void data type:- void means nothing. It is used to represent a function returns nothing.

Question 3.
Write valid reasons after reading the following statements in C++ and comment on their correctness by give reasons.

1. char num = 66;
2. char num – B’;
3. 35 and 35L are different
4. The number 14,016 and OxE are one and the same
5. Char data type is often said to be an integer type
6. To store the value 4.15 float data type is preferred over double

Answer:

1. The ASCII number of B is 66. So it is equivalent.
2. 35 is of integer type but 35L is Long
3. The decimal number 14 is represented in octal is 016 and in hexadecimal is OxE.
4. Internally char data type stores ASCII numbers.
5. To store the value 4.15 float data type is better because float requires only 4 bytes while double needs 8 bytes hence we can save the memory.

Question 4.
Suggest most suitable derived data types in C++ for storing the following data items or statements

1. 0 Age of 50 students in a class
2. Address of a memory variable
3. A set of instructions to find out the factorial of a number
4. An alternate name of a previously defined variable
5. Price of 100 products in a consumer store
6. Name of a student

Answer:

1. Integer array of size 50
2. Pointer variable
3. Function
4. Reference
5. Float array of size 100
6. Character array

Question 5.
Considering the following C++ statements. Fill up the blanks

1. lf p=5 and q=3 then q%p is _____
2. If E1 is true and E2 is False then E1 && E2 will be_____
3. If k=8, ++k <= 8 will be______
4. If x=2 then (10* ++x) % 7 will be_____
5. If t=8 and m=(n=3,t-n), the value of m will be______
6. If i=12 the value i after execution of the expres¬sion i+=i– + –i will be______

Answer:

1. 3
2. False
3. False(++k makes k=9. So 9<=8 is false)
4. 2(++x becomes 3, so 10 * 3 =30%7 =2)
5. 5( here m=(n=3,8-3)=(n=3,5), so m=5, The maximum value will take)
6. Here i=12

i + = i– + –i
here post decrement has more priority than pre decrement. So i — will be evaluated first. Here first uses the value then change so it uses the value 12 and i becomes 11
i + =12 + –i
now i =11.
Here the value of i will be changed and used so i– becomes 10
i + = 12 + 10
= 22
So i = 22 + 10
i = 32
So the result is 32.

Question 6.
Analyses the following statements and write Time or False. Justify

1. There is an Operator in C++ having no special character in it
2. An operator cannot have more than 2 operands
3. Comma operator has the lowest precedence
4. All logical operators are binary in nature
5. It is not possible to assign the constant 5 to 10 different variables using a single C++ expression
6. In type promotion the operands with lower data type will be converted to the highest data type in expression

Answer:

1. True (sizeof operator)
2. False( conditional operator can have 3 operands
3. True
4. False
5. False(Multiple assignment is possible, eg: a=b=c=___=5)
6. True

Question 7.
Match the following numbers and data types in C++ to form the most suitable pairs.

Answer:

Question 8.
#include
using namespace std;
int main()

Rewrite the above code using if else if ladder.
Answer:
#include
using namespace std;
int main()

Question 9.
Consider the following code
# include
using namespace std;
int main()

Is it possible to rewrite the above program using switch statement? Distinguish between switch and if else if ladder. Answer:
No. It is not possible to write the above code using switch statement. Following are the difference between switch and if else if ladder.

1. Switch can test only for equality but if can evaluate a relational or logical expression
2. If else is more versatile
3. If else can handle floating values but switch can not
4. If the test expression contains more variable if else is used
5. Testing a value against a set of constants switch is more efficient than if else

Question 10.
Write down the code for the following output using while loop.

Answer:
# include
using namespace std;
int main()

Question 11.
“We know that the execution of a program is sequential”. Is it possible to change this sequential manner and explain different jump statements in detail.
Answer:
The execution of a program is sequential but we can change this sequential manner by using jump statements. The jump statements are
1. goto statement:
By using goto we can transfer the control anywhere in the program without any condition. The syntax is goto label; Eg. # include
using namespace std;
int main()

2. break statement:
It is used to skip over a part of the code i.e. we can premature exit from a loop such as while, do-while, for or switch. Syntax:
while (expression)

The output is
1
2
3
4
5.

3. continue statement:
It bypasses one iteration of the loop.
Syntax:
while (expression)

The output is
1
2
3
4
5
6
7
8
9
10.

4. exit(O) function:
It is used to terminate the program. For this the header file cstdlib must be included.

Question 12.
Write a program to print the prime numbers less than 100
Answer:
# include
using namespace std;
int main()

Question 13.
Write a program to print the Armstrong numbers less than 1000
Answer:
# include
using namespace std;
int main()

Question 14.
Given the total mark of each student in SSLC examination. Write a C++ code fragment to find the grades.
Answer:
# include
using namespace std;
int main()

Question 15.
You are about to study the fundamentals of C++ programming Language. Do a comparative study of the basics of the new language with that of a formal language like English or Malayalam to familiarize C++?. Provide sufficient explanations for the compared items in C++ Language.
Answer:
Character set:
To study a language first we have to familiarize the character set. For example to study English language first we have to study the alphabets. Similarly here the characterset includes letters(A to Z & a to z), digits(0 to 9), special characters(+,-,?,*,/,___) white spaces(non printable) etc. Token: It is the smallest individual units similar to a word in English or Malayalam language. C++ has 5 tokens
1. Keywords:
These are reserved words for the compiler. We can’t use for any other purposes
Eg: float is used to declare variable to store numbers with decimal point. We can’t use this for any other purpose

2. Identifier:
These are user defined words.
Eg: variable name, function name, class name, object name etc….

3. Literals (Constants):
Its value does not change during execution
Eg: In maths pi = 3.14157 and boiling point of water is 100.

4. Punctuators:
In English or Malayalam language punctuation mark are used to increase the read ability but here it is used to separate the tokens.
Eg:{.}.(.)…..

5. Operators:
These are symbols used to perform an operation(Arithmetic, relational, logical,etc…)code, the middle button displays the object and the right button toggles the folder.

Question 16.

Consider the above data, we know that there are different types of data are used in the computer. Explain different data types used in C++.
Answer:
1. int data type:
It is used to store whole numbers without fractional (decimal point) part. It can be either negative or positive. It consumes 2 bytes(16 bits) of memory.i.e. 216 = 65536 numbers. We can store a number in between -32768 to + 32767.

2. char data type:
Any symbol from the keyboard, eg. ‘A’,’9′,…. It consumes one byte( 8 bits) of memory. It is internally treated as integers, i.e. 28 = 256 characters. Each character is having a ASCII code, ‘a’ is having ASCII code 97 and zero is having ASCII code 48.

3. float data type:
It is used to store real numbers i.e. the numbers with decimal point. It uses 4 bytes(32 bits) of memory. Eg. 67.89, 89.9 E-15.

4. double data type:
It is used to store very large real numbers. It uses 8 bytes(64 bits) of memory.

5. void data type:
void means nothing. It is used to represent a function returns nothing.

Question 17.
Explain conditional statements in detail?
Answer:
1. Simple if:
The syntax is given below
if(expression)
statement;
or
if(expression)
{
Block of statements
}
First expression evaluates if it is true then only statement will be executed.
Eg. if (n>0)
cout<<n<<” is positive”;

2. if else:
The syntax is given below.
if (expression)

First expression evaluates if it is true statement block 1 will be executed otherwise statement block 2 will be executed. Only one block will be executed at a time so it is called branching statement.
Eg.
if (n>0)
cout<<n<<” is positive”;
else
cout<<n<<” is negative”;

3. if else if ladder:
The syntax will be given below
if (expression 1)

Here first expression 1 will be evaluated if it is true only the statement block 1 will be executed otherwise expression 2 will be executed if it is true only the statement block2 will be executed and soon. If all the expression evaluated is false then only statement block n will be evaluated.
Eg.
If(mark>=90)
cout«<<“Your grade is A+”;

4. conditional operator:
It is a ternary operator and it is an alternative for if else construct. The syntax is given below. expression 1? expression 2: expression 3; or expression 1? Value if true: value if false; Here expression 1 will be evaluated if it true ex¬pression 2 will be executed otherwise expression 3 will be executed. Eg. n>0?cout<<n<<” is positive”:cout<<n<<” is negative”;

5. Switch:
It is a multiple branch statement. Its syntax is given below.
switch(expression)

Question 18.
Explain different loops in detail?
Answer:
1. For loop:
The syntax of for loop is
for(initialization; checking ; update loop variable)
{
Body of loop;
}
First part, initialization is executed once, then checking is carried out if it is true the body of the for loop is executed. Then loop variable is updated and again checking is carried out this process continues until the checking becomes false. It is an entry controlled loop.
Eg. for(i=1 ,j=1 ;i<=10;i++,j++)
cout<<i<<” * “<<j<<” = “<<i*j;

2. While loop:
It is also an entry controlled loop
The syntax is given below
Loop variable initialised
while(expression)
{
Body of the loop;
Update loop variable;
}
Here the loop variable must be initialised out side the while loop. Then the expression is evaluated if it is true then only the body of the loop will be executed and the loop variable must be updated inside the body. The body of the loop will be executed until the expression becomes false.
Eg.
i=1;
j=1;
while(i<=10)
{
cout<<i<<” * “<<j<<” = “<<i*j;
i++;
j++;
}

3. do While loop:
It is an exit controlled loop.
The syntax is given below
do
{
Statements
}while(expression);
Here the body executes atleast once even if the condition is false. After executing the body it checks the expression if it false it quits the body otherwise the process will be continue.

Question 19.
Write a program to find simple interest and compound interest.
Answer:
#include<iostream>
#include<cmath>
using namespace std;

Question 20.
Mr. X wants to get an output 9 when inputting 342 and he also wants to get 12 when inputting 651. Write the program and draw a suitable flowchart for X?
Answer:
Flow chart

#include
using namespace std;
int main()

Question 21.
Differentiate break and continue statements with suitable examples.
Answer:
1. break statement:
It is used to skip over a part of the code i.e. we can premature exit from a loop such as while, do-while, for or switch.
Syntax:
while (expression)

The output is
1
2
3
4
5.

2. continue statement:
It bypasses one iteration of the loop.
Syntax :
while (expression)

The output is
1
2
3
4
5
6
7
8
9
10.

Question 22.
Write a C++ program to print to get the following output.

Answer:
#include
using namespace std;
int main()

HSSLive.Guru providing HSE Kerala Board Syllabus HSSLive Higher Secondary SCERT Plus Two Study Material, Question Bank, Quick Revision Notes, Chapter Wise Notes, Chapter Wise Previous Year Important Questions and Answers, Previous Year Sample Question Papers with Answers based on CBSE NCERT syllabus in both English Medium and Malayalam Medium for Class 12. Students can also read NCERT Solutions.

HSSLive Plus Two Study Material / Question Bank Kerala

HSSLive Plus Two Previous Year Question Papers and Answers Kerala

Here HSSLive.Guru have given HSSLive Higher Secondary Kerala Plus Two Previous Year Sample Question Papers with Answers.

• Plus Two Maths Previous Year Question Papers and Answers
• Plus Two Physics Previous Year Question Papers and Answers
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• Plus Two Maths Notes
• Plus Two Physics Notes
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• Plus Two Botany Notes
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• Plus Two Computer Application Notes
• Plus Two English Notes (Chapters Summary)
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HSSLive Plus Two Chapter Wise Questions and Answers Kerala

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• Plus Two Maths Chapter Wise Questions and Answers
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HSSLive Plus Two Chapter Wise Previous Year Questions and Answers Kerala

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• Plus Two Physics Chapter Wise Previous Questions and Answers
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Students can Download Chapter 1 Reproduction in Organisms Questions and Answers, Plus Two Botany Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus Two Botany Chapter Wise Questions and Answers Chapter 1 Reproduction in Organisms

Plus Two Botany Reproduction in Organisms One Mark Questions and Answers

Plus Two Botany Chapter Wise Questions And Answers Pdf  Question 1.
Syngamy means:
(a) Fusion of similar spores
(b) Fusion of dissimilar spores
(c) Fusion of cytoplasm
(d) Fusion of gametes
Answer:
(d) Fusion of gametes

Plus Two Botany Chapter Wise Questions And Answers Question 2.
Fill in the blanks by observing the relationship of the first.

1. Amoeba: Binary fission
   Yeast: …………..
2. Reptiles: Oviparous
   Mammals: ………….

Answer:

1. Yeast: Budding
2. Mammals: Viviparous

Plus Two Botany Questions And Answers Chapter 1 Question 3.
Internal buds of Sponges are:,
(a) Spores
(b) Gemmules
(c) Planula
(d) Blastos
Answer:
(b) Gemmules

12th Botany 1st Lesson Important Questions  Question 4.
In honeybees and lizards, the female gamete undergoes development to form new organism without fertilization. Name this phenomenon.
Answer:
Parthenogenesis

Plus Two Botany Previous Question Papers Chapter Wise Question 5.
The life span of man is_____years.
(a) 60
(b) 70
(c) 85
(d) 100
Answer:
(d) 100

Plus Two Botany Chapter Wise Questions And Answers Hsslive Question 6.
What is meiocyte?
(a) The cell undergoes meiosis
(b) The cell undergoes mitosis
(c) Both a and b
(d) None of the above.
Answer:
(a) The cell undergoes meiosis

Plus Two Botany Chapter Wise Previous Questions And Answers Pdf Question 7
All individuals produced are genetically identical
(a) clone
(b) offspring
(c) fission
(d) monoecious
Answer:
(a) clone

Plus Two Botany Previous Year Questions And Answers Chapter 1 Question 8.
Hydra reproduces asexually by
(a) budding
(b) binary fission
(c) Multiple fission
(d) Vegetative propagation
Answer:
(a) budding

Plus Two Botany Focus Area Questions And Answers Chapter 1 Question 9.
Find the propagules of ginger
(a) Runner
(b) Bulbil
(c) Rhizome
(d) Bulb
Answer:
(c) Rhizome

Hsslive Botany Question Bank Plus Two Chapter 1 Question 10.
Bulb acts as a propagule in
(a) Onion
(b) Garlic
(c) Agave
(d) Both and b
Answer:
(d) Both and b

Plus Two Biology Chapter Wise Questions And Answers Pdf Question 11.
In some algae_____are motile
(a) male gametes
(b) female gametes
(c) both male and female gametes
(d) none of the above.
Answer:
(c) both male and female gametes

Plus Two Botany Chapter Wise Previous Questions And Answers Question 12.
A population of genetically identical plants derived from a single parent is called………..
Answer:
Clone

Plus Two Botany Previous Questions Chapter Wise Chapter 1 Question 13.
Embryo sac is found in:
(a) Endosperm
(b) Embryo
(c) Ovule
(d) Seed
Answer:
(c) Ovule

Plus Two Botany Previous Questions Chapter Wise Pdf Chapter 1 Question 14.
Types of asexual reproduction found in Hydra is………
(a) Gemmule formation
(b) Budding
(c) Sporulation
(d) Multiple fission
Answer:
(b) Budding

Reproduction In Organisms Class 12 Objective Questions Question 15.
Observe the relation and fill in the blanks. Syncarpous: the pistils remain united: the pistils remain free.
Answer:
Apocarpous

Reproduction In Organisms Class 12 Questions And Answers Pdf Question 16.
In honeybees and turkey new organisms are formed through a peculiar phenomenon. Name that phenomenon.
Answer:
Parthenogenesis

Botany Chapter Wise Questions And Answers Chapter 1 Question 17.
Choose the correct answer: Chlamydomonas reproduces asexually through
(a) Gemmules
(b) Conidia
(c) Bud
(d) Zoospores
Answer:
(d) Zoospores

Question 18.
In Marchantia male and female thallus are separate. This condition is called
(a) Dioecious
(b) Hermaphrodite
(c) Monoecious
(d) Bisexual
Answer:
(a) Dioecious

Question 19.
Find the odd one. Bulbil, Bulb, Rhizome, Stem tuber.
Answer:
Bulbil

Question 20.
Identify the correctly matched pair.
(a) Chlamydomonas – conidia
(b) Sponge – Zoospore
(c) Hydra – bud
Answer:
(c) Hydra – bud

Plus Two Botany Reproduction in Organisms Two Mark Questions and Answers

Question 1.
Sugarcane, Banana, Ginger, and Onion are flowering plants. But these are mostly cultivated by vegetative propagation.

1. What is meant by vegetative propagation.
2. Can you identify which part of the above plants are used for vegetative propagation.

Answer:

1. The regeneration of new plants from the portions of vegetative organs like stem, root, and leaves.
2. plants are used for vegetative propagation.

• Sugar cane – stem
• Banana – Rhizome
• Ginger – Rhizome
• Onion – Bulb

Question 2.
Leaves not only produce foods, but also produce young ones. Comment on this statement.
Answer:
In some plants, leaves are organ of vegetative propagation i.e new plants are formed from leaf margins eg-Bryophyllum.

Question 3.
How is pistia and zingiber officinale different in their mode of Asexual reproduction?
Answer:
The above two plants shows vegetative propagation. The vegetative propagation is a form of asexual reproduction The vegetative propagule of pistia is offset (short and thick internode) and zingiber is rhizome (underground stem).

Question 4.
Fill in the blanks by observing the relationship of the first.

1. Male and female flowers on the same plant: monoecious
   Male and female flowers on different plants: ………….
2. Fusion of gametes: Syngamy
   Offspring from unfertilized female gamete: ……………

Answer:

1. Dioecious
2. Parthenogenesis

Question 5.
Plant can reproduce both vegetatively and sexually. Name any 4 vegetative propagule.
Answer:

1. Eye of potato,
2. rhizome of ginger,
3. bulbil of agave,
4. offset of water hyacinth.

Question 6.
Given below is a diagram showing particular types of reproduction.

1. Name the process of reproduction.
2. Briefly explain the process

Answer:

1. Budding
2. It is the mode of asexual reproduction in which the unicellular organism divides unequally and the buds remain attached to the parent cell. Eg. yeast.

Question 7.
Given below the figures of different types of reproduction present in organisms. Identify and name the type of reproduction.

Answer:

1. Zoospores in chlamydomanas
2. Conidia of penicillium
3. Eyes of potato
4. Leaf buds of bryophyllum.

Question 8.
Match the following: (Hint: Name of organisms in column A and asexual reproductive structure in Column B)

Answer:

Question 9.
In diploid organisms, meiosis and gametogenesis are always interlinked. Justify.
Answer:
In diploid organism, reproductive cells undergoes reduction division – meiosis and produces haploid gametes. Gametogenesis means the process of gamete formation. So meiosis and gametogenesis are always interlinked.

Question 10.
Categorize the following into pre and post-fertilization changes in plants. Gamete transfer, pericarp formation, ovule development, embryogenesis.
Answer:
Pre fertilization-ovule development and gamete transfer. Post fertilization -embryogenesis and pericarp formation.

Question 11.
Events of sexual reproduction is given below.

1. Write the events in a sequential order. Fertilization, gamete transfer, zygote, gameto – genesis, embryogenesis.
2. Point out the differences between gametogenesis and embryogenesis

Answer:

1. Gametogenesis, gamete transfer, fertilization, zygote, embryogenesis.

Question 12.
‘Water-hyacinth’ is commonly called ‘Terror of Bengal’. Give reason.
Answer:
‘Water-hyacinth’ is a highly spreading aquatic weeds, which drains oxygen from the water and leads to the death of fishes.

Question 13.
Bamboo plant and strobilanthus kunthianus (Neela Kurunji) have similarity and dissimilarity in their reproductive and vegetative character. Justify.
Answer:

1. Similarity – Both Bamboo and neela kurinji are perennial plants.
2. Dissimilarity – Bamboo flowers only once in their life time (in the period of 50-100 years) and die whereas neelakurinji flowers once in 12 years.

Question 14.
Zygote is called as the vital link. Why?
Answer:
Zygote is the product of fertilization, that maintains the continuity of species between organisms of one generation and the next.

Question 15.
Post fertilization changes in flowering plants are given, by observing the given pair complete the others.
(a) Zygote: Embryo
(b) Ovule: ……….
(c) Ovary: ………
(d) Nucellus: Perlsperm
(e) Integument: ……….
(f) PEN: ………..
Answer:
(b) Ovule: Seed
(c) Ovary: Fruit
(e) Integument: seed coat
(d) PEN: Endosperm

Question 16.
Leaves are used not only for photosynthesis but also for reproduction.

1. Name the type of reproduction
2. Give an example.

Answer:

1. Vegetative propagation
2. Eg-Broyophyllum

Question 17.
Observe the relationship between first two terms and fill up the blanks.
1. Asexual reproduction – Unparental
Sexual reproduction……………….

2. Zygote: Diploid nucleus: Endosperm: ………….

3. Pea: non albuminous: wheat ………….
Answer:

1. biparental
2. Triploid nucleus
3. albuminous

Question 18.
In yeast and Amoeba the parent cell divides to give rise to two new individual cells. How does the cell division differ in these two organisms?
Answer:

• In yeast, the cell division is unequal and small buds are produced.
• In Amoeba, the cell division is equal and identical daughter cells are produced.

Question 19.
Offsprings formed due to sexual reproduction have better chances of survival. Why?
Answer:
Sexual reproduction combines the characters of two parents and introduces variations which make the offsprings better in environmental adaptation.

Question 20.
Some organism are capable of producing fertilized egg but others are not possible.

1. Name the organism producing fertilized egg.
2. Why are offspring of oviparous-animals subjected to greater risk as compared to offsprings of viviparous animals.

Answer:

1. oviparous animals
2. In oviparous orgaisms development of zygote take place outside the body of the female parent while in viviparous organisms development of zygote take place inside the body of female organisms. Hence viviparous type get proper embryonic care and protection.

Question 21.
In one type plant Adventitious buds develops into new leafy shoot by leaf as means of vegetative propagation but in others by rhizome. Give examples for leaf and rhizome used as unit of vegetative propagation.
Answer:

• Leave – bryophyllum
• Rhizome – banana, and Ginger

Question 22.
In certain lower plants, equal and un equal daughter cells are produced by asexual reproduction. Name these Asexual Reproduction with examples
Answer:
In binary fission equal daughter cells are produced. Example bacteria and Paramecium. In budding two unequal daughter cells are produced. Example Yeast and hydra.

Question 23.
In lower plants movement of gametes takes place by water but in seed plants male gametes are non motile. Which part of plant helps the movement of gametes?
Answer:
Pollen tube

Question 24.
Haploid gametes are produced in bryophytes and angiosperms by two types of cell division. Name it
Answer:

• bryophytes-Mitosis
• angiosperms-meiosis

Question 25.
Sexual reproduction is very common in higher plants to produce young ones that shows variation.

1. Name the product formed in sexual reproduction is considered as vital link
2. Give its significance

Answer:

1. product-zygote
2. It maintains continuity of species for many generation.

Question 26.
Nature prefer internal fertilization than external fertilisaiton. Do you agree with this statement.
Answer:
Yes, In nature the advanced plants and animals show internal fertilisation.

Question 27.
In fishes gamete fusion takes place in external medium. Give the disadvantage of this method.
Answer:
The offsprings formed through external fertilisation are subjected to the attack of predators.

Question 28.
Animals are categorized into viviparous and oviparous based on the development of the Zygote takes place outside the body or inside. In which of these two types the chances of survival is greater. Why?
Answer:
In oviparous animals like reptiles and birds, the fertilised eggs after the period of incubation young ones hatch out. In viviparous animals, the zygote develops into a young one inside the body of the female organism. After the period of growth, they are delivered out. The chances of survival is greater in viviparous animals.

Question 29.
Mention the characteristic feature and a function of zoospore in some algae.
Answer:

• Zoospores are flagellated, motile aquatic bodies
• On germination give rise to new plants

Question 30.
Name the site of occurrence of syngamy in amphibians and reptiles.
Answer:

• In amphibians syngamy occurs outside the body of organism i.e external.
• In reptile syngamy occur inside the body of the organism i.e internal

Question 31.
What are the three major phases in the life cycle of an organism? Define each phase.
Answer:
Juvenile phase, Reproductive phase, senescent phase

• Juvenile phase-The phase of growth in the organisms before reproductive maturity
• Reproductive phase- In this phase organism attains reproductive maturity
• Senescent phase- The phase between reproductive maturity and death

Question 32.
How does the progeny formed from asexual reproduction differ from those formed by sexual reproduction?
Answer:
The progeny formed from asexual reproduction is the product of single parent and does not have genetic variations.

Question 33.
In yeast and amoeba the parent cell divides and give rise to two new individual cells. How does the cell division differ in these two organisms?
Answer:
In yeast, cell division is unequal and small buds are produced that remain attached to parent cell. In amoeba the cell division is equal and produces identical daughter cells.

Question 34.
Mention the site where syngamy occurs in amphibians and reptiles respectively.
Answer:
In amphibians syngamy occurs outside the body of organisms in the external medium (water). In reptiles syngamy occurs inside the body of an organism.

Question 35.
The turkey usually produces females for several. generations. How is this possible?
Answer:
In a turkey, female gametes undergo development without fertilization. This phenomenon is called parthenogenesis.

Question 36.
Leaves not only produce food but also produce young ones. Substantiate.
Answer:
In few plants the leaves are the means of vegetative propagation in addition to photosynthesis. In such plants, plantlets are formed on the leaves eg- Bryophyllum.

Question 37.
Observe the figures given below, identify and name the organisms and their asexual reproductive structures.

Answer:
Organisms – Asexual reproductive Structures

1. Chlamydomonas – Zoospore
2. Penicilium – Conidia

Question 38.
The chromosome number in the meiocyte of housefly is 12 and that of its gamete is 6. Write the reason for the change in chromosome number of meiocyte and gamete.
Answer:
Meiocyte is a diploid cell undergo reduction division to form haploid gametes.

Question 39.
In coconut, male and female flowers are separate. Write the technical term for the male and female flowers. Write the condition of the flower.
Answer:

1. Female flower – pistillate
2. Male flower – staminate
3. Condition of the flower – unisexual

Question 40.
Observe the figures given below. Identify the gametes in A and B. Justify your answer.

Answer:

1. Homogametes
2. Heterogametes

In first figure gamates come to fusion have similar structure but in second figure gametes have dissimilar structure.

Question 41.
Match the items of column A with B

Answer:

Question 42.
Analyse the table given below and fill in the blanks.

Answer:

1. Hermaphrodite or bisexual
2. Female gamete develops into new organism without fertilisation
3. majority of algae or fishes or amphibians
4. Fertilisation occurs inside the body

Question 43.
The chances of survival of young ones is greater in viviparous organisms than oviparous organisms. Justify this statement.
Answer:
In viviparous organisms the zygote develops into young one inside the body of the female organism. So during the course of development proper embryonic care and protection is provided inside the female organism.

Question 44.
In some organisms male and female reproductive organs are seen in the same individual. Name that condition. Give two examples of such organisms.
Answer:
Hermaphrodite Eg.Earthworm, Leech.

Question 45.
Name of certain plants and their vegetative propagules are given below. Make correct pairs using them. Agave, Offset, Ginger, Bulb, Bulbil, Water hyacinth, Potato, Bryophyllum, Rhizome
Answer:

1. Agave – Bulbil
2. Ginger-Rhizome
3. Water hyacinth – offset
4. Onion-Bulb

Question 46.
Gametogenesis and gamete transfer are the two prefertilisation events. Write the differences between the two.
Answer:
Gametogenesis – It is the formation of gametes.
Gamete transfer – It is the transfer of male gamete to the female gamete.

Question 47.
Based on the nature of reproduction, organisms are classified as continuous breeders and seasonal breeders. Write the difference between the two.
Answer:

1. Continuous breeders – They are reproductively active throughout their reproductive phase.
2. Seasonal breeders – They reproduce only during favourable seasons in their reproductive phase.

Question 48.
Observe the relationship between the first two terms and fill in the blanks.

1. Hydra: Bud; …….: Gemmule
2. Birds: Internal fertilization; …….External fertilization.

Answer:

1. Sponge: gemmule
2. Algae or fishes or amphibian

Question 49.
Fertilisation in some organisms occur outside the body. Name that kind of fertilization. Write its disadvantage.
Answer:
External fertilization
In this type young ones are subjected to threat of predators. So, it is the disadvantage of external fertilisation.

Question 50.
The offspring formed by asexual reproduction is referred to as clone. Justify this statement.
Answer:
Offsprings formed are morphologically and genetically similar among themselves and to their parents. So such individuals are called clone.

Plus Two Botany Reproduction in Organisms Three Mark Questions and Answers

Question 1.
During sexual reproduction-fertilization is an important process. But in most aquatic organisms like fishes, amphibians, etc. external fertilization occur. In most terrestrial organisms internal fertilization is common.

1. Point out the differences between external and internal fertilization.
2. Write the disadvantages of external fertilization.

Answer:
(a) 1. External Fertilization:
Syngamy occurs in the external medium – water i.e. outside the body of organisms. Eggs and sperms are released outside the female and male parents respectively and move through water before fusion of gametes.

2. Internal Fertilization:
Syngamy occurs inside the body of organisms. Egg is formed inside the female body where they fuse with male gamete that is released by the male parent.

(b) Offsprings formed by external fertilization, are extremely vulnerable to predators threatening their survival up to adulthood.

Question 2.
Write technical terms for the following.

1. Morphologically different types of gametes.
2. Process of formation of male and female gametes.
3. Formation of new organisms without fertilization.

Answer:

1. Heterogametes
2. Gametogenesis
3. Parthenogenesis

Plus Two Botany Reproduction in Organisms NCERT Questions and Answers

Question 1.
In bacteria and lower organisms offspring formed are close similar among themselves and to their parents.

1. Name offsprings derived through such process
2. Write down the 2 characterstics of such offsprings

Answer:

1. Clone
2. Morphologically and genetically similar

Question 2.
The offsprings formed by a sexual reproduction have better chances of survival. Why?
Answer:
Sexual reproduction combines the characters of two parents and introduces variations which make the offsprings better in environmental adaption.

Question 3.
How does the progeny formed from asexual reproduction differ from those formed by sexual reproduction?
Answer:
The progeny formed from asexual reproduction is the product of single parent and does not have genetic variations.

Question 4.
In some lower and higher plants offsprings are produced shows greater similarity and it occurs mainly through asexual reproduction, in higher plants the process occurs through vegetative propagation.

1. What is vegetative propagation?
2. Give two suitable examples.

Answer:
1. The process of multiplication, in which parts or fragments of the plant act as reproductive unit or propagule to form new individuals is called vegetative propagation.

2. Examples,

• Buds (eyes) of Potato.
• Rhizome of Ginger.

Question 5.
Distinguish between asexual and sexual reproduction. Why is vegetative reproduction also considered as a type of asexual reproduction?
Answer:

Vegetative reproduction involves single parent and its offsprings are genetically identical hence it is considered as a type of asexual reproduction.

Question 6.
Higher organisms have resorted to sexual reproduction in spite of its complexity. Why?
Answer:
Because sexual reproduction induces genetic variability(adaptations) which make the offsprings better equipped for the struggle of existence.

Question 7.
Some organism are capable of producing fertilized egg but others are not possible.

1. Name the organism producing fertilized egg.
2. Why are offspring of oviparous animals at a greater risk as compared to offsprings of viviparous animals.

Answer:

1. oviparous animals
2. In oviparous orgaisms development of zygote take place outside the body of the female parent, (they lay fertilized /unfertilized egg). In viviparous organisms development of zygote develops into a young one inside the body of the female organism.

This offers proper embryonic care and protection and have better chances of survival than young ones of viviparous organisms.

Question 8.
Prefertilisation events events of sexual reproduction in all organisms are gametogenesis and gamete transfer.

1. What are the post fertilization events?
2. Name the parts of plants such as ovary, ovule and ovary wall develop in post fertilization process.

Answer:

1. Zygote formation Embrogenesis
2. Ovary-fruit, ovule-seed, ovary wall -pericarp

Plus Two Botany Reproduction in Organisms Multiple Choice Questions and Answers

Question 1.
In papaya, the flowers are:
(a) Unisexual
(b) Bisexual
(c) neuter
(d) Flowers are not formed
Answer:
(a) Unisexual

Question 2.
In vegetative propagation, characters of parent plants are:
(a) Changed
(b) Not preserved
(c) preserved
(d) Exchanged
Answer:
(c) preserved

Question 3.
Rhizopus reproduces asexually by:
(a) Conidia
(b) Spores
(c) Gemma
(d) Bulbil
Answer:
(b) Spores

Question 4.
In potato, vegetative propagation takes place by:
(a) Root
(b) Leaf
(c) Grafting
(d) Stem tuber
Answer:
(d) Stem tuber

Question 5.
Vegetatively propagated plants are:
(a) Genetically similar
(b) Genetically dissimilar
(c) Do not bear roots
(d) Do not form buds
Answer:
(a) Genetically similar

Question 6.
Syngamy means:
(a) Fusion of similar spores
(b) Fusion of dissimilar spores
(c) Fusion of cytoplasm
(d) Fusion of gametes
Answer:
(d) Fusion of gametes

Question 7.
In which pair both the plants can be vegetatively propagated by leaf pieces?
(a) Bryophyllum and Kalanchoe
(b) Chrysanthemum and Agave
(c) Agave and Kalanchoe
(d) Asparagus and Bryophyllum
Answer:
(a) Bryophyllum and Kalanchoe

Question 8.
Regeneration of a plant, cell to give rise to new plant is called :
(a) Reproduction
(b) Budding,
(c) Totipotency
(d) Pleuripotency
Answer:
(c) Totipotency

Question 9.
Hydra reproduces asexually through:
(a) iragmettatwn
(b) Budding
(c) binary fission
(d) Sporulation
Answer:
(d) Sporulation

Question 10.
Animals giving birth to young ones are
(a) Oviparous
(b) Ovoviviparous
(c) viviparous
(d) both b and c
Answer:
(c) viviparous

Question 11.
The offspring that are exactly identical to one another as well as identical to their parents are called as
(a) clone
(b) twins
(c) replicates
(d) drones
Answer:
(a) clone

Question 12.
Buds and conidia are asexual reproductive structures of
(a) hydra&rhizopus
(b) rhizopus & penciriium
(c) hydra & pencillium
(d) both a&b
Answer:
(c) hydra & pencillium

Question 13.
Banana is multiplied through
(a) suckers
(b) seeds
(c) rhizome
(d) stolen
Answer:
(c) rhizome

Question 14.
In rotifers, the type of reproduction responsible for the organisms to multiply is
(a) apomixis
(b) parthenogenesis
(c) asexual reproduction
(d) sexual reproduction
Answer:
(b) parthenogenesis

Question 15.
Bulbils are employed for multiplication of
(a) bryophyllum
(b) crocus
(c) Agave
(d) strawberry
Answer:
(c) Agave

Question 16.
During favourable condition Amoeba reproduces by
(a) binary fission
(b) buds
(c) multiple fission
(d) both a and c
Answer:
(a) binary fission

Question 17.
After post-fertilization, the ovary and ovule develops into
(a) pericarp and fruit
(b) fruit and seed
(c) fruit and seed coat
(d) none of the above
Answer:
(b) fruit and seed

Question 18.
The plants which flower every year after attaining certain maturity are called
(a) monocarpic
(b) polycarpic
(c) perennials
(d) annuals
Answer:
(b) polycarpic

Question 19.
The type of reproduction occurs in ciliated protozoans is
(a) syngamy
(b) conjugation
(c) budding
(d) cross fertilization
Answer:
(b) conjugation

You can Download Social Institutions: Continuity and Change Questions and Answers, Notes, Plus Two Sociology Chapter Wise Questions and Answers Kerala Chapter 3 help you to revise complete Syllabus and score more marks in your examinations.

Kerala Plus Two Sociology Chapter Wise Questions and Answers Chapter 3 Social Institutions: Continuity and Change

Social Institutions: Continuity and Change Questions and Answers

Social Institutions Continuity And Change Important Questions Chapter 3  Question 1.
In the Census taken by the British Government in the year ………… information about the caste was included.
Answer:
1860

Social Institutions Continuity And Change Questions And Answers Chapter 3 Question 2.
From the names given below, who is not considered to be a leader of the lower castes of South India?
a) Sri Narayana Guru
b) Ayyankali
c) Chattambi Swamikal
d) Gandhiji
Answer:
Gandhiji

Social Institutions: Continuity And Change Questions And Answers Chapter 3 Question 3.
From… the British Government began to take regular census every 10 years.
a) 1781
b) 1881
c) 1891
d) 2001
Answer:
1881

Social Institutions Questions And Answers Chapter 3 Question 4.
From among the given things what is not an important feature of the Upper Classes?
a) right to education
b) right to enter temples
c) Not drinking alcohol
d) political power
Answer:
Not drinking alcohol

Sociology Class 12 Chapter 3 Questions And Answers Chapter 3 Question 5.
From the following chose the family in which members of only two generations live: Joint family, Nuclear family, Extended Family.
Answer:
Nuclear family

In India The Institution Of Family Has A Trend Towards Chapter 3 Question 6.
The family in which newly married couples stay with the family of the father of the groom is called …….
Answer:
Patriarchal family

Social Institutions Continuity And Change Notes Chapter 3 Question 7.
A family of a mother with her children and their children is called ………
Answer:
Matriarchal family

Social Institutions Continuity And Change Chapter 3 Question 8.
What are the 3 most important social institutions of a society?
Answer:
Jati, Tribe (Gotram), Family

Caste System Multiple Choice Questions Chapter 3 Question 9.
The 4-phase division of the society is called ……….
Answer:
Caste System

Social Institutions Continuity And Change Pdf Chapter 3 Question 10.
Who is the father of Indian Sociology?
a) VenierElvin
b) G. S. Ghurye
c) M.N. Srinivas
d) Periyar
Answer:
G.S. Ghurye

Sociology Class 12 Important Questions Chapter 3 Question 11.
Match the following

Answer:

Multiple Choice Questions On Social Institutions Chapter 3 Question 12.
Explain the different levels of the meaning of ‘Jati’.
Answer:
Jati is translated as ‘caste’ in English. Caste actually comes from Portuguese. It means ‘pure breed’. Jati shows a social arrangement of people based on birth. Varna is another word that means Jati. Both these words ‘Jati’ and ‘Varna’ are often used as synonyms. But actually there are some differences between them. Varna is a Sanskrit word. It means color. The ‘Varna’ system originated during the Veda period. At that time the people were divided into four groups – Brahmin, Kshatriya, Vaisya, and Sudra. This 4-class division is called Varna, in these 4 groups, a good number of people were not included.

They were excluded from the 4-Varna system. They included those ostracised from the Jati, foreigners, slaves and the people of the defeated nations. These people who were excluded from the 4-Varna system were called ‘Panchamar’ or ‘the fifth group’. Jati is a common name to indicate a group. In this, even inanimate things, plants, animals and persons were included. Thus Jati is simply an institution and S does not mean Varna.

Question 13.
Explain the relation between Jati and Varna.
Answer:
In fact, the actual relation between Jati and Varna is often debated by scholars. There are many imaginary concepts about this. Varna system is an all-India system. The 4-Varna system can be seen everywhere in India. But Jati is a regional or local institution. A Jati found in one area of India may not be found in another area. The Jati chain is different in each area. The main difference between Jati and Varna is in the number. Vamas are 4. But there are hundreds of Jatis and Updates. The Jati system is highly complicated.

Question 14.
What are the main features of Jati?
Answer:

• Jati is decided by birth.
• Marriage in the same group (Swagana Vivaham).
• Restrictions in food items and sharing of food.
• Hierarchical system by giving people high, low and middle status.
• Upajatis and upa-upajatis
• Kulathozhil (specified family jobs)

Question 15.
What re the contributions of Jyoti Rao Phule?
Answer:
Jyoti Rao Phule was later known as Mahatma Phule. He started a Social Reformation Movement in Maharashtra.

• He gave leadership to a fight against Brahmin domination and Jati system.
• He worked for the education of the lower castes and women.
• He rejected the idea of ‘purity-pollution’ (suddha- asuddha) concepts.
• He worked for righteousness and human rights of the lower castes.
• • He found the Satyajodhak Samaj.

Question 16.
Jati system is a combination of two kinds of principles. Explain.
Answer:
Theoretically, Jati system is a combination of two kinds of principles. One kind is based on differences and distance. The other kind is based on universality and power hierarchy (chain).
Each Jati is supposed to be different from others. Therefore each Jati was expected to keep away from other Jatis. Most of the rules and regulations of Jati are formulated on the principle of preventing the mingling of Jatis. Thus there were restrictions regarding marriage and ‘panthibhojanam’ (eating together).

At the same time a Jati can’t survive by itself. It can survive only as part of larger community. And this is its universality. The community (society) as a whole is not based on any principle of equality. There is a hierarchical order there. It is like a ladder. In this ladder each Jati is given its place.
Jati is a combination of two kinds of concepts:
a) Differences and distance from other Jatis.
b) Part of a larger community and part of a power hierarchy.

Question 17.
Explain the purity-pollution (Suddha-Asuddha) concept of Jati system.
Answer:
Purity and Pollution are like antonyms, opposite to each other. Purity is associated with the higher classes whereas impurity or pollution is associated with the lower classes. Purity is related to those things which are considered sacred. Thus some rituals in temples can be performed by only the Upper Castes like Brahmins. But those who do lowertypes of jobs, like cleaning, sweeping, etc. are considered impure and even their touch was avoided polluting (untouchability) by the Upper Classes.

Question 18.
What changes did Colonialism bring in the Jati system?
Answer:
Scholars say1 that colonialism brought drastic changes in the Jati system. There are some scholars who even argue the Jati-system as we see it today is not part of the Indian system, but is a creation of colonialism. However, these systems were not deliberately introduced but happened over centuries, it is true that the colonialists did make some changes in the existing system.

Question 19.
Who is Periyar? What were his contributions?
Answer:
E . V. Ramaswami Naicker is called Periyar. He was a rationalist and a leader of the lower caste people of South India. He taught that all people are equal and freedom and equality were the birthrights of everyone. He formed the ‘Swabhiman Movement.’ He took part in the Vaikom Satyagraha, in Kerala.

Question 20.
What were the reforms made for the prosperity of the lower castes by the Colonial rulers?
Answer:
Towards the end of their rule, the Colonial Masters took some interest in bringing prosperity to the so called lower classes of people. As part of the reform activities, in 1935, the Government prepared a schedule of the lower classes. This schedule was officially approved by a law. Those that were approved in the schedule were known as Scheduled Castes and Scheduled Tribes and they got special considerations from the Government.

All the lower class people who even suffered from the inhuman, horrible ‘untouchability’ were in the schedule. This way the Colonial rulers brought some good changes in the rigid caste system in India.

Question 21.
What were the factors that brought changes in the Indian Jati System after independence?
Answer:
Changes in the Jati System were brought by different factors working together. They included industrialization, urbanization and spread of modem education.
Developmental activities by the nation and the growth of private industries brought economic changes. This indirectly affected Jati system. Modern industries created a lot of new employment opportunities. The Jati laws did not apply to those jobs. When people of different castes began go work together in factories and business enterprises, many of Jati restrictions became impractical and irrelevant.

Urbanization made life according to Jati laws impossible. People of different Jatis had to live together in cities. It was not practical to live in the city following Jati system. There people had to live together.

Question 22.
Codify the ideas of Sree Narayana Guru.
Answer:

• He propagated the principle of universal brotherhood.
• He fought against the Varna system and dominance by the Upper Class.
• He tried to wipe away the evil practices among the Ezhavas.
• He formed the SNDPYogam.
• He brought a silent revolution in the Kerala Society. He spread the message of One Jati, One Religion and One God for Man.

Question 23.
What is Sanskritization?
Answer:
Sanskritization is a process by which members of the lower classes adapt the lifestyles and social conventions of the Higher classes with the intention of raising their own status in society. It is a way through which the lower class people try to enter the higher classes. They do it through imitation.

Question 24.
What is meant by dominant Caste (Prabala Jati)? What are they?
Answer:
Through the land reform measures after independence, many people got ownership of their lands. Among these new owners of land, the castes that had big numbers were called dominant castes by M.N. Srinivas. The land reforms took away the rights of many high caste estate owners to their estates. They were not making any contributions to the economic system except that they collected axes from the farmers. The lands that were confiscated from these landlords were given to people at the next lower level. The people who newly got the land rights were not farmers. They were simply managers of agriculture. They were middle-class Dalits who had a lot of members. Here are some dominant castes:
a) Yadavs of Bihar and Uttar Pradesh.
b) Vokkaligas of Karnataka.
c) Reddys and Khammans in Andhra Pradesh.
d) Marathis of Maharashtra
e) Jats of Punjab, Haryana and Western UP.
f) Patidars of Gujarat

Question 25.
What were the special features of the dominant castes?
Answer:
The special features are:

• Large number
• Land and economic power
• Political power

Question 26.
What are the permanent features of ‘Gotras’ (Tribes)?
Answer:
The permanent features of Gotras include their region, language, special physical features, and environmental habitat. The Tribals in India are scattered in many regions of the country. But in some places, there are some concentrations. Among the Tribals, some 85% live in Central India. Central India is a wide area extending to Western Gujarat and Rajasthan, Eastern West Bengal and Orissa. Madhya Pradesh, Jharkhand, Chhatisgarh, Parts of Maharashtra and Andhra Pradesh come in this vast area. Of the remaining 15%, more than 11% live in North-East States, and the remaining in different other States of India.

If we look State-wise, most of them are found in the North-East States. Except in Assam, all the North East States have Tribals which come to more than 30% of the total population. In Arunachal Pradesh, Mizoram and Nagaland 60 to 95% of the people belong to Tribal groups. IntherestoflndiatheTribalpopulation is negligible. Except in Orissa and Madhya Pradesh, the Tribals are less than 12% of the population. Hills, forests, village plains and even some industrial ‘ belts of cities are the habitats of these Tribals.

Question 27.
Based on language, how are the Tribal groups categorized?
Answer:
Based on language, Tribal groups are categorized into 4:
a) Indo-Aryan
b) Dravidian
c) Austric
d) Tibeto-Burman
The first two, Indo-Aryan and Dravidian, are also spoken by other people of India. Among the Tribals, 1% speak Indo-Aryan and 3% speak Dravidian languages. Austric and Tibeto-Burman are the most popular languages of the Tribals.
Based on physical and racial features, the Tribals of India are divided into 5:
a) Negrito
b) Australoid
c) Mongoloid
d) Dravidian
e) Aryan.
Of these the last two – Dravidian and Aryan, are shared by other Indians also.

Question 28.
Tribal Groups are categorized based on their acquired features. Explain.
Answer:
Acquired features include the ways they earn their livelihood and their mixing with Hindu communities. Sometimes both these happen simultaneously. Based on the means of their livelihood, Tribais are grouped as fishermen, collectors of food, hunters, shifting cultivators, peasants, estate workers, and industrial workers.
Adapting Hindu ways of life is another criterion for the categorization of Tribal Groups. In Sociology, political science and public matters this criterion is more widely used.

Question 29.
Write about the mainstream views about the Tribal Groups of India.
Answer:
In 1940 there was a controversy regarding separation/ integration of the Tribal groups in India. This was the result of a feeling that Tribal Groups should themselves separately from the mainstream society. The spokesman for the Separation theory was Verrier Elwin and the spokesman for Integration was G.S. Ghurye.

The proponents of the Separation theory argued that the Tribals should be kept separate from the mainstream society. They said that these Tribals should be protected from traders, financiers, Hindu and Christian missionaries. All these people are trying to make the Tribals laborers without land and thus make them non- Tribals. The Separation Theory supporters argued that the close relation between Tribals and mainstream society would result in their ruin.

On the other hand, the Integration theory supporters argued that Tribals are part of the Hindu community. GS. Ghurye called them backward Hindus. He argued that the Tribals should be integrated into the mainstream Hindu community. They also said that since the Tribals are backward Hindus, they also should be treated like the other Scheduled Castes and given all considerations.

This argument created a lot of noise in the Indian Constitutional Assembly. People supported both sides. Finally, it was agreed that the Tribals should be integrated into the mainstream gradually. It was this approach -gradual or controlled integration – that resulted in many welfare schemes for the Tribals. There were many welfare schemes for them, provisions for them in the Five Year Plans, specific Tribal schemes, Tribal welfare blocks, multiple-aim schemes and so on. But the integration of the Tribals created a basic problem. The Five Year Plans during the Nehru Era gave prominence to Industrial and agricultural development. Later government followed the same policy The stress was given to the construction of huge dams and factories and exploiting mineral wealth for the development of country.

Question 30.
What are the problems faced by the Tribals?
Answer:
Tribals depended on the forest for their livelihood. The loss of forests was a big blow to them. During the British rule forests were exploited. This tendency continued even after independence. The coming of the land under private ownership also adversely affected the Tribals. When private landowners had their own private lands, the Tribals held their land collectively. This collective ownership proved harmful to them. For example, when a series of dams were constructed on Narmada River, ail the communities did not equally share their advantages and disadvantages. It helped the private landowners but it was harmful to the Tribals, who owned the land collectively.

Many of the regions where* Tribals are concentrated are becoming the targets, and thus victims, of national development schemes. Non-Tribals migrate into their areas in large numbers. It proves a great threat to ihe Tribals and their ways of life. It also reduces their population. For example, in Jharkhand, because of the migration by non-tribals into the new industrial areas, the number of Tribals has been reduced drastically there. But the most dramatic development was in North-Easter States. In States like Tripura, the Tribal population has come down to half in just one decade. The same thing was seen in Arunachal Pradesh. ,

Question 31.
What are the reasons for the rise of Tribal Movements?
Answer:
There are mainly two reasons. One of them is the problem related to the control of land, forests and such other important economic resources. The second problem in connected with the racial-cultural being of the Tribals.

Question 32.
What are the special features of the internal structure of the family?
Answer:
The following are the features:

• A family can be nuclear or joint.
• It can be patriarchal or matriarchal.
• The hereditary rights can be paternal or maternal.

Question 33.
What are the differences between a nuclear family and an extended family?
Answer:
Nuclear family is the smallest. It is also called the primary family. In a nuclear family, there are the parents and their children. It consists of members belonging to two generations.
An Extended family is quite different. It is commonly known as joint family. There are different types of extended families. In an extended family, more than one couple and their children live. This can be a group of brothers and their families. It could be the family of an old couple whose children and grandchildren stay with them. An extended family is often seen as a sign of India. But that was never a strong-knit family. It was limited to some regions and some communities. An extended family is not a strong form even now.

Question 34.
What are the other forms of families?
Answer:
In the different communities of India, different forms of families are found. These differences occur because of the factors like residence, authority, and heredity. Depending on the residence (dwelling), families are of two kinds: paternal and maternal. When the newly married couple stays with the parents of the bride, we call it maternal family. On the other hand, when the newly married couple lives with the parents of the groom, it will be called paternal family.

Depending on hereditary rights there are two kinds of families-matriarchal and patriarchal. In matriarchal families, properties go to the daughters of the mother. In patriarchal families, the property goes to the sons.

Question 35.
How can we divide the family based on authority?
Answer:
Here also we divide the families into patriarchal and matriarchal. In patriarchal families the men wield authority. The father is the leader. In matriarchal families, women wield the authority. The mother is the leader here.

HSE Kerala Board Syllabus HSSLive Plus Two Notes Chapter Wise Pdf Free Download in both English Medium and Malayalam Medium are part of Plus Two Kerala SCERT. Here HSSLive.Guru has given Higher Secondary Kerala Plus Two Chapter Wise Quick Revision Notes based on CBSE NCERT syllabus.

HSSLive Plus Two Notes Chapter Wise Kerala

• Plus Two Maths Notes
• Plus Two Physics Notes
• Plus Two Chemistry Notes
• Plus Two Botany Notes
• Plus Two Zoology Notes
• Plus Two History Notes
• Plus Two Sociology Notes
• Plus Two Economics Notes
• Plus Two Business Studies Notes
• Plus Two Accountancy Notes
• Plus Two Computer Science Notes
• Plus Two Computer Application Notes
• Plus Two English Notes (Chapters Summary)
• Plus Two Hindi Notes (Chapters Summary)

We hope the given HSE Kerala Board Syllabus HSSLive Plus Two Notes Chapter Wise Pdf Free Download in both English Medium and Malayalam Medium will help you. If you have any query regarding Higher Secondary Kerala Plus Two Chapter Wise Quick Revision Notes based on CBSE NCERT syllabus, drop a comment below and we will get back to you at the earliest.

HSSLive Plus Two

HSE Kerala Board Syllabus HSSLive Plus Two Chapter Wise Questions and Answers Pdf Free Download in both English Medium and Malayalam Medium are part of Plus Two Kerala SCERT. Here HSSLive.Guru has given Higher Secondary Kerala Plus Two Chapter Wise Questions and Answers based on CBSE NCERT syllabus.

Kerala Plus Two Chapter Wise Questions and Answers

• Plus Two Maths Chapter Wise Questions and Answers
• Plus Two Physics Chapter Wise Questions and Answers
• Plus Two Chemistry Chapter Wise Questions and Answers
• Plus Two Botany Chapter Wise Questions and Answers
• Plus Two Zoology Chapter Wise Questions and Answers
• Plus Two History Chapter Wise Questions and Answers
• Plus Two Political Science Chapter Wise Questions and Answers
• Plus Two Economics Chapter Wise Questions and Answers
• Plus Two Business Studies Chapter Wise Questions and Answers
• Plus Two Accountancy Chapter Wise Questions and Answers
• Plus Two Computer Science Chapter Wise Questions and Answers
• Plus Two Computer Application Chapter Wise Questions and Answers
• Plus Two Sociology Chapter Wise Questions and Answers
• Plus Two English Textbook Answers
• Plus Two Hindi Textbook Answers

We hope the given HSE Kerala Board Syllabus HSSLive Plus Two Chapter Wise Questions and Answers Pdf Free Download in both English Medium and Malayalam Medium will help you. If you have any query regarding Higher Secondary Kerala Plus Two Chapter Wise Questions and Answers based on CBSE NCERT syllabus, drop a comment below and we will get back to you at the earliest.

HSSLive Plus Two

Kerala State Board New Syllabus Plus Two Malayalam Textbook Answers Unit 2 Tanatita Text Book Questions and Answers, Summary, Notes.

Kerala Plus Two Malayalam Textbook Answers Unit 2 Tanatita

Tanatita Summary